|
PHP - Image Script Output Workaround
sure, I know how to output a picture with a php script.
the problem is, the host I use, they won't let me edit the php.ini file to look through png files for PHP scripts before outputting. Of course, it is bad practice anyways... Is there any way to make it easy for a user to download the image with a .png extension instead of .php. (I know this is done automatically in windows 7, like: image.php.png because it reads the content type). Any good ideas? =) Similar Tutorialshello, when i add Code: [Select] echo $row['img']; to the code below it prevents it from working correctly. Have I written the line correctly or is there another underlying cause? any help greatly appreciated. working = http://www.1pw.co.uk/demo2.php not working = http://www.1pw.co.uk/demo.php Code: [Select] <?php define('INCLUDE_CHECK',1); require "../#########.php"; if(!$_POST['img']) die("There is no such product!"); $img=mysql_real_escape_string(end(explode('/',$_POST['img']))); $row=mysql_fetch_assoc(mysql_query("SELECT * FROM internet_shop WHERE img='".$img."'")); echo $row['img']; echo '{status:1,id:'.$row['id'].',price:'.$row['price'].',txt:\'\ \ <table width="100%" id="table_'.$row['id'].'">\ <tr>\ <td width="60%">'.$row['name'].'</td>\ <td width="10%">$'.$row['price'].'</td>\ <td width="15%"><select name="'.$row['id'].'_cnt" id="'.$row['id'].'_cnt" onchange="change('.$row['id'].');">\ <option value="1">1</option>\ <option value="2">2</option>\ <option value="3">3</option></slect>\ \ </td>\ <td width="15%"><a href="#" onclick="remove('.$row['id'].');return false;" class="remove">remove</a></td>\ </tr>\ </table>\'}'; ?> not sure if needed but this is the file that includes the above file.... Code: [Select] var purchased=new Array(); var totalprice=0; $(document).ready(function(){ $('.product').simpletip({ offset:[40,0], content:'<img src="img/ajax_load.gif" alt="loading" style="margin:10px;" />', onShow: function(){ var param = this.getParent().find('img').attr('src'); if($.browser.msie && $.browser.version=='6.0') { param = this.getParent().find('img').attr('style').match(/src=\"([^\"]+)\"/); param = param[1]; } this.load('ajax/tips.php',{img:param}); } }); $(".product img").draggable({ containment: 'document', opacity: 0.6, revert: 'invalid', helper: 'clone', zIndex: 100 }); $("div.content.drop-here").droppable({ drop: function(e, ui) { var param = $(ui.draggable).attr('src'); if($.browser.msie && $.browser.version=='6.0') { param = $(ui.draggable).attr('style').match(/src=\"([^\"]+)\"/); param = param[1]; } addlist(param); } }); }); function addlist(param) { $.ajax({ type: "POST", url: "ajax/addtocart.php", data: 'img='+encodeURIComponent(param), dataType: 'json', beforeSend: function(x){$('#ajax-loader').css('visibility','visible');}, success: function(msg){ $('#ajax-loader').css('visibility','hidden'); if(parseInt(msg.status)!=1) { return false; } else { var check=false; var cnt = false; for(var i=0; i<purchased.length;i++) { if(purchased[i].id==msg.id) { check=true; cnt=purchased[i].cnt; break; } } if(!cnt) $('#item-list').append(msg.txt); if(!check) { purchased.push({id:msg.id,cnt:1,price:msg.price}); } else { if(cnt>=3) return false; purchased[i].cnt++; $('#'+msg.id+'_cnt').val(purchased[i].cnt); } totalprice+=msg.price; update_total(); } $('.tooltip').hide(); } }); } function findpos(id) { for(var i=0; i<purchased.length;i++) { if(purchased[i].id==id) return i; } return false; } function remove(id) { var i=findpos(id); totalprice-=purchased[i].price*purchased[i].cnt; purchased[i].cnt = 0; $('#table_'+id).remove(); update_total(); } function change(id) { var i=findpos(id); totalprice+=(parseInt($('#'+id+'_cnt').val())-purchased[i].cnt)*purchased[i].price; purchased[i].cnt=parseInt($('#'+id+'_cnt').val()); update_total(); } function update_total() { if(totalprice) { $('#total').html('total: $'+totalprice); $('a.button').css('display','block'); } else { $('#total').html(''); $('a.button').hide(); } } not sure if this is needed, but it links to the above file; Code: [Select] <?php define('INCLUDE_CHECK',1); require "######.php"; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>shop</title> <link rel="stylesheet" type="text/css" href="demo.css" /> <script type="text/javascript" src="http://code.jquery.com/jquery-1.6.1.min.js"></script> <script type="text/javascript" src="jquery.ui.main.js"></script> <!