PHP - Form Values 2
Hi, how would i display the date that is already in db and was submitted by user when he logs in to their profile?
That code below works for the values like 'approved' 'denied' so on, but how would i do same for a date? thank you. Code: [Select] <?php include('config.php'); $uname=$_SESSION['username']; if($_SESSION['username']){ $sql="SELECT ApplicationStatus FROM table1 WHERE uname='$uname'"; $result=mysql_query($sql); $row = mysql_fetch_array($result);} echo '<form name="test" method="post"> <select name="ApplicationStatus"> <option value="">------</option> <option value="In process" '.(($row['column1']=='In process')?'selected="selected"':'').'>In process</option> <option value="Withdrawn" '.(($row['column1']=='Withdrawn')?'selected="selected"':'').'>Withdrawn</option> </select>'; ?> Similar Tutorialshi i was wondering how i can display the values for a form that already in db. users submitted a form and then when they log in to their profile they can change the value in a form, but the original value would show the one that they first submitted. makes sense? at the moment its set as blank, how would i display the option value to the one in the db on their profile? thanks Code: [Select] <form name="test" method="post"> <select name="ApplicationStatus"> <option value="'">------</option> <option value="In process">In process</option> <option value="Withdrawn">Withdrawn</option> </select> I have a form for a sign in page that I want the label for the form field to actually be displayed in the text box and clear when the box is selected to enter text. I've accomplished this using the code below and it works fine. The problem that I'm having is in IE the password field does not change to display dots or asterisk in place of each character. It works fine in Fire Fox but not in IE. Is there way to accomplish this using php or so that it is compatible with most browsers? Here's the code that I'm using: Code: [Select] <?php echo "<input type=\"text\" name=\"pword\" size=\"17\" value=\"Password...\" style=\"color: #999999\" onfocus=\"if (this.value == 'Password...') {this.value=''; this.style.color='#000000'; this.type='password';}\"> "; ?> On one of my calculators : https://bizztools.net/2017/qccu/bizztools2015_budgetTest.php
When you press on the envelope in the middle you can send a form to yourself. I've added the code in the file that gets used to send the form to the person's email.
for ($i = 0; $i <= 79; $i++) { $item_Annual[$i] = number_format($_REQUEST['itemAnnualDisplay[$i]']); } Body: (each line of the form has a different value for $item_Annual) from 1 to 79 <TD bgcolor="#EEEEEE" align="left" valign="middle" height="1"><Font style="font-family:Arial; font-size: 12px;"><font color="#000000"> '.$currencySymbol.$item_Annual[1].' </TD>
for ($i = 0; $i <= 6; $i++) { $incomeSubtotal += $values[$i] * $periods[$i]; $itemAnnual[$i] = $values[$i] * $periods[$i]; $return['itemAnnualDisplay[$i]'] = $itemAnnual[$i]; } //New addtions are lines 3 and 4, the others were already there
Now, I've done some process of elimination and when testing to see if $periods[$i] and values[$i] would show up on the form, the values were zero for each. So each $itemAnnual[$i]is calculated to be $0. You can see from the form screenshot, the subtotals are calculating, but the individual items are not. Could this have anything to do with the form on the calculator page? It's in bootstrap.
Help please!!
