JavaScript - Regular Expression Replace Question.

I have the following regular expression to test the validity of an input date:

Code:

([0-9][0-9]|[0-9])[\s/-]([0-9][0-9]|[0-9])[\s/-]([0-9][0-9][0-9][0-9]|[0-9][0-9])

It should allow 1 or two digits for the day of the month, then a separating character (" ", "/" or "-"), then 1 or two digits for the month, then 2 or 4 digits for the year.

Unfortunately it will accept anything above 2 digits for the year, which I understand why is happening but don't know how to fix! Can anyone help?

Thanks!

I am trying to find the correct regular expression (or an alternate) for if a user enter any more than 1-3 digits in the age field of a form it produces an error message. I already have the error set up, just the correct coding to produce the 1-3 digit condition.
Thanks, KWIKCUCUMBER.

I want to validate a form with only numbers and "$" sign.
so far i know this
Code:

		currencyValue = which.value;
		var re = /^[0-9]*$/;
		if (!re.test(currencyValue)) {
		    alert("Value must be all numberic charcters, non numeric's removed from field!");
		    field.value = field.value.replace(/D/g,"");
		}

but how do I also add the "$" sign as ok?

Hi,
Can someone fix the following regular expression? It is validating every thing expect YEAR. It only matches first 2 digits for year instead of 4. I want it to be 4 digits for a year. It returns true if I put 12/25/19.I want it to return false for the above date.

Code:

var RegExPattern = /^(?=\d)(?:(?:(?:(?:(?:0?[13578]|1[02])(\/|-|\.)31)\1|(?:(?:0?[1,3-9]|1[0-2])(\/|-|\.)(?:29|30)\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})|(?:0?2(\/|-|\.)29\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))|(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|\.)(?:0?[1-9]|1\d|2[0-8])\4(?:(?:1[6-9]|[2-9]\d)?\d{2}))($|\ (?=\d)))?(((0?[1-9]|1[012])(:[0-5]\d){0,2}(\ [AP]M))|([01]\d|2[0-3])(:[0-5]\d){1,2})?$/;

Thanks

I want to find in all occurrences of #(...) in a string (what is between the parentheses is unknown. At the moment I have
Code:

str.match(/#\(.*\)/)

The problem is, I want to be able to have multiple of these in one string, like "#(hello) good #(world)", but RegExp takes me from the first '#', to the last ')'.

I want to allow nested parentheses, so I am thinking that there should be away to not let it look past the second '#'. How would I do this?

Dear experts

I have following codes

Var re=/(\d){4}-(\d){7}/;

When I test this string
0300-685706263

It says TRUE

But I validate this string exactly

0300-6857062

Please help

Hello,

How can i validate string with alphanumeric, space, dash and dot in regular expression ?

for the character classes [ ] ,
if i want to match ,.[] i cannot put them into the square brackets so how to deal with that? what if the characters are . or ! or ." (<-- combined) it fails if the regexp is [.!(.")] which will treat ( as one of the element.

also the book javascript: the definitive guide says that (?=p) requires that the following characters match the pattern p, but do not include those characters in the match. However, the browser failed to figure this out (IE8)
i.e. "asd:ert".match(/(?=\\w/) returns null

thx in advance

can anyone explain me in detail what this regular expression mean...
each and every part of this sentence:
var baseRegex = new RegExp("^(?=.{6,})(?=.*^[A-Za-z]([a-zA-Z0-9_-]+)$)(?=.*[A-Z])");

Hi all, I have this line (part of a larger function that converts a few common BBCodes into HTML) and I don't know how to do one thing. First, here's the line:

Code:

str.replace(/\[color=(.*?)\](.*?)\[\/color\]/gi,'<span style="color:$1;">$2</span>');

It works fine if I do this (I'll mis-spell "color" to prevent messing up the board):

THIS works fine.....
[colur=#ff0000]Red Text[/colur]

But of course, if I do this:
[colur="#ff0000"]Red Text[/colur]

It doesn't work.

What I need to do is take the $1 variable, AFTER it's captured, but BEFORE it's used, and strip out any quote marks I find. I may want to also strip out, then add the hash sign (#) also, then put it back so it works with or without the #.

While I'm at it, I'll also probably detect color as a hex string vs. a keyword (so that both "#ff0000" and "red" work) and probably also support the rgb() method.

But first I need to know how to access and modify $1 BEFORE it's used. I'm hoping that I don't need to use two lines (or two separate .replace() calls).

Thanks!

-- Roger

I'm trying to convert a line using a regular expression.

The re I am using is this: <div><span>&middot;<span>[\s*]<\/span><\/span>([^<]*)<\/div>

I'm using the expression in the replace function like this:

html = html.replace( /<div><span>&middot;<span>[\s*]<\/span><\/span>([^<]*)<\/div>/gi,'<li>$1</li>') ;

the line of code I am changing is like this:

<div><span>&middot;<span> </span></span>Illness - where a pupil is too ill to leave the house</div>

eg it should strip out the code and leave <li>Illness - where a pupil is too ill to leave the house</li>

it works fine here http://www.regular-expressions.info/...ptexample.html
but when used with the replace command it does not?

Can anyone see the problem?

(I'm trying to convert bullet points from word)

Darren

Hi all,

As I scan each line of data that was entered into a textarea box, I need to call a function once I come across a line that starts with the following:

Code:

"0 B3C  0020365077 0045740301 3 09FEB2008 09MAR2010 " (without quotes)

I have created the following legend to help with the creating a regular expression that will validate when I have found a line that needs further processing:

N - number
L - letter
A - letter or number
S - space

So using the above legend, the first 51 characters of the line that I need to validate should always be in the following format:

Code:

"NSAAASSAAAAAAAAAASNNNNNNNNNNSASNNLLLNNNNSNNLLLNNNNS" (once again, without the quotes)

I have been reading a few articles on JavaScript regular expressions but am a bit lost at this point as how to start?

Hi i am using this form to validate my input
Code:

function validateForm() {
	var name = document.getElementById("name");
	var descp = document.getElementById("descp");
	var language = document.getElementById("language");
	var txtFileName = document.getElementById("txtFileName");
	var alphaNumExp = /^[a-zA-Z0-9 _-]+$/;
	var isValid = true;
	if ((name.value === "" || name.value.length < 1 || name.value.length > 30) && !name.value.match(alphaNumExp)) {
		isValid = false;
	}
	if ((descp.value === "" || descp.value.length < 1 || descp.value.length > 1000) && !descp.value.match(alphaNumExp)) {
		isValid = false;
	}
	if (language.value === "") {
		isValid = false;
	}
	if (txtFileName.value === "") {
		isValid = false;
	}
	
	document.getElementById("btnSubmit").disabled = !isValid;

}

for a form. It checks everything else correctly EXCEPT for the alpha numeric part. Any ideas?? I am new to JS writing on my own(just was using other's scripts)

I want a regular expression for Citi where first character should not be a blank space.

Thanks in advance

Me again, having some issues with the following code...

PHP Code:
if (str.match(regEx)) {
       alert("illegal character");
} 


regEx = /[^0-9a-zA-z]/g

I have tried typing in loads of strings, and nothing is causing the alert to work.

Edit: Fixed it, it seems the fix is:
regEx = [^0-9a-zA-z]

I thought you need the /. I also can't use any modifiers, although it works fine without them.