PHP - Display Images From Database Issue
Hi guys its me again,
I am having a problem that I cant figure out... Here is my code: <?php $sqlCommand = "SELECT image FROM background"; $query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); $sqlCommand2 = "SELECT backgroundimage FROM site"; $query2 = mysqli_query($myConnection, $sqlCommand2) or die (mysqli_error()); while ($row = mysqli_fetch_array($query)) { while ($row2 = mysqli_fetch_array($query2)) { if($row['image'] == $row2['backgroundimage']){ echo '<img src="site_background/'.$row['image'].'" width="75px" height="75px" style="border:2px solid red;" /><br /><br />'; } if($row['image'] != $row2['backgroundimage']){ echo '<img src="site_background/'.$row['image'].'" width="50px" height="50px" style="border:2px solid black;" />'; } } } mysqli_free_result($query); mysqli_free_result($query2); ?> What is will do is get the images from the "backgrounds" table and the image from the "site" table (the current image). I am then wanting to pick out the current image and give it a red border and then display the other left over images smaller with a black border. I can get the images to all display with the black border or the current image to display with a red border but the other images dont show... I have tried mixing things around but I have not been able to get all the images to display with the formatting I want. I dont know if it is a simple syntax error or I am doing things completely wrong... I have been looking at it for so long its just become one big mess of code to me lol Any help to get this working as I want would be great! Cheers Ben Similar TutorialsI want to display 3 clickable images in a single row which repeats as long as there is data in the database, so far it is displaying a single clickable image from the database. below is all the code.. <table width="362" border="0"> <?php $sql=mysql_query("select * from `publication` GROUP BY `catsue`") or die(mysql_error()); $num=mysql_num_rows($sql); while($rowfor=mysql_fetch_array($sql)) { $cat=$rowfor['catsue']; $pic=mysql_query("select * from `category` where `catsue`='$cat'") or die(mysql_error()); $picP=mysql_fetch_array($pic); $base=basename($picP['title']); ?> <tr> <td width="352" height="88"><table width="408" border="0"> <tr> <td width="113" rowspan="5"><a href="archive_detail.php?id=<?php echo $rowfor['id'];?>&category=<?php echo $rowfor['catsue'];?>"><img src="ad/pic/<?php echo $base;?>" width="100" height="100" border="0"/></a></td> <td width="94">Title</td> <td width="179" height="1"><?php echo $rowfor['catsue'];?> </td> </tr> <tr> <td> </td> <td width="179" height="3"> </td> </tr> <tr> <td> </td> <td width="179" height="8"> </td> </tr> <tr> <td> </td> <td width="179" height="17"> </td> </tr> <tr> <td> </td> <td width="179" height="36"> </td> </tr> </table></td> </tr> <?php }?> </table> Hi, here's my problem: I am trying to make a simple online buying website and I want to display a table with all the fields for each item. So I got that part down which is to just use mysql_fetch_assoc("SELECT * FROM myTable") and use the html table tags stuff, but now I want to display my images in the table, so here's my code to display my mysql database table in html's table tag along w/ php: <html> <head> <title>My Online buying website project</title> </head> <body> <?php mysql_connect("localhost","root"); mysql_select_db("myTable"); $imagesArray=array("Apple_iPhone3GS.jpg","Apple_iPhone4.jpg","product3.jpg","product4.jpg","product5.jpg"); $result=mysql_query("SELECT Name, Manufacturer, Price, Description, SimSupport FROM myTable"); if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { print "<table border='border'>"; print "<tr> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { extract($row); print "<tr> <td>$Name</td> <td>$Manufacturer</td> <td>$Price</td> <td>$Description</td><td>$SimSupport</td> </tr>"; }//END WHILE }//END IF ?> </table> </body> </html> *So how do I go about adding my images in this table? I have this script from http://lampload.com/...,view.download/ (I am not using a database) I can upload images fine, I can view files, but I want to delete them. When I press the delete button, nothing happens
http://www.jayg.co.u...oad_gallery.php
<form>
<?php $dir = dirname(__FILENAME__)."/images/gallery" ; $files1 = scandir($dir); foreach($files1 as $file){ if(strlen($file) >=3){ $foil = strstr($file, 'jpg'); // As of PHP 5.3.0 $foil = $file; $pos = strpos($file, 'css'); if ($foil==true){ echo '<input type="checkbox" name="filenames[]" value="'.$foil.'" />'; echo "<img width='130' height='38' src='images/gallery/$file' /><br/>"; // for live host //echo "<img width='130' height='38' src='/ABOOK/SORTING/gallery-dynamic/images/gallery/ $file' /><br/>"; } } }?> <input type="submit" name="mysubmit2" value="Delete"> </form>
any ideas please?
