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PHP - Simple Insert, View, And Delete Record Mysql And Php
I have a form that submits a record and saves it to the database, I've got that working already, I'm trying to figure out if there is a cleaner way to delete a record with a button that gets a value from the unique key, in this case 'id'
here is how the delete button looks like: // get info from table $query = "SELECT id, Title, Message FROM table_name"; $result = mysql_query($query); //displaying all data while($row = mysql_fetch_assoc($result)) { echo" <div class='status'><h3>{$row['Title']} <br></h3>" . " <h5>{$row['Message']} <br><br></h5>"; $id = $row['id']; //trying to get unique key from database //delete button echo "</div> <form action='delete.php' method='post' /> <input type='hidden' name='delete' value='yes' /> <input type='hidden' name='id' value='$id' /> <input type='submit' value='remove' /></form>"; } As you can see, i'm trying to give $id a unique value but for some reason i'm not getting it. The delete.php code looks like this: if (isset($_POST['delete']))// check if delete was clicked { $query = "DELETE FROM table_name WHERE id='$id'"; echo "$id Deleted successfully"; } elseif(!mysql_query($query, $db_server)) { echo "DELETE failed: $query<br />" . myql_error() . "<br /><br />"; } mysql_close(); I'm new to php and still learning so, if you think there are other ways to do this, please let me know, the button won't do anything to the data. Thanks in advance Similar TutorialsHi All, I have a simple 'delete record' code that is not working. Would someone please take a gander at it and let me know if they see anything wrong that would prevent it from actually deleting a record. Code: [Select] <?php //connects to the database include ('db_connect.php'); //post variable $pk = $_POST['pk']; //MySQL code to query ---- 'contacts' = table & 'primary_key' = record id # $deleteContact = "DELETE FROM `contacts` WHERE `primary_key` = ".$pk." LIMIT 1"; //excutes query to MySQL $res = mysqli_query($link,$deleteContact); //close connection to database mysqli_close($link); ?> Any help would be great. Thank you. I'd like to write - or acquire - code that displays a simple table (name, phone number, email address, plus a comments field) on a web page in a password-protected page and allows a user to add his own information, update it or delete it. I figure hundreds of people and companies have written something like this so I'd like to find either an example I can imitate or even an existing package that I can simply customize to the specifics for my own table. Can anyone help me with that? Or am I going to have to reinvent the wheel for the gazillionth time and write it myself? Hello everyone I need code for this question
would you help me please..?
Alright so I am trying to code a very simple form that adds a user to my SQL database with certain information filled in and certain information kept hidden with default values in a form. My index.php file is as follows (not all of the code but just the form part): <?PHP $submitMessage = $_GET['value']; if ($submitMessage == success) { echo '<div class="congratulations"><font color="#84d20c"><strong>Congratulations:</strong></font> The user has been added.</div>'; }else if($submitMessage == NULL){ }else if($submitMessage == fail){ echo '<div class="error"><font color="#d3430c"><strong>Error:</strong></font> An error occurred please check the error details below:</div>'; echo 'ERROR DETAILS:'; echo mysql_error(); } ?> <h1><i>Add User</i></h1> <p>This page is where you would manually add a user to the donations databases (for example you or a member of the community with elevated status that does not need to pay).</p> <br/> <form enctype="multipart/form-data" action="scripts/admin_save_sm_db.php" method="post"> <input name="authtype" value="steam"/><br /><br /> <h3><i>STEAM ID:</i></h3> <input name="identity" value="STEAM_0:X:XXXXXXXX"/><br /> <div class="form_help">Steam ID of the player you wish to add. Must be in the format STEAM_0:X:XXXXXXXX</div><br /> <input name="flags" value="o"/><br /><br /> <input name="name" value="Donator"/><br /><br /> <input name="immunity" value="0"/><br /><br /> <h3><i>Your Email Address</i></h3> <input name="user_email"/><br /> <div class="form_help">Your Email Address for security purposes.