PHP - Moved: Xammp Default Locahost?

Hi. I have drop down boxes for date and time that work. The year is a problem because I am using variables instead of fixed values.

Code: [Select]
<select name="Year" style="width:60px">
<option value="2010" >Test
<option value="<?=$ThisYear?>" <? if ($Year == "<?=$ThisYear?>"){?> SELECTED <?}?> ><?=$ThisYear?>
<option value="<?=$NextYear?>" <? if ($Year == "<?=$NextYear?>"){?> SELECTED <?}?> ><?=$NextYear?>
</select>

<select name="Hour" style="width:50px">
<option value="10" <? if ($_SESSION["Hour"] == "10"){?> SELECTED <?}?> >10
<option value="11" <? if ($_SESSION["Hour"] == "11"){?> SELECTED <?}?> >11
<option value="12" <? if ($_SESSION["Hour"] == "12"){?> SELECTED <?}?> >12
<option value="13" <? if ($_SESSION["Hour"] == "13"){?> SELECTED <?}?> >13
<option value="14" <? if ($_SESSION["Hour"] == "14"){?> SELECTED <?}?> >14
<option value="15" <? if ($_SESSION["Hour"] == "15"){?> SELECTED <?}?> >15
<option value="16" <? if ($_SESSION["Hour"] == "16"){?> SELECTED <?}?> >16
<option value="17" <? if ($_SESSION["Hour"] == "17"){?> SELECTED <?}?> >17
<option value="18" <? if ($_SESSION["Hour"] == "18"){?> SELECTED <?}?> >18
<option value="19" <? if ($_SESSION["Hour"] == "19"){?> SELECTED <?}?> >19
<option value="20" <? if ($_SESSION["Hour"] == "20"){?> SELECTED <?}?> >20
</select>

however this works

Code: [Select]
<select name="Year" style="width:60px">
<option value="2010" >Test
<option value="<?=$ThisYear?>" <? if ($Year == "2011"){?> SELECTED <?}?> ><?=$ThisYear?>
<option value="<?=$NextYear?>" <? if ($Year == "2012"){?> SELECTED <?}?> ><?=$NextYear?>
</select>

Can anyone help with this please
TIA

Desmond.
   

How to define default folder. For example I have folder images and in that folder specific image. In the root directory I have index.php with
Code: [Select]
<?php require_once("public/includes/header.php"); ?>and in index.php there are links which goes to different folder:
  Code: [Select]
<a href="public/sajt/kategorija.php?id=<?php echo $id;  ?>">which also have header.php, but there is no image. How to make default folder for image, or some similar solution?

How do I set the date format so that it's always going by the UTC date?

I've used:
Code: [Select]
date_default_timezone_set('UTC');
but, when I change my date on my computer, the date changes on the website.

This is really confusing me, googled different ways for like 10/20 minutes and can't find anything.

If anyone can help it'd be great,

Thanks,
Andy.

I am using this php code <?php echo $_GET['CiFrame']; ?> to check the url for the variable CiFrame, this allows me to link to a page through my page containing the iframe.

Here is my iframe code.
<iframe name="CiFrame" width="727" height="805" src="<?php echo $_GET['CiFrame']; ?>" scrolling="auto" frameborder="0"></iframe>

The problem is that if the url does not contain a variable the iframe will not open a page. How can i set a default variable if one is not provided?

Thank You

I have a few dropdown forums and would like it to select the current values that are requested.

Code: [Select]
global $filename,$fileid,$filetype,$filedir,$fileby;
  global $months,$pg;


echo "<h2>Search Files</h2>";
echo "<p>";
  echo "<form name = 'File_Search' action = '#' method = 'POST'>";
echo "<table border=\"0\" width=\"100%\"><tr>";
echo "<td>File Name<br><input type = 'text' name = 'name'></td><td>File Type<br><select name = 'type'>
<option value = '0'>All Types</option>
  <option value = 'o'>Official Files</option>
<option value = '1'>Quests</option>
  <option value = '2'>Graphic/Spritesheets</option>
  <option value = '3'>Entity/Scripts</option>
  <option value = '4'>Sound/Music</option>
  <option value = '5'>QuestPack/Programs</option>
  <option value = '6'>Miscellaneous</option>
  </select></td>";
  echo "<td>Order By<br><select name = 'order'>
  <option value = '0'>Last Updated</option>
  <option value = '1'>ID</option>
  <option value = '2'>Name</option>
  <option value = '3'>Downloads</option>
  <option value = '4'>Rating</option>
<option value = '5'>Points</option>
  <option value = '6'>Random</option>
  </select></td>";
  echo "<td>Acending?<br><select name = 'dir'><option value = '0'>False</option><option selected value = '1'>True</option></select></td>";
echo "</tr><tr><td rowspan = '4'><input type = 'submit' name = 'search' value = 'search'></td></tr></table></form>";
echo "</p>";

