PHP - Php Variable Variables?

Is it possible to split a variable into 2 variables?


///  I have this sentence
$item = "Below Telegraph Hill, Smallwork Canvas Edition";

/// And I want to be able to do this
$item = "Below Telegraph Hill" ;
$medium = "Smallwork Canvas Edition";


Is it possible to find the comma in a string, and remove the comma & everything before or after it? Any recommendations would be appreciated.

Question about variable variables and using session variables for them. O.K. So if I have:

$foo = 3;
$_SESSION['bar'] = "foo";

$$_SESSION['bar']  should equal the value of $foo, however I can't get it to work. Can someone tell me what I am doing wrong..... is it formatting???

Thanks,
Thomas

I know how to use $$ and ${} to use variable variables, but how would I get the same functionality out of a variable that is storing an object name?

I have a function that is passed the name of an array of objects.  As you can guess, that name will change based on which portion of the program is calling
the function.  How would I use variable variables of objects in this instance?  Would it just be:

Code: [Select]
$this->${$objArrayName}->threadName = etc;
?

To make sure I'm not being misunderstood, I have 3 arrays of objects (replies, mainThreads, and stickies) and depending on which name I pass the function, I want it
to use $this->replies OR $this->mainThreads OR $this->stickies to apply properties of those objects to.

Thanks for any help.

-Adam

I'm not versed in PHP OOP and I have some code that I need to echo out onto a page. I don't know what the meaning of $ct->something is in this code. Is this an array of some type? How do I echo out the $ct->title onto another page? Use a function call? I just don't know what all of the $ct variables are and how to get to them. Any help is appreciated.
Code: [Select]
function current_theme_info() {
    $themes = get_themes();
    $current_theme = get_current_theme();
    if ( ! isset( $themes[$current_theme] ) ) {
        delete_option( 'current_theme' );
        $current_theme = get_current_theme();
    }
    $ct->name = $current_theme;
    $ct->title = $themes[$current_theme]['Title'];
    $ct->version = $themes[$current_theme]['Version'];
    $ct->parent_theme = $themes[$current_theme]['Parent Theme'];
    $ct->template_dir = $themes[$current_theme]['Template Dir'];
    $ct->stylesheet_dir = $themes[$current_theme]['Stylesheet Dir'];
    $ct->template = $themes[$current_theme]['Template'];
    $ct->stylesheet = $themes[$current_theme]['Stylesheet'];
    $ct->screenshot = $themes[$current_theme]['Screenshot'];
    $ct->description = $themes[$current_theme]['Description'];
    $ct->author = $themes[$current_theme]['Author'];
    $ct->tags = $themes[$current_theme]['Tags'];
    $ct->theme_root = $themes[$current_theme]['Theme Root'];
    $ct->theme_root_uri = $themes[$current_theme]['Theme Root URI'];
    return $ct;
}

This topic has been moved to Other Libraries and Frameworks.

http://www.phpfreaks.com/forums/index.php?topic=357370.0

i have Created a Session  with this code $_SESSION['USER_NAME'] = trim($_POST['username'])


How can i access the $_SESSION['USER_NAME'] in other Pages ;

and will this code for $var = $_SESSION[USER_NAME] 

can i get the SESSIOn value in " $var"  variable ??

Say I have two variables like below. I basically want to select one of them, but through random choice. How do I do that?

$orange = 'Orange';
$apple = 'Apple';

 

I have this simple while loop which retrieves data from a mysql query and displays several links on my homepage.

I would like to avoid using the php get function and add query strings to my urls

I am thinking of using session variables but I need help and I'm pretty sure this can't be done.

When a visitor clicks a link from the several ones displayed by the while loop, that particular variable would be set in a session.

In my code, the session will always send the last var

Can this be done?

    Code: [Select]
<? session_start(); // Start Session Variables

    $result = mysql_query("my query");

    while($slice = mysql_fetch_assoc($result)){
        $url = $slice['url'];
        $name  = $slice['name']; ?>

        <a href="<? echo $url; ?>"><? echo $name; ?></a>

    <? }

    $_SESSION['name'] = $name; // Store session data  ?>

I am trying to achieve something that appears simple but  I spent few hours in vain



Quote

$tag1 = '<a href="layout_m.php?k='.$k.'&name='.$name.'&type='.$type.'">';

if ($k=="1") {$history = ucfirst($name) . ' - ' . $tag1 . $k .'</a>'  ; }
else {$history = $history . ' - '. $tag1 . $k . '</a>' ;}

print $history;



This is part of a page which is involved in passing data by forms or/and URL (eg layout.php?k=1) and the display of the page depends on k.


