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PHP - A Query Thats Abit Beyond Me
Hi All,
Im doing something for work (unpaid lol) that basically takes 2 tables, links them, then seperates out the results into "chargable" and "non chargeable" ... I need a query that will basically do this. Im going to type out what i think should happen.. OK 2 tables, incidents and jobs. SELECT incidentNumber, code1 FROM incidents ---- This gets ALL the incidents from the 1st table and returns all the $incidentNumber's aswell as $code1 SELECT job FROM jobs WHERE incidentNumber = $incidentNumber ---- This is the 2nd table with a matching incidentNumber field that the same as the 1st table incidentNumber field . AND THEN SELECT job FROM jobs where code2 = $code1 ---- this selects all the jobs with a code2 from the 2nd table that matches code1 from the 1st table. The end result is to only select incident numbers from the incidents table that have a matching code1 and code2 in the jobs table. Where do i start? i need to join the queries and the tables somehow and pass code1 as a var to the last bit when matching code1 to code2. Similar TutorialsHere is my code: // Start MySQL Query for Records $query = "SELECT codes_update_no_join_1b" . "SET orig_code_1 = new_code_1, orig_code_2 = new_code_2" . "WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)"; $results = mysql_query($query) or die(mysql_error()); // End MySQL Query for Records This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this??? Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1 Hello all,
Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).
The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).
Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:
In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).
I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.
Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.
So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:
1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red.
2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red.
3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.
Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.
Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.
Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.
Cheers guys!
case "update-delete":
if(isset($_POST['highlight-purchased']))
{
// ****** Setup customized query to obtain only items that are checked ******
$sql = "SELECT * FROM shoplist WHERE";
for($i=0; $i < count($_POST['checkboxes']); $i++)
{
$sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or";
}
$sql= rtrim($sql, "or");
$statement = $conn->prepare($sql);
$statement->execute();
// *** fetch results for all checked items (1st query) *** //
$result = $statement->fetchAll();
$statement->closeCursor();
// Setup query that will change the purchased flag to "N", if it's currently set to "Y"
$sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'";
// Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL
$sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL";
$statementSetToN = $conn->prepare($sqlSetToN);
$statementSetToY = $conn->prepare($sqlSetToY);
/*** loop through the results/collection of checked items ***/
foreach($result as $row)
{
if ($row["purchased"] != "Y")
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToY = $statementSetToY->fetch();
foreach($resultSetToY as $row)
{
$statementSetToY->execute();
}
}
else
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToN = $statementSetToN->fetch();
foreach($resultSetToN as $row)
{
$statementSetToN->execute();
}
}
}
break;
}
CRUD Queston.png 20.68KB
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If you also have any feedback on my code, please do tell me. I wish to improve my coding base. Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference. Code: Code: [Select] mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); Full code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $name = mysql_real_escape_string($_POST['name']); $server_type = mysql_real_escape_string($_POST['type']); $description = mysql_real_escape_string($_POST['description']); if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1"); if(mysql_num_rows($check1) < 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); echo "Server has been succesfully created!"; } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> I was just wondering if it's possible to run a query on data that has been returned from a previous query? For example, if I do Code: [Select] $sql = 'My query'; $rs = mysql_query($sql, $mysql_conn); Is it then possible to run a second query on this data such as Code: [Select] $sql = 'My query'; $secondrs = mysql_query($sql, $rs, $mysql_conn); Thanks for any help I'm trying to update every record where one field in a row is less than the other. The code gets each row i'm looking for and sets up the query right, I hope I combined the entire query into one string each query seperated by a ; so it's like UPDATE `table` SET field2= '1' WHERE field1= '1';UPDATE `table` SET field2= '1' WHERE field1= '2';UPDATE `table` SET field2= '1' WHERE field1= '3';UPDATE `table` SET field2= '1' WHERE field1= '4';UPDATE `table` SET field2= '1' WHERE field1= '5'; this executes properly if i run the query in phpMyAdmin, however when I run the query in PHP, it does nothing... Any advice? Say I have this query: site.com?var=1 ..I have a form with 'var2' field which submits via get. Is there a way to produce: site.com?var=1&var2=formdata I was hoping there would be a quick way to affix, but can't find any info. Also, the query could sometimes be: site.com?var2=formdata&var=1 I would have to produce: site.com?var2=updatedformdata&var=1 Is my only option to further parse the query? What would be the correct way to close a mysql query? At current the second query below returns results from the 1st query AND the 2nd query The 3rd query returns results from the 1st, 2nd and 3rd query. etc etc. At the moment I get somthing returned along the lines of... QUERY 1 RESULTS Accommodation 1 Accommodation 2 Accommodation 3 QUERY 2 RESULTS Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 QUERY 3 RESULTS Takeaways 1 Takeaways 2 Takeaways 3 Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <?php include($_SERVER['DOCUMENT_ROOT'].'/include/db.php'); ?> <title>Untitled Document</title> <style type="text/css"> <!-- --> </style> <link href="a.css" rel="stylesheet" type="text/css" /> </head><body> <div id="listhold"> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Placestostay.html">Places To Stay</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Accommodation' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingout.html">Eating Out</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingin.html">Eating In</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Takeaways' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------SKILLED TRADES BELOW---------------------------------------------------> <div class="list"><a href="Skilledtrades.html">Skilled Trades</a><br/> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Skilled Trades' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> here's the code: Code: [Select] $companyName = 'big company'; $address1 = 'big bay #8'; $address2 = 'some big warehouse'; $city = 'big city'; $province = 'AB'; $postalCode = 'T1T0N0'; $phone = '0123456789'; $email2 = 'bigKahuna@bigKahuna.edu'; $query = "INSERT INTO clients ( companyName, address1, address2, city, province, postalCode, phone, email) VALUES ( ". $companyName.",".$address1.",".$address2.",".$city.",".$postalCode.",".$phone.",".$email2.")"; $result = mysql_query($query, $connexion); if ($result) { // Success! echo "Fabulous! check the DB, we did it! :D<br>"; ?> <pre> <?php print_r($result); ?> </pre> <?php } else { // Fail! echo"CRAAAAAPP! something went wrong. FIX IT! :P<br>"; echo mysql_error(); } if (isset($connexion)) { mysql_close($connexion); } i copied it over from an old *working* file to illustrate how a simple INSERT works. this is the error i get: Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'company,big bay #8,some big warehouse,big city,T1T0N0,0123456789,bigKahuna@bigKa' at line 4 looks completely valid to me. all the database table elements are set to VARCHAR(80), so it can't be a space/type issue... halp! WR! I'm restarting this under a new subject b/c I learned some things after I initially posted and the subject heading is no longer accurate. What would cause this behavior - when I populate session vars from a MYSQL query, they stick, if I populate them from an MSSQL query, they drop. It doesn't matter if I get to the next page using a header redirect or a form submit. I have two session vars I'm loading from a MYSQL query and they remain, the two loaded from MSSQL disappear. I have confirmed that all four session vars are loading ok initially and I can echo them out to the page, but when the application moves to next page via redirect or form submit, the two vars loaded from MSSQL are empty. Any ideas? I am trying to create a query which reads and uses a previous query which could go on for upto four queries. For example: Query: $carcolour(red), Query: $carmodel(ford), Query: $enginesize(1600), Query: $carlocation(New York) This displays all red cars, which are Ford, which 1600CC, which are located in New York. or Query: $enginesize(1600), Query: $carcolour(red), Query: $carmodel(ford), Query: $carlocation(New York) This displays all 1600CC cars, which red car, which are Ford, which are located in New York. (Same result as above) I have found this guide but Im not sure it what I am looking for. I have also come across the Join function. However this seems to be based on joining two seperate queries. http://www.suite101.com/content/how-tor-run-multiple-mysql-queries-with-php-a105672 Can anyone advise on the best way to create a set of queries which reads and uses the results of the previous query? Good Day Guys
I have a bit of a urgent problem.
