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PHP - Moved: Validating Multiple Form Fields
This topic has been moved to JavaScript Help.
http://www.phpfreaks.com/forums/index.php?topic=320940.0 Similar TutorialsHey, I have a script which processes an image when it is uploaded, but now i have a new form that allows users to upload four images at a time. I store them in an array in the form like so: name="file[]" So now i am wondering how do i process each image with a forloop because using $_FILES doesn't say which image to check in the array? Hope some one can help me! Heres my code: Code: [Select] <?php if(isset($_POST['submit'])){ echo '<p align="center">'; if ($_FILES["file"]["size"] < 1000000) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { $filename = $_FILES["file"]["name"]; if (file_exists("images/".$name."/".$filename)) { echo "Image already uploaded!"; } else { if (is_dir("userimages/".$name) == FALSE){ mkdir("images/".$name, 0777); } move_uploaded_file($_FILES["file"]["tmp_name"], "userimages/".$name."/" . $filename); echo "Image has been uploaded!"; } } } else { echo "Invalid file"; } } ?> Thanks This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=310792.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=354984.0 I have html form that looks like: <form method="post" action="?a=up"> ...some mysql query... while ($i = mysql_fetch_array($result)) { <input name="name[]" type="text" value="<?=$i['name'];?>" /> <input name="years[]" type="text" value="<?=abs($age);?>"/> <input name="to[]" type="checkbox" value="<?=$i['id'];?>" /> } <input name="" type="submit" value="go" /> </form> The problem I have is that I can not get the values of the form fields such as "name" and "years". I can only get a list of the ids (value of "to" checkbox). The php code looks like: $cnt = 0; for($p = 0; $p <= (sizeof($to)-1); $p++) { echo $to[$p].$name[$p].$years[$p]"<br>"; $cnt++; } $tm = array($cnt); What I'm doing wrong? Hi i would like to submit the following code to my database as a mutiple selection box. when i submit i just get the last selected value for example if i hold ctrl and press 1 2 3 4 i am only receiving 4 on my database. any ideas? thanks in advance for any help! Code: [Select] Hours Of Availability:<br> <select name="availability" multiple="multiple" size="9"> <option value="Monday - Period 1">Monday - Period 1</option> <option value="Monday - Period 2">Monday - Period 2</option> <option value="Monday - Period 3">Monday - Period 3</option> <option value="Monday - Period 4">Monday - Period 4</option> <option value="Monday - Period 5">Monday - Period 5</option> <option value="Monday - Period 6">Monday - Period 6</option> <option value="Monday - Period 7">Monday - Period 7</option> <option value="Monday - Period 8">Monday - Period 8</option> <option value="Monday - Period 9">Monday - Period 9</option> </select> <select name="availability" multiple="multiple" size="9"> <option value="Tuesday - Period 1">Tuesday - Period 1</option> <option value="Tuesday - Period 2">Tuesday - Period 2</option> <option value="Tuesday - Period 3">Tuesday - Period 3</option> <option value="Tuesday - Period 4">Tuesday - Period 4</option> <option value="Tuesday - Period 5">Tuesday - Period 5</option> <option value="Tuesday - Period 6">Tuesday - Period 6</option> <option value="Tuesday - Period 7">Tuesday - Period 7</option> <option value="Tuesday - Period 8">Tuesday - Period 8</option> <option value="Tuesday - Period 9">Tuesday - Period 9</option> </select> <select name="availability" multiple="multiple" size="9"> <option value="Wednesday - Period 1">Wednesday - Period 1</option> <option value="Wednesday - Period 2">Wednesday - Period 2</option> <option value="Wednesday - Period 3">Wednesday - Period 3</option> <option value="Wednesday - Period 4">Wednesday - Period 4</option> <option value="Wednesday - Period 5">Wednesday - Period 5</option> <option value="Wednesday - Period 6">Wednesday - Period 6</option> <option value="Wednesday - Period 7">Wednesday - Period 7</option> <option value="Wednesday - Period 8">Wednesday - Period 8</option> <option value="Wednesday - Period 9">Wednesday - Period 9</option> </select> <select name="availability" multiple="multiple" size="9"> <option value="Thursday - Period 1">Thursday - Period 1</option> <option value="Thursday - Period 2">Thursday - Period 2</option> <option