thanks
I want to display thumbnails for a picture gallery and when user clicks on image the larger image opens in a new window. I can't find a straight answer on the php.net website. Can someone help? I read everywhere where it says not to stoe images in MYSQL but I have a code where I'm trying to display the images. They are all jpegs that are stored in the table. Here is the code Code: [Select] <?php include "dbaptsConfig.php"; include "searchaptsstyle.css"; // test id, you need to replace this with whatever id you want the result from $id = "1"; // what you want to ask the db $query = "SELECT * FROM `apartments` WHERE `id` = ".$id; // actually asking the db $res = mysql_query($query, $ms); // recieving the answer from the db (you can only use this line if there is always only one result, otherwise will give error) $result = mysql_fetch_assoc($res); // if you uncomment the next line it prints out the whole result as an array (prints out the image as weird characters) // print_r($result); // print out specific information (not the whole array) echo "<br/>"; echo "<div id='title'>".$result['title']."<br/></div>"; echo "<br/>"; echo "<div id='description'>".$result['description']."<br /></div>"; echo "<br/>"; echo "<div id='table'><tr>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Provider's Phone Number: ".$result['phone']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Provider: ".$result['service']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Borough: ".$result['county']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Town: ".$result['town']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Bedrooms: ".$result['rooms']."</td>"; echo "<td> </td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Bathrooms: ".$result['bath']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Square Footage: ".$result['square']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Rent: ".$result['rent']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Listed On: ".$result['time']."<br /></td>"; echo "</tr></div>"; header("Content-type: image/jpeg"); echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Listed On: ".$result['image1']."<br /></td>"; ?> Thanks I am looking to display image paths in a row separated by commas. There are 6 images that goes to each user and I would like only the 6 images at be in each " " Like this: "images/listings/listing_516013019A-only.jpg,images/listings/listing_848813453A-1.jpg,images/listings/listing_664613453A-2.jpg,images/listings/listing_520313453A-3.jpg,images/listings/listing_690513453A-4.jpg,images/listings/listing_125113453A-5.jpg,images/listings/listing_641013453A-6.jpg," "images/listings/listing_736913186A-1.jpg,images/listings/listing_822713186A-2.jpg,images/listings/listing_136513186A-3.jpg,images/listings/listing_700313186A-4.jpg,images/listings/listing_716013186A-5.jpg,images/listings/listing_213113186A-6.jpg," "images/listings/listing_292113254A..-1.jpg,images/listings/listing_854413254A..-2.jpg,images/listings/listing_446013254A..-3.jpg,images/listings/listing_676313254A..-4.jpg,images/listings/listing_563413254A..-5.jpg,images/listings/listing_341513254A..-6.jpg," Right now it is displaying them like this "images/listings/listing_516013019A-only.jpg," "images/listings/listing_848813453A-1.jpg," "images/listings/listing_664613453A-2.jpg," "images/listings/listing_520313453A-3.jpg," "images/listings/listing_690513453A-4.jpg," "images/listings/listing_125113453A-5.jpg," "images/listings/listing_641013453A-6.jpg," "images/listings/listing_736913186A-1.jpg," "images/listings/listing_822713186A-2.jpg," "images/listings/listing_136513186A-3.jpg," "images/listings/listing_700313186A-4.jpg," "images/listings/listing_716013186A-5.jpg," "images/listings/listing_213113186A-6.jpg," "images/listings/listing_292113254A..-1.jpg," "images/listings/listing_854413254A..-2.jpg," "images/listings/listing_446013254A..-3.jpg," "images/listings/listing_676313254A..-4.jpg," "images/listings/listing_563413254A..-5.jpg," "images/listings/listing_341513254A..