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PHP - Replacing Characters
Similar TutorialsHey guys, I have a quick question. Im going to be making a script that will output the name of a news article along with the poster's name beside it. There is only a certain amount of space where that stuff can go so I want to know how I can make it so that say after 20 characters, it ends and puts "..." beside it. Is this possible with php? How would I do it? Hi I am trying to replace characters in a string with images so character 'a' will be replaced with a.jpg etc I have tried the following code but that doesn't result in the desired effect as the updated string gets it's characters replaced as the script works through it so the 'img' in the first updated string gets replaced with with images and it all ends up quite a mess. Is there a simpler way to do this? $content = "abc" ; $content = str_replace("a", "<img src=images/a.jpg >", $content); $content = str_replace("b", "<img src=images/b.jpg >", $content); $content = str_replace("c", "<img src=images/c.jpg >", $content); $content = str_replace("d", "<img src=images/d.jpg >", $content); $content = str_replace("e", "<img src=images/e.jpg >", $content); $content = str_replace("f", "<img src=images/f.jpg >", $content); $content = str_replace("g", "<img src=images/g.jpg >", $content); $content = str_replace("h", "<img src=images/h.jpg >", $content); $content = str_replace("i", "<img src=images/i.jpg >", $content); $content = str_replace("j", "<img src=images/j.jpg >", $content); $content = str_replace("k", "<img src=images/k.jpg >", $content); $content = str_replace("l", "<img src=images/l.jpg >", $content); $content = str_replace("m", "<img src=images/m.jpg >", $content); $content = str_replace("n", "<img src=images/n.jpg >", $content); $content = str_replace("o", "<img src=images/o.jpg >", $content); $content = str_replace("p", "<img src=images/p.jpg >", $content); $content = str_replace("q", "<img src=images/q.jpg >", $content); $content = str_replace("r", "<img src=images/r.jpg >", $content); $content = str_replace("s", "<img src=images/s.jpg >", $content); $content = str_replace("t", "<img src=images/t.jpg >", $content); $content = str_replace("u", "<img src=images/u.jpg >", $content); $content = str_replace("v", "<img src=images/v.jpg >", $content); $content = str_replace("w", "<img src=images/w.jpg >", $content); $content = str_replace("x", "<img src=images/x.jpg >", $content); $content = str_replace("y", "<img src=images/y.jpg >", $content); $content = str_replace("z", "<img src=images/z.jpg >", $content); echo $content ; Any help would be gratefully appreciated. Thanks Megalos (paul) Please help. I am trying to replace parenthesises () in a string with <>. I tried preg_replace and str_replace, but was not success. Here is what I have for str_replace: $word = "(test)"; $word = str_replace('(', '<', $word); $word = str_replace(array('(', ')'), array('<','>'), $word); Hey all, i need a function or a way to replace each letter in a string to a star (*) Thanks How come this is not replacing correctly? $rp = strtr($rp,"[TIMES]","<span style='font-family: Times New Roman, Times, serif'>") hi freaks, still working on my email bot. im currently trying to escape <>-tags to be displayed- but not the browser wont exectute it (i.e. xls-tags) i want them as chars. so whin my $content is like <xsl:stylesheet> <xsl:template match="/"> <more xls...> it shows a stylesheet. i just want the chars. Here is what ive been trying so far: but its bad Code: [Select] <?php $string='<tag> > < asdasf'; $bomb=array( '<', '>', ); $defusal=array( '-', '!', ); $string= preg_replace($bomb,$defusal,$string); echo $string; ?> error: Warning: preg_replace() [function.preg-replace]: No ending matching delimiter '>' found in C:\xampp1\htdocs\code.php on line 13 donno any further now Hello, Is str_replace the best way to go about this? In MYSQL, a html template is stored, such that: Quote <table width="{$width}">lots of other ........</table> This is extract from the database, and stored in a string. I would use eval(), but, any user can update this template, so I need to be able to set which variables will be replaced with what the variable is. Thanks! I have phrases in a string with the structure of "Note: some description" I want to replace "Note with (, but how can I replace the second " with )? Hi first post here and very new to php. I built a form so that a data entry perosn can "build" new pages for our companies website. I pretty much have the basics of the form and the action page coded correctly, however my issue is that I need this final page where the form inputs are posted too to be an html document. I read some about the str_replace() function, but I'm not understanding how I could use that to replace the file extension of a page. Maybe I'm going about this all wrong. I also read that one can edit the htaccess folder to allow an html file to run php script. Not sure which way would be the best. One thing to mention though, is this application would be run locally to our back up files which is then scheduled to be uploaded to the remote server very night. Any help or suggestions would be greatly appreciated. I'm having an issue with users uploading files with a Semi Colon in the file name. I am currently using a script that replaces characters within the file name, however, when I try to add a ";" as invalid characters to replace, it is like the semi-colon just stops the script, as the file does not upload (no errors are displayed). Here's the code I'm working with: $valid_chars_regex = '.A-Z0-9_ !