value="Thursday - Period 3">Thursday - Period 3</option> <option value="Thursday - Period 4">Thursday - Period 4</option> <option value="Thursday - Period 5">Thursday - Period 5</option> <option value="Thursday - Period 6">Thursday - Period 6</option> <option value="Thursday - Period 7">Thursday - Period 7</option> <option value="Thursday - Period 8">Thursday - Period 8</option> <option value="Thursday - Period 9">Thursday - Period 9</option> </select> <select name="availability" multiple="multiple" size="9"> <option value="Friday - Period 1">Friday - Period 1</option> <option value="Friday - Period 2">Friday - Period 2</option> <option value="Friday - Period 3">Friday - Period 3</option> <option value="Friday - Period 4">Friday - Period 4</option> <option value="Friday - Period 5">Friday - Period 5</option> <option value="Friday - Period 6">Friday - Period 6</option> <option value="Friday - Period 7">Friday - Period 7</option> <option value="Friday - Period 8">Friday - Period 8</option> <option value="Friday - Period 9">Friday - Period 9</option> </select> <select name="availability" multiple="multiple" size="9"> <option value="Saturday - Period 1">Saturday - Period 1</option> <option value="Saturday - Period 2">Saturday - Period 2</option> <option value="Saturday - Period 3">Saturday - Period 3</option> <option value="Saturday - Period 4">Saturday - Period 4</option> <option value="Saturday - Period 5">Saturday - Period 5</option> <option value="Saturday - Period 6">Saturday - Period 6</option> <option value="Saturday - Period 7">Saturday - Period 7</option> <option value="Saturday - Period 8">Saturday - Period 8</option> <option value="Saturday - Period 9">Saturday - Period 9</option> </select> <br>Press + Hold Ctrl For Multiple</p> I have a Form that has 10 questions. When the User completes the Form, each Response needs to be a separate record. (My database has a many-to-many relationship with a "member" and "question" table joined by a "answer" table in the middle. And each Form field will go into its own unique record to make the many-to-many work.) At the top of my Form I have... if ($_SERVER['REQUEST_METHOD']=='POST'){ // Form was Submitted (Post). // Initialize Errors Array. $errors = array(); // Trim all form data. $trimmed = array_map('trim', $_POST); // ************************ // Validate Form Data. * // ************************ // Validate Answer1. if (strlen($trimmed['answer01']) >= 2 && strlen($trimmed['answer01']) <= 1024){ // Valid Answer1. $answerArray[0] = $trimmed['answer01']; }else{ // Invalid Answer1. $errors['question01'] = 'Answer must be 2-1024 characters.'; }//End of VALIDATE ANSWER1 // Validate Answer2. // : // : // Validate Answer10. And down farther in my code, I have each Field in my Form set up like this... Code: [Select] <!-- Question 1 --> <label for="question01">1.) Why did you decide to start your own business?</label> <textarea id="question1" name="answer01" cols="60" rows="8"><?php if (isset($answerArray[0])){echo htmlentities($answerArray[0], ENT_QUOTES);} ?></textarea> <?php if (!empty($errors['question01'])){ echo '<span class="error">' . $errors['question01'] . '</span>'; } ?> So if my Form works like I am thinking, all 10 Form Fields would end up here... Code: [Select] $answerArray[0] $answerArray[1] $answerArray[2] $answerArray[3] $answerArray[4] $answerArray[5] $answerArray[6] $answerArray[7] $answerArray[8] $answerArray[9] First of all, does that sound correct? If that part is correct, then how do I take the $answerArray[] and INSERT each value into a different record in my "answer" table?? Hope that makes sense?! Thanks, Debbie HTML code: Code: [Select] <form method="post" action="viewpage.php?page_id=5"> Email: <input name="email" type="text"><br> Full Name: <input name="name" type="text"><br> Age: <input name="age" type="text"><br> Summoner Name: <input name="summon" type="text"><br> Do you have vent? <input name="vent" type="text"><br> Do you have a mic? <input name="mic" type="text"><br> How often can you be on? <input name="online" type="text"><br> What level are you? <input name="level" type="text"><br> Who do you like to play as? <input name="champs" type="text"> </form><br> Can you help donate to the clan for vent and the site?