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PHP - Strtotime Calculations Inaccurate ...
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I am trying to calculate the number of days between dates and have a major problem. When I try the example below, it gives me exactly 201 days, yet the dates have different times, meaning that a full day is impossible. If it matters, I am testing via xampp 1.7.3 with php version 5.3.1 with Windows XP. Can anyone explain what I am doing wrong. Can daylight savings play a role? $frmritedate7116 = strtotime('2010-12-13 23:00'); $frmritedate7156 = strtotime('2010-05-27 00:00'); // $frmritedate7251 = $frmritedate7156 - $frmritedate7116; // // 1274943600-1292310000=-17366400 // 86400 seconds in a day ( 201.00 ) // // // Similar TutorialsHi all, I post a strange behavior that could be reproduced (at least on apache2+php5). I don't know if I am doing wrong but let me explain what I try to achieve. I need to send chunks of binary data (let's say 30) and analyze the average Kbit/s at the end : I sum each chunk output time, each chunk size, and perform my Kbit/s calculation at the end. Code: [Select] <?php // build my binary chunk $var= ''; $o=9000; while($o--) { $var.= "testtest"; } // get the size, prepare the memory. $size = strlen($var); $tt_sent = 0; $tt_time = 0; // I send my chunk 30 times for ($i = 0; $i < 30; $i++) { // start time $t = microtime(true); echo $var."\n"; ob_flush(); flush(); $e = microtime(true); // end time // the difference should reprenent what it takes to the server to // transmit chunk to client right ? // add this chuck bench to the total $tt_time += round($e-$t,4); $tt_sent += $size; } // total result echo "\n total: ".(($tt_sent*8)/($tt_time)/1024)."\n"; ?> In this example above, it works so far ( on localhost, it oscillate from 7000 to 10000 Kbit/s through different tests). Now, let's say I want to shape the transmission, because I know that the client will have enough of a chunk of data to process for a second. I decide to use usleep(1000000), to mark a pause between chunk transmission. Code: [Select] <?php // build my binary chunk $var= ''; $o=9000; while($o--) { $var.= "testtest"; } // get the size, prepare the memory. $size = strlen($var); $tt_sent = 0; $tt_time = 0; // I send my chunk 30 times for ($i = 0; $i < 30; $i++) { // start time $t = microtime(true); echo $var."\n"; ob_flush(); flush(); $e = microtime(true); // end time // the difference should reprenent what it takes to the server to // transmit chunk to client right ? // add this chuck bench to the total $tt_time += round($e-$t,4); $tt_sent += $size; usleep(1000000); } // total result echo "\n total: ".(($tt_sent*8)/($tt_time)/1024)."\n"; ?> I am doing something wrong ? Does the buffer output is not synchronous ? Thanks a Lot Nunja I've written a small ELO class for calculating a players rating for a game league, and for the life of me I don't know why these calculations are coming up wrong. The Class:
Code for testing:
The output i'm getting is as follows, when they should match what i've stated above (as done on paper with a calculator) Player A (1000) has a 9% Chance of winning. Player B (1000) has a 9% chance of winning. Player A's new rating will be 1029 if they win. Player B's new rating will be 1029 if they win. Player A's new rating will be 997 if they lose. Player B's new rating will be 997 if they lose. I've tried re-writing the calculation over and over but just can't get it. I used the Wikipedia page to get my calculations. I've not added K Factor yet but I will be at some point. So, my problem is that I need to edit my Xmas calculator to understand when this year's Xmas is over, it will automatically jump to the next one (2011-12-25). I have no idea how to do this (noob to php...) Thanks in advance. Here's my code: Code: [Select] <?php $time=time(); $xmas=strtotime("2010-12-25 00:00:00"); $diff = $xmas - $time; $days=intval($diff/86400); $left=$diff%86400; $hs=intval($left/3600); $left=$left%3600; $mins=intval($left/60); $secs=$left%60; echo "<font size=12 face=corbel> Xmas is after:<br> <strong>$days days</strong><br> <strong>$hs hours</strong><br> <strong>$mins mins $secs secs</strong>! </font>"; ?