--[if lt IE 7]> <style type="text/css"> .pngfix { behavior: url(pngfix/iepngfix.htc);} .tooltip{width:200px;}; </style> <![endif]--> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/jquery-ui.min.js"></script> <script type="text/javascript" src="simpletip/jquery.simpletip-1.3.1.pack.js"></script> <script type="text/javascript" src="script.js"></script> </head> <body> <div id="main-container"> <div class="tutorialzine"> <h1>Shopping cart</h1> <h3>The best products at the best prices</h3> </div> <div class="container"> <span class="top-label"> <span class="label-txt">Products</span> </span> <div class="content-area"> <div class="content drag-desired"> <?php $result = mysql_query("SELECT * FROM internet_shop"); while($row=mysql_fetch_assoc($result)) { echo '<div class="product"><a href="#" class="item"><img src="img/products/'.$row['img'].'" alt="'.htmlspecialchars($row['name']).'" width="128" height="128" class="pngfix" /></a></div>'; } ?> <div class="clear"></div> </div> </div> <div class="bottom-container-border"> </div> </div> <div class="container"> <span class="top-label"> <span class="label-txt">Shopping Cart</span> </span> <div class="content-area"> <div class="content drop-here"> <div id="cart-icon"> <img src="img/Shoppingcart_128x128.png" alt="shopping cart" class="pngfix" width="128" height="128" /> <img src="img/ajax_load_2.gif" alt="loading.." id="ajax-loader" width="16" height="16" /> </div> <form name="checkoutForm" method="post" action="order.php"> <div id="item-list"> </div> </form> <div class="clear"></div> <div id="total"></div> <div class="clear"></div> <a href="" onclick="document.forms.checkoutForm.submit(); return false;" class="button">Checkout</a> </div> </div> <div class="bottom-container-border"> </div> </div> </div> <div class="bowlpic"> </div> </body> </html> Hi all, first time here and desperate. I have a host with php enabled so I figure why not use it as folks can turn off javascript. I am testing on a wamp windows setup. What I want to do is output an image or text to a div in a page, pause for 3 seconds then output a new pic or text to overwrite it. The code I am playing with is this. <html> <head><title></title></head> <body> <h1>what is this?</font></h1> <?php echo '<div id="main" style=" position: absolute; top:100; left: 100; width: 100px; height: 70px; visibility: show;"> my div content is here </div>'; //for ($x=0;$x<30000;$x++){} sleep(3); echo '<div id="main" style=" position: absolute; top:100; left: 100; width: 100px; height: 70px; visibility: show;"> new content now </div>'; ?> </body> </html> Firstly the second text output merges with the first ! can I destroy a div and then recreate it to get a clear canvas? BUT the thing I cant do is pause the output, as you see above I have tried an empty counting loop and the sleep function. Neither work as the pause happens before ANY output and then the div shows up with the merged outputs? Anyone explain to me how to do this and why does the sleep not occur wher it is placed? Thanks for your help people. Hi, I have a script that reads data from a website and insert this into a DB and every time a record is written into DB the script gives an output on the screen When I run this script local on my computer it runs ok and the screen update is every 20 or 30 seconds (not realtime) i though this maybe because of my computer is to slow etc. When I upload this to the server, it's even worse, no updates at all but it does insert the records into the DB. I believe it must be a setting in the Apache or PHP server. Anyone please, advice Thanks I'm writing a script to grab some info from a list of urls in the database, but it just continuously loads and doesn't display anything. Here's the script: <? $username="*****"; $password="*****"; $database="*****"; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT * FROM dvds"; $result=mysql_query($query); $num=mysql_numrows($result); echo "<b><center>Database Output</center></b><br><br>"; $i=0; while ($i < $num) { $url=mysql_result($result,$i,"imdb_url"); echo "<b>Getting page: $url</b><br>"; //get the page content $imdb_content = get_data($url); //parse for movie details $name = get_match('/<title>(.