PHP - Working With The Values Of Multiple Tables
hi everybody simply love this forum because i always get the question perfectly answered. i am here this time with a rather complicated question: i am creating a simple duty plan for different departments for exeample department #1 is "Tech" and department #2 is "Service" different employees working in these departments change their dutys and will are sent to another department or section or go on holidays. this is why i have at least 4 different mysql tables to store the data:- personel(storing the personal information of the workers) dutyplan(storing the week's working daysy of the workers) departments(storing the starting and ending dates of the department change) vacation(stores the start and ending dates of the vacations) in all the tables the common id is the pid which is issued unique to every worker. i am still able to work only with the 1st two tables. i can edit and create new plans for the weeks for employees working in the departments with the following php code(submitting only to edit the plan) if i add a date range for example Monday the 24th of January to Sunday the 30th of January for an employee working in the Tech department to work a few days in service department, it will show the employee in the week on the plan of both departments. if both department heads edit the plan without communicating to each other, and knowing on which date the worker goes out and in to the department, the 1st one will plan him for the whole week on his dutyplan and the second department head will overwrite this plan(if edited) or if creating a new plan(create the duty of the worker also one more time). i want to avoid this confusion and manual work. the same is with the vacation or sickness tables, if the employee has vacation, the program should check and return the selected value in the pulldown menu with the value stored in the vacation or sickness tables appropriate to the date in the plan table. ************************************************************************ form.php: <? require "config.php"; $result=mysql_query("select * from personel, dutyplan, department, vacation WHERE personel.pid = dutyplan.pid and personel.pid = vacation.pid and dp.pid = departments.pid and departments.Section = 'Service' order by dp.id asc"); ?> <? while($row=mysql_fetch_assoc($result)){ ?> // after that i create table, displaying all the days of the week from monday to sunday and use this code <tr> <td><? echo $row['FirstName'] . " " . $row['LastName']; ?>: </td> <td> <select name="monday_<? echo $row['id']; ?>" id="select1"> <option><? echo $row['Mo']; ?></option> <option>Duty</option> <option>Free</option> <option>Vacation</option> //the same way down to sunday, for every day the different options to be selected. it displays the records perfectly, as long as there is no change of department planed and the vacation must also be selected manually. +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ update.php <? if($_POST['Submit']){ require "includes/config.php"; $result=mysql_query("select * from dutyplan, departments, vacation order by dutyplan.id asc"); while($row=mysql_fetch_assoc($result)){ $mo=$_POST["monday_".$row[id]]; $tu=$_POST["tuesday_".$row[id]]; $we=$_POST["wednesday_".$row[id]]; $th=$_POST["thursday_".$row[id]]; $fr=$_POST["friday_".$row[id]]; $sa=$_POST["saturday_".$row[id]]; $su=$_POST["sunday_".$row[id]]; mysql_query("update dp set Mo='$mo', Tu='$tu', We='$we', Th='$th', Fr='$fr', Sa='$sa', Su='$su' where id='$row[id]'"); } echo "Records updated"; } ?> **************************************************** how would you gueys solve this problem? many thanks in advance Similar Tutorials
Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell
