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PHP - Simple Html & Css To Pdf Script
Hiya!
I need to create a simple PDF script that will always create A4 documents. I need the content to be controlled using HTML and CSS. Where do you start in creating such a script? Any help is greatly received. Similar TutorialsHello, im very green to php and I am having trouble creating a simple log in script. Not sure why this is not working, maybe a mysql_query mistake? I am not receiving any errors but nothing gets updated in the members table and my error message to the user displays. any help is appreciated! here is my php: <?php session_start(); $errorMsg = ''; $email = ''; $pass = ''; if (isset($_POST['email'])) { $email = ($_POST['email']); $pass = ($_POST['password']); $email = stripslashes($email); $pass = stripslashes($pass); $email = strip_tags($email); $pass = strip_tags($pass); if ((!$email) || (!$pass)) { $errorMsg = '<font color="#FF0000">Please fill in both fields</font>'; }else { include 'scripts/connect_db.php'; $email = mysql_real_escape_string ($email); $pass = md5($pass); $sql = mysql_query("SELECT * FROM members WHERE email='$email' AND password='$pass'"); $log_check = mysql_num_rows($sql); if ($log_check > 0) { while($row = mysql_fetch_array($sql)) { $id = $row["id"]; $_SESSION['id']; $email = $row["email"]; $_SESSION['email']; $username = $row["username"]; $_session['username']; mysql_query("UPDATE members SET last_logged=now() WHERE id='$id' LIMIT 1"); }//Close while loop echo "You are logged in"; exit(); } else { $errorMsg = '<font color="#FF0000">Incorrect login data, please try again</font>'; } } } ?> and the form: <?php echo $errorMsg; ?> <form action="log_in.php" method="post"> Email:<br /> <input name="email" type="text" /><br /><br /> Password:<br /> <input name="password" type="password" /><br /><br /> <input name="myBtn" type="submit" value="Log In" /> </form> Hi everyone, I'm trying to select either a class or an id using PHP Simple HTML DOM Parser with absolutely no luck. My example is very simple and seems to comply to the examples given in the manual(http://simplehtmldom.sourceforge.net/manual.htm) but it just wont work, it's driving me up the wall. Here is my example: http://schulnetz.nibis.de/db/schulen/schule.php?schulnr=94468&lschb= I think the HTML is invalid: i cannot parse it. Well i need more examples - probly i have overseen something! If anybody has a working example of Simple-html-dom-parser...i would be happy. The examples on the developersite are not very helpful. your dilbertone Hi can someone pls help, im tryin a tutorial but keep getting errors, this is the first one i get after registering. You Are Registered And Can Now Login Warning: Cannot modify header information - headers already sent by (output started at /home/aretheyh/public_html/nealeweb.com/regcheck.php:43) in /home/aretheyh/public_html/nealeweb.com/regcheck.php on line 46
require_once 'phpSimpleHtmlDomClass.php'; $html = '<div> <div class="man">Name: madac</div> <div class="man">Age: 18 <div class="man">Class: 12</div> </div>' $name=$html->find('div[class="man"]', 0)->innertext; $age=$html->find('div[class="man"]', 1)->innertext; $cls=$html->find('div[class="man"]', 2)->innertext;
wanna get a text from each div class="man" but it didn't work because there is a missing closing div tag on 2nd line of html code. please help me to fix this. thanks in advance. <html> <head></head> <body> My favourite bands a <ul> <?php // define arrays $morebands = array('Desturbed', 'Anthrax'); $artists = array('Metallica', 'Evanescence', 'Linkin Park', 'Guns n Roses', "$morebands"); // loop over it // print array elements foreach ($artists as $a) { if ($a != 'Array'){ echo '<li>'.$a; } Else { foreach ("${$a}" as $b){ echo '<li>'.$b; } } } ?> </ul> </body> </html> I can not figure out why this will not work:( I would like the foreach to run through the array as normal, but if it encounters a nested array, loop it as well. I know this likely is not the right, or best way to do this, but I am just learning PHP through a tutorial and I learn best by doing... So I take the lessons, make them more complicated, then figure out how to make it happen (like so). right now I am working on http://devzone.zend.com/node/view/id/635 anyhow thanks for any help! There is a sql query happening if the item is not empty, what I NEED and can not seem to figure out is to re run the rand() function. The server is PHP 4 so it is not possible