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PHP - What Is The Popular Way To 'delete' Records?
Hi all,
I'm just wondering how everyone deletes their records using PHP or if you can give me any recommendations. Not really deleting, but I use UPDATE and change the deleteStatus column value. What is the best / recommended way, with a customer confirmation? Similar TutorialsHi Guys, How come i am unable to delete a record with the same id from multi records with the following php code? $rid = "SELECT month_ID FROM monthA WHERE userID = '".$_POST['userID']."' AND thisMonth = '".$_POST['month']."' AND thisYear = '".$_POST['year']."'"; $rid_month = mysql_query($rid); $row = mysql_fetch_array($rid_month); $month_ID = $row["month_ID"]; $rid = "SELECT * FROM monthB WHERE month_ID = '$month_ID'"; $rid_month = mysql_query($rid); $row = mysql_fetch_array($add_member); while ($row = mysql_fetch_array($rid_month)) { $month_ID = $row["month_ID"]; $rid = "DELETE FROM monthBB WHERE month_ID = '$month_ID' "; $result = mysql_query($rid); } $rid = "SELECT * FROM monthC WHERE month_ID = '$month_ID' "; $rid_month = mysql_query($rid); while ($row = mysql_fetch_array($rid_month)) { $month_ID = $row["month_ID"]; $rid = "DELETE FROM monthCC WHERE month_ID = '$month_ID' "; $result = mysql_query($rid); } $rid = "DELETE FROM monthA WHERE month_ID = '$month_ID' "; $result = mysql_query($rid); I have tried a number of ways without any luck. How ever if i use this code? mysql_query("DELETE FROM monthA WHERE month_ID = '$month_ID'"); It allows me to delete one row from one table only. Please advise Hi all. I built an online finance tracking thingy for myself and I got it to work using the following database table and PHP code. I didn't write the PHP code, rather, I edited it to suit my needs. It works great for my needs. I have a way to enter records and view the last 180 records in a table. The thing is, while viewing the table, I would lke to be able to edit and delete records. I don't know enough to be able to do this. Can it be done? I realize my PHP code would probably, for the most part, be totally different. Thanks for any help with this. Here is my DB table structu Code: [Select] DROP TABLE IF EXISTS `money`; CREATE TABLE IF NOT EXISTS `money` ( `id` int(5) NOT NULL AUTO_INCREMENT, `date` date NOT NULL, `type` varchar(18) NOT NULL, `checking` decimal(5,2) NOT NULL DEFAULT '0.00', `cash` decimal(5,2) NOT NULL DEFAULT '0.00', `description` varchar(25) NOT NULL, `who` varchar(25) NOT NULL, `note` varchar(50) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; And here is the PHP: Code: [Select] <?php $result = mysql_query ('SELECT date, type, checking, cash, who, description, note' . ' FROM money' . ' ORDER BY date DESC LIMIT 0,180') or die(mysql_error()); echo "<table border='1' cellpadding='5'>"; echo "<tr><th>Date</th><th>Type</th><th>Checking</th><th>Cash</th><th>Who?</th><th>Description</th><th>Note</th></tr>"; while($row = mysql_fetch_array( $result )) { // Print out the contents of each row into a table echo "<tr><td>"; echo $row['date']; echo "</td><td>"; echo $row['type']; echo "</td><td>"; echo $row['checking']; echo "</td><td>"; echo $row['cash']; echo "</td><td>"; echo $row['who']; echo "</td><td>"; echo $row['description']; echo "</td><td>"; echo $row['note']; echo "</td></tr>"; } echo "</table>"; ?> Hi, I'm new to the forum so this could go in the MySQL section but I'm not sure. I am trying to make a page that will list all records from a column in HTML table and have a delete button to remove a specific record. I have got to the part where I have listed the records in a table. Note: Only records from a specific column ('links') are printed. Here is the code: Code: [Select] $con = mysql_connect("localhost","***","***"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("***", $con); $result = mysql_query("SELECT * FROM main"); echo "<table border='1'> <tr> <th>Current links</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['links'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); How would I go about adding a delete button next to each record to delete that