PHP - Count Mysql Tables And Rows[need Some Help]
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1 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 [20] [21] 22 23 24 25 [26] 27 28 29 30 31 2 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 3 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 4 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 5 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 6 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 7 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 8 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 9 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 10 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 11 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 12 puudu 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 ; i need help .. with calculating how many days are between example: january = 1 ; day =23 to feb =2; day 23 in php ... how can i do that Similar TutorialsThe following works, but I don't want to have to write 50 query statements for 50 states. How can I just write one query (using a variable I presume) and then echo the variable count each time for each state? I'm just trying to list the total number of rows for each state, that exist in the db. <? $result = mysql_query("SELECT * FROM mytable WHERE source = 'alabama'") or die(mysql_error()); $num_rows = mysql_num_rows($result); ?> href="/state/alabama/">alabama</a> (<?php echo("$num_rows");?>) <br> <? $result = mysql_query("SELECT * FROM mytable WHERE source = 'alaska'") or die(mysql_error()); $num_rows = mysql_num_rows($result); ?> href="/state/alaska/">alaska</a> (<?php echo("$num_rows");?>) <br> The above would give output such as: alabama (122) alaska (212) I insert data in mysql table row using multiple method : 1#2#3 . 1 is ID of country, 2 is Id of state, 3 is ID of town . now i have this table for real estate listings. for each list(home) i have country/state/town (1#2#3). in country table i have list of country - in country table i have list of state - in country table i have list of town. i need to The number of houses in country / state / town . my mean is : Code: [Select] USA [ 13 ] <!-- This Is equal of alabama+alaska+arizona --> ----Alabama [8] <!-- This Is equal of Adamsville+Addison+Akron --> -------Adamsville [2] -------Addison[5] -------Akron[1] ......(list of other City) ----Alaska [ 3 ] -------Avondale[3] ......(list of other City) ----Arizona [ 2 ] -------College[2] ......(list of other City) Lisintg Table : Code: [Select] ID -- NAME -- LOCATION -- DATEJOIN -- ACTIVE 1 -- TEST -- 1#2#3 -- 20110101 -- 1 2 -- TEST1 -- 1#2#3 -- 20110101 -- 1 3 -- TEST2 -- 1#3#5 -- 20110101 -- 1 4 -- TEST3 -- 1#7#6 -- 20110101 -- 1 Country Table : Code: [Select] id -- name 1 -- USA stats Table : Code: [Select] id -- countryid -- name 1 -- 1 -- albama 2 -- 1 -- alaska 3 -- 1 -- akron town Table : Code: [Select] id -- countryid -- statsid -- name 1 -- 1 -- 1 -- adamsville 2 -- 1 -- 1 -- addison 3 -- 1 -- 1 -- akron Thanks For Any Help. I'm trying to pull user referral data from my database. This is what I have so far. <table cellpadding="0" cellspacing="0" style="border:1px #000000 solid;" width="68%"> <tr> <td bgcolor="#eeeeee" style="padding:2px;border-right:1px #000 solid;border-bottom:1px #000 solid;"><font size="2" face="verdana"><b> User </b></font></td> <td bgcolor="#eeeeee" style="padding:2px;border-right:1px #000 solid;border-bottom:1px #000 solid;"><font size="2" face="verdana"><b> </b></font></td> <td bgcolor="#eeeeee" style="padding:2px;border-right:1px #000 solid;border-bottom:1px #000 solid;"><font size="2" face="verdana"><b> Date </b></font></td> <td bgcolor="#eeeeee" style="padding:2px;border-bottom:1px #000 solid;"><font size="2" face="verdana"><b> Visits </b></font></td> </tr> <? $lole=$_COOKIE["usNick"]; $tabla = mysql_query("SELECT * FROM tb_users where username='$lole' ORDER BY id ASC"); while ($row = mysql_fetch_array($tabla)) { echo "<tr><td><font size=\"2\" face=\"verdana\">"; echo $row["username"]; echo "</font></td><td><font size=\"2\" face=\"verdana\">"; echo $row["email"]; echo "</font></td><td><font size=\"2\" face=\"verdana\">"; echo $row["joindate"]; echo "</font></td><td><font size=\"2\" face=\"verdana\">"; echo $row["visits"]; echo "</font></td></tr>"; } echo "</table>"; ?> <script type="text/javascript"> initSortTable('myTable',Array('S','N','S','N','S')); </script> I just found out my user ID is missing from database.. hello all, i want to display each row from mysql table in a different page using this code: Code: [Select] <? require_once('config.php'); //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die("can't connect: " . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("can't select database"); } mysql_query("SET NAMES 'hebrew'"); //mysql_set_charset('utf8',$link); if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; }; $start_from = $page-1; $qry='SELECT * FROM ordering limit 0, 1'; $result = mysql_query($qry); while($row = mysql_fetch_array($result)){ echo "<div dir='rtl' charset='utf8'><h2>"," hover cam: ",$row['hover_camera'], "<br> stills: ",$row['stills'], "<br> video_photographers: ",$row['video_photographers'], "<br> increase: ",$row['increase'], "<br> video_edit: ",$row['video_edit'], "<br> digital_album: ",$row['digital_album'], "<br> photo_album: ",$row['photo_album'], "<br> small_digital_album: ",$row['small_digital_album'], "<br> video_clip: ",$row['video_clip'], "<br> magnets: ",$row['magnets'], "<br> comments: ",$row['comments'], "<br> date: ",$row['date'], "<br><br></h2></div>"; } $sql = "SELECT COUNT(userid) FROM ordering"; $result = mysql_query($sql,$link); $row2 = mysql_fetch_row($result); $total_records = $row2[0]; $total_pages = $total_records ; for ($i=1; $i<=$total_pages; $i++) { echo "<a href='table.php?page=".$i."'>".$i."</a> "; }; ?> this is the table: Code: [Select] CREATE TABLE IF NOT EXISTS `ordering` ( `userid` int(11) unsigned NOT NULL AUTO_INCREMENT, `hover_camera` varchar(10) DEFAULT NULL, `stills` int(5) NOT NULL, `video_photographers` int(5) NOT NULL, `increase` int(5) NOT NULL, `video_edit` varchar(10) NOT NULL, `digital_album` varchar(10) DEFAULT NULL, `photo_album` varchar(10) DEFAULT NULL, `small_digital_album` varchar(20) DEFAULT NULL, `video_clip` varchar(10) DEFAULT NULL, `magnets` int(10) NOT NULL, `comments` text NOT NULL, `date` date NOT NULL, PRIMARY KEY (`userid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 ; the problem is that only the first row is displayed no matter which page i choose and i want each page to display the row assigned to it (page 15 = row 15 etc...) any suggestions? hello i have a mysql table and i want to display each row in a different page with an added condition, the code: Code: [Select] if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; }; $start_from = $page-1; $qry="SELECT * FROM ordering WHERE userid='$page' AND email='$email' LIMIT 0,1"; $result = mysql_query($qry); while($row = mysql_fetch_array($result)){ echo "<div dir='rtl' charset='utf8'><h2>"," hover cam: ",$row['hover_camera'], "<br> stills: ",$row['stills'], "<br> video_photographers: ",$row['video_photographers'], "<br> increase: ",$row['increase'], "<br> video_edit: ",$row['video_edit'], "<br> digital_album: ",$row['digital_album'], "<br> photo_album: ",$row['photo_album'], "<br> small_digital_album: ",$row['small_digital_album'], "<br> video_clip: ",$row['video_clip'], "<br> magnets: ",$row['magnets'], "<br> comments: ",$row['comments'], "<br> date: ",$row['date'], "<br><br></h2></div>"; } $sql = "SELECT COUNT(userid) FROM ordering"; $result = mysql_query($sql,$link); $row2 = mysql_fetch_row($result); $total_records = $row2[0]; $total_pages = $total_records ; for ($i=1; $i<=$total_pages; $i++) { echo "<a href='myorders.php?page=".$i."'>".$i."</a> "; }; the table is as so: Code: [Select] CREATE TABLE IF NOT EXISTS `ordering` ( `userid` int(11) unsigned NOT NULL AUTO_INCREMENT, `hover_camera` varchar(10) DEFAULT NULL, `stills` int(5) NOT NULL, `video_photographers` int(5) NOT NULL, `increase` int(5) NOT NULL, `video_edit` varchar(10) NOT NULL, `digital_album` varchar(10) DEFAULT NULL, `photo_album` varchar(10) DEFAULT NULL, `small_digital_album` varchar(20) DEFAULT NULL, `video_clip` varchar(10) DEFAULT NULL, `magnets` int(10) NOT NULL, `comments` text NOT NULL, `date` date NOT NULL, `fname` varchar(100) NOT NULL, `email` varchar(100) NOT NULL, PRIMARY KEY (`userid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; now to the problem: this code displays all the userid as page numbers however, the email condition is good only for part of the rows it's a little hard to explain, i'll try an example: suppose the email '1@1.com' is at rows 22,25 and 30 my code displays 30 page numbers and page 22 is user 22, page 25 is user 25 etc. what i want is to display only the page numbers of the pages with the conditional email, and if possible to display them as 1,2,3 instead of 22,25,30 Hi guys, I need your help. I am trying to insert the rows in the mysql database as I input the values in the url bar which it would be like this: Code: [Select] www.mysite.com/testupdate.php?user=tester&pass=test&user1=tester&email=me@shitmail.com&ip=myisp