</div><br /> <input name="Submit" type="submit" value="Submit" class="form_submit" /> </form> My admin_save_sm_db.php file is as follows: <?php session_start(); if(!isset($_SESSION["username"])) { header('Location: login.php'); exit; } @require("../sm_admin_db.php"); $authtype = $_POST['authtype']; $identity = $_POST['identity']; $flags = $_POST['flags']; $name = $_POST['name']; $immunity = $_POST['immunity']; $user_email = $_POST['user_email']; $link = @mysql_connect(_HOST,_USER,_PASS); @mysql_select_db(_DB); $sql = @mysql_db_query(_DB,"INSERT INTO "._TBL." (`authtype`, `identity`, `flags`, `name`, `immunity`, `user_email`) VALUES (NULL, '$authtype', '$identity', '$flags', '$name', '$immunity', '$user_email')"); $okay = @mysql_affected_rows(); if($okay > 0) { header( "Location: ../index.php?value=success" ); } else { header( "Location: ../index.php?value=fail" ); } @mysql_close($link); ?> And finally my sm_admin_db.php file is as follows: <?PHP //host loaction define("_HOST", "localhost", TRUE); //database username define("_USER", "thatsact_admin", TRUE); //database username`s password define("_PASS", "*********", TRUE); //database name define("_DB", "thatsact_sadadmins", TRUE); //database table name change this to install multiple version on same database define("_TBL", "sm_admins", TRUE); //This is the email that you will recieve emails when someone signs up. define("_EMAIL", "admin@tag-clan.com", TRUE); ?> All of this together does not work and gives the echo error code, however the mysql_error() string does not return anything. Nothing is inserted into the database. Can I get some help on where I went wrong and please keep in mind I am VERY new to php and didn't write most of this script so just tell me what to edit and exactly how to do it please. Thanks in advance. Hi all . I have a script , which will display the records from sql . If user wish to view more details of the record , they can click view . Code: [Select] echo "<td>$objResult[Message] </td>"; echo "<td>$objResult[mylocaltime] </td>"; echo '<td><a href="historydetails.php?id=' . $objResult[Groupnumber] . '">View</a></td>'; Then it will link to a page which will display more details according to the Groupnumber . Which will display 2 records per page . Code: [Select] <? $groupnumber = $_GET['id']; $strSQL = "SELECT * FROM esp WHERE Groupnumber='$groupnumber'"; $objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]"); $Num_Rows = mysql_num_rows($objQuery); $Per_Page = 2; // Per Page $Page = $_GET["Page"]; if(!$_GET["Page"]) { $Page=1; } $Prev_Page = $Page-1; $Next_Page = $Page+1; $Page_Start = (($Per_Page*$Page)-$Per_Page); if($Num_Rows<=$Per_Page) { $Num_Pages =1; } else if(($Num_Rows % $Per_Page)==0) { $Num_Pages =($Num_Rows/$Per_Page) ; } else { $Num_Pages =($Num_Rows/$Per_Page)+1; $Num_Pages = (int)$Num_Pages; } $strSQL .=" order by id DESC LIMIT $Page_Start , $Per_Page"; $objQuery = mysql_query($strSQL); ?> But when I click next to view the third record , then the table will become blank . Is it because when I click to next page , the $groupnumber is no longer getting the data from $_GET['id'] ? Or is there any other problem? Thanks for every reply . New to php so I'm having trouble with deleting a record from my php table. This is my code for my page where the records are being displayed. I have a delete statement that is not working properly. Also, I was thinking maybe I need a array to delete records? Please help! Code: [Select] <?php require_once('database.php'); session_start(); if (isset($_POST['add_grade'])) { $query = "INSERT INTO grades (student_id, grade_type, grade_name, grade_points) "; $query .