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PHP - Dynamically Populating An Array?
I need to fill an array dynamically with all the data in the users table. Any help will be appreciated, thanks!
Similar TutorialsHi all, I hope someone can help me out here as I think I am close but am not sure where to go from here. The problem is: I have a cms where a user can see a list of photos in the gallery. I provide them the ability to select what photos they want to appear on a particular webpage. The problem I have is that the user wants to be able to put the photos in whatever order they choose. So, I have a form (see attached), the html code is: <table width="566px" cellspacing="0" border="0"> <tr> <td width="33%"> <div class="serviceCell"> <input type='checkbox' checked='checked' name='photos[][0]' value='119' /> Bathroom Sin... <img src="./images/help.gif" title="Enter an integer to signify the order in which this image will appear on the webpage." alt="Enter an integer to signify the order in which this image will appear on the webpage."/> <input type="text" size="2" name="photos[][1]" value="0"/> </div> </td> <td width="33%"> <div class="serviceCell"> <input type='checkbox' checked='checked' name='photos[][0]' value='113' /> Courtyard 1 <img src="./images/help.gif" title="Enter an integer to signify the order in which this image will appear on the webpage." alt="Enter an integer to signify the order in which this image will appear on the webpage."/> <input type="text" size="2" name="photos[][1]" value="0"/> </div> </td> <td width="33%"> <div class="serviceCell"> <input type='checkbox' name='photos[][0]' value='114' /> Courtyard 2 <img src="./images/help.gif" title="Enter an integer to signify the order in which this image will appear on the webpage." alt="Enter an integer to signify the order in which this image will appear on the webpage."/> <input type="text" size="2" name="photos[][1]" value=""/> </div> </td> </tr>... Now, lets assume that the user ticked the box next to 'Courtyard 2' and entered an integer '1' in the input box to signify that this image should be displayed 1st on the chosen webpage. These 2 values go into the multidimensional array (photoid, ranking) and are submitted in the form to php in the photos[][] array. But here is where I have the problem. I am trying to extract the values from the array and then do an insert to a table in mysql. My syntax must be wrong somewhere so I am asking anyone to please offer any advice: if (isset($_REQUEST['submitted'])){ $photos = $_REQUEST['photos']; ... if(!empty($photos)){ foreach($photos as $photoID){ $sql = "INSERT IGNORE INTO menuItemPhotos SET photoid='$photoID[0]', menuItemid='$id', ranking='$photoID[1]'"; $ok = @mysql_query($sql); // execute the query } // End of foreach($photos as $photoID){ } // End of if(!empty($photos)){ Thanks Conor [attachment deleted by admin] Given the following array $documentlist, displayed from print_r Array ( [MerchantDocumentInfo] => Array ( => Array ( [documentID] => 2760322451 [generatedDateTime] => 2010-08-03T16:02:45-07:00 ) [1] => Array ( [documentID] => 2761837402 [generatedDateTime] => 2010-08-03T23:01:15-07:00 ) ) ) I'm trying to figure out the syntax to use the documentID as a dynamic variable When I 'hard code' the variable, I get the document I want eg $order = $t->GetDocument('2760322451'); -- returns requested document info into $order array where $order is an array and $t are my connection credentials. I've made numerous attempts, but get errors in anything I try. Can someone tell me the correct syntax to use to pass a dynamic value for documentID from the $documentlist array at the top? I've tried $order = $t->GetDocument($documentlist['MerchantDocumentInfo' ]['documentID']) ; and get ===> syntax error, unexpected '[', expecting ']' $order = $t->GetDocument($documentlist->MerchantDocumentInfo[0]['documentID']) ; get nothing $order = $t->GetDocument($documentlist->MerchantDocumentInfo[1]['documentID']) ; get nothing $order = $t->GetDocument($documentlist->MerchantDocumentInfo[1][documentID]) ; get nothing Thanks in advance for any ideas, I've been trying to figure this out for days. Friends, I have a PHP script that populates a calendar based on an array as follows: $days = array(2=>array('javascript:showWhatsOnText(2);','linked-day'), 3=>array('javascript:showWhatsOnText(3);','linked-day'), 4=>array('javascript:showWhatsOnText(4);','linked-day')); echo generate_calendar(2011, 4, $days, 1, '#'); where, for instance, the 2, 3 4 are the days of the month, By extracting a series values from a MySQL database how would I generate this array dynamically. E.g I have startday, startmonth, name