Hi guys, I'm trying to query two tables for different data and echo the results that match both tables. Here are the tables I have and the query I'm trying to run. (Table) qc_reports (Fields) id report_date report_lot_number report_po report_supplier report_buyer report_inspectedby report_pulptemprange report_carrierconditions report_supplierclaim report_carrierclaim report_temprecorder report_temprange_N report_temprange_M report_temprange_B report_suppliercontact report_contactedby report_time report_comments (Table) qc_lots (Fields) id report_id lot_temprange lot_commodity lot_rpcs lot_brand lot_terms lot_cases lot_orgn lot_estnum lot_avgnum This is the query that I'm trying to do. Code: [Select] <?php $sql = "SELECT * FROM qc_reports, qc_lots WHERE "; if (!empty($start_date) and !empty($end_date)) $sql .= " qc_reports.report_date BETWEEN '$start_date' and '$end_date' AND "; if (!empty($search_fronteralot)) $sql .= " qc_reports.report_lot_number = '$search_fronteralot' AND "; if (!empty($search_buyer)) $sql .= " qc_reports.report_buyer = '$search_buyer' AND "; if (!empty($search_supplier)) $sql .= " qc_reports.report_supplier = '$search_supplier' AND "; if (!empty($search_po)) $sql .= " qc_reports.report_po = '$search_po' AND "; if (!empty($search_carrierconditions) and $search_carrierconditions != 'all') $sql .= " qc_reports.report_carrierconditions = '$search_carrierconditions' AND "; if (!empty($search_commodity) and $search_commodity != 'all') $sql .= " qc_lots.lot_commodity = '$search_commodity' AND "; if (!empty($search_inspectedby)) $sql .= " qc_reports.report_inspectedby = '$search_inspectedby' AND "; $sql = substr($sql, 0, -4); $query = mysql_query($sql); $numrows = mysql_num_rows($query); ?> RESULTS - <?php echo $numrows; ?> <hr> <table width='500'><tr><td><b>Date</b></td><td><b>Lot Number</b></td><td><b>PO</b></td><td> </td></tr> <tr> <td> </td> </tr> <?php while ($row = mysql_fetch_assoc($query)) { $id = stripslashes($row['id']); $report_lot_number = stripslashes($row['report_lot_number']); $report_po = stripslashes($row['report_po']); $report_date = stripslashes($row['report_date']); echo "<tr> <td>" . $report_date . "</td></td><td>" . $report_lot_number . "</td><td>" . $report_po . "</td><td><a href='view_report.php?id=" . $id . "'>View</a></td> </tr>"; } echo '</table><br><br><br><hr><br><br>'; } ?> All the variables are passed from a HTML form with $_POST. I need the search to work like this: If there is a value in a form field then the query gets appended with that value but when it gets to the $search_commodity it needs to search the second table (qc_lots) and check for the results. Any results that match have to be matched to the results from the first table (qc_reports) and display (echo) only qc_reports that match to both tables. The only common field is the report_id on the qc_lots table and the id on the qc_reports table. I'm stuck and need some guidance. Can someone help please? Back with a new problem. I have 8 tables interconnected. Table#1 - Users user_id | name Table#2 - user_categories id | user_id | category_id Table#3 - user_cities id | user_id | city_id Table#4 - user_dates id | user_id | dates_available Table#5 - categories category_id | category_name Table#6 - cities city_id | city_name Table#7 - provinces province_id | province_name Table#8 - categories country_id | country_name Each user will have multiple categories, cities and available dates listed in these tables. I simply want to retrieve and list each user and their data on a page. Here's my query. $url_city = 1; $url_category = 2; $url_date = '2021-07-19'; $find_records = $db->prepare("SELECT user_categories.*, categories.*, user_cities.*, cities.*, provinces.*, countries.*, user_dates.*, users.* FROM users LEFT JOIN user_categories ON users.user_id = user_categories.user_id LEFT JOIN user_cities ON users.user_id = user_cities.user_id LEFT JOIN user_dates ON users.user_id = user_dates.user_id LEFT JOIN categories ON user_categories.category_id = user_categories.category_id LEFT JOIN cities ON user_cities.city_id = cities.city_id LEFT JOIN provinces ON cities.province_id = provinces.province_id LEFT JOIN countries ON provinces.country_id = countries.country_id WHERE user_cities.city_id = :city_id AND user_categories.category_id = :category_id AND user_dates.date_available = :date_available GROUP BY users.user_id"); $find_records->bindParam(':city_id', $url_city); $find_records->bindParam(':category_id', $url_category); $find_records->bindParam(':date_available', $url_date); $find_records->execute(); $result_records = $find_records->fetchAll(PDO::FETCH_ASSOC); if(count($result_records) > 