PHP - Submit Form To Php Function.
Is it possible to link action in the form to a function thats included from a functions file? Like so:
Code: [Select] <form action="<?php add($text); ?>" > <input type="text" name="text" /> <input type="submit" /> </form> What I want to do is add a block of text to the database. The add function does that. So ideas? I have like 9 of these forms on the same page they all do different things though but all involve modify the database. Similar TutorialsHi, I wouder if someone can help me with this issue? I want a user to click submit on a form which posts the data of to a processing page! but i only want a user to be taken to the processing page if the data in the fields passes some vailation. If the data does not pass the validation error message appear! What way could this be done? Hello, I am a newbie to php. I am trying to figure out how to call a function when a user clicks submit on a form. I have a sample script that I am writing where the user inputs there name, address, etc.. and then clicks submit and it inserts into the mysql database. I have successfully done this with form action to my adduser.php file, but I would rather have a single function file with adduser, delete a user, edit a user, etc.. here is my form <form action="includes/customersfunctions.php?add" method="post"> name: <input type="text" name="name" /><br /> address: <input type="text" name="address" /><br /> city: <input type="text" name="city" /><br /> state: <input type="text" name="state" /><br /> zip: <input type="text" name="zip" /><br /> <input type="submit" /> </form> Here is my function <?php function add() { include("config.php"); mysql_query("INSERT INTO customers (name,address,city,state,zip) VALUES ('name','address','city','state','zip') ") or die(mysql_error()); echo "added"; mysql_close($con); } ?> The function will have delete, update, etc.. later Thanks for your help in advance! I have two pages one is db.php and another is form.php. In form.php i have created a form which contains different fields and a submit button. But i want to write the queries in db.php. And when i click on the submit button the insert query in db.php should be executed and insert data in database but the focus remains on form.php. How can i do this??? Any Idea? Say I have an "Entries" table. I want to submit same multiple entries using a form submission. And If I have other queries submitted in the same form, I want those quarries to be submitted only once. Is that possible to do? Here's my code. if(isset($_POST['submit'])) { $entries = 10; $id = 55; $name = 'Smith'; $insert = $db->prepare("INSERT INTO entries(id, name) VALUES(:id, :name)"); $insert->bindParam(':id', $id); $insert->bindParam(':name', $name); $result_insert = $insert->execute(); if($result_insert == false) { echo 'Fail'; } else { echo 'Success'; } } ?> <form action="" method="post"> <input type="submit" name="submit" value="SUBMIT" /> </form> Edited January 13, 2019 by imgrooot Hi. Pretty straight forward I guess but as the name suggests am a newbie. I have a form that requires the user to enter certain parameters. If the values are blank it submits to itself and loads the error messages. What I want to do is create PHP code that submits the form to a different url. What I thought was create two forms (the second with hidden fields replicating the first form), each form having a different url in the action"" code. What I cant work out is the PHP IF ELSE code to submit form 2 if Form1 is is validated correctly. This is the PHP code relevant to the form validation. Help? <?php //If form was submitted if ($_POST['submitted']==1) { $errormsg = ""; //Initialize errors if ($_POST[width]){ $title = $_POST[width]; //If title was entered } else{ $errormsg = "Please enter width"; } if ($_POST[drop]){ $textentry = $_POST[drop]; //If comment was entered } else{ if ($errormsg){ //If there is already an error, add next error $errormsg = $errormsg . " & content"; }else{ $errormsg = "Please enter drop"; } } } if ($errormsg){ //If any errors display them echo "<div class=\"box red\">$errormsg</div>"; } //If all fields present if ($title && $textentry){ //Do something echo 'THIS IS WHERE I WANT THE CODE TO SUBMIT FORM 2 or SUBMIT FORM 1 TO A DIFFERENT URL'; } ?