PHP - Show A Certain Quarry When Page With Form First Loaded.

I'm restarting this under a new subject b/c I learned some things after I initially posted and the subject heading is no longer accurate.

What would cause this behavior - when I populate session vars from a MYSQL query, they stick, if I populate them from an MSSQL query, they drop.

It doesn't matter if I get to the next page using a header redirect or a form submit.  I have two session vars I'm loading from a MYSQL query and they remain, the two loaded from MSSQL disappear. 

I have confirmed that all four session vars are loading ok initially and I can echo them out to the page, but when the application moves to next page via redirect or form submit, the two vars loaded from MSSQL are empty. 

Any ideas?

Quesion: Show each movie in the database on its own page, and give the user links in a "page 1, Page 2, Page 3" - type navigation system. Hint: Use LIMIT to control which movie is on which page. I have provided 3 files: 1st: configure DB, 2nd: insert data, 3rd: my code for the question. I would appreciate the help. I am a noob by the way.

First set up everything for DB:

<?php
//connect to MySQL
$db = mysql_connect('localhost', 'root', '000') or
    die ('Unable to connect. Check your connection parameters.');

//create the main database if it doesn't already exist
$query = 'CREATE DATABASE IF NOT EXISTS moviesite';
mysql_query($query, $db) or die(mysql_error($db));

//make sure our recently created database is the active one
mysql_select_db('moviesite', $db) or die(mysql_error($db));

//create the movie table
$query = 'CREATE TABLE movie (
        movie_id        INTEGER UNSIGNED  NOT NULL AUTO_INCREMENT,
        movie_name      VARCHAR(255)      NOT NULL,
        movie_type      TINYINT           NOT NULL DEFAULT 0,
        movie_year      SMALLINT UNSIGNED NOT NULL DEFAULT 0,
        movie_leadactor INTEGER UNSIGNED  NOT NULL DEFAULT 0,
        movie_director  INTEGER UNSIGNED  NOT NULL DEFAULT 0,

        PRIMARY KEY (movie_id),
        KEY movie_type (movie_type, movie_year)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die (mysql_error($db));

//create the movietype table
$query = 'CREATE TABLE movietype (
        movietype_id    TINYINT UNSIGNED NOT NULL AUTO_INCREMENT,
        movietype_label VARCHAR(100)     NOT NULL,
        PRIMARY KEY (movietype_id)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die(mysql_error($db));

//create the people table
$query = 'CREATE TABLE people (
        people_id         INTEGER UNSIGNED    NOT NULL AUTO_INCREMENT,
        people_fullname   VARCHAR(255)        NOT NULL,
        people_isactor    TINYINT(1) UNSIGNED NOT NULL DEFAULT 0,
        people_isdirector TINYINT(1) UNSIGNED NOT NULL DEFAULT 0,

        PRIMARY KEY (people_id)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die(mysql_error($db));

echo 'Movie database successfully created!';
?>



********************************************************************
***********************************************************************

second file to load info into DB:



<?php
// connect to MySQL
$db = mysql_connect('localhost', 'root', '000') or
    die ('Unable to connect. Check your connection parameters.');

//make sure you're using the correct database
mysql_select_db('moviesite', $db) or die(mysql_error($db));

// insert data into the movie table
$query = 'INSERT INTO movie
        (movie_id, movie_name, movie_type, movie_year, movie_leadactor,
        movie_director)
    VALUES
        (1, "Bruce Almighty", 5, 2003, 1, 2),
        (2, "Office Space", 5, 1999, 5, 6),
        (3, "Grand Canyon", 2, 1991, 4, 3)';
mysql_query($query, $db) or die(mysql_error($db));

// insert data into the movietype table
$query = 'INSERT INTO movietype
        (movietype_id, movietype_label)
    VALUES
        (1,"Sci Fi"),
        (2, "Drama"),
        (3, "Adventure"),
        (4, "War"),
        (5, "Comedy"),
        (6, "Horror"),
        (7, "Action"),
        (8, "Kids")';
mysql_query($query, $db) or die(mysql_error($db));

