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CSS - Css Background Image Question
I have a website and i want to use two background images like this:
Code: +---------------------------------------+ | Main page with | | background image 1 | | | | +-----------------------+ | | | Box 1 with top of | | | | background image 2 | | | | | | | +-----------------------+ | | (background image 1) | | +-----------------------+ | | | Box 2 with middle of | | | | background image 2 | | | | | | | +-----------------------+ | | (background image 1) | | +-----------------------+ | | | Box 3 with bottom of | | | | background image 2 | | | | | | | +-----------------------+ | | | +---------------------------------------+ Basically, I want the boxes to "share" the same background image (i.e. not have it repeat in each box) but to have the first background image appear between (and on the sides) of each box. Is this possible? (And if so, how can it be done?) Similar TutorialsI'm still pretty new to css, so please be patient. I've downloaded some pictures that are meant to take the place of the entire background without repeating. I've tried dev'ing an external style file that has this pictu here is the code I have in the style file as is: body {color: black; background: url(write020.jpeg) center center} Well, every time I use this picture, it never comes up, I know I've linked it correctly, because when I place pictures that are meant to be tiled(repeated) they work, any suggestions? Ok, if you go to http://www.fgdesigns.net on a higher resolution (great than 1024x whatever) you will see that the footer is hovered and the picture extends down. I want to either: hide the rest of the picture, or have the footer all the way at the bottom. Though, I believe it is impossible to have the footer touch the bottom on such a high resolution, given such little content. So, is there a suggested way to hide the rest of the picture? I have successfully added a background image to the page but it does not center how I want it to. Right now it is positioned at top center. I would like to move it to Center center of entire page. Using this code instead of center for background-position did not do anything. Neither did 50%, 50%. What can I do to move this over. I have the same problem with a picture file to go above the background file and web links which are all placed at top left of page. It would be nice to move them to top center of page. How is this possible through html code? Here is the code for the background image: <style type="text/css"> body { background-image: url(picture/bamboo.jpg) } body { background-position: center } body {background-repeat: no-repeat } </style> Thank you for your help, The layout I have going is a bit difficult to explain. Here's a diagram.. The area of importance is the header. The content and main head area are centered. The area to the left and right of the header are a <div>. However, as you can see, the background image on the left is different than the one on the right. I'm having difficulty making this work. the images can be stretched horizontally without a problem, but the two sides must meet in the middle beneath the header. I hope this makes sense. What I've got to do, I think, is tell the background image of the underlying <div> to stretch to 100%, and make this image 300px wide or so including both sides of the image and a split. The split would hide behind the header. I can't find a method to stretch the background image, though. Does anybody know of a better way, or a way to achieve this method at all without getting into completely different layouts? Thanks in advance for any assistance/suggestions. In short, I'm trying to get this one image to tile down the page to the bottom, underneath a static background image. Basically, it's a 2pixel high image that's ready to tile vertically, just having a tough time getting it to work. You can clearly see the problem here, a gap at the bottom: http://www.groundedgroup.com/clients/NWR/ Here's the relevant css: http://www.groundedgroup.com/client...WR-GG/style.css I've googled and subsequently tried out some solutions, but no luck. Got any ideas? Thanks in advance. PS - Is there a way to keep the spiders from indexing my links above? The site is on a test server, so I don't want the url indexed. Hi. Really hoping someone can help me with this... I'll try and explain this as best I can(!) Basically I've got a page containing a block of 9 images, with each linking to a video clip. At the moment I've got the CSS coded so that whenever the mouse is hovered over the 'infobar' (at the bottom of each image) it goes from having a transparent background with black text to having a grey background with white text. What I'm trying to achieve is that same effect whenever the mouse is hovered over any part of the image and infobar. The live online link can be found at: www.markmcm.co.uk/test/test.html The CSS is as as follows: Code:
/*
* Page Stylesheet
*/
body {
font-family: Arial, Helvetica, sans-serif;
background-color: #eaeaea;
border:0; margin:0; padding:0;
height: 100%;
}
a:link {
text-decoration: none;
}
a:visited {
text-decoration: none;
}
a:hover {
text-decoration: none;
}
a:active {
