JavaScript - Jquery Graphing Help

i keep getting the error

GET http://code.jquery.com/jquery.min.map net::ERR_TOO_MANY_REDIRECTS
& Failed to load resource: net::ERR_TOO_MANY_REDIRECTS

when i load my page...and the havascript doesn't work properly on ym page...how do i resolve this.

thanx in advance

var s="attr"
var i=$(s)
// jQuery(elem).attr(attr,eval("elm"+attr));
jQuery(elem).$(s)(attr,eval("elm"+attr));//i tried this.

how to assign a variable name in the above code(in place of s) so that i need to add an attribute to the element "elem".

Ok, I would post my entire data here but then yall would be reading insane amounts of script. I've got a div content jquery slider on my site I am making and it works beautifully in all browsers(took me a while). Then, I decided why not have it where when people click on a "read more" link that it pops up a box, instead of directing to the new page, and displays the contents of a div. It would not work at all. My question is there a possible way to do this?

i want get value form path :
ex..
xxx.com/index.php?cat

" cat " read cookie with jquery

who?

I'm not sure if this is something jquery can do or what but here's what I want to do but I have this following code and when it shows either Public or Archived for the Event Status I want it to be a link so that if I click on Public then it turn it into Archived because it'll change its status_id in the DB from 4 to 5.

PHP Code:
case 1:
            echo $e;
            ?>
            <h1 class=backstage>Archiving Management</h1><br />
            <h2 class=backstage>Weekly Events</h2><br />
                
                <?php
                $query = "SELECT ecb.bookingdate, els.name, ele.statusname, ecb.label FROM `efed_content_booking` AS ecb LEFT JOIN `efed_list_shownames` AS els  ON ( ecb.event_id = els.id ) LEFT JOIN `efed_list_eventstatus`  AS ele ON ( ecb.status_id = ele.id ) WHERE els.type = 'singular' OR els.type = 'recurring'"; 
                
                $result = mysql_query ( $query ); 
                $rows = mysql_num_rows($result);
                if ($rows > 0)  {
                print'<table width="100%" class="table1">
                    <tr class="rowheading">
                        <td>Event</td>
                        <td align="center">Booking Date</td>
                        <td align="center">Event Status</td>
                    </tr>';
                $i = 0;
                while ( $row = mysql_fetch_array($result, MYSQL_ASSOC) ) {
                    $sClass = 'row2';
                    if ($i++ % 2) $sClass = 'row1';
                    printf ( "<tr class=\"%s\">", $sClass );
                    printf ( "<td valign=\"top\">%s%s</td>", $row['name'],$row['label'] );  
                    printf ( "<td valign=\"top\" align=\"center\">%s</td>", convertdate($row['bookingdate'] ));
                    printf ( "<td valign=\"top\" align=\"center\">%s</td>", $row['statusname'] );
                    echo '</tr>';
                 }
                echo '</table><br>';
            } else {
                echo '<span>There are no weekly events to archive.</span><br /><br />';
            }
            ?>
                <h2 class=backstage>Pay-Per-View Events</h2><br />
                
                <?php
                $query = "SELECT ecb.bookingdate, els.name, ele.statusname, ecb.label FROM `efed_content_booking` AS ecb LEFT JOIN `efed_list_shownames` AS els  ON ( ecb.event_id = els.id ) LEFT JOIN `efed_list_eventstatus`  AS ele ON ( ecb.status_id = ele.id ) WHERE els.type = 'ppv'"; 
                
                $result = mysql_query ( $query ); 
                $rows = mysql_num_rows($result);
                if ($rows > 0)  {
                print'<table width="100%" class="table1">
                    <tr class="rowheading">
                        <td>Event</td>
                        <td align="center">Booking Date</td>
                        <td align="center">Event Status</td>
                    </tr>';
                $i = 0;
                while ( $row = mysql_fetch_array($result, MYSQL_ASSOC) ) {
                    $sClass = 'row2';
                    if ($i++ % 2) $sClass = 'row1';
                    printf ( "<tr class=\"%s\">", $sClass );
                    printf ( "<td valign=\"top\">%s%s</td>", $row['name'],$row['label'] );
                    printf ( "<td valign=\"top\" align=\"center\">%s</td>", convertdate($row['bookingdate']) );
                    printf ( "<td valign=\"top\" align=\"center\">%s</td>", $row['statusname'] );
                    echo '</tr>';
                 }
                echo '</table><br>';
            } else {
                echo '<span>There are no ppv events to archive.</span><br /><br />';
            }
            returnmain();
            footercode();
        break;

I'm not sure if I'm in the right place or not, but I am in desparate need of some help. I have this code:

Code:

<script type="text/javascript">


$(document).ready(function(){
	$('#add').click(function() {
	alert('test');
	});
	$("form#exercise").submit(function() {
	// we want to store the values from the form input box, then send via ajax below
	var activity     = $('#activity').attr('value');
		$.ajax({
			type: "POST",
			url: "newActiveProc.php",
			data: "activity="+ activity +"&func=search",
			success: function(activity){
				$("span#results").html(activity);

			}
		});
	return false;
	});

});
</script>

As you can see by the highlighted portion, the user is alerted once they make a selection. It should go something like this:

[Add to table] Football
[Add to table] Basketball
[Add to table] Baseball

Once they click the 'add to table' button, their selection should be added to a table that is at the bottom of the page. So far, all I've been able to do is generate an alert box, but I know thats not right. Any information anyone has would be helpful. Thanks in advance.

