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PHP - Help With Query By Example (wildcard "%") Form
I am trying to make a simplified query by example search form for my website.
I would like to allow my users to do more complicated queries from one my prospects table. The user will be able to search by 1 or more field(s), select the operator for each field & enter the search value for each field. The advanced_search .php file is below: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Advanced Query</title> </head> <body> <form name="form1" method="post" action="do_advanced_search.php"> <table border="0" cellspacing="5" cellpadding="5"> <tr> <th>Field Name</th> <th>Operator</th> <th>Value</th> </tr> <tr> <td><input name="company_name" type="text" id="company_name" value="Company Name" readonly="readonly" /></td> <td><select name="company_operator" size="1" id="company_operator"> <option value="=" selected="selected">=</option> <option value="<>">Not Equal</option> <option value="Like %...%">Like %...%</option> </select></td> <td><input type="text" name="company_value" id="company_value" /></td> </tr> <tr> <td><input name="state" type="text" id="state" value="State" readonly="readonly"/></td> <td><select name="state_operator" size="1" id="state_operator"> <option value="=" selected="selected">=</option> <option value="<>">Not Equal</option> <option value="Like %...%">Like %...%</option> </select></td> <td><input type="text" name="state_value" id="state_value" /></td> </tr> <tr> <td><label> <input name="County" type="text" id="County" value="County" readonly="readonly" /> </label></td> <td><select name="county_operator" size="1" id="county_operator"> <option value="=" selected="selected">=</option> <option value="<>">Not Equal</option> <option value="Like %...%">Like %...%</option> </select></td> <td><input type="text" name="county_value" id="county_value" /></td> </tr> <tr> <td><input name="city" type="text" id="city" value="City" readonly="readonly" /></td> <td><select name="city_operator" size="1" id="city_operator"> <option value="=" selected="selected">=</option> <option value="<>">Not Equal</option> <option value="Like %...%">Like %...%</option> </select></td> <td><input type="text" name="city_value" id="city_value" /></td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td><label> <input type="submit" name="button" id="button" value="Search" /> </label></td> <td> </td> </tr> </table> </form> </body> </html> The do_advanced_search.php is below: $connection=mysql_connect($servername,$dbusername,$dbpassword); $db=mysql_select_db($dbname,$connection) or die(mysql_error()); $sql=mysql_query("SELECT * FROM smf_prospects where companyname '". $_POST['company_operator'] ."' '" . $_POST['company_value'] ."' AND state '" . $_POST['state_operator'] ."' '" . $_POST['company_value'] ."' AND county '". $_POST['county_operator'] ."' '" . $_POST['county_value'] . "'); echo $sql; $result=mysql_query($sql,$connection) or die(mysql_error()); while($row=mysql_fetch_array($result)) { $comapanyname= $row['companyname']; $state=$row['state']; $county=$row['county']; } echo $companyname; echo $state; echo $county; ?> Any help would be greatly appreciated. I will poet a completed version of this once it is finished. Thank you, Terry Mullins Similar TutorialsCan someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> Hi, I have a page on my Intranet which lists a bunch of install files (for example, Microsoft Office), which are stored in the same directory structure as the site itself. I also have a duplicate installs folder structure in another office, on their local server. I want to make it so that the link changes, depending on which office the user is in. To simplify: If (user is in London) display London link else display Blackpool link I've been trying to make it work via IP Address. The IP range in London is 10.44.6.* However, I can't make the script work with a wildcard (it works fine if I put a specific address in). The code I have so far is: Code: [Select] <?php $ip=$_SERVER['REMOTE_ADDR']; if ($ip == '10.44.6.*') { ?><a href="link1.php">Click Here</a><?php } else { ?><a href="link2.php">Click Here</a><?php }; ?> I think it may be an obvious solution, but if some kind person could perhaps point out my mistakes? Thanks, Dave Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=318175.0 Hi. I have just one question (I have searched for an answer for this but have not been able to locate one): How do you go about changing the text on a "Submit Query" button to display simply "Submit"? Below is the current code for the page that displays said button. Thank-you in advance for any help or direction. <?php include 'connection.php'; $query = "SELECT * FROM people"; $result = mysql_query($query) or die(mysql_error()); while ($person = mysql_fetch_array($result)){ echo $person ['name']; echo $person ['descrip']; } ?> <H1>Add Your Review:</H1> <form action="create.php" method="post"> Subject <input type="text" name="inputName" value=""/> </br > Review <textarea cols="50" rows="4" name="inputDesc" value=""/></textarea> </br > <input type= "submit" name= "submit"/> </form> <html> <head></head> <body> <p>The current second is <span style='font-size:16px;font-weight:bold;color:red;position:absolute;right:25px;'><?php echo time(); ?></span> on this computer.