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PHP - Help With Getting Users Screen Resolution For Stats Page Using Js And Php
Hey guys,
What im trying to do is get the users screen resolution and place it into a database so that i can call it up and place it onto a stats page. So far i get the idea that you have to use Javascript to get the resolution then use PHP to pull that information. What i want to do is pull the screen resolutions and place them into a database so that i can call upon them to place into a stats page So far i have the following getting certain bits of information and banging them into the database using the stats.inc.php then calling them up and placing them onto stats.php. the stats.inc.php is included on every page of my site so it can track where a users has been etc etc. Im assuming i can insert something into my headerLoggedin.inc.php file that will pull the users resolution then use some PHP in the stats.inc.php script to pull that information and then insert it into my database which i can then easily pull from and place into the stats.php page. I know this seems like a bit of a silly thing to be doing, its for a college assignment and im pretty stumped. Any help is appreciated thanks guys. headerLoggedin.php Code: [Select] <?php include('includes/security.inc.php'); ?> <?php include('includes/stats.inc.php');?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-type" content="text/html; charset=utf-8" /> <meta http-equiv="Content-Language" content="en-us" /> <link rel="stylesheet" href="css/index.css" type="text/css"/> <title>############</title> </head> <body> <!-- Start of wrapper div--> <div id="wrapper"> <!-- Start of header div--> <div id="header"> <div id="logo"><img src="./images/logo.png" width="412" height="32" alt="Elite Recruitment Services" /></div> <div id="navigation"> <ul class="nav"> <li><a href="news.php">News Page</a></li> <li><a href="edit.php">Edit text file</a></li> <li><a href="upload.php">Upload text file</a></li> <li><a href="stats.php">Stats</a></li> <li><a href="logout.php">Logout</a></li> </ul> </div> </div> <!--End of header div--> <!--Start of loginContainer div--> <div id="formsContainer"> stats.inc.php Code: [Select] <?php $db_host = "localhost"; // Databases host name $db_username ="#######"; // Database Username $db_password ="#######"; // Database Password $db_name ="dannymit_stats"; // Databases name $db_table="statTracker"; // Database table where the logins are stored mysql_connect("$db_host", "$db_username", "$db_password"); // Connects to the database using the preset host, username and password mysql_select_db("$db_name"); // Selects the database. //collect information... $browser = $_SERVER['HTTP_USER_AGENT']; // get the browser name $curr_page = $_SERVER['PHP_SELF'];// get page name $ip = $_SERVER['REMOTE_ADDR']; // get the IP address $from_page = $_SERVER['HTTP_REFERER'];// page from which visitor came $page = $_SERVER['PHP_SELF'];//get current page $width = $_GET['width']; //Gets users screen width $height = $_GET[['height']; //Gets users screen height //Insert the data in the table... $query_insert = "INSERT INTO statTracker (browser,ip,thedate_visited,page,from_page) VALUES ('$browser','$ip',now(),'$page','$from_page')" ; $result=mysql_query ( $query_insert); if(!$result){ die(mysql_error()); } ?> stats.php Code: [Select] <?php // Header include include('includes/headerLoggedin.inc.php'); include('includes/stats.inc.php'); ?> <br/><br/> <?php $db_host = "localhost"; // Databases host name $db_username ="######"; // Database Username $db_password ="######"; // Database Password $db_name ="dannymit_stats"; // Databases name $db_table="statTracker"; // Database table where the logins are stored mysql_connect("$db_host", "$db_username", "$db_password"); // Connects to the database using the preset host, username and password mysql_select_db("$db_name"); // Selects the database. $sqlquery = "SELECT * FROM `$db_table`"; $result = mysql_query($sqlquery); $num = mysql_num_rows($result); mysql_close(); while ($row = mysql_fetch_array($result, MYSQL_NUM)) { printf ("Browser:<br/> %s<br/> IP Address:<br/> %s<br/> Date Visited:<br/> %s<br/> Page Visited:<br/> %s<br/> Paged Visited From:<br/> %s<br/>", $row[1], $row[2], $row[3], $row[4], $row[5]); echo "<br />"; } ?> <?php include('includes/footer.inc.php');?> Similar TutorialsI built a Bootstrap site but when I view it on my phone (Samsung Galaxy S3), it doesn't collapse the navigation menu into the mobile button like I thought it would. I did some research and realized that my phone is actually the same resolution as my desktop (1920x1080) so it's giving me the desktop view. Bootstrap, to my surprise, only seems to be responsive to resolutions, not physical screen sizes. How do I overcome this? I want to build a site which is responsive to physical screen size, regardless of resolution.