0) { foreach($result_records as $row) { $user_id = $row['user_id']; $name = $row['name']; $country_id = $row['country_id']; $country_code = $row['country_code']; $country_name = $row['country_name']; $province_id = $row['province_id']; $province_code = $row['province_code']; $province_name = $row['province_name']; $city_id = $row['city_id']; $city_name = $row['city_name']; $category_id = $row['category_id']; $category_name = $row['category_name']; } } There are no errors but the above query would only return a single row with only 1 "user" despite having multiple users in the "users" table. If I remove the GROUP BY, then it'll return multiple rows of the same user instead of all the relevant users. So what do you think I am doing wrong with my query? Edited July 20 by imgrooot
Basically I want to add up multiple tables and display a grand total on my page when the radio button is pressed. The radio button has values that connect to my database and the values link to and ID with a price. How can I use this code in order to work out a grand total? Many thanks. I have searched everywhere but found nothing. Hi, My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck. The HTML/PHP code is below: <table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%"> <thead> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> <th>Actions</th> </tr> </thead> <tbody> <?php //QUERY TO SELECT ALL USERS FROM DATABASE $query = "SELECT * FROM users"; $select_users = mysqli_query($connection,$query);
// SET VARIABLE TO ARRAY FROM QUERY while($row = mysqli_fetch_assoc($select_users)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_phone = $row['user_phone']; $user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id'];
// POPULATES DATA INTO THE TABLE echo "<tr>"; echo "<td>{$user_id}</td>"; echo "<td>{$user_firstname}</td>"; echo "<td>{$user_lastname}</td>"; echo "<td>{$username}</td>"; echo "<td>{$user_phone}</td>";
//PULL SITE STATUS BASED ON SITE STATUS ID $query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} "; $select_site = mysqli_query($connection, $query); while($row = mysqli_fetch_assoc($select_site)) { $site_name = $row['site_name']; echo "<td>{$site_name}</td>"; } echo "<td>{$user_title_id}</td>"; echo "<td>{$user_role_id}</td>"; echo "<td class='table-action'> <a href='#'><i class='align-middle' data-feather='edit-2'></i></a> <a href='#'><i class='align-middle' data-feather='trash'></i></a> </td>"; //echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>"; echo "</tr>"; } ?>
<tr> <td>ID</td> <td>FirstName</td> <td>LastName</td> <td>Username</td> <td>Phone #</td> <td>Location</td> <td>Title</td> <td>Role</td> <td class="table-action"> <a href="#"><i class="align-middle" data-feather="edit-2"></i></a> <a href="#"><i class="align-middle" data-feather="trash"></i></a> </td> </tr> </tbody> <tfoot> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> </tr> </tfoot> </table>
I have a search where I want to be able to search a string of words. The search is going to be looking in 2 different table joined by a left outer join. The tables are "quotes" and "categories". $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; The above mysql statement works and returns values..BUT if say, I search "john" and "funny", and a quote is posted by the user "john", but has a category of "funny" it will output the same quote twice. I was wondering if there was a way to see if a quote has either 1 term or both terms, if so display that quote but only display it once. Below is what the query is outputting. [100] => Array ( [id] => 100 [username] => John [quote] => new test quote blah blah [by] => John [voteup] => 0 [votedown] => 0 [servtime] => 2010-12-02 @ 16:27:03 [label] => Array ( [0] => Historic [1] => Serious [2] => Funny ) ) Here is the code in full. //// $sword = explode(" ",$search); foreach($sword as $sterm){ $srch="%".$sterm."