I've got a form that submits values to itself and the user input values are saved into the database in a table with an auto incrementing ID. After SUBMIT is clicked, it reloads the page and all the values are gone, I'm wondering how I can get it to keep the values so that the user can make a single change and resubmit again. I know I can save all the values into the session or in the URL or pass them through $_POST in an array but I'm wondering what is the proper way to do this. Thanks. Hello Everyone.. Im a programer in php with little experience. I have a form with 3 pages. 1st page display categories which come from category table. then user can select 1 or upto 3 category there. Then 2nd page display that selected categories and need to display relevant subject to that categories. In second page I use radio button for selected categories to keep a one category as a main category. each categories' subjects display with check boxes. In there too, user can select 1 or 3 more subject in to a particular category. In third form page, that my problem was encounter, there I need to print out selected category and their subjects in a table. first two pages are no problem for me and third form I have a problem in how to get categories and their subjects and they print as apiece in the page. like this category1 | subject1, subject2, subject3 category2 | subject1, subject2, subject3, subject and so forth. This same to my first form page Code: [Select] $q = 'SELECT * FROM category ORDER BY category_id'; $r = mysqli_query( $dbc, $q); $c = 0; $i = 0; echo '<form action="subjects.php" method="post">'; echo '<table class="form_table" ><tr>'; while($row = mysqli_fetch_array( $r, MYSQLI_ASSOC )){ // if remainder is zero after 2 iterations (for 2 columns) and when $c > 0, end row and start a new row: if( ($c % 2) == 0 && $c != 0){ echo "</tr><tr>"; } echo '<td width="50%"><input type="checkbox" name="category[]" value="' . $row['category_id'] . '" /> ' . $row['category_name'] . '</td>'; $c++; } // while.. // in case you need to fill a last empty cell: if ( ( $i % 2 ) != 0 ){ // str_repeat() will be handy when you want more than 2 columns echo str_repeat( "<td> </td>", ( 2 - ( $i % 2 ) ) ); } echo "</tr></table>"; ?> In second page 'subjects.php' I use Code: [Select] if ( isset($_POST['submitted1']) && isset($_POST['category']) && sizeof( $_POST['category']) == 3 ) { $_SESSION['category'] = $_POST['category']; print_r ( $_SESSION['category']); $q = 'SELECT * FROM category ORDER BY category_id'; $r = mysqli_query( $dbc, $q); while($_SESSION = mysqli_fetch_array( $r, MYSQLI_ASSOC )){ foreach( $_POST['category'] as $value ) { if ( $value == $_SESSION['category_id']) { $q = "SELECT category_subject.category_id, category_subject.subject_id, subjects FROM category_subject INNER JOIN category ON category_subject.category_id = category.category_id INNER JOIN subject ON category_subject.subject_id = subject.subject_id WHERE category_subject.category_id = {$_SESSION['category_id']}"; $r1 = mysqli_query( $dbc, $q); $c = $i = 0; echo '<table class="form_table" ><tr>'; while($_SESSION = mysqli_fetch_array( $r1, MYSQLI_ASSOC )){ // if remainder is zero after 2 iterations (for 2 columns) and when $c > 0, end row and start a new row: if( ($c % 2) == 0 && $c != 0){ echo "</tr><tr>"; } echo '<td width="50%"><input type="checkbox" name="subject[]" value="' . $_SESSION['subject_id'] . '" /> ' . $_SESSION['subjects'] . '</td>'; $c++; } // while.. // in case you need to fill a last empty cell: if ( ( $i % 2 ) != 0 ){ // str_repeat() will be handy when you want more than 2 columns echo str_repeat( "<td> </td>", ( 2 - ( $i % 2 ) ) ); } echo "</tr></table>"; } } } } Those two pages working properly. In third page that my problem page I tried something like this , but its not working. value come from subject.php page. Code: [Select] if ( ( isset($_POST['submitted2'])) && ( isset($_SESSION['category'])) && (isset( $_SESSION['subjects'])) && sizeof( $_SESSION['category']) == 