PHP - Creating And Writing A File By Form

I'm trying to write to a file with the following code.

$fh = fopen("../inc/config.php", "a") or die("\r\nCan't open file.");
$write = "\$config['database_host'] = {$mysqlh};
\$config['database_user'] = {$mysqlu};
\$config['datbase_pass'] = {$mysqlp};
\$config['datbase_name'] = {$dbn};
\$config['table_prefix'] = {$tp};";

fwrite($fh, $write);
fclose($fh);


It is printing out "Can't open file", which I guess means it can't find the file or I've given the wrong path. The file that is executing this code is /install and the file I'm trying to write to is /inc/config.php. I thought .. put you up a directory so if I do .. I will be at the root and then do /inc I will be in inc.

Can someone please guide me on what I'm doing wrong?

Thanks.

I am using a script I adapted from a tutorial to print the contents of a text box to a txt file. Basically, it's a really simple way of seeing who has logged in. I only have a handful of users.

The problem is, although the text file is being created in the proper folder, it isn't being written to and just remains blank.

<div align="center">
<table width="300" border="2" bordercolor="#FFFFFF" style="-moz-border-radius: 18px;
-webkit-border-radius: 18px;" height="120" cellpadding="0" cellspacing="0">
<tr>
<form name="form1" method="post" action="checklogin.php">
<td>
<table width="100%" border="0" cellpadding="3" cellspacing="1" background="images/loginbg.jpg"  style="-moz-border-radius: 15px;
-webkit-border-radius: 15px;">
<tr align="center">
<td colspan="3"><font color="#FFFFFF"><strong>Family Login </strong></font></td>
</tr>
<tr>
<td width="78"><font color="#000000">Username</font></td>
<td width="6">:</td>
<td width="294"><input name="myusername" type="text" id="myusername">
<?php
$myusername = $_POST['myusername'];

$data = "$myusername\n";


//open the file and choose the mode
$fh = fopen("logs/login.txt", "a");

fwrite($fh, $data);

fclose($fh);

?></td>
</tr>
<tr>
<td><font color="#000000">Password</font></td>
<td>:</td>
<td><input name="mypassword" type="password" id="mypassword"></td>
</tr>
<tr>
<td>&nbsp;</td>
<td>&nbsp;</td>
<td><input type="submit" name="Submit" value="Login">
</td>
</tr>
</table>
</td>
</form>
</tr>
</table>
</div>

I'm not sure what's going wrong but I'm guessing it's the placing of the php, or at least some of it.
I'd quite like to add the time they logged in as well. Any idea's anyone? 

I have a code for writing a log file...
The code is working fine but it inserts the new details at the bottom of the file but i want to insert in the top...

So what function should i use... Here is the file my_log.php

Code: [Select]
<?php

$usname = $_SESSION['usname'];
date_default_timezone_set('Asia/Calcutta');
$date = date("l dS \of F Y h:i:s A");
$file = "log.php"; 
$open = fopen($file, "a+"); 
fseek($open,289);
fwrite($open "<b><br/>USER NAME:</b>              ".$usname . "<br/>"); 
fwrite($open, "<b>Date & Time:</b>            ".$date. "<br/>"); 
fwrite($open, "<b>What have they done :</b>   ".$reason . "<br/><br/>"); 
fclose($open); 

?>

and here is my log.php file :

Code: [Select]
<?php
session_start();
if($_SESSION['stage']!=1 || $_SESSION['stage2']!=2)
{header('location:index.php');
die(" ");
}
?>
<?php
if($_GET['valu']=="view_log")
{
$reason=" ".$_SESSION['usname']." Viewed the LOG";
include('my_log.php');
header('location:log.php');
die("");
}
// bytes till here are 289

//LINE 1 : Log details have to insert here



I want to insert every detail from the top of the page but just below the php code..
What should i do...