to use the goto statement... That would be to easy. So any help would be great... Here is the code... the script running after the script finds a empty sql row is ot included... it works... just this one part does not. Code: [Select] <?php $connection = mysql_connect(CREDENTIALS REMOVED) or die(mysql_error()); mysql_select_db("testingblock", $connection)or die(mysql_error()); $random_num = rand(1,10); if($random_num == 1){ $query = sprintf("SELECT email FROM access_codes WHERE id='1'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 2){ $query = sprintf("SELECT email FROM access_codes WHERE id='2'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 3){ $query = sprintf("SELECT email FROM access_codes WHERE id='3'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 4){ $query = sprintf("SELECT email FROM access_codes WHERE id='4'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); echo '<br />'; if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 5){ $query = sprintf("SELECT email FROM access_codes WHERE id='5'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 6){ $query = sprintf("SELECT email FROM access_codes WHERE id='6'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if($random_num == 7){ $query = sprintf("SELECT email FROM access_codes WHERE id='7'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 8){ $query = sprintf("SELECT email FROM access_codes WHERE id='8'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 9){ $query = sprintf("SELECT email FROM access_codes WHERE id='9'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); echo '<br />'; if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 10){ $query = sprintf("SELECT email FROM access_codes WHERE id='10'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } ?> [icode] I've tried Googling this for a long time but I only find complete member systems with ugly code, not something i'm looking for. What I am looking for is just a simple tutorial or commented code to make a admin login. What it's going to do is just: Loading a MD5 salt hasched password from my MYSQL database. You'll get to fill in one field: Password. If it validates with the MYSQL password it'll show the hidden content; if not it'll just give a "not correct error". That's basicly it. I have only one page of secret admin stuff so yeah.. it would be awesome to have the ability to logout and I of curse want to have everything in sessions! It would be to big help! Can someone show me a simple mail script that I can run in cli, I can enter a $to = email@email.com and then have it send to my email? just in cli.. Thanks Good evening guys and gals, for some reason I cant get my head around something quite simple, basically I am trying to work out a way of simply recording referrals to my site when the potential user registers. This worded example is basically what I want: registered user a with a username of smithy invites his friend western to become a member of a site he has joined: I guess here I would basically use something like mysite.com?refid=smithy as the link he gives he's friend Now this is where my brain refuses to work, what if western decides to have a look around the site before he decides to register and clicks on a few internal pages? Obviously the referral id will no longer be in the address bar. So my 1st question is, how can I check to see if a referral is used when accessing the site? I could then store the username in a session or cookie. If I had something like this: <?php $refid = $_GET('refid') setcookie("user", $refid, time()+3600); ?> But how would I check that a refid exists in the url so it doesnt throw up a parse error? I have more questions but 1 thing at a time! Many Thanks Hi all, Im coding a simple script for my website which just changes the users rank. Code: [Select] <?php session_start(); include "../includes/db_connect.php"; include "../includes/functions.php"; logincheck(); ini_set ('display_errors', 1); error_reporting (E_ALL); $username=$_SESSION['username']; $get = mysql_query ("SELECT * FROM users WHERE username = '$username'"); $fetch = mysql_fetch_object($get); if ($fetch->userlevel >= "2"){ $newrank = $_POST['newrank']; $user1 = $_POST['user']; if (strip_tags($_POST['update'])){ mysql_query("UPDATE users SET `rank` = '$newrank' WHERE username='$user1'") or die (mysql_error()); echo ("You have updated $user1's rank to $newrank !"); } } else{ echo ("Your userlevel isnt high enouth to be here!"); } ?