PHP - Unexpected T-string!!

I have the following function, which takes a string with commas in it and attempts remove those commas. The way I have it here is that I use explode to take out the commas, which makes an array, and then iterate through that array to put a string back together without the commas.

function tags_to_sort_by( $sortMeta ) {      
   $sortByArray = explode(",", $sortMeta);
   $sortByCount = count($sortByArray);
   for ($i = 0; $i < $sortByCount; $i++) {
      $sortByString += $sortByArray[$i];
   }
   return $sortByString;
}

What does not work is the following line:
$sortByString += $sortByArray[$i];
Somehow that outputs a 0, which I don't understand. It should output something like: arrayItem1 arrayItem2 array3 etc.

My question is if there either is an easier way to remove the commas from the original string or what I am doing wrong in this line:
$sortByString += $sortByArray[$i];  // I am trying to concatenate each part of the array back into the string.

Thanks a lot for help with this!

hey guys im trying to find a string inside a string which could be made up of different things eg...

{$test}, {$test1}, {$test2}   
etc (but the varable inside could be called anything hence maybe using regex im not sure?)
is this possible?...i hope you guys understand....thanks

In PHP Version 8.0 shows error as :
PHP Fatal error:  Uncaught TypeError: Unsupported operand types: string * string 
String is as under :
$TAXVALUE= round($QNTY*($PRICE- ($PRICE*$DISC/100)),2);

In previous versions of PHP it does not show any error.

Please resolve the issue.

Hello guys i am trying to figure out how to fwrite a string for example "Recommended Settings for Service Pack" under "Current Settings for Service Pack: 5.1.2600ServicePack3Build2600". I figure i cant use line number as an argument because the file report may be dynamic so i will need to use Current Settings as an argument. Please guide me if you have any ideas..thanks:) !

auditreport 
table
ServicePackSetting
Service Pack Requirement: Fail
Current Settings for Service Pack: 5.1.2600ServicePack3Build2600   
MajorAuditandAccountPolicies   
Maximum Password Age Requirement: Fail
Current Settings for Maximum Password Age Requirement: 42   
Minimum Password Length: Fail
Current Settings for Minimum Password Length Requirement: 0

Ok... I had typed this post out ONCE already and when I clicked REFRESH IMAGE to get a diff captcha it ERASED MY POST

LMAO this is not my night....


What I need help with is probably more simple then I can even think right now - ive been digging at this for 3 hrs now and im out of time for the night

I have a DB Record storing ID's between PIPES |

when the initial entry is made in DB it stores it like so
|47|      NOTE: the number could be different these are ID's number doesnt matter its just between Pipes

When the second entry is added its added like so

|47||67|

say we have a total of 5 Entries

|47||67||82||55||69|

I need to find ID 82 in that string and it has to be between Pipes
Find 82 in data between | and return that ID 82

I am putting between pipes because the ID's can be duplicate digits in different lengths
so say I have 8 as my ID and down the string i have another id as 88  -- I cant possibly find the correct ID without some sort of seperation character so i used Pipes

soo my end goal is the ability to search and if true or false do action

if ($result == $find_id){
echo "ID is there";
}else{
echo "NOT THERE -- Adding it";
}
Any help is appreciated guys
Thanks
SangrelX

I need to know if a string exists within a string.

I've tried using STRIPOS() but it returns zero or false if what I'm looking for is the first part of the string.

I don't care what function I use, but I need to get a "true" when the needle string is present anywhere in the haystack string, even at location zero.

Is there some way to set up the STRIPOS() statement?

I've tried:


if ((stripos($title, 'needle') > 0 )
if ((stripos($title, 'needle') = true )
and even
if ((stripos($title, 'needle') >= 0 )
which returns true for everything, even when the needle string is NOT present.

Any help appreciated.

thanks,
Tom

I am looking for a date within larger string, lets say the date is December 4, 2010.
To find it I use pattern and function below:

$Pattern='/[(January|February|March|April|May|June|July|August|September|October|November|December)] \d, \d\d\d\d/i';
preg_match_all($Pattern, $String, $Matches, PREG_OFFSET_CAPTURE, $NumberPosition);

The function finds the dates within the string but to my supprise the result I get in $Matches is: r 4, 2010
What I would like to get is: December 4, 2010 but don't know how it should be fixed. I thought that with the pattern I am using but obviously that is not the case.