</p> </body> </html> An insert function is not inserting. I keep getting "Could not store data, please try again." After some probing, it seems that "$result = $conn->query($user_degree_insert_query); " is where the problem is. Variables before it seem to pass testing. I can't figure out why this line is messing thins up though. Any idea? Thank you in advance for your help! The "//$degree_id = mysql_fetch_array($degree_id_query, MYSQL_BOTH) ;" is commented out because it was giving me trouble, i replaced it with the line above that $conn = db_connect(); $arraycount = count($degree_Array); //loop through the categories chosen and add them each into member-category for($i =0; $i < $arraycount; $i++){ $degree_id_query = "SELECT degree_id FROM degree WHERE degree_type ='".$degree_Array[$i]."'"; $result = $conn->query($degree_id_query); //place the id found into the array, which automatically cancatonates it. $degree_id = $result->fetch_array(); //$degree_id = mysql_fetch_array($degree_id_query, MYSQL_BOTH) ; $user_degree_insert_query = "INSERT INTO user-degree ( `user_id` , `degree_id` ) VALUES ( '".$user_id."', '".$degree_id[0]."' )"; $result = $conn->query($user_degree_insert_query); if($result) { header("Location: survey2.php"); }else { echo "<p>Could not store data, please try again.</p>"; exit; This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=354981.0 I have a registration form on my website and after Registration I want the user to activate first his account. I don't have problem on sending this email to the user. What I want to appear is like this.. GoodDay "username", Blah Blah! how can you actually do that? I know that you can do that through session variables but the thing is email's can't accept scripts on sending emails. how can I get the value from a session variable for example and convert it to plain html text so that i can OUTPUT it to the email.. HELP PLEASE! Hi, I currently have an if, elseif, else program that starts off with Code: [Select] if( $v_name == "" || $v_msg == "" ) echo "something" how do I turn this into a switch? but the very next elseif I have Code: [Select] elseif( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) ) echo "something" is it possible to turn this into a switch with 2 different strings like that to evaluate? This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=347922.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=326600.0 Hi all, Using a form with check boxes divided into different categories, I collect data selected by the user. I now want to combine each choice in each category with each choice in the other categories and list the combinations to the user. If the user chooses one or more options in each category, it is relatively easy to nest foreach loops, since the number of categories will always be the same. For example, if the form contains three categories of options, the code will be: Code: [Select] foreach ($form['cat_1'] as $k1 => $val1) { foreach ($form['cat_2'] as $k2 => $val2) { foreach ($form['cat_3'] as $k3 => $val3) { echo $val1.' _ '.$val2.' _ '.$val3.'<br/>'; } } } Things get complicated if the user does not select options within a given category. More generally, I want to be able to generate the list regardless of the number of categories in which the user selects options. Thank you in advance for your advice. Hey guys! I have the following doubt: I have a php file that does the following alongside with other code not displayed he $fp = fopen("emails.txt", "w"); It opens a txt file called emails.txt that is in the same folder where the php is saved but how do I tell $fp = fopen("/folderbefore/emails.txt", "w"); ?? In other words, how do I write the path on the script that the emails.txt is located in a previous folder where the php file is located?? Thanks in advance for your help Cheers! hello, I was wondering what is the point of writing for a dropdown: <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?> or for a checkbox/ radio button: <?php if ($_POST['cb/radioID'] == "value") { echo "checked"; } ?> I guess it's for after submit, if there is any error, the values filled will still be echoed in the inputfield, or am i wrong? But then if that is true, i have a php search box where i use AJAX object to to send all the input they filled in after submit. But after pushing submit the inputted values remain. I guess when using AJAX to send the information i don't need <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?> in my html forms? Little confused Can maybe somebody bring clearness Hi guys , can someone help me with this code its giving me "query was empty Error" its connecting but...? and please find attached the entire php page for clarity. Thanks . <?php //connect database require_once "connect_to_mysqli.php"; //query the datbase $sqlcommand = "SELECT post_id, title, body From posts ORDER by post_id desc"; $query = mysql_query($sqlCommand) or die (mysql_error()); while($row = mysql_fetch_array($query)) { $title = $row["title"]; echo "<h3>$title</h3>"; } // Free the result set if it is large mysql_free_result($query); // close mysql connection mysql_close(); ?> $sql = "SELECT * FROM `users` WHERE `$searchField` like '%$search%'"; I still have to put in the EXACT value, it can't be similar. |
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