PHP - Easy Question! Removing Slashes And Other Things In Strings You Get From Forms

I need make error lower then 3 and higher then 15 how should i add higher then 15?
Code: [Select]
if (strlen($searchTerms) < 3) {
      $error[] = "Add more then 3 symbols and less then 15!";
   }else {
      $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection.
   }

I want to know can we do text formatting to a result coming from echo if so then kindly guide how?

While going through an instructional book, I ran across some code that I didn't immediately understand.  I've stripped it down to the relevant bits:


function example($object_a, $object_b) {

  $compare = $object_a->id == $object_b->id;

  return another_function('argument 1') && $compare || another_function('argument 2');

}



My first confusion was this line:
$compare = $object_a->id == $object_b->id;
Does this set $compare to TRUE if the ids match and FALSE if they do not?

And the second confusion:
return another_function('argument 1') && $compare || another_function('argument 2');
What is returned if the ids match?  What is returned if they are different? 

When I try testing this out on my machine, it returns both functions whether or not the ids match, but I know that's not what's supposed to happen.  Can anyone break this down for me?

Thanks.

So I am extending the DateTime class and would like to completely disable the modify() function that is built in so i have this:
Code: [Select]
<?php
class NewDateTime extends DateTime
{

public function modify()
{
throw new Exception('modify() has been disabled.');
}
}

thats not the entire class description, just the pertinent part of course

now any time I create a new object from NewDateTime I get this message at the top of the screen:

Quote

Strict Standards: Declaration of NewDateTime::modify() should be compatible with that of DateTime::modify() in C:\xampp\htdocs\.....my file path here.....\NewDateTime.php on line 62


what gives? how do I get rid of this and still disable modify()? I'm betting its a setting that i have wonky but I am really rusty in php so dont know where to look in php.ini

hello. i want to know what is *$ or +$ because i see it in many contact forms. also, what is the difference between these:
/^[A-Z]+[a-z]*$/
/^[A-Z]+[a-z]+$/
/^[A-Z]+[a-z]$/
/^[A-Z]+[a-z]/

also, which is the shortest and efficient method of checking somebodys name to be exactly "Name Surname" - "Green Trancer" ? in my form, i use
var filter = /^[A-Z]+[a-z]*$/;
var filter2 = /^[A-Z]+[a-z]+\s+[A-Z]+[a-z]+$/;
and then i check the name to be like filter or filter2.

how can i check that between the words to be exactly one space character ?

thank you very much.

Hey people!

I've been setting a coding script for experience and this is my situation:

To buy a virtual flower, one needs to have 50 virtual coins.
So I first extract the number of coins the person has from the DB.
If the user doesn't have the sufficient number of coins, the BUY button will not be available and vice versa.

When the BUY button is clicked, I update the database, adding the flower to the user's inventory and subtracting 50 from the total number of coins the user has. This I do in that page itself using
if(isset($_POST['submit'])) 

Now, I need to know how I could check whether the user has at least 50 coins even if the button is available.
I hope that you could understand this.
I want to do it for validation purposes. Its to prevent the user spending the coins he has in another browser window and then returning to the visible button to click it.

I hope that I make sense. Thanks in advance!

Regards,
Thauwa

Hello Everybody   I usually work with C#, but I'm doing a website right now and have a question: I want a picture in my header and when I change the window size the image may not move.   My code so far:

#a1 { 
position: relative;
top:-175px; left:0px; width:50px; height:50px;
background-image:url(http://domain.png);
      background-repeat:no-repeat;}
</style>

Hope someone can answer this question easy

I'm trying to search the 'ad' column where 'ad' = 1 or 3

I'm having problems doing this.

Here is what I currently have, but it is not bringing back 'ad' where ='1' (for obvious reasons)
Quote

    $query = "SELECT * FROM users WHERE ad='3' AND state='$state1'";



Here is what I thought would work, but it displays every listing in my database when I do it this way.

Quote

    $query = "SELECT * FROM users WHERE ad='3' OR ad='1' AND state='$state1'";




Thank you in advance for your answers, google is not being so kind to me right now.

How can I use an include file that has a list of links in any directory at my website without breaking those links?

You can see it in action here...

The links in this directory work...

https://www.billelgin.com/primary-directory/

The links in this directory (being created from the same include file) do not work...

https://www.billelgin.com/primary-directory/subsection-one/

Obviously the problem is the include file is being called from different directories, so it's breaking the relative path links in the include file, but what can I do to fix it?

