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PHP - Need To Insert Field Fields Into Input
can someone tell me why this won't work? I just want to key in the amtpaid and have fields inserted. I get no errors but the only field inserted is the datepaid .
<html><head> <script> function $_(IDS) { return document.getElementById(IDS); } function calculate_paid() { var amtpaid = parseInt($_("amtpaid").value); var rentdue = parseInt($_("rentdue").value); var prevbal = parseInt($_("prevbal").value); var secdep = parseInt($_("secdep").value); var latechg = parseInt($_("latechg").value); var damage = parseInt($_("damage").value); var courtcost = parseInt($_("courtcost").value); var nsf = parseInt($_("nsf").value); var hudpay = parseInt($_("hudpay").value); var late = ($_("late").value); var paidsum = parseInt($_("paidsum").value); var dateNow = new Date(); var dayNow = dateNow.getDate(); var datePaid = (dateNow.getMonth()+1)+"/"+dateNow.getDate()+"/"+dateNow.getFullYear(); $_('datePaid').value = datePaid; if(dayNow > 5) { late = "L"; prevbal = prevbal + 10; } paidsum = paidsum + amtpaid var tentpay = amtpaid - hudpay; var totOwed = rentdue + prevbal - hudpay; var left = totOwed - amtpaid; if (amtpaid <= totOwed) { prevbal = left; } left = amtpaid - totOwed; if (left <= secdep) { secdep = secdep - left; } left = left - secdep; if (left <= damage) { damage = damage - left; } left = left - damage; if (left <= latechg) { latechg = latechg - left; } left = left - latechg; if (left <= courtcost) { courtcost = courtcost - left; } left = left - courtcost; if (left <= nsf) { nsf = nsf - left; } prevbal = left - nsf; } </script> </head><body> <?php mysql_connect(localhost,root,""); mysql_select_db(test) or die( "Unable to select database"); if(!empty($_POST["submit"])) { $apt = $_POST['apt']; $query="SELECT * FROM testdata Where apt='$apt'"; $result=mysql_query($query); if(mysql_num_rows($result)) { echo "<form action='#' method='post'><b>Rent Payment :<br /><br /> <table cellspacing=0 cellpadding=0 border=1> <tr> <th>Name</th> <th>Apt</th> <th>Paid</th> <th>Due</th> <th>Prev Bal</th> <th>Sec Dep</th> <th>Late Chg</th> <th>Dmg</th> <th>Court Cost</th> <th>NSF</th> <th>Tent Pay</th> <th>Hud Pay</th> <th>Date Paid</th> <th>Late</th> <th>Comments</th> <th>Paidsum</th> </tr>"; while($row = mysql_fetch_assoc($result)) { echo "<tr> <td><input type='text' size=25 name='name' value='" . $row['name'] . "'></td> <td><input type='text' size=2 name='apt' value='" . $row['apt'] . "' ></td> <td><input type='text' size=4 id='amtpaid' name='amtpaid' value='" . $row['amtpaid'] ."' onBlur='calculate_paid(this)'></td> <td><input type='text' size=4 id='rentdue' name='rentdue' value='" . $row['rentdue'] . "'></td> <td><input type='text' size=4 id='prevbal' name='prevbal' value='" . $row['prevbal'] ."'></td> <td><input type='text' size=4 id='secdep' name='secdep' value='" . $row['secdep'] ."'></td> <td><input type='text' size=4 id='latechg' name='latechg' value='" . $row['latechg'] ."'></td> <td><input type='text' size=4 id='damage' name='damage' value='" . $row['damage'] ."'></td> <td><input type='text' size=4 id='courtcost' name='courtcost' value='" . $row['courtcost'] ."'></td> <td><input type='text' size=4 id='nsf' name='nsf' value='" . $row['nsf'] ."'></td> <td><input type='text' size=4 id='tentpay' name='tentpay' value='" . $row['tentpay'] . "'></td> <td><input type='text' size=4 id='hudpay' name='hudpay' value='" . $row['hudpay'] ."'></td> <td><input type='text' size=10 id='datepaid' name='datepaid' value='" . $row['datepaid'] . "'></td> <td><input type='text' size=1 id='late' name='late' value='" . $row['late'] . "'></td> <td><input type='text' size=25 name='comments' value='" . $row['comments'] . "'></td> <td><input type='text' size=4 id='paidsum' name='paidsum' value='" . $row['paidsum'] . "'></td> </tr>"; } echo "</table> <input type='submit' name='update' value='Make Payment' /> </form>"; } else{echo "No listing for apartment $apt.