text-decoration: none;
}
#container {
margin-left: auto;
margin-right: auto;
min-height: 100%;
width: 936px;
}
* html #container {
height: 100%;
}
#content {
float:left;
position: relative;
height: 528px;
width: 936px;
z-index: 0;
}
.miniscreen1, .miniscreen2, .miniscreen3, .miniscreen4, .miniscreen5, .miniscreen6, .miniscreen7, .miniscreen8, .miniscreen9 {
position: absolute;
float: left;
display: block;
width: 312px;
height: 176px;
}
.miniscreen1 {
top: 0;
left: 0;
}
.miniscreen2 {
top:0;
left: 312px;
}
.miniscreen3 {
top: 0;
left: 624px;
}
.miniscreen4 {
left: 0;
top:176px;
}
.miniscreen5 {
left: 312px;
top:176px;
}
.miniscreen6 {
left: 624px;
top:176px;
}
.miniscreen7 {
left: 0;
top:352px;
}
.miniscreen8 {
left: 312px;
top:352px;
}
.miniscreen9 {
left: 624px;
top:352px;
}
.info {
height: 30px;
top:3px;
left: 40px;
width: 265px;
float: left;
position: absolute;
}
.infobar {
left:0px;
position: absolute;
top: 140px;
width: 312px;
height: 36px;
outline: none;
color:#000;
background: url("data/infobar.png") no-repeat 0 0;
z-index: 650;
}
.infobar:hover {
background-position: 0 -36px;
outline: none;
color:#fff;
}
#infobar span {
display: none;
outline: none;
}
.clip_title {
outline: none;
font-size: 85%;
font-weight: 700;
vertical-align: top;
text-align: left;
}
.clip_sub {
outline: none;
height: 13px;
font-size: 80%;
line-height: 13px;
font-weight: 700;
vertical-align: top;
text-align: left;
}
And the HTML is: Code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Test Page</title> <meta name="description" content=" " /> <meta name="keywords" content=" " /> <meta name="generator" content=" " /> <link rel="stylesheet" type="text/css" href="page.css" media="screen" /> </head> <body> <div id="container"> <div id="content"> <span class="miniscreen1"> <a href="#"> <img src="img/clip1.jpg" width="312" height="176" border="0"> <span class="infobar"><span class="info clip_title">Test Clip 1<br><span class="clip_sub">123 Productions</span></span></span></a> </span></span> <span class="miniscreen2"> <a href="#"><img src="img/clip2.jpg" width="312" height="176" border="0"> <span class="infobar"><span class="info clip_title">Test Clip 2<br><span class="clip_sub">123 Productions</span></span></span></a> </span></span> <span class="miniscreen3"> <a href="#"><img src="img/clip3.jpg" width="312" height="176" border="0"> <span class="infobar"><span class="info clip_title">Test Clip 3<br><span class="clip_sub">123 Productions</span></span></span></a> </span></span> <span class="miniscreen4"> <a href="#"><img src="img/clip4.jpg" width="312" height="176" border="0"> <span class="infobar"><span class="info clip_title">Test Clip 4<br><span class="clip_sub">123 Productions</span></span></span></a> </span></span> <span class="miniscreen5"> <a href="#"><img src="img/clip5.jpg" width="312" height="176" border="0"> <span class="infobar"><span class="info clip_title">Test Clip 5<br><span class="clip_sub">123 Productions</span></span></span></a> </span></span> <span class="miniscreen6"> <a href="#"><img src="img/clip6.jpg" width="312" height="176" border="0"> <span class="infobar"><span class="info clip_title">Test Clip 6<br><span class="clip_sub">123 Productions</span></span></span></a> </span></span> <span class="miniscreen7"> <a href="#"><img src="img/clip7.jpg" width="312" height="176" border="0"> <span class="infobar"><span class="info clip_title">Test Clip 7<br><span class="clip_sub">123 Productions</span></span></span></a> </span></span> <span class="miniscreen8"> <a href="#"><img src="img/clip8.jpg" width="312" height="176" border="0"> <span class="infobar"><span class="info clip_title">Test Clip 8<br><span class="clip_sub">123 Productions</span></span></span></a> </span></span> <span class="miniscreen9"> <a href="#"><img src="img/clip9.jpg" width="312" height="176" border="0"> <span class="infobar"><span class="info clip_title">Test Clip 9<br><span class="clip_sub">123 Productions</span></span></span></a> </span></span> </div> </div> </body> </html> There must be a better (and easier?) way to do this. Any help would be very-much appreciated - and save an old bloke from tearing too much of his hair out(!) Hi, I have a question about setting up the Body background-image via a linked external stylesheet. I have a index.html file and a myStyle.css file. I want to setup the background to load an image file, test.JPG. When I embed the following in my index.html, I see the background show up: ** inside index.html file ** <BODY STYLE="background-image: url(test.JPG);"> blah </BODY> BUT, when I define my background in the externally linked myStyle.css file, the background does not load: ** inside myStyle.css file ** BODY { background-image: url(test.JPG); } ** inside index.html file ** <LINK REL="stylesheet" TYPE="text/css" HREF="myStyle.css"> <BODY> blah </BODY> </LINK> Please help. thanks! Hi I am redesigning my blog and took it down completely. I want to place the day's text post on the day's photo post on top of the latter, while graying out the photo. Is that possible without using flash? I'm trying to create a little background image for each image on this page. A kind of crappy looking polaroid type background image. It works fine in Firefox, but not in IE. Any ideas? http://www.rhizaowns.com/holly/index.php Code: div.top {