Edited by DeX, 11 June 2014 - 04:01 PM. Hello PHPers, One more help I think may be wrong. I currently have code as $_GET['width'] . "x" . $_GET['height'];. This provides continually with 640 * 480. believe this to be incorrect as I do not think that everyones screen is set to this. Neither is my screen resolution and is still capturing these figures. Is there something wrong with the variable that should be changed so that it can pick up the visitors screen resolution. Thank you kindly, HJ I have two css external style sheets. One for the 800x600 screen resolution and other for 1200x768. How can I detect the screen resolution and apply the according style sheet using PHP. If I use Javascript, It is possible that the Javascript may not be enable on client side. has some one a better solution? i am creating a responsive website.
I'll give you an example.
I am retriving 100 items from mysql database using php. I am only showing 20 items per page using simple pagination with arrows. I keep this format on desktop and tablets. However, I would like to show less items when I am viewing the page on a smartphone. So instead of 20 items per page, it'll show 5 items per page along with the pagination arrows.
I was wondering if this is possible with PHP or would I have to use javascript?
So, I'm designing a website (who isn't?) and I created the basic framework for a users page from a tutorial I found. Using some previous knowledge I managed to make it display a few custom fields that are defined by the user. Everything works fine as is, but now I want to do a few things to it that I have not the slightest clue how to even begin... Here is my user page code so far... and oh yes I'm using WordPress which is why I made it check manually for page status in my Page.php file. <?php if ( is_page('Users')) { echo "<ul id=\"UsersList\">"; /* First we set how we'll want to sort the user list. You could sort them by: ------------------------ * ID - User ID number. * user_login - User Login name. * user_nicename - User Nice name ( nice version of login name ). * user_email - User Email Address. * user_url - User Website URL. * user_registered - User Registration date. */ $szSort = "user_nicename"; /* Now we build the custom query to get the ID of the users. */ $aUsersID = $wpdb->get_col( $wpdb->prepare("SELECT $wpdb->users.ID FROM $wpdb->users ORDER BY %s ASC", $szSort )); /* Once we have the IDs we loop through them with a Foreach statement. */ foreach ( $aUsersID as $iUserID ) : /* We use get_userdata() function with each ID. */ $user = get_userdata( $iUserID ); /* Here we finally print the details wanted. Check the description of the database tables linked above to see all the fields you can retrieve. To echo a property simply call it with $user->name_of_the_column. */ if($user->user_login != "Unknown") // don't show the placeholder for [unknown] author { echo '<a href="">' . get_avatar( $iUserID, $size = '45', $border='0') . '</a>'; echo '<li>' . ucwords( strtolower( $user->user_login ) ) . '</li>'; if($user->favorite_player != "") { echo '<li>' . $user->favorite_player . '</li>'; } if($user->player_name != "") { echo '<li>' . $user->player_name . '</li>'; } } /* The strtolower and ucwords part is to be sure the full names will all be capitalized. */ endforeach; // end the users loop. echo "</ul>"; }; ?> Problem one: This does NOT sort my name, despite the tutorial's insistence that it will. I have not even a guess as to why this is. Problem two: I would like to either sort this list into two columns or paginate it or both but I am not sure how to do either. Problem three: I want to insert some static text between the echo '<li>' and the . $user->player_name . '</li>'; so that it reads: o Player Name: USER'S VARIABLE ' PLAYER NAME' HERE Yes that 'o' is supposed to be the list item dot. I know how strings work, I just can't get my attempts to work out syntax-wise. Any help would be greatly appreciated! Tutorials, answers, suggestions, examples, anything. The extent of my previous coding knowledge is several years of UnrealScript, so you can see why this simple thing is baffling me. Frankly I'm surprised this much of it works. Afternoon All. I wish to re-direct users to a 404 error page on my site if an article does not exist in my database. Here's my code: $SQL = "SELECT headline FROM news