-6.jpg," Here is the code I have: Code: [Select] <?php // Make a MySQL Connection mysql_connect("localhost", "xxxxxxxx", "xxxxxxxx") or die(mysql_error()); mysql_select_db("xxxxxxxx") or die(mysql_error()); $result = mysql_query("SELECT * FROM listimages ORDER BY listimages.listingid DESC ") or die(mysql_error()); while($row = mysql_fetch_array($result)) { echo "\""; echo "$row[imagepath],"; echo "\""; echo "<br>"; } ?> My tables for the images is "listimages" and the columns a id (which are the auto_increments) imagepath (which shows the path/image1.jpg) mainimage (which just shows 0 or 1 depending on the picture that is the default for that listing, 1 being default) listingid (shows numbers 1 2 3 etc corresponding to the Id in the listings table to show what images go with what listing) There are up to 6 images for each listing. Any idea how to fix this? I'm creating a funeral home site and on the side of the page I would like to display the last 5 funeral obituaries that are in mySQL database (name and certain sized image (images are in "image" field) w/ a link to an "obituaries detail page for the individual deceased person"). I am able to do this successfully listing only the names....how can I list the image associated with the name? This is what I have so far: Code: [Select] <?php include("connect.php"); ?> Code: [Select] <?php $query = "SELECT id, deceased_name, deceased_date, DATE_FORMAT(deceased_date, '%M %D, %Y') as datetext"; $query .= " FROM scales_obits ORDER BY deceased_date DESC LIMIT 5"; $listings = mysql_query($query); if (!listings) { echo("<p>Error retrieving listings from lookup table<br>". "Error: " . mysql_error()); exit(); } echo("<table border=\"0\" width=\"100%\" class=\"obit\">"); while ($listing = mysql_fetch_array($listings)) { $deceased_name = $listing["deceased_name"]; $deceased_date = $listing["datetext"]; $id = $listing["id"]; echo("<tr><td width=\"100%\"><a href=\"obitdetail.php?id=".$id."\"><strong>".$deceased_name."</strong></a></td><td> </td>"); } echo("</table>"); ?> Hi all, while I was coding a script for my website something struck me which ive not really got an idea how to code it, but anyway, in my Database ive got a table which holds image URL's but how could I echo them out in PHP which will show the image? Not just the writing. Thanks for your help. Hi I tried to write a script: 1) to locate all directories in a directory (1 level) 2) with the function GetImages() I try to display the image(s) in the subfolder there are only images in the subfolder I guess I'm doing something wrong in the GetImages() with the glob function, can anyone check this ? Thanks in advance function GetImages($map) { $files = glob('$map/*.jpg'); //$files = glob("$map/*.*"); for ($i=0; $i<count($files); $i++) { $num = $files[$i]; echo '<img height="50" width="50" src="'.$num.'" />'." <br />"; } } if ($handle = opendir('mystuff')) { /* loop through directory. */ while (false !== ($dir = readdir($handle))) { if($dir != ".." && $dir != "."){ echo '<option value='.$dir.'>'.$dir.'</option><br>'; GetImages($dir); } } closedir($handle); } How can i display all the images in a certain directory and echo the image names. So if a new image is uploaded, it will still display without edited the gallery.php file. Cheers. I want to retrieve an image id from a db and show the images. I cant get the syntax right for the image tag.Any help appreciated. Code: [Select] function display_covers() { global $wpdb; $query = "select * from wp_cover"; $result = mysql_query($query)or trigger_error("Query: $query\n<br />MySQL Error: " . mysql_error()); echo mysql_error(); if (!$result) return false; echo'<div class="wrap"><p>choose from one of the covers below</p></div>'; echo'<div id="main">'; echo'<table class="main" cellpadding="2">'; //echo"<caption>Please choose a book cover</caption>"; ?> <thead><tr><td colspan="5" ><h6 class="main">Book Covers</h6></td></tr> </thead> <?php $i=0; $size=3; echo "<tbody>"; echo "<tr>"; while ($row = mysql_fetch_array($result,MYSQL_ASSOC)) { /* display picture */ ?> <td class="main"> <?php echo"<img src="/Applications/MAMP/htdocs/wordpress_3/wp-content/plugins/Authors2/jackets/"{.$row['pix'].