ANy helo would be appreciated

Pranshu Agrawal
pranshu.a.11@gmail.com

Greetings,   I am new to these forums, I am working on this assignment, and these are the current issues I am running into.   Notice: Undefined variable: year in G:\EasyPHP-5.3.2i\www\PHP_Projects\ChineseZodiacs\zodiac_year_switch.php on line 77 ie. $year = validateInput($year,"Birth Year"); Notice: Undefined variable: year_count in G:\EasyPHP-5.3.2i\www\PHP_Projects\ChineseZodiacs\zodiac_year_switch.php on line 138 ie. echo "<p>You are person " . $year_count . "to enter " . $year . "</p>\n";   Honestly, I believe they are linked, because what should be happening, as the user enters the year, and hits submit, it should create a file called counts/$year.txt - $year should equal the entered data in the textbox, any help would be appreciated.   Thank you for your help.

<!DOCTYPE html>
<head>
<title>Write to and From a File</title>
<meta http-equiv="content-type" content="text/html; charset=iso-8859-1" />

<?php

$dir = "counts";
if ( !file_exists($dir)) {
	mkdir ($dir, 0777);
	}

function validateInput($year, $fieldname) {
	global $errorCount;
	if (empty($year)) {
		echo "\"$fieldname\" is a required field.<br />\n";
		++$errorCount;
		$retval = "";
	}
	else
	{ // if the field on the form has been filled in
		if(is_numeric($year))
		{
			if($year >=1900 && $year <=2014)
			{
				$retval = $year;
			}
			else
			{
			++$errorCount;
			echo "<p>You must enter a year between 1900 and 2014.</p>\n";
			}
		}
		else
		{
			++$errorCount;
			echo "<p>The year must be a number.</p>\n";
		}
		
	} //ends the else for empty
	return($retval);
} //ends the function
function displayForm() {
?>
<form action = "<?php echo $_SERVER['SCRIPT_NAME']; ?>" method = "post"> 
<p>Year of Birth: <input type="text" name="year" /></p>
<p><input type="reset" value="Clear Form" />&nbsp; &nbsp;<input type="submit" name="submit" value="Show Me My Sign" /></p> 
</form>
<?php
}

function StatisticsForYear($year) {
		global $year_count;
	$counter_file = "counts/$year.txt";
	if (file_exists($counter_file)) {
		$year_count = file_get_contents($counter_file);
		file_put_contents($counter_file, ++$year_count);
	} else {
		$year_count = 1;
		file_put_contents($counter_file, $year_count);
	}
return ($year_count);
}?>	
	
</head>
<body>
<?php

$showForm = true;
$errorCount = 0;
//$year=$_POST['year'];

$zodiac="";
$start_year =1900;
if (isset($_POST['submit'])) 
	$year = $_POST['year'];
	$year = validateInput($year,"Birth Year");

	if ($errorCount==0)
		$showForm = false;
	else
		$showForm = true;

if ($showForm == true)
{
		//call the displayForm() function
		displayForm();
}
else
{ //begins the else statement
	//determine the zodiac
	 
	$zodiacArray = array("rat", "ox", "tiger", "rabbit", "dragon", "snake", "horse", "goat", "monkey", "rooster", "dog", "pig");
	
	 switch (($_POST['year'] - $start_year) % 6) {
	case 0:
			$zodiac = $zodiacArray[0];
	break;		
	case 1:
			$zodiac = $zodiacArray[1];
	break;		
	case 2:
			$zodiac = $zodiacArray[2];
	break;		
	case 3:
			$zodiac = $zodiacArray[3];
	break;		
	case 4:
			$zodiac = $zodiacArray[4];
	break;		
	case 5:
			$zodiac = $zodiacArray[5];
	break;		
	case 6:
			$zodiac = $zodiacArray[6];
	break;		
	case 7:
			$zodiac = $zodiacArray[7];
	break;		
	case 8:
			$zodiac = $zodiacArray[8];
	break;		
	case 9:
			$zodiac = $zodiacArray[9];
	break;		
	case 10:
			$zodiac = $zodiacArray[10];
	break;		
	case 11:
			$zodiac = $zodiacArray[11];
	break;
	default:
		echo "<p>The Zodiac for this year has not been determined.</p>\n";
	break;
	} //ends the switch statement

	echo "<p>You were born under the sign of the " . $zodiac . ".</p>\n";
	echo "<p>You are person " . $year_count . "to enter " . $year . "</p>\n";
} //ends the else statement	
	
?>
</body>
</html>

Edited by mstevens, 16 October 2014 - 06:36 PM.

