PHP - Delete Multiple Entries
Hi guys
Im trying to delete multiple images from a page with the code below, I have retirieved the images successfully but i can not delete the with checkbox, wht it does is just refereshing the page and thats it, what im trying to do is to delete the image from the database but it wont. can u help me please? <?php session_start(); include ("../../global.php"); //welcome messaage $username=$_SESSION['username']; echo "$username"; $query=mysql_query("SELECT id FROM users WHERE username='$username'"); while($row = mysql_fetch_assoc($query)) { $user_id = $row['id']; } $ref=$_GET['reference']; $images=mysql_query("SELECT * FROM img WHERE refimage='$ref'"); while($row = mysql_fetch_array($images)) { $image=$row['image']; $thumb=$row['thumb']; ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td><form name="" method="post" action=''> <tr> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $rows['id']; ?>"></td> <td bgcolor="#FFFFFF"><? echo "<a href='$image' rel='lightbox[roadtrip]'><img src= '$thumb' width='60' height='40' alt='$title'>";?></td> <? } ?> <tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td> </tr> <?php // Check if delete button active, start this $delete = $_REQUEST['delete']; if( $delete != '' ){ $checkbox = $_REQUEST['checkbox']; $count = count($_REQUEST['checkbox']); for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $del = mysql_query("DELETE FROM img WHERE id = '$del_id'"); } } ?> Similar TutorialsHi, I want to build into my html table that populates my database table to have a column for checkboxes with a delete button that takes the user to another page to confirm the deletion by outputting a message: Are you sure you want to delete ____, followed by a for loop to see how many checked records to get its ID in order to get its appropriate name. So I have a submit button with name attribute of "delete0" and the values of the input type of checkbox is $row['ID'], for some reason, I get the notice: "Notice: Undefined index: modifyArray in C:\display.php" and modifyArray is the name I give to the checkbox attribute (please see this in my display.php below) Here is my display.php Code: [Select] <table border="border"> <!--NB: checkbox form for multiple delete/update/insert--> <form method="post" action=""> <input type='submit' value='DELETE' name='delete0' /> <?php session_start(); require 'bellSessionDisconnect.inc'; require 'bellConnect.inc.php'; $result=mysql_query("SELECT ID, Image, Name, Manufacturer, Price, Description, SimSupport FROM bellProducts"); //phpinfo(); //NB: print table headings if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { //$counter+=1; print "<table border='border'>"; print "<tr> <th>ID</th> <th>Select entries to modifiy</th> <th>Image</th> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> <th colspan='2' align='center'>Modify</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { //extract($row); "<tr align='center'> <td>$row[ID]</td> <td><input type='checkbox' name='modifyArray[]' value='$row[ID]' /></td> <td>"; if(!empty($row['Image'])) { $curImage=$row['Image']; } else if(empty($row['Image'])) { $curImage='fileUploadIcon.jpg'; //$title="please upload item image"; } print "<img src=$curImage width='70px' height='90px' /> </td> <td> $row[Name] </td> <td> $row[Manufacturer] </td> <td> $$row[Price]</td> <td align='left'>$row[Description]</td> <td>$row[SimSupport]</td> <td><a href='bellUploadForm.php?ID=$row[ID]'>UPLOAD IMAGE</a></td> <td><a href='bellUpdateForm.php?ID=$row[ID]'>UPDATE</a></td> </tr>"; //}//END INNER IF }//END WHILE }//END BIG IF ?> <?php if(array_key_exists('delete0', $_POST)) { $modifyArray=$_POST["modifyArray"]; if(!empty($modifyArray)) { header("Location: http://localhost/bellDeleteForm.php"); exit(); } } ?