}""/>"; echo"</td>"; $i++; if($i==$size) { echo "</tr><tr>"; $i=0; } } } Hi everyone!! I have looked into how the upload script works and this is what i have: Code: [Select] <?php if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/pjpeg")) && ($_FILES["file"]["size"] < 20000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; } } } else { echo "Invalid file"; } ?> Which is un-tested at the moment, but let's just say for talking sake it worked 100% what elements of this script would i be looking at to display the files uploaded on to another page, in my case my homepage? ive found as to yet, that the uploads have to be stored on a file somewhere on my server, which i've set up. But i thought it would be just as easy to have a field in my table named upload and display it within the table next to the other results? instead i just get whatever the file name is named.jpg. Any help in looking towards the answer? many thanks in advance guys! Hello everyone, I need help figuring out why im not getting images displayed. I have tried everything I could think of and narrowed down the issue. What Im doing id querying urls from DB for my images. Then using md5 to encrypting the url them before display on web page. Here is the code: Code: [Select] $img = @ md5(mysql_result(mysql_query("SELECT `url` FROM `pictures` WHERE `mls`='{$row['mls']}' ORDER BY `id` LIMIT 1",$avenu->link),0)); When html is displayed I get the hash.jpg. The image failed to be loaded. Hi all, Newbie here, i am having a problem to get my images to show which are stored in mysql database as a mediumblob. I get id number to print in table ut am just getting empty square with red cross in where my image should be. Is my code incorrect or is it something else? Appreciate your help with this. I have included both of the pages codes i am using. Thanks Tony image2.php <?php include("common.php"); error_reporting(E_ALL); $link = mysql_connect(host,username,password) or die("Could not connect: " . mysql_error()); mysql_select_db(db) or die(mysql_error()); $sql = "SELECT id FROM photos"; $result = mysql_query("$sql") or die("Invalid query: " . mysql_error()); ?> <table border="1"><tr><td>id</td><td>image</td></tr> <?php while($row=mysql_fetch_assoc($result)){ print '<tr><td>'.$row['id'].'</td><td>'; print '<img src="image1.php?id='.$row['id'].'height="75" width="100"">'; } echo '</td></tr></table>' ?> image1.php <?php ob_start(); include("common.php"); mysql_connect(host,username,password) or die(mysql_error()); mysql_select_db(db) or die(mysql_error()); $query = mysql_query("SELECT imgage FROM photos WHERE id={$_GET['image_id']}"; $row = mysql_fetch_array($query); $content = $row['image']; header('Content-type: image/jpg'); echo $content; } ob_end_flush(); ?> I have this code which uoploads and resizes the images into a folder without a problem. My problem is I am unable to view the Thumb or Full image which has uploaded to the folder and the database with the other data. How do i correct this problem code below. Thanks upload form and script Code: [Select] <?php //database properties $dbhost = 'localhost'; $dbuser = 'user'; $dbpass = 'pass'; $dbname = 'DB'; // make a connection to mysql here $conn = mysql_connect ($dbhost, $dbuser, $dbpass) or die ("I cannot connect to the database because: " . mysql_error()); mysql_select_db ($dbname) or die ("I cannot select the database '$dbname' because: " . mysql_error()); /******** start function ********/ function errors($error){ if (!empty($error)) { $i = 0; echo "<blockquote>\n"; while ($i < count($error)){ echo "<p><span class=\"warning\">".$error[$i]."