WHERE news_id=".mysql_real_escape_string($_GET['news_id']); $result = mysql_query($SQL) OR die(mysql_error()); $num = mysql_num_rows($result); //** Check that the entry exists otherwise send to error page if ($num > 0) { $row = mysql_fetch_array($result); $headline = $row['headline']; } else { echo "Why is this printed? - I should be leaving this page?"; header("Location: error.php"); exit; } Now the wierd thing is that when I enter a news_id for a value that does not exist it prints the message Why is this printed? - I should be leaving this page? so it's actually going to the ELSE statement which is good, but surely it should not do this as I ask the page to re-direct? Thank you i have a mysql db, i have a form that i use to post data to db. i would like to have visitors to my site be able to post to db as well, but they would have to be registered and have their own profile. when logged in they could see and edit their own space and content that they posted to mysql. how would i go about creating something like this? can someone point me in the right direction ? thank you. I am trying to make a login and direct for my clients. I have all the login stuff working but can't figure out how to redirect specific clients to their pages only. Any help anyone can offer would be great. Code: [Select] <?php //Start session session_start(); //Include database connection details require_once('config.php'); //Array to store validation errors $errmsg_arr = array(); //Validation error flag $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: login-form.php"); exit(); } //Create query $qry="SELECT * FROM members WHERE login='$login' AND passwd='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['member_id']; $_SESSION['SESS_FIRST_NAME'] = $member['firstname']; $_SESSION['SESS_LAST_NAME'] = $member['lastname']; session_write_close(); header("location: member-index.php"); exit(); }else { //Login failed header("location: login-failed.php"); exit(); } }else { die("Query failed"); } ?> Hi, I'm very new to php/mysql, but for a project I'm working on I need to create users that are admins, and normal users. The admins would be able to post news stories, and delete user accounts. Whereas the users would just be able to comment on the news stories. I'm just wondering how I would create a normal 'register' page for both, which has the same fields, but somehow creates some people as admins, and others as normal users... with the ability to limit who can become an admin, so not everyone can register as one. I'm not sure how I would achieve this, or even know how to do it. Does anyone know any tutorials or code on how to achieve this? Your help is greatly appreciated, Thanks. MySQL Version: 5.5.20 (<-- This is my WAMPServer version to test my program, my hosting has 5.1 though) PHP Version: 5.3.10 (My Hosting says its PHP 5 but not sure what version, i know its not the newest) What im trying to do is have my site have a page like "www.mysite.com/data.php?user=Nicholas&country=USA" Thing is, i dont know what to add in my data.php source code to make it work like that. What im trying to achieve is for my users to sign up for my page but I DO NOT want to add my MySQL user and pass in the page where it can be cracked and hacked. When the user goes to the page, a script will automatically put the user and country and then the page will automatically add the user and his country to the MySQL table on my database. Im also making a program that will work like this and that will have a higher chances of being hacked if i add my MySQL info into the program in order to add data. Can someone please provide me of a sample source i can try? I will not only be adding user and country but i want to test this out. Thanks! hi i was wondering how i would make a website that allowed a user to login and edit there website ... like im a hoster and they can have a webpage on my server... how would i do this? allow them to create a database , and use all types of code? please help me this is important , if i didnt explain good enough please tell me Hi, I have a restricted area for my work's company. This is an area where registered users with their own user name and password can access to download technical documents etc. I am hearing some reports that users will have to login twice to get to the area - This happens