Hey Guys. I am trying to write to the file depending on which condition is met. The code works fine on my local machiene but not on my remote server.
  I have also tried to output any error messages to see if it would output anything, and I don't get anyting on my browser. Can anyone help me with this issue? Thanks

<?php
if($_SERVER['REQUEST_METHOD'] == "POST") {


isset($_POST['interfax']) ? $option= "interfax" : $option= "";
isset($_POST['metrofax']) ? $option= "metrofax" : $option= "";


switch ($option) {
	case 'interfax':
	$file = "fax.php";
	$fax_client = "interfax";
	if(file_put_contents($file, "<?php ".'$fax_client = "' . $fax_client . '"'." ?>"))
	{ echo "Successful"; } else {
			die("Can't write file");
		}
		break;
	
		


    // By defualt all the orders go to metrofax so by selecting the variable it resets it self 
	case 'metrofax':
	$file = "fax.php";
	$fax_client = "metrofax";
	file_put_contents($file, "<?php ".'$fax_client = "' . NULL . '"'." ?>");
		break;	

			}


		}
?>


<form action="#" method="POST"> 

 <input type="radio" name="interfax" value="interfax">Switch To Interfax<br>
<input type="radio" name="metrofax" value="metrofax">Switch To Metrofax<br>

<input type='submit' name="submit" >

Ok, I know how to write to a file, but what I'm looking for is to check if a line of code exists, and if it is, don't recreate it. It would also be nice to not recreate the file either.

Code: [Select]
$file = fopen("index.html", "w");
fwrite($file,"This is a line of text");
fclose($file);

I need help! I cant get this to write the correct way!

What i need is based on the value of what is posted to the script it has to write it in the config file and also make a folder!

Please help


Code: [Select]
<?php
$start = '$uploadpath=\'';
$structure = '../banner/images/'.$_POST['FOLDER'].'\';\n';

$myFile = "PHP/confup.php";
$fh = fopen($myFile, 'w') or die("can't open file");
$stringData = "<?\n";
fwrite($fh, $stringData);
$stringData = "$start $structure";
fwrite($fh, $stringData);
$stringData = "?>\n";
fwrite($fh, $stringData);
fclose($fh);

// Desired folder structure


// To create the nested structure, the $recursive parameter
// to mkdir() must be specified.

if (!mkdir($structure, 0777, true)) {
    die('Failed to create folders...');
}

// ...
?>

Is it possible to write to an exact line and column of a text file with PHP like with fwrite or something?

for($i=0; $i!=count($account_data); $i++){
  echo "\n::: ".strtoupper($account_data[$i][0])." :::\n";
  if($account_data[$i][1] != "" && stristr($account_data[$i][0], "@") && stristr($account_data[$i][0], ".")){
    list($place[0],$place[1],$place[2],$place[3]) = authorize($account_data[$i], $game_link);
    if($place[2] > 1 && strlen($place[3]) == 40){
  $filename = 'auth-keys.txt';
  $fp = file($filename,'a+');
  $data = $place[2]." ".$place[3]."\r\n";
  file_put_contents($filename, $data, FILE_APPEND);
  echo $data;    
  }
    else echo "Account Skipped: wrong password/email combo, or a login error...\n";
$echo = file_put_contents($filename, FILE_APPEND);
  }
  else echo "Account Skipped: invalid email or blank password...\n";
}
echo "\n::: PROGRAM FINISHED, YOU CAN CLOSE THIS AT ANY TIME :::";
sleep(10000);

You see where I tried to put $echo file_put_contents etc...

On success the acct writes a security id and a security auth key to a file, ever acct puts the tokens on a new line every acct... now when an acct echos account skipped, how can I make it print the echo on the file new line instead of nothing being writen and it just skipping the account

I have a file named example.xml

I want to know how to write to the 3rd line on this file? What function to use?

I want to be able to write to this xml file right after the <sitemapindex xmlns="http://www.sitemaps.org/schemas/sitemap/0.9"> tag.

Please someone tell me how?

Much appreciated.

