PHP - No Records Pulling From Database

Good evening,

This has been bugging me for 24 hours now. I have created 2 web applications. The first one is the dummy, and the second one is the final. Basically, this two web applications does the same, just a few modifications made on the final one. I have a process of pulling out of information from the database should the user would want to modify a field. I have a problem though, the dummy one works perfectly, but the new one don't. In fact, if I use the dummy php file together with the new files, the dummy won't be working. But if I use it together with the old files, it works perfectly fine.

This is the error I am getting:


Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\xampp\htdocs\invent-asia\edit_client.php on line 46

<?php
include("dbconnection.php");

if(isset($_POST["btnSubmit"]))
{
$id = $_POST["id"];
$territory = $_POST["territory"];
$job_title = $_POST["job_title"];
$area_of_work = $_POST["area_of_work"];
$employer = $_POST["employer"];
$location = $_POST["location"];
$job_title = $_POST["job_title"];
$date_posted = $_POST["date_posted"];
$closing_date = $_POST["closing_date"];
$department = $_POST["department"];
$gender = $_POST["gender"];
$first_name = $_POST["first_name"];
$last_name = $_POST["last_name"];
$title = $_POST["title"];
$telephone = $_POST["telephone"];
$address_1 = $_POST["address_1"];
$address_2 = $_POST["address_2"];
$address_3 = $_POST["address_3"];
$country = $_POST["country"];
$city = $_POST["city"];
$postal_code = $_POST["postal_code"];
$website = $_POST["website"];
$email_address = $_POST["email_address"];
$comment_by_cg = $_POST["comment_by_cg"];
$date_emailed = $_POST["date_emailed"];
$mailing_comments = $_POST["mailing_comments"];
$telesales_comments = $_POST["telesales_comments"];

$query = "UPDATE contacts SET territory= '".$territory."', job_title = '".$job_title."', area_of_work = '".$area_of_work."', employer = '".$employer."', location = '".$location."', job_title = '".$job_title."', employer = '".$employer."', date_posted = '".$date_posted."', department = '".$department."', closing_date = '".$closing_date."', gender = '".$gender."', first_name = '".$first_name."', last_name = '".$last_name."', title = '".$title."', telephone = '".$telephone."', address_1 = '".$address_1."', address_2 = '".$address_2."', address_3 = '".$address_3."', country = '".$country."', city = '".$city."', postal_code = '".$postal_code."', website = '".$website."', email_address = '".$email_address."', comment_by_cg = '".$comment_by_cg."', date_emailed = '".$date_emailed."', mailing_comments = '".$mailing_comments."', telesales_comments = '".$telesales_comments."' WHERE id = '".$id."'";
mysql_query($query) or die(mysql_error());

echo "<script>
alert('You have successfully updated a record');
window.location = 'view.php';
</script>";
}

$query = "SELECT * FROM contacts WHERE id = '".$_GET["id"]."'";
$result = mysql_query($query, $connection);

if(mysql_num_rows($result) > 0) - THIS IS THE 46th LINE IN THE CODE
{
$territory = mysql_result($result,0, "territory");
$job_title = mysql_result($result, 0, "job_title");
$area_of_work = mysql_result($result, 0, "area_of_work");
$employer = mysql_result($result, 0, "employer");
$status = mysql_result($result, 0, "status");
$location = mysql_result($result,0, "location");
$department = mysql_result($result,0, "department");
$date_posted = mysql_result($result,0, "date_posted");
$closing_date = mysql_result($result,0, "closing_date");
$gender = mysql_result($result,0, "gender");
$first_name = mysql_result($result,0, "first_name");
$last_name = mysql_result($result,0, "last_name");
$title = mysql_result($result,0, "title");
$telephone = mysql_result($result,0, "telephone");
$address_1 = mysql_result($result,0, "address_1");
$address_2 = mysql_result($result,0, "address_2");
$address_3 = mysql_result($result,0, "address_3");
$city = mysql_result($result,0, "city");
$country = mysql_result($result,0, "country");
$postal_code = mysql_result($result,0, "postal_code");
$website = mysql_result($result,0, "website");
$email_address = mysql_result($result,0, "email_address");
$comment_by_cg = mysql_result($result,0, "comment_by_cg");
$date_emailed = mysql_result($result,0, "date_emailed");
$mailing_comments = mysql_result($result,0, "mailing_comments");
$telesales_comments = mysql_result($result,0, "telesales_comments");
}
?>

Can anyone help me solve this issue? This is the only feature in my project that is left bugged

Your quick response is well appreciated. Thank you very much

Right now I am using code such as this:

$query = "SELECT somevalue FROM sometable WHERE id=1"
$result = mysql_query($update) or die ('Error in query: ' . mysql_error());

$somevalue = '';

if (mysql_num_rows($result) == 1)
  {
  while($row = mysql_fetch_assoc($userstatsresult))
    {
    $somevalue = $row['somevalue'];
    }
  }

echo $somevalue;

Is there a short-hand method to get that single value without the IF/WHILE stuff?