and text fields in the database and would need to loop through them all to create the array. I tried playing around with something like this without any luck: $queryCat1 = "SELECT * FROM $dbCalendarEvents ORDER BY id ASC"; // WHERE visible = '1' $result1 = mysql_query($queryCat1) or die (mysql_error()); $num1 = mysql_num_rows($result1); $i=0; $daysArray = array(); while ($i < $num1) { $startday=mysql_result($result1,$i,"startday"); $startmonth=mysql_result($result1,$i,"startmonth"); $name=mysql_result($result1,$i,"name"); $name=mysql_result($result1,$i,"name"); $copy=mysql_result($result1,$i,"copy"); $daysArray[$i] = $startday=>array('/weblog/archive/2004/Jan/02','linked-day'); $i++; } Your help is appreciated. I have a slideshow that I am having to modify for my needs. The data file uses an array and i need this to be dynamic. I need to loop through all images in a directory and create the array. I have the directory being stored in a variable already. Now i just need to loop though all images in that directory to create the array like you see in the below code. You can also see the directory variable at the top. Can someone give me a hand with this please? Code: [Select] <?php echo $slideimagefolder; //http://localhost:82/images/groupphotos/1/1/ $slides = array( // --- Start slide list --- // slide elements array( "slidelink" => "http://www.frontpageslideshow.net", "title" => "Frontpage Slideshow 1.7", "category" => "About Frontpage Slideshow", "tagline" => "Image taken from the movie \"Shoot 'em up\"", "text" => "\"Frontpage SlideShow\" is the most eye-catching way to display your featured articles, stories or even products in your php based website or CMS, like Time.com, Joost.com or Yahoo! Movies do. \"Frontpage SlideShow\" creates an uber-cool slideshow with text snippets laying on top of images. These \"slides\" are being rotated one after the other with a nice fade effect. The slideshow features navigation and play/pause buttons, so the visitor has complete control over the slideshow's \"playback\"! And best of all, Frontpage Slideshow can be skinned!", "slideimage" => "ao4.jpg" ), // slide elements array( "slidelink" => "http://www.frontpageslideshow.net", "title" => "Use Frontpage Slideshow on any PHP based site!", "category" => "About Frontpage Slideshow", "tagline" => "Image taken from the movie \"The Kingdom\"", "text" => "JoomlaWorks has developed this modification of Frontpage Slideshow to work on every website that supports PHP as a minimum requirement. We call this modification the \"Static PHP\" version of Frontpage Slideshow. It's ideal for use on non-Joomla!/Mambo websites, like for example your corporate PHP based website or your Wordpress blog or Drupal website! You can obviously use this version on any CMS that is based on PHP!", "slideimage" => "the_kingdom_20070820114258369.jpg" ), // slide elements array( "slidelink" => "http://www.frontpageslideshow.net/content/view/14/37/", "title" => "FPSS is Search Engine Friendly!", "category" => "About Frontpage Slideshow", "tagline" => "Image taken from the movie \"Invaders\"", "text" => "Unlike Flash based slideshows, Frontpage Slideshow uses unobtrusive javascript and some CSS wizardry only. The content of the slides is laid out as html code, which means it can be \"read\" by search engines. The proper usage (and order) of h1, h2, p (and more) tags will make sure Google (or any other search engine) regularly \"scans\" your latest/featured items.", "slideimage" => "TVD_TR_02183_2.jpg" ), // slide elements (***TIP***: copy this data block and paste it below itself to add more slides) array( "slidelink" => "http://www.joomlaworks.gr", "title" => "About JoomlaWorks", "category" => "", "tagline" => "Image taken from the movie \"Transformers\"", "text" => "JoomlaWorks is a team of professional web designers and developers dedicated to delivering high-quality extensions and templates for Joomla! (the most popular open source Content Management System (CMS) worldwide) and Mambo (award winning CMS). JoomlaWorks has established a solid reputation in the Joomla! & Mambo communities, having developed some of the most popular and innovative free & commercial extensions & templates, since 2006.", "slideimage" => "2007_transformers_014_1.jpg" ), // --- End slide list --- ); ?> I'm trying to convert a one dimensional array into a multidimensional array by grouping matching parts of the keys,
i.e. array('onetwothreefour'=>'value',
'onetwothreesix'=>'value2')
would become
array('onetwothree'=>array('four'=>'value',
'six'=>'value2'));
Essentially I'm trying to convert XML to YML and have a one dimensional array of the XML with index => value.