So if the $filetype equals 2 I want the dropdown box to show "Graphic/Spritesheets" by default. BTW Official Files is not actually a type so that's why I chose to give it a small letter o and will work the same way as All Types but run a different function.

$fileby is used for the OrderBy field.
$filedir is for the Acending field.
The other data is for the other parts of the script.

If you like you can give advice on the name's default because you may have a better method then what I have in my head.

Hi, I am trying to get the date and time that a particular table was last updated, which the code below does, but it doesn't seem to be putting it in the correct timezone, it is 5 hours behind, anyone know why this is? or how i can fix it? Thanks

Code: [Select]
<?php
date_default_timezone_set('Europe/London');
        $query = "SELECT UPDATE_TIME FROM information_schema.tables WHERE TABLE_SCHEMA = 'tffdb' AND TABLE_NAME = 'test_team_points'";
        $result = mysql_query($query) or die(mysql_error());
        
        $row = mysql_fetch_assoc($result);
echo $row['UPDATE_TIME'];

?>

In a Switch statement, can you give the Default: a specific name, maybe like this...


switch ($resultsCode){
// Missing Primary Key.
case 'COMMENT_MISSING_KEYS_2050':
echo '<h1>System Error</h1>';
echo '<p>A Fatal Error has occurred.  Please contact the System Administrator. (2050)</p>';
break;

default 'DEFAULT_CATCHALL_ERROR_CODE_9999':
echo '<p>You have reached the catch-all error code... (9999)</p>';
break;



Debbie

Hi guys and gals ,

got a minor problem.  I have a table in which i want the "photo" column to have a default value of "noimage.jpg".

I set the default value to "noimage.jpg" and put "as defined" too.

but when i fill the form in and leave the upload field blank it doesnt show the noimage.jpg as it should and in the mysql table it leaves it blank and not with default value.

Here is the inserts.php which adds the data to the mysql table.   

Can you help please.

<CENTER><B>Vehicle Added</B></CENTER>
<BR>

<?php

mysql_connect("localhost", "wormste1_barry", "barry") or die(mysql_error());
mysql_select_db("wormste1_barry") or die(mysql_error());

$CarName = mysql_real_escape_string(trim($_POST['CarName']));
$CarTitle = mysql_real_escape_string(trim($_POST['CarTitle']));
$CarPrice = mysql_real_escape_string(trim($_POST['CarPrice']));
$CarMiles = mysql_real_escape_string(trim($_POST['CarMiles']));
$CarDescription = mysql_real_escape_string(trim($_POST['CarDescription']));
$pic = mysql_real_escape_string(trim($_FILES['uploadedfile']['name'])); 


$target_path = "images/";

$target_path = $target_path . basename( $_FILES['uploadedfile']['name']); 

if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
    echo "The file ".  basename( $_FILES['uploadedfile']['name']). 
    " has been uploaded";
    echo "<br />";
} else{
    echo "There was an error uploading the file, please try again!";
}



mysql_query("INSERT INTO cars 
(CarName, CarTitle, CarPrice, CarMiles, CarDescription, photo) VALUES('$CarName', '$CarTitle', '$CarPrice', '$CarMiles', '$CarDescription', '$pic' ) ") 
or die(mysql_error());  


echo "The vehicle data has been added!";

?>

I have this code, for an Upload Form, that works successfully renaming and moving an uploaded file to the upload/ folder. 

I am loading a link with ajax. When the link pops on the screen and I click it, I get redirected to my 404 page and my lightbox doesn't load.

If the link pops in and I refresh my browser, then I click the link my lightbox will show up.

How can I do a prevent default on the <a href> in pure JS? No frameworks please.

My 1st try practice uploading file to the server and it was successful.

