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PHP - Display Unchecked 'checkboxes' - Arrays, Ifs And Posts!
Hi,
I have a set of checkboxes a bit like a checklist and I then want the items that aren't checked to displayed. On the first page, I have this code: <? while($row = mysql_fetch_array($result)) { ?> <form action="packed.php" method="post"> <div> <label><input type="checkbox" name="<? echo stripslashes($row['checklistitem']); ?>" value="yes"> <? echo stripslashes($row['checklistitem']); ?> </label> </div> This basically takes an array from a database. The info is then posted to the next page which hopefully will display the boxes which are 'unticked' or unchecked if you will. The code I have on the second page is: <?php $query_string = ""; if ($_POST) { $kv = array(); foreach ($_POST as $key => $value) { $kv[] = "$key"; } $query_string = join("<br />", $kv); } else { $query_string = $_SERVER['QUERY_STRING']; } echo $query_string; ?> At the moment, it returns the array items that were checked but I want the unchecked ones to be shown. Is that possible? Thanks very much! -Steve Similar TutorialsHey forum, I am a new php user and am having some issues (probably pretty basic to the likes of more experienced users), I am trying to make a script that has 4 checkboxes and a submit button, the values of the checkboxes should be passed through the array using a foreach loop, I got the basic template setup but when trying to pass the array I ran into a few problems. If anyone would take a peek at my code and point me in the right direction it would be much appreciated. Thanks forum. [attachment deleted by admin] Hi all. This seems like a pretty basic function but I can't work it out. I'm developing a WordPress site and want to list posts (products) by category. I'm using Advanced Custom Fields and have set up the taxonomy of 'category'. I just want to produce a heading for that category and then list all of the posts with that category assigned. Please see below functions.php excerpt and section-archive.php excerpt. Can anyone please help??? Massive good karma if you can. ----------------------- functions.php -------------------------------------- //Assign Category to Products
function taxonomy ()
$args = array (
}; ?> ------------------------- section-archive.php ------------------------------------------------ <?php if(have_posts()):while(have_posts()): the_post();?>
****** if product category= this ***** Category heading ****** Posts ******* Else ****** if product category= this2 ***** Category heading ****** Posts **** etc
<div class="prod-listing">
hey I am not usually in this php forum, I am usually around html/css but a task arose and I figure since this forum uses smf it would be a perfect place to ask. Not saying you are all smf experts though. My question is how do I display the latest posts for smf in a page thats not a forum page. Like On my index page I want to display the latest posts on the forum. Help anyone? I have a posting system worked out, as well as my database configured to my linking.. But as of right now, my posts are posted from oldest to newest, having users scroll down or go to the next page to see the most recent post.
How would I "flip" that around and make my posts start from newest to oldest by its date/time (Which is stored in the database)?
Thanks!
This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=350021.0 <?php echo $error_msg=''; if(isset($_POST['submit'])) { $LoginId=$_POST['LoginId']; $Password1=$_POST['Password1']; $Password2=$_POST['Password2']; $Name=$_POST['Name']; $Age=$_POST['Age']; $BloodGroup=$_POST['BloodGroup']; $Sex=$_POST['Sex']; $Qualification=$_POST['Qualification']; $Email=$_POST['Email']; $Address=$_POST['Address']; $AboutYourself=$_POST['AboutYourself']; [b]$countCheck=count($_POST['checkbox']); echo $countCheck;[/b] //$checkbox=$_POST['checkbox']; //$countCheck=count($checkbox); if(empty($LoginId)){echo 'Please enter Login Id';} elseif(empty($Password1)){echo 'Please enter Password';} elseif(empty($Password2)){echo 'Please confirm Password';} elseif($Password1!