= "VALUES (:student_id, :grade_type, :grade_name, :grade_points) "; $statement = $db->prepare($query); $statement->bindValue (':student_id', $_SESSION['student_id']); $statement->bindValue (':grade_type', $_POST['grade_type']); $statement->bindValue (':grade_name', $_POST['grade_name']); $statement->bindValue (':grade_points', $_POST['grade_point']); $statement->execute(); $statement->closeCursor(); if (isset($_POST['remove'])) { foreach($_POST['delete'] as $delete_id) { $query = "DELETE FROM grades WHERE grade_id = $delete_id"; mysqli_query($dbc, $query) or die ('can\'t delete user'); } } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>View Course Grades</title> <link rel="stylesheet" type="text/css" href="main.css" /> </head> <body> <?php $student_name = $_SESSION['student_name']; $student_id = $_SESSION['student_id']; $query = "SELECT * FROM grades WHERE student_id = :student_id "; $statement = $db->prepare($query); $statement->bindValue (':student_id', $student_id); $statement->execute(); $grades = $statement->fetchAll(); $statement->closeCursor(); echo "<h1>Show Grades for $student_name </h1>"; foreach ($grades as $grade) { echo $grade['grade_type'] . " " . $grade['grade_name']. " " . $grade['grade_points'] . "<br />"; } $query = "select*from se266"; $result = mysql_query($dsn, $query); while($row = mysql_fetch_array($result)) { echo '<input type="checkbox" value="' .$row['grade_id'] . '"name="delete[]" />'; echo ' ' .$row['grade_type']; echo ' ' .$row['grade_name']; echo '<br />'; } ?> <div id="content"> <!-- display a table of products --> <table> <tr> <th>Grade Type</th> <th>Grade Name</th> <th>Grade Points</th> <th>Remove</th> </tr> <?php foreach ($grades as $grade) : ?> <tr> <td><?php echo $grade['grade_type']; ?></td> <td><?php echo $grade['grade_name']; ?></td> <td><?php echo $grade['grade_points']; ?></td> <td><form action="grades.php" method="post"> <input type="submit" name="remove" value="Delete" /> </form></td> </tr> <?php endforeach; ?> </table> </div> </div> <div id="footer"> </div> <form name="grades" method="post" action="grades.php"> <p>Grade Type<SELECT NAME="grade_type"> <OPTION VALUE="Mid-Term">Mid-Term <OPTION VALUE="Final">Final <OPTION VALUE="Lab">Lab </SELECT> <br> Grade Name:<input type="text" name="grade_name" value=""><br /> Grade Points:<input type="text" name="grade_point" value=""> <input type="submit" name="add_grade" value="Add Grade"> </form> </table> </body> </html> Hello: I am making a dynamic food menu system for a project so a client can manage his food and drink menus. I gave him the ability to add, edit, and delete menus. However, for the "Delete Menu" option, I would like to first check and see if a Category (menuCatID) or a Menu Item (menuItemID) is associated to the Main Menu (menuID) and - if so - to *NOT* allow that Menu to be deleted. I would like to send them back to the a_Menus.php page and display a message like "You must delete all Categories and Menu Items associated with this Menu before the Menu can be deleted." This is the code: a_Menus.php Code: [Select] <a href="a_MenusDelete.php?menuID=".$menuData['menuID'].">Delete Menu</a> a_MenusDelete.php Code: [Select] <?php include('../include/myConn.php'); include('../include/myCodeLib.php'); include('include/myCheckLogin.php'); $menuID = $_REQUEST['menuID']; mysql_query("DELETE FROM theMenus WHERE menuID = $menuID"); header("Location: a_Menus.php"); ?> <html> <head> <title></title> </head> <body> </body> </html> How would I be able to accomplish this? Thanks. Hi I've been scouring the net and I cant find anything that works. Can someone tell me how to put a delete button next to each record? Any help is appreciated, thank you! Code: [Select] $term = strtolower ($_POST['term']); $sql = mysql_query("select * from $table where first like '%$term%' or last like '%$term%'"); while ($row = mysql_fetch_array($sql)){ echo 'ID: '.$row['id']; echo '<br/> first: '.$row['first']; echo '<br/> last: '.$row['last']; echo '<br/> phone: '.$row['phone']; echo '<br/> mobile: '.$row['mobile']; echo '<br/> fax: '.$row['fax']; echo '<br/> email: '.$row['email']; echo '<br/> web: '.$row['web']; echo '<br/><br/>'; } ?> </p> This should be a simple task I am just not fully grasping laravel yet. I have my controllers view and models setup. I want to use my users.destroy route to delete my row in the db. But I want to do it a certain way. I want to have an alert show In my alert area on my page asking to confirm the deletion of a certain user. Im assuming I need to pass the user id in a session to an alert to confirm my delete on a delete button click. Click 1 button to open an alert on the top of my page if I click confirm it calls user.destroy.
