PHP - Php Date() Issues...
I'm trying to write a function that'll give me the days of the week of any submitted date. This keep returning 1/30/2011 even though I am submitting 1/05/2011 (the Monday should be 1/03/2011)...I know it's incomplete I'm just trying to get the Monday right now
Code: [Select] function getWeekDays($date) { //convert string to date $thisdate = date($date); $dow = idate('w', mktime(0,0,0,$thisdate)); if ($dow == 1) { $monday = date('m/d/Y', mktime(0,0,0, date('m'), date('d', $thisdate), date('Y'))); } else if ($dow == 2) { $monday = date('m/d/Y', mktime(0,0,0, date('m'), date('d', $thisdate) - 1, date('Y'))); } else if ($dow == 3) { $monday = date('m/d/Y', mktime(0,0,0, date('m'), date('d', $thisdate) - 2, date('Y'))); } else if ($dow == 4) { $monday = date('m/d/Y', mktime(0,0,0, date('m'), date('d', $thisdate) - 3, date('Y'))); } else if ($dow == 5) { $monday = date('m/d/Y', mktime(0,0,0, date('m'), date('d', $thisdate) - 4, date('Y'))); } $weekarray = array($thisdate); return $weekarray; } Similar TutorialsFor some reason the time is always staying the same throughout the listing tweets even when there's posts with different times. What am I doing wrong? function getTwitterStatus($userid, $x) { $url = "http://twitter.com/statuses/user_timeline/$userid.xml?count=$x"; $xml = simplexml_load_file($url) or die("could not connect"); foreach ($xml->status as $status) { $text .= "<tr>"; $text .= "<th>" . date("m/d/Y - g:ia", strtotime($xml -> status[0] -> created_at)); "</th>"; $text .= "<td class=\"full\">" . $status -> text . "</td>"; $text .= "<td><img src=\"images/ball_grey_16.png\" class=\"block cr-help\" alt=\"\" title=\"Twitter Message\"/></td>"; } echo $text; } I'm having some trouble understanding how to use date and time when updating my database. The table is already populated with Date and Time fields in date and time format. I need to update the table based on the date and time, but I can't make it work. I tested all the variables and they are being sent correctly. I'm pretty sure the problem lies in how I'm trying to match the Date and Time fields with $dateID and $timeID in the WHERE part of the query, but I'm not sure how to fix that! Code: [Select] <?php include("opendatabase.php"); $size = count($_POST['player1']); $i=0; $thisyear = date("Y"); while ($i < $size) { $dateID = $_POST['date'][$i]; $timeID = $_POST['time'][$i]; $player1 = ($_POST['player1'][$i]); $player2 = ($_POST['player2'][$i]); $player3 = ($_POST['player3'][$i]); $player4 = ($_POST['player4'][$i]); $player5 = ($_POST['player5'][$i]); mysql_query(" UPDATE Daysheets$thisyear SET Player1='$player1', Player2='$player2', Player3='$player3', Player4='$player4', Player5='$player5' WHERE Date = '$dateID' AND Time = '$timeID' "); $i++; } header("Location: /teetimes/publicteetimes.php?teetimedate=$dateID"); mysql_close($con) ?>Any help appreciated! I should also mention that whenever I run this query it erases anything that was previously entered in the database except the date and time columns... Hi everyone, I have a basic calendar that I am trying to change to highlight the current date. I have got the current date highlighted using an if else statement inside a while clause, however, the issue arises when I use the forward/previous links to go to a different month - the same day is highlighted on those months as well. Here is the code snippet in question (the entire code is below): while( $day_num <= $days_in_month ) { if(date('d') != $day_num) { echo "<td> $day_num </td>"; $day_num++; $day_count++; } // display today's date else { echo "<td class=\"today\"> $day_num </td>"; $day_num++; $day_count++; } My question is how do I get this calendar to display the current date, just on the current month. I assume there is something I am missing when it comes to handling the date(s) correctly, but what? Any help is appreciated. Thanks, kaiman Full code: // gets today's date $date = time () ; // puts