> Hello, first time poster.. I've looked the web over for a long time and can't figure this one out. - Below is basic code that successfully checks MySQL for a match and displays result. I was debugging and forced the "height" and "width" to be 24 and 36 to make sure that wasn't the problem. That's good.. - I'd like to give the user ability to select width and height from a form.. and have it do an onchange this.form.submit so the form can be changing as fields are altered (thus the onchange interaction) - In a normal coding environment I've done this numerous times with no "Page cannot be displayed" problems. It would simply change one select-option value at a time til they get down the form and click submit... but in WordPress I'm having trouble making even ONE single onchange work! - I've implemented the plugins they offer which allows you to "copy+paste" your php code directly into their wysiwyg editor. That works with basic tests like my first bullet point above. - I've copied and pasted the wordpress url (including the little ?page_id=123) into the form "action" url... that didn't work... tried forcing it into an <option value=""> tag.. didn't work. I'm just not sure. I've obviously put xx's in place of private info.. Why does this form give me Page Cannot Be Displayed in WordPress every time? It won't do anything no matter how simple.. using onchange.. Code.. $con = mysql_connect("xxxx.xxxxxxx.com","xxxxxx","xxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("xxxxxx", $con); $myprodwidth=24; $myprodheight=36; $result = mysql_query("SELECT * FROM product_sizes WHERE prodwidth='$myprodwidth' and prodheight='$myprodheight'"); while($row = mysql_fetch_array($result)) { echo $row['prodprice']; } mysql_close($con); <form method="post" action=""> <select name="myheight" onchange="this.form.submit();"> <option selected="selected" value="">select height</option> <option value="xxxxxxxxx.com/wordpress/?page_id=199&height=36">36</option> <option value="xxxxxxxxx.com/wordpress/?page_id=199&height=36">48</option> </select> Hi- the code below lets me upload a CSV file to my database if I have 1 field in my database and 1 column in my CSV. I need to add to my db "player_id" from the CVS file and "event_name" and "event_type" from the form... any ideas??? here's the code: Code: [Select] <?php $hoststring =""; $database = ""; $username = ""; $password = ""; $makeconnection = mysql_pconnect($hoststring, $username, $password); ?> <?php ob_start(); mysql_select_db($database, $makeconnection); $sql_get_players=" SELECT * FROM tabel ORDER BY player_id ASC"; // $get_players = mysql_query($sql_get_players, $makeconnection) or die(mysql_error()); $row_get_players = mysql_fetch_assoc($get_players); // $message = null; $allowed_extensions = array('csv'); $upload_path = '.'; //same directory if (!empty($_FILES['file'])) { if ($_FILES['file']['error'] == 0) { // check extension $file = explode(".", $_FILES['file']['name']); $extension = array_pop($file); if (in_array($extension, $allowed_extensions)) { if (move_uploaded_file($_FILES['file']['tmp_name'], $upload_path.'/'.$_FILES['file']['name'])) { if (($handle = fopen($upload_path.'/'.$_FILES['file']['name'], "r")) !== false) { $keys = array(); $out = array(); $insert = array(); $line = 1; while (($row = fgetcsv($handle, 0, ',', '"')) !== FALSE) { foreach($row as $key => $value) { if ($line === 1) { $keys[$key] = $value; } else { $out[$line][$key] = $value; } } $line++; } fclose($handle); if (!empty($keys) && !empty($out)) { $db = new PDO( 'mysql:host=host;dbname=db', 'user', 'pw'); $db->exec("SET CHARACTER SET utf8"); foreach($out as $key => $value) { $sql = "INSERT INTO `table` (`"; $sql .= implode("`player_id`", $keys); $sql .= "`) VALUES ("; $sql .= implode(", ", array_fill(0, count($keys), "?")); $sql .= ")"; $statement = $db->prepare($sql); $statement->execute($value); } $message = '<span>File has been uploaded successfully</span>'; } } } } else { $message = '<span>Only .csv file format is allowed</span>'; } } else { $message = '<span>There was a problem with your file</span>'; } } ob_flush();?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>CSV File Upload</title> </head> <body> <form class="form" action="" method="post" enctype="multipart/form-data"> <h3>Select Your File</h3> <p><?php echo $message; ?