> First time posting code and very new to php aka learning as I go... The below code works as shown, but in the 'else' clause, I'd like to replace the +4 with a variable. How to do this? I've tried, Code: [Select] $renewaldate = strtotime($subscriptiondate); $sft = "' +" . $duesmultiplier . " year'"; $next_year = date('Y-m-d',strtotime($sft,$renewaldate)); but this doesn't return what I expect. Perhaps this can't be done using this technique? Code: [Select] if($n == 0) { $renewaldate = strtotime($subscriptiondate); $next_year = date('Y-m-d',strtotime('next year',$renewaldate)); echo $next_year; } else { $renewaldate = strtotime($subscriptiondate); $next_year = date('Y-m-d',strtotime('+4 year',$renewaldate)); echo $next_year; } Thank you Hi, I have a bit of an issue with my application, I didn't notice until today, Sunday... Apparently PHP sees Sunday as the first day of the week, which I cannot fathom where it got hat notion from... but anyway, so I have the following samples of my code: Code: [Select] $mondayoflastweek = date('Y-m-d H:i:s', strtotime('monday last week')); $sundayoflastweek = date('Y-m-d 23:59:59', strtotime('sunday last week')); The crazy and very troublesome thing about the results of that code is that if you run that today, Sunday, it shows today as last week... So therefore, the next bit of code is just as problematic: Code: [Select] $mondayofthisweek = date('Y-m-d H:i:s', strtotime('monday this week')); $sundayofthisweek = date('Y-m-d 23:59:59', strtotime('sunday this week')); As you can imagine, for payroll, this is causing a big problem... My week starts at precisely 12:00 am on Monday and ends at precisely 11:59 pm on Sunday... Could someone please help me out with this... I'm trying to add 5 days to $today date: Code: [Select] <?php $exp_date = "2011-09-11"; $todays_date = date("Y-m-d"); $today = strtotime("+5 days", $todays_date); $expiration_date = strtotime($exp_date); if ($expiration_date > $today) { echo "Valid: Yes"; } else { echo "Valid: No"; } ?> Is +5 days used wrong? when i use strtotime('+3 HOURS') everything is fine. so why cant i use strtotime('+3.5 HOURS')? what would be the proper way to do this? Hello! A user is going to input a date in the form "mm/dd/yyyy". I'd like to convert this to a time stamp so that I can store it via MySql. I've heard about the "strtotime" function in PHP but I'm not sure how it can tell that the user 03/04/2011 represents March,4th 2011 and not, say April,3rd 2011 (European version). Help with the correct syntax for conversion would be greatly appreciated. Thank you, Eric Hello,
I'm trying to use strtotime to add time to a mysql type timestamp. Any help would be appreciated. I think I have tunnel vision from looking at it when I know it has to be something obvious...lol
$start = "2014-05-22 09:16:24";
$type = 30;
$endtime = date($start,strtotime("+ '.$type.' minutes"));
echo "End: ".$endtime."</br>Start: ".$start;
Right now it returns:
End: 2014-05-22 09:16:24
Start: 2014-05-22 09:16:24
Hello, I am trying to take the calculations of two variables to create a new data for a new variable. For example.....
LRH_calcLevel($LRH_current, $LRH_bankfull); +/- $LRH_totalDepth = $newVar
Which should translate to -10.43 Ft +/- 40 = $newVar (-29.57) <----- What I want
Instead it is showing up as 10.43 Ft +/- 40 = $newVar (-50.43) <----- How it is displaying which is incorrect
Here is the code I am using. The second function is what I am trying to use to create the new variable data based on the calculations above from the data provide via XML. How can I get this to display correctly?