I've been staring at it for a while now and have tried a few recursive functions to build it though I've come to a few dead ends and would appreciate any words of wisdom if someone can spot the answer easier than I
Edited by joel24, 23 May 2014 - 09:51 AM. I'm having an issue with building a multidimensional array via a for (....) the array should look like the example any help would be much, much appreciated thanks siouxx array ["username"] = "steve" array ["item"] = "12345" array "model" = "some model" "quantity" = "36.2" "details" array 0 = "detail 1" 1 = "detail 2" 2 = "detail 3" ["username"] = "steve" array ["item"] = "000257" array "model" = "some other model" "quantity" = "77.8" "details" array 0 = "detail 1" 1 = "detail 2" ["username"] = "bob" array ["item"] = "45678" array "model" = "other model" "quantity" = "99.5" "details" array 0 = "detail 1" 1 = "detail 2" 2 = "detail 3" 3 = "detail 3" the array return by sql looks like this Array ( => Array ( [id_prod] => 6 [id_tipo] => CPT [marca] => HP [modello] => Pavilion p6-200 [prezzo] => 599.00 [desc] => Computer da Tavolo [chiave] => 32 [utente] => steve [qta] => 1 [indata] => 2011-10-10 16:32:20 [dettaglio] => HD 320GB - RAM 4GB - Scheda audio 5.1 ) [1] => Array ( [id_prod] => 6 [id_tipo] => CPT [marca] => HP [modello] => Pavilion p6-200 [prezzo] => 599.00 [desc] => Computer da Tavolo [chiave] => 31 [utente] => steve [qta] => 1 [indata] => 2011-10-10 16:32:20 [dettaglio] => Intel Core i3-550 (3.20GHz, 4MB L3) Here is my dilemma and thank you in advance! I am trying to create a variable variable or something of the sort for a dynamic associative array and having a hell of a time figuring out how to do this. I am creating a file explorer so I am using the directories as the keys in the array. Example: I need to get this so I can assign it values $dir_list['root']['folder1']['folder2'] = value; so I was thinking of doing something along these lines... if ( $handle2 = @opendir( $theDir.'/'.$file )) { $tmp_dir_url = explode($theDir); for ( $k = 1; $k < sizeof ( $tmp_dir_url ); $k++ ) { $dir_list [ $dir_array [ sizeof ( $dir_array ) - 1 ] ][$tmp_dir_url[$k]] } this is where I get stuck, I need to dynamically append a new dimension to the array durring each iteration through the for loop...but i have NO CLUE how Could anyone point me in the correct direction of how to go about excluding results from a drown down menu, Basically i'm calling everyone who's a contact to the user in the code below, id like to remove contacts who already have a bank account with the user, So basically its something along the lines of if the player_id is already in the table bank_accounts as PlayersID, then its excluded, Hope this makes sense and any help would be great, Thanks Code: [Select] <select name="contact1" class="maintablepstats" id="contact1"> <option value=""></option> <?php $sql = "SELECT player_id, contact_id, name, is_active FROM contacts as c JOIN players as p ON c.contact_id = p.id WHERE c.player_id = $playerID AND is_active = 1 ORDER BY name ASC"; $que = mysql_query($sql) or die(mysql_error()); while($list = mysql_fetch_array($que)) { ?> <option value="<?php echo $list['contact_id'] ?>"><?php echo $list['name'] ?></option> <?php } ?> </select> hi, I have a form that has 2 lists, first one has the months from Jan to Dec which i am done with, for the second list i want to have years from current year for other say 5 years. Example, we are in 2020 so i should have the list populate 2020,2021,2022,2023,2024 and next year it should show 2021-2025, how to do that. Here is what i have as HTML: <html> <head> <link rel="stylesheet" type="text/css" href="reportstyle.css"> </head> <body> <div class="form-wrapper"> <form action="reportanalysis.php" method="post"> <div class="form-item"> <h4>Select a month:</h4> <select id="months" name="months" required="required"> <option selected="selected" value="chose">Choose one option...</option> <option value="jan">Jan - 01</option> <option value="feb">Feb - 02</option> <option value="mar">Mar - 03</option> <option value="apr">Apr - 04</option> <option value="may">May - 05</option> <option value="jun">Jun - 06</option> <option value="jul">Jul - 07</option> <option value="aug">Aug - 08</option> <option value="sep">Sep - 09</option> <option value="oct">Oct - 10</option> <option value="nov">Nov - 11</option> <option value="dec">Dec - 12</option> </select> </div> <div class="form-item"> <h4>Select a year:</h4> <select id="years" name="years" required="required"> <option selected="selected" value="chose">Choose one option...