==$Password2){echo 'Password didn\'t match';} elseif(empty($Name)){echo 'Please enter Name';} elseif(empty($Age)){echo 'Please enter Age';} elseif(empty($Sex)){echo 'Please enter Sex';} elseif(empty($Qualification)){echo 'Please enter Qualification';} elseif(empty($Email)){echo 'Please enter Email';} elseif(empty($Address)){echo 'Please enter Address';} elseif(empty($AboutYourself)){echo 'Please enter About Yourself';} [b]elseif($countCheck==0){ echo 'You have to register at least one activity.';}[/b] else { $dbc=mysqli_connect('localhost','root','','nog'); $query="select * from registration where LoginId='$LoginId'"; $result=mysqli_query($dbc,$query); if(mysqli_num_rows($result)==0) { $checkbox=$_POST['checkbox']; $countCheck=count($_POST['checkbox']); $reg_id=' '; for($i=0;$i<$countCheck;$i++) { $reg_id=$reg_id.$checkbox[$i].','; } $query="insert into registration (LoginId,Password,Name,Age,BloodGroup,Sex,Qualification,Email,Address,AboutYourself,Activity)values ('$LoginId',SHA('$Password1'),'$Name','$Age','$BloodGroup','$Sex','$Qualification','$Email','$Address','$AboutYourself','$reg_id')"; $result=mysqli_query($dbc,$query) or die("Not Connect"); echo ' Dear '.$Name.'.<br>Your Account is waiting for approval<br>'; echo "<a href='RegistrationAndActivity.php'>Back to Home</a>"; //header('Location: index.php'); // header('Location: Registration.php'); } else { echo 'Dear '.$Name. ' <br>Account already exist with Login Id '.$LoginId.' <br>Try another Login Id'; }} } ?> <html> <body> <?php echo $error_msg; ?> <h3>New User?</h3> <form action='<?php echo $_SERVER['PHP_SELF'];?>' method='post'> Enter Login id<br><input type='text' name='LoginId' value='<?php if(!empty($LoginId))echo $LoginId;?>'/><br> Enter Password<br><input type='password' name='Password1' value='<?php if(!empty($Password1))echo $Password1;?>'/><br> Confirm Password<br><input type='password' name='Password2' value='<?php if(!empty($Password2))echo $Password2;?>'/><br> Enter Name<br><input type='text' name='Name' value='<?php if(!empty($Name))echo $Name;?>'/><br> Enter Age<br><HEAD> <SCRIPT language=Javascript> function isNumberKey(evt) { var charCode = (evt.which) ? evt.which : event.keyCode if (charCode > 31 && (charCode < 48 || charCode > 57)) return false; return true; } </SCRIPT> </HEAD> <INPUT onkeypress='return isNumberKey(event)' type='text' name='Age' value='<?php if(!empty($Age))echo $Age;?>'><br/> Enter Blood<br><input type='text' name='BloodGroup'value='<?php if(!empty($BloodGroup))echo $BloodGroup;?>'/><br> Enter Sex<br><input type='text' name='Sex'value='<?php if(!empty($Sex))echo $Sex;?>'/><br/> Enter Qualification<br><input type='text' name='Qualification' value='<?php if(!empty($Qualification))echo $Qualification;?>'/><br> Enter Email<br><input type='text' name='Email' value='<?php if(!empty($Email))echo $Email;?>'/><br> Enter Address<br><input type='text' name='Address' value='<?php if(!empty($Address))echo $Address;?>'/><br> About Yourself<br/><textarea rows='10' cols='22' name='AboutYourself' value='<?php if(!empty($AboutYourself))echo $AboutYourself;?>'></textarea><br/> <?php echo" <b>Select fields for which you want to register</b><br/>"; $dbc=mysqli_connect('localhost','root','','nog'); $query="select * from activity"; $result=mysqli_query($dbc,$query); while($row=mysqli_fetch_array($result)){ $Title=$row['Title']; $ActivityId=$row['ActivityId']; echo $Title; //echo $ActivityId; [b]echo "<input type='checkbox' name='checkbox[]' value=$ActivityId />"[/b];//value=$ActivityId tells ActivityId variable extracts with name="checkbox" echo "<br/>"; } echo "<input type='submit' value='Register' name='submit'/><br>"; echo "</form> </body> </html>";?> Quote Hi friends......... In above code I want to manadatory the checkboxes which works properly as well but when user not select any checkbox it should display "You have to register at least one activity." according to above code but user get an extra server error also "Notice: Undefined index: checkbox in C:\wamp\www\NGOProject\RegistrationAndActivity.php on line 16 You have to register at least one activity. " I don't want to display this extra server error "Notice: Undefined index: checkbox in C:\wamp\www\NGOProject\RegistrationAndActivity.php on line 16" to user............... please help me .......... Anyone??????????????? thanks in advance.................. Hey, So I'm doing a school assignment and my professor wants us to use an array to display forms and I have no idea how to do that.