></p> <input type="file" name="file" id="file" size="30" /> <br/> <label>Event Name:</label><input name="event_name" type="text" value="" /> <br/> <label>Event Type:</label><input name="event_type" type="text" value="" /> <br/> <input type="submit" id="btn" class="button" value="Submit" /> </form> <br/> <h3>Results:</h3> <?php do { ?> <p><?php echo $row_get_players['player_id'];?></p> <?php } while ($row_get_players = mysql_fetch_assoc($get_players)); ?> </body> </html> Hi all, What I am trying to achieve is, I thought quite simple! Basically, a user signs up and chooses a package, form is submitted, details added to the database, email sent to customer, then I want to direct them to a paypal payment screen, this is where I am having issues! Is their any way in php to submit a form without user interaction? Here is my code for the form process page Code: [Select] <?php include('config.php'); require('scripts/class.phpmailer.php'); $package = $_POST['select1']; $name = $_POST['name']; $email = $_POST['email']; $password = md5($_POST['password']); $domain = $_POST['domain']; $a_username = $_POST['a_username']; $a_password = $_POST['a_password']; $query=mysql_query("INSERT INTO orders (package, name, email, password, domain, a_username, a_password) VALUES ('$package', '$name', '$email', '$password', '$domain', '$a_username', '$a_password')"); if (!$query) { echo "fail<br>"; echo mysql_error(); } else { $id = mysql_insert_id(); $query1=mysql_query("INSERT INTO customers (id, name, email, password) values ('$id', '$name', '$email', '$password')"); if (!$query1) { echo "fail<br>"; echo mysql_error(); } if($package=="Reseller Hosting") { //email stuff here - all works - just cutting it to keep the code short if(!$mail->Send()) { echo "Message could not be sent. <p>"; echo "Mailer Error: " . $mail->ErrorInfo; exit; } ?> <form name="_xclick" action="https://www.paypal.com/cgi-bin/webscr" method="post"> <input type="hidden" name="cmd" value="_xclick-subscriptions"> <input type="hidden" name="business" value="subscription@jollyhosting.com"> <input type="hidden" name="currency_code" value="USD"> <input type="hidden" name="item_name" value="Jolly Hosting Reseller Packages"> <input type="hidden" name="no_shipping" value="1"> <!--1st month --> <input type="hidden" name="currency_code" value="USD"> <input type="hidden" name="a3" value="3.00"> <input type="hidden" name="p3" value="1"> <input type="hidden" name="t3" value="M"> <input type="hidden" name="src" value="1"> <input type="hidden" name="sra" value="1"> </form>'; <?php } //last } //end ?> Hi all, I have a regular comment section and i want the submit button to call a mysql_query function in comment.class.php so Code: [Select] <form method="post" action="../php/comment.class.php?action=addcomment" name="commentform" id="commentform" onsubmit="validateForm()"> <label for "body">Your Comment</label> <div><textarea cols="20" rows="4" name="body" id="body"></textarea></div> <input type="submit" id="submit" value="Submit"/> and my comment.class.php is... Code: [Select] function addcomment($body){ $body=mysql_real_escape_string($_POST['body']); if($body!=''){ mysql_query("INSERT INTO comment(uid,screenname,body) VALUES ('$_SESSION[uid]','$_SESSION[screenname]','$body')") or die('lame'); } header("location:../index.php"); } but when I click submit, i'm taken to a blank page with the URL: http://test/php/comment.class.php?action=addcomment any tips? and is there a better alternative to header? Thanks I have a simple log in form. By debugging I found that isset post submit function is not responding. It remains on the same page after submitting form. I have googled all the possible solutions to this problem but none worked. Any help is greatly appreciated. The form is in multiplelogin.php file and the code is in multi.php file. After login redirection is to teachers.php file. <?php session_start(); $conn = mysqli_connect("localhost", "root", "", "signup");
if(isset($_SESSION['username'])) {
?>
<head> <link rel="stylesheet" type="text/css" href="bootstrap.css"> <title> Teachers Students Login </title> </head> <body class="bg-secondary"> <div class="container"> <div class="row justify-content-center"> <div class="col-log-5 bg-light mt-5 px-0"> <h3 class="text-center text-light bg-primary py-3 px-5"> Log In </h3>