> <html> <head> <title>Change Rank</title> <link rel="stylesheet" href="../includes/in.css" type="text/css"> <style type="text/css"> .infobg { font-family: Arial; font-weight:normal; font-size:12px; border-top: 1px solid #000000; border-right: 1px solid #000000; border-bottom: 1px solid #000000; border-left: 1px solid #000000; background: URL(textbg1.png); font-weight:300; } .button { font-size: 12px; background:url(button.png); vertical-align: middle; border-top: 1px solid #000000; border-right: 1px solid #000000; border-bottom: 1px solid #000000; border-left: 1px solid #000000; color: #FFFFCC; height:23px; font-weight:300; border-radius: 10px; padding-bottom:2px; } </style> </head> <body> <form action='' method='post' name='form1'> <table width='30%' cellpadding='0' align='center' cellspacing='0' border='1' bordercolor='#000000' bgcolor='#808080' style='border-collapse: collapse'> <tr> <td background='../header.jpg' colspan='2' align='center'>Change Rank</td> <tr> <td>Username:</td><td><input type='text' name='user'></td> </tr> <tr> <td>Rank:</td><td><input type='text' name='newrank'></td> </tr> <tr> <td> </td><td><input type="submit" name="update" value="Update Rank"></td> </tr> </form> </table> </body> </html> But there seems to be something wrong with that code, which I carnt see or work out. When I click Update submit button it does nothing, but can anyone see why it does nothing? Thanks. I was told that you guys could probably help me with this, so heres my situation. I use this program called Activeworlds, and me and my buddies are makeing a "tv show" if you will within the program. To do so, you take screenshots, save the screenshots, and add the image files into a directory on your domain. You need a .php script to present them as a slideshow. Now the problem is, ive searched for scripts already made from other sites, but the thing is, they are all fancy slideshow viewers, meaning they come with control buttons to cycle through the pictures and all kinds of other banners and flashy looking things. The only script im needing, is a simple script that will display and cycle through the raw images, and nothing else, within the web browser, in a slideshow format. Id also like to have a value I can edit that will change how fast the pictures cycle through, 15 seconds or so would be perfect however. If someone could refer me to this code or even make it for me, it would be soo appreciated. I know im probably asking for alot, but it would help me soo much. I wish I knew a little more about .php files to do it myself, or else I would. If you do link me to a script, please give me simple instructions on what to do with it lol because like I said, I dont know anything about the world of .php yet. Thank you all for your time. The attached script does everything I want it to do, but it's not very elegant. I could use some help cleaning it up. Any and all help is greatly appreciated. Thanks!!! I'm very new to PhP and one of my asignments in class is to create a simple login using php and mysql. I made a simple page using html, php, and mysql and i keep getting errors. Here is my code so far: This is my index.php page: <html> <form action = 'login.php' method='POST'> Username: <input type='text' name='username'><br> Password: <input type='password' name='password'><br> <input type='submit' value='Log in'> </form> </html> This is my login.php page: <?php $username = $_POST['username']; $password = $_POST['password']; if ($username&&$password) { &connect = mysql_connect("localhost", "root", " ") or die ("Couldnt connect"); mysql_selct_db("phplogin") or die("Couldn't find db"); } else die ("Please enter a username and password"); ?> mySql file is very basic: 3 columns, id, username, password I dont think my problem is with the mySQL page that was the easiest to make but everytime I hit login in the index.php, the entire script for login.php gets outputted on screen. I would appreciate all the help. If you look at the botton of http://getminecraft.net/ you see my latest tweets. The problem is that it shows http://getminecraft.net/%22http://twitter.com/PC_Gamer%22 instead of the original twitter url, that results to a wrong url and wrong site. How can I fix it? so it shows the original twitter url. Here is the script: <?php $username = "getminecraft"; $prefix = ""; $suffix = ""; $feed = "http://search.twitter.com/search.atom?q=from:" . $username . "&rpp=1"; function parse_feed($feed) { $stepOne = explode("<content type=\"html\">", $feed); $stepTwo = explode("</content>", $stepOne[1]); $tweet = $stepTwo[0]; $tweet = str_replace("<", "<", $tweet); $tweet = str_replace(">", ">", $tweet); return $tweet; } $twitterFeed = file_get_contents($feed); echo stripslashes($prefix) . parse_feed($twitterFeed) . stripslashes($suffix); ?