1) { //$_SESSION['category'] = $_POST['category']; print_r ( $_SESSION['category']); echo 'good'; } elseif ( ( isset($_POST['submitted2'])) && ( isset($_SESSION['category'])) && (isset( $_POST['main_category'] ))) { print_r ( $_SESSION ); echo 'very good'; } So can any body tell me where is my mistake and help me fix this problem. any help greatly appreciated. thank you. Hi, I would like to know if there's a way to quickly collect and sort form data, then use that data in an if statement. I've tried for a while now and i just can't seem to figure it out. I would like to do this with radio buttons. Hopefully this will make it clear: Code: Code: [Select] <?php if (isset($_POST['submit'])) { // I don't know how to do this but maybe something like // if $_POST values == "Yes" // put them into an array // then count how many are in the array, e.g. 2 if 2 "Yes" radio buttons are selected $count = count($array) . " Yes values selected"; echo $count; //else if do the same for "No" values // hopefully this is understandable } ?> <!-- i want to take these values and group them, so all the "Yes" values selected together and the "no" values together --> <form method="post" action=""> <input type="radio" name="first" value="Yes" /> <input type="radio" name="first" value="No" /> <input type="radio" name="second" value="Yes" /> <input type="radio" name="second" value="No" /> <input type="submit" name="submit"> </form> I have a textarea feild in my form where the user can type in several keywords such as Textarea Box Below Cars Trains Buses I have a database with the meanings of the words entered and want to be able to get the three definitions from the database on for submission. In a normal input box where i only type one word i can grab no problem like so $word = $_POST['word']; $sql = "SELECT meaning FROM table WHERE word='$word'"; Though i am trying to get multiple values from the same textarea box So if a user types in 3 words the query would query the database on thoses three words, the problem is i dont know how to get the diffrent words from the form for example $first = $_POST['word']; which would be the first word $sec = $_POST['word']; which would be the second word etc. Any help here would be great thanks. Well, folks, thanks to all the help, I've narrowed my problem down to needing a way to allow a variable value to traverse into subsequent calls of a function. I have a simple integer - "companyID", and it's set in "actionfile.php" which is called by two forms. The first time it's called by Form A, it's set. I'd LIKE to put it into $_SESSION, but apparently $_SESSION is zeroed out before I can use it in the second call to "actionfile.php" by Form B. A new form/function call is a new session? I've tried setting it to global and static, to no avail. Anything more elegant than writing the value to SQL for later retrieval? Thanks! Mark i am writing this script for use as an include in joomla and the directphp plugin so in my joomla article i have: Code: [Select] <?php include 'test/conducttest.php'; conducttest(); ?> Ok now my issue! the form in this function is passing only the values for the last item in the loop rather than for the selected radio item when submitted. so when say for example the radio selected is: ID TEST TYPE UNIQUE TEST ID AVAILABLE 5 Adolescent Clinical 50021629 1 and the last item in the list is: ID TEST TYPE UNIQUE TEST ID AVAILABLE 4 Adult Clinical 12341629 1 When the form is submitted even if the 1st item is selected, it returns the value for the second one. I am sorta new to php so any suggestions will be appreciated. Here is my full code: Code: [Select] <?php function conducttest() { //GET JOOMLA USER ID & USERNAME FOR LOGGED USER $user =& JFactory::getUser(); $userID = $user->id; //GET JOOMLA DATABASE OBJECTS $db =& JFactory::getDBO(); //NEW TESTS QUERY (what purchased test are available for use with 'item_available' == '1' {unused test} and matching current 'user_id') $new_query = " SELECT * FROM crt_transactionHistory WHERE user_id = ".