> </form> </table> I will worry about redirecting to bellDeleteForm.php to confirm the records the user wants to delete after I get this going, please help!!! thanks Hello, I'm requesting your help here cause I'm really confused. I'm looking for deleting entries when an image doesn't load on my links test. I got all my links in a .txt file like this : links.txt = Code: [Select] <div class="gallery"> <a href="http://www.website.com/page"> <img src="http://tc16.easythumbhost.com/image.jpg" onerror="ImgError(this)"/> </a> </div> #enddiv the "onerror" code in img src sends an "Image Missing" pic. What I'd want is to change the "onerror" function to open a php script which deletes all the lines of the div. This is the script I use to show the links on my page : Code: [Select] $links = "links.txt"; $fd = fopen ($links, "r"); $content = fread ($fd,filesize ($links)); fclose ($fd); $delimiter = "#enddiv"; $splitcontent = explode($delimiter, $content); $output = array_slice($splitcontent, 0,100); foreach ( $output as $divs ) { echo "$divs"; } I've searched hours and tried lots of codes before posting Help would be very appreciated. Thanks. Maybe some of the great coders here can help this noob out. So here is what I have so far: Code: [Select] //set age criteria for deletion $age = 60; //get current date $datenow = date("Y-m-d"); //set the range we want to delete $delete_range = $datenow - $age; //get old user_id from users table $oldusers_users = mysql_query ("SELECT user_id FROM users WHERE lastvisit < $delete_range "); //get user_id from images table that correspond to users table $oldusers_images = mysql_query ("SELECT user_id FROM images WHERE $oldusers_users=user_id.images "); //find folders that correspond to the usernames and delete $oldusers_files = mysql_query ("SELECT username FROM users WHERE lastvisit < $delete_range "); //print out username //$result = mysql_($oldusers_files); $foldername = mysql_result($oldusers_files, 0); $sigspath = "sigs/"; unlink($sigspath . $foldername . ".gif/index.php"); rmdir($sigspath . $foldername . ".gif"); //now delete user_id's from database mysql_query("DELETE * FROM users WHERE user_id=$oldusers_users"); mysql_query("DELETE * FROM images WHERE user_id=$oldusers_images"); unset($oldusers_users, $oldusers_images, $oldusers_files, $foldername, $sigspath ); mysql_close($link); Right now it is only returning the first entry, not the entire list that meets the criteria. It does delete that one file though but does not remover the rows from the database. I am sure the database stuff is jacked up I am really new to that part. What am I doing wrong here or is there a better way to do this perhaps I have a form where a user can duplicate part of a form like below: I've named the fields with the HTML arrays (ie. "fieldName[]") and came up with this: //--> CONTROLLERS $system_controllers_qty = $_POST['system_controllers_qty']; $system_controllers_make = $_POST['system_controllers_make']; $system_controllers_model = $_POST['system_controllers_model']; $system_controllers_serial_no = $_POST['system_controllers_serial_no']; for ($i = 0; $i < count($system_controllers_qty); $i++) { echo "qty " . clean($system_controllers_qty[$i]) . "<br/>"; echo "make " . clean($system_controllers_make[$i]) . "<br/>"; echo "model " . clean($system_controllers_model[$i]) . "<br/>"; echo "serial_no " . clean($system_controllers_serial_no[$i]) . "<br/>"; } //--> CPUS $system_cpus_qty = $_POST['system_cpus_qty']; $system_cpus_model = $_POST['system_cpus_model']; $system_cpus_serial_no = $_POST['system_cpus_serial_no']; $system_cpus_speed = $_POST['system_cpus_speed']; for ($i = 0; $i < count($system_cpus_qty); $i++) { echo "qty " . clean($system_cpus_qty[$i]) . "<br/>"; echo "model " . clean($system_cpus_model[$i]) . "<br/>"; echo "serial_no " . clean($system_cpus_serial_no[$i]) . "<br/>"; echo "speed " . clean($system_cpus_speed[$i]) . "<br/>"; } //--> DISKS $system_disks_qty = $_POST['system_disks_qty']; $system_disks_make = $_POST['system_disks_make']; $system_disks_model_no = $_POST['system_disks_model_no']; $system_disks_size = $_POST['system_disks_size']; $system_disks_serial_no = $_POST['system_disks_serial_no']; for ($i = 0; $i < count($system_disks_qty); $i++) { echo "qty " . clean($system_disks_qty[$i]) . "<br/>"; echo "make " . clean($system_disks_make[$i]) . "<br/>"; echo "model_no " . clean($system_disks_model_no[$i]) . "<br/>"; echo "size " . clean($system_disks_size[$i]) . "<br/>"; echo "serial_no " . clean($system_disks_serial_no[$i]) . "<br/>"; } //--> MEMORY $system_memory_qty = $_POST['system_memory_qty']; $system_memory_serial_no = $_POST['system_memory_serial_no']; $system_memory_manf = $_POST['system_memory_manf']; $system_memory_part_no = $_POST['system_memory_part_no']; $system_memory_size = $_POST['system_memory_size']; for ($i = 0; $i < count($system_memory_qty); $i++) { echo "qty " . clean($system_memory_qty[$i]) . "<br/>"; echo "serial " . clean($system_memory_serial_no[$i]) . "<br/>"; echo "manf " . clean($system_memory_manf[$i]) . "<br/>"; echo "part_no " . clean($system_memory_part_no[$i]) . "<br/>"; echo "size " . clean($system_memory_size[$i]) . "<br/>"; } This just outputs all the fields I post at the moment. Say I have 3 different disk types, it's going to loop 3 times. Is it possible to make this all into 1 giant query or am I better off doing each query separately? Each section is a different table. Hello, Hopefully I can ger som help here I have been googling this for months and seem to cant find anything that will help me out. I am trying to create a form (which is the easy part) but I want this form to send multiple entries at once from what I gather so far I need to use for each and/or loop which i am not familiar with it with my lack of knowledge........ what I have so far is Table= locations fields are id state county city the form is set up as follows state county city city city city city city city city city city city city The reason for so many cities is so i can update all cities in one county at the same time saving time I am not sure if its % doable in the manner i would like it to be done but i hope so ok i enter the state and county then i enter the cities i want i submit the form i want it to create the state/county and the first city with the next id # then enter the state/county and next city and id#. please some help me if u need to see my file let me know and ill post it im just not sure which one you need i believe it will be the save.php file but i also have the create.php file which is the form itself Thanks anyone for the help i can get Hello, For starters I'm not sure if what I want to do is possible, but if it is I would like your input. I have a script that will show a number of fields to fill out in a second form based on the number the user puts into the first from. the problem is that only the last one saves into the database and not all of them. Code: [Select] <form auction="index.php" method="post"> System Name: <input type="text" name="systemname"> Number of E-sites: <input type="text" name="events"> Number of Sigs: <input type="text" name="sigs"><br> <input type="reset" name="reset" value="Reset"> <input type="submit" name="start" value="Start"> </form> <form auction="index.php" method="post"> <?php $events = $_POST['events']; $system = $POST['systemname']; if (isset($_POST['start'])) { $num = $_POST['sigs']; $i = 0; While ($i < $num) { echo "Sig ID: <input type=text name=sigid>"; echo "Type: <input type=text name=type>"; echo "Name: <input type=text name=name>"; echo "Notes: <input type=text name=notes>"; echo "<br>"; $i++; } } ?> <input type="submit" name="enter" value="Enter"> </form> <?php $sigid = $_POST['sigid']; $type = $_POST['type']; $name = $_POST['name']; $notes = $_POST['notes']; mysql_connect('xt', 'x', 'x'); mysql_select_db('wormhole'); if (isset($_POST['enter'])) { $query = "INSERT INTO sites VALUES ('$system','$events','$sigid','$type','$name','$notes')"; mysql_query($query); } ?> How do I get it so all the data saves, lets say that $num = 5, I want all 5 to save not just the last one. MySQL returns an error in the form of a number, a state, and a message. Without parsing the message you will not be able to determine what column is duplicated.While parsing the error code, I have also notice that, if you have multiple unique fields as duplicates, only the first duplicate encountered will be returned in the message. This is not very helpful to the end user.
Is there any way to parse the returned error code to reflect all duplicate fields, please see sample code below?