</span></p>\n"; $i ++;} echo "</blockquote>\n"; }// close if empty errors } // close function // ----------------Create Smaller version of large image--------------------- function createthumbfull($src_filename, $dst_filename_full) { // Get information about the image list($src_width, $src_height, $type, $attr) = getimagesize( $src_filename ); // Load the image based on filetype switch( $type ) { case IMAGETYPE_JPEG: $starting_image = imagecreatefromjpeg( $src_filename ); break; case IMAGETYPE_PNG: $starting_image = imagecreatefrompng( $src_filename ); break; case IMAGETYPE_GIF: $starting_image = imagecreatefromgif( $src_filename ); break; default: return false; } // get the image to create thumbnail from $starting_image; // get image width $width = imagesx($starting_image); // get image height $height = imagesy($starting_image); // size to create thumnail width $thumb_width = 600; // divide iwidth by specified thumb size $constant = $width/$thumb_width; // round height by constant and add t thumb_height $thumb_height = round($height/$constant, 0); //create thumb with true colours $thumb_image = imagecreatetruecolor($thumb_width, $thumb_height); //create thumbnail resampled to make image smooth imagecopyresampled($thumb_image, $starting_image, 0, 0, 0, 0, $thumb_width, $thumb_height, $width, $height); $ran = rand () ; $thumb1 = $ran.".jpg"; global $thumb_Add_full; $thumb_Add_full = $dst_filename_full; $thumb_Add_full .= $thumb1; imagejpeg($thumb_image, "" .$dst_filename_full. "$thumb1"); } //-------------------- create thumbnail -------------------------------------------- //$src_filename = source of image //$dst_filename_thumb = location to store final image function createthumb($src_filename, $dst_filename_thumb) { $size = getimagesize($src_filename); // get image size $stype = $size['mime']; //get image type : gif,png,jpg $w = $size[0]; // width of image $h = $size[1]; // height of image //do a switch statment to create image from right image type switch($stype) { //if image is gif create from gif case 'image/gif': $simg = imagecreatefromgif($src_filename); break; //if image is jpeg create from jpeg case 'image/jpeg': $simg = imagecreatefromjpeg($src_filename); break; //if image is png create from png case 'image/png': $simg = imagecreatefrompng($src_filename); break; } $width = $w; // get image width $height = $h; // get image height // size to create thumnail width $thumb_width = 150; $thumb_height = 150; //use true colour for image $dimg = imagecreatetruecolor($thumb_width, $thumb_height); $wm = $width/$thumb_width; //width divided by new width $hm = $height/$thumb_height; //height divided by new height $h_height = $thumb_height/2; //ass new height and chop in half $w_height = $thumb_width/2; //ass new height and chop in half //if original width is more then original height then modify by width if($w> $h) { $adjusted_width = $w / $hm; // add original width and divide it by modified height and add to var $half_width = $adjusted_width / 2; // chop width in half $int_width = $half_width - $w_height; // take away modified height from new width //make a copy of the image imagecopyresampled($dimg,$simg,-$int_width,0,0,0,$adjusted_width,$thumb_height,$w,$h); //else if original width is less or equal to original height then modify by height } elseif(($w <$h) || ($w == $h)) { $adjusted_height = $h / $wm; // diving original height by modified width $half_height = $adjusted_height / 2; // chop height in half $int_height = $half_height - $h_height; // take away modified height from new width //make a copy of the image imagecopyresampled($dimg,$simg,0,-$int_height,0,0,$thumb_width,$adjusted_height,$w,$h); } else { // don't modify image and make a copy imagecopyresampled($dimg,$simg,0,0,0,0,$thumb_width,$thumb_height,$w,$h); } $ran = "thumb_".rand (); // generate random number and add to a string $thumb2 = $ran.".jpg"; //add random string to a var and append .jpg on the end global $thumb_Add_thumb; //make this var available outside the function as it will be needed later. $thumb_Add_thumb = $dst_filename_thumb; // add destination $thumb_Add_thumb .= $thumb2; // append file name on the end //actually create the final image imagejpeg($dimg, "" .