the day, month, and year in seperate variables $day = date('d', $date) ; $month = (int) ($_GET['month'] ? $_GET['month'] : date('m')); $year = (int) ($_GET['year'] ? $_GET['year'] : date('Y')); // generate the first day of the month $first_day = mktime(0,0,0,$month, 1, $year) ; // get the month name $current_month = date('F', $first_day) ; // determine what day of the week the first day of the month falls on $day_of_week = date('D', $first_day) ; // determine blank days before start of month switch($day_of_week){ case "Sun": $blank = 0; break; case "Mon": $blank = 1; break; case "Tue": $blank = 2; break; case "Wed": $blank = 3; break; case "Thu": $blank = 4; break; case "Fri": $blank = 5; break; case "Sat": $blank = 6; break; } // determine how many days are in the current month $days_in_month = cal_days_in_month(0, $month, $year) ; // determine next month $next_month_link = '<a href="?month='.($month != 12 ? $month + 1 : 1).'&year='.($month != 12 ? $year : $year + 1).'">>></a>'; // determine previous month $previous_month_link = '<a href="?month='.($month != 1 ? $month - 1 : 12).'&year='.($month != 1 ? $year : $year - 1).'"><<</a>'; // start building the table echo " <table border=0 width=294>\n"; echo " <tr>\n"; // display month and year echo " <th> $previous_month_link </th>\n"; echo " <th colspan=4> $current_month $year </th>\n"; echo " <th> $next_month_link </th>\n"; echo " </tr>\n"; // display days of week echo " <tr>\n"; echo " <td width=42>S</td>\n"; echo " <td width=42>M</td>\n"; echo " <td width=42>T</td>\n"; echo " <td width=42>W</td>\n"; echo " <td width=42>T</td>\n"; echo " <td width=42>F</td>\n"; echo " <td width=42>S</td>\n"; echo " </tr>\n"; // counts the days in the week $day_count = 1; echo " <tr>\n"; // display blank days while ( $blank > 0 ) { echo " <td></td>\n"; $blank = $blank-1; $day_count++; } // sets the first day of the month to 1 $day_num = 1; // count the days in the month and display them while( $day_num <= $days_in_month ) { if(date('d') != $day_num) { echo "<td> $day_num </td>"; $day_num++; $day_count++; } // display today's date else { echo "<td class=\"today\"> $day_num </td>"; $day_num++; $day_count++; } // make sure we start a new row every week if ($day_count > 7) { echo " </tr>\n"; echo " <tr>\n"; $day_count = 1; } } // finish calendar while ( $day_count >1 && $day_count <=7 ) { echo " <td>\n"; echo " </td>\n"; $day_count++; } echo " </tr>\n"; echo " </table>\n"; I'm working on a project that has a lot of different timezone options, and all I have from the users is their UTC offset. After weeks of doing tweaks, I come to new issues every time I add something, one would think it would be a lot easier to just get the correct time and day :) The latest issue is that when I try to rewrite a date to a better fomat, it disregards the GMT offset. Like this: 4/14/19, 12:00 PM GMT+2 (=$date) becomes ... 14-04-2019 10:00 when using this code: $bp_date_to_format = date_create_from_format('Y-m-d\TH:i:sP', $date); echo date_format($bp_date_to_format, 'd-m-Y H:i'); I figured it would just rewrite the format, keeping the exact time. It isn't. We do have all these sorts of localization functions as well, but because there doesn't seem to be one single standard (each 3rd party API connection we have uses its own default datetime format so it seems). // Remove UTC Text $UTC_offset = str_replace('UTC', '', $timezone); // Get Offset in Minutes if (stripos($UTC_offset, ':') !== false) { // Calculate seconds from offset list($hours, $minutes) = explode(':', $offset); $seconds = $hours * 60 * 60 + $minutes * 60; } else { $seconds = $UTC_offset * 60 * 60; } // Get User timezone name from seconds $timezone = timezone_name_from_abbr('', $seconds, 1); if ($timezone === false) { $timezone = timezone_name_from_abbr('', $seconds, 0); } // Set new TZ return date_default_timezone_set($timezone);
Isn't there any "one way"solution that can be used? It's confusing to say the least.