> Hi everybody, my goal is to get the IP of someone accesing the site, writing the time and date along with his IP into the database. Of course, I would be adding the script to my frontpage when I make it work. But I get this error: Quote Parse error: syntax error, unexpected T_VARIABLE in D:\Program Files\xampp\xampp\htdocs\script1.php on line 8 I've checked line 8, I dont find anything in it that is out of place. Here is the code: <?php $ip = $_SERVER['REMOTE_ADDR']; $date = date("m.d.y"); $time = time(); mysql_connect ("localhost", "root", "********") or die ('Error: '. mysql_error()); mysql_select_db ("ip"); $query = "INSERT INTO ipdo (time, date, ip) VALUES ('"$time"', '"$date"', '"$ip"')"; mysql_query($query) or die ('Error updating database'); echo "Database updated with: " .$ip. "" ; ?> This is the first script I write entirely on my own, so be gentle Help? i already have the front page that calls the script, but its not letting me login, i don't see the problem i know its returning the rows from the database but i don't understand why its not letting me login and when i do get it to login messing around with the code everybody logs in as an admin, my database has, user, pass, and role inside admin, poweruser, and reg user but when i get it to log in everybody logs in as an admin, can someone please help me ? i even tried the error thing but that doesn't seem to work either ini_set('display_errors', 1); error_reporting(E_ALL); //echo ini_set('display_errors'); session_start(); $username = $_POST['username']; $password = $_POST['password']; if (mysql_connect("localhost", "root", "")) { //echo 'connect'; } else { echo 'failure'; } if (mysql_select_db("athentication")) { //echo 'connect'; } else { echo 'no connect'; } $result = mysql_query("SELECT * FROM login WHERE user = '$username'"); $rows = mysql_num_rows($result); $role = $rows['role']; if ($rows != 0) { if ($role == 'admin') { header('Location: admin.php'); $_SESSION['username'] = $username; } elseif ($role == 'poweruser') { header('Location: poweruser.php'); $_SESSION['username'] = $username; } /*elseif ($role ==' reg') { echo "WHAT UP"; $_SESSION['username'] = $username; }*/ } else echo "enter a valid user name"; Hey guys! I'm not that good with PHP, and I really need to finish this script. I'm having a hard time finding the problem..it keeps saying Error, query failed and I've also checked the database info, connectivity info and even tried a connection and database selection verification to see if that was working. Is there any other error you guys can find in the script that may be causing the message? Edit: The files I want to be able to upload should be pdf's, txts, docs, etc. Would that be possible with this script? Thanks!! Code: [Select] <form method="post" enctype="multipart/form-data"> <table width="350" border="0" cellpadding="1" cellspacing="1" class="box"> <tr> <td width="246"> <input type="hidden" name="MAX_FILE_SIZE" value="104857600"></td> <td width="80"> </td> </tr> </table> <p>Archivo: <input name="userfile" type="file" id="userfile" /> </p> <p>Nomb <label for="name"></label> <input type="text" name="nombrelista" id="nombrelista" /> </p> <p>Password (para luego borrar si necesario): <input type="text" name="pass" id="pass" /> </p> <p> <input name="upload" type="submit" class="box" id="upload" value=" Upload " /> </p> <?php if(isset($_POST['upload']) && $_FILES['userfile']['size'] > 0) { $fileName = $_FILES['userfile']['name']; $tmpName = $_FILES['userfile']['tmp_name']; $fileSize = $_FILES['userfile']['size']; $fileType = $_FILES['userfile']['type']; $filePass = $_POST['pass']; $nombreLista = $_POST['nombrelista']; $fp = fopen($tmpName, 'r'); $content = fread($fp, filesize($tmpName)); $content = addslashes($content); fclose($fp); $host_db = "localhost"; $user_db = "melkien_rudesa"; $pass_db = "jorlan2407"; $base_db = "melkien_rudesa"; $link = mysql_connect($host_db, $user_db, $pass_db); if (!$link) { die('Could not connect: ' . mysql_error()); mysql_close($link); } mysql_select_db($base_db, $link) or die(mysql_error()); if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); } $query = "INSERT INTO 'upload'('nombrelista', 'name', 'pass', 'size', 'type', 'content' ) VALUES ('$nombreLista', $fileName', '$filePass', $fileSize', '$fileType', '$content')"; mysql_query($query) or die('Error, query failed'); echo "<br>File $fileName uploaded<br>"; mysql_close($link); } ?