He wants us to create an array of arrays like this: display_form( array( "type" => "text", "name" => "first_name", "value" => "", "label" => "First Name" ), array( "type" => "text", "name" => "last_name", "value" => "", "label" => "Last Name" ), array( "type" => "email", "name" => "email", "value" => "", "label" => "Email" ), array( "type" => "number", "name" => "extension", "value" => "", "label" => "Extension" ) ); But I dont understand how you use that array to actually display the form. Does anyone know how? Hi I have an array of checkboxes whose values if checked can be updated in mysql. The code I have below accomplishes that just fine. On my form I have: print "<form method='post' action='update.php'>\n"; /////// mysQL query here $myID = $itemRow['myID']; $chk = $itemRow['item_shipped'] == 1 ? 'checked' : ''; echo "<input type=checkbox name=cbox[] value='{$itemRow['myID']}' $chk>"; echo"</form>"; The above code displays various items with a checkbox next to them. So if that checkbox is checked the code below stores that in mysql. On my update.php page I have: if(sizeof($_POST['cbox'])) { //means if at least one check box is selected foreach($_POST['cbox'] AS $id) { mysql_query("UPDATE om SET item_shipped ='1' WHERE myID=$id"); } //end foreach } //end IF The problem is though i can check a checkbox and store that value '1' in mysql, I have no way of unchecking an already checked checkbox and storing the '0' in mysql. Can anyone help? Thanks in advance hi, i am showing an error when i submit a form and a checkbox is not checked. here is the line that is giving me the error. any fix for this? Error Code: [Select] Notice: Undefined index: billable in E:\Website\portal\mobile\editreport.php on line 14 Code Code: [Select] if($_POST['billable'] == "ON") { $pbillable = "1"; } else { $pbillable = "2"; } Even though i am getting an error, it still updates my database with a number 2. Hi, I just cannot seem to get this to work, have been testing and searching all morning and not getting anywhere. I have a form with a series of checkboxes which populates the MySqL database, this works fine. Trying to print the results from the form if the row is empty show an unchecked checkbox, if there is a value show a checked checkbox. I have tested my if statement and can echo correctly wether empty or not empty, just cannot get the checkbox to be unticked if there is no value in the row Code: [Select] while ($row = mysql_fetch_array($qry, MYSQL_BOTH)) { // show total fields for debugging // $totalfields = mysql_num_fields($qry); // print ($totalfields) ; // if ( ! empty ( $row ['acid_wash'] ['neutralise'] ['clean'] ) ) { if ( ! empty ( $row ['clean'] ) ) { ///if it's 1 (true) then we add 'checked' to a variable we will use in the input //to cause it to be checked $checked = 'checked'; // test if row has data echo "full"; }else{ //if the value is 0 (false) we set the variable to be empty, not checked $checked = ''; // test for no value echo "empty" ; } To Display Result: <tr> <td>High Pressure Clean <input style='font-size:10px;' name='clean[]' type='checkbox' checked='$checked'></td> </tr> The empty and full test echos do seem to work, showing me the if statement works. The problem is even when the row is empty the checkbox shows checked.... Thanks. Hi, my PHP code currently outputs the results from a users search by querying a backend postgresql database. As result/row is retuned to the user i would like to be able to detect whether or not they have checked a checkbox at the end of each rown in which case multiple rows can then be deleted from the database upon the user clicking a 'delete multiple records' button. I have no problem in being able to display the checkboxes on the webpage but i am a little unsure as to how to refernce them and detect which ones the user has checked. Given my database stores hostnames/IP addresses would it be best to name each checkbox to reflect the hostname or name the value it returns when checked to reflect the hostname. Given the above and that I also store the results of a users search in a $_SESSION['hosts'][][] array how can I then tie the two together? Thanks for reading. I'm having troubling with trying to create a function to spit out a single array with the following array. I can write it in a away that looks through the arrays manually. the results i am trying to generate is that each item in generated array. Array to convert
array(
"account" => array(
"login",
"register",
"logout",
"edit",
),
"p" => array(
"report",
),
"array1.0" => array(
"array2.0" => array(
"array3.0",
"array3.1
),
"array2.1",
),
generating the array will look like this
Array ( [0] => account [1] => account/login [2] => account/register [3] => account/logout [4] => account/edit [5] => p [6] => p/report [7] => array1.0 [8] => array1.0/array2.0 [9] => array1.0/array2.0/array3.0 [10] => array1.0/array2.0/array3.1 [11] => array1.0/array2.1 ) The idea is that id generates a single array with combined labels and arrays inside, etc. I just can't figure out how to create a script that will create this array even If I add a new value or array.