specific record? Thanks for any help. I need Delete Duplicate Email Records That Are Attached To One Account But Can Be Found In Multiple Accounts I have a table, consumer_mgmt. It collects consumer information from various forms. These forms are available through different pages that are part of a business package. A business can offer these signups to gather names and emails from consumers for various types of specials they may offer. So a consumer my be in the consumer_mgmt table 5, 10, 15 times for that particular business. But, that consumer may be in the consumer_mgmt table multiple times for a different business. So multiple times for multiple businesses. I need to remove duplicates for each business account so the consumer is only the consumer_mgmt only once for each business. There are approximately 15,000 rows currently in the consumer_mgmt table. I'm not sure where to begin on the logic. Since there are multiple business accounts that the emails are attached to, would one have to build a case for each loop? I was searching a bit on how to properly secure user input/queries then I stumbled upon parametrized queries, people recommended them as they were basically immune to SQL attacks while being a bit faster than the regular mysql_query function. All well in theory. My question is, why these are not popular? I only read about them by chance and it doesn't seem to be used widely. Are there any hidden drawbacks for using parametrized queries? Should I simply keep using mysql_query and filter user input manually? I'm starting a new project so I would appreciate any input on this. I am having trouble showing reports for a given date range. Currently if I specify something like 11/03/2010 to 11/05/2010 I get results for all years within that month and day such as I may get results for 11/03/2008 11/03/2009 11/03/2010 11/04/2008 11/04/2009 11/04/2010 11/05/2008 11/05/2009 11/05/2010. I am using the following code $result = mysql_query("SELECT * FROM report WHERE date>='$date_begin' and date<='$date_end' ORDER BY 'date'",$db); I use the following format in my date feild mm/dd/yyyy My script is finally working as intended, but I want to add some additional data results. I am trying to resolve how I can display a count of ONLY the records updated by my query: // START :: Query to replace matches mysql_query("UPDATE orig_codes_1a AS a JOIN old_and_new_codes_1a AS b ON concat(a.orig_code_1, a.orig_code_2) = concat(b.old_code_1, b.old_code_2) SET a.orig_code_1 = b.new_code_1, a.orig_code_2 = b.new_code_2") or die(mysql_error()); // END :: Query to replace matches In this query I count ALL records selection: // START :: Create query to be displayed as final results of original codes table. $result = mysql_query("SELECT * FROM orig_codes_1a") or die(mysql_error()); I want to display a count on this part of the query: ....concat(a.orig_code_1, a.orig_code_2) = concat(b.old_code_1, b.old_code_2).... Hi all. Here is my scripts which allow user to check multiple rows of data and delete it , but it require select data and click for twice to delete the rows , what should be the error? Code: [Select] <form name="frmSearch" method="post" action="insert-add.php"> <table width="600" border="1"> <tr> <th width="50"> <div align="center">#</div></th> <th width="91"> <div align="center">ID </div></th> <th width="198"> <div align="center">First Name </div></th> <th width="198"> <div align="center">Last Name </div></th> <th width="250"> <div align="center">Mobile Company </div></th> <th width="100"> <div align="center">Cell </div></th> <th width="100"> <div align="center">Workphone </div></th> <th width="100"> <div align="center">Group </div></th> </tr> </form> <? echo "<form name='form1' method='post' action=''>"; while($objResult = mysql_fetch_array($objQuery)) { echo "<tr>"; echo "<td align='center'><input name=\"checkbox[]\" type=\"checkbox\" id=\"checkbox[]\" value=\"$objResult[addedrec_ID]\"></td>"; echo "<td>$objResult[addedrec_ID] </td>"; echo "<td>$objResult[FirstName]</td>"; echo "<td>$objResult[LastName] </td>"; echo "<td>$objResult[MobileCompany] </td>"; echo "<td>$objResult[Cell] </td>"; echo "<td>$objResult[WorkPhone] </td>"; echo "<td>$objResult[Custgroup] </td>"; echo "</tr>"; } echo "<td colspan='7' align='center'><input name=\"delete\" type=\"submit\" id=\"delete\" value=\"Delete\">"; if (isset($_POST['delete']) && isset($_POST['checkbox'])) // from button name="delete" { $checkbox = ($_POST['checkbox']); //from name="checkbox[]" $countCheck = count($_POST['checkbox']); for($d=0;$d<$countCheck;$d++) { $del_id = $checkbox[$d]; $sql = "DELETE from UserAddedRecord where addedrec_ID = $del_id"; $result2=mysql_query($sql) or trigger_error(mysql_error());;; } if($result2) { $fgmembersite->GetSelfScript(); } else { echo "Error: ".mysql_error(); } } echo "</form>"; Thanks for every reply. <body> <?php
include 'sql.php';
$query = "SELECT * FROM validation";
$result = mysqli_query($con , $query);
$rows = mysqli_fetch_assoc($result) ;
$totals = mysqli_num_rows($result) ;
?>
<div id="css">
<form >
<table width="80%" border="0" cellpadding="2" cellspacing="2" >
<caption><h2>Personal Details of Customers</h2></caption>
<tr class="white">
<td bgcolor="#330033"> </td>
<td bgcolor="#330033"> Id Number </td>
<td bgcolor="#330033"> Full Name </td>
<td bgcolor="#330033"> Email Address </td>
<td bgcolor="#330033"> Website </td>
<td bgcolor="#330033"> Comment </td>
<td bgcolor="#330033"> Time </td>
</tr>
<?php while($rows=mysqli_fetch_assoc($result)
{
<tr>
<input type="raido" name="ID" value="<?php echo $rows['ID']; ?>" />
<td bgcolor="#FFFFCC"><?php echo $rows['ID'];?></td>
<td bgcolor="#FFFFCC"><?php echo $rows['Name'];?> </td>
<td bgcolor="#FFFFCC"><?php echo $rows['Email'];?></td>
<td bgcolor="#FFFFCC"><?php echo $rows['Website'];?></td>
<td bgcolor="#FFFFCC"><?php echo $rows['Comment'];?></td>
<td bgcolor="#FFFFCC"><?php echo $rows['Time'];?></td>
<td> </td>
<td> <a href="delete.php? ID= "$rows[ID]" /"> <input type="submit" name="del" value="Delete" /> </a> <input type="button" name= "edit" value="Edit" /> </td>
</tr>
}
?></table> </form> </div> </body> Hi,
I wish to find out is there any possible that I can delete some data inside my php website but inside my sql database, the record will still at there?
Thank you.
I'm trying to set it so that it will delete an entire populated directory based upon a value in the database then after finishing that to go back and delete that row in the database. my current code is Code: [Select] <?php $page_title = "Central Valley LLC | Photo Addition" ?> <?php include("header.php"); ?> <?php include("nav.html"); ?> <div id="content"> <form action="delprod.php" method="post" enctype="multipart/form-data"> <label for="which">Choose A Product To Remove:</label> <?php $con = mysql_connect("localhost","phoenixi_cv","centraladmin"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("phoenixi_cvproducts", $con); $result = mysql_query("SELECT * FROM Products"); echo "<select name=\"which\">"; while($row = mysql_fetch_array($result)) { echo "<option "; echo "value=\"" . $row['id'] . "\">"; echo $row['Name'] . "</option>"; } echo "</select>"; mysql_close($con); ?> <br /> <input type="submit" name="submit" value="Submit" /> </form> </div><!--#content--> <?php include("footer.html") ?> and the delete script Code: [Select] <?php $con = mysql_connect("localhost","phoenixi_cv","centraladmin"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("phoenixi_cvproducts", $con); $result = mysql_query("SELECT id FROM Products WHERE id=$_POST['which']"); $row = mysql_fetch_array($result) chdir('assets'); chdir('images'); $mydir = $row . '/'; $d = dir($mydir); while($entry = $d->read()) { if($entry!="." && $entry!="..") { unlink($_POST['which'] . '/' . $entry); } } rmdir($mydir); $result = mysql_query("DELETE * FROM Producs WHERE id=$_POST['which']"); ?> Thank you in advance for all your help. any easier ways of approaching this will be welcome as well I am have a query with a limit of 3 i want it to echo the first two in one li class and the 3 in another li class. This is what i have, but i know the logic is not right, but i cant figure it out Code: [Select] </div> <?php echo "<ul class='services-list'>"; //echo "<li class='bubble'>"; $i = 1; foreach ($rows_class as $record_class ){ ?