// insert data into the people table
$query  = 'INSERT INTO people
        (people_id, people_fullname, people_isactor, people_isdirector)
    VALUES
        (1, "Jim Carrey", 1, 0),
        (2, "Tom Shadyac", 0, 1),
        (3, "Lawrence Kasdan", 0, 1),
        (4, "Kevin Kline", 1, 0),
        (5, "Ron Livingston", 1, 0),
        (6, "Mike Judge", 0, 1)';
mysql_query($query, $db) or die(mysql_error($db));

echo 'Data inserted successfully!';
?>



**************************************************************
****************************************************************

MY CODE FOR THE QUESTION:


<?php
$db = mysql_connect('localhost', 'root', '000') or
die ('Unable to connect. Check your connection parameters.');

mysql_select_db('moviesite', $db) or die(mysql_error($db));

//get our starting point for the query from the URL
if (isset($_GET['offset'])) {
   $offset = $_GET['offset'];
} else {
   $offset = 0;
}

//get the movie
$query  = 'SELECT
   movie_name, movie_year
FROM
   movie
ORDER BY
   movie_name
LIMIT ' . $offset . ' , 1';
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
?>
<html>
<head>
<title><?php echo $row['movie_name']; ?></title>
</head>
<body>
<table border = "1">
<tr>
<th>Movie Name</th>
<th>Year</th>
</tr><tr>
<td><?php echo $row['movie_name']; ?></td>
<td><?php echo $row['movie_year']; ?></td>
</tr>
</table>
<p>
<a href="page.php?offset=0">Page 1</a>,
<a href="page.php?offset=1">Page 2</a>,
<a href="page.php?offset=2">Page 3</a>
</p>
</body>
</html>

I want to show a cookie of a referral's username on a sign up page. The link is like this, www.mysite.com/signup?ref=johnsmith.

The cookie doesn't show if I go to that url page. But it does show up once I reload the page.  So I'm wondering if it's possible to show the cookie the first time around, instead of reloading the page?

Here is my code.

// This is in the header
$url_ref_name = (!empty($_GET['ref']) ? $_GET['ref'] : null);

if(!empty($url_ref_name)) {

  $number_of_days = 365;
  $date_of_expiry = time() + 60 * 60 * 24 * $number_of_days;
  setcookie( "ref", $url_ref_name, $date_of_expiry,"/");

} else if(empty($url_ref_name)) {
  if(isset($_COOKIE['ref'])) {
    $user_cookie = $_COOKIE['ref'];
  }
} else {}

// This is for the sign up form
if(isset($_COOKIE['ref'])) {
  $user_cookie = $_COOKIE['ref'];
  ?>
  <fieldset>
    <label>Referred By</label>
    <div id="ref-one"><span><?php if(!empty($user_cookie)){echo $user_cookie;} ?></span></div>
    <input type="hidden" name="ref" value="<?php if(!empty($user_cookie)){echo $user_cookie;} ?>" maxlength="20" placeholder="Referrer's username" readonly onfocus="this.removeAttribute('readonly');" />
  </fieldset>
  <?php
}

 

Hi,

I would like to do the following but not sure how.

If the you/user is on index.php of http://www.domain.com/ show one page
If not show another

How would I do this?

Thanks

Hi ,

I know my code sucks but i'm learning fast!! I'm trying to show a form if the qty value in a database == 10 or a different form if the value ==20.  I tried but failed.  Any help really appreciated.

Code: [Select]

<?php require_once('Connections/book.php'); ?>
<?php
$colname_cardpayment = "-1";
if (isset($_GET['orderid'])) {
  $colname_cardpayment = (get_magic_quotes_gpc()) ? $_GET['orderid'] : addslashes($_GET['orderid']);
}
mysql_select_db($database_book, $book);
$query_cardpayment = sprintf("SELECT * FROM cards WHERE orderid = '%s' ORDER BY qty ASC", $colname_cardpayment);
$cardpayment = mysql_query($query_cardpayment, $book) or die(mysql_error());
$row_cardpayment = mysql_fetch_assoc($cardpayment);
$totalRows_cardpayment = mysql_num_rows($cardpayment);

