PHP - Make A Link Execute A Script?

How can I achieve the following scenario with an anchor tag?

Code: [Select]
if(isset($_POST['submit'])) {
     // execute script
}

I do need it for a label system to sort content with labels.

Hi guys,

I am new here, and I am a bit stuck with doing something unusual.

I want to create a script that can turn on a program (dynamips and dynagen). So far, I have tried 'exec' and 'shell_exec'. Soon I realized that apache runs the commands as 'www-data' user (apache2 in ubuntu) and it's very limited on what you can execute.

Is there any way to do that at all? What would be the best practice? I am not concerned about security as this is not a production environment...

Thanks

Hi,

 

I am a newbie at php and I recently tried making a small php configuration that runs on the localhost. 

execution.php

<?php
	echo "first script has been executed";
	exec('execution2.php');
?>

execution2.php

<?php
	echo "Second script has been executed";
?>

The script is designed to call another php file whereas on the web page I would expect seeing, "first script has been executed" and "Second script has been executed". I am honestly not sure how the execution method is supposed to work however I am not planning on using "include" or "require" since they do not meet my criteria for another project. I am using xampp localhost server on a windows 10 computer. I tried entering "localhost:8080/dir/execution.php" however it did not work. 

 

Any help would be appreciated, thanks!

Hi all

I have this problem on a server using php5, unix based, safe_mode is On globally, i have turned it off locally through php.ini.

Ok, this is testing example script i used:

$cmd = ( "php -v" );
$out = shell_exec( $cmd );
print $out;

On my own server this returns php version. On this mentioned server i'm using (commercial) this causes complete server breakdown, when logged in with SSH, i can't even issue "ls" command after that, nor find and kill the process.
What could be so wrong with it? I don't think calling php-cli would make any difference.

Hi everyone, i'm trying to get it so when i visit my webpage called start.php it executes the command (/bigbrotherbot start) in the terminal which then should start the process on my linux machine.

I'm currently using this code

Code: [Select]
<?php
shell_exec('sudo /bigbrotherbot start');
?>
This script doesn't appear to do anything though. I'm very new to php and would really appreciate the help.

P.S the file bigbrotherbot is the bash script which works if i actually go to the terminal myself and type /bigbrotherbot start yet when i try to make the php do it it doesnt do anything.

any ideas?

Hi,   In reference to my first attached image, I have a form which displays two SELECT/drop-down fields (labeled "Store Name" and "Item Description".....and both of which pull-in values from two separate lookup/master tables, in addition to providing an additional option each for "NEW STORE" and "NEW ITEM").   Now, when first-run, and/or if "NEW STORE" and "NEW ITEM" are not selected from the drop-down's then the two fields in green ("New Store Name" and "New Item Name" are hidden, by means of the following code:  

<div class="new-store-container" id="new-store-container" name="new-store-container" style="display:none;">
    <div class="control-group">
        <div class="other-store" id="new_store_name">
            <?php echo standardInputField('New Store Name', 'new_store_name', '', $errors); ?>
        </div>
    </div>
</div>

  Conversely, if "NEW STORE" and/or "NEW ITEM" are selected from the two drop-down's then one (or both) of the "New Name" fields are unhidden by means of the following two pieces of code, one PHP and the second JS:    

<select class="store-name" name="store_id" id="store_id" onclick="toggle_visibility('store_id','new-store-container')">
    <?php echo $store_options; ?>
                            
    <?php
        if($values['store_id'] == "OTH")
            {
                echo "<option value='OTH' selected> <<<--- NEW STORE --->>> </option>";
            }
        else
            {
                echo '<OPTION VALUE="OTH"> <<<--- NEW STORE --->>> </OPTION>';
            }
    ?>
</select>

 

function toggle_visibility(fieldName, containerName)
{
    var e = document.getElementById(fieldName);
    var g = document.getElementById(containerName);
            
    if (e.value == 'OTH')
        {
            if(g.style.display == 'none')
                g.style.display = 'block';
            else
                g.style.display = 'none';
        }
}

  All  of that is working just fine. The problem I'm having is that when I click the "Create" button, after having left any one of the form fields blank, the two "New Name" fields are hidden again, which I don't want to happen i.e. I want them to remain visible (since the values of "store_id" and/or "item_id" are "OTH"), so that the user can enter values into one or both of them, without havng to click on the drop-down a second time in order to execute the "on-click" code.   The second attached image shows how the fields are hidden, after clicking "Create".   How can I achieve that? It would be greate if someone could cobble-up the required code and provide it to me, since I'm relatively new to this.   Thanks much.    Snap1.png   26.14KB   0 downloads    Snap2.png   149.47KB   0 downloads      

Okay so my news script is set to view only 10 pieces of news. But I want it so that it starts a new page once I have more than 10 pieces of news.