<br> <textarea name="name" rows="7" cols="25"></textarea><br> Before you say anything about the PHP not scripted to do all fields, I already know this I'm trying to figure out how to send multiple ones in one message: PHP Code: Code: [Select] <?php if (isset($_POST['submit'])) { $to = "hidden for privacy"; $subject = "LoL Recruitment"; $email = $_REQUEST['email'] ; $message = ($_REQUEST['name'], $_REQUEST['age']) ; $headers = "From: $email"; $sent = mail($to, $subject, $message, $headers) ; if($sent) { print "Your mail was sent successfully"; } else { print "We encountered an error sending your mail"; } } ?> I'm willing to bet my Code: [Select] $message = ($_REQUEST['name'], $_REQUEST['age']) ;if FAR wrong Hi Guys, I am attempting to create a program for a local auction house. I arrived at a stand still on a certain issue which is creating a sticky form. On the "enter auction details page" the user will be entering data as the auction is in session. 1. item Description 2. Item Price 3. Bidders Id 4. Qty Of course it would be repetitive to require the user to keep entering the same data for every bidder, so I want to stick the obvious fields which are "item description" & "Item Price" as these don't change until a new item comes up for sale. As of know I am processing the input on a separate page which records all input to the database with a redirect back to the "enter auction details page". I have tried many times to get the item description and item price fields to stick. These would need to change as the user moves onto the next item in which the description and price would change as well. Here is my current code for this part: Code: [Select] <?php session_start(); $field_itemDescription = ""; //iyem description, default as blank if (isset($_SESSION['itemDescription'])) $itemDescription = $_SESSION['itemDescription']; ?> <form action="record_trans.php" method="post"> <font face= "calibri" size= "4"> <table> <tr> <td><b>Item Description:</b></td> <td><input type= "text" name= "itemDescription" size= "30" value="<?php echo $itemDescription;?>"></td> </tr> <tr> <td><b>Item Price:</b></td> <td><input type= "text" name= "itemPrice" size= "5" value="<?php echo $itemPrice;?>"> </td> </tr> </tr> <td><b>Winning Bidders:</b></td> <td><input type="text" name= "bidderId" size= "5" /> </td> </tr> <tr> <td><b>How many deals?:</b></td> <td><input type="text" name= "itemQty" size= "3" value= "1" /></td> </tr> </table> <center><input type="submit" name="submit" value= "Save & Cont." " /></center> </form></font> This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=353188.0 First, Happy X-Mas to all! I want to do a form for entering dog-show results. On first site of form the user is able to enter how many dogs for each class (there are youth and open class for example) he want to insert. So on second site there will be formfields for every dog in every class, created with php. User should be able to take dogname from jquery autocomplete - this works for multiple fields. But i need the according id to the dogname - and actual only one id is given - the first one is changing by choosing from autocomplete in next fields... Data came from a json array like
0: {dogidindatabase: "9892", value: "Excalibur Khali des Gardiens de la Cour ",…}
dogidindatabase: "9892"
label: "<img src='../main/img/female.png' height='20'>Excalibur Khali des Gardiens de la Cour "
value: "Excalibur Khali des Gardiens de la Cour "
1: {dogidindatabase: "15942", value: "Excalibur from Bandit's World Kalli",…}
dogidindatabase: "15942"
label: "<img src='../main/img/male.png' height='20'>Excalibur from Bandit's World Kalli"
value: "Excalibur from Bandit's World Kalli"
all i need is inside ...the script in form is
<script type='text/javascript'>
//<![CDATA[
$(function() {
$(".dog").autocomplete({
source: "xxx.php",
minLength: 3,
select: function(event, ui) {
$('#dogidindatabase').val(ui.item.dogidindatabase);
}
});
$["ui"]["autocomplete"].prototype["_renderItem"] = function( ul, item) {
return $( "<li></li>" )
.data( "item.autocomplete", item )
.append( $( "<a></a>" ).html( item.label ) )
.appendTo( ul );
};
});
//]]>
</script>
and the form looked like
<input type='text' name='dog' class='dog' value='".strip_tags(${'dogname' .($countbabymale+1)})."' size='35' data-required='true' /><br>
<input class='readonly' readonly='readonly' type='text' id='dogidindatabase' name='dogidindatabase' size='5' />
I changed in script and form id='dogidindatabase' to class, but it doesn´t work.