$userID." AND item_available = '1' ORDER BY item_name, id "; $db->setQuery($new_query); $new = $db->loadAssocList(); //OPEN TESTS QUERY (what purchased test are available for use with 'item_available' == '2' {resume test} and matching current 'user_id') $resume_query = " SELECT * FROM crt_transactionHistory WHERE user_id = ".$userID." AND item_available = '2' ORDER BY item_name, id "; $db->setQuery($resume_query); $resume = $db->loadAssocList(); //DISPLAY use_test FORM if(!isset($_POST['test'])) { //SELECT FORM: WHICH TEST WOULD YOU LIKE TO USE? echo ' <fieldset> <table> <form method="post" action="'.$PHP_SELF.'">'; if (empty($new)) { echo ' <th colspan="3"align="left">NO NEW TESTS AVAILABLE</th>'; } else { echo ' <th colspan="3"align="left">NEW TESTS AVAILABLE</th> <tr> <td width="75px">SELECT</td> <td width="50px">ID</td> <td width="150px">TEST TYPE</td> <td width="150px">UNIQUE TEST ID</td> <tr>'; foreach ($new as $result1) { echo ' <tr> <td><input type="radio" value="' .$result1['id']. '" name="test_id"></td> <td>'.$result1['id'].'</td> <td><input type="hidden" value="'.$result1['item_name'].'" name="item_name">'.$result1['item_name'].'</td> <td><input type="hidden" value="'.$result1['item_number'].'" name="item_number">'.$result1['item_number'].'</td> <input type="hidden" value="'.$result1['item_available'].'" name="item_available"> <input type="hidden" value="'.$userID.'" name="userID"> <tr>'; } } echo ' </table> <hr /> <table>'; if (empty($resume)) { echo ' <th colspan="3"align="left">NO TESTS TO RESUME</th>'; } else { echo ' <th colspan="3"align="left">RESUME TEST</th> <tr> <td width="75px">SELECT</td> <td width="50px">ID</td> <td width="150px">TEST TYPE</td> <td width="150px">UNIQUE TEST ID</td> <tr>'; foreach ($resume as $result2) { echo ' <tr> <td><input type="radio" value="' .$result2['id']. '" name="test_id"></td> <td>'.$result2['id'].'</td> <td><input type="hidden" value="'.$result2['item_name'].'" name="item_name">'.$result2['item_name'].'</td> <td><input type="hidden" value="'.$result2['item_number'].'" name="item_number">'.$result2['item_number'].'</td> <input type="hidden" value="'.$result2['item_available'].'" name="item_available"> <input type="hidden" value="'.$userID.'" name="userID"> <tr>'; } } echo ' </table> </fieldset> <input type="submit" name="test" value="Conduct Test" /> </form> '; } //NOW A TEST HAS BEEN SELECTED FOR USE if(isset($_POST['test'])) { $test_id = $_POST['test_id']; $item_name = $_POST['item_name']; $item_number = $_POST['item_number']; $item_available = $_POST['item_available']; $userID = $_POST['userID']; echo $test_id.'<br />'; echo $item_name.'<br />'; echo $item_number.'<br />'; echo $item_available.'<br />'; echo $userID.'<br />'; //IF THIS IS A NEW TEST... if ($item_available == "1") { echo 'new test'; } //IF WE ARE RESUMING A TEST... elseif ($item_available == "2") { echo 'resume test'; } } } ?> Hi, I'm trying to pass values from an array into a form. As a newbie, I've came up with the code underneath, but I want to pinpoint all the first values toward 1 selection list in the form. Any suggestions how to accomplish this? Thanks in advance. Ruud <html> <head> <title>Test formulier</title> </head> <body> <h2>Test formulier</h2> <form action="test.php" method="post"> <p> <?php $prijzen = array( array("01", "125","150", "A" => true,"B" => true), array("02", "125","150", "A" => true,"B" => true), array("03", "125","150", "A" => true,"B" => false), array("04", "125","150", "A" => true,"B" => true) ); ?> </P> <select name="prijzen[]" id="prijzen" multiple="multiple" size="7" class="none"> <?php while(list($key, $val) = each($prijzen)){ while(list($key2, $val2) = each($val)){ echo '<option value="'.$key2.'">'.$val2.'</option>'.PHP_EOL; } } ?> </select> </body> </html> Hi, I got this form which passes hidden values as well as a select menu. The only thing is, it doesnt seem to post the form data to the script.