> <li class="bubble"><a href="viewclass.php?class_id=<?php echo base64_encode($record_class[class_id]) ?>" /><h6 class="title"><img src="./images/services/picture-services.png" class="picture" alt="logo" /><? echo $record_class[class_title]; ?></h6></a><p><?php $string = $record_class['description']; echo substr(strip_tags($string), 0, 200); ?></p> <?php if( $i % 2 === 0 && $record_class !== end($rows_class) ) { echo "</li>\n<li class='bubble last'>\n";?> <?php } elseif ( $record_class === end($rows_class) ) { echo "</li>\n "; } $i++; } ?> </ul> again my tables are movies| ID(PK) - Titles - Category(FK) - URL 0 Name 1 www.xyz.com categories| ID(PK) - Category 1 Comedy say i create a query SELECT * FROM movies WHERE Category="1" and it gave me all the movies from my table that is in the comedy category which should look like this: ID - Title - Category - URL 0 Name Comedy www.xyz 1 xyz Comedy www.abc etc.. How can i add a drop down menu beside each movie listed in that result that would let me change the category for it and save it ? like this, ID - Title - Category - URL 0 Name Comedy www.xyz [Dropdown] 1 xyz Comedy www.abc [Dropdown] [Save Button] being a newbie im going to guess that i will need a INSERT in here somewhere and not really sure how i would write my result echos. i have been trying all kinds of "update records" forms and cant get them right so i figured it may be easier to just try and create my own. if i could get some example or if you have more simple suggestions Hi all Complete noob here..... What I have to do is create a new database every year, but I can't just import last years data completely, only records when needed. I can do it myself in PHPMyAdmin, but I don't want my employees touching mysql directly. What I am trying to do is write a php script that will serach for a reocrd in last years database and if it exists insert it into the new database if it doesn't exists bring up a form so it can be entered. Any help would be greatly appreciated. Thanx ZZ Howdy, The following code wil geenrate a dynamic pull-down list based on column values. Can someone help me tweak it so that is will NOT display a duplicate record value. That is, if the sponsors values in the table were Hart, Michaels, Michaels, Morella ...it would only display Hart, Michaels, Morella in the pull-down menu. <form name="form0"> <? $result = @mysql_query("select distinct sponsor from table ORDER BY sponsor ASC"); if (mysql_num_rows($result) > 0) { print "<select name=\"link\">"; ?> <option <?php if(empty($_GET['sponsor'])){ echo "selected=\"selected\""; } ?> value="<? echo "$page_name" ?>">SELECT A SPONSOR</option> <? while ($row = mysql_fetch_array($result)) { print "<option "; if($_GET['sponsor'] == $row['sponsor'] ){ echo "selected=\"selected\""; } print " value=\"index?sponsor=" . $row['sponsor'] . "\">" . $row['sponsor'] . "</option>\n"; } print "</select>"; } ?> </form> Thank you. ~Wayne Hey again guys, i am building a site admin page and i want to do a php script with will show the heading and the date of my news database into a table, and on the right or left side of each row i want to put 2 small icons one which will remove the specific record and one which will open a new small window with the whole record viewing. any idears? Hi, can someone help me understand why it 's only printing the first record in the database ? Code: [Select] <?php require_once("functions.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <?php DatabaseConnection(); mysql_select_db("auntievics"); $query= "SELECT product_id FROM treats"; $result_set= mysql_query($query); if ($result_set){ $products= mysql_fetch_row($result_set); foreach ($products as $value){ print $value; } print "<br />"; } //print_r(mysql_fetch_row($result_set)); ?> </body> </html> Is there a php method/function that can count how many records in a table have the same id. For example you have two tables relating to one another there for there is reason for a coloum to have the same id as another. I've got query. |
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