</option> <option value="2020">2020</option> <option value="2021">2021</option> <option value="2022">2022</option> <option value="2023">2023</option> <option value="2024">2024</option> </select> </div> <div class="button-panel"> <center><button type="submit" name="reporting" class="buttonstyle">Generate Graph Report</button></center> </div> <div class="reminder"> <p><a href="home.php">Return to Main Menu</a> </div> </form> </div> </body> </html> Edited April 3, 2020 by ramiwahdan typo error <?php $con=mysql_connect("localhost","root",""); if(!$con) { die('could not connect' .mysql_error()); } mysql_select_db("hrc_fault",$con); $query = "SELECT * " . "FROM fault_book"; $result = mysql_query($query, $con) or die(mysql_error()); $num_movies = mysql_num_rows($result); $registered_comp=<<<EOD <h2><center>Registered Fault HRC</center></h2> <table width="70%" border="1" cellpadding="2" cellspacing="2" align="center"> <tr> <th>Job Cd No</th> <th>Date</th> <th>Section</th> <th>Item Description</th> <th>Item Sl.No</th> <th>Fault</th> </tr> EOD; $fault_details = ''; while ($row = mysql_fetch_array($result)) { $jc_no = $row['jc_no']; $date = $row['date']; $section = $row['section']; $itm_des = $row['itm_des']; $itm_slno = $row['itm_slno']; $fault_brf = $row['fault_brf']; $fault_details .=<<<RAM <tr> <td>$jc_no</td> <td>$date</td> <td>$section</td> <td>$itm_des</td> <td>$itm_slno</td> <td>$fault_brf</td> </tr> RAM; } $movie_footer ="</table>"; $movie =<<<MOVIE $jc_no $date $section $itm_des $itm_slno $fault_brf MOVIE; echo "There are $num_movies complains in our database"; echo $movie; ?> I m using above code but it only display the last record please debug the code I'm trying to retrieve data from my DB and have it populate the dropdown values inside a form: echo "<option value='0.00' " . ($array['roastturkey'] == '0.00' ? 'selected="selected"' : '') . ">0</option>";echo "<option value='1.00' " . ($array['roastturkey'] == '1.00' ? 'selected="selected"' : '') . ">1</option>";echo "<option value='2.00'> " . ($array['roastturkey'] == '2.00' ? 'selected="selected"' : '') . ">2</option>";echo "<option value='3.00'> " . ($array['roastturkey'] == '3.00' ? 'selected="selected"' : '') . ">3</option>";echo "<option value='4.00'> " . ($array['roastturkey'] == '4.00' ? 'selected="selected"' : '') . ">4</option>";echo "<option value='5.00'> " . ($array['roastturkey'] == '5.00' ? 'selected="selected"' : '') . ">5</option>";echo "<option value='6.00'> " . ($array['roastturkey'] == '6.00' ? 'selected="selected"' : '') . ">6</option>";echo "<option value='7.00'> " . ($array['roastturkey'] == '7.00' ? 'selected="selected"' : '') . ">7</option>";echo "<option value='8.00'> " . ($array['roastturkey'] == '8.00' ? 'selected="selected"' : '') . ">8</option>";echo "<option value='9.00'> " . ($array['roastturkey'] == '9.00' ? 'selected="selected"' : '') . ">9</option>";echo "<option value='10.00'> " . ($array['roastturkey'] == '10.00' ? 'selected="selected I'm using this code, but cannot get the data that's inside the DB to populate the dropdown value. I want it to get the info from the database so that the option that is saved in the database will be new default when the page is loaded. If I don't change it to the previous info it will update the database with the default option rather then the actual option. Hi, I'm trying to populate the previous and next links with an id from mysql. The code below works but also displays ids that do not exist in the database. I want the code to only show me the rows that exist not the ones that do not exist. For example, at this time I have 5 rows. The ids of the rows are 1, 2, 3, 4, 6 when I get to say, id 6 and click on next it displays id 7 instead of going back to 1 or greying out next - meaning there's no more to view. Can someone help?
<?php
include('connection.php');
if(isset($_GET['id'])){
$start = $_GET['id'];
}else{
$start = 0;
}
$sql = mysql_num_rows(mysql_query("SELECT * FROM thetable"));
$result = mysqli_query($con,$sql);
$rows = mysql_fetch_array($result);
echo $rows['thetable'];
if($start == 0){
echo "Previous «";
}else{
echo "<a href=\"./thepage.php?id=" . ($start - 1) . "\">« Previous </a>";
}
if($start == $sql-1){
echo "Next »";
}else{
echo "<a href=\"./thepage.php?id=" . ($start + 1) . "\">Next »</a>";
}
?>
<?php
// End while loop.