All,
I have the following jQuery code:
Code:

$("#other").click(function(){
    		var checked = $(this).is(':checked');
    		if(checked){
       			$('textarea#other_text').removeAttr("disabled");
    		}else {
        		$('textarea#other_text').attr("disabled", "disabled");
    		}
    	});

This works fine. However, what I'm allowing the users to do is edit this field. So I have the following PHP code:
PHP Code:
<input type="checkbox" name="other" value="x" id="other" <?php if($resultsetedits['other']=="x"){ echo "checked"; } ?>>&nbsp;Other:<br>If you choose other, please explain what other options you'd like us to do to your photo:<textarea name="other_text" rows="3" cols="119" id="other_text" disabled><?php if($resultsetedits['instructions']!=""){ echo $resultsetedits['instructions']; } ?></textarea>

Since the checkbox is checked with the PHP code the click function to jQuery never gets invoked and my textarea remains disabled. Is there anyway to basically invoke the jQuery code with my PHP script? Thanks in advance.

i am a newbie to jquery and need help.

i want to alert anything when i click at any button that have the class .resetBtn using jquery.
I know doing it with javascript is much easier but i learning jquery so trying to create function by myself.

my code currently does not work when i click on my button.


Code:

$(".resetBtn").click(function() {
	alert ("asd");
});

Hi All,

i have an autosuggest feature on my site where the user searches for a product and as they type it lists matching products from my database.

here is the javascript/jquery code
Code:

$(document).ready(function(){$(document).click(function(){$("#ajax_response").fadeOut('slow');});$("#keyword").focus();var offset=$("#keyword").offset();var width=$("#keyword").width()-2;$("#ajax_response").css("left",offset.left);$("#ajax_response").css("width",width);$("#keyword").keyup(function(event){var keyword=$("#keyword").val();;if(keyword.length)
{if(event.keyCode!=40&&event.keyCode!=38&&event.keyCode!=13)
{$("#loading").css("visibility","visible");$.ajax({type:"POST",url:"/ajax_server.php",data:"data="+keyword,success:function(msg){if(msg!=0)
$("#ajax_response").fadeIn("slow").html(msg);else
{$("#ajax_response").fadeIn("slow");$("#ajax_response").html('<div style="text-align:left;">No Matches Found</div>');}
$("#loading").css("visibility","hidden");}});}
else
{switch(event.keyCode)
{case 40:{found=0;$("li").each(function(){if($(this).attr("class")=="selected")
found=1;});if(found==1)
{var sel=$("li[class='selected']");sel.next().addClass("selected");sel.removeClass("selected");}
else
$("li:first").addClass("selected");}
break;case 38:{found=0;$("li").each(function(){if($(this).attr("class")=="selected")
found=1;});if(found==1)
{var sel=$("li[class='selected']");sel.prev().addClass("selected");sel.removeClass("selected");}
else
$("li:last").addClass("selected");}
break;case 13:$("#ajax_response").fadeOut("slow");$("#keyword").val($("li[class='selected'] a").text());searchValue=document.getElementById('keyword').value; searchValue = searchValue.replace( /\([^\)]*\)/g, "" );searchValue = searchValue.replace(/^\s*|\s*$/g,'');searchValue=searchValue.replace(/(\s-)/gi,"");searchValue=searchValue.replace(/\s/gi, "_");searchValue=searchValue.replace(/[:',]/gi,"");window.location="/CDs/"+searchValue.toLowerCase();break;}}}
else
$("#ajax_response").fadeOut("slow");});$("#ajax_response").mouseover(function(){$(this).find("li a:first-child").mouseover(function(){$(this).addClass("selected");});$(this).find("li a:first-child").mouseout(function(){$(this).removeClass("selected");});$(this).find("li a:first-child").click(function(){$("#keyword").val($(this).text());$("#ajax_response").fadeOut("slow");});});});

this runs this php script to get the product names
PHP Code:
<?php
session_start();

    include("config.php");
    $keyword = $_POST['data'];
    $keyword = preg_replace("/s*\(.*\)/i", "", $keyword);
    $keyword = ucwords($keyword);

