JavaScript - Firefox Not Detecting Enter/return

My problem is the following. I have an editable <div>:
<div class='edit' id='divContent' name='divContent' ContentEditable>some text</div>

If I press 'enter' two lines are skipped. I know that if I press 'shift+enter' only one line will be skipped. If I check the unformatted code of the contenteditable div, 'enter' gives me <p> and 'shift+enter' gives me <br>, which makes sense because <p> is formatted differently than <br>.

So I want to change 'enter' into 'shift+enter'

I have already found something to capture and kill 'return'
function killReturn()
{
key = event.keyCode;
if (key == 13) return false;
}

But now for some means to replace the killed 'enter' with 'shift+enter'?

Thanks a lot in advance for any advise!

This has me completely stumped. I have a multiple select form element in my HTML document that needs to be manipulated by two different sets of context-sensitive controls. One set of controls is marked up as follows:
Code:

<div id="divControls1" name="divControls1" style="display:none">
<form id="fControls1" name="fControls1">
  <input type="button" id="btnAdd" name="btnAdd" value="Add" onClick="addStuff();" />
  <input type="button" id="btnEdit" name="btnEdit" value="Edit" onClick="editStuff();" disabled />
  <input type="button" id="btnDelete" name="btnDelete" value="Delete" onClick="deleteStuff();" disabled />
</form>
</div>

When I load this page into Safari (on Mac OS X) and set the style of divControls1 to "display:block," I have an enabled "Add" button, a disabled "Edit" button, and a disabled "Delete" button, just as I expected. (I monitor selections in a multiple selection element to turn the buttons on and off.)

But when I load this page into Firefox (also Mac OS X), all three buttons are disabled at startup.

My page runs a function called startup() when the body fires onLoad. To try to troubleshoot the problem, I wrote this line at the beginning of the startup() function:
Code:

function startup() {
  alert (document.getElementById("btnAdd").disabled);
  ...

When I run this code in Safari, the alert returns "false" (not disabled), just as I would expect, and intended. However, the same code in Firefox (Mac OS X) returns "true" (disabled) ... but the same code in Firefox (WinXP) returns "false"!

Any insight into what might be happening here?

I don't understand the logic of Break, Return False, Return True. It was never really covered in our college class, and I see everyone using it. I got an A in the class, if that 'proves' that I really tried to apply myself.

NOTE: I understand what the function is doing. I just don't understand WHEN to use break, return false or return true if the the translator can determine the conditional statements.


PHP Code:
function submitForm(){
var ageSelected = false;

for (var i=0; i<5; ++1){
if (document.forms[0].ageGroup[i].checked == true) {
ageSelected = true;
break; 
  }
}

if (ageSelected == false){
window.alert("You must select your age group");
return false;
}

else
return false;
} 




if the the translator can determine the conditional statements, why not write it like this:

PHP Code:
function submitForm(){
var ageSelected = false;

for (var i=0; i<5; ++1){
if (document.forms[0].ageGroup[i].checked == true) {
ageSelected = true;
break; // what's the point for the 'break'? Won't the rest of the code be ignored since it passed the first condition?
  }
}

if (ageSelected == false){
window.alert("You must select your age group");
return false;
}
// why not leave the last else out? is it just a 'safety' catch, in case something other than true or false is inputted?
else
return false; // what's the point?
} 




Questions:
Why use return true, if the translator knows it's ture? Why use "return false" if the translator knows it's false and the alert window has already gone up? why not use "break" to stop the code? Why use the "return false" at the end "else" statement?

Hi room,

Hey, I opened up the source code for this page in google chrome and since i'm learning javascript, i wanted see if i could "read" it and figure out what was going on. I'm am having the hardest time understanding "return false" and "return true". Could someone step me through this via interpreting this code (in bold typeface):

Code:

	var DefaultValue = 'Search';						
	function clearSearch() {
	  if (document.searchForm.q.value == DefaultValue) {
		document.searchForm.q.value = '';
	  }
	}						
	function validateSearchHeader() {
		if ( document.searchForm.q.value == '' || document.searchForm.q.value.toLocaleLowerCase() == DefaultValue.toLocaleLowerCase() ) {
			alert('Please enter at least one keyword in the Search box.');
			document.searchForm.q.focus();
			return false;
		}
	  return true;
	}

Thanks!