%"; echo"$srch<br />"; $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; $result=mysql_query($sql); while($row=mysql_fetch_object($result)){ $quote[$row->id]['id'] = $row->id; $quote[$row->id]['username'] = $row->username; $quote[$row->id]['quote'] = $row->quote; $quote[$row->id]['by'] = $row->by; $quote[$row->id]['voteup'] = $row->voteup; $quote[$row->id]['votedown'] = $row->votedown; $quote[$row->id]['servtime'] = $row->servtime; $quote[$row->id]['label'][] = $row->label; } echo"<pre>"; print_r($quote); echo"</pre>"; I don't think this is the fastest way of doing this, as it loops for each item in the db, per each keyword that is search. Any help would be great!! -BaSk I am trying to export multiple csv files to download from 2 separate tables in my database. Some background: I have a web app that links to a phpmyadmin database. There are 2 tables in the database (entering and exiting). These tables hold the phone inventory information of employees currently entering or exiting the organization. The fields in my tables a location, firstname, lastname, username, extension, mac, type What I am trying to do is export the data in these 2 tables to CSV (which I have working now) but I need to have multiple CSVs for each. For example, for my exiting table, I need to have one CSV export all the fields in the table and I also need another CSV to export just the location and username field. I have a simple html form with a submit button which is currently working now: <form action="exportexiting.php" method="POST" style="width: 456px; height: 157px"> <div> <fieldset> <legend style="width: 102px; height: 25px"><strong>Entering CSV:</strong></legend> <input name="Export" type="submit" id="Export" value="Export"> </fieldset><br/> </div> </form> This links to my exportexiting.php file: <?php $host = 'localhost'; $user = 'root'; $pass = 'xxxx'; $db = 'PhoneInventory'; $table = 'exiting'; // Connect to the database $link = mysql_connect($host, $user, $pass); mysql_select_db($db); require 'exportcsv.inc.php'; exportMysqlToCsv($table); ?> Then to exportcsv.inc.php: <?php function exportMysqlToCsv($table,$filename = 'export.csv') { $csv_terminated = "\n"; $csv_separator = ","; $csv_enclosed = ''; $csv_escaped = "\\"; $sql_query = "select * from $table"; // Gets the data from the database $result = mysql_query($sql_query); $fields_cnt = mysql_num_fields($result); $schema_insert = ''; for ($i = 0; $i < $fields_cnt; $i++) { $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, stripslashes(mysql_field_name($result, $i))) . $csv_enclosed; $schema_insert .= $l; $schema_insert .= $csv_separator; } // end for $out = trim(substr($schema_insert, 0, -1)); $out .= $csv_terminated; // Format the data while ($row = mysql_fetch_array($result)) { $schema_insert = ''; for ($j = 0; $j < $fields_cnt; $j++) { if ($row[$j] == '0' || $row[$j] != '') { if ($csv_enclosed == '') { $schema_insert .= $row[$j]; } else { $schema_insert .= $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed; } } else { $schema_insert .= ''; } if ($j < $fields_cnt - 1) { $schema_insert .= $csv_separator; } } // end for $out .= $schema_insert; $out .= $csv_terminated; } // end while header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Length: " . strlen($out)); // Output to browser with appropriate mime type, you choose header("Content-type: text/x-csv"); //header("Content-type: text/csv"); //header("Content-type: application/csv"); header("Content-Disposition: attachment; filename=$filename"); echo $out; exit; } ?> Again, this is working perfectly for only exporting all the data from the exiting table into one CSV file. My question is, how can I make my one submit button export the 2 CSV files that I need? Thanks for the help... I have a form where a user can duplicate part of a form like below: I've named the fields with the HTML arrays (ie. "fieldName[]") and came up with this: //--> CONTROLLERS $system_controllers_qty = $_POST['system_controllers_qty']; $system_controllers_make = $_POST['system_controllers_make']; $system_controllers_model = $_POST['system_controllers_model']; $system_controllers_serial_no = $_POST['system_controllers_serial_no']; for ($i = 0; $i < count($system_controllers_qty); $i++) { echo "qty " . clean($system_controllers_qty[$i]) . "<br/>"; echo "make " . clean($system_controllers_make[$i]) . "<br/>"; echo "model " . clean($system_controllers_model[$i]) . "<br/>"; echo "serial_no " . clean($system_controllers_serial_no[$i]) . "<br/>"; } //--> CPUS $system_cpus_qty = $_POST['system_cpus_qty']; $system_cpus_model = $_POST['system_cpus_model']; $system_cpus_serial_no = $_POST['system_cpus_serial_no']; $system_cpus_speed = $_POST['system_cpus_speed']; for ($i = 0; $i < count($system_cpus_qty); $i++) { echo "qty " . clean($system_cpus_qty[$i]) . "<br/>"; echo "model " . clean($system_cpus_model[$i]) . "<br/>"; echo "serial_no " . clean($system_cpus_serial_no[$i]) . "<br/>"; echo "speed " . clean($system_cpus_speed[$i]) . "<br/>"; } //--> DISKS $system_disks_qty = $_POST['system_disks_qty']; $system_disks_make = $_POST['system_disks_make']; $system_disks_model_no = $_POST['system_disks_model_no']; $system_disks_size = $_POST['system_disks_size']; $system_disks_serial_no = $_POST['system_disks_serial_no']; for ($i = 0; $i < count($system_disks_qty); $i++) { echo "qty " . clean($system_disks_qty[$i]) . "<br/>"; echo "make " . clean($system_disks_make[$i]) . "<br/>"; echo "model_no " . clean($system_disks_model_no[$i]) . "<br/>"; echo "size " . clean($system_disks_size[$i]) . "<br/>"; echo "serial_no " . clean($system_disks_serial_no[$i]) . "<br/>"; } //--> MEMORY $system_memory_qty = $_POST['system_memory_qty']; $system_memory_serial_no = $_POST['system_memory_serial_no']; $system_memory_manf = $_POST['system_memory_manf']; $system_memory_part_no = $_POST['system_memory_part_no']; $system_memory_size = $_POST['system_memory_size']; for ($i = 0; $i < count($system_memory_qty); $i++) { echo "qty " . clean($system_memory_qty[$i]) . "<br/>"; echo "serial " . clean($system_memory_serial_no[$i]) . "<br/>"; echo "manf " . clean($system_memory_manf[$i]) . "<br/>"; echo "part_no " . clean($system_memory_part_no[$i]) . "<br/>"; echo "size " . clean($system_memory_size[$i]) . "<br/>"; } This just outputs all the fields I post at the moment. Say I have 3 different disk types, it's going to loop 3 times. Is it possible to make this all into 1 giant query or am I better off doing each query separately? Each section is a different table. Hey guys. I have ran into a problem once again. I want to print a list of data I have in my database being monsters (ID, Name, HP, attack) I want to be able to print them fromt he database then get the "ID" of the monster being selected by a submit button to give the id of that row in some form (a POST?) so i can get the information for that monster in a SELECT when the button is hit. I will try show you what im trying to do. Code: [Select] //Grt the id from the table print at the bottom. $monster_id = $_POST["monsterid"]; //this is at the top to get stats on the monster the user has selected to fight $query="SELECT * FROM monsters WHERE id='$monster_id'"; $result=mysql_query($query); $result=mysql_fetch_array($result); $monster_exp=$result["exp"]; $exp_dead = round(($monster_exp/100) * 10); $monster_hp =$result["hp"]; $goldwon =$result["gold"]; $mindam =$result["mindam"]; $maxdam =$result["maxdam"]; // my battle code goes here using the stats I want above. ------------------------------------------------------------------------------ //This is where the user selects the monster they want to fight. $query="SELECT * FROM monsters"; $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); $i=0; <form action="training.php" method="post"> <table border='0' width="400" class="tablee"> <tr> <th>Monster</th> <th>Level</th> <th>HP</th> <th>Protection</th> <th>Fight?</th> </tr> <? $query="SELECT * FROM monsters"; $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); $i=0; while ($i < $num) { $id=mysql_result($result,$i,"id"); $name=mysql_result($result,$i,"name"); $level=mysql_result($result,$i,"lvl"); $hp=mysql_result($result,$i,"health"); $pro=mysql_result($result,$i,"pro"); ?> <tr> <th><? echo $mon_name; ?> </th> <th><? echo $mon_level; ?> </th> <th><? echo $mon_hp; ?> </th> <th><? echo $mon_pro; ?> </th> <th><input type="hidden" value="<? echo $mon_id; ?>" name="monsterid" /> <input type="submit" value="Fight!" name="submit" /></th> </tr> <? $i++; } ?