Just trying to do a basic query... not working and don't know why:

here is inserts.php:

<?php

$username="wormste1_barry";
$password="barry";
$database="wormste1_barry";

$CarName=$_POST['CarName'];
$CarTitle=$_POST['CarTitle'];
$CarPrice=$_POST['CarPrice'];
$CarMiles=$_POST['CarMiles'];
$CarDescription=$_POST['CarDescription'];

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");

$query = "INSERT INTO tablename VALUES
('','$CarName','$CarTitle','$CarPrice','$CarMiles','$CarDescription');

mysql_query($query);

mysql_close();

?>

That parses the simple form of :

form.html:

<HTML>

<HEAD>

</HEAD>

<BODY>


<form action="inserts.php" method="post">
car Name: <input type="text" name="CarName"><br>
Car Title: <input type="text" name="CarTitle"><br>
Car Price: <input type="text" name="CarPrice"><br>
Car Miles: <input type="text" name="CarMiles"><br>
Car Description: <input type="text" name="CarDescription"><br>
<input type="Submit">
</form>

</BODY>

</HTML>

I get the error: Parse error: syntax error, unexpected $end in /home/wormste1/public_html/tilburywebdesign/shop/FTPServers/barryottley/showroom/inserts.php on line 23

Don't know whats wrong?

I know this is probably a missing curly bracket or some other syntax, but I can't seem to spot it, anyone see it? i get this error btw.

Parse error: syntax error, unexpected $end in C:\Program Files\xampp\htdocs\cameo\login.php on line 39

<?php
session_start();
//sql variables
$server = "localhost";
$user = "root";
$pass = "";
$db = "cameo";

//iff user isn't logged in, try to log them in
if(!isset($_SESSION['username'])){
  if(isset($_POST['submit'])){
    //connect to database
      $dbc = mysqli_connect($server, $user, $pass, $db);
    
    //grab entered form data
    $user_username = mysqli_real_escape_string($dbc, trim($_POST['username']));
    $user_password = mysqli_real_escape_string($dbc, trim($_POST['username']));
     
    //if both username and password are entered then find a match in the database
    if((!empty($user_username)) && (!empty($user_password))) {
     //look up the username and password in the database
      $query = "SELECT username FROM cameo WHERE username = '$user_username' AND '$user_password'";
      $data = mysqli_query($dbc, $query);
    
     //authenticate if data matches a row
     if(mysqli_num_rows($data) == 1){
        //login is okay
       $row = mysqli_fetch_array($data);
       $_SESSION['username'] = $row['username'];
       $_SESSION['is_admin'] = $row['is_admin'];
       header('Location:index.php');
 }
  else {
    //username and password are incorrect or missing, so send a message
   $error_msg = 'Sorry, you must enter a valid username and password to log in.';
  }
}
}
?>

Hi, could someone please tell me why I'm getting an unexpected { error in the following code.  I have went over it several times and everything seems to be matching. 

Code: [Select]
<?php
require_once("functions.php"); 
?> 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>

<body>
<?php 
DatabaseConnection();  

$query= "SELECT * FROM treats";
$result_set= mysql_query($query);
/*if( $result_set = mysql_query($query) ) {

while( $products = mysql_fetch_row($result_set) ) {
     echo $products[0];
     echo $products[1]; 
     echo $products[2];
     echo $products[3]; 
     echo $products[4];  
     echo "<img src=\"{$products[5]}\">"; // assuming this is where the image url is
     }
}
//print_r(mysql_fetch_row($result_set));*/
$output = "<table>";
while($row = mysql_fetch_array($result)) 
{
$productDetail1['product_id']; 
$productDetail2['product_title']; 
$productDetail3['product_Description']; 
$productDetail4['price']; 
$productDetail5['product_pic'];  
$output .= (" 
<tr>
<td>".$productDetail1['product_id'] ."</td>  
</tr>
") 
}
$output .= "</table>";
?>   
</body>
</html>

Hi, could someone please tell me why I'm getting unexpected $end  error in the following code? 

