PHP - Php Rounding Currency
Hi all,
Can anyone please help me with my problem. I want to know how to round a decimal - eg. 12.34 to the nearest .10 so it would be 12.30 or if 12.35 go to 12.30 or 12.40. // my example: round(12.34, 2); // I want to to go to: 12.30 Any help is greatly appreciated. Similar TutorialsI want to round off an integer vaule to 10-6 grd from 52.71666666 to 52716666 0.926888888 to 926888 does anyone know a simple way to do this? I am trying to take a number (three for example) and want to round it to five, or sixty-seven up to seventy. I looked at round and ceil, but those don't seem like they are the right things. Thanks, Joseph How can I round this with 2 decimals: Code: [Select] echo " $row[team_treasure] "; I've tried round($row[team_treasure],2) but doesn't seem to work inside my echo tags :/ hi there all, I need some help for rounding currency issue.. example: 0.98 round to 0.95 0.95 when round = 0.95 0.91 roun to 0.95. mean. i wanna round the end of number 0.98. if the end of number is 0.01,0.02,0.03&0.04 it would be automatic round to nearest 0.05 *0.01 round = 0.05 *if the mineral water =$0.71 i should get $0.75 and if the end of number is 0.06,0.07,0.08,0.09 it would automatic round to nearest -0.05 *0.06 round = 0.05 *if the mineral water = $0.79 then i should get $0.75 i had googling this for 2months and no answer.. please help me.TQ So I just started working with php (not programming) a couple days ago. In this formula, I need to round something down to the nearest 5 OR 0. Whatever comes first. Any thoughts on how i might do this? Here's what I have so far. <?php $magicLevel = $_POST['magicLevel']; $playerLevel = $_POST['playerLevel']; $rune = $_POST['rune']; //gets the value "lmm" $maxDamage = 0; switch($rune) { case "lmm": $maxDamage = ($playerLevel*0.2)+($magicLevel*0.81)+4; break; } echo $maxDamage; ?> What I need to round down is this part: ($playerLevel*0.2) Thanks in advance! Here is the number: $GrandTotal = "68.835"; $Deposit = round($GrandTotal , 2) * .5; echo $Deposit; I am looking for: 68.84 but the function doesn't seem to work right. Any help? I am very new to PHP and programming in general. About 3 weeks into this. I have this simple expression and some echo in my code. $x1 = $lat_b + $lat_a1; echo "<br>lat b: ".$lat_b; echo "<br>lat a1: ".$lat_a1; echo "<br>x1: ".$x1; $lat_b and $lat_a1 are derived from some xml extractions from a yahoo geocode api (that part works fine). The results of the expression and echos above are as follows: lat b: 40.402866 lat a1: 40.252590 x1: 80 Why is $x1 rounding automatically on me? Later, I substituted the expression above with $x1 = 40.402866 + 40.252590 ; The new result (shown below) makes sense to me. lat b: 40.402866 lat a1: 40.252590 x1: 80.655456 Bascially i add a couple numbers up and display the sum. sometimes the number is something like this: 234.237 i want it to display : 234.24 i realize its needs "round()" in it but i dont know how to use it.. any help? Hi, Having trouble rounding the output. I would need to be sure the output is not longer than 2 spaces after comma. Any ideas? My code Code: [Select] <script type="text/javascript"> $(document).ready(function() { $("<?php echo "#".$input_end_time; ?>").blur(function(){ var start_time = $("<?php echo "#".$input_start_time; ?>").val(); var end_time = $("<?php echo "#".$input_end_time; ?>").val(); $.getJSON("include/timedifferencecalculation.php?s="+start_time+"&e="+end_time, function(data){ var success = data.success; if (success == 1) { $("<?php echo "#".$input_difference; ?>" ).val(data.hours + " h " + data.minutes + " m "); if (data.hours + data.minutes/60 >= 6){ $("<?php echo "#".$hours_difference; ?>").val(data.hours + data.minutes/60 - 0.5); }else { $("<?php echo "#".$hours_difference; ?>").val(data.hours + data.minutes/60); } }else { $("#message").text("Viga! " + data.reason); } }) }); }); </script> Code: [Select] This is before $("<?php echo "#".$hours_difference; ?>").val(data.hours + data.minutes/60 - 0.5); This is what im trying to get but its not working. $("<?php echo "#".$hours_difference; ?>").val( round(data.hours + data.minutes/60 - 0.5), 2 ); Hey Everybody, I was replying to someone elses question about number formatting and came up with a class that will format a number of any length with decimal or not, without rounding. It works perfectly, but after a comment by a noteworthy member my curiosity was aroused. Is there an easier/faster/better way to achieve this?? My Object: <?php /*GHETTO NUMBER FORMATTER v1.0*/ class ghettoNumber { private $input; private $output; public $whole; public $decimal; public $number; function __construct($input){ $this->input = $input; $this->output = $output; $this->number = $number; $this->whole = $whole; $this->decimal = $decimal; } private function ghettoFormat(){ //Split number at the .