I am pulling an youtube embedded code from a database however when I have the homepage pull it from the database it will not show anything after the video....

EXAMPLE...(this is what it should look like)

1.) Title By: Author
     Youtube Video
     Message
     Posted By:

(however this is what it looks like)

1.) Title By: Author
     Youtube Video
 
*The "message" and "Posted By:" just do not show up*

The code is below can someone help me with this problem., it would be greatly appreciated.


Code: [Select]
<?php
//open database
$connect = mysql_connect("Database","name","password") or die("Not connected");
mysql_select_db("database") or die("could not log in");

$query = "SELECT * FROM boox ORDER BY date DESC";
$result = mysql_query($query);

 // Get the page number, if none is set - it is 0
if( isset($_GET['page']) )
{ 
$page =$_GET['page']; 
}
else
{
$page  = 0;
}

$resultsPerPage = 15;
$num = mysql_num_rows($result); // amount of rows
$loops = $page*$resultsPerPage; // starting loops at..

while ($loops < $num && $loops <  ($page+1)*$resultsPerPage )
{
$link = mysql_result($result,$loops,"link"); // get result from the 'link' field in the table
$username = mysql_result($result,$loops,"username"); // get result from the 'username' field in the table
$messsage = mysql_result($result,$loops,"message");
$author = mysql_result($result,$loops,"author");
$title = mysql_result($result,$loops,"title");
$date = mysql_result($result,$loops,"date");
if ($pagelimit == 0)
{
$pagelimit == 1;
}
if ($pagelimit <= 15)
// echo stuff here
$loopz = $loops + 1;
 echo "&nbsp;&nbsp;&nbsp
 </br><align='left'><table width='297' height='900' border='1' align='center' bgcolor='#111'>
  <tr>
    <td>$loopz.)&nbsp;$title By: $author
</br>
$link
</br>
$message
</br>
Posted By: $username $date
</td>
  </tr>
</table></br><br>";
 $count++ ;
 $pagelimit++;
 $loops++;
}

if ( $page!=0 ) // Show 'Previous' link
{
$page--;
$prevpage = ($page +  1);
echo "<br><br><br><a href='index.php?page=$page'>Previous  $prevpage &nbsp;&nbsp;&nbsp;&nbsp;</a>";
$page++;
}
if ($loops > 5&&($page+1)*$resultPerPage < $num ) // Show 'next' link
{
$page++;
$nextpage = ($page + 1);
echo "<a href='index.php?page=$page'>   Next $nextpage</a>";
}
 
?>

Unfortunately I have no code for this yet cuz I don;t even know if its possible...

I am programming an application that is used by a couple of stores, which could end up being a lot of stores.

Anyways, the basis is that the stores would, though a separate application (and therefore separate database) create a username and password, I now want to use this username and password to do the following

1. Allow them to login to my application using the same username and password
2. I want the store the username in a session to pull tables based on the username from my database

For instance, a user has the login store123, after loggin in it now pulls the information from the tables store123_items, store123_prices, store123_settings, etc. Now my database will have quite a lot of store###_tables

I am, sadly, a noobie to PHP and I do recall seeing an article (somewhere on the net, and I stupidly forgot to bookmark it, knowing I would need it eventually) on how to access multiple databases easily.  Now because they are both under my account I can use the same username and password for both, its accessing the MySQL username/password database and storing the info I know I am lacking on how to do it.

Any ideas?

Hi,

I have a table that contains posts and each post has a datetime field.

Im trying to work out how I can show entries from today, this week and this month so I can have a link that shows all posts from today or this month etc.

Any one know how I can do this ? My current piece of code that pulls the data from the db looks like this :

Code: [Select]
$texts= mysql_query("SELECT * FROM submittedtexts Order by id DESC LIMIT " . (($page - 1) * 6) . ", 6");
I want to add a bit that acts like : WHERE date = today


Hope that makes sense, Im a bit of a newbie

Thanks in advance,

Scott

Hi all

Complete noob here.....