in Chrome, IE 7/8 and some Firefox's. It has only happened to me once or twice. Does anyone know why this may be? Here is the HTML code from the login form on the index page: Code: [Select] <form name="login_form" method="post" action="log.php?action=login"> <p>Login:<br /> <input type="text" name="user" /> </p> <p>Password: <br /><input type="password" name="pwd" /> </p> <p class="submit"> <input type="submit" value="Submit" name="submit" class="submit" /> </p> </form> Here is the log.php File: (personal connection details edited) Code: [Select] <?php $hostname = "IP:3306"; $username = "user"; $password = "password"; $database = "db_name"; $link = MYSQL_CONNECT($hostname,$username,$password); mysql_select_db($database); ?> <?php session_name("MyWebsiteLogin"); session_start(); if($_GET['action'] == "login") { $conn = mysql_connect("IP:3306","user","password"); $db = mysql_select_db("db_name"); //Your database name goes in this field. $name = $_POST['user']; $ip=$_SERVER['REMOTE_ADDR']; $country = file_get_contents('http://api.hostip.info/country.php?ip='.$ip); $q_user = mysql_query("SELECT * FROM customer WHERE username='$name'"); ?> <?php $insert_query = ("INSERT INTO login(username, ip, country) VALUES ('$name','$ip','$country');"); mysql_query($insert_query) or die('Error, insert query failed'); ?> <?php if(mysql_num_rows($q_user) == 1) { $query = mysql_query("SELECT * FROM customer WHERE username='$name'"); $data = mysql_fetch_array($query); if($_POST['pwd'] == $data['password']) { session_register("name"); header("Location: http://#/download/index.php?un=$name"); // This is the page that you want to open if the user successfully logs in to your website. exit; } else { header("Location: login.php?login=failed&cause=".urlencode('Wrong Password')); exit; } } else { header("Location: login.php?login=failed&cause=".urlencode('Invalid User')); exit; } } ?> Any help or ideas would be greatly appreciated. I have a Yahtzee system Code: [Select] session_start(); $_SESSION['Yahtzee']['totaltime'] =time(); echo $_SESSION['Yahtzee']['totaltime']; Now, Long STORY Short when somone finishes playing the Yahtzee, I update there username with the score they had, and I want to update how long they have been playing, and it will be for "Total Time Playing globally" no matter how many games. If I do this session and echo it out, it echo's out the time, but I need it to echo out seconds instead so I can just add that to my totaltime field in my database each time they finished a game. Hello all...fairly new to this php/mysql thing... working on my final project thats due in about 24 hours... and i hit a rut... im making a pretty basic, online classifieds site. users can sign up, login, post new listings and view others listings by clicking on different categories. the problem i am having right now is this...When the user clicks on "My listings" i need it to pull only the listings that were created by that users user_id, which is the primary key in my user_info table...my professor suggested storing it in hidden field through the login submit button...very confused and frustrated... any help is much appreciated... Hi there, I have updated a webpage and it appears that some users are still seeing the older version of the page. Is there a way I can force the user's version of the page to display the latest content on the page? I have see I can add some meta tags which control the cache, but my site relies quite heavily on cookies, so I guess clearing the cache would reset/have an effect on the cookies? Does anyone have any ideas on how I can make users always see the latest content? Thanks! Hi! I have read like crazy to find a tutorial on a login page without My_SQL. Anyway I am working on a easy login/logged out page with sessions. Here is the login page with tree users in an array.
The things that I need some hints to solve is, when clicking on login the error message don't show. Instead the script goes to the logged in page right away. And when you write the wrong password you get loged in anyway.
I am not sure how or if it's possible to write a varible to a file this way. But I tried and recived a parse error with the txt varible.
When searching for topics I get more confused with the My_SQL varibles. I am near a breaking point at cracking the first step on PHP, but need some advice.