border: 10px solid #CCCCCC;
border-bottom-width: 0px;
padding: 0px;
background-image: url(menutile.jpg);
}
The code above yields this . It is uneven with the normal image, though both are the same size. I simply want to tile the bg image to the border even with the normal menu images. What am I doing wrong? I am trying to put labels below images on my new site design. See: www.jwsuretybonds*com/jw09 I figured out how to get them vertically aligned, but I am having problems with the horizontal, as when I change the browser size, they move. Here is one of the examples: Code:
#homepage-bar h2.construction {
position:fixed;
top:225px;
left:505px;
}
I tried changing to position: absolute; I also tried to use percentages on the left: I know this is easy, but I can't find the fix after googling for 30 minutes. Help! I was wondering if there is a way to make your wrapper have a background color to make your font more readable but still be transparent so that you still can see the body background pic? Hopefully this doesn't sound like a stupid question. Is that possible? What would be the code for that? Hello, I created a 1px x 1000px image for my background that is a gradient. In my css I have the following code: background-image: url(images/background.jpg); background-repeat: repeat-x; Now, on longer pages (that obviously exceed 1000px) the graphic stops. Is there a way to get around this using CSS code, or should I just make the graphic longer? Thanks! All I'm new to html and css and this one has put a flat spot on my forehead over the last 2 days. Anyway, I have an image that I want to cover successive rows in a table with; one image spanning 6 rows. The table has no borders because I would prefer to group the data fields in the cells with an image. The image is a trim box with a little faded color around the edge. I'll take any ideas!! Thanks'Pete I was wondering on this table I have I want it to have black background colour but I want to change the opacity to where you could see the background image too Hi all, I need to have two CSS stylesheets that change the background color of my page. All I need to know is the CSS code to change the background color. Cheers. I want to use php to get images from a database and display them as css background-image attributes I know that the css Code: #id { background-image: url ('path/file'); }
works (obviously) and the html Code: <img src='image-generator-script.php'> also works but the css Code: #id { background-image: url ('image-generator-script.php'); }
doesn't work for me. It seems as though it should work. Why place such a seemingly arbitrary limitation on CSS as only being able to display images from existing files? I've done lots of searching through documentation and on forums, but not found anything conclusive either way. A couple of people have said it works. But it doesn't for me. Is there some extra configuration step I'm missing? Does anyone know for a fact that it works? -- so I can know for sure that somewhere I'm making a blunder in my code. But the code is simple, and I don't see where it could go wrong. (As is always the case!!) I can see the image in the browser just by pasting in the script link to the address bar. I know that url() specifiers are relative to the location of the stylesheet, not the html document, but in this case the html, the css, and the php are all in the same directory. I can't see what I could be doing wrong, so it really looks like you can't do it. But why?? And why isn't it mentioned in the documentation? (At least in the placers I've looked.) If you store all your images in a database, how on earth can you display any of them in CSS except by using a script in the url() specifier? I've seen plenty of tips about generating css files from php (I already do it), but that won't help in this case. All I can think of is to have php write the image data from the database into a temporary file, and put that file name into the url() specifier. But what a horrible kludge!! I will be very grateful to anyone who can give me solid facts on this question. Andrew Blake I'm trying to make a td change it's background when you rollover the link within it. This code seems ok to me, but I'm not having any luck with the rollover effect. Can any experts take a look? .nav{ background-image:url('images/topmenu/blacknav.jpg'); } .nav a{ font:12px Verdana, Arial, Helvetica, sans-serif; color:#fff; display: block; font-weight:bolder; text-decoration:none; text-align:center; } td.nav a:hover { background-image:url('images/topmenu/nav_highlight.jpg'); } Thanks for taking the time to read my question. I have a small logo that I would like to stay in the top and bottom corners of my page. Can I do that? Here is what I have so far Code: background-image: url('HelpImages/LandmarkBorder.jpg');
background-repeat: no-repeat;
background-attachment: fixed;
background-position: top right;
but this only gives me one image. I need something to show up in the top left, and both bottom corners. If this can't be done, can I have one image for the background and stretch it across the whole page? Thanks, Brad |
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