<?php
function documentType(){
echo <<<HEREDOC
<?xml version="1.0" encoding="UTF-8"?>   
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"              `              `     "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>   
   }
HEREDOC;
?>

Am I blind? I don't see the problem with this code. It says:

Parse error: syntax error, unexpected '}' in /data/21/2/40/160/2040975/user/2235577/htdocs/edit_user1.php on line 35


Code: [Select]



<html>
<body>

<?php


if ( (isset($_GET['id'])) && (is_numeric($_GET['id'])) ) {

$id = $_GET['id'];

} elseif ( (isset($_POST['id'])) && (is_numeric($_POST['id'])) ) {

$id = $_POST['id'];

} else {

echo 'you have reached this page in error. no variable passed';
exit();
}

// that was the part to check for passed variables. This is what does something with it

require ('databaseconnect.php');

if (isset($_POST['submitted'])) {

$errors = array();

}

if (empty($_POST['scientific name'])) {

$errors[] = 'you did not enter a scientific name'

} else {

$sn = escape_data($_POST['scientific_name']);

}

// now the common name

if (empty($_POST['common_name_english'])) {

$errors[] = 'you did not enter a common name'

} else {

$cn = escape_data($_POST['scientific_name_english']);
}

// now make changes

if (empty($errors)) {

$query = "UPDATE table SET plant_name='$id', scientific_name='$sn', common_name_english='$cn' WHERE plant_name=$id";


$result = $mysql_query ($query);
if (mysql_affected_row() == 1) {

echo 'edit a plant<br>
The plant has edited'
} else {
echo 'system error<br>
the plant could not be edited due to a system error.';

echo mysql_error() . 'query:' . $query ;
exit();
}

} else {

echo 'error<br>
something already insystem or did not work.';

}

} else {

echo 'error<br>';
foreach ($errors as $msg) {

echo " - $msg<br>";

}
echo ' please try again';

} // end of if
} //  endo of submit condition
 // always show form

$query = "SELECT scientific_name, Common_name_english FROM table WHERE plant_name=$id";

$result = $mysql_query ($query); 

if(mysql_num_rows($result) == 1) {

$row mysql fetch_array ($result);

echo 'edit a user'

<form action="edit_user1.php" method="post">
scientific name: <input type="text" name="scientific_name" size="45" value="'
. $row[scientific_name] . '"><br>
common name: <input type="text" name="common_name_english" size="45" value="'
. $row[common_name_english] . '"><br>

<input type="submit" name="submit" value="submit" /><br>
<input type="hidden" name="submitted" value="TRUE" />
<input type="hidden" name="id" value="' . $id . '"/>
</form>';

} else { 
echo 'page error';

}

mysql_close();

</body>
</html>

hello i keep getting an error Parse error: syntax error, unexpected $end in /home/cookbook/public_html/cookbook.php on line 144 can someplease explain it to me? here is the code

[list type=decimal]
[li][/li]
[li][/li]
[/list]<?php
//include("include/session.php");
@session_start();
// Start_session, check if user is logged in or not, and connect to the database all in one included file
include_once("scripts/checkuserlog.php");
// Include the class files for auto making links out of full URLs and for Time Ago date formatting
include_once("wi_class_files/autoMakeLinks.php");
include_once ("wi_class_files/agoTimeFormat.php");
// Create the two objects before we can use them below in this script
$activeLinkObject = new autoActiveLink;
$myObject = new convertToAgo;
?>
<?php
// Include this script for random member display on home page
include_once "scripts/homePage_randomMembers.php"; 
?>
<?php
$sql_blabs = mysql_query("SELECT id, mem_id, the_blab, blab_date FROM blabbing ORDER BY blab_date DESC LIMIT 30");

$blabberDisplayList = ""; // Initialize the variable here

while($row = mysql_fetch_array($sql_blabs)){

$blabid = $row["id"];

$uid = $row["mem_id"];

$the_blab = $row["the_blab"];

$notokinarray = array("fag", "gay", "shit", "fuck", "stupid", "idiot", "asshole", "cunt", "douche");
    $okinarray   = array("sorcerer", "grey", "shug", "farg", "smart", "awesome guy", "asshole", "cake", "dude");

$the_blab = str_replace($notokinarray, $okinarray, $the_blab);

$the_blab = ($activeLinkObject -> makeActiveLink($the_blab));

$blab_date = $row["blab_date"];

$convertedTime = ($myObject -> convert_datetime($blab_date));
    $whenBlab = ($myObject -> makeAgo($convertedTime));

//$blab_date = strftime("%b %d, %Y %I:%M:%S %p", strtotime($blab_date));

// Inner sql query

$sql_mem_data = mysql_query("SELECT id, username, firstname, lastname FROM myMembers WHERE id='$uid' LIMIT 1");

//die($sql_mem_data);

while($row = mysql_fetch_array($sql_mem_data)){

$uid = $row["id"];

$username = $row["username"];

$firstname = $row["firstname"];

if ($firstname != "") {$username = $firstname; } // (I added usernames late in  my system, this line is not needed for you)