(decimal) $this->number = explode('.', $this->input); //Define the whole number $this->whole = $this->number[0]; //Format the whole number $this->whole = number_format($this->whole, 0,'', ','); //Define the decimal $this->decimal = $this->number[1]; //Format the decimal $this->decimal = rtrim($this->decimal, '0'); if(is_string($this->input)){ $this->output = $this->decimal != '' ? $this->whole.'.'.$this->decimal : $this->whole; } else{ $this->output = '<strong>ERROR:</strong> Input arg must be passed as type: <em>string</em>'; } //Return result return 'Original - '.$this->input.'<br> GhettoFormat - '.$this->output.' <br><br>'; } public function makeItGhetto(){ return $this->ghettoFormat(); } } ?> Sample Instantiation: $ghettoFormat = new ghettoNumber('12565456565.123401201001210000'); print $ghettoFormat->makeItGhetto(); I will reiterate my question once more... Is there, in your opinion, a BETTER way to achieve this (number formatting w/o rounding)? Thanks People, E Hi fellas, Can anyone show me why my script is still rounding up / down? printf ("<tr> %s Avg gun Ahit %%</td> %s %.2f %%</td></tr>\n",$tdo,$tdor,number_format($ahit/$fired*100, 3, '.', '')); Do I have a syntax error as I cannot get my math equation to display more than 2 decimal places even though it's set to 3? Any help or advice would be really great. I need to round a number based on it's decimal. 3 or below should round down, 4 should round up to 5, 6 and 7 should round down to 5; 8 and 9 should round up to the next whole number. The below is returning 3 from 2.16. Code: [Select] <?php $a=2.16; $i=round($a, 1); $b=$i; $i=explode(".", $a); $decimal=$i[1]; if($decimal < 5){ $j=floor($b); $i= $decimal > 3 ? $j + .5 : $j; echo $i; } else{ $j=ceil($b); $i= $decimal < 8 ? $j - .5 : $j; echo $i; } ?> EDIT: The explode should have been on $i not $a. hi, how can i make a autoupdate currency table currency value CHF USD EURO KD (Kuwaiti Dinars) 1 Converted Value Converted Value Converted Value when the page loads, it will convert the currency and the value of CHF, USD and EURO are real time please kindly help tia hi, how can i make a autoupdate currency table currency value CHF USD EURO KD (Kuwaiti Dinars) 1 Converted Value Converted Value Converted Value when the page loads, it will convert the currency and the value of CHF, USD and EURO are real time please kindly help tia hello everyone i am newbie to php just wanted to make a script for currency converter the problem i am facing is if i want to convert a value from $usd to $euro,$pond,$yen there are three possible values for usd kindly help me out with designing the values for tables and fetching data from them what will be structure of the table what will be the values kindly help me out it,s request thanks I'm trying to develop a function to check to see if the value inputted was in a currency format. I'm checking for: if the value is numeric if the value is an integer if not integer check the number of digits to the right of the decimal point I can't tell how the php function is_int() works though. I want to accept integers and also numbers with two decimal places. So accepted values will be "123" and also "123.99". The script tells me the value is not an integer no matter what. Code: [Select] <?php $num = $_POST['number']; $positionOfDecimalPoint = strpos($num, '.'); $numbersToLeft = substr($num,0,$positionOfDecimalPoint); $numbersToRight = substr($num,$positionOfDecimalPoint + 1);//Add one so decimal point isn't included in output. echo "You submitted ".$num."<br><br>"; if(!is_numeric($num)) { echo "Not Numeric"; } else { if(!is_int($num)) { $adecimal = strlen($numbersToRight); if($adecimal !== 2) { echo "There needs to be exactly two numbers after the decimal."; } echo "<br><br>The number is not an integer."; }else { echo "The integer is ".$num; } } ?> Is there an easy way for me to return 123.50 instead of 123.5.... I'm trying to return the trailing zero? $f15 = 0.345677 (output from sql data pull) <?php echo number_format ($f15,3); ?> output = 0.345 <?php echo ltrim($f15,"0"); number_format ($f15,3); ?> output = .345677 How do I combine these so that I am BOTH rounding the result AND trimming a leading zero? Seems I can get one or the other, but not both. Suggestions on the syntax? Hi, i have 2 currencies in my mysql and when user add new article, he choose currency and price. Now i need search engine for searching articles, and i have problem in part when user choose to show only articles between 100 and 200 euros, so i need help to convert all currencies to euro(all in mysql query) and show from 100 to 200 dollars, so if article price is 100 euros, then to show it too. Can someone help me ? 1 euro = 0.70 $ (example for values) |