*)<\/title>/isU',$imdb_content); $director = strip_tags(get_match('/<h5[^>]*>Director:<\/h5>(.*)<\/div>/isU',$imdb_content)); $plot = get_match('/<h5[^>]*>Plot:<\/h5>(.*)<\/div>/isU',$imdb_content); $release_date = get_match('/<h5[^>]*>Release Date:<\/h5>(.*)<\/div>/isU',$imdb_content); $mpaa = get_match('/<a href="\/mpaa">MPAA<\/a>:<\/h5>(.*)<\/div>/isU',$imdb_content); $run_time = get_match('/Runtime:<\/h5>(.*)<\/div>/isU',$imdb_content); //build content $content.= '<h2>Film</h2><p>'.$name.'</p>'; $content.= '<h2>Director</h2><p>'.$director.'</p>'; $content.= '<h2>Plot</h2><p>'.substr($plot,0,strpos($plot,'<a')).'</p>'; $content.= '<h2>Release Date</h2><p>'.substr($release_date,0,strpos($release_date,'<a')).'</p>'; $content.= '<h2>MPAA</h2><p>'.$mpaa.'</p>'; $content.= '<h2>Run Time</h2><p>'.$run_time.'</p>'; $content.= '<h2>Full Details</h2><p><a href="'.$url.'" rel="nofollow">'.$url.'</a></p>'; //display the content echo $content; $i++; } //gets the match content function get_match($regex,$content) { preg_match($regex,$content,$matches); return $matches[1]; } //gets the data from a URL function get_data($url) { $ch = curl_init(); $timeout = 5; curl_setopt($ch,CURLOPT_URL,$url); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout); $data = curl_exec($ch); curl_close($ch); return $data; } ?> Hopefully someone better at php can tell me how to fix it! Thanks! I'm trying to make colourized output of bash script in php. So far I have this:
<?php
$cmd = '/home/thebalk/FiveM/manage.sh restart';
while (@ ob_end_flush()); // end all output buffers if any
$proc = popen($cmd, 'r');
echo '<pre>';
while (!feof($proc))
{
echo fread($proc, 4096);
@ flush();
}
echo '</pre>';
//
// Converts Bashoutput to colored HTML
//
function convertBash($cmd) {
$dictionary = array(
'[1;30m' => '<span style="color:black">',
'[1;31m' => '<span style="color:red">',
'[1;32m' => '<span style="color:green">',
'[1;33m' => '<span style="color:yellow">',
'[1;34m' => '<span style="color:blue">',
'[1;35m' => '<span style="color:purple">',
'[1;36m' => '<span style="color:cyan">',
'[1;37m' => '<span style="color:white">',
'[m' => '</span>'
);
$htmlString = str_replace(array_keys($dictionary), $dictionary, $cmd);
return $htmlString;
}
?>
and my output looks like this: [1;36m BOT:[0;39m THE [1;32m TheBalkanRP-SRV01-test SERVER [0;39m WAS RUNNING [1;36m BOT:[0;39m STOPPING THE [1;32m TheBalkanRP-SRV01-test SERVER [1;36m BOT:[0;39m GTA V SERVER HAS STOPPED [1;36m BOT:[0;39m REMOVING CACHE FOLDER [1;36m BOT:[1;31m CACHE FOLDER HAS BEEN REMOVED [0;39m [1;36m BOT:[0;39m STARTING THE [1;32m TheBalkanRP-SRV01-test [0;39m SERVER [1;36m BOT:[1;32m SERVER HAS STARTED [0;39m I know my function is not connected with the code above but what is the right way to do it? Thank you! I have made a script that reads values from MySQL database and "Echo" them. When I run the script the variables from the DB are printed on the page as they should be. Now I want to make those variables accessible to my C++ application to read. I am using WinInet functions to communicate with the script. Can somebody explain to me what I have to do in my php script be able to access the variables directly. The below script gets the value $var = $_GET['Version']; that is sent from my C++ app. It then reads from the DB table the Version number entered in the table. Then compares the version number from my C++ app to the DB version number. Now I want to make the Version Number from the DB accessible to my C++ app. I want to be able to get the exact value stored in: $row['VersionNumber']; with my C++ app. <?php $dbhost = 'host'; $dbuser = 'dbusername'; $dbpass = 'dbpass'; mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); $dbname = 'MyDbsName'; mysql_select_db($dbname); $query = mysql_query("SELECT * FROM Users"); $var = $_GET['Version']; while($row = mysql_fetch_array($query)) { if($var == $row['VersionNumber']) { echo $row['VersionNumber']; } } ?