 // Database connect
$con = mysql_connect("mysql1.myhost.ie","admin_book","root123");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("book_test", $con);


//Parse Values from Coupon.php Form
$orderid = mysql_real_escape_string(trim($_POST['orderid']));
$name  = mysql_real_escape_string(trim($_POST['name']));
$surname  = mysql_real_escape_string(trim($_POST['surname']));
$add1 = mysql_real_escape_string(trim($_POST['add1']));
$add2 = mysql_real_escape_string(trim($_POST['add2']));
$town = mysql_real_escape_string(trim($_POST['town']));
$county = mysql_real_escape_string(trim($_POST['county']));
$postcode = mysql_real_escape_string(trim($_POST['postcode']));
$phone = mysql_real_escape_string(trim($_POST['phone']));
$email = mysql_real_escape_string(trim($_POST['email']));
$letterstyle = mysql_real_escape_string(trim($_POST['letterstyle']));


$sql="INSERT INTO custdetails (orderid, name, surname, add1, add2, town, county, postcode, phone, email, letterstyle)
VALUES
('$orderid','$name','$surname','$add1','$add2','$town','$county','$postcode','phone','$email','$letterstyle')";

if (!mysql_query($sql))
  {
  die('Error: ' . mysql_error());
  }
?>

<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Digital Scribe Books</title>
<link href="style.css" rel="stylesheet" type="text/css" />

<script type="text/javascript">
function MM_preloadImages() { //v3.0
  var d=document; if(d.images){ if(!d.MM_p) d.MM_p=new Array();
    var i,j=d.MM_p.length,a=MM_preloadImages.arguments; for(i=0; i<a.length; i++)
    if (a[i].indexOf("#")!=0){ d.MM_p[j]=new Image; d.MM_p[j++].src=a[i];}}
}
function MM_swapImgRestore() { //v3.0
  var i,x,a=document.MM_sr; for(i=0;a&&i<a.length&&(x=a[i])&&x.oSrc;i++) x.src=x.oSrc;
}
function MM_findObj(n, d) { //v4.01
  var p,i,x;  if(!d) d=document; if((p=n.indexOf("?"))>0&&parent.frames.length) {
    d=parent.frames[n.substring(p+1)].document; n=n.substring(0,p);}
  if(!(x=d[n])&&d.all) x=d.all[n]; for (i=0;!x&&i<d.forms.length;i++) x=d.forms[i][n];
  for(i=0;!x&&d.layers&&i<d.layers.length;i++) x=MM_findObj(n,d.layers[i].document);
  if(!x && d.getElementById) x=d.getElementById(n); return x;
}

function MM_swapImage() { //v3.0
  var i,j=0,x,a=MM_swapImage.arguments; document.MM_sr=new Array; for(i=0;i<(a.length-2);i+=3)
   if ((x=MM_findObj(a[i]))!=null){document.MM_sr[j++]=x; if(!x.oSrc) x.oSrc=x.src; x.src=a[i+2];}
}
</script>


</head>

<body onload="MM_preloadImages('images/buttons/home_over.png','images/buttons/books_over.png','images/buttons/cards_over.png','images/buttons/letters_over.png')">


<div id="snow">
<div id="wrapper">


<div id="header">

<div id="logo"><img src="images/digital_scripe.png" width="218" height="91" /></div>


<div id="menu"><a href="index.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Home','','images/buttons/home_over.png',1)"><img src="images/buttons/home_act.png" name="Home" width="131" height="132" border="0" id="Home" /></a><a href="books.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Books','','images/buttons/books_over.png',1)"><img src="images/buttons/books_act.png" name="Books" width="131" height="132" border="0" id="Books" /></a><a href="cards.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Cards','','images/buttons/cards_over.png',1)"><img src="images/buttons/cards_act.png" name="Cards" width="131" height="132" border="0" id="Cards" /></a><a href="letters.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Letters','','images/buttons/letters_over.png',1)"><img src="images/buttons/letters_act.png" name="Letters" width="131" height="132" border="0" id="Letters" /></a></div>
 </div>
 