$error=array(); $sql = 'INSERT INTO staff(username, email, phone) VALUES (?, ?, ?)'; $stmt = $conn->stmt_init(); $stmt = $conn->prepare($sql); // bind parameters and insert the details into the database $stmt->bind_param('sss', $username, $email, $phone); $stmt->execute(); if ($stmt->errno == 1062) { $errors[] = "One of the fields is already in use."; } Here is one of those purely conceptual questions, which involves no code. I'm trying to create a select query which among other things, allows a user of a website to search other members who fall within a particular age range. I have a column in the table where the members' information are stored which records their ages. Which brings us to the problem. On any given day, a member's age may increase by one year compared to what it was the previous day, hence the need to update this column periodically. I can't think of any way to automatically update this column on a daily basis. So my solution is to run an initial update query every time a member tries to search other members based on age, which updates the age column for all other members, before running the select query which eventually retrieves the desired age range. This leads to the second problem. Imagine there are thousands of users using the website. At any given instance, there could be hundreds of members, trying to search others based on age. This means hundreds of users will be updating a single column (the age column) in one table at the same time. Is this feasible? Can it cause the server to crash? Or is there really a more reasonable way to do all of this? Thank you all for taking your time to read this. Appreciate any responses. Hi All, I am adding a button that will delete many things in the system which all have the same $job_id There is going to be 10 or so tables that need to delete * where $job_id = ? Is there a better way to do this rather than just iterating my code 10 times. I was looking at just joining but isnt one benefit of prepared statements that they can be used again and again to increase speed. I have the following session variables for each item in a cart, which gets updated each time an item is added from the catalog // Register the session variables $_SESSION['ses_basket_items']=$ses_basket_items; $_SESSION['ses_basket_name']=$ses_basket_name; $_SESSION['ses_basket_amount']=$ses_basket_amount; $_SESSION['ses_basket_price']=$ses_basket_price; $_SESSION['ses_basket_stockcode']=$ses_basket_stockcode; $_SESSION['ses_basket_image']=$ses_basket_image; $_SESSION['ses_basket_size']=$ses_basket_size; $_SESSION['ses_basket_sizechoice']=$ses_basket_sizechoice; $_SESSION['ses_basket_id']=$ses_basket_id; I have a current cart page which loops through the sessions and displays them in a form. I have a check box for each item with the name="remove[]" and the value is the itemID which is the $ses_basket_id of item in the session. I have a select box with name="size[]" and the value is the users selected size for each item in the session which is $ses_basket_size Finnally I have a quantity text box with name="quantity[]" and the value is the users quantity value selected which is $ses_basket_amount. After all the looping through the products displaying each item in a row I have an update cart submit button name="change" outside the loop. What I want to know is how do I setup to perform each of these actions for each item in the session, how do I create the foreach loops for each array to delete or modify the correct items in the session if they are modified. I have the code to perform each task but dont know how to loop it through for each item in the session affecting only the correct session items. so if I have 3 items in the session for example, and I want to change the size of item 1, remove item 2 and change item 3 for quantity 1 to quantity 3 with only the 1 form and change button for all items and actions? Hope that makes sense any help with this would be appreciated. Hello all, im new to this forum, im a noobie, just started coding about 3 weeks ago, don't be too hard on me.
My question is I wan't to check for challenges a user's team posted that have not been excepted after 1 day, then auto refund the user's team back there credits, and then also delete all the challenges. So far here is my code.