> </form> well I lowered my standards massively. LOL. I decided to google, "php upload and display image", instead of "php gallery". Here is the error I get Warning: copy(/images/sheila.jpg) [function.copy]: failed to open stream: No such file or directory in /hermes/bosweb/web173/b1739/sl.brendansite1/public_html/ealike2/smallgallery/smallgallery.php on line 59 and here is the script that I mostly understand. I thought it was the ..images/, but now I don't know what it is. any help greatly appreciated. thank you. below is the code for the page. Code: [Select] <!-- Start PHP Code For Image Upload --> <?php //define a maxim size for the uploaded images in Kb define ("MAX_SIZE","5060"); //This function reads the extension of the file. It is used to determine if the file is an image by checking the extension. function getExtension($str) { $i = strrpos($str,"."); if (!$i) { return ""; } $l = strlen($str) - $i; $ext = substr($str,$i+1,$l); return $ext; } //This variable is used as a flag. The value is initialized with 0 (meaning no error found) //and it will be changed to 1 if an errro occures. //If the error occures the file will not be uploaded. $errors=0; //checks if the form has been submitted if(isset($_POST['Submit'])) { //reads the name of the file the user submitted for uploading $image=$_FILES['image']['name']; //if it is not empty if ($image) { //get the original name of the file from the clients machine $filename = stripslashes($_FILES['image']['name']); //get the extension of the file in a lower case format $extension = getExtension($filename); $extension = strtolower($extension); //if it is not a known extension, we will suppose it is an error and will not upload the file, //otherwise we will do more tests if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { //print error message echo '<h2>Unknown extension!</h2>'; $errors=1; } else { //get the size of the image in bytes //$_FILES['image']['tmp_name'] is the temporary filename of the file //in which the uploaded file was stored on the server $size=filesize($_FILES['image']['tmp_name']); //compare the size with the maxim size we defined and print error if bigger if ($size > MAX_SIZE*1024) { echo '<h2>You have exceeded the file size limit! Please reduce the image size to 100 Kb or less!</h2>'; $errors=1; } //we will give an unique name, for example the time in unix time format $image_name=$filename; //the new name will be containing the full path where will be stored (images folder) $newname="../images/".$image_name; //we verify if the image has been uploaded, and print error instead $copied = copy($_FILES['image']['tmp_name'], $newname); if (!$copied) { echo '<h2>Copy unsuccessful!</h2>'; $errors=1; }}}} //If no errors registred, print the success message if(isset($_POST['Submit']) && !$errors) { echo "<h2>File Uploaded Successfully!</h2><br />"; echo "<img src='http://ealike.com/images/<?php echo $image_name; ?> />"; } ?> <!-- End PHP Code For Image Upload --> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <!-- Start Image Upload Form --> <form name="newad" method="post" enctype="multipart/form-data" action=""> <input type="file" name="image"> <input name="Submit" type="submit" value="Upload image"> </form> <!-- End Image Upload Form --> </body> </html> Hi there, I have a simple login script written but I get an error with it. It does work but shows an error on some pages. Let me explain. Three Files: Admin.php Login.html checklogin.php When the user has logged in they go to checklogin.php. If the username and password match 1 row in the database then it forwards the user to admin.php fine. Except I keep getting mysql warning messages: Warning: Cannot modify header information - headers already sent by (output started at /home/wormste1/public_html/tilburywebdesign/shop/templates/template1/admin/updatescompanyinformation.php:3) in /home/wormste1/public_html/tilburywebdesign/shop/templates/template1/admin/companyinfoupdated.php on line 3 At the start of each page I want password protected I put the following code: <? session_start(); if(!session_is_registered(myusername)){ header("location:login.html"); } ?> I can't work out why I am getting this error. Many Thanks, Ian |
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