Here is the form
echo '<form action="regsale.php" method="POST">'; echo '<input type="hidden" name="username" value="<?php echo $username ?>"'; echo '<input type="hidden" name="listing_title" value="<?php echo $listing_title ?>"'; echo '<input type="hidden" name="speciesCommon" value="<?php echo $speciesCommon ?>"'; echo '<input type="hidden" name="cost" value="<?php echo $cost ?>"'; echo '<input type="hidden" name="business" value="<?php echo $business ?>"'; echo '<input type="hidden" name="postage_cost" value="<?php echo $postage_cost ?>"'; echo '<input type="hidden" name="multipostage" value="<?php echo $multipostage ?>"'; echo "<ul class='results'>"; echo '<li>Quantity:</li>'; echo '<select name="quantity">'; echo "<option value='$quantity'>Maximum of $quantity available</option>"; for ($q=1; $q<=$quantity; $q++) { echo "<option value='$q'>$q</option>"; } echo '</select>'; echo' </ul><br>'; echo '<div align="center">'; echo '<br>'; echo '<input type="submit" value="Confirm Purchase"><br>'; echo '</form><br>';And here is the script that the form is posted to <?php include 'init.php'; include 'includes/overall/header.php'; include 'includes/logo.php'; if (!isset($_SESSION['loggedin'])) { die("You must be logged in to submit care guides"); //this causes to script to stop executing and lets the user know there is a problem /* Note: instead of the die() function, you could use the echo() function and provide an HTML link back to the login page, or use the header() function to just redirect users to the login page without any message. It is up to you to decide what your application should behave. */ } //else { //logged in elseif (isset($_SESSION['loggedin']) ){ //logged in $username = $_SESSION['loggedinuser']; if (isset($_POST['listing_title'], $_POST['speciesCommon'], $_POST['cost'], $_POST['business'], $_POST['postage_cost'], $_POST['multipostage'], $_POST['quantity'] ) ) { if( $_POST['listing_title'] == "" ) { echo "Error: Please go back and try again"; } elseif( $_POST['speciesCommon'] == "" ) { echo "Error: Please go back and try again"; } elseif( $_POST['cost'] == "" ) { echo "Error: Please go back and try again"; } elseif( $_POST['business'] == "" ) { echo "Error: Please go back and try again"; } elseif( $_POST['postage_cost'] == "" ) { echo "Error: Please go back and try again"; } elseif( $_POST['multipostage'] == "" ) { echo "Error: Please go back and try again"; } elseif( $_POST['quantity'] == "" ) { echo "Error: Please go back and try again"; } else { $listing_title = mysqli_real_escape_string($con, $_POST['listing_title']); $speciesCommon = mysqli_real_escape_string($con, $_POST['speciesCommon']); $cost = mysqli_real_escape_string($con, $_POST['cost']); $business = mysqli_real_escape_string($con, $_POST['business']); $postage_cost = mysqli_real_escape_string($con, $_POST['postage_cost']); $multipostage = mysqli_real_escape_string($con, $_POST['multipostage'] ); $quantity = mysqli_real_escape_string($con, $_POST['quantity'] ); if( $multipostage == "per item" ) { $postage_cost = $quantity * $postage_cost; } elseif( $multipostage == "Combined Postage" ) { $postage_cost; } $total = $cost + $postage_costage; // Writes customer_sales information to the MySQL database $sqlCustomerSales = "INSERT INTO customer_sales(username, listing_title, speciesCommon, total, business, postage_cost, multipostage ) VALUES ( '". $username ."', '". $listing_title ."', '". $speciesCommon ."', '". $total ."', '". $business ."', '". $postage_cost ."', '". $multipostage."' )"; $result1 = mysqli_query($con, $sqlCustomerSales); // This writes the transaction to the MySQL database $memo = $listing_title; $datetime = date("Y-m-d H:i:s"); $regCustomerTransaction = "INSERT INTO customer_transactions(username, datetime, cost, postage_cost, memo) VALUES ( '". $username ."', '". $datetime ."', '". $cost ."', '". $postage_cost ."', '". $memo."' )"; // Query the database $result2 = mysqli_query($con, $regCustomerTransaction); } // This writes the user_stats to the MySQL database $total_items_sold = $quantity; $regUserStats = "INSERT INTO user_stats(username, datetime, total, items_listed, bonus_credits, last_credit_purchase, total_care_guides, total_items_sold, total_currently_listed_items, total_items_purchased, total_diary_entries, feedback ) VALUES ( '". $username ."', '". $datetime ."', '". $total ."', '". $quantity ."', '". $subtotal ."', '". $last_credit_purchase ."', '". $total_care_guides ."', '". $total_items_sold ."', '". $total_currently_listed_items ."', '". $total_items_purchased ."', '". $total_diary_entries ."', '". $feedback."' )"; // Query the database $result3 = mysqli_query($con, $regUserStats); } ?