PHP - Variable Variable Array Call How?

Code: [Select]
<?

$i=1;

$analysts[$i] = array(0=>'alpha');
$regions[$i] = array(0=>'beta');
$countries[$i] = array(0=>'gamma');
$provinces[$i] = array(0=>'delta');
$events[$i] = array(0=>'epsilon');

$selectable_document_elements = array
(
0=> analysts,
1=> regions,
2=> countries,
3=> provinces,
4=> events
);

foreach($selectable_document_elements as $value)
{

echo $value;
print_r($$value[$i]);
echo "</br>";
}
?>


I can't seem to call $$value[$i], however when I leave off the [$i] part     Code: [Select]
print_r($$value); I get the individual elements...

Code: [Select]
analystsArray ( [1] => Array ( [0] => alpha ) )
regionsArray ( [1] => Array ( [0] => beta ) )
countriesArray ( [1] => Array ( [0] => gamma ) )
provincesArray ( [1] => Array ( [0] => delta ) )
eventsArray ( [1] => Array ( [0] => epsilon) )
However, I would like to get the 1 part of the array, in this example. Is there a magic trick to calling variable arrays' individual elements?

My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user  and $priv are  undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working.

The code I'm using:

<?php
session_start();
function verify() {
	//verify that the user is logged in via the login page. Session_start has already been called. 
	if (!isset($_SESSION['loggedin'])) {
	header('Location: /index.html'); 
	exit;
	}
	//if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges   // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users. 
        $user === $_SESSION['name'];
    //Connect to Databse
	$link = mysqli_connect("127.0.0.1", "database user", "password", "database");
	if (!$link) {
  	  echo "Error: Unable to connect to MySQL." . PHP_EOL;
    	echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
    	echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
    	exit;
        }
        //SQL Statement to lookup privlege information. 
       if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) {
         //LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv.
            while ($row = $result->fetch_assoc()) {
           $priv === $row["su"];
            }
        }
        // close SQL connection.
        mysqli_close($link);

 // Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special 
//accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators. 

        if ($priv !== 1) {
        echo $_SESSION['name'];
        echo "you have privlege level of $priv";
        echo "<br>";
        echo 'Your account does not have the privleges necessary to view this page';
        exit;
        }
        
}
verify();
?>

 

Hi guys im in the middle of optimizing code..

Code: [Select]
$sql = "SELECT * FROM sa_enemystats WHERE username='$username'";
$res = mysql_query($sql);
while ($row = mysql_fetch_assoc($res)) {

$enemy['current_health'] = $row['current_health'];
$enemy['current_skill'] = $row['current_skill'];
$enemy['level'] = $row['level'];
$enemy['damage'] = $row['damage'];
$enemy['evade'] = $row['evade'];
$enemy['accuracy'] = $row['accuracy'];
$enemy['speed'] = $row['speed'];
$enemy['luck'] = $row['luck'];

echo 'debug: variables synced with db table';
}I know that the setting of these variables are messy  and can be done in a better way... but how? I have tried foreach and copying other's code for an array copy but it lead no where. Then again my syntax could be wrong... I used something like
Code: [Select]
foreach ( $enemy[$value] as $row => $value) {
$enemy[$value] = $row[$value];
}

Hi

I am buidling a Blog System using OO techniques (or at least attempting to)..

I keep getting an error :

Notice: Undefined variable: blog_categoryName in C:\wamp\www\atkinsonsCMS\admin170976\blog_categories.php on line 13
...And then underneath all that is is displaying 'Call Stack'. I've never come across this notification before so I guess it is an OO term, and the a list of unexpected outputs: #, time, memory, function and location....each with an associated value.
I attempted to resolve the variable issue in the usual way (as you can see in my code), but still the errors/warnings persist.

The purpose of this part of the code is to simply retrieve SQL data (which is a list of blog categories), allowing the user to select one and then click through to be directed to the appropriate category page (although this last requirement of the code has not yet been programmed).

Could those who have experience of this please take a look at my code and let me know where I am going wrong?

Thanks

blog_categories.php
This file calls on the the blogFunctions.php Category Class, and the displays the results.


session_start();
$pageTitle = "Blog Categories";
include("../includes/admin_header.php");
include("../classes/blogFunctions.php");
echo '<div class="admin_main_body"><br /><br />';
echo "<h2>Category List</h2><br />";
$content = new Category;
$content -> process();
//print_r(debug_backtrace());
echo "<a href=blog.php>$blog_categoryName</a>";
echo '</div>';
echo '</div>';
include("../includes/admin_footer.php");




blogFunctions.php
This class deals with the retreaval of the SQL data, and then passes it to blog_categories.php


class Category {
               public $errors;
               public $blog_categoryName = NULL;
public function __construct() {
                $this->errors = array();
                $blog_categoryName = $this->blog_categoryName;
                }                       
public function getCategories(){
                if(!isset($blog_categoryName))
                {
                $blog_categoryName = 'value';
                }
                ($GLOBALS["___mysqli_ston"] = mysqli_connect("localhost", "atkinson", "XYZ111WA")) or die(((is_object($GLOBALS["___mysqli_ston"])) ? mysqli_error($GLOBALS["___mysqli_ston"]) : (($___mysqli_res = mysqli_connect_error()) ? $___mysqli_res : false)));
                ((bool)mysqli_query($GLOBALS["___mysqli_ston"], "USE atkinsonscms")) or die (((is_object($GLOBALS["___mysqli_ston"])) ? mysqli_error($GLOBALS["___mysqli_ston"]) : (($___mysqli_res = mysqli_connect_error()) ? $___mysqli_res : false)));
                mysqli_query($GLOBALS["___mysqli_ston"], "SELECT * FROM blog_category ORDER BY ASC");
                $result = @mysqli_query($GLOBALS["___mysqli_ston"], $query);
                if ($result) {
                while ($row = $result->fetch_object()) {
                $blog_categoryName = $row->blog_categoryName;
                 }
                //need to use mysqli query to retrieve results. 
                if(mysqli_affected_rows($GLOBALS["___mysqli_ston"])< 1)
                $this->errors[] = 'Could not retrieve data';
                }
                                }
public function show_errors(){
                echo "<h3>Errors</h3>";
                foreach($this->errors as $key=>$value)
                echo $value."<br>";
                                    }
public function process() {
                $this->getCategories();
                return count($this->errors)? 0 : 1;
                                    }
} //Closes Category Class.            

Hello,
   I have the situation shown below in the code:

if(//condition is met)
{ $val = new Val();
  $valon = $val->check($_POST, array(.........));
}
if($valon->passes())
{ $use = new Use();
  ........
}
//check() and passes() both belong to class Val
public function check($source, $items = array())
{ ......................
  return $this;
}

I get the following warning and error:

Notice: Undefined variable: valon
and
Fatal error: Call to a member function passes() on a non-object

I can't see anything wrong with the code. check() returns an object of class Val which is assigned to $valon, $valon then calls a member function of class Val. Could you please help. Please let me know whether to include further code.