I have this thing that i am trying to make but i cant get it to work.. can anyone help? Code: [Select] function sql_read( $dbname,$dbusername,$dbpassword ) { $names = array(); $password = array(); $connect = @mysql_connect("mysql11.000webhost.com",$dbusername,$dbpassword) or die("Could Not Connect"); @mysql_select_db ($dbname) or die("Could not find DataBase"); $query = mysql_query("select * from users"); $numrows = mysql_num_rows($query); if ($numrows > 0){ while($row = mysql_fetch_assoc($query)){ $names[] = $row["uname"]; $password[] = $row["password"]; $id = $row["id"]; } $return = array($names,$password,$id); }else{ $return = array(); } return $return[]; } $names = array(); $names = sql_read("XXXXXX","XXXXXX","XXXXXXX")[0]; The error i get is Code: [Select] Parse error: syntax error, unexpected '[' in /home/a5480952/public_html/sql/index.php on line 28 Line 28 is "$names = sql_read("XXXXXX","XXXXXX","XXXXXXX")[0];" Please help... i REALLLLD need help with this.. ask questions if you want to know more about what i am trying to do... thanks! Hello everybody, I have a question I've been striving with for a while and I was wondering if someone more experienced than me could have an answer or point me in the right direction. I'm building a website with an integrated forum what is the best system to detect and return which post is 'new', which one is 'hot' and which one hasn't changed from the user's last visit? In my user's table I store the last time the user logged in and the last time the user browsed a page... but it seems to be not enough to accurately return the information I need... Any suggestion is appreciated. Thanks. im trying to run a query which will get posts from the database that have tags similar to the current ones. Unfortunatly the echoed result isnt displaying as it should. $query = $link->query("SELECT t.*, p.* FROM ".TBL_PREFIX."topics t JOIN ".TBL_PREFIX."posts p ON (p.p_tid = t.t_tid) WHERE t.t_name = '".decode_url($_GET['t_name'])."' LIMIT 1") or die(print_link_error()); $row = $query->fetch(PDO::FETCH_ASSOC); $tag_query = $link->query("SELECT p_name FROM ".TBL_PREFIX."posts WHERE MATCH (p_tags) AGAINST ('".$row['p_tags']."' IN BOOLEAN MODE) ")or die(print_link_error()); $result = $tag_query->fetch(); foreach($result as $key => $value) { echo 'Name = '.$result[$key]['p_name'].'<br />'; } i have done a dump of result and it shows: Code: [Select] $ => Array (2) ( ['p_name'] = String(12) "File Updates" ['0'] = String(12) "File Updates" ) but there should only be one item in this array(p_name). I dont know where the second is coming from. The query has pulled the right results, it just isnt displaying it right. Hey! So, I don't know if this is the current section, couldn't really decide on what section/board to post it, so ..
I've got a code that I got from a friend of mine (it was a gaming website (a game server), but he shut it down, I asked for some scripts, he sent me the whole site ..). I got all other scripts correctly, but I do not know how to get this Last Forum Posts to work (IP.Board). I've got the SEO set up as it should and everything, doesn't work.