Cheers. Hey, I'm using a script which allows you to click on a calendar to select the date to submit to the database. The date is submitted like this: 2014-02-08 Is there a really simple way to prevent rows showing if the date is in the past? Something like this: if($currentdate < 2014-02-08 || $currentdate == 2014-02-08) { } Thanks very much, Jack Hello. I'm new to pHp and I would like to know how to get my $date_posted to read as March 12, 2012, instead of 2012-12-03. Here is the code: Code: [Select] <?php $sql = " SELECT id, title, date_posted, summary FROM blog_posts ORDER BY date_posted ASC LIMIT 10 "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { $id = $row['id']; $title = $row['title']; $date_posted = $row['date_posted']; $summary = $row['summary']; echo "<h3>$title</h3>\n"; echo "<p>$date_posted</p>\n"; echo "<p>$summary</p>\n"; echo "<p><a href=\"post.php?id=$id\" title=\"Read More\">Read More...</a></p>\n"; } ?> I have tried the date() function but it always updates with the current time & date so I'm a little confused on how I get this to work. I have tried a large number of "solutions" to this but everytime I use them I see 0000-00-00 in my date field instead of the date even though I echoed and can see that the date looks correct. Here's where I'm at: I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year. Using the POST array, I have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. <code> $date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day']; echo $date_value; </code> This outputs 2012-5-7 in my test echo but 0000-00-00 in the database. I have tried unsuccessfully to use in a numberof suggested versions of: strtotime() mktime Any help would be extremely appreciated. I am aware that I need to validate this data and insure that it is a valid date. That I'm okay with. I would like some help on getting it into the database. Alright, I have a Datetime field in my database which I'm trying to store information in. Here is my code to get my Datetime, however it's returning to me the wrong date. It's returning: 1969-12-31 19:00:00 $mysqldate = date( 'Y-m-d H:i:s', $phpdate ); $phpdate = strtotime( $mysqldate ); echo $mysqldate; Is there something wrong with it? Hi, I have a job listing website which displays the closing date of applications using: $expired_date (This displays a date such as 31st December 2019) I am trying to show a countdown/number of days left until the closing date. I have put this together, but I can't get it to show the number of days. <?php $expired_date = get_post_meta( $post->ID, '_job_expires', true ); $hide_expiration = get_post_meta( $post->ID, '_hide_expiration', true ); if(empty($hide_expiration )) { if(!empty($expired_date)) { ?> <span><?php echo date_i18n( get_option( 'date_format' ), strtotime( get_post_meta( $post->ID, '_job_expires', true ) ) ) ?></span> <?php $datetime1 = new DateTime($expired_date); $datetime2 = date('d'); $interval = $datetime1->diff($datetime2); echo $interval->d; ?> <?php } } ?> Can anyone help me with what I have wrong? Many thanks (continuing from topic title) So if I set a date of July 7 2011 into my script, hard coded in, I would like the current date to be checked against the hard coded date, and return true if the current date is within a week leading up to the hard coded date. How could I go about doing this easily? I've been researching dates in php but I can't seem to work out the best way to achieve what I'm after. Cheers Denno Hi, Currently I am making a module for joomla. every article has an publish date, if the article was published in 7 days ago, it will displayed as "article in last week", My idea is to use today's date - publish date, if the result is greater than 7 and smaller than 14, the article will be displayed as "article in last week. Any one know how to write this code? Here is what I have got, but not working. <?php $todays_date = date("Y-m-d"); $result = mysql_query("select * from jos_content where $test between $todays_date-14 and $todays_date-7"); while($row = mysql_fetch_array($result)) { echo "$todays_date - $row[title]"; } ?> Hi guys, I'm putting together a small event system where I want the user to add his own date and time into a textfield (I'll probably make this a series of drop-downs/a date picker later). This is then stored as a timestamp - "0000-00-00 00:00:00" which displays fine until I try to echo it out as a UK date in this format - jS F Y, which just gives today's date but not the inputted date. Here's the code I have right now: Code: [Select] $result = mysql_query("SELECT * FROM stuff.events ORDER BY eventdate ASC"); echo "<br />"; echo mysql_result($result, $i, 'eventvenue'); echo ", "; $dt = new DateTime($eventdate); echo $dt->format("jS F Y"); In my mysql table eventdate is set up as follows: field - eventdate type - timestamp length/values - blank default - current_timestamp collation - blank attributes - on update CURRENT_TIMESTAMP null - blank auto_increment - blank Any help as to why this could be happening would be much appreciated, thanks. i have a table that shows payments made but want to the payments only showing from a set date(06/12/14) and before this date i dont want to show
this is my sql that doesnt seem to work and is showing dates before the specified date.