mysqli_close($con);
?>
I am trying to figure out how to display member records after selecting it from the box. I've got the dropdown box working which retrieves the members name but cannot figure out how to populate that members details on the same page? I'm using php/mysql and although I want to display the records I also want a user to update that record aswell, creating it for administrators to update accounts? Any help would be appreciated I've researched that ajax or javascript might be helpful but not totally familiar with them. Hello, I'm trying to populate a dropdown box in a RSForm using this code:
//<code>
$db = JFactory::getDbo();
$db->setQuery("SELECT Bruel_ID FROM mpctz_rsform_bruels");
return $db->loadObjectList();
//</code>
However, it displays nothing in the box and some code outside of it (see attached file). Can anyone help?Thanks, Dani Attached Files APNAE.jpg 16.92KB 0 downloads Basically, I have a database table called 'users' and I would like to populate a drop down box with these values of 'users'. How?? - to call upon the values is this: 'upduser2' Right now, all I am using is a text box, in where you have to type in the users name manually (this is so an admin can change variables and settings according to that current user). This is what I am using so far: <h3>Update User Level</h3> <? echo $form->error("upduser"); ?> <table> <form action="adminprocess.php" method="post"> <tr> <td> Username:<br /> <input type="text" name="upduser" maxlength="30" value="<? echo $form->value("upduser"); ?>" /></td> <td> Level:<br /> <select name="updlevel"> <option value="1">1 </option> //example settings <option value="9">9 </option> </select></td> <td><br /> <input type="hidden" name="subupdlevel" value="1" /> <input type="submit" value="Update Level" /></td> </tr> </form> </table></td> </tr> Much help would be appreciated. How would I force a certain table format and then populate it with the SQL results in their respective columns and rows? i.e. Code: [Select] +------------------+----------+----------+----------+ | | Col 1 | Col 2 | Col 3 | +-------------------+----------+----------+----------+ | row 1 lab data | 16777216 | | 573 | +-------------------+----------+----------+----------+ | row 2 lab data | 23454235 | 87247247 | 65743 | +-------------------+----------+----------+----------+ | row 3 lab data | 16777216 | 47832364 | | +-------------------+----------+----------+----------+ Currently I'm just using a while loop to populate it horizontally, but that doesn't work for row 1. Code: [Select] <?PHP while($row = mysql_fetch_array($result) { ?> blah blah blah html here <?PHP echo $row[0]; ?> more html <?PHP echo $row[1]; ?> and so forth <?PHP } ?> It ends up producing this: Code: [Select] +------------------+----------+----------+----------+ | | Col 1 | Col 2 | Col 3 | +-------------------+----------+----------+----------+ | row 1 lab data | 16777216 | 573 | | +-------------------+----------+----------+----------+ | row 2 lab data | 23454235 | 87247247 | 65743 | +-------------------+----------+----------+----------+ | row 3 lab data | 16777216 | 47832364 | | +-------------------+----------+----------+----------+ Hi, Can someone help me with the following problem... I am populating a html table with results from a mysql query. These results populate the 1st of four columns. The second column is a "RAG STATUS" dropdown menu - so GREEN/AMBER/RED. When this is selected I want it to change the colour of the corresponding row it is on. I have had a play around but can only get it to change the colour of the first row, no matter which dropdown menu I change. Code is below. If anything is not clear please let me know. Any help appreciated Code: [Select] <?php include ("commonTop.php"); include("dbvariables.php"); include("functions.php"); ?> <script type="text/javascript"> function changeBGCol(status) { document.getElementById("colour").bgColor=status; } </script> <?php $Checkout_ID = 2; $result = mysql_query( "SELECT Task FROM Task T, Checkout C Where T.Checkout_ID = C.Checkout_ID and C.Checkout_ID= $Checkout_ID" ) or die("SELECT Error: ".mysql_error()); $num_rows = mysql_num_rows($result); echo "This will be sent to the following recepients $num_rows records.