Here is my Query:
$query = "SELECT distinct Img.propertyId as PropertyId, Title, ImageUrl, Location, Bedrooms, Bathrooms, Parking, Price FROM PROPERTIES as Prop LEFT JOIN IMAGES as Img ON Img.PropertyId = Prop.PropertyId WHERE 1=1 AND Price >=1000 AND Price <=5000 "; If ($_GET['CODE'] == '2') { $MemId = $_GET['memid']; $CurrentGroupQry = "SELECT * FROM ".MEMBER_PROFILE_TABLE." WHERE user_id='".$MemId."'"; $CurrentGroupRes = mysql_query($CurrentGroupQry, $db); $CurrentGroup = mysql_result($CurrentGroupRes, 0, 'Group'); If ($CurrentGroup == '4') { $UpdateQuery = "UPDATE ".MEMBER_PROFILE_TABLE." SET Group='3' WHERE user_id='".$MemId."';"; $UpdateRes = mysql_query($UpdateQuery, $db); If (!$UpdateRes) { die('Error: Please contact administrator!'); } Echo "Congratulations. You are now fully Registered. Click <a href='./index.php?act=login&CODED=0'>Here</a> to Login.<br><br>"; } Else { Echo "Your Account is already completely Registered.<br><br>"; } } For some reason The script keepts dying and when I check the mysql database I notice that the $UpdateQuery query doesn't actually go through and when I try type it in manually I get a syntax error. Can anyone see that error?? MEMBER_PROFILE_TABLE is a constant containing a table name. Address for this is index.php?CODE=2&memid=X hi , can someone tell me what 's wrong with this query ? Code: [Select] INSERT INTO out( name , section , wo , printer_name , toner_code , quantity , remarks , technician , trainee ) VALUES ('$name','$section','$wo','$printer_name','$toner_code','$quantity', '$remarks','$technician','$trainee') thanks Situation: I have a table that I fill with various types of bugs. Each bug in the table will have an id, name(of a program/script), the bug information, and a resolved column (0 or 1). What I need to be able to do is query the number of bugs that each program has but also query it for each script/program.
I have tried:
SELECT `name`, COUNT(`bug`) AS `bugs` FROM `bugs`but that returns only one row being the first script/program name and the count of all bugs for all scripts/programs. Could someone please advise me where I'm going wrong? Edited by TeddyIso, 22 May 2014 - 12:10 PM. Shouldn't Code: [Select] INSERT INTO `users` (`email`,`password`,`date_of_birth`) VALUES('$EMAIL','xx''xx''xx','$DOB_FULL') Error out because of the 'xx''xx''xx' I'm confused... it puts xx'xx'xx in the password field Not sure whether this belongs in php or javascript seeing as how it deals with both but we'll see what kind of responses I get. I have a dropdown that lists countries and their id from my database and then when the user selects one it sends a post parameter through jquery to a php process page where it matches up the countryid to all the arenas in a table and then here's wehre I'm stuck I already have a dropdown in form like so: Code: [Select] <div class="field required"> <label for="arena">Arenas</label> <select class="dropdown" name="arenas" id="arenas" title="Arenas"> </select> <span class="required-icon tooltip" title="Required field - This field is required, it cannot be blank, and must contain something that is different from emptyness in order to be filled in. ">Required</span> </div> I'm not sure how I should send over the values if I should just pass over the entire dropdown box with the values or just send back the values. Any opinions? I have a query which displays statuses from users:
$result = mysql_query("SELECT * FROM stream ORDER BY stream_id DESC");
while($row = mysql_fetch_array($result)) {
$tha = $row['stream_time'];
$time = strtotime($tha);
echo "<tr><td><b>" . $row['stream_username'] . "</b></tr></td>" . " <tr><td>" . $stream_pp . "</td><td>" . $row['stream_status'] . " " . humanTiming($time) . $msg;
echo "<br></tr></td>";
}
echo "</table>";
I want to get the profile picture of each user, how would I add this code?$query = "SELECT `profile_picture` FROM `users` WHERE `user_username` = '$status_username'"; $result = mysql_query($query) or die($query."<br/><br/>".mysql_error()); $stream_pp = mysql_result($result, 0, 0);By simply just adding it within it only displays one result. Any ideas? Thanks Hi all, I am placing First and Last names together as $name; and Phone and E-mails together, as $contact. $query = "SELECT user.Member,user.First,user.Last,user.Phone,user.Email,user.Type FROM user WHERE ((user.MemberNo LIKE '$MemberNo%') and (user.First LIKE '%$name%') or (user.Last LIKE '%$name%') and (user.Phone LIKE '$contact%') and (user.Email LIKE '$contact%') and (user.Type LIKE '$Type%')) ORDER BY user_stuff.$sort LIMIT $eu, $limit "; $result = mysql_query($query); I use the OR becasue I want to be able to search the "whole" name, first and last. When I run a URL query, it works for name, but everything else (Type, contact, Member)won't filter by URL. If I remove the OR and replace it with AND, everything else works again. Is this something that happens after using OR? (Except for name) Help please? Do I need to separate the query? ~Wayne I tried to search for the answer on google, but it's hard to seach for "and" and "or". Anyway I want this query: Code: [Select] $query = "select * from table where (term1= '$term1' or term2 like '$term2%') and user_id ='$id'"; such that ALWAYS limit the search to the user_id = $id, but search for either term1 or term2. Is the above query correct? Thanks. |
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