<div class="container">
<div class="row justify-content-center">
<div class="col-md-12">
<div class="card">
<div class="card-header">
<h4>View All Users</h4>
@if(session()->get('success'))
<div class="alert alert-success">
{{ session()->get('success') }}
</div>
@endif
@if(session()->get('danger'))
<div class="alert alert-danger">
{{ session()->get('danger') }}
</div>
@endif
</div>
<div class="card-body">
<div class="text-center my-2">
<a href="{{ route('register') }}" class="btn btn-primary">New User</a>
</div>
<div>
<table class="table table-striped table-bordered">
<thead>
<tr>
<th>ID</th>
<th>Name</th>
<th>Email</th>
<th>Username</th>
<th colspan="2">Actions</th>
</tr>
</thead>
<tbody>
@foreach($users as $user)
<tr>
<th>{{$user->id}}</th>
<td>{{$user->name}}</td>
<td>{{$user->email}}</td>
<td>{{$user->username}}</td>
<td class="text-center">
<a href="{{ route('users.show', $user->id) }}" class="btn btn-primary mr-3">Show</a>
<a href="{{ route('users.edit', $user->id) }}" class="btn btn-info text-white ml-3">Edit</a>
<a href="#" class="btn btn-danger">Delete</a>
</td>
</tr>
@endforeach
</tbody>
</table>
public function destroy($id)
{
User::find($id)->delete();
return redirect()->route('users.index')->with('success','User Deleted');
}
Route::resource('users', 'UserController');
<?php if(!isset($_SESSION)) { session_start(); } // UNCOMMENT NEXT LINE TO PRINT THE $_SESSION ARRAY TO THE SCREEN . . . // echo '<pre>'; print_r($_SESSION); echo '</PRE>'; if(empty($_SESSION['userID']) || $_SESSION['authorized'] != true ) { header("Location: login.php"); exit; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html lang="EN" dir="ltr" xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/xml; charset=utf-8" /> <meta http-equiv="refresh" content="5;url=editprofile.php"> <title>Saving Profile</title> </head> <body> <?php require_once ("dbconn.php"); ?> <?php $userID = $_SESSION['userID']; $insert_query = 'insert into users WHERE userID='$userID'( aim, msn, yim, psnID, xblGamertag, otherContact ) values ( "' . $_POST['aim'] . '", "' . $_POST['msn'] . '", "' . $_POST['yim'] . '", "' . $_POST['psnID'] . '", "' . $_POST['xblGamertag'] . '", "' . $_POST['otherContact'] . '" )'; mysql_query($insert_query); ?> Your profile has been saved! You will now be redirected from where you came from. <br /><a href="editprofile.php" title="Click here if you don't want to wait">Click here if you don't want to wait.</a> </body> </html> It creates a new record but I want it to update an existing one. It's an editprofile script. hi all ,, I have a table : test (id , name , title , area , city) and I want from user to insert more than one record .. I made the script but I don't know there are better than this code .. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>My test</title> </head> <body> <table align="center" width="70%"> <tr> <form action="<?php $_SERVER['PHP_SELF']?>?>" method="get"> <?php if($_GET['submit']){ $con = mysql_connect("localhost","root",""); $db = mysql_select_db("test",$con); for($i = 1 ; $i < 10 ; $i++){ $name = $_GET['name'.$i]; $title = $_GET['title'.$i]; $area = $_GET['area'.$i]; $city = $_GET['city'.$i]; $sql = "INSERT INTO `test`.`test` (`title` ,`name` ,`area` ,`city`)VALUES ( '$name', '$title', '$area', '$city');"; $query = mysql_query($sql , $con); } }else { $con = mysql_connect("localhost","root",""); $db = mysql_select_db("test",$con) or die (mysql_error()); echo '<tr><td>Name</td><td>Title</td><td>Area</td><td>City</td></tr>'; for ($i = 1 ; $i < 10 ; $i++){ echo '<tr><td><input type="text" name="title'.$i.'" /></td> <td><input type="text" name="name'.$i.'" /></td> <td><input type="text" name="area'.$i.'" /></td> <td><input type="text" name="city'.$i.'" /></td></tr> <br /> '; } echo '<tr><td colspan="4"><input type="submit" name="submit" value="submit" /></td></tr>'; } ?> </form> </tr> </table> </body> </html> I wait you to advise me and I want your opinion .. than you very much .. I am trying to create a query to insert data into a table in my Access database. I have the following query:
INSERT INTO Issues (DateRequested, CustomerID, ComputerID, Issue, ItemsIncl, ImageName) VALUES (#1/14/2015#, 1, 1, "Computer freezes while I'm on the internet.", "AC Adapter", "none.gif")which should be performed from within my PHP page. However, when I check the database afterward, the new record isn't there. I then tried performing the query directly in Access and it worked fine. Why would it work in Access, but not when I run the same query in PHP? Chris I have 2 tables, access_level and pages. In pages table i will have all the details of page like page_id, code, herf, pagename.. and i will select few from this table and store it in access_level table depending on the department and position. Now while editing, i will display all the pages which is stored in access_level pages with a particular page code along with those pages from pages table. if the page_id exists in access_level table, its has to get updated, if its not present then it should get inserted into access_level table. These things am doing with checkbox and <li>. my access_level table access_level.JPG 18.19KB 0 downloads and my pages table pages.JPG 37.86KB 0 downloads here is my code
$s1 = mysql_query("SELECT pages.page_id as pid, pages.code, pages.page,
pages.href, access_level.aid, access_level.page_id as pgid,
access_level.department, access_level.position,
access_level.active
FROM pages
LEFT JOIN access_level ON (pages.page_id=access_level.page_id
AND access_level.department=".$department."
AND access_level.position=".$position.") WHERE pages.code='snor die(mysql_error());
while($s2 = mysql_fetch_array($s1)) { ?>
<tr><td><li><?php echo $s2['page']; ?> </td><td><input type="checkbox" name="sn[]" value="<?php echo $s2['pid']; ?>" <?php if($s2['pgid'] === $s2['pid']) echo 'checked="checked"';?> />
<input type="hidden" value="<?php echo $s2['pid']; ?>" name="page_id[<?php echo $s2['pgid']; ?>]">
while submittings i am not getting the logic, how can be done. Please somebody suggest me
Not sure if this is right. I can't get it to insert my record. Can someone please tell me if I'm doing it right?
cus_functions.php
function dbRowInsert($table_name, $form_data)
{
global $conn;
$fields = array_keys($form_data);
$sql = "INSERT INTO ".$table_name."
(`".implode('`,`', $fields)."`)
VALUES('".implode("','", $form_data)."')";
return mysqli_query($sql);
}
process.php
include("new_db.php");
include("cus_functions.php");
$do=$_GET['do'];
if($do=='addpro'){
if(isset($_POST['submit'])){
$input = $_POST['title'];
$comp = '0';
$form_data = array('title' => $input, 'completed' => $comp);
dbRowInsert('projects', $form_data);
}}
Greetings mates, I have not been here for years. I have been thrust into an app written by someone else. The requirement is to amend, not edit, an existing record. In other words, rather than edit an existing record, management would like an empty new text box to enter amended data and save to another table so that when queried, would display existing record and the newly amended record. Below is an ID of an existing record:
$sql = "SELECT * FROM DBO.existingTable where year_created = 2019 Order by Id";
echo '<table id="results-table">
<thead>
<tr>
<th>ID</th>
<th>Edit</th>
<th>View PDF</th>
<th>Task Lead</th>
<th>Task Title</th>
<th>Division</th>
</tr>
</thead>';
while ( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_BOTH ) ) {
$div = ($row['division'] == "1" ? "Divname" : ($row['division'] == "2" ? "Highway" : "NULL"));
$taskType = ($row['task_type'] == 0 ? "Annual" : ($row['task_type'] == 1 ? "Carryover" : ($row['task_type'] == 2 ? "New" : "NULL")));
if($row['year_created'] == 2019){
echo '<tr id="taskId">
<td>'.$row['Id'].'</td>
<td><a href="project_edit.html?id='.$row['Id'].'" target="_blank">Edit</a></td>