<P>"; echo "<table width=70% border=3>\n"; echo "<tr><th>Check</th><th>STATUS</th><th>JIRA</th><th>Comments</th></tr>"; while ($get_info = mysql_fetch_row($result)){ echo "<tr id=colour>\n"; foreach ($get_info as $field) echo "\t<td><font face=arial size=1/>$field</font></td>\n"; echo "\t<td><select name='Status'> <option value='None'>-- Choose --</option> <option onclick='changeBGCol(this.value)' value='green' >GREEN</option> <option onclick='changeBGCol(this.value)' value='orange'>AMBER</option> <option onclick='changeBGCol(this.value)' value='red'> RED</option> </select></td>"; echo "\t<td><input type='text' name='JIRA'></td>"; echo "\t<td><input type='text' name='Comments'></td>"; echo "</tr>\n"; } print "</table>\n"; ?> [code] </code> trying to get a drop-down menu (in a form) to work that needs to get populated from a table table called : CarCategory in this table are 2 columns called CarCategoryID (unique number from 1-18) CarCategoryDesc (actual name of category.. e.g. 'convertible') link : http://98.131.37.90/postPart.php I'm a total novice.. and can't figure out why the first is not working and the second (country) is working code : <!--NOT WORKING ... why not ?? should show drop down menu--> <label> <div align="center"> <select name="carcategory" id="CarCategory" class="validate[required]" style="width: 200px;"> <option value="">Select Car Category from list...</option> <?php while($obj_queryCarCategory = mysql_fetch_object($result_queryCarCategory)) { ?> <option value="<?php echo $obj_queryCarCategory->CarCategoryID;?>" <?php if($obj_queryCarCategory->CarCategoryID == $UserCountry) { echo 'selected="selected"'; } ?> > <?php echo $obj_queryCarCategory->CarCategoryDesc;?></option> <?php } ?> </select> </div> </label> <!-- working ! --> <label> <div align="center"> <select name="country" id="Country" class="validate[required]" style="width: 200px;"> <option value="">Select...</option> <?php while($obj_queryCountry = mysql_fetch_object($result_queryCountry)) { ?> <option value="<?php echo $obj_queryCountry->CountryID;?>" <?php if($obj_queryCountry->CountryID == $UserCountry) { echo 'selected="selected"'; } ?> > <?php echo $obj_queryCountry->CountryName;?></option> <?php } ?> </select> </div> </label> Ok, so i got this website project dropped in my lap, and I'm stuck not really having done much php coding ever. I have a database which is linked already, and it was working when pulling data from a specific table. The problem arose when I was asked to make it work with other tables. I have a table with the table names in it, and the drop down field to select the table populates. The next field is a multiple select field that is supposed to populate report dates from the previously selected table, and then finally the last multiple select field is supposed to populate with names that match the dates selected from the previous field. The last one I can live without, as the existing code takes into account if the name selected doesn't exist in the table with the selected date, but at the moment the date field just comes up blank. Any help would be greatly appreciated. Hi!! the question look simple at his base because I will receive TONS of answer saying ... " hey men use javascript OR ajax " but I don't want to use these... I want to populate the second dropdown menu dynamicly with PHP code. and sql query. why?? because I have over 43000 possibility and doing a script manually is impossible. the database is changing every hour. this is the code of my working page. the form NOTE: i REMOVE ALL DB CONNECTION FOR SECURITY PURPOSE. THANKS FOR YOUR UNDERTANDING. <!doctype html public "-//w3c//dtd html 3.2//en"> <html> <head> <title>(Type a title for your page here)</title> </head> <body > <img src="http://www.scale24-25.com/images/banners/banner.jpg" alt="banner" width="997" height="213" border="0" usemap="#Map" /> <map name="Map" id="Map"> <area shape="poly" coords="0,100,85,102,92,55,108,50,326,51,323,7,3,3" href="http://www.hobby-shop.qc.ca" alt="hobby-shop" /> <area shape="poly" coords="672,57,891,53,887,4,995,4,985,108,673,102" href="http://www.hobby-shop.qc.ca" alt="hobby-shop" /> <area shape="poly" coords="326,13,330,53,98,54,90,92,670,99,668,54,889,51,886,5" href="http://www.scale-auto-style.com" alt="" /> </map> <?php if (isset($_POST['todo']) && $_POST['todo'] == "search") { $todo=$_POST['todo']; $manufacturer_reel=$_POST['manufacturer_reel']; $query="select * from kit where "; ////////// Including manufacturer_reel field search //// if(strlen($manufacturer_reel) > 0 ){ $query.