-Thanks
//Parse Lake Ray Hubbard XML Data
$site = simplexml_load_file($LRH_data);{
$LRH_bankfull = '435.5';
$LRH_totalDepth = '40';
$LRH_current = $site->observed->datum[0]->primary;
$LRH_vaild = $site->observed->datum[0]->valid;
$LRH_updated = DATE("D, M d, g:i a", STRTOTIME($LRH_vaild));
}
//Lets calculate the lake depatures from full pool for Lake Ray Hubbard
function LRH_calcLevel($LRH_current, $LRH_bankfull)
{
//Get float values from strings
$LRH_current = floatval($LRH_current);
$LRH_bankfull = floatval($LRH_bankfull);
//Calculate the difference
$LRH_calcLevel = $LRH_current - $LRH_bankfull;
//Format difference to two decimal places and add 'Ft'
$LRH_calcLevelStr = (string) number_format($LRH_calcLevel, 2) . ' Ft';
//If vlaue is positive add a + to beginning
if($LRH_calcLevel>0) { $LRH_calcLevelStr = '+'.$LRH_calcLevelStr; }
//Return the calculated formatted value
return $LRH_calcLevelStr;
}
////Lets calculate the lake percentage from full pool for Lake Ray Hubbard
$val1 = $LRH_current;
$val2 = $LRH_bankfull;
$LRH_prec = ( $val1 / $val2) * 100;
// 1 digit after the decimal point
$LRH_prec = round($LRH_prec, 1);
//Lets convert the depature from full pool for Lake Ray Hubbard
function LRH_calcDepth($LRH_calcLevelStr, $LRH_totalDepth)
{
//Get float values from strings
$LRH_calcDepthStr = floatval($LRH_calcLevelStr);
$LRH_totalDepth = floatval($LRH_totalDepth);
//Calculate the difference
$LRH_calcDepth = $LRH_calcDepthStr - $LRH_totalDepth;
//Format difference to two decimal places and add 'Ft'
$LRH_calcDepthStr = (string) number_format($LRH_calcDepth, 2) . ' Ft';
//If vlaue is positive add a + to beginning
if($LRH_calcDepth>0) { $LRH_calcDepthStr = '+'.$LRH_calcDepthStr; }
//Return the calculated formatted value
return $LRH_calcDepthStr;
}
////Lets calculate the lake percentage from full pool for Lake Ray Hubbard
$val1 = LRH_calcLevel($LRH_current, $LRH_bankfull);
$val2 = $LRH_totalDepth;
Hi, I have been set a task to use 300000 values from a csv to find the total amount of the values and the averages of the values (mode, mean and median). The csv is set into 2 columns, number and amount with 300000 records for each. I am unsure as to how to use only the values from one of the columns in order to get the results i need. Below is the code I have so far; Code: [Select] $filepath = "testdata.csv"; $file = fopen($filepath, "r") or die("Error opening file"); $i = 0; while(($line = fgetcsv($file)) !== FALSE) { if($i == 0) { $c = 0; foreach($line as $col) { $cols[$c] = $col; $c++; } } else if($i > 0) { $c = 0; foreach($line as $col) { $data[$i][$cols[$c]] = $col; $c++; } } $i++; } //this prints the whole of the data still while (($cols[1])) print_r($data); //this still prints all the data!! while ($data) print_r($cols[1].$data); Am I going about this wrong by using an associative array? so i have a basic html table and down the left column i have monday,tuesday,wednesday.... sunday. In the column 2nd from the left, i want to fill it with the current weeks dates, which is really based on the current date. So if today is Jul 29th Friday, then strtotime("last monday") would give me Jul 26th Monday... my issue is "last monday" wont work if today is monday because that will give me 19th of july... and since I technically dont know what day is today i'm not sure how to cleanly work around this without having to use some if statement... if today is monday do "last monday +7 days" or just do "now" etc... Thanks! how do I use strtotime() instead of mktime()? $matchTimea = mktime($mHour, $mMinute, 0, $mMonth, $mDay, $mYear); if($matchTimea-time() < $cutoffTimea*60) { Hi! the following code sucessfully outputs a timestamp. Code: [Select] $datealt=strtotime('2012-03-13 ,23:13:00'); The following however does not: Code: [Select] $datealt=strtotime('$date ,$hours:$minutes:00'); I have checked if the variables echo out and they do.. any clues much appreciated x what is the propper way to write Code: [Select] $payrollweek="10"; date('Y-m-d', strtotime("+($payrollweek - 2) week $payrollend") ), "<br />"; its the ("+($payrollweek - 2) that isnt working i think I have this php code: length is 15 , that is what it is coming out of the database $length = $get['length']; $time = date('Y-m-d', strtotime('+$length days')); But when I echo time it comes out with this result 1969-12-31 What am I doing wrong? Hi I am new to PHP and trying to convert a date from a registration form (in the form 01/01/2011) to Y-m-d so that it can be stored in the database. This is the code I have, pretty sure it worked before but not it has stopped working! Any ideas? $dateformat = $_POST['dob']; $correctformat = date('Y-m-d',strtotime($dateformat)); I have checked what $_POST['dob'] is printing and that is correct, however the $correctformat is printing 1970-01-01 everytime. Any help would be greatly apreciated. Thank you Good Day, I'm struggling to get strtotime() to return anything. I have the following code.. $fields['birth']['day'] = 9; $fields['birth']['month'] = 7; $fields['birth']['year'] = 1982; $dob = $fields['birth']['day'].' '.$fields['birth']['month'].' '.$fields['birth']['year']; // Returns: 9 7 1982 $dob = strtotime($dob); die($dob); No matter what I do $dob isn't returning anything once strtotime() is used. I've tried matching my day/month/year 's with examples in the manual on the strtotime() page but using date() on the fields, but it still doesn't want to return anything. I feel I'm missing something simple here. Any help is appreciated. Regards, Ace Hey freaks, running into a little issue with the use of date and strtotime.... basically I wanna present the date in the format m-d-y to the user and insert it into the DB in the Y-m-d format. What seems to be happening is a freaky Y-d-m format and I don't know why this is. This code is an example that expresses my frustration. Code: [Select] $nmon = strtotime("next Monday"); $next = date('m-d-Y', $nmon); $_SESSION['REPORT_DUE'] = $next; $nfri = strtotime("Friday"); $due = date('m-d-Y', $nfri); $_SESSION['WEEK_ENDING'] = $due; $ses1 = $_SESSION['WEEK_ENDING2'] = date('Y-m-d', strtotime($due)); $ses2 = $_SESSION['WEEK_ENDING3'] = date('d-m-Y', strtotime($ses1)); .....output.... Quote [WEEK_ENDING] => 09-02-2011 [WEEK_ENDING2] => 2011-02-09 [WEEK_ENDING3] => 09-02-2011 ) Thank you for any assistance. Little confuzzled. I have got a bunch of listings that will be printed at the end of the page but I need to subtract a time specified in a textbox (send it to itself) on the page. Code: [Select] $row['active'] = (strtotime('$row[etd]') + $rwy1 = $_POST['tmatttextfield']);Well this just converts the time in the database which is always going to be a four character number such as: 1300 for 1PM into a time and adds the textbox value to the time. Code: [Select] <td width="50" bgcolor="<?php echo $bc?>"><strong><?php echo date('hi', $row['active']);?></strong></td>That just prints it all out formatting the time to only Hours and Minutes. So just to clarify the user would put in say '10' in the textbox which would constitute 10 minutes. The code above should then define that '10' as 10 minutes. Define the database result, ie. 1500 as 3PM and add the 10 minutes to it so it would become 1510. I have been getting some wierd and wonderful results whilst trying to get it to work. Mainly just 1200 though. Harry. |
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