<div class="form-group px-5"> <input type="email" name="email" class="form-control form-control-lg" placeholder="Email" required> </div> <div class="form-group px-5"> <input type="password" name="password" class="form-control form-control-lg" placeholder="Password" required> </div> <div class="form-group px-5"> <input type="submit" name="submit" value="Submit" class="btn btn-primary btn-block"> </div> </form> </div> </div> </div>
<?php
ini_set( 'display_errors', 1 );
$password = $_POST['password'];
$stmt = mysqli_stmt_init($conn); header("Location: multilogin.php?error=sqlerror"); exit();
} else { mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
if ($pwdCheck == false) {
exit(); $_SESSION['username'] = $row['username']; $_SESSION['email'] = $row['email']; header("Location: teachers.php?login=success");
exit ();
exit();
exit();
else {
exit(); Code: [Select] <?php $db = mysql_connect("localhost", "root") or die("Could not connect."); //username and password if(!$db) die("no db"); if(!mysql_select_db("simple",$db)){ if(!mysql_select_db("regis",$db)){//database name die("No database selected.");}} $message=$_POST['message']; print "<form action='registration.php' method='post'onsubmit='return msg();'>"; print "Your message:<br>"; print "<textarea name='message' cols='40' rows='2'></textarea><br>"; print "<a onClick=\"addSmiley(':)')\"><img src='smile.gif'></a> "; print "<a onClick=\"addSmiley(':(')\"><img src='blush.gif'></a> "; print "<a onClick=\"addSmiley(';)')\"><img src='images/wink.gif'></a> "; print "<input type='submit' name='submit' value='Set Name'></form>"; print "<script language=\"Java Script\" type=\"text/javascript\">\n"; print "function addSmiley(a)\n"; print "{\n"; print "document.form.message.value += a;"; print "document.form.message.focus();\n"; print "}\n"; print "</script>\n"; print "<br><br>"; ?> <script type="text/javascript"> <?php function msg(){ if(isset($_POST['submit'])) //if submit button push has been detected { if(strlen($message)<1) { // print "You did not input a message"; echo"<SCRIPT LANGUAGE='javascript'>alert('You did not input a message')</SCRIPT>"; } else { $message=strip_tags($message); $IP=$_SERVER["REMOTE_ADDR"]; //grabs poster's IP $checkforbanned="SELECT IP from admin where IP='$IP'"; $checkforbanned2=mysql_query($checkforbanned) or die("Could not check for banned IPS"); if(mysql_num_rows($checkforbanned2)>0) //IP is in the banned list { print "You IP is banned from posting."; } else if(strlen($message)>=1) { $message=strip_tags($message); echo("<SCRIPT LANGUAGE='JavaScript'>window.alert('$message')</SCRIPT>"); // die("<meta http-equiv=\"refresh\" content=\"0; url=registration.php\">"); } $message=$_POST['message']; $message=strip_tags($message); /* if($_POST['username'] && $_POST['pass']) { $name = mysql_query("SELECT * FROM Persons"); $thedate = date("U"); //grab date and time of the post $insertmessage="INSERT into mesej (name,IP,postime,message) values('$name','$IP','$thedate','$message')"; mysql_query($insertmessage) or die("Could not insert message"); } */ } } return false; } return true; </script> ?> This is my code in my submit2.php im clicked submit button but if it is empty it should return an javascript alert error but why it directs through registration.php without reading the rules? Hi, I want to submit a form using ajax ans jquery with two fields input text and file. Code: [Select] <script> $(document).ready( function() { $('#basicinfofrm').ajaxForm(function() { url: ''+PN+'.php', type:'POST', data:'action=yes&'+frmFeilds, success: function(html) { alert(html); } }).submit(); </script> <form action='' method='post'> <label>name</label> <input type='text' name='txtname' /> <input type='file' name = 'txtfile' /> <input type='submit' value='save' /> </form> but is is not working... can anyone tell me how to? i don't want to refresh my page Thanks Code: [Select] <?php if (isset($_POST['checking'])) { echo $_POST['checking']; } if (isset($_POST['test'])) { echo $_POST['test']; } ?> <form id="testform2" action="testform.php" method="post"> <select name="checking" onchange="this.form.submit()"><option value="5">5</option><option value="6">6</option></select> <input type="text" name"test" id="test"> <a href="#" onclick="this.form.submit()">submit it!