When I use this
<?php
$_handlerForum = new mysql("Forum","localhost","*********_fqipb2","*********_fqipb2","password");
$topics = $_handlerForum->fetch("SELECT `tid`,`title`,`last_post`,`title_seo`,`last_poster_name` FROM `topics` ORDER BY `last_post` DESC LIMIT 0,3;",array());
$content = "";
foreach($topics as $topic) {
$content .= "<a href='http://website.com/forum/index.php?/topic/".$topic['tid']."-".$topic['title_seo']."' target='_blank'>".$topic['title']."</a><br />
<small class='dim'>".$topic['last_poster_name']." - ".date("H:i F d, Y",$topic['last_post'])."</small><hr style='margin: 5px 0px;' />";
}
return $content;
return "Under Construction";
?>
I get this error
Fatal error: Class 'mysql' not found in /home/***/***/***/public_html/extra/forum.php on line 2Thought that the problem was "new mysql" (on line 2), so I put in mysql_connect, still get an error. Can anyone help? I have made a website that deals with the sales of different products. It handles the total sales of a specific product. One of the aspects of the website is that it can change the current sales data of the products. At the moment I can change the sales figures fine however I have to click the submit button once and then physically refresh the page for it to change the data in the table. Is there a way that I can automatically refresh the page once the submit button is pressed? I have tried using headers for example: Code: [Select] if (!empty($_POST['NSales'])) { header('location: currentpage.php'); } however this just constantly refreshes the page. Any help would be greatly appreciated Hi there, I have a piece of code that takes all posts with the category of 'model' and puts it on the models page. It then displays the post as a gallery using fancy box. The problem is I want all posts with the category of 'faces' to go on the faces page, but at the moment they are appearing on both pages. Here is the code I have. Any help will guarantee a donation as I am at my wits end trying to figure this out. Code: [Select] <?php global $post; $args = array( 'numberposts' => 8, 'offset' => 0, 'category' => 'models', 'orderby' => 'post_date', 'order' => 'DESC', 'post_type' => 'post', 'post_status' => 'publish' ); $posts_array = get_posts( $args ); $x = 1; // track model foreach( $posts_array as $post ) { setup_postdata($post); ?> <div id="model-thumb"> <?php $arg2 = array( 'post_type' => 'attachment', 'numberposts' => -1, 'order' => 'ASC', 'post_status' => null, 'post_parent' => $post->ID ); $attachments = get_posts($arg2); if ($attachments) { $i = 1; // track images foreach ( $attachments as $attachment ) { $image_attributes = wp_get_attachment_image_src( $attachment->ID, 'full' ); if ($i == 1) { // Get thumbnail info to display with second image $img1src = $image_attributes[0]; $img1w = $image_attributes[1]; $img1h = $image_attributes[2]; } elseif ($i == 2) { // Display thumbnail with link to second image ?> <a class="allModels" rel="gallery<?php echo $x; ?>" href="<?php echo $image_attributes[0]; ?>" ?><img src="<?php echo $img1src; ?>" width="<?php echo $img1w; ?>" height="<?php echo $img1h; ?>"/></a><br /><p><?php the_content();?></p></div> <?php } else { // Other images ?> <div style="display:none;"><a class="allModels" rel="gallery<?php echo $x; ?>" href="<?php echo $image_attributes[0]; ?>"><img src="<?php echo $image_attributes[0]; ?>" width="<?php echo $image_attributes[1]; ?>" height="<?php echo $image_attributes[2]; ?>"/></a></div> <?php } $i++; // Increase image count } } $x++; // Increase model count } ?> i have a problem..my posts are showing up like this: July 6: post message July 6: post message July 6: post message im trying to get it like this: July 6: post message post message post message how do i group them like this in all in one post? Hey all, I have a relationship where a zone has many posts and a category has many zones but a zone can also have many categories. The zones are basically parts of a page, such as the main area and sidepanel stored in database as records with name fields such as 'panel' and 'main'. There's a serious flaw right now and I would like to know the best solution to address it. Right now I access the posts of a zone of a category like this: Code: [Select] $category->zone->get()->post->get(); The above ends up displaying all the posts in the database for any given category because when category is selected, it searches for the associating zones, and then selects all posts related to those zones, which is wrong. i want to select all posts of the zones associated with that particular category. Current database: Code: [Select] posts id zone_id zones id name categories_zones id zone_id category_id categories id What should I do? Add a category_id column to the posts table and relate the post directly to the category as well as directly to the zones table so the post table would have two foreign keys: category_id and zone_id Would this be the most effective thing to do given my requirements? Thanks for response. |
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