However i have got a error which i don't know how to fix it. Error: Column count doesn't match value count at row 1 <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbusername'); define('DB_PASSWORD', 'mydbpassword'); define('DB_DATABASE', 'mydbname'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $username = clean($_GET['user']); $password = clean($_GET['pass']); $adduser = clean($_GET['user1']); $email = clean($_GET['email']); $IP = clean($_GET['ip']); if($username == '') { $errmsg_arr[] = 'username is missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'PASSWORD is missing'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $sql = "INSERT INTO `members` (`username`,`email`,`IP`) VALUES ('$adduser','$email','$IP')"; if (!mysql_query($sql,$link)) { die('Error: ' . mysql_error()); } echo "The information have been updated."; } ?> Here's the name of the columns i have got in my database: Code: [Select] username IP I have input the correct columns names, so I can't correct the problem I am getting. Please can you help? Hi guys, I want to count the number of rows in a table and want to display them. However that field stays empty. Everythign else works. What do I do wrong? Code: [Select] <?php //$sql="SELECT * FROM $tbl_name ORDER BY user_id"; $sql="SELECT * from sp_users,sp_schools where sp_users.user_id=sp_schools.school_id"; $result=mysql_query($sql); $num_rows=mysql_num_rows($result); ?> <style type="text/css"> <!-- .style2 {font-weight: bold} .style3 { font-family: Arial, Helvetica, sans-serif; color: #000000; } .style10 {font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 10px; color: #000000; } --> </style> <title>User overview</title><table width="779" border="0" align="left" cellpadding="0" cellspacing="1" bgcolor="#996600"> <tr> <td width="777"> <div align="left"> <table width="779" border="1" cellspacing="0" cellpadding="3"> <tr> <td colspan="6" align="center"><div align="center" class="style1 style3"><strong>SchoolPorta.com Users </strong></div></td> </tr> <tr> <td width="25" align="center"><span class="style2">No.</span></td> <td width="62" align="center"><span class="style2">Name</span></td> <td width="104" align="center"><span class="style2">Lastname</span></td> <td width="130" align="center"><span class="style2">Email</span></td> <td width="342" align="center"><span class="style2">school</span></td> <td width="64" align="center"><span class="style2">Update</span></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td><span class="style10"><? echo $rows['num_rows']; ?></span></td> <td><span class="style10"><? echo $rows['user_first_name']; ?></span></td> <td><span class="style10"><? echo $rows['user_surname']; ?></span></td> <td><span class="style10"><a href="mailto:<?php echo $rows['user_login']; ?>"><?php echo $rows['user_login']; ?></a></span></td> <td><span class="style10"><? echo $rows['school_name']; ?></span></td> <td align="center"><a href="update.php?id=<? echo $rows['user_id']; ?>" class="style10">update</a></td> </tr> <?php } ?> Can any one tell me whats the best ( actually error free ) which i can use to count the number of rows finally resulting after select command. I use this ... Code: [Select] $sql = mysql_query("select * from usname where name1='$name1' and name2='$name2' and amm='$amm'"); $num=mysql_num_rows($sql); echo $num; But it always gives the same error.... and the error is.......... Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\money\insert.php on line 20 where line 20 is... Code: [Select] $num=mysql_num_rows($sql); - Pranshu Agrawal pranshu.a.11@gmail.com Hi I'm not at all good at PHP and haven't really played with it for some years, so bare with me if code examples are old I'm looking for a simple solution to count rows (MySQL), without using multiple queries. The below code is quite simple, counting rows where 'Department' is 'Sales': $sql ="SELECT * FROM DB WHERE Department ='Sales'"; $result=mysqli_query($con,$sql); $rowcount=mysqli_num_rows($result); But what If I need to count the rows for the different departments?: $sql ="SELECT * FROM DB WHERE Department ='Sales'"; $result=mysqli_query($con,$sql); $rowcount=mysqli_num_rows($result); $sql ="SELECT * FROM DB WHERE Department ='Support'"; $result=mysqli_query($con,$sql); $rowcount=mysqli_num_rows($result); $sql ="SELECT * FROM DB WHERE Department ='Online'"; $result=mysqli_query($con,$sql); $rowcount=mysqli_num_rows($result); There must be a better / simpler way to this with a single query? Hope for someone to show me the light