Code: [Select]

<?xml version="1.0" encoding="UTF-8"?>
<sitemapindex xmlns="http://www.sitemaps.org/schemas/sitemap/0.9">
   <sitemap>
      <loc>http://www.example.com/sitemap1.xml.gz</loc>
      <lastmod>2004-10-01T18:23:17+00:00</lastmod>
   </sitemap>
   <sitemap>
      <loc>http://www.example.com/sitemap2.xml.gz</loc>
      <lastmod>2005-01-01</lastmod>
   </sitemap>
</sitemapindex>

<?php
$file = 'test.txt';
$lastfm = file_get_contents('http://www.last.fm/group/Rishloo/members');
preg_match_all('/id="r4_([\d]+)">/', $lastfm, $matches);
file_put_contents($file, $matches[1]);


sleep(100000);

?>



That puts the array in a file but I need each value on a new line but it bunches it all up..

this just puts "Array" in file

[php]

<?php
$file = 'test.txt';
$lastfm = file_get_contents('http://www.last.fm/group/Rishloo/members');
preg_match_all('/id="r4_([\d]+)">/', $lastfm, $matches);
file_put_contents($file, $matches[1]."\n");


sleep(100000);

?>

what do I need to do to print all of the values on a new line?

Thanks

Hello

I am in need of writting to a txt file on a remote server. When trying  I get this error:

"failed to open stream: HTTP wrapper does not support writeable connections in /home....."

How can I write to a siply txt file on a remote server?

Hi, I am a newbie to php and am trying to copy mysql data to a text file. The format I need to create is

I just wrote a php page that pulls live data from a database and presents it in an XML layout.

In Internet Explorer, I can Edit, Select All, then Copy-Paste and save as XML. The resulting XML works fine.

In Firefox, I can click File, Save Page As, select Text Files, then name it as an XML. Again, it works fine as XML.

So..... how do I skip the Copy/Paste (IE) or Save Page As (Firefox) steps and write the output directly to an XML file? I've played with stdout(), buffers, page capturing utilities (wget, cURL, httrack, etc....), but no luck so far. This creates a pretty intense page due to the amount of data involved (1.3+ MB).

Any help is appreciated!


 

i have this script where the user enters their name and their favorite quotes.  It adds their favorite quotes and their names to quotes.txt and prints out their name and their quotes on view_quote.php.  I need to use a foreach() loop to print out the name and the quotes, but I'm confused about how to set it up. Here's my files.
add_quote.php
Code: [Select]
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Add A Quotation</title>
</head>
<body>
<?php // add_quote.php
/* This script displays and handles an HTML form. This script takes text input and stores it in a text file. */

// Identify the file to use:
$file = 'quotes.txt';

// Check for a form submission:
if ($_SERVER['REQUEST_METHOD'] == 'POST') { // Handle the form.

if ( !empty($_POST['quote']) && ($_POST['quote'] != 'Enter your quotation here.'
 ) ){ // Need some thing to write.

if (is_writable($file)) { // Confirm that the file is writable.

file_put_contents($file, $_POST['quote'] . PHP_EOL, FILE_APPEND | LOCK_EX); // Write the data.
file_put_contents($file, $_POST['name'] . PHP_EOL, FILE_APPEND | LOCK_EX);
// Print a message:
print '<p>Your quotation has been stored.</p>';

} else { // Could not open the file.
print '<p style="color: red;">Your quotation could not be stored due to a system error.</p>';
}

} else { // Failed to enter a quotation.
print '<p style="color: red;">Please enter a quotation!</p>';
}

} // End of submitted IF.

// Leave PHP and display the form:
?>

<form action="add_quote.php" method="post">
<p>Name:<input type="text" name="name"/><br />
<textarea name="quote" rows="5" cols="30">Enter your quotation here.</textarea><br />
<input type="submit" name="submit" value="Add This Quote!" />
</form>

</body>
</html>view_quote.php
Code: [Select]
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>View A Quotation</title>
</head>
<body>
<h1>View My Quotes</h1>
<?php // view_quote.php
/* This script displays and handles an HTML form. This script reads in a file and prints a random line from it. */

// Read the file's contents into an array:
$data = file('quotes.txt');

// Count the number of items in the array:
$n = count($data);

// Pick a random item:
$rand = rand(0, ($n - 1));

// Print the quotation:
print '<p>' . trim($data[$rand]) . '</p>';


?>
</body>
</html>and the quotes.txt file is blank until the user enters their names and quotes.  Im trying to get this done kind of quick so any help would be awesome.