</a> </form> It works when I try to submit by selecting a new value from the dropdown box but when I try to click the link it won't display the text field value. That is a test case for a problem I m having in one of my codes. hello everyone, I have a php form, everything works, I do not carry any header() at the end of the form because I have to stay on the same page and because I feel it wipes out the message you sent the form successfully, but for this though if reloading the page shows me the popup asking me to resend the form. how can i solve? I found a function in js with replacestate but I saw that it doesn't work with mobile Safari. if ( window.history.replaceState ) { window.history.replaceState( null, null, window.location.href ); }
I can't submit php form using IE 8. This works fine on Firefox very well. I tried following code but none of them is working. 1. <button type="submit">Submit</button> 2. <input type="submit" value="Submit" name="submit"> I would appreciate if any one help me in this. Can anybody see as to why, if any, this form takes forever to execute? Code: [Select] <?php if(isset($_POST['submitted'])){ $z = $_POST['zipcode']; $r = $_POST['radius']; $sql = mysql_query("SELECT DISTINCT m.LocAddZip, m.MktName,m.LocAddSt,m.LocAddCity,m.LocAddState,m.x1,m.y1,z1.lat,z2.long FROM mrk m, zip z1, zip z2 WHERE m.LocAddZip = z1.zipcode AND z2.zipcode = $z AND ( 3963 * acos( truncate( sin( z2.lat / 57.2958 ) * sin( z1.lat / 57.2958 ) + cos( z2.lat / 57.2958 ) * cos( z1.lat / 57.2958 ) * cos( z1.long / 57.2958 - z2.long / 57.2958 ) , 8 ) ) ) <= $r ") or die(mysql_error()); while($row = mysql_fetch_array( $sql )) { $store = $row['MktName']."<br />"; $store .= $row['LocAddSt']."<br />"; $store .= $row['LocAddCity'].", ".$row['LocAddState']." ".$row['LocAddZip']; $lat1 = $row['lat']; $lon1 = $row['long']; $lat2 = $row['y1']; $lon2 = $row['x1']; $dis = distance($lat1, $lon1, $lat2, $lon2); echo "<p>".$store."</p>"; echo ceil($dis) . " mile(s) away"; echo "<hr/>"; } } ?> I get a timeout error sometimes, and sometimes I don't. Is it the form, or would it be on the server? Thanks in advance Hi, I have setup a basic enquiry form with a Captcha - once the code has been inserted and is correct I want to action the form (submit) in PHP. <?php session_start(); if($_SERVER['REQUEST_METHOD'] == 'POST'){ $vResult = ''; if(strtolower($_SESSION['security_code']) != strtolower($_POST['security_code'])){ $vResult = 'Invalid code!'; } else{ "/enquiry.php" } } ?> I want to submit the form to /enquiry.php - I tried header(Location.. and realised that just redirects, and doesn't submit the form. Any suggestions or tips would be great. Cheers, Paul I'm a bit new to PHP and I'm getting my feet wet with mvc with code igniter. I'm having a bit of trouble with my view accessing a function from my controller. If anyone has seen CodeIgniter from Scratch Day 4, it's that tutorial - i've created an email newsletter signup.
In my my view (newsletter.php), my submit button is not working and isn't able to access a function from my controller (email.php). The inaccessible function is called function send(). Instead, I get a 404 error. I'll post the code from both the view and controller, but I highly suspect the error is contained within the view because my controller loads the view, but my view can't call a function from the controller. Any help you can provide would be greatly appreciated. Thanks.
Here's the code from my view (newsletter.php):
<html lang='en'> I have a form in the follwoing link: http://isupportentourage.dyndns.info//CARES/application.htm I would like to send the inputs to an email address so I have used a php file called sendEmail.php which has the following code: <?php $redirectTo = "http://www.yahoo.com"; $to = "fatemeh.elmi@gmail.com"; $subject = "Form Submission"; $headers = "From:\r\n"; $message = ""; $formFields = array_keys($_POST); for ($i = 0; $i < sizeof($formFields); $i++) { $theField = strip_tags($formFields[$i]); $theValue = strip_tags($_POST[$theField]); $message .= $theField; $message .= " = "; $message .= $theValue; $message .= "\n"; } $success = mail($to, $subject, $message, $headers); if ($success) { header("Location: " . $redirectTo); } else { echo "An error occurred when sending the email."; } ?> Could someone tell me why it is not working at all. |