PS. Once this is resolved, I'll probably need further help, to accomplish my final result. Hi. I having trouble with counting rows in phpmyadmin. It works fine this way: Code: [Select] $result_rows = mysql_query("SELECT * FROM events"); But when i modify the code to this it doesnt work at all. Code: [Select] $result_rows = mysql_query("SELECT * FROM events WHERE category = 'adults' ORDER BY 'date'"); Any idea what is wrong? I have a mysql table that holds data for cars - each car has it's own ID, name, and year. Some cars are repeated. Example: (ID - year - car name) 0001 - 2009 - Honda Civic 0002 - 2008 - Toyota Prius 0003 - 2009 - Honda Civic 0004 - 2008 - Toyota Prius 0005 - 2008 - Toyota Prius 0006 - 2007 - Honda Civic How would I count how many of the same type of cars I have in that table and then display the quantity next to the car name? Like for the above example it would be: 2009 Honda Civic: 2 2007 Honda Civic: 1 2008 Toyota Prius: 3 Thanks in advance for any help :D I have 2 queries that I want to join together to make one row
It's late and I'm not thinking straight. I'm posting this question. Hopefully I get a reply in the morning. I have two tables. TABLE 1 - PRODUCTS TABLE 2 - LIKES I am a User who has posted these products. I want to find out ALL the Likes I have received for all my products. Here is my code. $find_products = $db->prepare("SELECT product_id FROM products WHERE user_id = :user_id"); $find_products->bindParam(':user_id', $my_user_id); $find_products->execute(); $result_products = $find_products->fetchAll(PDO::FETCH_ASSOC); if(count($result_products) > 0) { foreach($result_products as $row) { $product_id = $row['product_id']; $find_likes = $db->prepare("SELECT like_id FROM product_likes WHERE product_id = :product_id"); $find_likes->bindParam(':product_id', $product_id); $find_likes->execute(); $result_likes = $find_likes->fetchAll(PDO::FETCH_ASSOC); if(count($result_likes) > 0) { $get_likes = 0; foreach($result_likes as $row) { $get_likes++; } } } } The issue with the above code is that It only shows the Likes if I echo inside the foreach loop. And it'll show combined Likes from each of my products. But I want to actually combine ALL the Likes from ALL the products and be able show them as a single number, outside of the foreach loop. How do I do that? Edited August 17, 2019 by imgroootHi Everyone, I am working on implementing a blog comment system using the query below to display comments. My question is what is the best way to do a row count for the id column with this query or do I need to do a second db query to accomplish this? The purpose of this is to echo out the number of comments for that post, before displaying them. Any help is appreciated. Thanks in advance, kaiman <?php // get url variables $post_id = mysql_real_escape_string($_GET['id']); include ("../../scripts/includes/nl2p.inc.php"); // connects to server and selects database include ("../../scripts/includes/dbconnect.inc.php"); // table name $tbl_name3="blog_comments"; // select info from comments database $result3 = mysql_query ("SELECT count(*) FROM $table_name3 WHERE id='$post_id' ORDER BY id DESC LIMIT 1") or trigger_error("A mysql error has occurred!"); if (mysql_num_rows($result3) > 0 ) { while($row = mysql_fetch_array($result3)) { extract($row); // display number of comments // display date $row_date = strtotime($row['date']); putenv("TZ=America/Denver"); echo "<p class=\post\">On ".date('F, jS, Y', $row_date)." "; // display commenter name if($row['url'] == "") { echo $row['name']." wrote:</p>\n"; } else { echo "<a href=\"".$row['url']."\" target=\"_blank\">".$row['name']."</a> wrote:</p>\n"; } // display content $comments = $row['comment']; echo nl2p($comments); } } else { echo "<p class=\"large_spacer\">No Comments</p>"; } ?> $result = mysql_query("SELECT * FROM `friend_system` WHERE `friend_system_accepter` = '$myusername' "); echo mysql_num_rows($result);This displays the total rows in the table. $result = mysql_query("SELECT COUNT(friend_system_accepter) FROM `friend_system` WHERE `friend_system_accepter` = '$myusername' "); echo mysql_num_rows($result);This displays '1', which is incorrect. I want to echo out the number of rows where 'friend_system_accepter' = $myusername Thanks Folks, Having trouble here. Forgot how you use the COUNT. Not interested in the num_rows due to it being slow compared to COUNT. I have users table like this: id|username|sponsor_username 0|barand|requinix 1|phpsane|alison 2|mickey_mouse|requinix Now, I want to check if a sponsor username exists or not. Such as does the entry "requinix" exists or not in one of the rows in the "sponsor_username" column. In our example it does twice and so the variable $sponsor_username_count should hold the value "2". Else hold "0". I get error: Fatal error: Uncaught mysqli_sql_exception: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '?' at line 1
