PHP - Moved: Using Current Year To Match Against Where Clause
This topic has been moved to MySQL Help.
http://www.phpfreaks.com/forums/index.php?topic=332417.0 Similar TutorialsHi, I'm wanting to find rows whose date is within the next week of the current month of the current year. The format of the date is, for example: 2010-10-28 Any ideas guys? Thanks lots! How to acheive it friends? i want my current codes to show results accouding to current month followed by year, the precious month goes to the page two.
would really appreciate if someone could help me acheive it
$tableName="records"; Edited by lovephp, 02 December 2014 - 11:50 AM. This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=330779.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=350684.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=342695.0 Hello, i have two fields. a beginning year and an ending year. How can i make new fields out of the years in between the beginning and ending years. i hope that makes sense. This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=332077.0 This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=331482.0 This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=345772.0 This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=326673.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=317758.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=342459.0 i get this error Warning: current() [function.current]: Passed variable is not an array or object.. for this Code: [Select] $lastblock = current( ${"s".$row} ); print_r($lastblock); when i change to this it works.. Code: [Select] $lastblock = current( $s0 ); print_r($lastblock); The problem is i won't know the $row seeing as it is in a while loop. Solution? This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=331562.0 Hello - I've come to an issue with something I'm working on and have searched around with no luck. When editing user accounts I want it to not be able to change the e-mail address into existing ones on other rows, but when submitting the form it takes into account that this particular rows email address is the same as the one which was sent via $_POST and throws up the error. The desired behaviour I want is for it to ignore the ID of the row which was posted, but take into account every other row. Here's the code as it stands at the moment: $email = $_POST['email']; $checkemail = mysql_query("SELECT email FROM users WHERE email='$email'"); } if (mysql_num_rows($checkemail) > 0) { return $this->error("The e-mail address you provided is already associated with an account."); } Hi i have this drop down list current the year is 2010 and downwards but i want to change the list to 2010 upwards u can notice on the 50-- so shows current year minus so current is 2010 to 61 how can i change 2010 to 2030 or sunfin?? echo '<select name="year_of_birth">',"\n"; $year = date("Y"); for ($i = $year;$i > $year-50;$i--) { if($i == $thisYear) { $s = ' selected'; } else { $s=''; } echo '<option value="' ,$i, '"',$s,'>' ,$i, '</option>',"\n"; } echo '</select>',"\n"; Hi
I am now on to viewing listings but want to to show listings that are just submitted by that user and display them on their profile page but can't get the WHERE clause working
Below is the coding for what I have
Profile page
echo "<p><a href='view-private-listings.php?id={$_SESSION['user_id']}'>View Listings</a></p>";Add Listing page HTML Submitted By: <input type="text" name="submittedby">View Listings Page <?php ini_set('display_startup_errors',1); ini_set('display_errors',1); error_reporting(-1); ?> <?php $title = "Private Seller Listings"; include ( 'includes/header.php' ); ?> <?php require_once("functions.php"); $con=mysqli_connect("host","username","password","database"); // Check connection if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } // Start a session for error reporting session_start(); $submittedby=$_POST['submittedby']; $listingtitle=$_POST['listingtitle']; $query = mysqli_query($con,"SELECT listingtitle FROM privatelistings WHERE item LIKE '%$submittedby%'"); echo "<p>Title: {$listingtitle['listingtitle']}</p>"; mysqli_close($con); ?> <?php include( 'includes/footer.php' ); ?>All I get is the following error Notice: Undefined index: listingtitle in /zacs-car-site/view-private-listings.php on line 26 Thank you in advance Kind regards Ian Hi. I am building an update table form. In this table there are only two fields, Header and Intro. Now I have the form and currently it displays whats already in the database. Now when the user edits these two fields and presses edit. Obviously I want it to update these fields. I have the code here but there is an issue with it. At the end of the update I believe I need a update fields WHERE....... which would be used if there was more than one entrance in the table but there is and only ever will be one entry. WHERE what? I dont have a where anything. Do I need this or can it be omitted somehow? <?php if(isset($_POST['edit'])){ //Process data for validation $header = trim($_POST['header']); $intro = trim($_POST['intro']); //Perform validations next //Prepare data for db insertion $header = mysql_real_escape_string($header); $intro = mysql_real_escape_string($intro); //insert $qUpdateDetails = "UPDATE index SET `header` = '".$header."', `intro` = '".$intro."', WHERE ???????='".?????????."'"; $rUpdateDetails = mysql_query($qUpdateDetails) or die(mysql_error()); //next page $page_edit = "Index page has been edited"; $url = "signed.php?edit='".$page_edit."'" or die(mysql_error()); header("Location: ".$url."") or die(mysql_error()); exit(); } } ?> This may be super simple, but it's stumping me. Is this an If/Then clause: Code: [Select] ($month != 1 ? $month - 1 : 12) Is it saying if $month does not equal 1 then $month-1; if so, then what does the colon mean? If not, then what is this piece of code doing? |