Code: [Select]
<?php
require("functions.php");
include("dbconnect.php");

session_start();

head1();
body1();
new_temp();
sotw();
navbar();
     
$start = 0;
$display = 10;
$query = "SELECT * FROM news ORDER BY id DESC LIMIT $start, $display";
$result = mysql_query( $query );

if ($result) {
    while( $row = @mysql_fetch_array( $result, MYSQL_ASSOC ) ) {
        news_box( $row['news'], $row['title'], $row['user'], $row['date'], $row['id'] );
    }
    mysql_free_result($result);
} else {
    news_box( 'Could not retrieve news entries!', 'Error', 'Error', 'Error');
}
                   
footer();

mysql_close($link);
?>
I tried a few things but they failed....miserably.

This topic has been moved to HTML Help.

http://www.phpfreaks.com/forums/index.php?topic=307669.0

Hey,

What i want is that if a username inserts some text into a field like "Hey @martin how are ya" ? then it will display @martin as a link that takes you to site.com/martin, i searched php.net from preg_replace and str_replace...unfortunately for me things got so complicated that i don't even want to talk about it.

Anyone who can do it will be my saviour!

ok, how do I make this button go to the specific link that is set with it.......it goes to page without eventid=eventid:
Code: [Select]
<form action= \"editevent.php?eventid=".$row['eventid']."\" method=\"link\"><INPUT TYPE=\"submit\" VALUE=\"Edit\"></form>";

I have created a database that echos out the result on a webpage, what i want to do is create one of the echo results into a link - the code is as follows:

"Web Address: $web_address <br>" .

Is there an easy way to make the result a link as the input will always be a web address?

Thanks in advance!

I have a table where it displays some data. How do I make this Code: [Select]
echo "<td>" . $row['title'] . "</td>"; into a link?

I basically have a PHP Search Form, and when a user fills in a form it outputs the results. Each result displays a image of a property, how could i make them images have their own unique link which will take them directly to the page of the property being shown?

Im using PHP and mySQL tables

Any help is appreciated,

Thank You.

Heres the PHP that outputs the results:
Code: [Select]

<?php
require_once 'mstr_ref.php';
function san($input){
if(get_magic_quotes_gpc()){
$input=stripcslashes($input);
}
$output = mysql_real_escape_string($input);
return $output;
}
if(isset($_POST['submit'])){
$pVars = array('area'=>$_POST['areas'], 'propType'=>$_POST['prop_type'], 'saleType'=>$_POST['ptype'], 'minB'=>$_POST['min_bedrooms'], 'maxB'=>$_POST['max_bedrooms'], 'minP'=>$_POST['min_price'], 'maxP'=>$_POST['max_price']);
foreach ($pVars as $k=>$v){
$v = san($v);
}
$sql = new makeQuery();
$sql->manAdd('location_id', $pVars['area']);
if($pVars['propType'] != 'Any'){
$sql->manAdd('catagory_id', $pVars['propType']);
}
if ($pVars['maxB'] > 0){
$sql->manAdd('bedrooms', $pVars['maxB'], '<=');
}
if($pVars['minB'] > 0){
$sql->manAdd('bedrooms',$pVars['minB'],'>=');
}
if($pVars['saleType'] != 'Any'){
if($pVars['saleType'] == "forsale"){
$sql->manAdd('market_type', 'sale');
if($pVars['minP'] != 0){
$pVars['minP'] = $pVars['minP'] * 1000;
}
if($pVars['maxP'] != 0){
$pVars['maxP'] = $pVars['maxP'] * 1000;
}
}
if($pVars['saleType'] == 'forrent'){
$sql->manAdd('market_type', 'rent');
}
}

$qry = $sql->sqlStart.$sql->stmt.'Group By property.id';
$results = mysql_query($qry) or die (mysql_error()."<br />|-|-|-|-|-|-|-|-|-|-|-|-<br />$qry");
if(mysql_num_rows($results) < 1){
die ("Sorry, No Results Match Your Search.");
}
while($row = mysql_fetch_assoc($results)){
echo '<div class="container" style="float:left;">';
echo '<div class="imageholder" style="float:left;">';
echo "<img class='image1' src='{$row['image_path']}' alt='{$row['summary']}'> <br />";
echo '</div>';
echo '<div class="textholder" style="font-family:helvetica; font-size:14px; float:left; padding-top:10px;">';
echo "{$row['summary']}";
echo "<span style=\"color:#63be21;\"><br><br><b>{$row['bedrooms']} bedroom(s) {$row['bathrooms']} bathroom(s) {$row['receptions']} reception room(s)</b></span>";
if($row['parking'] != null){
echo "<span style=\"color:#63be21;\"><b> {$row['parking']} parking space(s)</b></span>";
}

echo '</div>';
echo '<div style="clear:both"></div>';
}

}
else{
echo "There was a problem, please click<a href='index.php'> Here </a>to return to the main page and try again";
}
?>

Lets say that I want to make a certain word (or words) on a page a link. How would I make it a link without having to code in a link.

Some site have adds on certain words; one day and not the next day. I am looking for similar feature, but less intrusive. No pop-up, just a link.