<br />Please select another.<br />";} } if(!empty($_POST["update"])) { $sql = "UPDATE testdata SET name = '" . mysql_real_escape_string($_POST['name']) . "', amtpaid = '" . mysql_real_escape_string($_POST['amtpaid']) . "', rentdue = '" . mysql_real_escape_string($_POST['rentdue']) . "', prevbal = '" . mysql_real_escape_string($_POST['prevbal']) . "', secdep = '" . mysql_real_escape_string($_POST['secdep']) . "', latechg = '" . mysql_real_escape_string($_POST['latechg']) . "', nsf = '" . mysql_real_escape_string($_POST['nsf']) . "', damage = '" . mysql_real_escape_string($_POST['damage']) . "', courtcost = '" . mysql_real_escape_string($_POST['costcost']) . "', tentpay = '" . mysql_real_escape_string($_POST['tentpay']) . "', hudpay = '" . mysql_real_escape_string($_POST['hudpay']) . "', datepaid = '" . mysql_real_escape_string($_POST['datepaid']) . "', late = '" . mysql_real_escape_string($_POST['late']) . "', comments = '" . mysql_real_escape_string($_POST['comments']) . "', paidsum = '" . mysql_real_escape_string($_POST['paidsum']) . "' WHERE apt='".$_POST["apt"]."'"; mysql_query($sql) or die("Update query failed."); echo "Record for apartment ".$_POST["apt"]." has been updated"; } ?><form method="post" action="#"> <br /> <input type="text" name="apt"/> <p> <input type="submit" name="submit" value="select apartment"/> </form> </body></html> Similar TutorialsHello I though this code would work Code: [Select] mysql_query("UPDATE cart SET totprice = quantity * price WHERE ID='{$id}'")or die(mysql_error());because this is working fine Code: [Select] mysql_query("UPDATE products SET rating = rating + 1 WHERE ID='{$id}'")or die(mysql_error()); Anything wrong with it, or how should i do it? I would like to split the field specific location on a page into two fields. ( This is how it looks now: http://qwikad.com/?view=post&cityid=269&lang=en&catid=3&subcatid=27&shortcutregion= ) I want keep the same MySQL table for that field but make it possible for visitors to enter 2 separate texts. This is how the code looks right now: <input name="area" type="text" size="40" class="input" maxlength="50" value="<?php echo $data['area']; ?>"> I am not strong in PHP programming at all, so I tried to copy and paste that field twice, but it only posts one entry out of the two. Can this be done? I have a register script, and I am wanting to make it so that if the username field contains, lets say "mod", "ass", and more, then it'll return an error and wont let them register. Hey guys,
Thank you in advance... here is my situation, I have a form with three (3) fields in it, the 'student name' is unlimited textfield with an "add more" button to it and I have two select fields ('number of shirts' and 'trophies') that depend on the number of entries for 'student name'...
I want to create the select fields based on this math, for as many 'student name' entries:
1- i want to have the select form for 'number of shirts' to be 0 up to that number... so if there are 6 'student name' entries, the select options will be 0,1,3,4,5,6,7
2- I want to have the select form for 'trophies' to be 5 'student name' entries to 1 'trophies', for example if there are 6 'student name' entries, the select options will be 0,1... if there are 13 entries, options will be 0,1,2... So if there are less than 5 'student name' entries, the select field will not show (hidden)
of course if there are no 'student name' entries, these two fields won't show up (hidden)
let me know if that make sense and ANY help or directions will be GREATLY APPRECIATED.