@#$%^&()+={}\[\],~`-'; $file_name = preg_replace('/[^'.$valid_chars_regex.']|\'.+$/i', "", basename($_FILES[$upload_name]['name'])); if (strlen($file_name) == 0 || strlen($file_name) > $MAX_FILENAME_LENGTH) { HandleError("Invalid file name"); exit(0); } I tried placing the semi colon all over the place in the preg_replace function, but nothing seems to work. How can I do this? How can I replace ' and " with str_replace? When I using the following code, I will get error. $string = str_replace(""", "something", $string); Hello, I have been trying to replace a variable's value inside a function in case it matches a certain criteria but I can't seem to get it right. Let me give an example: Code: [Select] <?php function replace_value($obj) { if($obj==1) { $obj=2; } } $number = 1; replace_value($number); echo $number; So how do I go about making $number = 2, because it still has a value of 1 even after I pas it through the function replace_value. I want to be able to replace, let's say, every fifth letter from a string. The string is unknown, though, it could come from database, or a POST form. So I'm unsure if I could use str_replace. I think I may need to use preg_replace(), but I'm not not sure. Hi Guys, I use this function to generate seo friendly names for my products once pulled from the database: function generate_seo_friendly_links($pNM, $pID) { $replacedNM = str_replace(" ", "-", $pNM); $replacedNM = rtrim($replacedNM); $brandNewSEOFriendlyURL = "<a href='$replacedNM-$pID.html'>$pNM</a>"; return $brandNewSEOFriendlyURL; } This works great, the only thing is say a product is stored in the database like: product name it would then be converted to: product-name.html if for example theres 2 spaces: product name it would then be converted to: product--name.html with the 2 "--" so for every space it finds we replace with a "-" etc is there a way i could ignore more than 1 space and always have it like product-name-here.html so the names are more uniformed, i can't think of a way to do it. any help would be appreciated thanks guys Graham If this were an example post in a forum: Code: [Select] $post = '[quote author=james]hello this is a quote[/quote] here is some mor text between the next coming quote [quote author=david]hello this is another quote[/quote]'; What is the best way to replace the [quotes author=x] with opening html tag eg: Code: [Select] <div class="quote"><div class="quoteTitle">author=x</div> And then determine if the next is a [/quote ] is an opener or close quote? And then of course there is the issue of the user deleting a [/quote] or even placing a [/quote] before an open quote... Does anyone know of an example to look at? //$x = ereg_replace('[-a-z0-9!#$%&\'*+/=?^_`{|}~]+@([.]?[a-zA-Z0-9_/-])*','<a href=\'mailto:\\0\' '.$style.'>\\0</a>',$x); Hi I wonder if anyone will be kind enough to help. I am getting into forking with pcntl_fork() I intend to create a script that runs 24/7 running 100 forks/children/'threads' simultaneously. Once a child has finished it's task and exited how can I start a new child to replace it? I need some kind of infinite loop that can continually check for exited children and set up new ones. I'm finding it hard to get my head round since I'm new to forking. Can anyone suggest a way to do this? Thanks in advance. Ok mixing javascript with php.... im having bugs . I basically want to replace any broken image links with a picture "noimage.gif" in the images folder. I tried this code but am getting the error: Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /home/wormste1/public_html/tilburywebdesign/shop/FTPServers/barryottley/showroom.php on line 78 This is the javascript header - all seems fine: <script language="JavaScript" type="text/javascript"> function ImgError(source){ source.src = "/images/noimage.gif"; source.onerror = ""; return true; } </script> this is the code thats erroring... is it the way ive written in the code into the IMG tag? while($row = mysql_fetch_array($result)){ echo "<TABLE CELLPADDING=0 CELLSPACING=0 WIDTH=100% BORDER=0>"; echo "<TR />"; echo "<TD WIDTH=30% VALIGN=TOP />"; echo " <A HREF='images/".$row['photo']."' target=_blank><IMG SRC='images/".$row['photo']."' width=186 height=155 border=0 onerror="ImgError(this);" /></A> "; echo "<br />"; echo "</TD>"; echo "<TD WIDTH=10 VALIGN=TOP />"; |
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