> I found this site: http://www.wallpaperama.com/forums/how-to-save-html-output-code-from-php-script-t6898.html it demonstrates how to save html output code from php script. here is an example: http://ads4agents.com/date.php I cant get it to work on my site...where is the correct place ad these: ob_start(); $HtmlCode= ob_get_contents(); ob_end_flush(); How can I get this to work in my php? view_ad.php <html> <body> <center> <br/> <h1>Apartment Reference #: <?php echo $_POST["reference"]; ?><br /></h1> <br/> <?php echo $_POST["application"]; ?>, <?php echo $_POST["deposit"]; ?><br /> <?php echo $_POST["pets"]; ?><br /> <br/> <?php echo $_POST["community"]; ?><br /> <?php echo $_POST["interior"]; ?><br /> <?php echo $_POST["amenities"]; ?><br /> <br/> <?php echo $_POST["contact"]; ?><br /> <a href="<?php echo $_POST['website'] ?>"><?php echo $_POST['website'];?></a><br/> <br/> <br/> <br/> </body> </html> im testing the following script and it wont send 1 2 3 until the script has finished executing. What can i do to flush the buffer after every echo statement?? <?php echo "1"; ob_flush();flush(); sleep(5); echo "2"; ob_flush();flush(); sleep(5); echo "3"; ob_flush();flush(); ?> Well the subject line is pretty explicit. I found this script that uploads a picture onto a folder on the server called images, then inserts the the path of the image on the images folder onto a VACHAR field in a database table. Code: [Select] <?php //This file inserts the main image into the images table. //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); //authenticate user //Start session session_start(); //Connect to database require ('config.php'); //Check whether the session variable id is present or not. If not, deny access. if(!isset($_SESSION['id']) || (trim($_SESSION['id']) == '')) { header("location: access_denied.php"); exit(); } else{ // Check to see if the type of file uploaded is a valid image type function is_valid_type($file) { // This is an array that holds all the valid image MIME types $valid_types = array("image/jpg", "image/jpeg", "image/bmp", "image/gif"); if (in_array($file['type'], $valid_types)) return 1; return 0; } // Just a short function that prints out the contents of an array in a manner that's easy to read // I used this function during debugging but it serves no purpose at run time for this example function showContents($array) { echo "<pre>"; print_r($array); echo "</pre>"; } // Set some constants // This variable is the path to the image folder where all the images are going to be stored // Note that there is a trailing forward slash $TARGET_PATH = "images/"; // Get our POSTed variable $image = $_FILES['image']; // Sanitize our input $image['name'] = mysql_real_escape_string($image['name']); // Build our target path full string. This is where the file will be moved to // i.e. images/picture.jpg $TARGET_PATH .= $image['name']; // Make sure all the fields from the form have inputs if ( $image['name'] == "" ) { $_SESSION['error'] = "All fields are required"; header("Location: member.php"); exit; } // Check to make sure that our file is actually an image // You check the file type instead of the extension because the extension can easily be faked if (!is_valid_type($image)) { $_SESSION['error'] = "You must upload a jpeg, gif, or bmp"; header("Location: member.php"); exit; } // Here we check to see if a file with that name already exists // You could get past filename problems by appending a timestamp to the filename and then continuing if (file_exists($TARGET_PATH)) { $_SESSION['error'] = "A file with that name already exists"; header("Location: member.php"); exit; } // Lets attempt to move the file from its temporary directory to its new home if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); header("Location: images.php"); echo "File uploaded"; exit; } else { // A common cause of file moving failures is because of bad permissions on the directory attempting to be written to // Make sure you chmod the directory to be writeable $_SESSION['error'] = "Could not upload file. Check read/write persmissions on the directory"; header("Location: member.php"); exit; } } //End of if session variable id is not present. ?