What I have to do is create a new database every year, but I can't just import last years data completely, only records when needed.

I can do it myself in PHPMyAdmin, but I don't want my employees touching mysql directly.

What I am trying to do is write a php script that will serach for a reocrd in last years database and if it exists insert it into the new database if it doesn't exists bring up a form so it can be entered.

Any help would be greatly appreciated.


Thanx
ZZ

I created this database
Code: [Select]
<?php
$mysqli = mysqli_connect('localhost', 'admin', 'jce123', 'php_class');
if(mysqli_connect_errno()) {
printf("connection failed: %s\n", mysqli_connect_error());
exit();
}else{
$q = mysqli_query($mysqli, "DROP TABLE IF EXISTS  airline_survey");
  if($q){echo "deleted the table airline_survey....<br>";}
  else{echo "damm... ".mysqli_error($mysqli);}
$sql = "CREATE TABLE airline_survey
(
id INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
staff CHAR(10) NOT NULL,
luggage CHAR(10) NOT NULL,
seating CHAR(10) NOT NULL,
clean CHAR(10) NOT NULL,
noise CHAR(10) NOT NULL 
)"; 
$res = mysqli_query($mysqli, $sql);
if($res === TRUE) {
echo "table created";
} else {
printf("Could not create table: %s\n", mysqli_error($mysqli));
}
mysqli_close($mysqli);
}
?>
When I look at it it looks fine.
I have a form that sends data to this script:
Code: [Select]
<?php
$con = mysql_connect('localhost', 'admin', 'abc123');
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("php_class", $con);

foreach ($_POST as $key => $value) {
$staff = "";
$luggage = "";
$seating = "";
$clean = "";
$noise = "";

  switch($key){
   case "staff":
$staff = $value;
break;
case "luggage":
$luggage = $value;
break;
case "seating":
$seating = $value;
break;
case "clean":
$clean = $value;
break;
case "noise":
$noise = $value;
break;
    default:
echo "we must be in the twilight zone";
}
echo $staff."<br>";
[color=red] mysql_query("INSERT INTO airline_survey 
(staff, luggage, seating, clean, noise)
VALUES ($staff, $luggage, $seating, $clean, $noise)");[/color]
}

?>
as you can see right before the insert query I test one of the variables to see if it has the string I'm expecting and it does.
The problem is the script runs without giving me an error message but the data never gets inserted into the table.   

Google Chrome Developer Tool causes an error when I run the following and there are not any records.  I keep getting errors when I try to change it.

 

<?php
$host = 'localhost';
$user = 'root';
$pass = '';
$database = 'ecommerce';

$options = array(
    PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
    PDO::ATTR_EMULATE_PREPARES => false
);

$keyword = $_GET['keyword'];

$dbo = new PDO("mysql:host=$host;dbname=$database", $user, $pass, $options);


$q1 = "SELECT * FROM products INNER JOIN keywords on keywords.keywordID = products.KeywordID  and keywords.KeyWord1  = \"$keyword\"  ";

$counter = 10;
$counter1 = 0;

foreach ($dbo->query($q1) as $row) {
  
  

 

hello every body... two I'm creating an IPN in paypal for my membership site but the problem I'm facing is that on successfull verification of the purchase, four rows are getting inserted in the database...   The code is

<?php   
    require '../db.php';
    $paypalmode     =   '.sandbox';        
    $req = 'cmd=' . urlencode('_notify-validate');
    foreach ($_POST as $key => $value) {
        $value = urlencode(stripslashes($value));
        $req .= "&$key=$value";
    }
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, 'https://www'.$paypalmode.'.paypal.com/cgi-bin/webscr');
    curl_setopt($ch, CURLOPT_HEADER, 0);
    curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $req);
    curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 1);
    curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 2);
    curl_setopt($ch, CURLOPT_HTTPHEADER, array('Host: www'.$paypalmode.'.paypal.com'));
    $res = curl_exec($ch);
    curl_close($ch);

    if (strcmp ($res, "VERIFIED") == 0)
    {
        $transaction_id = $_POST['txn_id'];
        $payerid = $_POST['payer_id'];
        $firstname = $_POST['first_name'];
        $lastname = $_POST['last_name'];
        $payeremail = $_POST['payer_email'];
        $paymentdate = $_POST['payment_date'];
        $paymentstatus = $_POST['payment_status'];
        $mdate= date('Y-m-d h:i:s',strtotime($paymentdate));
        $otherstuff = json_encode($_POST);
        $date = date("y-m-d");
        