Thanks guys!
I have a calendar select date function for my form that returns the date in the calendar format for USA: 02/16/2012. I need to have this appear as is for the form and in the db for the 'record_date' column, but I need to format this date in mysql DATE format (2012-02-16) and submit it at the same time with another column name 'new_date' in the database in a hidden input field. Is there a way to do this possibly with a temporary table or something? Any ideas would be welcome. Doug I have a form with a series of text boxes where the User enters specific data, be it text, numeric, or date/time. It is not mandatory to fill in every box, but when I submit the form to be put into a mysql table, I get errors such as "Incorrect time value: '' for column 'starttime' at row 1" "Incorrect decimal value: '' for column 'workkj' at row 1" How can I setup the mysql table to accept blank answers? Or is there something I need to do in php to fix this? Sorry if this is simple... I'm still learning. Thanks for the help! Hello, i need to validate 200 input fields if they are not empty, i have the following code where i'm stuck and i'm missing something any help is appreciated Code: [Select] if($_SERVER['REQUEST_METHOD'] == 'POST') { //print_r($_POST); foreach ($_POST as $value) { if (empty($value)){ echo 'empty'; } else { echo 'notempty'; } } } I have 2 fields, one for Mother's mobile, the other for Father's mobile. I want to ensure that at least one of the 2 fields contains a number. This is what I have: Code: [Select] <?php if(!isset($_POST['guardian1_mobile']) && !isset($_POST['guardian2_mobile'])) { // no number entered in either field $errors[] = 'You must enter a mobile number in at least one of the Guardian1 or Guardian2 Mobile fields.'; } else { // if Mother mobile if(!is_numeric($_POST['guardian1_mobile']) || strlen(trim($_POST['guardian1_mobile'])) != 7) { // number must be numeric and exactly 7 digits $errors[] = '<strong>Guardian1 mobile</strong>: please enter a 7-digit number without spaces or dashes.'; } else { $_SESSION['guardian1_mobile'] = $_POST['guardian1_mobile']; } // if Father mobile if(!is_numeric($_POST['guardian2_mobile']) || strlen($_POST['guardian2_mobile']) != 7) { $errors[] = '<strong>Guardian2 mobile</strong>: please enter a 7-digit number without spaces or dashes.'; } else { $_SESSION['guardian2_mobile'] = $_POST['guardian2_mobile']; } } However, when I leave both fields blank, errors for the 'else' part of the condition are returned ('Please enter a 7-digit number...'). But it should never get as far as the 'else'.... Can anyone tell me what's wrong with my logic in the first line?... Thanks in advance. I have a website with a variable number of inputs in various categories. I want to allow the user to add rows to the table with the input lines in every category. The table looks like this:
<tr><th>Working Capital Changes</th></tr><tr><td><input type="hidden" name="category_code[]" value="WORK"><input type="text" name="description[]" value="Increase (decrease) in working capital" size="60"></td>
<td><input type="text" name="amount[1][]" value="" onblur="this.value = formatNumber2Comma(this.value);" ></td></tr>
<tr><td><input type="hidden" name="category_code[]" value="WORK"><input type="text" name="description[]" value="" size="60"></td>
<td><input type="text" name="amount[1][]" onblur="this.value = formatNumber2Comma(this.value);" ></td></tr>
<tr><th>Depreciation and Amortization</th></tr><tr><td><input type="hidden" name="category_code[]" value="DEPR"><input type="text" name="description[]" value="Depreciation and Amortization (for taxes)" size="60"></td>
<td><input type="text" name="amount[1][]" value="" onblur="this.value = formatNumber2Comma(this.value);" ></td></tr>
<tr><td><input type="hidden" name="category_code[]" value="DEPR"><input type="text" name="description[]" value="" size="60"></td><td><input type="text" name="amount[1][]" onblur="this.value = formatNumber2Comma(this.value);" ></td></tr>
I tried adding the following near the top of the page:
<script src="//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script type="text/javascript">
var count = 0;
$(function(){
alert ('wow');
$('tr#add_field').click(function(){
alert ('whee');
count += 1;
$('#container').append('<table><tr><td><input id="field_' + count + 'type="hidden" name="category_code[]" value="DEPR"><input type="text" name="description[]" value="" size="60"></td><td><input type="text" name="amount[1][]" onblur="this.value = formatNumber2Comma(this.value);" ></td></tr></table>' );
});
});
I get the wow alert on page load and whee when I click the link:
<tr id="add_field"><th><a href="#">Click to add another line</a></th></tr>that I added to the bottom of the table before the </table> but I do not get an additional line I have tried moving the add_field line outside of the table and changing the <tr></tr> to a <p></p> but that does not help. I'm trying to do this with the code below. I get an error because explode thinks I'm just sending it one argument since the string is held by an array element. If I can get the array from the explode function I can insure it into the first and last name fields in my table. Any suggestions? --Kenoli
require '__classes/Db.php';
$sql = "SELECT name FROM tbl_persons";
$stmt = $pdo->query($sql);
$row = $stmt->fetchall(PDO::FETCH_ASSOC);
foreach ($row as $name) {
$names = explode($name['name']);
}
I have an email form that is sending to an email address. There are five fields where the person sending can input their Name, Address, City, State, and Zip. Everything is working, except I want the input from these fields to be the the headers in the PHP email. For instance it submits and send the letter, but I want the senders Name, Address, City, State, and Zip to be posted after the "Sincerely" in the letter sent. Here is what the input boxes of the form looks like: Code: [Select] <p>Sincerely,<br /> <label for="from">Name:</label> <input type="text" name="from" id="name" value="<?php echo $_POST['from'];?>"/><br /> <label for="street">Street:</label> <input type="text" name="street" id="street" value="<?php echo $_POST['street'];?>"/><br /> <label for="city">City:</label> <input type="text" name="city" id="city" value="<?php echo $_POST['city'];?>"/><br /> <label for="zip">Zip:</label> <input type="text" name="zip" id="zip" value="<?php echo $_POST['zip'];?>"/><br /> <label for="email">E-mail:</label> <input type="text" name="email" id="email" value="<?php echo $_POST['email'];?>"/></p> <input type="submit" class="button" value="Submit" /> How do I go about posting the PHP headers in the email upon submission? Hello people, thank you to everyone that has helped me on this forum. You have been terrific. I am submitting a form to a database and am having a small problem with the validation scripts. Basically if the user doesn't put something into one of the fields they get an error message. However, I am keeping the information already submitted in the input box with the following code Code: [Select] <input type='text' name='username' size = '40' maxlength='30' value = '<?php echo $username; ?>'> This is so that the user doesn't have to input the same data again if he forgot one box. How do I do the same for "drop down" boxes? Here is the code from the form for the "ppr" (aviation terms 'Prior Permission Required') Code: [Select] <select name = "ppr"> <option value = "Yes">Yes </option> <option value="No">No </option> </select> The problem I have is that there are quite a number of these drop down boxes on the form I have created. And it always goes back to the first "option value" when there is an error. I do have a variable for $ppr, please could someone tell me how to incorporate it so that the user doesn't have to select the correct option value all over again. Hope my explanation is clear. Thanks in advance. Hi, I have a field called experience in mysql and I want to add +7 to said field, is it possible using UPDATE or insert? If so, what's the syntax? Here's what I have that doesn't work, it sets experience to 7, but won't add another 7 when clicked again. if(isset($_POST['submit'])){ $query = "UPDATE