JavaScript - Beginner Js Help. 3 Questions

hello!
i have a problem:
i want to change the height of my side bar as long as the text in the center of page long,
it means when I have for ex 3 news in a page the side bar which have a background color must be increase to fit the long of text(3 news).

i think it will do by javascript but i'm not sure!

i my question isn't clear please tell me to explane more i really need it,

I will start off by saying yes this is homework but I only want help. I'm trying to make the content show up in the read only boxes but I can't figure out where I'm going wrong. My test page can be found at http://sidewalk-cafe.com/test/maddox-hw2a.html. It's small. Any help would be appreciated.

Code:

function orderForm() {
	var formDaysStaying = document.getElementById("daysStaying").value;
	var formSeason = document.getElementById("season").value;
	var formPropertyType = document.getElementById("propertyType").value;
    document.getElementById("FEE").value = "$" + today.toFixed(2);
    document.getElementById("totalCost").value = "$" + today.toFixed(2);	
    document.getElementById("today").value = "$" + today.toFixed(2);
    document.getElementById("due").value = "$" + due.toFixed(2);	
    }


function formTotalCost(form) {
	const FEE = 55;
    var totalCost = (formPropertyType * formSeason) * formDaysStaying;
	var today = totalCost * .10;
	var due = (totalCost + FEE) - today;
    if (document.getElementById("daysStaying").value == "" ||
    isNaN(document.getElementById("daysStaying").value))
    alert("Please provide the number of days you will be staying.");
          // Submit the order to the server
          form.submit();
}

Hi there, im wondering if you can help me i need help in finding javascript resources to build my skills and knowledge of Jscript because im a beginner.

Please help

I am very new to JavaScript and I am currently following the Eloquent JavaScript book online.
On one of the exercises, we are told to make a function that returns the range of the inputs in an array.
I tried this code below but it doesn't seem to work. The problem seems to be in the "If" function because if I change the condition to (start < end) it seems to work.
Can someone please explain to me why this is?


function range (start, end) {
var j = [];
if (start > end) {
for (i = start; i <= end; i++) {
j.push(i); }
} else {
for (i = start; i >= end; i--) {
j.push(i); }
}
return j;
}

console.log(range(10, 2));
console.log(range(2, 10));





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01-26-2015, 08:49 PM #2
Labrar View Profile View Forum Posts

New Coder Join Date Jun 2008 Posts 65 Thanks 0 Thanked 12 Times in 12 Posts

Why you do not use something like this

var range = function(start, end, step) {
var range = [];
var typeofStart = typeof start;
var typeofEnd = typeof end;

if (step === 0) {
throw TypeError("Step cannot be zero.");
}

if (typeofStart == "undefined" || typeofEnd == "undefined") {
throw TypeError("Must pass start and end arguments.");
} else if (typeofStart != typeofEnd) {
throw TypeError("Start and end arguments must be of same type.");
}

typeof step == "undefined" && (step = 1);

if (end < start) {
step = -step;
}

if (typeofStart == "number") {

while (step > 0 ? end >= start : end <= start) {
range.push(start);
start += step;
}

} else if (typeofStart == "string") {

if (start.length != 1 || end.length != 1) {
throw TypeError("Only strings with one character are supported.");
}

start = start.charCodeAt(0);
end = end.charCodeAt(0);

while (step > 0 ? end >= start : end <= start) {
range.push(String.fromCharCode(start));
start += step;
}

} else {
throw TypeError("Only string and number types are supported");
}

return range;

}


Thats pretty similar to php range





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01-26-2015, 09:25 PM #3
Old Pedant View Profile View Forum Posts

Supreme Master coder! Join Date Feb 2009 Posts 28,310 Thanks 82 Thanked 4,754 Times in 4,716 Posts

Ignore Labrar's ridiculously complicated answer to a very simple problem.

Instead look CAREFULLY at this code: Code:

if (start > end) {
    for (i = start; i <= end; i++) {

Let's use your first example, where you call range(10, 2)

So start is 10. And end is 2.

So you get to if ( start > end ) and JavaScript executes that as if ( 10 > 2 )

Indeed, 10 *IS* greater than 2, yes?

SO you the go execute the NEXT line: for (i = start; i <= end; i++)

Which, of course, JavaScript then executes as for (i = 10; i <= 2; i++)

But then 10 is *IMMEDIATELY* <= 2. So the for loop NEVER RUNS.

All you need to do to fix your code is change Code:

if (start > end) {

into Code:

if (start < end) {

PRESTO!

**********

The tiniest bit of debugging using your JavaScript debugger would have found this. But also just learning to THINK like the computer would help. Actually run the code in your head, using your example numbers, and you'd see where you went wrong.

Hey guys, I am working on building a new site and was wondering if I could get some clarity on something with JS, as I am el noobo.

I have the basic layout he http://www.temp3.hangnailproductions.com/

Now this is just a mock up and I plan to validate the code, make it more semantic and clean up my CSS quite a bit, but right now I just want to get an idea of what I have to do and something has caught my eye. When the page loads, it takes quite a few seconds for the javascript I have attached to populate a few areas on the screen. At the top of the page there is a random testimonial and the current date. Both are populated from this script: http://www.temp3.hangnailproductions.com/js/master.js

I don't know if these areas take a few seconds because my code is horribly wrong, too large, or if this is just normal. Does the array that holds the testimonials hold too much information? I would really appreciate some help.

Also, the section that says "This should be a small blurb about the link above." is going to be a snippet of text that changes when a user mouseovers a main link at the top. I think this will also be JS and included in the same "master.js" file - thoughts?

Thanks very much.

(And I know it is ironic that I am asking for help on a site that sells web design, but Javascript is not something I plan to push, and if need be I would hire someone to help with any in-depth JS. I thought this would just be a simple little project...)