<td><input type="button" onclick="getReport('.$row['Id'].')" value="View PDF"></td>
<td>'.$row['task_lead'].'</td>
<td>'.$row['task_title'].'</td>
<td>'.$div.'</td>
</tr>
}
}
echo '</table>'
The above code isa snippet of code in edit.php. What I would like to do is grab the ID which is '.$row['Id'].' from this edit page and use it when inserting the amended code which is in insert,php file:
//The ID from edit.php code should go here
$task_lead = (empty($_POST['task_lead'])) ? "''" : "'" . str_ireplace( "'", "", $_POST[ 'task_lead' ] ) . "'";
$task_title = (empty($_POST['task_title'])) ? "''" : "'" . str_ireplace( "'", "''", $_POST[ 'task_title' ] ). "'";
$division = (empty($_POST['division'])) ? "''" : "'" . str_ireplace( "'", "", $_POST[ 'division' ] ) . "'";
//Then my insert statement should be something like this:
$sql = "INSERT INTO DBO.Amended_Records ({id from table with existing record}, amended_taskActivities, amended_taskProducts,amendscope_dev_fhwa, amendconsultant_procurement, amendcontract_negotiations, amendconsultant_notice, amendtotal_duration, year_created)
VALUES ({$rowId - that I need to get from edit.php}, $amendproposed_activities, $amendanticipated_products,$amendscope_dev_fhwa,$amendconsultant_procurement,$amendcontract_negotiations,$amendconsultant_notice,$amendtotal_duration, 2021)";
When I insert this record into the DB, the id from edit.php is getting inserted as null. Can you please advise how I can resolve this? I am trying to get this query correct. I want to insert a record into the database upon form submission but only if the record does not already exist. If the record exists, then I want it to be updated in the database.
What is happening: Upon form submit, a new record is entered into the database every time. Note: The contact_id column is both primary key and unique in my database. Here is my code:
if($_POST['submit']){
$con=mysqli_connect("localhost","username","password","database_name");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$org = mysql_real_escape_string($_POST['organization']);
$namefirst = mysql_real_escape_string($_POST['firstName']);
$namelast = mysql_real_escape_string($_POST['lastName']);
$emailaddy = mysql_real_escape_string($_POST['email']);
$phonenum = mysql_real_escape_string($_POST['phone']);
$appquestion = mysql_real_escape_string($_POST['appquestion']);
$banner = mysql_real_escape_string($_POST['banner']);
$bulletin = mysql_real_escape_string($_POST['bulletin']);
$giveaway = mysql_real_escape_string($_POST['giveaway']);
$app = mysql_real_escape_string($_POST['app']);
$tshirt = mysql_real_escape_string($_POST['tshirt']);
$tshirtp = mysql_real_escape_string($_POST['tshirtp']);
$print = mysql_real_escape_string($_POST['print']);
$party = mysql_real_escape_string($_POST['party']);
$orgnotes = mysql_real_escape_string($_POST['notes']);
$sql="INSERT INTO database_name (contact_id, first_name, last_name, email_address, phone_number, org, appquestion, banner, bulletin, giveaway, app, tshirt, promised_tee, print, party, org_notes)
VALUES
('','$namefirst','$namelast','$emailaddy','$phonenum','$churchorg','$appquestion','$banner','$bulletin','$giveaway','$app','$tshirt','$tshirtp','$print','$party','$orgnotes')
ON DUPLICATE KEY UPDATE first_name = '$namefirst', last_name = '$namelast', email_address = '$emailaddy', phone_number = '$phonenum', org = '$org', appquestion = '$appquestion', banner = '$banner', bulletin = '$bulletin', giveaway = '$giveaway', app = '$app', tshirt = '$tshirt', promised_tee = '$tshirtp', print = '$print', party = '$party', org_notes = '$orgnotes'" ;
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error($con));
}
echo "1 record added";
mysqli_close($con);
}
From everything I have read, I need to use ON DUPLICATE KEY UPDATE to replace the old information with new information in the database upon form submission. While the insert part of my code is working, the portion with ON DUPLICATE KEY UPDATE is not working.