 
 
 
<div id="content">



<?php 
echo 'Order ID is :  '. $orderid . '.<br />';

if ($row2['qty'] == 10)
    echo "<div>

<form action="https://www.paypal.com/cgi-bin/webscr" method="post">
<input type="hidden" name="cmd" value="_xclick">
<input type="hidden" name="business" value="accounts@agraphics.ie">
<input type="hidden" name="lc" value="IE">
<input type="hidden" name="item_name" value="10 Christmas Cards">
<input type="hidden" name="item_number" value="<? echo $orderid; ?>">
<input type="hidden" name="amount" value="12.99">
<input type="hidden" name="currency_code" value="EUR">
<input type="hidden" name="button_subtype" value="services">
<input type="hidden" name="shipping" value="2.99">
<input type="hidden" name="return" value="http://www.digitalscribe/thanks.php">
<input type="hidden" name="bn" value="PP-BuyNowBF:btn_buynowCC_LG.gif:NonHosted">
<input type="image" src="https://www.paypalobjects.com/en_US/i/btn/btn_buynowCC_LG.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!">
<img alt="" border="0" src="https://www.paypalobjects.com/en_US/i/scr/pixel.gif" width="1" height="1">
</form>
</div>";

if ($row2['qty'] == 20)
    echo "<div>

<form action="https://www.paypal.com/cgi-bin/webscr" method="post">
<input type="hidden" name="cmd" value="_xclick">
<input type="hidden" name="business" value="accounts@agraphics.ie">
<input type="hidden" name="lc" value="IE">
<input type="hidden" name="item_name" value="20 Christmas Cards">
<input type="hidden" name="item_number" value="<? echo $orderid; ?>">
<input type="hidden" name="amount" value="21.99">
<input type="hidden" name="currency_code" value="EUR">
<input type="hidden" name="button_subtype" value="services">
<input type="hidden" name="shipping" value="2.99">
<input type="hidden" name="return" value="http://www.digitalscribe/thanks.php">
<input type="hidden" name="bn" value="PP-BuyNowBF:btn_buynowCC_LG.gif:NonHosted">
<input type="image" src="https://www.paypalobjects.com/en_US/i/btn/btn_buynowCC_LG.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!">
<img alt="" border="0" src="https://www.paypalobjects.com/en_US/i/scr/pixel.gif" width="1" height="1">
</form>
</div>";


?>

</div>


<div id="footer" class="clear"><div id="sign"><div id="sign_text">Personalised<br />
Books</div>
</div></div>

</div></div>






</body>
</html>
<?php
mysql_free_result($cardpayment);
?>

Hi All,

I want to be able to show selected pages of my website as PDF using a 'PDF' button much like this site does:

http://www.westmeon.org.uk/index.php?option=com_content&task=blogsection&id=8&Itemid=35

I presume that I will need to install some sort of software on my server (which runs the latest PHP, MySQL etc.) but after hours of searching online I cannot find a simple way of doing this.

Does anyone have any suggestions or pointers for how I can do this?

FYI my website is written in PHP drawing data from a MySQL database.

Regards,
Neil

Hi

I want to make something like this -

My Sites index.php will be avail avail to user after he has clicked in a link that will come after every 24 Hour in my site. Means when a user first enters the site it will come and clicking in there the site will be avail avail. again after 24 Hour it will come again.

But i am not getting how to do it.

So need help

SaKIB

Hi,

This may be something for JavaScript but I would like to know if and how it's possible to show who is currently active/viewing the page. Users are logged into the system with their own account.

The purpose of this is for a CRM where more than one person may be editing the same record, so undesired overwrites might occur which is what I'd like to avoid with this "other user editing this record" notification.

Hi,

I want to show part of the text from a page containing my article on my main page. The article resides in a database in mysql. How do I limit the amount of text that is shown without setting up a separate excerpt box for the article. I want to then provide a link so the user can go to another page that displays the entire article. Thanks for any suggestions.

http://2eastvalleyhomes.expandyourwebpresence.com/
In this site on the right widget the search option opens a new page and directs you off the page. I have created a page not visible on the home page called MLS and I would like the search on the right side to have its information populate in a page I created in my wordpress site, does any one have any suggestions or any ideas for this thank you for any help.