    $sql = "select DISTINCT prodName,prodShortName,prodCategory from ".$db_table." where (".$db_column." like '".$keyword."%' AND prodCategory = '".$_SESSION['subpage']."') limit 0,10";
    $result = mysql_query($sql) or die(mysql_error());
    
    if(mysql_num_rows($result))
    {
        echo '<ul class="list">';
        while($row = mysql_fetch_array($result))
        {
            $category = strtolower($row['prodCategory']);
            $str = ucwords($row['prodName']);
            $start = strpos($str,$keyword); 
            $end   = similar_text($str,$keyword); 
            $last = substr($str,$end,strlen($str));
            $first = substr($str,$start,$end);
            $link = "/".$category."/".$row['prodShortName'];
            
            $final = '<span class="bold">'.$first.'</span>'.$last;
        
            echo '<li><a href="'.$link.'">'.$final.'</a></li>';
        }
        echo "</ul>";
    }
    else {
        echo "0";
        }
?>

which works fine, what i am trying to acheive is to pull out the category of the products in the list and use it in the script.

so where it says this
Code:

window.location="/CDs/"+searchValue.toLowerCase();break;

i want the value of the php value $category to be. but i have no idea how to do this or if it is even possible? any help is appreciated

many thanks
Luke

Hi,

I have this js script which is working on mouse click, what is my requirment is that it do the same function wiht on mouse over:

click: function(e) {
var el = this;
el.blur();
// if the image was not preloaded yet then wait
if (el.zoomimageCfg.loading === true) {
return false;
}
//zoom it in if not zoomed already
if (el.zoomimageCfg.zoomed == false) {
EYE.zoomimage.zoomIn(el);
//else zoom it out
} else {
EYE.zoomimage.zoomOut(el, false);
}
return false;
},

Thank you

Best Regards,
mnightwalker

Hi Guys,

Please check this link out. I'm curious if you can attain the same functionality with jquery. Which include the hover over effects and sliding. If this can be done can you point me in the right direction to find some documentation to start learning. Thanks.

http://www.gensler.com/#projects

Hello There,

I am using Jquery Tabs http://jqueryui.com/demos/tabs/ with the codes below

Code:

<script type="text/javascript"> 
	$(function() {
		$( "#tabs" ).tabs().addClass( "ui-tabs-vertical ui-helper-clearfix" );
		$( "#tabs li" ).removeClass( "ui-corner-top" ).addClass( "ui-corner-left" );
              $("#tabs").tabs( { fx: { height: 'toggle', opacity: 'toggle' } } );
	});
	</script>

I have got 4 tabs and I want to link each of them in the menu. Therfore I must arrange the default one in my each html page. How can I do that?

I am using tooltip plug in on a site and when I use it on a blank template, it works then when I transfer it to the page I want to use it on it does not work.

The site is

Here is they javascript code:

Code:

this.imagePreview = function(){	
	/* CONFIG */
		
		xOffset = 10;
		yOffset = 30;
		
		// these 2 variable determine popup's distance from the cursor
		// you might want to adjust to get the right result
		
	/* END CONFIG */
	$("a.preview").hover(function(e){
		this.t = this.title;
		this.title = "";	
		var c = (this.t != "") ? "<br/>" + this.t : "";
		$("body").append("<p id='preview'><img src='../"+ this.href +"' alt='Image preview' />"+ c +"</p>");								 
		$("#preview")
			.css("top",(e.pageY - xOffset) + "px")
			.css("left",(e.pageX + yOffset) + "px")
			.fadeIn("fast");						
    },
	function(){
		this.title = this.t;	
		$("#preview").remove();
    });	
	$("a.preview").mousemove(function(e){
		$("#preview")
			.css("top",(e.pageY - xOffset) + "px")
			.css("left",(e.pageX + yOffset) + "px");
	});			
};


// starting the script on page load
$(document).ready(function(){
	imagePreview();
});

Here is the HTML code.

Code:

<ul>
		<li><a href="mailto:rragon@cumberland.k12.il.us">Mr. Russell Ragon</a>&nbsp;<a href="../../Images/staffbios/rragon.gif" class="preview"><img src="1s.jpg" alt="BIO" /></a></li>
	</ul>

Here is the CSS code:
Code:

#preview{
	position:absolute;
	border:1px solid #ccc;
	padding:5px;
	display:none;
	color:#fff;
	background-color: #333;
	}

This is my first post on this forum so I hope the code is clear you can check out the site up above just hover over one of the names. I am only getting image preview instead of the image I want. Ont thing I did do was I took out the image so I could get the Alternate code.

My objective here is to have a name and when you hover over it an image pops up and on the image will be a biography of the teacher.

Thanks for any help.

I am using this code he http://tablesorter.com/docs/

I have a table that works great but when I update values on, it has drop down in some cells, it wont sort that. So for that when I change a drop down a hidden div in the same cell gets updated with the value so I can sort on that. Well that works but then I have to reinitialize the table sorter to find the new value. That creates two functions and messes things up when you go to sort.

Does anyone have a way to unload a function or even a better method to sort a table?

Here is the code to initialize the sorting js:
Code:

$(document).ready(function() 
    { 
        $("#myTable").tablesorter(); 
    } 
);