            $q = $pdo->connect()->query("INSERT INTO payment (mid,username,amount,paypal_id,txn_id,received_date)   VALUES('{$_SESSION['user_id']}','{$_SESSION['uname']}','{$_POST['mc_gross']}','{$_POST['payer_email']}','{$_POST['txn_id']}','$date')");
            $q->execute();
            $q1 = $pdo->connect()->query("UPDATE members SET amount_loaded = amount_loaded + {$_SESSION['amount']} WHERE mid = '{$_SESSION['user_id']}'");
            $q1->execute();
            //header("Location: funds.php");
            echo "verified";
        
        
}



?>

two for the payment and in the members table, the amount is getting doubled. (i.e if anybody purchases For $2, it shows $4 in the database....)   Any help will be really appreciated...

I have a problem .
I 've been trying for a long time to make an update for php mysql to change the data.
but every time I do not manage to make it work with a form.
but it works if I only if I put this ($ sql = "UPDATE users SET username = 'value' WHERE id = 10 " ; )
so it only works when I put the value of the id.

but I want in an html form to indicate what I want to change and what id goes.

but I have tried so long that I do not feel like I so want someone help me.

make the same database and same as my records and make the code and test it if it works show me please
my database name : web test
my table called : users
my records are called :

id int ( 11) AUTO_INNCREMENT
username , varchar ( 255 )
password , varchar ( 255 )
first_name , varchar ( 255 )
last_name , varchar ( 255 )
email, varchar ( 255 )
Age, int ( 11)             Look, my update.php is like this now
<?php
$servername = "localhost";
$username = "root";
$password = ".....";
$dbname = "webtest";


$conn = new mysqli($servername, $username, $password, $dbname);

if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
} 

$sql = "UPDATE users SET password='cotton candy' WHERE id=10";

if ($conn->query($sql) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $conn->error;
}

$conn->close();
?>
but now i have still have to go into the php file to change the valeu or the id 
but i looked on site and youtube how to put it in a simple html form 
but it still does not work.

i want it in a html from.
I want that when I enter the ID that the data of the user appears and that I can change any valeu separately.

Hello all.

Please I need help to update customer table. I get the texboxes populated with select query no problem.
 I have html page with a search box and when the user enter their first name or last name and click search it will call up the search.php file here is the file:

This code below populate the textboxes to be updated:

Code: [Select]
<?php


     if(isset($_POST['submit'])){ 
     if(isset($_GET['go'])){ 
     if(preg_match("^/[A-Za-z]+/", $_POST['name'])){ 
      $name=$_POST['name']; 
     } 
     } 
     else{ 
     echo  "<p>Please enter a search query</p>"; 
     } 
   }
//connect  to the database 


$con = mysql_connect("localhost","dbusrn","dbpwd");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("mydb", $con);
$name = $_POST['name'];
$result = mysql_query ("select * from Customer_Registration where Firstname like '%$name%' or lastname like '%$name%' ");



$row = mysql_fetch_row($result);
$cf_uid = $row[0];
$Firstname = $row[6];
$lastname = $row[7];
$Address = $row[8];
$Postcode = $row[9];
$Phone = $row[10];
$Email = $row[11];
$Customer_Type = $row[12];
$Computer_type = $row[13];
$Computer_maker = $row[14];
$Model = $row[15];
$OS = $row[16];
$Appointment_date = $row[17];
$Problem = $row[18];
$Solution = $row[19];
$Comment = $row[20];
?>



 <form action="updatecus1.php" method="post">
     
      <table width="100%" border="2" cellspacing="0" cellpadding="8">
     
      <tr><td width="45%" class="FormText">Customer ID:</td>
<td width="55%"><?php echo $cf_uid;?></td></tr>
<tr><td width="45%" class="FormText">First name:</td>
<td width="55%"><input  name="Firstname" type="text" value="<?php echo $Firstname;?>"?> </td></tr>


<tr><td width="45%" class="FormText">Last name:</td>
<td width="55%"><input  name="lastname" type="text" value="<?php echo $lastname;?>"?> </td></tr>