> </table> </form> I hope this makes sense because I am really having problems. My gues is use an array but I could get it to work. PS: I did a get and it sends ALL the IDs instead of the selected row. Thanks for any help guys, Ruddy Hey guys, I am kind of new to php but I am stuck on this question. I have a mySQL database and table set up called members. I have some data in the table and I want to be able to add certain things to a paticular row in the table based off the ID number of the row. One of the values of the table is an auto incremeted ID number. I want to add a text value called message to a specified ID number. How do I go about doing that. I have this code already but it doesn't seem to work. Code: [Select] $sql = "INSERT INTO members (message) VALUES ('$_POST[message]',(SELECT id FROM members WHERE id='$_POST[id]'))"; Any Ideas? Thanks When I echo the POST, it echoes the correct value. The MySQL portion seems to just ignore it all together. I've tried changing the dropdown option to just a text field, same thing occurred. I have text fields right above this particular one that update just fine with the SAME exactly scripting. if POST, update query, done. Works. This one for some reason will not. MySQL portion: if ($_POST['bUpdate']){ mysql_query("UPDATE `Patients` SET `b` = '$_POST[bUpdate]' WHERE `id` = '".$_GET['id']."'"); } echo $_POST['bUpdate']; Form Portion: Code: [Select] <tr onmouseover="color(this, '#baecff');" onmouseout="uncolor(this);"> <td width="310" colspan="2" align="center"><span class="fontoptions">Postcard Status </span><br /> <? if ($data['b'] == 1){ echo '<select name="bUpdate"><option value="1" selected>Yes</option><option value="0">No</option></select>'; } else { echo '<select name="bUpdate"><option value="1">Yes</option><option value="0" selected>No</option></select>'; } ?> </td> </tr> Hi guys! Once again i require your endless talents! I have 2 tables in my mysql DB. One table is a list of products a store offers, the other is the cart of the user. I need to find the most efficient way or retrieving the images and prices from the LIST OF PRODUCTS table based on the list of PRODUCT NUMBERS stored in the cart table of the user. List of products offered ************************* Prod # * Price * img src * ************************* 001 * 19.99* imgs/pic1.jpg * 002 * 29.99 * imgs/pic2.jpg * ************************* User's Cart ********************* Prod # * quantity * size * ********************* 001 * 10 * m * 002 * 4 * s * ******************** Basically i just want to retrieve ONLY the rows that i need (ones that the user has added to his/her cart) and ASSOCIATE the img src with the quantity and size so that i can lay it out in a table on a view_cart page... If you want a good laugh just take a look at what ive done so far... Code: [Select] $cart = mysql_query("SELECT * FROM ".$session.""); $cart_row_count = mysql_fetch_assoc($cart); $cart_row_count = mysql_num_rows($cart_row_count); if($cart_row_count != 0){ $i = 1; while($cart_result = mysql_fetch_assoc($cart)){ ${"product$i"} = $cart_result['product']; ${"size$i"} = $cart_result['size']; $i++; } $i2 = 1; $query = "product = ".${"$product$i2"}." "; while($i2 <= $i){ $i2++; $query .= "AND ".${"$product$i2"}." "; } } CREATE TABLE `members` ( `id` int(4) NOT NULL auto_increment, `username` varchar(65) NOT NULL default '', `password` varchar(65) NOT NULL default '', PRIMARY KEY (`id`) ) TYPE=MyISAM AUTO_INCREMENT=2 ; Hi, i would like to add values automattically from a form that my users fill out that corresponds to their login details. The form templete is above. Thanks! Hi,
I am a bit of a MYSQL newbie so please bear with me. I have a database created about football/soccer stats. The database at the moment contains the following tables but more maybe added:
Players
Clubs
Seasons
Competitions
I will create php pages for these tables that add, edit and delete records for each. But the problem I can't get my head around is how to add a record that uses data from other tables, for example we would add a...
player -> club-season-competition
Lets say we want create a player called 'Joe Bloggs' and want to add his details, we need somehow for the page to display an option for club, season and competition. Maybe they can be drop down boxes but how does one fill those drop down boxes with records that are already added in the database for each table?