At k=1,(first page)  things are ok [Joe -  <a href="layout_m.php?k=1&name=Joe&type=genus"> 1 </a>]

but on passing to the next page, the output is not as desired

part of the variable is escaped out on the browser and breaks the variable content


View source gives this:
Joe -  <a href= -  <a href="layout_m.php?k=3&name=Joe&type=genus"> 1 </a>

while I want:

Joe -  <a href="layout_m.php?k=1&name=Joe&type=genus"> 1 </a> -  <a href="layout_m.php?k=3&name=Joe&type=genus"\> 3 </a>

What I achieve to do is a simple history based on an accumulation of k

EG Joe - 1 - 3 - 5 - 6 - 8  Where each number (k) is linked and when pressed each go to the corresponding keypage.

Hello,

If I have this string:

$tags="baseball glove face" (this can vary from 1 to 15 different words)

how would i loop through and divide these into different

$tag1=baseball
$tag2=glove
$tag3=face
.. and so on (if more words)

Thanks for help

First page adds a new job number, then the order page loaded with the job number id as a get id. Basically there is a while loop in the order page which shows products/services client can order and he chooses what he requires 'one or eight services' (8 in total) and some other variables like date of order and client name etc. Here is the order item code

The first sql statement executes fine, but in the second sql query nothing happens


$sql="insert into job_order(order_num,order_date,order_customer_id, order_remarks) values(".$_GET['id'].",NOW(),".$_POST['companyBox'].",'".$_POST['remarkBox']."');"; $res=mysql_query($sql);  $id=mysql_insert_id();   foreach($_POST as $key => $value) {          if(!empty($value)) {           $key.' => '.trim(strip_tags($value));            $order="INSERT INTO orderprod (order_num,prod_id,order_amount,teeth_amount) VALUES ('$_GET[id]','$value','$value','$value');"; $orderres=mysql_query($order) or die(mysql_error()); } }?>$sql="insert into job_order(order_num,order_date,order_customer_id,
order_remarks)
values(".$_GET['id'].",NOW(),".$_POST['companyBox'].",'".$_POST['remarkBox']."');";
$res=mysql_query($sql);

$id=mysql_insert_id();


foreach($_POST as $key => $value) {


        if(!empty($value)) { 
 
         $key.' => '.trim(strip_tags($value));  
     
         $order="INSERT INTO orderprod (order_num,prod_id,order_amount,teeth_amount) VALUES
('$_GET[id]','$value','$value','$value');";
$orderres=mysql_query($order) or die(mysql_error());
}
}
?>



=============

This is the formI have removed parts which are irrelevant. Please note that dateBox and companyBox are not required to be looping as they are only for first table,



echo "<form action=".$config_basedir."./vieworder.php?id=".$_GET['id']."  name=form1 method=post>";?><table><tr><td><h4>JOB ORDER</H4></TD><TD></TD></TR><TR><TD>ORDER NUMBER</TD><TD><?PHP ECHO $_GET['id'] ?></td></tr><tr><td>ORDER DATE</td><td><input type=text name=dateBox></td></tr> <tr><td>COMPANY NAME</td><td><?PHP$sql="select * from customers";$res=mysql_query($sql);echo "<select name=companyBox><option value=''>Please select</option>";WHILE($fetch=mysql_fetch_assoc($res)){ echo "<option value='".$fetch['id']."'>".$fetch['cust_name']."</option>";} echo "</select>"; echo "</td></tr>"; ?>   </table> <table><tr><th>ITEM</th><th>QUANTITY</th><th>N0. of Teeths</th></tr><tr><?PHP$sql="select * from products";$res=mysql_query($sql); WHILE($fetch=mysql_fetch_assoc($res)){ echo "<td><input type=text name=desBox value='".$fetch['prod_id']."'>".$fetch['prod_name']."</td><td><input type=text name=quantBox></td><td><input type=text name=teethBox></td>";echo "</tr>";}echo "</table>";?>echo "<form action=".$config_basedir."./vieworder.php?id=".$_GET['id']."  name=form1 method=post>";
?>
<table>
<tr>
<td><h4>JOB ORDER</H4></TD><TD></TD>
</TR>
<TR>
<TD>ORDER NUMBER</TD><TD><?PHP ECHO $_GET['id'] ?></td>
</tr>
<tr>
<td>ORDER DATE</td><td><input type=text name=dateBox></td>
</tr>

<tr>
<td>COMPANY NAME</td><td>
<?PHP
$sql="select * from customers";
$res=mysql_query($sql);
echo "<select name=companyBox><option value=''>Please select</option>";
WHILE($fetch=mysql_fetch_assoc($res)){

echo "<option value='".$fetch['id']."'>".$fetch['cust_name']."</option>";}
echo "</select>";
echo "</td></tr>";
?>