<tr><td width="45%" class="FormText">Address:</td>
<td width="55%"><input  name="Address" type="text" value="<?php echo $Address; ?>"?> </td></tr>

 <tr><td width="45%" class="FormText">Postcode:</td>
<td width="55%"><input  name="Postcode" type="text" value="<?php echo $Postcode; ?>"?> </td></tr>


 <tr><td width="45%" class="FormText">Phone:</td>
<td width="55%"><input  name="Phone" type="text" value="<?php echo $Phone; ?>"?> </td></tr>

 <tr><td width="45%" class="FormText">Email:</td>
<td width="55%"><input  name="Email" type="text" value="<?php echo $Email; ?>"?> </td></tr>

 <tr><td width="45%" class="FormText">Customer:</td>
<td width="55%"><input  name="Customer_type" type="text" value="<?php echo $Customer_Type; ?>"?> </td></tr>

 <tr><td width="45%" class="FormText">Computer :</td>
<td width="55%"><input  name="Computer_type" type="text" value="<?php echo $Computer_type; ?>"?> </td></tr>

 <tr><td width="45%" class="FormText">Manufactural:</td>
<td width="55%"><input  name="Computer_maker" type="text" value="<?php echo $Computer_maker; ?>"?> </td></tr>

 <tr><td width="45%" class="FormText">Model:</td>
<td width="55%"><input  name="Model" type="text" value="<?php echo $Model; ?>"?> </td></tr>

 <tr><td width="45%" class="FormText">Operating System:</td>
<td width="55%"><input  name="First name" type="text" value="<?php echo $OS; ?>"?> </td></tr>

 <tr><td width="45%" class="FormText">Appointment:</td>
<td width="55%"><input  name="Operating System" type="text" value="<?php echo $Appointment_date; ?>"?> </td></tr>

  <tr><td width="45%" class="FormText">Problem:</td>
<td width="55%"><textarea name="Problem" rows="10" cols="20" ><?php echo $Problem; ?></textarea></td></tr>

 <tr><td width="45%" class="FormText">Solution:</td>
<td width="55%"><textarea name="Solution" rows="10" cols="20" ><?php echo $Solution; ?></textarea></td></tr>

 <tr><td width="45%" class="FormText">Comment:</td>
<td width="55%"><textarea name="Comment" rows="10" cols="20" ><?php echo $Comment; ?></textarea></td></tr>

 
 
<td width="55%"><input name="submit"  value="submit"  type="submit" <br> <input type="Submit" value="Cancel"</br></td>


 </form>
         <?php



--------------------------------------------------------------------------------------
The update.php file have the following code:

Code: [Select]
<?php
//connect  to the database 


$con = mysql_connect("localhost","dbusrn","dbpwd");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("mydb", $con);

if (isset($_POST['submit']))  {

$cf_uid  = $_POST['cf_uid'];
$Firstname = $_POST['Firstname'];
$lastname = $_POST['lastname'];
$Address = $_POST['Address'];
$Postcode = $_POST['Postcode'];
$Phone = $_POST['Phone'];
$Email = $_POST['Email'];
$Customer_Type = $_POST['Customer_Type'];
$Computer_type = $_POST['Computer_type'];
$Computer_maker = $_POST['Computer_maker'];
$Model = $_POST['Model'];
$OS = $_POST['OS'];
$Appointment_date = $_POST['Appointment_date'];
$Problem = $_POST['Problem'];
$Solution = $_POST['Solution'];
$Comment = $_POST['Comment'];



$query = "UPDATE Customer SET  Firstname='$Firstname',lastname='$lastname',Address='$Address',Postcode='$Postcode',Phone='$Phone',Email='$Email',Customer_Type='$Customer_Type',Computer_type='$Computer_type',Computer_maker='$Computer_maker',Model='$Model',OS='$OS',
Appointment_date='$Appointment_date',Problem='$Problem',Solution='$Solution',Comment='$Comment' WHERE cf_uid='$cf_uid '";


mysql_query($query) or die(mysql_error());
mysql_close($con);
 
echo "<p>Congrats Record Updated</p>";
}
?>

     
I got congrats record updated but in actual fact no record are updated.

Please help

MOD EDIT: code tags added.

Hi,

I have contact form in my website project.

Users fill First name ,Last Name ,Email etc information.

I do not want to create database and table to store this information.

I want to store this information in XML file.

When user will add information then information will be added in XML file.