> The script seems to work fine because I managed to upload a picture which was successfully inserted into my images folder and into the database. Now the problem is, I can't figure out exactly how to write the script that displays the image on an html page. I used the following script which didn't work. Code: [Select] //authenticate user //Start session session_start(); //Connect to database require ('config.php'); $sql = mysql_query("SELECT* FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main' "); $row = mysql_fetch_assoc($sql); $imagebytes = $row['image']; header("Content-type: image/jpeg"); print $imagebytes; Seems to me like I need to alter some variables to match the variables used in the insert script, just can't figure out which. Can anyone help?? Hello There, I have been trying to get my page going for some time. I have managed to setup my database on mysql. I have managed to create myself a few pages that look how I want and do what I want. I have managed to get the data I want into my database. Where I am struggling big time is to find some way to get the images that I have gotten into my database back out again with a php page. I have managed to do a dynamic drop down, from one of the tables, but when I bring back the image files I get the binary, or a readout of the file. (I have a .gpx file as well as a load of .jpg files). The code I have managed so far is below, does anyone feel inclined to help me get a little further with this? I am new to HTML and to PHP, although databases are perhaps a little more familiar to me. I would like if possible to show the images in the lower half of the same page that the drop down is on, although if this is not possible then please let me know. <?php require_once 'login.php'; $db_server = mysql_connect($db_hostname, $db_username, $db_password); if (!$db_server) die("unable to connect to MySQL: " . mysql_error()); //connecting to the database. mysql_select_db($db_database) or die("Unable to select database: " . mysql_error()); // If submitted, check the value of "select". If its not blank value, get the value and put it into $select. if(isset($select)&&$select!=""){ $select=$_GET['select']; } ?> <body> <form method="POST" action="predroptest.php"> Hills : <select name="selecthill"> <option value="">--- Select Hill---</option> <? // Get records from database (table "Hills"). $list=mysql_query("select ID, Hill from Hills order by Hill"); // Show records by while loop. while($row_list=mysql_fetch_assoc($list)){ ?> <option value="<? echo $row_list['ID']; ?>" <? if($row_list['ID']==$select){ echo "selected"; } ?>><? echo $row_list['Hill']; ?></option> <? // End while loop. } ?> </select> <input type="submit" name="Submit" value="Select" /> </form> <hr> <p> <? // Get records from database (table "Hills"). $select1=$_POST['selecthill']; $query="SELECT * FROM Objects Where Data_ID='$select1'"; $result=mysql_query($query); $num=mysql_numrows($result); echo "<b><center>Hill Info</center></b><br><br>"; $i=0; while ($i < $num) { $Data_ID=mysql_result($result,$i,"Data_ID"); $Object=mysql_result($result,$i,"Object"); $Type=mysql_result($result,$i,"Type"); $Description=mysql_result($result,$i,"Description"); header('Content-type: image/jpg'); echo "<b>$Data_ID<br>$Object<br>$Type<br>$Description<hr><br>"; $i++; } mysql_close(); ?> </p> </body> Thanks very much for the help Diana Tracy www.up-a-hill.me.uk The servers at my uni blocked the fwrite & fputs functions. Is there another way to write to a file using php? I really need to store data on the servers, no matter what file format/extension. Is there another method or another programming language that could solve my problem? How can I resize an image that i'm showing and rather than saving it, just output the file? And would this vary if I was to be first calling the image through AJAX? Hi, I have an image (a weather map) which is created using php which pulls data from a mysql database. I would like to be able to output the result image as a gif or jpg file. Can anyone suggest how this could be done? Many thanks, Simon I know this has been addressed in tutorials and forums, but I'm not sure how to search for it (i.e. what to type into google). I have a header.php that I include in all files. It has a section like the following: if($showHello) { echo "Hello"; } I would like to control to header in