<?php
$page_title = 'Logged in'; //Dynamic title
include('C:/wamp/www/PHP/includes/header.html');
?>
<?php
session_start();
//A array for the sites users with passwords
$users = array(
'Dexter'=>'meow1',
'Garfield'=>'meow2',
'Miro'=>'meow3'
);
//A handle to save the varible users to file on a new line from the last entry
$handle = fopen("newusers.txt, \n\r")
$txt = $users;
fclose($handle);
if(isset($_GET['logout'])) {
$_SESSION['username'] = '';
header('Location: ' . $_SERVER['PHP_SELF']);
}
if(isset($_POST['username'])) {
if($users[$_POST['username']] == $_POST['password']) {
$_SESSION['username'] = $_POST['username'];
}else {
echo "Something went wrong, Please try again";
}
}
?>
<?php
echo "<h3>Login</h3>";
echo "<br />";
?>
<!--A legend form to login-->
<fieldset><legend>Fill in your username and password</legend>
<form name="login" action="777log.php" method="post">
Username: <br />
<input type="text" name="username" value="" /><br />
Password: <br />
<input type="password" name="password" value="" /><br />
<br />
<input type="submit" name="submit" value="Login" />
</fieldset>
</form>
<?php //Footer include file
include('C:/wamp/www/PHP/includes/footer.html');
?>
The logged in page
<?php //Header
$page_title = 'Reading a file';
include('C:/wamp/www/PHP/includes/header.html');
?>
<?php
session_start();
//Use an array forthe sites users
$users = array(
'Dexter'=>'meow1',
'Garfield'=>'meow2',
'Miro'=>'meow3'
);
//
if(isset($_GET['logout'])) {
$_SESSION['username'] = '';
echo "You are now loged out";
//The user is loged out and returned to the login page
header('Location: ' . $_SERVER['PHP_SELF']);
}
if(isset($_POST['username'])) {
//Something goes wrong here when login without any boxes filled
if($users[$_POST['username']] == $_POST['password']) {
$_SESSION['username'] = $_POST['username'];
}else {
echo "Something went wrong, Please try again";
$redirect = "Location: 777.php";
}
}
?>
<?php if($_SESSION['username']): ?>
<p><h2>Welcome <?=$_SESSION['username']?></h2></p>
<p align="right"><a href="777.php">Logga ut</a></p><?php endif; ?>
<p>Today Ben&Jerrys Chunky Monkey is my favorite!</p>
<?php //Footer
include('C:/wamp/www/PHP/includes/footer.html');
?>
Hello
I am trying to work out how many regular users I have to my site and how long those users tend to be users..
So, I have a table that logs every time a user visits my site and logs in, it stores the date / time as a unix timestamp and it logs their user id.
I started by getting the id's of any user who logs in more than 5 times in a specified period, but now I want to extend that...
SELECT userID as user, count(userID) as logins FROM login_history where timestamp > UNIX_TIMESTAMP('2014-06-01 00:00:00') and timestamp < UNIX_TIMESTAMP('2014-07-01 00:00:00') group by user having logins > 5;
Hi,
I am trying to make a page where the footer is loaded according to the screen size, so if someone is accessing the website via a tablet will be a footer, if it is from the computer, there will be another footer.
my problem is that although it is recognizing the windows width, it is not changing the footer accordingly.
this is my code:
$width = "<script>document.write(window.innerWidth);</script>";
if ($width < 900)
{
include("footer_mobile.php");
}
else
{
include("footer.php");
}
for some reason it is always loading the else footer even though the windows with changes.
I added echo"$width" ; and the result of the variable was fine.
does anyone know what the problem is cause it is driving me crazy?For my site I need to screenscrape a page on a site. The problem is, to access the page that contains the data I need, I have to login to my account first. I know there are ways to simulate a form submission with ASP, but my server is Linux and can't use ASP. I'm wondering if any of you know how I would be able to simulate a POST with something like cURL? And possibly write an example script? Thanks in advance. (This may be in the wrong section, please move it if it is. Thanks) Hello i whant to creat stats page for my website can sombady help me how can SELECT database id |user_id | site_id | date 1 | 2222 | 18 | 2011-11-28 06:10:06 select id COUNT(site_id ) from table WHERE date = ? i whant to select last 7 days from database and count site_id per day . |
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