Any solution for this ?


- Thanks

This is the form that I'm using and it populates just fine but when you make the changes I can't figure out how to get it to update each record in my database.
Code: [Select]
<table width="100%" cellspacing="1" cellpadding="2" border="0">
<form action="<?php echo $_SERVER["PHP_SELF"] . "?update=1"; ?>" method="post">
<tr>
<td><b>Category Name</b></td>
<td><b>Category Description</b></td>
<td><b>Order</b></td>
<td align="right"><input type="submit" value="Update"></td>
</tr>
<?php
read_cat_list($cat);
for ($i = 0; $i < $cat["count"]; $i++) {
echo "<tr>\n";
echo "<td width=\"30%\" valign=\"top\"><input type=\"text\" name=\"cat_name_" . safe_string($cat[$i]["cat_id"]) . "\" size=\"30\" maxlength=\"250\" value=\"" . safe_string($cat[$i]["cat_name"]) . "\"></td>\n";
echo "<td width=\"36%\" valign=\"top\"><textarea name=\"cat_desc_" . safe_string($cat[$i]["cat_id"]) . "\" rows=\"2\" cols=\"30\">" . safe_string($cat[$i]["cat_desc"]) . "</textarea></td>\n";
echo "<td width=\"10%\" valign=\"top\"><input type=\"text\" name=\"cat_order_" . safe_string($cat[$i]["cat_id"]) . "\" size=\"3\" maxlength=\"3\" value=\"" . safe_string($cat[$i]["cat_order"]) . "\"></td>\n";
echo "<td width=\"24%\" valign=\"top\">[&nbsp;<a href=\"#\" onmouseover=\"window.status = 'Delete " . safe_string($cat[$i]["cat_name"]) . "'; return true;\" onmouseout=\"window.status = ''; return true;\" onclick=\"javascript:del_cat(" . $cat[$i]["cat_id"] . ", '" . safe_string($cat[$i]["cat_name"]) . "'); return false;\">Delete</a>&nbsp;]</td>\n";
echo "</tr>\n";
}
?>
<tr>
<td colspan="4" align="right"><input type="submit" value="Update"></td>
</tr>
</form>
</table>
the safe_string function just cleans up the output/input from the database, This next block is my form processor for this form.
Code: [Select]
<?php
function update_cats($vars) {
$err = "";

#if ($SESSION["level"] != ADMIN) {
# $err = ERR_NOT_ENOUGH_ACCESS;
#} else {
$temp = array_keys($vars);

for ($i = 0; $i < count($temp); $i++) {
if (substr($temp[$i], 0, 9) == "cat_name_") {
if ($vars[$temp[$i]] == "") {
$err = "Category names cannot be blank.";
break;
} else {
$name_query["cat_name"] .= substr($temp[$i], 9) . ", ";
}
}
}
for ($i = 0; $i < count($temp); $i++) {
if (substr($temp[$i], 0, 9) == "cat_desc_") {
$desc_query["cat_desc"] .= substr($temp[$i], 9) . ", ";
}
}
for ($i = 0; $i < count($temp); $i++) {
if (substr($temp[$i], 0, 10) == "cat_order_") {
if ($vars[$temp[$i]] == "") {
$err = "Category orders cannot be blank.";
break;
} else {
$order_query["cat_order"] .= substr($temp[$i], 10) . ", ";
}
}
}
#}

if (!$err) {
if ($name_query["cat_name"]) {
$update_name_query  = "update category";
$update_name_query .= "   set cat_name = '" . $name_query["cat_name"] . "'";
$update_name_query .= " where cat_id in (" . substr($name_query["cat_name"], 0, -2) . ")";

update_db($update_name_query);
}

if ($desc_query["cat_desc"]) {
$update_desc_query  = "update category";
$update_desc_query .= "   set cat_desc = '" . $name_query["cat_desc"] . "'";
$update_desc_query .= " where cat_id in (" . substr($desc_query["cat_desc"], 0, -2) . ")";

update_db($update_desc_query);
}

if ($order_query["cat_order"]) {
$update_order_query  = "update category";
$update_order_query .= "   set cat_order = '" . $name_query["cat_order"] . "'";
$update_order_query .= " where cat_id in (" . substr($order_query["cat_order"], 0, -2) . ")";

update_db($update_order_query);
}
}

return $err;
}
?>
update_db is my database caller, if you need any of the functions that I use that are not here please post back and tell me.