Hi, okee so I'm new to everything that has to do with scripting, especially when it comes to PHP and stuff,
but what is the best way to display information from a table on a page?
I'm creating this site where users can post their events, but I want the Location to be based on the Location they inserted during the registration process, so that the location will be displayed directly.
How am I able to do that? I've already got an login script, it looks like this:
Code: [Select]
<?php
ob_start();
$host="localhost"; // Host name
$username="root"; // Mysql username
$password=""; // Mysql password
$db_name="whats_happening_db"; // Database name
$tbl_name="members"; // Table name

// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

// Define $myusername and $mypassword
$myusername=$_POST['myusername'];
$mypassword=$_POST['mypassword'];

// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);

$sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);

// Mysql_num_row is counting table row
$count=mysql_num_rows($result);
// If result matched $myusername and $mypassword, table row must be 1 row

if($count==1){
// Register $myusername, $mypassword and redirect to file "login_success.php"
session_register("myusername");
session_register("mypassword");
header("location:membersarea.php?user=$myusername");
}
else {
echo "Wrong Username or Password";
}

ob_end_flush();
?>
Sorry if my English is terrible haha.

Dante.

Hi im trying to pass a variable through a url.

Here's the code :

echo"<td class='tableContent'><span onmouseover=\"tooltip.show('Click to add details to ".$result['workObject']."');\" onmouseout=\"tooltip.hide();\"><a href='addRemarksBucc.php?workObject=".$result['workObject']."'>".$result['systemRemarks']."</a></span></td>";

and here's the code to the next page:

 <table width="550" border="0" cellspacing="5" cellpadding="0">
                  <tr>
                    <td width="78" valign="top">Work Object</td>
                    <td><input name="workObject" id="workObject" type="text" value="<?php $_GET['workObject']; ?>" /></td>
                    </tr>
                  <tr>
                    <td valign="top">Remark Details</td>
                    <td><textarea name="errorMessage2" cols="50" rows="10" id="errorMessage2" accesskey="p" tabindex="1"></textarea>
                      <input name="workObject2" type="hidden" value="" /></td>
                  </tr>
                  <tr>
                    <td valign="top">&nbsp;</td>
                    <td>&nbsp;</td>
                  </tr>
                  <tr>
                    <td>&nbsp;</td>
                    <td><input name="submit" type="submit" class="btn" id="submit" accesskey="R" tabindex="11" value="Submit" />
                      <input name="reset" type="reset" class="btn" id="reset" accesskey="e" tabindex="12" value="Reset" /></td>
                    </tr>
                </table>


What am I doing wrong? The address bar shows the right url but the second page doesn't display any value for workObject.

Thanks!

I need to come up with a script that will get the number of products under a category and return the number of products shown on each page in

Showing 1-20 Products out of (total number)

I have this MYSQL which I'm also using to generate pagination.
Code: [Select]
$query5 = "SELECT COUNT(*) as num FROM $tbl_name WHERE product_category='$cat'";
$total_pages = mysql_fetch_array(mysql_query($query5));
$total_pages = $total_pages[num];

/* Setup vars for query. */
$targetpage = "store.php?cat=".$cat; //your file name  (the name of this file)
$limit = 20; //how many items to show per page
$page = $_GET['page'];
if($page){
$start = ($page - 1) * $limit; //first item to display on this page
}
else{
$start = 0; //if no page var is given, set start to 0
}

The products are pulled from the database he
Code: [Select]
$sql30 = "SELECT * FROM $tbl_name WHERE product_category='$cat' LIMIT $start, $limit";
$result30 = mysql_query($sql30);

I came up with one way, but it will only work when there are 20 products on the page. If there's less it won't calculate that amount.

I'm trying to do a simple PHP form with Securimage Captcha and whenever I add this variable "$securimage = new Securimage();" the page displays nothing.  Could someone please help me with this?  My php file is already in the securimage directory so that's why I'm pointing directly to the file.