</table>

<table>
<tr>
<th>ITEM</th><th>QUANTITY</th><th>N0. of Teeths</th>
</tr>
<tr>
<?PHP
$sql="select * from products";
$res=mysql_query($sql);

WHILE($fetch=mysql_fetch_assoc($res)){

echo "<td><input type=text name=desBox value='".$fetch['prod_id']."'>".$fetch['prod_name']."</td>
<td><input type=text name=quantBox></td>
<td><input type=text name=teethBox></td>";
echo "</tr>";}
echo "</table>";
?>



HERE IS THE IMAGE showing the populated services.
http://dubads.com/images/order.jpg

I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here.  It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere.

<?PHP require('connect.php'); ?>

<form action ='' method='post'> <select name="id">

<?php
$extract = mysql_query("SELECT * FROM cars");
   
   while($row=mysql_fetch_assoc($extract)){
   $id = $row['id'];
   $make= $row['make'];
   $model= $row['model'];
   $year= $row['year'];
   $color= $row['color'];

echo "<option value=$id>$color $year $make $model</option>
";}?>

</select>

Which attribute would you like to change?<br />
<input type="radio" name="getchanged" value="make"/>Make<br />
<input type="radio" name="getchanged" value="model"/>Model<br />
<input type="radio" name="getchanged" value="year" />Year<br />
<input type="radio" name="getchanged" value="color"   />Color<br /><br />

   <br /><input type='text' value='' name='tochange'>
   <input type='submit' value='Change' name='submit'>

</form>

//This is where I need help...

<?PHP
if(isset($_POST['submit'])&&($_POST['tochange'])){
mysql_query("
   UPDATE cars
   SET '$_POST[getchanged]'='$_POST[tochange]'
   where id = '$_POST[id]'
         ");}?>

Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment.

My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted."
The program should not accept any numbers greater than 100 or any characters.

Once I do this, I must take a second number and do a similar thing.

Finally, I must have a statement show up at the bottom stating which number is greater.

Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters.

Any help you can provide will be greatly appreciated!

Hi. I have some code which needs to return a single variable from the function and stored as a variable within this page, so it can be echoed later on in the page. I couldn't get it to return as a variable, so i used "return compact();" to return the variable and "extract (myFunction());" to extract it to variables. However, when I turned on php's display errors and error reporting function, I got an error message saying "Warning: extract() [function.extract]: First argument should be an array in /my/web/site/index.php on line 6" (which is where my extract function is). This works fine with passing more than one variables through, is there another way pass one variable from a function to be stored as a variable on the page which called the function?

Here is the function:
Code: [Select]
<?php
//This is a list of numeric error codes against their text. this will return the error code as the variable $issue
function checkLoginIssue() {

//If there is an error code
if (isset($_GET["issue"])) {
 
  //cycle through the list until the code is reached, return the text and break the switch
    switch ($_GET["issue"]) {

      case "1":
              $issue = '<p class="warning">Please log in to view this page</p>';
              break;
  
      case "2":
              $issue = '<p class="warning">Wrong Username or Password</p>';
              break;

        case "3":
              $issue = '<p class="warning">No user found with those details</p>';
              break;

    }
 
 //return the variable in an array with a single value
 return compact('issue');
 
}
 
}
?>
And here is the code which calls the function:
Code: [Select]
<?php
extract(checkLoginIssue());
?>

My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user  and $priv are  undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working.

The code I'm using:

<?php
session_start();
function verify() {
	//verify that the user is logged in via the login page. Session_start has already been called. 
	if (!isset($_SESSION['loggedin'])) {
	header('Location: /index.html'); 
	exit;
	}
	//if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges   // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users. 
        $user === $_SESSION['name'];
    //Connect to Databse
	$link = mysqli_connect("127.0.0.1", "database user", "password", "database");
	if (!$link) {
  	  echo "Error: Unable to connect to MySQL." . PHP_EOL;
    	echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
    	echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
    	exit;
        }
        //SQL Statement to lookup privlege information. 
       if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) {
         //LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv.
            while ($row = $result->fetch_assoc()) {
           $priv === $row["su"];
            }
        }
        // close SQL connection.
        mysqli_close($link);

 // Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special 
//accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators. 

        if ($priv !== 1) {
        echo $_SESSION['name'];
        echo "you have privlege level of $priv";
        echo "<br>";
        echo 'Your account does not have the privleges necessary to view this page';
        exit;
        }
        
}
verify();
?>