Thanks
$username = $_POST['uid']; $email = $_POST['mail']; $password = $_POST['pwd']; $passwordRepeat = $_POST['pwd-repeat']; $date = $_POST['date2']; $stream = $_POST['relationship']; $sql1 = "INSERT INTO users (uidUsers, emailUsers, pwdUsers, relationship) VALUES (?, ?, ?, ?);"; $sql2 = "INSERT INTO Family1 (username, application_filed, relationship) VALUES (?, ?, ?);"; $sql3 = "INSERT INTO Family2 (username, application_filed, relationship) VALUES (?, ?, ?);"; mysqli_query($sql1, $conn); mysqli_query($sql2, $conn); mysqli_query($sql3, $conn); $stmt = mysqli_stmt_init($conn); if (!mysqli_stmt_prepare($stmt, $sql2)) { header("Location: ../signup.php?error=sqlerror"); exit(); } else { mysqli_stmt_bind_param($stmt, "sss", $username, $date, $stream); $result = mysqli_stmt_get_result($stmt); if ($row = mysqli_fetch_assoc($result)) ($username==$_SESSION['uid'] and $stream =='nursing'); mysqli_stmt_execute($stmt); } if (!mysqli_stmt_prepare($stmt, $sql3)) { header("Location: ../signup.php?error=sqlerror"); exit(); } else { mysqli_stmt_bind_param($stmt, "sss", $username, $date, $stream); $result = mysqli_stmt_get_result($stmt); if ($row = mysqli_fetch_assoc($result)) ($username==$_SESSION['uid'] and $stream =='doctoral'); mysqli_stmt_execute($stmt); } if (!mysqli_stmt_prepare($stmt, $sql1)) { header("Location: ../signup.php?error=sqlerror"); exit(); } if (!mysqli_stmt_prepare($stmt, $sql1)) { header("Location: ../signup.php?error=sqlerror"); exit(); } else { $hashedPwd = password_hash($password, PASSWORD_DEFAULT); mysqli_stmt_bind_param($stmt, "ssss", $username, $email, $hashedPwd, $stream); mysqli_stmt_execute($stmt); header("Location: ../signup.php?signup=success"); exit(); I was wondering if someone could point me in the right direction. I have this code. They idea I had behind it is to insert values into different tables depending on variables being passed. So when user fills out a form and selects $stream="nursing" I want results to go to table 'users' and 'Family1', but not 'Family2' table. and if user selects $stream='doctoral' results should go to table 'users' and 'Family2', and not go to 'Family1' But with my query I get results go to both table and also users table. And there is no restriction to what users selects, variable $stream being passed no matter what it is. Is this the wrong way to go here? Did I completely mess up the logic? I have 3 tables w/ the following fields: Cities id | state_id | city_name States id | state_name New_cities id | state_id | city_name I am trying to write a script (and still working on it) that will INSERT new cities in cities WHERE New_cities.state_id = Cities.state_id. Obviously I am still in testing and results sort out, but honest to all hell, I might be going about this all wrong, and would appreciate any comments, criticism, assistance or feedback on what I am trying to do. <?php $query = "SELECT * FROM cities, states, new_cities"; if ($results = mysqli_query($cxn, $query)) { $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { if ($row['cities']['state_id'] == $row['new_cities']['new_state_id']) { $insert_city_query = "INSERT INTO cities id, new_state_id, city_name VALUES ('','$new_state_id','$city_name')" or mysqli_error(); } //if ($row['cities']['state_id'] == $row['new_cities']['new_state_id']) echo "$row[new_city_name]<br />"; } //while ($row = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) } //if ($results = mysqli_query($cxn, $query)) ?> $query = mysql_query("SELECT COUNT(tickets.id),tickets.id,tickets.status,tickets.date,tickets.question,tickets.title,users.position FROM tickets,users WHERE tickets.id='$existing' users.username='$username'"); How do I get it so it selects data from the table tickets where id='$existing', but I also want to get a user's (who is viewing the ID) position (rank). $username is a session. So, any thoughts on how I would do so? My updated code: <?php session_start(); include("../includes/mysql.php"); include("../includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <link href="../style.css" rel="stylesheet" type="text/css" /> <title><?php echo $title; ?></title> </head> <body> <div id="container"> <div id="content"> <div id="left"> <div class="menu"> <?php include("../includes/navigation.php"); ?> <div class="menufooter"></div> </div> <?php include("../includes/menu.php"); ?> </div> <div id="middle"> <?php $existing = $_POST['existing']; $ip = $_SERVER['REMOTE_ADDR']; $username = $_SESSION['user']; $query = mysql_query("SELECT COUNT(tickets.id),tickets.id,tickets.status,tickets.date,tickets.question,tickets.title,users.position FROM tickets,users WHERE tickets.id='$existing' OR users.username='$username'"); $get = mysql_fetch_assoc($query); if(!