PHP - Header() Simple Question

So say i have this:

Code: [Select]
<link rel="stylesheet" media="all" type="text/css" href="_css/styles.css" />
now the file that is linking to that is 3 directories deep, besides using a rel or absolute link, could i define the path by using something like this

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<link rel="stylesheet" href="<?php require($_SERVER['DOCUMENT_ROOT'] . "/_css/portfolio-styles.css"); ?>" type="text/css" />
but this is actually opening the CSS in the header

thanks for any explanation on how to do this

I have a web site with a user login requirement that has worked splendidly for months.  I also have a development version of my site on my laptop, localhost.  At the moment, I have identical code on both the development and production sites.  I'm getting some header error in production, but not on development.

Is it guaranteed that my page is generating some white space, or is it possible that there may be another issue at hand (I'm fairly non-technical, so I'm grasping here - my web host upgraded to a different PHP version that is creating whitespace in production while development on my laptop is a different version of php, my web host has done something else that is causing this, fill in the blank with your own conspiracy theory)?  Any reading material out there (besides the php.net manual) that explores what may be going on?

Thanks in advance - this community has been wonderfully helpful for me over the last year!

Hi:

Does this header redirection:
Code: [Select]
header("Location: http://www.WebSite.com/Page.php");

Happen on the server, and then get sent to the browser, or is it something that happens on the users computer?

Hi guys, this function below is for card validation, however anycard i enter i get the invalid card number, this is not connected to any gateways, this is just an Luhn card validation demonstration.

can you tell me please why i get that?

<?php
  if ($_POST['pay'])
    {

$cardNo = addslashes(strip_tags($_POST['cardNo']));









function luhnCheck($cardNo) {
    $cardNo = str_replace(" ", "", trim($cardNo));
    if(!is_numeric($cardNo) or strlen($cardNo)>19) return false;
    $skip = $newNum = $total = 0;
    for($i=0;$i<=(strlen($cardNo)-1);$i++) {
        if($skip ==0) {
            $tmpNum = ($cardNo[$i]*2);
            $total += (strlen($tmpNum)==2 ? (substr($tmpNum, 0, 1)+substr($tmpNum, 1)) : $tmpNum);
            $skip = 1;
        }else{
            $total += $cardNo[$i];
            $skip = 0;
        }
    }
    return (($total % 10) == 0);
}

/* Example Usage */
if(luhnCheck($_GET['cc'])) {
    echo("Valid Number.");
}else{
    echo("Invalid Number.");
}





}





?>


<form name="confirm" method="post" action="">

<input type="text" name="cardNo">
 
                <input type="submit" name="pay" value="Pay Now">
                
  </form>

I know it could be a issue with this line if(luhnCheck($_GET['cc'])) { but im wondering where should and how put this cc in my form?

regards

Hello to everyone

I would like to ask for this simple question.. Im trying to put if and else condition on my php code. However this condition is not working..

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if($file == #3#){
echo "No results found";
}else{ echo "results has been found"; }
This variable $file is the result after i used an API.. If the API does not see any results they would return #3# as the result. This means they returned a transaction code of 3 which you can see here http://developer.textapp.net/WebService/TransactionCodes.aspx means that there was nothing to return.

The condition does not function well even if i make 3 or #3# as part of the condition. Can you help me guys?

thanks

Hello everyone! I am a new user and I have a simple question. How do I set a password for a user to log in to my site with PHP? I have no MySQL database just a iOS code/host app. I know this isn’t secure but only me and my friends are on the site. Any help is appreciated. 

I'm teaching myself php and mysql -- and my coding is a little rough.   But what i'm trying to do is display information from a mysql table in another table on a website.  I can do this just fine simply displaying the table, but i want a little something different.  I am only displaying one column of the table, instead of displaying it all in one column, i want to display the information in 5 columns.  for example.....  the table from mysql has names scott, john, james, mary, simon.  with the code I have i can make it display like this:
                                                                                         scott scott scott scott scott
                                                                                         john john john john john
                                                                                         james james james james james
                                                                                         mary mary mary mary mary
                                                                                         simon simon simon simon simon
i want it to diplay like this:
                                                                                          scott john james mary simon
                                                                                          new names will continue down

here is my code:

<?php

require ("connectigb.php");


$result = mysql_query ("SELECT pledgeName FROM pledgewall");

$fields_num = mysql_num_fields($result);


echo "<center> <h1>TSA It Gets Better Pledge Wall</h1>";
echo "<table border='1' align='center' style='width:960px;'><tr>";


while($row = mysql_fetch_row($result))
{
    echo "<tr>";

    // $row is array... foreach( .. ) puts every element
    // of $row to $cell variable
    foreach($row as $cell)
      if ($cell != "") {
for ($j=0; $j<5; $j++) {
        echo "<td>$cell</td>";
   }
   }

    echo "</tr>\n";

}
mysql_free_result($result);
echo "</table></center>";
?>

any ideas on what i can do here, i'm sure this is a simply fix.  i just haven't come across it yet.  thanks for the help in advance.

Hi.  I have an ID in md5 format but in the database its not.  I pass the md5 ID to a page and then I am trying to load the correct record via a look up in the database of that ID.  Im wondering is this code possible?



<?php $query = mysql_query("SELECT * FROM table WHERE ".md5(tableID)." = $ID"); ?>



Thanks

what does the # symbol do in php(e.x index.php?cat=1#privacy)? How can i use it? From what i 've seen you use it for changing a whole div without reloading the page like tabs..

I can't figure out why im getting an error with this code.

if ($notif = mysql_query("SELECT * FROM notifications_1 WHERE recieverid='". $_SESSION['id']."' ORDER BY read ASC, id DESC") or die (mysql_error())); {

Code: [Select]
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'read ASC, id DESC' at line 1

Hi, I am trying to convert a php function into perl and need to understand the following line in red :        function pagination($query, $per_page = 10,$page = 1, $url = '?'){       
     $query = "SELECT COUNT(*) as `num` FROM {$query}";
     $row = mysql_fetch_array(mysql_query($query));
     $total = $row['num'];
        $adjacents = "2";      $page = ($page == 0 ? 1 : $page); 
     $start = ($page - 1) * $per_page;        
  
     $prev = $page - 1;       
     $next = $page + 1;
        $lastpage = ceil($total/$per_page);
     $lpm1 = $lastpage - 1;
     
     $pagination = "";
     if($lastpage > 1)
     {  .........................................     What will be the output of this line above in red.   Thank you very much. Regards. Tonya

Hi, I'm working on a product page and I got it to list all the products in one column of a table, but when I add a second column it just duplicates the first column.  What do I need to change? 

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<?php
require_once("functions.php"); 
?> 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<style type="text/css">
td {
border-top-style: solid;
border-right-style: solid;
border-bottom-style: solid;
border-left-style: solid;
border-top-color: #30C;
border-right-color: #30C;
border-bottom-color: #30C;
border-left-color: #30C;
}
</style>
</head>

<body>
<form action="" method="post" name="catalog">
<?php 

DatabaseConnection();  

  $query = "SELECT * FROM treats";
        $result_set = mysql_query($query) or die(mysql_error());

        $output = "<table>";
        while ($row = mysql_fetch_array($result_set))
        {
            $output .= (" 
<tr>
<td width=\"400px\">" . $row['product_title']."<br /> ".$row['product_Description']."<br />" .$row['price'] . "<br />  Quantity: <input name=\"quantity\" type=\"text\" size=\"2\" /> </td>  
<td width=\"400px\">" . $row['product_title']."<br /> ".$row['product_Description']."<br />" .$row['price'] . "<br />  Quantity: <input name=\"quantity\" type=\"text\" size=\"2\" /> </td>  
</tr>
");
        }
        $output .= "</table>";
        echo $output;
?>   
</form>
</body>
</html>

hello all I'm VERY new to php and I just have a simple question

how do I bold the output text of this string

echo $row['name']."<BR>";

Lets say I have:

$var=5;

What would an output look like to get me:

1<br>
2<br>
3<br>
4<br>
5<br>

Im at a complete loss!


Thanks!

Hey! I have a drop down field for my "register" form, but this is clearly easy to edit, I just used tamperdata for firefox and yeah...pretty easy, is there any way that you could prevent tampering with the values when submitting this form!?