//Delete all matches not accepted after 1 day $arrayin = array(); $autorefund = mysql_query("SELECT * FROM `challenges` WHERE `a` = " . $team['id'] . " " . "AND `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < " . ((int) time()) . ")"); if (mysql_num_rows($autorefund) > 0) { while ($autorefund = mysql_fetch_assoc($autorefund)) { $arrayin[] = $autorefund['id']; mysql_query("UPDATE `teams` SET `balance` = `balance` + " . $autorefund['credits'] . " " . "WHERE `id` IN (" . mysql_real_escape_string(implode(',', $arrayin)) . ")"); mysql_query("DELETE FROM `challenges` WHERE `a` IN " . "(" . mysql_real_escape_string(implode(',', $arrayin)) . ") " . "AND `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 " . "AND (`expires` < " . ((int) time()) . ")"); } }FYI here is the code i had, it works fine, however it will only delete 1 challenge per team, not all of there challenges. $autorefund = mysql_query("SELECT * FROM `challenges` WHERE `a` = " . $team['id'] . " AND `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < ".((int)time()).")"); if (mysql_num_rows($autorefund) > 0) { while ($autorefund = mysql_fetch_assoc($autorefund)) { if ($autorefund['accepted'] == 0 and $autorefund['expires'] < time()) { mysql_query("UPDATE `teams` SET `balance` = `balance` + " . $autorefund['credits'] . " WHERE `id` = " . $team['id'] . ""); mysql_query("DELETE FROM `challenges` WHERE `a` = " . $team['id'] . " AND `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < ".((int)time()).")); } } }I inherited this script, its using deprecated statements, i know im not skilled to rewrite the entire site to use prepared statements. I need Delete Duplicate Email Records That Are Attached To One Account But Can Be Found In Multiple Accounts I have a table, consumer_mgmt. It collects consumer information from various forms. These forms are available through different pages that are part of a business package. A business can offer these signups to gather names and emails from consumers for various types of specials they may offer. So a consumer my be in the consumer_mgmt table 5, 10, 15 times for that particular business. But, that consumer may be in the consumer_mgmt table multiple times for a different business. So multiple times for multiple businesses. I need to remove duplicates for each business account so the consumer is only the consumer_mgmt only once for each business. There are approximately 15,000 rows currently in the consumer_mgmt table. I'm not sure where to begin on the logic. Since there are multiple business accounts that the emails are attached to, would one have to build a case for each loop? Hi all. Here is my scripts which allow user to check multiple rows of data and delete it , but it require select data and click for twice to delete the rows , what should be the error? Code: [Select] <form name="frmSearch" method="post" action="insert-add.php"> <table width="600" border="1"> <tr> <th width="50"> <div align="center">#</div></th> <th width="91"> <div align="center">ID </div></th> <th width="198"> <div align="center">First Name </div></th> <th width="198"> <div align="center">Last Name </div></th> <th width="250"> <div align="center">Mobile Company </div></th> <th width="100"> <div align="center">Cell </div></th> <th width="100"> <div align="center">Workphone </div></th> <th width="100"> <div align="center">Group </div></th> </tr> </form> <? echo "<form name='form1' method='post' action=''>"; while($objResult = mysql_fetch_array($objQuery)) { echo "<tr>"; echo "<td align='center'><input name=\"checkbox[]\" type=\"checkbox\" id=\"checkbox[]\" value=\"$objResult[addedrec_ID]\"></td>"; echo "<td>$objResult[addedrec_ID] </td>"; echo "<td>$objResult[FirstName]</td>"; echo "<td>$objResult[LastName] </td>"; echo "<td>$objResult[MobileCompany] </td>"; echo "<td>$objResult[Cell] </td>"; echo "<td>$objResult[WorkPhone] </td>"; echo "<td>$objResult[Custgroup] </td>"; echo "</tr>"; } echo "<td colspan='7' align='center'><input name=\"delete\" type=\"submit\" id=\"delete\" value=\"Delete\">"; if (isset($_POST['delete']) && isset($_POST['checkbox'])) // from button name="delete" { $checkbox = ($_POST['checkbox']); //from name="checkbox[]" $countCheck = count($_POST['checkbox']); for($d=0;$d<$countCheck;$d++) { $del_id = $checkbox[$d]; $sql = "DELETE from UserAddedRecord where addedrec_ID = $del_id"; $result2=mysql_query($sql) or trigger_error(mysql_error());;; } if($result2) { $fgmembersite->GetSelfScript(); } else { echo "Error: ".mysql_error(); } } echo "</form>"; Thanks for every reply. <body> <?php include 'sql.php'; $query = "SELECT * FROM validation"; $result = mysqli_query($con , $query); $rows = mysqli_fetch_assoc($result) ; $totals = mysqli_num_rows($result) ; ?> <div id="css"> <form > <table width="80%" border="0" cellpadding="2" cellspacing="2" > <caption><h2>Personal Details of Customers</h2></caption> <tr class="white"> <td bgcolor="#330033"> </td> <td bgcolor="#330033"> Id Number </td> <td bgcolor="#330033"> Full Name </td> <td bgcolor="#330033"> Email Address </td> <td bgcolor="#330033"> Website </td> <td bgcolor="#330033"> Comment </td> <td bgcolor="#330033"> Time </td> </tr> <?php while($rows=mysqli_fetch_assoc($result) { <tr> <input type="raido" name="ID" value="<?php echo $rows['ID']; ?>" /> <td bgcolor="#FFFFCC"><?php echo $rows['ID'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Name'];?> </td> <td bgcolor="#FFFFCC"><?php echo $rows['Email'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Website'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Comment'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Time'];?></td> <td> </td> <td> <a href="delete.php? ID= "$rows[ID]" /"> <input type="submit" name="del" value="Delete" /> </a> <input type="button" name= "edit" value="Edit" /> </td> </tr> }?> </table> </form> </div> </body> Hi,
I wish to find out is there any possible that I can delete some data inside my php website but inside my sql database, the record will still at there?