Why might this portion of the code not be working? Is there a better way to insert else update the information?
Thank you for any help or guidance you can give me! I've been working on this concept for three days and have read a ton of information about it, but am still not able to get it to work.
I'm trying to set it so that it will delete an entire populated directory based upon a value in the database then after finishing that to go back and delete that row in the database. my current code is Code: [Select] <?php $page_title = "Central Valley LLC | Photo Addition" ?> <?php include("header.php"); ?> <?php include("nav.html"); ?> <div id="content"> <form action="delprod.php" method="post" enctype="multipart/form-data"> <label for="which">Choose A Product To Remove:</label> <?php $con = mysql_connect("localhost","phoenixi_cv","centraladmin"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("phoenixi_cvproducts", $con); $result = mysql_query("SELECT * FROM Products"); echo "<select name=\"which\">"; while($row = mysql_fetch_array($result)) { echo "<option "; echo "value=\"" . $row['id'] . "\">"; echo $row['Name'] . "</option>"; } echo "</select>"; mysql_close($con); ?> <br /> <input type="submit" name="submit" value="Submit" /> </form> </div><!--#content--> <?php include("footer.html") ?> and the delete script Code: [Select] <?php $con = mysql_connect("localhost","phoenixi_cv","centraladmin"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("phoenixi_cvproducts", $con); $result = mysql_query("SELECT id FROM Products WHERE id=$_POST['which']"); $row = mysql_fetch_array($result) chdir('assets'); chdir('images'); $mydir = $row . '/'; $d = dir($mydir); while($entry = $d->read()) { if($entry!="." && $entry!="..") { unlink($_POST['which'] . '/' . $entry); } } rmdir($mydir); $result = mysql_query("DELETE * FROM Producs WHERE id=$_POST['which']"); ?> Thank you in advance for all your help. any easier ways of approaching this will be welcome as well I may not be a PHP wizard, but a view counter seems pretty damn simple and easy to implement. Unless you leave it in my hands... It's a pretty simple problem, so I'm hoping it'll be a simple solution. Every time you load a game on my website, at the top of the php "playgame.php" is a function call: $objGlobal->update_gameplay($gameid); In my functions.class.php is the function declaration: function update_gameplay() { $args = func_get_args(); $getsql = mysql_query("select * from games where gameid = $args[0]"); if($getsql) { $resultgame = mysql_fetch_array($getsql, MYSQL_ASSOC); $timesplayed = $resultgame['timesplayed'] + 1; $updatesql = "update games set timesplayed = '$timesplayed', last_played = now() where gameid = $args[0]"; if(mysql_query($updatesql)) return true; else return false; } } Yet, when I load the playgame page, it adds 1,2 or 3!!! So this means the function is being called 1, 2 or 3 times, but how can that be if it is at the VERY top of the page? Try it yourself on my website, www.gpstudios.com. Click on a game and reload. For some reason, the newer games always add 1, but other older/more popular games add 1, 2 or 3 I've searched for the string "update" and the string "timesplayed" in every file using a program called FileSeek and I can say for certain that the function must be being called multiple times for some reason. What's weirder is that my game reviews (http://www.gpstudios.com/reviews.php) are also having their view counter incremented by 1 or 2 on a page load. Please help me solve this quick. Thanks, -Tom Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Right now I redirect to index page after I delete a record. However I am looking to make it so that I can delete a record without redirecting the page. I know this can be accomplised using Ajax. I have spent countless hours before trying to make it work, but it did not work.
So here is a basic setup I created. Can you please update it with ajax code so that I can see how it's done properly?
<!DOCTYPE HTML> <html lang="en"> <head> <meta charset="UTF-8"> <title>Home Page</title> </head> <body> <div class="record" > <a href="record.php?id=<?php echo $record_id ?>"><?php echo $record_name; ?></a> <div class="delete-record"> <a href="delete.php">Delete Record</a> </div> </div> </body> </html> Edited by man5, 18 August 2014 - 08:55 PM. |
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