the body of the other pages: $showHello = true; From what I can tell it is a problem with the order in which the page is processed: $showHello = true; if($showHello) { echo "Hello"; } // works whereas: if($showHello) { echo "Hello"; } $showHello = true; // does not work The reason for this makes sense, but my question is... how do I make the second scenario work? Is there a structure within PHP that I can use? I am trying to produce a thresholded image with only an rgb value of zero or 255. As you can see, although I only output 0 and 255, I am finding that if I output as jpg file, I get other values in there as well. If I output as gif, I also get other values in there too. I am sure I am doing something stupid as there must be a way to do this. My test file is this attached jpg greyscale file. Is there a way to process this test file so that only 0 or 255 appears in the output image please? Thanks. Here is my program <?php $url = 'greyscale_image.jpg'; $outfile = 'greyscaleout'; $src = imagecreatefromjpeg($url); $w = imagesx($src);$h = imagesy($src); $loband = 80;$hiband = 255; $im_r = imagecreatetruecolor($w,$h); imagefill($im_r,0,0,imagecolorallocate($im_r,255,0,0)); $im_j = imagecreatetruecolor($w,$h); imagefill($im_j,0,0,imagecolorallocate($im_j,255,0,0)); for ($x=0;$x<$w;$x++) { for ($y=0;$y<$h;$y++) { $idx = imagecolorat($src,$x,$y); $rgb = imagecolorsforindex($src,$idx); // this is safest (for gifs) rather than some calculation - apparently $r =$rgb['red']; $g = $rgb['green']; $b = $rgb['blue']; $gryout = $r; if ($r <= $loband) { $gryout = 0; // everything less than= loband is black } if ($r > $loband) { $gryout = 255; // everything else is white } if ( ($gryout == 0) || ($gryout == 255) ) { // only zero or 255 allowed $idx = imagecolorallocate($im_r,$gryout,$gryout,$gryout); imagesetpixel($im_r,$x,$y,$idx); // imagesetpixel($im_j,$x,$y,$idx); // $idx2 = imagecolorat($im_r,$x,$y);// if ($idx != $idx2) { die($idx2." at x,y ".$x.",".$y); } $rgb = imagecolorsforindex($im_r,$idx); // this is safest (for gifs) rather than some calculation - apparently $r =$rgb['red']; $g = $rgb['green']; $b = $rgb['blue']; if ($r != 0) { if ($r != 255) { die($r." at x,y ".$x.",".$y); } } } else { die('<br>Grey going out to image is '.$gryout); } } } imagegif($im_r,$outfile.'.gif');imagedestroy($im_r); imagejpeg($im_j,$outfile.'.jpg');imagedestroy($im_j); // ========================== // done the writing, now check it // ========================== // $outfile = 'greyscale_image'; // test using original $src = imagecreatefromjpeg($outfile.'.jpg'); $w = imagesx($src);$h = imagesy($src); $errcount = 0; $x = 0; while($x<$w) { $y = 0; while($y<$h) { $idx = imagecolorat($src,$x,$y);// $rgb = imagecolorsforindex($src,$idx); // this is safest (for gifs) rather than some calculation $r =$rgb['red']; $g = $rgb['green']; $b = $rgb['blue']; if ($r != 0) { if ($r != 255) { echo sprintf('<br>r(%d,%d) r=%d g=%d b=%d',$x,$y,$r,$g,$b);$errcount++; } } if ($g != 0) { if ($g != 255) { echo sprintf('<br>g(%d,%d) r=%d g=%d b=%d',$x,$y,$r,$g,$b);$errcount++; } } if ($b != 0) { if ($b != 255) { echo sprintf('<br>b(%d,%d) r=%d g=%d b=%d',$x,$y,$r,$g,$b);$errcount++; } } if ($errcount > 10) {break 2;} $y++; } $x++; } if ($errcount == 0) {die( ' Checked OK' );} die( ' Checked NOT OK' ); // ================= ?> Well I have a script that executes a scan on a system set to run infinitely, and I need it to echo out a message each time it loops through, but I don't want it to echo out the message with the next loop message below it, and the next one below that etc... I've tried using the flush(); function and been messing around with that with no luck. For security reasons I don't want to release any of the processing code, but here is the basic construction of the script: <?PHP ***PROCESSING AND SCAN CODE*** ***PROCESSING AND SCAN CODE*** ***PROCESSING AND SCAN CODE*** ***PROCESSING AND SCAN CODE*** $RepeatIt = -1; for($g=1; $g!=$RepeatIt+1; $g++) { ***PROCESSING AND SCAN CODE*** ***PROCESSING AND SCAN CODE*** ***PROCESSING AND SCAN CODE*** ***PROCESSING AND SCAN CODE*** $ScanMessage = ":.:.: SCANNING THE HITLIST FOR MOBSTER: ".$MobName." (SCAN #$g) :.:.:"."