Now I wonder how can I set a default file name to the file that will be uploaded and overwrite the existing one.

I have tried experimenting on the code but I can't get it to work.


Here's my simple code..

edit_logo.php

Code: [Select]
<?php

<form enctype="multipart/form-data" method="post"  action="uploaded_logo.php">

<input type="hidden" name="MAX_FILE_SIZE" value="100000" />

<tr>
<td>Choose a Logo to Upload: </td>
    <td><input name="uploaded_file" type="file" /></td>
</tr>

<tr>
<td>&nbsp;</td>
    <td><input type="submit" value="Upload File" name="submit>"</td>
</tr>




</form>

?>

uploaded_logo.php
Code: [Select]
<?php

if($_FILES['uploaded_file']["type"] == "image/gif")
{

$target_path = "logo/";

$target_path = $target_path. basename($_FILES['uploaded_file']['name']);



if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $target_path))
{
echo "<span class=\"error_validation\">The Logo has been successfully changed!<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}
else
{
echo "<span class=\"error_validation\">There was an error uploading the logo. Pls. try again.<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}

}
else
{
echo "<span class=\"error_validation\">Invalid file format. We are only accepting image file. Pls. try again.<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}


?>

So what the code suppose to do is.. If I upload an image file as the new logo it should have the default logo name "my_logo.gif", then it will overwrite the existing one...

Anyone?

Hi all,

I have this script below where I am trying to display a default image if an image can not be found.

For some reason though it is not working.


<?php 
foreach (glob('./aircraft/' . $rowX['reg'] . '[0-8].jpg') as $file)
{
   if (file_exists($file)) {
 echo "<img src=\"" . $file . "\"  /><br />";
}
else { echo "><img src=\"aircraft/wrightflyer.jpg\" /><br />";}
}
?>

ok this grabs mp3 from 4shared but the download link appears as preview.mp3

how could i get it to be renamed as the original reach name like here_without_you.p3 or something else?

Code: [Select]
<?php

$file = file_get_contents("http://www.4shared.com/audio/PmMMpPFs/here_without_you.htm"); 
$body = preg_replace("/.*file[^=]*=|\&volume.*/si", "", $file);  
preg_match("/((ftp)|(http(s?))\:\/\/(([A-z0-9\?\-\:\=\;\.\@\/]+)))/is",$body, $result);  
$download_url = $result[1];  

print_r($download_url);
?>

Hi guys,

Before we go further, yes, I know I should use prepared statements. This is just a project that will probably never go live. If I do decide to go live, I will change to prepared statements.

Anyways, I am populating a text box from the selection of an options dropdown and updating MySQL. This all works fine. However, what I want to do is have the newly inserted option display by default in the dropdown. Hope this makes sense.

Here is the dropdown code with the select statement...

                         <div class="row form-group">
                          <div class="col-6">
                        <div class="form-group"><label for="location" class=" form-control-label">location</label>
<?php
$sql = "SELECT location_name, location_phone FROM locations";
$result = $con->query($sql);
?>

 <select name="location" id="location" onchange="myFunction()" class="form-control">
<?php

        while($r = mysqli_fetch_row($result))
{
        echo "<option data-location_name='$r[1]'  data-location_phone='$r[2]'  value='$r[0]'> $r[0] </option>";
}
?>

</select>
<label>Phone</label><input type="text" class="form-control" name="location_phone" id="location_name" value = "<?php echo $row['location_phone']; ?>"/>

I am grabbing the location name and phone number from locations. Then inserting them into tours. So after the form is submitted, I want the location name to stay in the dropdown. This is in the table "tours". How do I implement that in here?

Thanks heaps.

having a problem figuring out how to change the default on a drop down box to equal the users current timezone. So when they view it the drop box default is showing what their setting is atm. The problem is the value is differant from whats displayed. Is it possible to some how say if users time offset is equal to a option value set selected=""> to yes.

if not what is the idea behind this? Cant find a guide showing an example
In other drop down boxes where the value is the same as whats displayed I just simply created another value field at the top of the list and echo it in.
Code: [Select]
<select name="gmt">

<option value="-28800">(GMT -0800) Pacific Time </option>
<option value="-25200">(GMT -0700) Mountain Time </option>
<option value="-21600">(GMT -0600) Central Time</option>
<option value="-18000">(GMT -0500) Eastern Time </option>

</select>