Testsite is under http://www.wolfdog-d...how.php?lang=de (only german at first) - Insert a number (higher than 1) under baby 3-6 (first box, the others are not working for testing); submit to get to page 2; you see all post-variables (for testing).
Try to insert a dogname in first input-field (choose "exc") and insert first one - the id is under dogname. In second dogname inputfield you can choose second dog - the id for the first one changes to id of seond one ....
How can i get both for every dog?
This topic has been moved to Other Programming Languages. http://www.phpfreaks.com/forums/index.php?topic=347582.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=316889.0 Hey there - how are you? I'm trying to add up multiple fields from a table and it's mostly working but I have one curious error. It always seems to miss the field upgrade6_fee. I'm totally baffled. I thought it was my syntax but I'm not seeing anything wrong with it. Any ideas? Otherwise it all seems to be working. <?php $query = "SELECT fee1, upgrade3_fee, upgrade4_fee, upgrade5_fee, upgrade6_fee, upgrade7_fee, SUM(fee1 + upgrade3_fee + upgrade4_fee + upgrade5_fee + upgrade6_fee + upgrade7_fee) AS ttotal FROM Register"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo number_format(($row['ttotal']), 2); } ?> According to http://www.phpfreaks.com/forums/index.php?topic=350872.0: Is this a correct usage of what I am trying to create? Code: [Select] <?php $connect = mysql_connect("mysql12.000webhost.com","***","***") or die(mysql_error()); mysql_select_db("***") or die(mysql_error()); $id = mysql_real_escape_string($_GET['id']); $extract = mysql_query("SELECT * FROM webclientcreate WHERE id='$id' LIMIT 1 WHERE ip='$ip' WHERE port='$port' WHERE name='$name' WHERE background='$background'"); ?> Code: [Select] <applet name=client width=765 height=503 archive='<?php echo $jars; ?>' code='client.class'> <PARAM name='java_arguments' value='-Xmx700m'> <PARAM name='server_name' value='<?php echo $name; ?>'> <PARAM name='detail' value='low'> <PARAM name='ip' value='<?php echo $ip; ?>'> <PARAM name='port' value='<?php echo $port; ?>'> <PARAM name='background_image' value='<?php echo $background; ?>'> <PARAM name='headicons' value=''> I've tried several types of the query line such as : Code: [Select] webclientcreate WHERE id='$id' LIMIT 1, WHERE ip='$ip', WHERE port='$port' Code: [Select] webclientcreate WHERE id='$id' LIMIT 1, ip='$ip', port='$port' Code: [Select] webclientcreate WHERE id='$id' LIMIT 1 ip='$ip' port='$port'Without any success I appreciate any help I can get! I am debugging a PHP file that validates a user registration form. I'm very confused on this error message I'm receiving. ( Parse error: syntax error, unexpected '[' in C:\wamp\www\reg.php on line 17 ) I have looked until I cross-eyed to finf the syntax error. Here is a copy of my code: <?php // Post registration to database // Connects to your Database $userName = "taft65_admin"; $passWord = "taft65_paris4505"; $host="localhost"; $dbName = "taft65_members"; mysql_connect("dbName", "userName", "passWoord", "host") or die(mysql_error()); mysql_select_db("dbn") or die(mysql_error()); //This code runs if the form has been submitted if (isset($_POST['submit'])) { [color=yellow]//This makes sure they did not leave any fields blank if (!$_POST['id'] | !_POST['userName'] | !$_POST['passWord'] | !$_POST['confpassWord'] | !$_POST['email'] ) { die('You did not complete all of the required fields'); }[/color] // checks if the userName is in use if (!get_magic_quotes_gpc()) { $_POST['userName'] = addslashes($_POST['userName']); } $usercheck = $_POST['userName']; $check = mysql_query("SELECT userName FROM users WHERE userName = '$usercheck'") or die(mysql_error()); $check2 = mysql_num_rows($check); //if the name exists it gives an error if ($check2 != 0) { die('Sorry, the userName '.$_POST['userName'].' is already in use.'); } // this makes sure both passWoords entered match if ($_POST['passWord'] != $_POST['ConfPassWord']) { die('Your passWoords did not match. '); } // here we encrypt the passWord and add slashes if needed $_POST['passWord'] = md5($_POST['passWord']); if (!get_magic_quotes_gpc()) { $_POST['passWord'] = addslashes($_POST['passWord']); $_POST['userName'] = addslashes($_POST['userName']); } // now we insert it into the database $insert = "INSERT INTO registration (userName, passWord, email ) VALUES ('".