$existing) { echo ' <div class="post"> <div class="postheader"><h1>Error</h1></div> <div class="postcontent"> <p>You have not enetered in a ticket ID. Please go back and do so.</p> </div> <div class="postfooter"></div> </div> '; } elseif($get['COUNT(id)'] < 1) { echo ' <div class="post"> <div class="postheader"><h1>Error</h1></div> <div class="postcontent"> <p>The ticket ID you are trying to use doesnt exist. Please go back or submit another ticket.</p> </div> <div class="postfooter"></div> </div> '; } elseif($get['tickets.ip']==$ip || $get['user.position'] >= 1) { $status["tickets.status"]["0"] = "Waiting for support..."; $status["tickets.status"]["1"] = "Waiting for user..."; $status["tickets.status"]["2"] = "Ticket Closed..."; $status["tickets.status"]["3"] = "Ticket Opened..."; echo ' <div class="post"> <div class="postheader"><h1>View Ticket Status - ID '. $get["id"] .'</h1></div> <div class="postcontent"> <p>Title: '. $get["tickets.title"] .' - Posted on: '. $get["tickets.date"] .'</p> <p>Ticket Status: '. $status[$get["tickets.status"]] .'</p> <p>Question: '. nl2br($get["tickets.question"]) .'</p> </div> <div class="postfooter"></div> </div> '; } else { echo ' <div class="post"> <div class="postheader"><h1>Error</h1></div> <div class="postcontent"> <p>This is not your ticket. You only have permission to view your tickets. Please go back.</p> </div> <div class="postfooter"></div> </div> '; } ?> </div> </div> </div> </body> </html> I'm having a hard time grasping how to select data from several tables. Here's the code Code: [Select] <?php require_once "config.php"; $gamedate = $_SESSION['date']; echo "These umpires are not currently scheduled on this date, and have not asked for the day off:<br />"; $umpirelist = Array('umpire 1 name', 'umpire 2 name', 'umpire 3 name'); $dbc = mysql_pconnect($host, $username, $password); mysql_select_db($db,$dbc); foreach($umpirelist as $data) { //now get stuff from a table $sql = "SELECT calendar.date, calendar.ump1, calendar.ump2, calendar.ump3, calendar.ump4, calendar.ump5, vacation.date, vacation.umpire FROM umps, calendar, vacation WHERE umps.full_name = $data AND $gamedate = `calendar.date` AND $gamedate = `vacation.date` AND $data NOT IN ('calendar.ump1', 'calendar.ump2', 'calendar.ump3', 'calendar.ump4', 'calendar.ump5') AND $data NOT IN ('vacation.umpire') order by umps.full_name asc"; $rs = mysql_query($sql,$dbc); $matches = 0; while ($row = mysql_fetch_assoc($rs)) { $matches++; echo "$row[$data]<br />"; } } ?> The table CALENDAR holds the date of the game, who is playing, and what umpires are schedule for that game. it does have a unique "row_number" column as well, but didn't think I'd need it in this select. The table VACATION has the date, and umpire's name that is on vacation. The table UMPS contains the umpires name (same names as the array in the code) and email addresses and login info. I'm getting this error: Quote Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource on line 152 This is line 152 Quote while ($row = mysql_fetch_assoc($rs)) { Can someone please point me in the right direction as to where I'm going wrong? Thanks! Hi, I'm very new to PHP and have managed to get through most of the problems I've encountered so far, but I have got to one point that I can't seem to solve. I have two mysql tables (Categories & Products), I have a page that shows the categories (generated from the categories table) and when a category is selected it lists the products in that category. Due to stock etc. not all categories always have products associated to them. The Category & Product Tables are automatically updated, so what I need to do is only show categories that have products associated to them, both tables have a column category_no, and nothing I've tried so far seems to work. The code I have so far is:- Code: [Select] Require_once('config.php'); Mysql_connect(db_host, db_user, db_password); @mysql_select_db(db_database) or die( "unable to select database"); $query="select * from categories"; $result=mysql_query($query); $num=mysql_numrows($result); Mysql_close(); Thanks Pete I hope this isn't a stupid question. I have written a fairly large site using php and SQL. The site has multiple features (how tos, classifieds, photos, videos, ect) with each section's data housed in its own table. Now I would like to have one highlight from each section appear in boxes on the index page simutaniously. (basically returning one random item from each table when the page is loaded) I know how to call each table individually with sql = mysql_query, however, I fear that calling the database that many times over and over in one page load could be problematic if the site begins to get a lot of traffic. Am I correct in worring about overloading the server and is there a better way to do this?
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