= " manufacturer_reel='$manufacturer_reel' and "; } //// End of class field search /////////// $query=substr($query,0,(strLen($query)-4)); echo $query; echo "<br><br>"; $nt=mysql_query($query); echo mysql_error(); // End if form submitted }else{ echo "<form method=post action='search-keyword.php?go'><input type=hidden name=todo value=search>"; ?> <table width="960" border="0"> <tr> <td colspan="3"><p align="center"></td> </tr> <tr> <td><div align="right"></div></td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td><div align="right">Echelle du modele</div></td> <td align="center"> <?php // strat of drop down /// $q=mysql_query("SELECT DISTINCT scale FROM kit ORDER BY scale"); echo '<select name="scale"><option value="scale">Please Choose an Option</option>'; while($row = mysql_fetch_array($q)) { $thing = $row['scale']; echo '<option>'.$thing.'</option>'; } echo "</select>"; echo " <br> \n"; echo " <br> \n"; ?></td> <td><div align="left">Scale of model</div></td> </tr> <tr> <td> </td> <td> </td> <td><div align="right"></div></td> </tr> <tr> <td><div align="right">Nom du manufacturier automobile</div></td> <td align="center"><?php // strat of drop down /// $q=mysql_query("SELECT DISTINCT manufacturer_reel FROM kit ORDER BY manufacturer_reel"); echo '<select name="manufacturer_reel"><option value="reel manufacturer">Please Choose an Option</option>'; while($row = mysql_fetch_array($q)) { $thing = $row['manufacturer_reel']; echo '<option>'.$thing.'</option>'; } echo "</select>"; // end of drop down /// echo " <br> \n"; echo " <br> \n"; // end of drop down /// ?></td> <td><div align="left">Name Of vehicule manufacturer</div></td> </tr> <tr> <td> </td> <td> </td> <td><div align="right"></div></td> </tr> <tr> <td><div align="right">Nom du manufacturier de modele reduit</div></td> <td align="center"><?php // start of drop down /// $q=mysql_query("SELECT DISTINCT manufacturer_kit FROM kit ORDER BY manufacturer_kit"); echo '<select name="manufacturer_kit"><option value="kit manufacturer">Please Choose an Option</option>'; while($row = mysql_fetch_array($q)) { $thing = $row['manufacturer_kit']; echo '<option>'.$thing.'</option>'; } echo "</select>"; // end of drop down /// echo " <br> \n"; echo " <br> \n"; ?></td> <td><div align="left">Name Of kit manufacturer</div></td> </tr> <tr> <td><div align="right"></div></td> <td> </td> <td> </td> </tr> <tr> <td><div align="right">Annee de fabrication du Vehicule</div></td> <td align="center"><?php // strat of drop down /// $q=mysql_query("SELECT DISTINCT year_prod_reel FROM kit ORDER BY year_prod_reel"); echo '<select name="year_prod_reel"><option value="vehicules year manufactured">Please Choose an Option</option>'; while($row = mysql_fetch_array($q)) { $thing = $row['year_prod_reel']; echo '<option>'.$thing.'</option>'; } echo "</select>"; // end of drop down /// echo " <br> \n"; echo " <br> \n"; ?></td> <td><div align="left">Year of production of the vehicule</div></td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td align="center"> </td> <td> </td> </tr> <tr> <td><div align="right"><strong></strong></div></td> <td align="center"> <?php echo " <br><input type=submit value=Search name='name' action='search-keyword.php?go' > </form> "; } ?> <td><div align="left"><strong></strong></div></td> </body> </html> AND THE PAGE RESULT <!doctype html public "-//w3c//dtd html 3.2//en"> <html> <head> <title>(Type a title for your page here)</title> </head> <body > <p align="center"><img src="http://www.scale24-25.com/catalog/images/banners/banner.jpg" alt="banner" width="997" height="213" border="0" usemap="#Map" /> <map name="Map" id="Map"> <area shape="poly" coords="0,100,85,102,92,55,108,50,326,51,323,7,3,3" href="http://www.hobby-shop.qc.ca" alt="hobby-shop" /> <area shape="poly" coords="672,57,891,53,887,4,995,4,985,108,673,102" href="http://www.hobby-shop.qc.ca" alt="hobby-shop" /> <area shape="poly" coords="325,11,329,51,97,52,89,90,669,97,667,52,888,49,885,3" href="http://www.scale-auto-style.com" alt="" /> </map></p> <table width="920" border="0"> <tr> <td width="359"><p class="style5">You will find some TBC. TBC is for "To Be Confirmed". If somebody know the missing information ( TBC ) it will be appreciate to send it to me at this mail: <a href="mailto:info@hobby-shop.qc.ca">info@hobby-shop.qc.ca</a> <br /> <br /> thanks in advance for your help</p> </td> <td width="161"> </td> <td width="386"> <div align="right"> <p>This logo <img src= 'http://www.scale24-25.com/images/PDF_logo.gif' width='50' height='50'/> mean that you can download a PDF file. To read it you need minimum Acrobat reader and you can download it <a href="http://get.adobe.com/reader/">here</a></p> <p>Some link will return a TBC. Sorry for any inconveniant. as soon as we will receive or do the PDF it will be updated.