$_POST['userName']."', '".$_POST['passWord'].", '".$_POST['email']."')"; $add_member = mysql_query($insert); ?> <p>Thank you, you have successfully registered. <a href="memPage.html"></a>you may now login.</p> Can someone help me with this by checking the code and tell me where I wen in error. BobLan66 Hello, I am trying to validate my form using php and would like some advice as this is the first time I have attempted this. I have a script which runs when the user clicks the submit button. What I am trying to do is validate the user input before inserting it into the database. This is the script: [font=monospace]<?php session_start(); $dbhandle = mysql_connect('localhost', 'root', '') or die("Unable to connect to MySQL"); $selected = mysql_select_db("commentdatabase",$dbhandle) or die("Could not select the database"); $name = check_input($_POST['fname']); $loc = check_input($_POST['loc']); $com = check_input($_POST['com']); function check_input($data) { $data = trim($data); $data = stripslashes($data); $data = htmlspecialchars($data); return $data; } $sql = "INSERT INTO userinfo (name, location, comment) VALUES ('{$name}','{$loc}','{$com}')"; if(!mysql_query($sql, $dbhandle)) { die('Error: ' . mysql_error()); } header('Location: ../contact.php'); mysql_close(); ?> [/font] What's happening is that when it is submitted to the database, it is displaying < and > characters as < and >. Yet once being redirected with the header function the input is displayed with the < and > signs. I'm not sure if the function in the action script is in the wrong place or not. I have tried moving it around above and below the post variables. Just looking for a bit of advice really. Thank you, Regards, BuNgLe This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=351561.0 I'm trying to add an email validation into the code so that it pops up with a similar message as the others if you don't use the @ or .com in your email address and it just ignores it and keeps sending the email anyways no matter what i put into the email field. here is the php i have for it i'm sure it's something really simple but i am not as familiar with php as i would like to be...
When i try and test this to make sure it works it only gives me the message that my email has been sent and i want it to not send if the email address doesn't have the @ sign or the .com or whatever kind of website it's from. I bolded the code that is not working the way i want it too.
<?php
if ($_POST['submit']) { Hi all, Im creating a simple quiz where some of the questions are checkbox because there is more than one correct answer. What I would like to be able to do, is run an if statement to check if, say for example, options 1 and 5 out of 6 have been selected, then award the point. However the point is only awarded is both options are selected. Any suggestions? Thank you in advance I have problem that only last text field is updated, how should I fix this? Here's the code <?php if(isset($_POST["update"])){ mysql_query("UPDATE categories SET name_category = '".$_POST['category']."' WHERE ID= ".$_POST['currentCat']." ") or die(mysql_error()); mysql_query("UPDATE podkategorije SET name_subcategory = '".$_POST['subcategory']."' WHERE id_subCat= ".$_POST['currentSubCat']." ") or die(mysql_error()); } ?> <form action="" method="post" > <?php //creating texfields from db $query = "SELECT k.ID, k.name_category, pk.name_subcategory, pk.id_subCat FROM `categories` AS k JOIN `subcategories` AS pk ON pk.id_mainCat = k.ID"; $result = mysql_query($query) or die(mysql_error()); $currentCat = false; while($row = mysql_fetch_array($result)) { //so it doesn't repeat itself if($currentCat != $row['ID']) { //display of main Categories ?> <ul> <li> <br/><input name="categories" type="text" value="<?php echo $row['name_category']; ?>" /> </li> </ul> <? $currentCat = $row['ID']; } //display subcategories ?> <input name="subcategories" type="text" value="<?php echo $row['name_category']; ?>" /><br/> <input type="hidden" name="currentCat" value="<?php echo $row['ID']; ?>" /> <input type="hidden" name="currentSubCat" value="<?php echo $row['id_subCat']; ?>" /> <? } ?> <br /> <input type="button" value="Back" onClick="history.go(-1);return true;"> <input type="submit" value="Update" name="update"/> </form> |
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