Thank you.
I'm trying to set it so that it will delete an entire populated directory based upon a value in the database then after finishing that to go back and delete that row in the database. my current code is Code: [Select] <?php $page_title = "Central Valley LLC | Photo Addition" ?> <?php include("header.php"); ?> <?php include("nav.html"); ?> <div id="content"> <form action="delprod.php" method="post" enctype="multipart/form-data"> <label for="which">Choose A Product To Remove:</label> <?php $con = mysql_connect("localhost","phoenixi_cv","centraladmin"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("phoenixi_cvproducts", $con); $result = mysql_query("SELECT * FROM Products"); echo "<select name=\"which\">"; while($row = mysql_fetch_array($result)) { echo "<option "; echo "value=\"" . $row['id'] . "\">"; echo $row['Name'] . "</option>"; } echo "</select>"; mysql_close($con); ?> <br /> <input type="submit" name="submit" value="Submit" /> </form> </div><!--#content--> <?php include("footer.html") ?> and the delete script Code: [Select] <?php $con = mysql_connect("localhost","phoenixi_cv","centraladmin"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("phoenixi_cvproducts", $con); $result = mysql_query("SELECT id FROM Products WHERE id=$_POST['which']"); $row = mysql_fetch_array($result) chdir('assets'); chdir('images'); $mydir = $row . '/'; $d = dir($mydir); while($entry = $d->read()) { if($entry!="." && $entry!="..") { unlink($_POST['which'] . '/' . $entry); } } rmdir($mydir); $result = mysql_query("DELETE * FROM Producs WHERE id=$_POST['which']"); ?> Thank you in advance for all your help. any easier ways of approaching this will be welcome as well Below is the part of my code that creates the html table. How do I add pagination every 30 entries? $db = mysql_connect("localhost","trend_learnu","asdfasdf"); mysql_select_db("trend_learningdb",$db); $result = mysql_query("SELECT * FROM Peoples ORDER BY number ASC"); $table = '<table width="608" border="0" align="center" cellpadding="10" cellspacing="0"> <tr> <td style="color:#fff;" width="207" bgcolor="#425d74"><strong>Firstname</strong></td> <td style="color:#fff;" width="204" bgcolor="#425d74"><strong>Lastname</strong></td> <td style="color:#fff;" width="197" bgcolor="#425d74"><strong>Date</strong></td> <td style="color:#fff;" width="197" bgcolor="#425d74"><strong>Weight</strong></td> </tr>'; while($row=mysql_fetch_array($result)) { $firstname = $row['Firstname']; $lastname = $row['Lastname']; $weight = $row['Weight']; $date = $row['Date']; $table.= '<tr>'; $table.= '<td bgcolor="#e8f4ff">'.$firstname.'</td>'; $table.= '<td bgcolor="#e8f4ff">'.$lastname.'</td>'; $table.= '<td bgcolor="#e8f4ff">'.$date.'</td>'; $table.= '<td bgcolor="#e0ffe6"><strong>'.$weight.'</strong></td>'; $table.= '</tr>'; } $table .= '</table>'; echo $table; mysql_close($con) the problem is that when I add an item to be displayed in the blog, shows three instead, which two are empty. It should not create three entries when I just add one entry. How can I fix this? <?PHP /* define the blog content file name */ $filename = "myBlogContent.txt"; ?> <?php /* check to see if the file exists */ if (!file_exists($filename)) { echo "The Blog Is Empty"; }else{ /* get the file lines into an array */ $BlogArray = file($filename); /* count the number of blog entries */ $count = count($BlogArray); $i=0; while($i<$count) { $new_array = explode("|", $BlogArray[$i]); echo "Posted by: " . $new_array[1] . "<br>"; echo "Posted on: " . date("m/d/y h:iA", time($new_array[0])) . "<br>" echo "Title: " . $new_array[2] . "<br>"; echo $new_array[3] . "<hr>"; $i ++; } } ?