$dst_filename_thumb. "$thumb2"); } /********end functions ***********/ // if form submitted then process form if (isset($_POST['submit'])){ // check feilds are not empty $imageTitle = trim($_POST['imageTitle']); if (strlen($imageTitle) < 3 || strlen($imageTitle) > 255) { $error[] = 'Title must be at between 3 and 255 charactors.'; } // check feilds are not empty or check image file size if (!isset($_FILES["uploaded"])) { $error[] = 'You forgot to select an image.'; } // check feilds are not empty $imageDesc = trim($_POST['imageDesc']); if (strlen($imageDesc) < 3) { $error[] = 'Please enter a description for your image.'; } // location where inital upload will be moved to $target = "productimages/" . $_FILES['uploaded']['name'] ; // find the type of image switch ($_FILES["uploaded"]["type"]) { case $_FILES["uploaded"]["type"] == "image/gif": move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target); break; case $_FILES["uploaded"]["type"] == "image/jpeg": move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target); break; case $_FILES["uploaded"]["type"] == "image/pjpeg": move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target); break; case $_FILES["uploaded"]["type"] == "image/png": move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target); break; case $_FILES["uploaded"]["type"] == "image/x-png": move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target); break; default: $error[] = 'Wrong image type selected. Only JPG, PNG or GIF accepted!.'; } // if valadation is okay then carry on if (!$error) { // post form data $imageTitle = $_POST['imageTitle']; $imageDesc = $_POST['imageDesc']; //strip any tags from input $imageTitle = strip_tags($imageTitle); $imageDesc = strip_tags($imageDesc); // add slashes if needed if(!get_magic_quotes_gpc()) { $imageTitle = addslashes($imageTitle); $imageDesc = addslashes($imageDesc); } // remove any harhful code and stop sql injection $imageTitle = mysql_real_escape_string($imageTitle); $imageDesc = mysql_real_escape_string($imageDesc); //add target location to varible $src_filename $src_filename = $target; // define file locations for full sized and thumbnail images $dst_filename_full = 'productimages/'; $dst_filename_thumb = 'productthumb/'; // create the images createthumbfull($src_filename, $dst_filename_full); //call function to create full sized image createthumb($src_filename, $dst_filename_thumb); //call function to create thumbnail image // delete original image as its not needed any more. unlink ($src_filename); // insert data into images table $query = "INSERT INTO table (imageTitle, imageThumb, imageFull, imageDesc) VALUES ('$imageTitle', '$thumb_Add_thumb', '$thumb_Add_full', '$imageDesc')"; $result = mysql_query($query) or die ('Cannot add image because: '. mysql_error()); // show a message to confirm results echo "<h3 align='center'> $imageTitle uploaded</h3>"; } } //dispaly any errors errors($error); ?> <form enctype="multipart/form-data" action="" method="post"> <fieldset> <legend>Upload Picture</legend> <p>Only JPEG, GIF, or PNG images accepted</p> <p><label>Title<br /></label><input type="text" name="imageTitle" <?php if (isset($error)){ echo "value=\"$imageTitle\""; }?> /></p> <p><label>Image<br /></label><input type="file" name="uploaded" /></p> <p><label>Description<br /></label><textarea name="imageDesc" cols="50" rows="10"><?php if (isset($error)){ echo "$imageDesc"; }?></textarea></p> <p><label> </label><input type="submit" name="submit" value="Add Image" /></p> </fieldset> </form> view data Code: [Select] <?php // Connects to your Database mysql_connect("localhost", "user", "pass") or die(mysql_error()) ; mysql_select_db("DB") or die(mysql_error()) ; //Retrieves data from MySQL $data = mysql_query("SELECT * FROM table") or die(mysql_error()); //Puts it into an array while($info = mysql_fetch_array( $data )) { ?> <?php echo "<img src=http://www.web.com/productimages/" .$info['imagefull'] ." > <br>"; ?> <?php echo "<img src=http://www.web.com/productthumb/" .$info['imageThumb'] ." > <br>"; ?> <?php echo "<b>imageTitle:</b> ".$info['imageTitle'] . "<br> "; ?> <?php echo "<b>imageDesc:</b> ".$info['imageDesc'] . " <hr>"; ?> <?php }?