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"SELECT * FROM payments2014, signup2014, editprop2014 WHERE signup2014.userid = payments2014.payment_userid AND editprop2014.prop_id = signup2014.prop_id AND signup2014.userid !='page1' AND signup2014.userid !='page6' AND signup2014.userid !='page4' AND payments2014.payment_transaction_status !='none' AND payments2014.payment_transaction_status !='CANCELLEDa' AND payments2014.payment_type !='deposit' AND payments2014.payment_paid_timestamp NOT LIKE '%2012%' AND payments2014.payment_paid_timestamp NOT LIKE '%2011%' AND payments2014.payment_paid_timestamp >= '06/12/14' ORDER BY payments2014.payment_id DESC"i have some other parts in the statment but this one that should be filtering is host_payments2014.payment_paid_timestamp >= '06/12/14'thanks in advance I'm getting this Time Zone error. Perhaps it's a compatibility issue with PHP 5.3. Looked all over for an answer without finding one. Here is the error message Warning: date() [function.date]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST' instead in /blocked.php on line 41 12/02/12 Here is the code. Line 41 is near the bottom, the one with the d,m,y. Perhaps the echo date (d/m/y") needs to be changed. Appreciate any help! Code: [Select] <table border="3" width="16%" align="center" cellspacing="0" bgcolor="#FF6600" bordercolor="red" bordercolordark="red" bordercolorlight="red"> <tr> <td width="176"> <p align="center"><?php // shows IP Number on Page echo $ip; ?> </p> </td> </tr> </table> <p align="center"><?php // Show the user agent echo 'Your user agent is: <b>'.$_SERVER['HTTP_USER_AGENT'].'</b><br />';?></p> [b]<h1 align="center"><?php echo date("d/m/y");?></h1>[/b] </td> </tr> </table [,code] Hi Guys.. How can I change a date on the fly ? Everything is UTC on my server. How can I change a date to something else on the fly? Ie: $timezone = "cet"; $datetime = "2011-09-04 19:53:00"; echo $datetime($timezone); So I can give it a datetime and have it echo the datetime as if it were in the other timezone? Thanks Graham Hi there, I have a string '12/04/1990', that's in the format dd/mm/yyyy. I'm attempting to convert that string to a Date, and then insert that date into a MySQL DATE field. The problem is, every time I try to do so, I keep getting values like this in the database: 1970-01-01. Any ideas? Much appreciated. Hi, I am trying to convert a String date into numeric date using PHP function's, but haven't found such function. Had a look at date(), strtotime(), getdate(); e.g. Apr 1 2011 -> 04-01-2011 Could someone please shed some light on this? Regards, Abhishek Hi, I have database stored a field of date. I want to check if the date in the DB field is the same as the current date, how to do it? Code: $oracle = mysqli_real_escape_string($con, $_POST['oracle']); $query = mysqli_query($con, "SELECT indate FROM staff WHERE OracleID ='$oracle'"); $row = mysqli_fetch_array($query); $num_row = mysqli_num_rows($query); if ($num_row > 0) { $curdate = date(); if ($row['indate'] !== $curdate) { $query1=mysqli_query($con, "update staff set ClockedIn = 0, ClockedOut = 0 where OracleID='$session_id'")or die('Error In Session'); header('location:home.php'); } }
Does anybody know how to take the queried standard date format - 2012-04-02 for example - and print it to the page as April 2, 2012? Or at the very least, to switch to 04-02-2012? Trying to find some tutorials online. |