</p> </div></td> </tr> </table> <br> <?php if (isset($_POST['todo']) && $_POST['todo'] == "search") { $todo=$_POST['todo']; $name=$_POST['manufacturer_reel']; $name1=$_POST['manufacturer_kit']; $name2=$_POST['year_prod_reel']; $name3=$_POST['scale']; //-query the database table for the post field $sql="SELECT kit_id, kit_number, kit_name, description, manufacturer_kit, manufacturer_reel, scale, engine_detail, year_prod_kit, year_prod_reel, image_id, image_id1, image_id2 FROM kit "; $sqlOperand="WHERE"; if ($name != "reel manufacturer") { $sql = $sql . $sqlOperand . " manufacturer_reel LIKE '%" . $name ."%' "; $sqlOperand = " AND "; } if ($name1 != "kit manufacturer") { $sql = $sql . $sqlOperand . " manufacturer_kit LIKE '%" . $name1 ."%' "; $sqlOperand = " AND "; } if ($name2 != "vehicules year manufactured") { $sql = $sql . $sqlOperand . " year_prod_reel LIKE '%" . $name2 ."%' "; $sqlOperand = " AND "; } if ($name3 != "scale") { $sql = $sql . $sqlOperand . " scale LIKE '%" . $name3 ."%' "; $sqlOperand = " AND "; } if ($sqlOperand == "WHERE") { echo "<p>Please enter a search query</p>"; } else { // echo '<img src="web-design/sorry.jpg" alt="sorry">'; // echo "Sorry nothing match your selection / Desolle rien ne correspond a votre selection"; // echo "run sql: <BR> $sql <BR> and display results"; } //-run the query against the mysql query function $result=mysql_query($sql); //-make the header of the table echo " <table align=center width=\"1340\" border=\"\">\n"; echo " <tr>\n"; echo" <td nowrap align=center width='95'> kit manufacturer \n"; echo" <td nowrap align=center width='55'> scale \n"; echo" <td nowrap align=center width='90'> kit number \n"; echo" <td nowrap align=center width='290'> kit name \n"; echo" <td nowrap align=center width='400'> description \n"; echo" <td nowrap align=center width='125'> vehicule year \n"; echo" <td nowrap align=center width='80'> complete engine detail\n"; echo" <td nowrap align=center width='80'> Select Picture to get bigger\n"; echo" <td nowrap align=center width='75'> instruction sheet\n"; echo" <td nowrap align=center width='75'> box contain\n"; echo " <tr>\n"; //-create while loop and loop through result set while($row=mysql_fetch_array($result)){ $description =$row['description']; $manufacturer_kit=$row['manufacturer_kit']; $scale=$row['scale']; $manufacturer_reel=$row['manufacturer_reel']; $kit_id=$row['kit_id']; $kit_number=$row['kit_number']; $kit_name=$row['kit_name']; $engine_detail=$row['engine_detail']; $year_prod_reel=$row['year_prod_reel']; $image_id=$row['image_id']; $image_id1=$row['image_id1']; $image_id2=$row['image_id2']; //-create table of item during he while loop echo " <table align=center width=\"1340\" border=\"\">\n"; echo" <td nowrap align=center width='95'> $manufacturer_kit \n"; echo" <td nowrap align=center width='55'> $scale \n"; echo" <td nowrap align=center width='90'> $kit_number \n"; echo" <td nowrap align=center width='290'> $kit_name \n"; echo" <td nowrap width='400'> $description \n"; echo" <td nowrap align=center width='125'> $year_prod_reel \n"; echo" <td nowrap align=center width='80'> $engine_detail \n"; echo" <td nowrap width='80'> <a href=".$image_id."> <img src='".$image_id."' width='75' height='50' border='0'/>"; echo" <td nowrap width='75'> <a href= ".$image_id1."> <img src= 'http://www.scale24-25.com/images/PDF_logo.gif' width='50' height='50' border='0'/>"; echo" <td nowrap width='75'> <a href=".$image_id2."> <img src='http://www.scale24-25.com/images/PDF_logo.gif' width='50' height='50' border='0'/>"; echo " </tr>\n"; echo " </table>\n"; echo " </tr>\n"; echo " </table>\n"; } } else{ echo "<p>Please enter a search query</p>"; } ?> </body> </html> YOU CAN SEE IN THE FORM i HAVE A DROP DOWN MENU CALL Name Of vehicule manufacturer .. IN VACT THIS IS THE REAL CAR MANUFACTURER EX: TOYOTA, gmc ETC.. WHEN THE USER WILL SELECT ONE OF THESE AN OTHER DROPDOWN ( NOT SHOWN ) WILL DISPLAY EVERY MODEL FOUND IN THE DATABASE IN RELATION WITH THE MANUFACTURE. IN FACT IT'S LOCATED IN THE TABLE. SO HOW I CAN GET THIS RELATION?? YOURS SEBASTIEN |
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