You can download the example directory structure here...

https://www.billelgin.com/EXAMPLE.zip

Wow, am I glad I found this forum!  I spent the past few hours trying to modify a PHP/mySQL script in order to test it. What this script does is basically look up a mySQL database (based on ip2nation) to find out what country and currency the IP address belongs to. This is the code sample:

Code: [Select]
$sql = 'SELECT  c.country, c.curr_code FROM  ip2nationcountries c, ip2nation i WHERE  i.ip < INET_ATON("24.24.24.24") AND c.code = i.country ORDER BY  i.ip DESC LIMIT 0,1';

        $countryName = $db->get_sql_row($sql);

I tested the code in PHPmyAdmin and it returns 2 rows:

country ------- curr_code (row names)
United States ------- USD (actual values)

So basically 2 variables, United States and USD. Now comes the problem, in order to test the script for several countries, I need to be able to "override" the result in the PHP script

I tried to do that by commenting out the part that returns the result from the mySQL query and modifying it with the following style, but I think I'm doing something wrong:

Code: [Select]
### $countryName = $db->get_sql_row($sql); ###

$countryName = "United States USD";

Is there any way that I can temporarily override the result returned by mySQL and "fake it" so to say? I understand the mySQL query returns 2 rows, so how would I go about overriding 2 rows?

I hope this makes sense ...you're all my last hope.

 

I am very new to php and am trying to create a simple application that uploads a PDF file to a database. I have one field for the Volume Number and on file field for the PDF to be uploaded. My issue is i can't get the PDF to upload or insert the name of the pdf (eg volume1.pdf) into the data base.

I would also like to point out that I know i have a low post count, but i only seek help when i truly need it and have exhausted all other resources...

Here is what i have, please go easy on me this is my first round at php:
Code: [Select]
<?php
if(isset($_POST['submit'])){
$vol_num = $_POST['vol_num'];
$pdf = $_FILES['pdf']['name'];
$path = '../pdf/'.$_FILES['pdf']['name'];
move_uploaded_file($_FILES["pdf"]["tmp_name"], $path);
        mysql_query("INSERT INTO volumes set vol_num='$vol_num', vol_link='$pdf'") or die (mysql_error());
echo "<script>location.href='add_volume.php'</script>";
}
?>
what am i doing wrong here?

Thanks in advance

I'm almost embarrassed to ask such a simple question but I just cannot get this to work.  I'm trying to figure out how to use sessions  that takes the information from a form on the first page and displays it on the last.
I have this on page 1:
<?php
session_start();
?>
<form action="test2.php" method="post">
<p>Page 1</p>
<p>First Name <input type="text" name="first" /></p>
 
<p><input type="submit" value="Next page 2"  /></p>

And this for page 2:
<?php
SESSION_START();

$_SESSION['first'] = $_POST['first'];
echo $_SESSION['first'] = $_POST['first'];

?>
<form action="test3.php" method="post">
<p>Page 2</p>
<input type="submit" value="Next page 3" />
</form>

And this for page 3:
<?php
SESSION_START();

$_SESSION['first'] = $_POST['first'];
echo $_SESSION['first'] = $_POST['first'];

?>

<p>Page 3</p>
<p>You're done</p>

I can get it to display on page 2 but not on page 3.  Can anyone tell me why?  I've been at this for a long time and it should be simple but I cannot get it to work.  Thanks in advance.

I have a php page that processes a form.  How do I prevent someone from making their own form on their own domain and then saying <form metod=post action = "www.hackerdomain.com/bad.php">

and then passing their own variables?

Do I set up a $session variable on my form page and assign it to  $_SERVER["PHP_SELF"]?

Hi All I Am confused

I would like to put info into a database but need it to be secure. I have some code shown below. The problem is I would like to put in ' but keep the data secure.
When it comes back I do not want to show \' I think you might know what I am trying to do.
Here is the code but would like to know how to stop the \' showing.
Code: [Select]
$password = mysql_real_escape_string(stripslashes(trim($_POST['password'])));
Any help would be great thank you.

Hi:

Is this the proper way to remove slashes from apostrophes:
Code: [Select]
if ($_SERVER['REQUEST_METHOD'] == 'POST')
{

$myTitle = mysql_real_escape_string(stripslashes($_POST['myTitle']));
$myDesc = mysql_real_escape_string(stripslashes($_POST['myDesc']));
$myHeader = mysql_real_escape_string(stripslashes($_POST['myHeader']));
$mySubHeader = mysql_real_escape_string(stripslashes($_POST['mySubHeader']));
$myPageData = mysql_real_escape_string(stripslashes($_POST['myPageData']));


It seems to work fine, I'd just like to clarify I'm not missing anything.

Thanks!