///////  Mechanism to Display Pic. See if they have uploaded a pic or not  //////////////////////////

$ucheck_pic = "members/$uid/image01.jpg";

$udefault_pic = "members/0/image01.jpg";

if (file_exists($ucheck_pic)) {

$blabber_pic = '<div style="overflow:hidden; width:40px; height:40px;"><img src="' . $ucheck_pic . '" width="40px" border="0" /></div>'; // forces picture to be 100px wide and no more

} else {

$blabber_pic = "<img src=\"$udefault_pic\" width=\"40px\" height=\"40px\" border=\"0\" />"; // forces default picture to be 100px wide and no more

}

$blabberDisplayList .= '
      

<table width="100%" align="center" cellpadding="4" bgcolor="#CCCCCC">
        <tr>
          <td width="7%" bgcolor="#FFFFFF" valign="top"><a href="profile.php?id=' . $uid . '">' . $blabber_pic . '</a>
          </td>
          <td width="93%" bgcolor="#EFEFEF" style="line-height:1.5em;" valign="top"><span class="greenColor textsize10">' . $whenBlab . ' <a href="profile.php?id=' . $uid . '">' . $username . '</a> said: </span><br />
          ' . $the_blab . '</td>
        </tr>
      </table>';

}

}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
  <head>
    <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" />
    <meta name="Description" content="Web Intersect is a deft combination of powerful free open source software for social networking, mixed with insider guidance and tutorials as to how it is made at its core for maximum adaptability. The goal is to give you a free website system that has a network or community integrated into it to allow people to join and interact with your website when you have the need." />
    <meta name="Keywords" content="web intersect, how to build community, build social network, how to build website, learn free online, php and mysql, internet crossroads, directory, friend, business, update, profile, connect, all, website, blog, social network, connecting people, youtube, myspace, facebook, twitter, dynamic, portal, community, technical, expert, professional, personal, find, school, build, join, combine, marketing, optimization, spider, search, engine, seo, script" />
    <title>CookBookers</title>
    <link href="style/main.css" rel="stylesheet" type="text/css" />
    <link rel="icon" href="favicon.ico" type="image/x-icon" />
    <link rel="shortcut icon" href="favicon.ico" type="image/x-icon" />
    <script src="js/jquery-1.4.2.js" type="text/javascript"></script>
<style type="text/css">
#Layer1 {

height:210px;

background-image: url(images/top_container_bg_recipes_new.gif);
}
body {

background-color: #3c60a4;
}
</style>
</head>
<body>
<?php include_once "header_template.php"; ?>
<center>
  <table cellpadding="0px" cellspacing="0px" style="border:0px solid #666666;" width="950">
    <tr>
      <td>
        <table width="95%" height="22" border="0" align="center" cellpadding="10" cellspacing="0" style="background-color:#F2F2F2; border:0px solid #666666;">
          <tr>
            <td style="padding-left:45px;">
<?php
//die($_SESSION['username']);
$qryUsers = "SELECT * from recipies WHERE user='".$_SESSION['username']."'";
//die($qryUsers);
$rsUsers = @mysql_query($qryUsers) or die(mysql_error());
?>
<table width="100%"  border="0" cellspacing="0" cellpadding="0">
  <tr>
    <td width="16%"><h3>All Recipies of </h3></td>
    <td width="84%"><h3><?php print $_SESSION['username']; ?></h3></td>
  </tr>
  <tr>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
  </tr>
</table>
<?php
while($rowUsers = @mysql_fetch_object($rsUsers))
{
?>

<?php
print"<h3>Public Recipes</h3><br>";
$qryUsers = "SELECT * from recipies WHERE user='".$_SESSION['username']."'";
print"<ol>";
$rsUsers = @mysql_query($qryUsers) or die(mysql_error());

if( @mysql_num_rows($rsUsers)>0 )

{

while($rowUsers = @mysql_fetch_object($rsUsers) )

{

 print "<li style='margin:5px 0px;'><a href=description.php?Rid=".$rowUsers->Rid.">".$rowUsers->title."</a></li>";

 

}

}
print"</ol>";



?>
</td>
          </tr>
        </table>      </td>
    </tr>
   <tr>
     </td>
   </tr>
  </table>
  </center>
  <?php include_once "footer_template.php"; ?>
</body>
</html>

 hey guys just a simple one...im trying to replace {$name}  but i dont think ive got the right prefix in the str_replace function...if anyone could tell me where i am going wrong please

$content = str_replace("{/$".$variable."}", $value, $content);
{$name}