> <h1>Payment to <?php echo $username ?></h1><br> <?php echo '<strong>Thank you for confirming you would like to purchase $speciesCommon; </strong>'; echo '<br>'; echo '<strong>Your payment comes to a total of $total; </strong></h2>'; echo '<br>'; echo '<br>'; echo 'Please complete payment using the PayPal button<br>'; echo '<br>'; echo '<br>'; ?> <form name="_xclick" action="https://www.paypal.com/cgi-bin/webscr" method="post"> <input type="hidden" name="cmd" value="_xclick"> <input type="hidden" name="shipping" value="<?php echo $postage_cost ?>"> <input type="hidden" name="business" value="<?php echo $business ?>"> <input type="hidden" name="currency_code" value="GBP"> <input type="hidden" name="item_name" value="<?php echo $speciesCommon ?>"> <input type="hidden" name="amount" value="<?php echo $cost ?>"> <input type="image" src="https://www.paypalobjects.com/en_US/GB/i/btn/btn_buynowCC_LG.gif" border="0" name="submit" onclick="OnButton1(); OnButton2();" alt="PayPal – The safer, easier way to pay online." > <img alt="" align="center" border="0" src="https://www.paypalobjects.com/en_GB/i/scr/pixel.gif" width="1" height="1"></form> <?php } else { echo 'Sorry we were unable to process your listing. Please contact <a href="mailto:helpdesk@aquapetcentre.com?Subject=Listing%20error">helpdesk@aquapetcentre.com'; die(); include('includes/overall/footer.php'); } // Close the connection mysqli_close($con); ?><h1>Payment to <?php echo $username ?></h1><br> works, but I think that is because it is passed in the SESSION. Any other $variable such as those below echo '<strong>Thank you for confirming you would like to purchase $speciesCommon; </strong>'; echo '<br>'; echo '<strong>Your payment comes to a total of $total; </strong></h2>';does not work. Why is the form not posting the values to the database. Just in case it helps, the form gets its values from the database, and the values are displayed in the sales page on which the form is contained. Here is the page containing the form. <?php include 'init.php'; include 'includes/overall/header.php'; include 'includes/logo.php'; if (!isset($_SESSION['loggedin'])) { die("You must be logged in to view this page!"); //this causes to script to stop executing and lets the user know there is a problem /* Note: instead of the die() function, you could use the echo() function and provide an HTML link back to the login page, or use the header() function to just redirect users to the login page without any message. It is up to you to decide what your application should behave. */ } //else { //logged in elseif (isset($_SESSION['loggedin']) ){ //logged in $username = $_SESSION['loggedinuser']; $results = $con->query("SELECT * FROM user WHERE username = '$username';"); while($row = $results->fetch_array()) { $business = $row['paypal_email']; $user_id = $_GET['user_id']; $results1 = $con->query("SELECT * FROM live_sales WHERE user_id = '$user_id';"); while($row = $results1->fetch_array()) { $username = $row['username']; $fishtype = $row['fishtype']; $speciesCommon = $row['speciesCommon']; $speciesScientific = $row['speciesScientific']; $listing_title = $row['listing_title']; $age = $row['age']; $quantity = $row['quantity']; $origin = $row['origin']; $size = $row['size']; $environment = $row['environment']; $waterChemistry = $row['waterChemistry']; $temperature = $row['temperature']; $feeding = $row['feeding']; $sexing = $row['sexing']; $compatability = $row['compatability']; $temperament = $row['temperament']; $breeding = $row['breeding']; $comments = $row['comments']; $postage_type = $row['postage_type']; $postage_cost = $row['postage_cost']; $multipostage = $row['multipostage']; $cost = $row['cost']; echo "<div class='result'>"; echo "<h3>$speciesCommon</h3>"; echo "<h2>$listing_title</h2>"; echo "<ul class='results'>"; echo "<li>Species</li>" . str_replace("_"," "," $fishtype") . "<br>"; echo "<li>Common Name:</li> $speciesCommon<br>"; echo "<li>Scientific Name:</li> $speciesScientific<br>"; echo "<li>Age:</li> $age<br>"; echo "<li>Quantity:</li> $quantity<br>"; echo "<li>Price per item:</li> £$cost<br>"; echo "<li>Origin:</li> $origin<br>"; echo "<li>Size:</li>$size<br>"; echo "<li>Environment:</li> $environment<br>"; echo "<li>Water Chemistry</li> $waterChemistry<br>"; echo "<li>Temperatu </li> $temperature<br>"; echo "<li>Feeding:</li> $feeding<br>"; echo "<li>Sexing:</li> $sexing<br>"; echo "<li>Compatability:</li> $compatability<br>"; echo "<li>Temperament:</li> $temperament<br>"; echo "<li>Breeding:</li>$breeding<br>"; echo "<li>Comments:</li> $comments<br>"; echo "<li>Postage Type:</li>$postage_type<br>"; echo "<li>Postage Cost:</li> £$postage_cost $multipostage<br>"; echo '<form action="regsale.php" method="POST">'; echo '<input type="hidden" name="username" value="<?php echo $username ?>"'; echo '<input type="hidden" name="listing_title" value="<?php echo $listing_title ?>"'; echo '<input type="hidden" name="speciesCommon" value="<?php echo $speciesCommon ?>"'; echo '<input type="hidden" name="cost" value="<?php echo $cost ?>"'; echo '<input type="hidden" name="business" value="<?php echo $business ?>"'; echo '<input type="hidden" name="postage_cost" value="<?php echo $postage_cost ?>"'; echo '<input type="hidden" name="multipostage" value="<?php echo $multipostage ?>"'; echo "<ul class='results'>"; echo '<li>Quantity:</li>'; echo '<select name="quantity">'; echo "<option value='$quantity'>Maximum of $quantity available</option>"; for ($q=1; $q<=$quantity; $q++) { echo "<option value='$q'>$q</option>"; } echo '</select>'; echo' </ul><br>'; echo '<div align="center">'; echo '<br>'; echo '<input type="submit" value="Confirm Purchase"><br>'; echo '</form><br>'; echo '<br><br> </div>'; exit(); } } echo 'Sorry but we could not find any results.'; } include 'includes/overall/footer.php'; ?>Any help is always appreciated. aquaman How does everyone take data input from an HTML Form and convert it into an Object in OOP? I am thinking it would be better if user inputs resided in an object so that I could manipulate the data in OOP terms instead of referencing the Form procedurally. TomTees If I store a value in a hidden form control, and then use that as a means to pass the value to another PHP script, could that cause any security issues?
Hi all I have a form with a few textareas and a bunch of input fields. The input fields are dynamically created from querying a country table. $query = $DB->query("SELECT country_code, country_id, IF(country_code = '".$country_code."', '', '') AS sel FROM countries WHERE site = 'test' ORDER BY country_name ASC"); foreach ($query->result as $row) { $options .= '<label>' . 'Phrase for ' . $this->settings['countries'][$row['country_code']] . '</label>' . '<br />'; $options .= '<input style="width: 100%; height: 5%;" id="country_data" type="text" name="' . $row['country_id'] . '" />' . '<br /><br />'; $options .= '<input type="hidden" name="country_id" id="country_id" value="' . $row['country_id'] . '" />'; } This is fine and outputs all the input fields I need. The problem comes when I need to get the value of each field input field and pass it into a query. The 'value' field of the inputs are numbers, such as 68, 70, 124, 108 etc so I can't get them in a for loop etc What's the easiest way to get all of these input field values? Can I use $_POST? Hi Everyone, I'm trying to figure out why my my form isn't accepting any values I put into it. I've been trying to figure this out for the past 2 hrs and I'm stumped. Any ideas please let me know. Thanks everyone! http://whatsmyowncarworth.com/auto/form2.php Code: [Select] <?php include('init.php'); $firstname = mysql_real_escape_string($_POST['firstname']); $lastname = mysql_real_escape_string($_POST['lastname']); $address = mysql_real_escape_string($_POST['address']); $state = mysql_real_escape_string($_POST['state']); $city = mysql_real_escape_string($_POST['city']); $sql="INSERT INTO customers (first_name, last_name, address, state, city) VALUES('$firstname','$lastname','$address','$state','$city')"; if ($firstname && $lastname && $address && $state && $city) { } else echo "You must fill the entire form!"; ?