<br/><br/>"; echo $ScanMessage; ***PROCESSING AND SCAN CODE*** ***PROCESSING AND SCAN CODE*** ***PROCESSING AND SCAN CODE*** ***PROCESSING AND SCAN CODE*** } ?> At the moment it's returning: :.:.: SCANNING THE HITLIST FOR MOBSTER: DEUS EX DESTROYER (SCAN #1) :.:.: :.:.: SCANNING THE HITLIST FOR MOBSTER: DEUS EX DESTROYER (SCAN #2) :.:.: :.:.: SCANNING THE HITLIST FOR MOBSTER: DEUS EX DESTROYER (SCAN #3) :.:.: :.:.: SCANNING THE HITLIST FOR MOBSTER: DEUS EX DESTROYER (SCAN #4) :.:.: So what I want it to do is just delete the scanning message and replace it with the next scan message so while running this script you would see just the number increment on the same line. Any suggestions? Thanks. I have 23 products in a db, all with a unique ID that Im creating a user site for. Some of the items have 1 or 2 images and others have as many as 30 images. In my db I have a field called "pics". All the images are saved as a .jpg, according to their id on the server. So if item 1 has 10 images the files a "1_001.jpg," "1_002.jpg," ect. How do I create a script that will display the correct amount of images based on the number in the db. I was going to do something like this: Code: [Select] if ($row['pics'] =="1") { $pictures = '<img src="pictures/'.$id.'_001.jpg" width="200" alt="" />'; } elseif ($row['pics'] =="2") { $pictures = '<img src="pictures/'.$id.'_001.jpg" width="200" alt="" /><img src="pictures/'.$id.'_002.jpg" width="200" alt="" />'; } elseif ($row['pics'] =="3") { $pictures = '<img src="pictures/'.$id.'_001.jpg" width="200" alt="" /><img src="pictures/'.$id.'_002.jpg" width="200" alt="" /><img src="pictures/'.$id.'_003.jpg" width="200" alt="" />'; } but that would just be retarded... Thank you! hello i have this php code to show the last image upload in a folder and the result is this http://theplattan.com/screenlive2/Screenshooter2.php this code must be in the same image folder to work. I need add a php code from my joomla website but i dont know where i can change the path image folder on this script. i have tried by my self to change rad 33 $files = dirList('.'); to $files = dirList('screenlive2'); but this show only the list and not the image, somebody have any idea? Code: [Select] 1: <html> 2: <head> 3: <style type="text/css"> 4: #files { float: left; font-size: small; } 5: #image { float: right; } 6: .links { float: right; left: -40px; position: relative; } 7: .selected { font-weight: bold; } 8: </style> 9: </head> 10: <body> 11: 12: <?php 13: 14: function dirList ($directory) 15: { 16: $results = array(); 17: $handler = opendir($directory); 18: while ($file = readdir($handler)) { 19: if ($file != '.' && $file != '..') 20: { 21: $suffix = "gif"; 22: 23: if( substr($file, -3) == $suffix ) 24: { 25: $results[] = $file; 26: } 27: } 28: } 29: closedir($handler); 30: return $results; 31: } 32: 33: $files = dirList('.'); 34: 35: arsort($files); 36: 37: //$files = array_reverse( $files ); 38: 39: echo "<div id='files'><ul>"; 40: 41: $prev = ""; 42: $next = ""; 43: $last = ""; 44: 45: foreach( $files as $entry ) 46: { 47: if( isset($_GET['sel']) == false ) 48: { 49: $_GET['sel'] = $entry; 50: } 51: 52: $style = ""; 53: 54: if( $_GET['sel'] == $entry ) 55: { 56: $style="selected"; 57: $selected = $entry; 58: $prev = $last; 59: } 60: 61: echo "<li class='".$style."'><a href='i.php?sel=".$entry."'>"; 62: print_r( $entry ); 63: echo "</a></li>"; 64: 65: if( ($last == $selected) && ($last != "") ) 66: { 67: $next = $entry; 68: } 69: 70: $last = $entry; 71: } 72: 73: echo "</ul></div>"; 74: 75: echo "<div id='image'><img src='".$selected."' alt=''/></div>"; 76: 77: echo "<p class='links'>"; 78: 79: if( $prev != "" ) echo "<a href='i.php?sel=".$prev."'>Up</a>"; 80: echo "<br/>"; 81: if( $next != "" ) echo "<a href='i.php?sel=".$next."'>Down</a>"; 82: 83: echo "</p>"; 84: 85: ?> 86: 87: </body> 88: </html> Hi Guys, I am trying to disguise my php script as a .gif file for the purposes of a shopping cart. Basically, you click on the .gif which is placed on the page and it takes you to an image unless it has variables attached to it. Google use this for their checkout so I know this is possible. Does anyone have any ideas how I would go about doing this? Thanks in advance, Jacob. |
|||||||