My code:
$stmt_1 = mysqli_prepare($conn,"SELECT COUNT(sponsor_username) from users = ?"); mysqli_stmt_bind_param($stmt_1,'s',$sponsor_username_count); mysqli_stmt_execute($stmt_1); //Show error if 'users' tbl was not successfully queried". if (!$stmt_1) { echo "ERROR 1: Sorry! Our system is currently experiencing a problem loading this page!"; exit(); } else { mysqli_stmt_bind_result($stmt_1,$sponsor_username_count); mysqli_stmt_fetch($stmt_1); mysqli_stmt_close($stmt_1); //Check if Sponsor Username in Url ($_GET) is already registered or not. If not then show "Invalid Url" or Link message. if ($sponsor_username_count < 1) { echo "<b>Invalid Url or Link!<br> Invalid Sponsor: \"$sponsor_username\"!</b><?php "; exit(); } }
I have a html table displaying data from mysql database. I can count rows properly with mysql_num_rows but is there a way to echo which row number it is. What I want to do is count the rows ordered by cities and echo row number. Thanks for any help. Hi Everyone, I am working on developing a blog/comment system for my website. I have 3 tables, the first a blog post table with a row/primary key of id that is auto incremented as each new article is created via a form. The second table is a comments table with a row of article_id and the third table is a category table with an article_id row as well. From the main blog page I have links that will take users to each individual blog post using $_GET like so: Code: [Select] http://www.mydomain.com/blog/article/?id={$row['id']} From here I would like to be able to display the comment for that particular article below the article and also have a sidebar with links to blog categories which will then display each post according to whether they are in that category or not. My question is two-fold: First, what is the best way to pull the id field from the blog/post table, form, or url and enter it into the article_id rows of the second two tables? Should I use a hidden field, the URL id via $_GET, using a join, or what? Secondly: What is the best way to compare and display those rows so that the appropriate comments are being shown for the correct article, etc. This is my first time doing this so I am grateful for any help or suggestions. Thanks, kaiman Hi, So i'm having a little trouble trying to simplify some code I already have. Code: [Select] $result = mysql_query("SELECT images, cat_id FROM image_cat"); while ($row=mysql_fetch_array($result)) { $cat_id=$row['cat_id']; echo $cat_id; $imgresult = mysql_query("SELECT * FROM images WHERE cat_id='".$cat_id."'"); while ($col=mysql_fetch_array($imgresult)) { echo $col['img_id']; } } Okay, so this works, however i'm sure I can bring it together under one query, though i'm truly stumped as to how? I thought I could do a simple join: Code: [Select] $result = mysql_query("SELECT image_cat.cat_id, images.img_id WHERE image_cat.cat_id=images.image_cat"); This works, but repeats the image category on each loop. I could remove this via php if statements, but there must be a simpler/mysql solution. If it doesn't make any sense I need to get Img cat 1 -img 1 -img 2 img cat 2 -img 3 -img 4 etc etc That join will give img cat 1 -img 1 img cat 1 -img 2 img cat 2 -img 3 Hope that makes sense?? And any help would be amazing! Thanks. This portion is kind of stumping me. Basically, I have a two tables in this DB: users and users_access_level (Separated for DB normalization) users: id / username / password / realname / access_level users_access_level: access_level / access_name What I'm trying to do, is echo the data onto an HTML table that displays users.username in one table data and then uses the users.access_level to find users_access_level.access_name and echo into the following table data, I would prefer not to use multiple queries if possible or nested queries. Example row for users: 1234 / tmac / password / tmac / 99 Example row for users_access_level: 99 / Admin Using the examples above, I would want the output to appear as such: Username: Access Name: Tmac Admin I am not 100% sure where to start with this, but I pick up quickly, I just need a nudge in the right direction. The code I attempted to create just shows my lack of knowledge of joining tables, but I'll post it if you want to see that I did at least make an effort to code this myself. Thanks for reading! |