account_info SET experience = +7 WHERE username = $name"; $result = mysql_query($query) or die(mysql_error()); } don't ask for the whole script, because you won't need it to answer that o.0 Hi all, I'm working on this site which I'll soon ask the guys in the testing forum to have a peek at. It's essentially an online community that was a uni project that has spiraled and grown exponetially. I've spent many many hours in front of books and tutorals etc to put it together and as far as scripting goes, it seems to be fine. The problem i'm having...The tut's that I read / watched were using eregi_replace to protect text fields and this is now unsuported. I want my site to be as secure as it can be, within reason. I've tried using preg_replace instead and have searched for the syntax but i keep getting strang results. I'm working on the "bio" field at the moment and then when that works I can move on and a-ply the same idea to the other fields. This si what I have and what I've changed. if ($_POST['parse_var'] == "bio"){ $bio_body = $_POST['bio_body']; //$bio_body = str_replace("'", "'", $bio_body); (WAS TESTING THIS BUT NO JOY) //$bio_body = str_replace("`", "'", $bio_body); $bio_body = mysql_real_escape_string($bio_body); $bio_body = nl2br(htmlspecialchars($bio_body)); $bio = $_POST['bio']; $bio = eregi_replace("'", "'", $bio); (This works but is not as secure) $bio = eregi_replace("`", "'", $bio); $bio = mysql_real_escape_string($bio); $bio = nl2br(htmlspecialchars($_POST['bio'])); $sqlUpdate = mysql_query("UPDATE members SET bio='$bio' WHERE id='$id'"); and so on....} When I change it to str_replace if I type in don't the whole word is deleted. when I type in preg I get an error. Can someone please give me the correct code / syntax for getting the result I want. I just want to make sure that every single field that has a user input is protected against any malicious attacks. Thanks. Hey Guys. I have a quick question. Should i "prep" input values coming from a radio or checkbox input field? Can an SQL injection occur through those 2 input fields, or is it only text fields?
Hi I have a form that is to input data from input fields to a table. The form is as follows: $query = $DB->query("SELECT country_code, country_id, IF(country_code = '".$country_code."', '', '') AS sel FROM exp_sme_countries WHERE site_id='".$this->settings['site_id']."' ORDER BY country_name ASC"); foreach ($query->result as $row) { $options .= '<label>' . 'Phrase for ' . $this->settings['countries'][$row['country_code']] . '</label>' . '<br />'; $options .= '<input style="width: 100%; height: 5%;" id="country_data" type="text" name="country_id[]" />' . '<br /><br />'; $options .= '<input type="hidden" name="country_data[' . $row['country_id'] . ']" value="'.$row['country_id'].'" />'; } This outputs: Code: [Select] <input style="width: 100%; height: 5%;" id="country_data" type="text" name="country_id[]" /> <input type="hidden" name="country_data[68]" value="68" /> <input style="width: 100%; height: 5%;" id="country_data" type="text" name="country_id[]" /> <input type="hidden" name="country_data[28]" value="28" /> What I need to do, is get the values from the input fields and then match them with the correct hidden field value So if in the first input field, I typed in 'Test data' and the second input, i typed 'This is great' On the POST, I need to find the the value ('Test data') and also the value from the hidden field. So something like: Quote The text you entered is: Test data with hidden value of 68 The text you entered is: This is great with hidden value of 28 I'd rather not use $_GET as this is a form that inserts data into a database. Could someone point my in the right direction or provide an example? - I am inserting a new record into a table called "parts". The key field is "partid", which is autoincremented. - After I do the insert, how do I get the value for partid for the new record? I cannot select the record because there are no unique combinations of fields to select on. Here is my code to insert the new record into table "parts". //Insert new part. $query="INSERT INTO parts (modelnum, prodcat, ". "prodname, prodsubname, createuser, createdate) " . "VALUES ( ". "'".