> >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> http://whatsmyowncarworth.com/auto/form.php Code: [Select] <html> <body> <form method="post" action="form2.php"> <table> <tr> <td>Firstname:</td> <td><input type="text" name="firstname"></td> </tr> <tr> <td>Lastname:</td> <td><input type="text" name="lastname"></td> </tr> <tr> <td>Address:</td> <td><input type="text" name="address"></td> </tr> <tr> <td>State:</td> <td><input type="text" name="state"></td> </tr> <tr> <td>City:</td> <td><input type="text" name="city"></td> </tr> <tr> <td><input type="submit" name="submit" value="Register!"></td> </tr> </table> </form> </body> </html> I have managed to create an update script that allows a user to submit changes to their details but I need help to finish of the code. I'm using sessions to login in members, here is my update.php code. After while($member = mysql_fetch_array($result)) { I would like to retrieve the new values entered by them to be displayed back to the previous form which uses $_SESSION to hold their information when they previously login. Any suggestions or ideas, as I think it's to do with clearing the session but unfamiliar on how to proceed. <?php include("config.php"); mysql_connect("$dbhost","$dbuser","$dbpass") or die(mysql_error()); mysql_select_db("$dbname") or die(mysql_error()); $id= mysql_real_escape_string($_POST['member_id']); $fname= mysql_real_escape_string($_POST['firstname']); $lname= mysql_real_escape_string($_POST['lastname']); $address= mysql_real_escape_string($_POST['address']); $town= mysql_real_escape_string($_POST['address2']); $county= mysql_real_escape_string($_POST['county']); $postcode= mysql_real_escape_string($_POST['postcode']); $telephone= mysql_real_escape_string($_POST['telephone']); $mobile= mysql_real_escape_string($_POST['mobile']); $username= mysql_real_escape_string($_POST['login']); $email=mysql_real_escape_string($_POST['email']); $id= $_POST['member_id']; $sql="UPDATE members SET firstname='$fname', lastname='$lname', address='$address', address2='$town', county='$county', postcode='$postcode', telephone='$telephone', mobile='$mobile', login='$username', email='$email' WHERE member_id='$id' LIMIT 1"; $result=mysql_query($sql) or die ("Error: ". mysql_error(). " with query ". $sql); $query = "SELECT * FROM members WHERE member_id = '$id'"; $result = mysql_query($query) or die(mysql_error()); while($member = mysql_fetch_array($result)) { } ?> Hi, I have this form currently setup and is showing the value from the table. <form action="updaterates.php" method="post"> <table width="350"> <tr> <td width="100">7 Nights</td> <td width="100"><input type="text" name="rates1" value="<?php echo ($row['rates1']); ?>" maxlength="3" size="3"></td> </tr> </table> </form> What do I need to do in order for it to update the value in the table... Thanks in advance... This is really cool if I can get it to work My PHP CODE: Code: [Select] $ids = implode (",", $ibforums->input['checkbox']); Grabs from this data in my HTML FORM: Code: [Select] <input name="checkbox[]" type="checkbox" value="{$r['id']},{$r['friendid']}"> Now when I pass my input, I will get 2 different values in both array's how do I separate them out? I know how to seperate them out using implode, but I need to seperate BOTH of the array's that are being passed, and I need to use them separately. Hey everyone. I have a project I'm working on and am having some issues. I'm trying to build a web-based FTP program for a client. I have all the ftp stuff down packed, but I'm having issues with connecting to a local computer. I can get the directories an a local disk viewing and changing just fine, my problem is I'm wondering how I might pass each value of the array generated by the scandir() function into a form element value such as a checkbox. The furthest I've been able to get with this is displaying the last object in the array. Here is some code: <?php foreach ($d as $key => $val) { echo "<table width=auto height=auto border=0> <tr> <td><img src=".$icon." width=16 height=16></td> <td>".$val."</td> <td><input name=selection type=checkbox value=".$val."></td> </tr> </table>"; ?> All I get is the last item in the array. any help is appreciated. |