> I want users to be allowed to upload images to a table in a database but I cannot seem to find a suitable way to implementing using the code I already have, here is the code below; Code: [Select] <?php error_reporting(E_ALL ^ E_NOTICE); ini_set("display_errors", 1); require_once ('./includes/config.inc.php'); require_once (MYSQL); $add_cat_errors = array(); if ($_SERVER['REQUEST_METHOD'] == 'POST') { if (!empty($_POST['product'])) { $prod = mysqli_real_escape_string($dbc, strip_tags($_POST['product'])); } else { $add_cat_errors['product'] = 'Please enter a Product Name!'; } if (filter_var($_POST['prod_descr'])) { $prod_descr = mysqli_real_escape_string($dbc, strip_tags($_POST['prod_descr'])); } else { $add_cat_errors['prod_descr'] = 'Please enter a Product Description!'; } // Check for a category: if (filter_var($_POST['cat'], FILTER_VALIDATE_INT, array('min_range' => 1))) { $catID = $_POST['cat']; } else { // No category selected. $add_page_errors['cat'] = 'Please select a category!'; } if (filter_var($_POST['price'])) { $price = mysqli_real_escape_string($dbc, strip_tags($_POST['price'])); } else { $add_cat_errors['price'] = 'Please enter a Product Description!'; } if (filter_var($_POST['stock'])) { $stock = mysqli_real_escape_string($dbc, strip_tags($_POST['stock'])); } else { $add_cat_errors['stock'] = 'Please enter a Product Description!'; } if (empty($add_cat_errors)) { $query = "INSERT INTO product (product, prod_descr, catID, price, image, stock) VALUES ('$prod', '$prod_descr', '$catID', '$price', '$image', '$stock')"; $r = mysqli_query ($dbc, $query); if (mysqli_affected_rows($dbc) == 1) { echo '<p>Record Successfully Added!!!!!</p>'; $_POST = array(); } else { trigger_error('OH NOOOOO!!!!'); } } } require_once ('./includes/form_functions.inc.php'); ?> <form action="add_product.php" method="post"> Product Name: <?php create_form_input('product', 'text', $add_cat_errors);?> Product Description: <?php create_form_input ('prod_descr', 'text', $add_cat_errors);?> Category: <select name="cat"<?php if (array_key_exists('cat', $add_cat_errors))?>> <option>Select a Category</option> <?php $q = "SELECT catID, cat FROM category ORDER BY cat ASC"; $r = mysqli_query($dbc, $q); while ($row = mysqli_fetch_array($r, MYSQLI_NUM)) { echo "<option value=\"$row[0]\""; if (isset($_POST['cat']) && ($_POST['cat'] == $row[0])) echo 'selected="selected"'; echo ">$row[1]</option>\n"; } ?> Price: <?php create_form_input('price', 'text', $add_cat_errors);?> Upload an Image: <?php if(array_key_exists('image', $add_cat_errors)) { echo '<input type="file" name="image" />'; } ?> Stock: <?php create_form_input('stock', 'text', $add_cat_errors);?> <input type="submit" name="submit_button" value="ADD RECORD" /> </form> Everything else writes perfectly but I have been trying ways to create a file upload and write successfully to the database. The 'image' field has a data type of 'varchar'. I apologise immensely for the long winded explanation but if anyone could help me please that would be much appreciated. Hello, I am new to PHP coding, and I have some issues trying to upload multiple images into database. The code works only for 1 image, but when I try to add foreach, I receive this message: Warning: Invalid argument supplied for foreach() . Can anyone help me ?
I am trying to display images on a html page alphabetically in descending order by their filename. This script inserts all the images in a directory on the page. Just can't figure out how to maintain this with a sorting option <?php $dir = "./plate_cache"; $handle = opendir($dir); while (($file = readdir($handle))!==false) { if (strpos($file, '.png',1)) { echo "<img id=\"plates\" src=\"/tags/plate_cache/$file\"></a><br />;"; } } closedir($handle); } ?> I have a supplement store that we'll call SiteA . On the homepage there is a list of featured and best selling products with images. I have a separate blog that we'll call SiteB. I want to get the images and the url they link to (for the product page) from SiteA and display them on SiteB. So that when a user is browsing SiteB and they click on one of the product images, it takes them to the correct product page. I have a script where I can manually accomplish this. However, since the content on the homepage of SiteA is always changing, I'd like to automate this process. For example: If you do a google search for "php", then click on "images" at the top, you will see a list of images relevant to PHP. If you click on any one of them, it takes you to that images page. That is what I want to essentially accomplish. Any suggestions? |