> <?PHP /* obtain the form data */ $who = $_POST['who']; $title = $_POST['title']; $content = $_POST['content']; $content = str_replace(array("\r\n", "\r", "\n"), "<br>", $content); /* create timestamp variable for current date and time */ $when_ts = time(); /* define the blog content file name */ $filename = "myBlogContent.txt"; /* prepare the variables for adding to the file */ $new_line_content = $when_ts . "|" . $who . "|" . $title . "|" . $content . "\n"; /* open the file in the APPEND MODE */ $fh = fopen($filename, 'a+') or die("can't open file"); /* add the new content */ fwrite($fh, $new_line_content); /* close the file */ fclose($fh); //exit; // Closes further script execution . ?> I have an issue with some code I have. All the code works correctly apart from when submit is clicked not only does it update a the current club but it creates a blank entry in the database! I cant see whats wrong. Here is the code......... //gets $validation = $_GET['new_club']; //Querys $qGetClub = "SELECT * FROM clubs WHERE validationID = '$validation'"; $rGetClub = mysql_query($qGetClub); $Club = mysql_fetch_array($rGetClub); //Query for category by name $qGetCat = "SELECT * FROM club_category WHERE catID = ".$Club['cat'].""; $rGetCat = mysql_query($qGetCat); $CatName = mysql_fetch_array($rGetCat); //query for related sub categorys. $qGetSub = "SELECT * FROM sub_categorys WHERE catID =".$Club['cat'].""; $rSubCat = mysql_query($qGetSub); // query for groups created $Groupq = mysql_query("SELECT * FROM groups WHERE memberID = '".$User['memberID']."'"); //end of querys if(isset($_POST['insert_clubbtn1'])){ //Process data for validation $subcat = trim($_POST['subcat']); $NewSubCat = trim($_POST['NewSubCat']); //Prepare data for db insertion $subcat = mysql_real_escape_string($subcat); //find the new category //insert $result = mysql_query("UPDATE clubs SET `sub_category` = '$subcat' WHERE validationID ='$validation'") or die(mysql_error()); if ($result!=="") { $otherg = trim($_POST['other_groups']); $newg = trim($_POST['new_group']); $newg = mysql_real_escape_string($newg); //if an item other than none from the list is selected then update the club with an ID relating to the group it belongs to if ($otherg !=='None') { $groupsq = mysql_query("UPDATE `clubs` SET groupID ='$otherg' WHERE validationID ='$validation'") or die (mysql_error()); } // If none is selected then $newg must have a value so create a new group in the groups table and then on the next page I will add the group in the club table else { $groupsq = mysql_query("INSERT INTO `groups` (`memberID`, `group`, `clubID`) VALUES ('".$User['memberID']."', '$newg', '".$Club['clubID']."')")or die (mysql_error()); } } if ($NewSubCat !="") { mail("mail","New Sub Category Request","Dear Ring Master, \n\nThe club in the name of $name with a validation code of $validationID would like a new sub category called $new_cat\n\n \nTeam Arena\n\n\n\n"); } $url = "/members/create/create_clubp3.php?new_club=$validation"; header("Location: $url"); } Code: [Select] $query = mysql_query("SELECT a.*, b.* FROM friendlist a INNER JOIN friendlist b ON (a.friendemail=b.friendemail) INNER JOIN users c ON (b.friendemail = c.EmailAddress) WHERE a.email = 'asdf@gmail.com' AND c.Username LIKE '%carol%' GROUP BY a.id ORDER BY count(*) DESC"); Code: [Select] while ($showfriends = mysql_fetch_array($query)) { echo $showfriends['Username']; } and I would get nothing. It produces the correct number of <div> so i know it's getting through, but it's having trouble displaying the entries? |