$modelvar."', " . "'".$prodcatvar."', ". "'".$prodnamevar."', ". "'".$prodsubnamevar."', ". "'".$_SESSION['username']."', ". "NOW() ". ");"; $result=mysqli_query($dbc,$query); if (!$result) { $msg=mysql_error().'<br/>Could not run SELECT. '; //There was an error. crError($_SERVER['PHP_SELF'].' line '.__LINE__,$msg,true); } else { $s='Inserted new product cat='.$prodcatvar.', model='.$modelvar; crInfomsg($s); } } Thank you. I built a basic form with certain fields required. When a required field isn't filled, the errors are echoed but not in the best area. I'd like for each error message to be displayed underneath their respected input fields. What do I need to look into? <?php if(!empty($_POST['submit'])) { // set variables $name = mysql_real_escape_string($_POST['name']); $email = mysql_real_escape_string($_POST['email']); $email2 = mysql_real_escape_string($_POST['email2']); $age = mysql_real_escape_string($_POST['age']); $city = mysql_real_escape_string($_POST['city']); $state = mysql_real_escape_string($_POST['state']); // 1A. REQUIRED FIELDS VERIFICATION if(!empty($name) && !empty($email) && !empty($email2) && !empty($city) && !empty($state)) { // 1B. END REQUIRED FIELDS VERIFICATION } else { echo '<img src="images/icon_error.png" alt="" title="" /> Please fill out the required fields.<br />'; if (empty($name)) { echo 'Whats your name?!<br />'; } if (empty($email)) { echo 'No email given.<br />'; } if (empty($email2)) { echo 'Please verify your email<br />'; } if (empty($city)) { echo 'What city are you from?<br />'; } if (empty($state)) { echo 'What State!<br />'; } echo '<br /><br />'; } // 1B. END REQUIRED FIELDS ERROR CODES } ?> <form action="<?php $_SERVER['PHP_SELF']; ?>" method="post"> <div class="formSec"><label for="name" class="required">Full Name:</label> <input type="text" name="name" id="name" value="" /></div> <div class="formSec"><label for="email" class="required">Email:</label> <input type="text" name="email" id="email" value="" /></div> <div class="formSec"><label for="email2" class="required">Confirm Email:</label> <input type="text" name="email2" id="email2" value="" /></div> <div class="formSec"><label for="age" class="required">Age:</label> <input type="text" name="age" id="age" value="" /></div> <div class="formSec"><label for="city" class="required">City:</label> <input type="text" name="city" id="city" value="" /></div> <input class="submit" type="submit" name="submit" value="Submit" /> </form> Hi i have a form that logins at a mail. I have installed an SSL at this domain and i would like to add an option at the form for the user to login using https or not the form is above. How can i add an option with check-box from user to login using https ???? IF this is checked when the user clicks "login" he will redirected to https and will login. If i have not describe well please ask for details. Thanks <form class="login-form" action="<?php echo $this->moduleBaseUrl; ?>/XXX/XXXXXX" name="loginPage" id="loginPage" method="post"> <input type='hidden' name='emailName' value=''/> <input type='hidden' name='emailDomain' value=''/> <input type='hidden' name='cssStyle' value='<?php echo $this->cssStyle ?>'/> <table class="login"> <tbody> <tr> <td> <label class="user"><?php print $this->translate('Email') ?>:</label> <input id="email" class="input-email" type="text" name="email" tabindex="1" /> </td> </tr> <tr> <td> <label class="pass"><?php print $this->translate('Password') ?>:</label> <input id="password" class="input-pass" type="password" name="password" tabindex="2" /> </td> </tr> <tr id="LoginBtn" style="display: none;"> <td> <input class="loginbtn <?php echo $this->cssStyle ?>" type="submit" value="<?php print $this->translate('Login') ?>" /> <span class="remember"><?php print $this->translate('Remember Me') ?></span> <input class="check" type="checkbox" value="1" name="RememberMe" /> </td> </tr> </tbody> </table> </form> |
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