now when I process the form all my fields change to this:

cat_name: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15,
cat_desc:
cat_id: 0

for all the records in the database table, I'm just trying to update each record with the values it needs

Here is my database table with the data.
Code: [Select]
CREATE TABLE `category` (
  `cat_id` int(11) NOT NULL AUTO_INCREMENT,
  `cat_name` varchar(255) NOT NULL,
  `cat_desc` text NOT NULL,
  `cat_order` int(11) NOT NULL,
  PRIMARY KEY (`cat_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=16 ;

--
-- Dumping data for table `category`
--

INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(1, 'Hand Tossed Pizza', '', 1);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(2, 'Hand Tossed Specialty Pizzas', '', 2);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(3, 'Chicago Style Deep Dish', '', 3);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(4, 'Specialty Chicago Style Deep Dish', '', 4);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(5, 'Chicken Wings & Tenderloins', '', 5);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(6, 'Hot Sides', '', 6);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(7, 'Hot Sandwiches', '', 7);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(8, 'Cold Sandwiches', '', 8);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(9, 'Pastas', '', 9);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(10, 'Fresh Salads', '', 10);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(11, 'Fresh Breads', '', 11);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(12, 'Soups', '', 12);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(13, 'Kids Menu', '', 13);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(14, 'Drinks', '', 14);
INSERT INTO `category` (`cat_id`, `cat_name`, `cat_desc`, `cat_order`) VALUES(15, 'Desserts', '', 15);

Hope I have provided plenty of info on what I got and what I need for it todo

Thanks

Hi.

When a record is added its done via a form and processed via inserts.php.

I need to use the same form but to recall the data (by id) so it can be editted.

Cant work it out though.  Help would be well appreciated!

edit.php:

<CENTER><B>Update a Vehicle</B></CENTER>
<BR>

<?php

$query="SELECT * FROM cars";
$result=mysql_query($query);

$i=0;
while ($i < $num) {

$carname=mysql_result($result,$i,"CarName");
$cartitle=mysql_result($result,$i,"CarTitle");
$carprice=mysql_result($result,$i,"CarPrice");
$carmiles=mysql_result($result,$i,"CarMiles");
$cardesc=mysql_result($result,$i,"CarDescription");

?>

<form action="showroomedit.php" method="post">
<CENTER>Vehicle Name:</CENTER> 
<CENTER><input type="text" name="CarName" value="<?php echo $carname; ?>"></CENTER>
<br>
<CENTER>Vehicle Type:</CENTER>
<CENTER><input type="text" name="CarTitle" value="<?php echo $cartitle; ?>"></CENTER>
<br>
<CENTER>Vehicle Price:</CENTER>
<CENTER><input type="text" name="CarPrice" value="<?php echo $carprice; ?>"></CENTER>
<br>
<CENTER>Vehicle Mileage:</CENTER>
<CENTER><input type="text" name="CarMiles" value="<?php echo $carmiles; ?>"></CENTER>
<br>
<CENTER>Vehicle Description:</CENTER>
<CENTER><textarea name="CarDescription" rows="10" cols="30" value="<?php echo $cardesc; ?>"></textarea></CENTER>
<br>

<CENTER><input type="Submit"></CENTER>

</form>

</TD>

cant work out why it isnt working...

Code: [Select]
<?php
require "db/config.php";
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$country = $_POST['country'];
$state = $_POST['state'];
$city = $_POST['city'];
$zcode = $_POST['zcode'];
$address = $_POST['address'];
$ppemail = $_POST['ppemail'];
$pnumber = $_POST['pnumber'];
$cemail = $_POST['cemail'];
$url = $_POST['url'];
$price = "$5.00";
$query = "INSERT INTO custpackage1000(
id,
FirstName,
LastName,
Country,
State,
City,
ZipCode,
Address,
PayPalEmail,
PhoneNumber,
PrimaryEmail,
WebsiteURL) VALUES (
'1',
'$fname',
'$lname',
'$country',
'$state',
'$city',
'$zcode',
'$ppemail',
'$pnumber',
'$cemail',
'$url')";

mysql_connect($host, $user, $pass) or die("<br /><br /><h1>Fatal error. Please contact support if this persists.</h1>");
mysql_select_db($dbname);
mysql_query($query) or die ("could not open db".mysql_error());
sleep(2);
?>
Why won't the code insert into my database upon submission of data? What am I doing wrong?