PHP - Rounding A Variable To The Next 5

Here is the number:



$GrandTotal = "68.835";
$Deposit = round($GrandTotal , 2) * .5;

echo $Deposit;



I am looking for: 68.84 but the function doesn't seem to work right.

Any help?

Hi fellas,

Can anyone show me why my script is still rounding up / down?

printf ("<tr> %s Avg gun Ahit %%</td> %s %.2f %%</td></tr>\n",$tdo,$tdor,number_format($ahit/$fired*100, 3, '.', ''));

Do I have a syntax error as I cannot get my math equation to display more than 2 decimal places even though it's set to 3?

Any help or advice would be really great.

Hi,

Having trouble rounding the output. I would need to be sure the output is not longer than 2 spaces after comma.
Any ideas?

My code
Code: [Select]
<script type="text/javascript">
$(document).ready(function() {
  $("<?php echo "#".$input_end_time; ?>").blur(function(){
   var start_time = $("<?php echo "#".$input_start_time; ?>").val();
   var end_time = $("<?php echo "#".$input_end_time; ?>").val();
  $.getJSON("include/timedifferencecalculation.php?s="+start_time+"&e="+end_time, function(data){
   var success = data.success;
    if (success == 1) {
     $("<?php echo "#".$input_difference; ?>" ).val(data.hours + " h " + data.minutes + " m ");
  if (data.hours + data.minutes/60 >= 6){
$("<?php echo "#".$hours_difference; ?>").val(data.hours + data.minutes/60 - 0.5);
}else { $("<?php echo "#".$hours_difference; ?>").val(data.hours + data.minutes/60); }
  }else { $("#message").text("Viga! " + data.reason); }
    })
    });
  });
</script>

Code: [Select]
This is before
$("<?php echo "#".$hours_difference; ?>").val(data.hours + data.minutes/60 - 0.5);

This is what im trying to get but its not working.
$("<?php echo "#".$hours_difference; ?>").val( round(data.hours + data.minutes/60 - 0.5), 2 );

Hey Everybody,

I was replying to someone elses question about number formatting and came up with a class that will format a number of any length with decimal or not, without rounding. It works perfectly, but after a comment by a noteworthy member my curiosity was aroused.

Is there an easier/faster/better way to achieve this??


My Object:

<?php

/*GHETTO NUMBER FORMATTER v1.0*/

class ghettoNumber {

private $input;
private $output;

public $whole;
public $decimal;
public $number;

function __construct($input){
$this->input = $input;
$this->output = $output;
$this->number = $number;
$this->whole = $whole;
$this->decimal = $decimal;
}

private function ghettoFormat(){

//Split number at the .(decimal)
$this->number = explode('.', $this->input);
//Define the whole number
$this->whole = $this->number[0];
//Format the whole number
$this->whole = number_format($this->whole, 0,'', ',');
//Define the decimal
$this->decimal = $this->number[1];
//Format the decimal
$this->decimal = rtrim($this->decimal, '0');

if(is_string($this->input)){
$this->output = $this->decimal != '' ? $this->whole.'.'.$this->decimal : $this->whole;
}
else{
$this->output = '<strong>ERROR:</strong> Input arg must be passed as type: <em>string</em>';
}

//Return result
return 'Original - '.$this->input.'<br>
  GhettoFormat - '.$this->output.'
<br><br>';

}

public function makeItGhetto(){
return $this->ghettoFormat();
}
}

?>


Sample Instantiation:

$ghettoFormat = new ghettoNumber('12565456565.123401201001210000');
                print $ghettoFormat->makeItGhetto();



I will reiterate my question once more...
Is there, in your opinion, a BETTER way to achieve this (number formatting w/o rounding)?

Thanks People,

E

I am very new to PHP and programming in general. About 3 weeks into this.
I have this simple expression and some echo in my code.

    $x1 = $lat_b + $lat_a1;
    echo "<br>lat b: ".$lat_b;
    echo "<br>lat a1: ".$lat_a1;   
    echo "<br>x1: ".$x1;

$lat_b and $lat_a1 are derived from some xml extractions from a yahoo geocode api (that part works fine).

The results of the expression and echos above are as follows:

    lat b: 40.402866
    lat a1: 40.252590
    x1: 80

Why is $x1 rounding automatically on me?

Later, I substituted the expression above with  $x1 = 40.402866 + 40.252590 ; The new result (shown below) makes sense to me.

   lat b: 40.402866
   lat a1: 40.252590
   x1: 80.655456

Bascially i add a couple numbers up and display the sum.

sometimes the number is something like this: 234.237

i want it to display : 234.24

i realize its needs "round()" in it but i dont know how to use it..

any help?

I need to round a number based on it's decimal. 3 or below should round down, 4 should round up to 5, 6 and 7 should round down to 5; 8 and 9 should round up to the next whole number.

The below is returning 3 from 2.16.
Code: [Select]
<?php
$a=2.16;
$i=round($a, 1);
$b=$i;

$i=explode(".", $a);
$decimal=$i[1];

if($decimal < 5){
$j=floor($b);
$i= $decimal > 3 ? $j + .5 : $j;
echo $i;
}
else{
$j=ceil($b);
$i= $decimal < 8 ? $j - .5 : $j;
echo $i;
}
?>

EDIT: The explode should have been on $i not $a.

$f15 = 0.345677 (output from sql data pull)

<?php echo number_format ($f15,3); ?>
 output = 0.345

<?php echo ltrim($f15,"0"); number_format ($f15,3); ?>
output = .345677

How do I combine these so that I am BOTH rounding the result AND trimming a leading zero?  Seems I can get one or the other, but not both.

Suggestions on the syntax?

Hello. This is my first post here. I am not an expert developer but I generally manage to do what is asked of me. However, now and then I'm stumped, like now...

I have an online database system for our company in which staff can enter JOB related data, this includes 2 dimensions which they enter in millimetres (mm).

Here's an example

$dimension1 might be entered as 850
$dimension2 might be entered as 1447
$square_metres is the value I need to calculate.

Firstly, I need to round both dimensions up to the next 100mm so the 850 in this example would become 900 and the 1447 would become 1500.

Once I've done that, I need to calculate the square metres (900mm x 1500mm / 1000 was my first thought) but that raised the second thing; adding a decimal point in the result. 900 x 1500 / 1000 = 1350 but I need the result to be 1.350

I know my way around basic PHP code but I'm no expert by any stretch.

If anyone can help me understand how to get this calculation done I would be hugely appreciative.

Thank you

Martin

HI. I have written a mysql database query to add up invoice totals. It seems to be automatilaly adding .01 to the result when I run a group by. Let me explain more ..   When I do a select on the field that I am adding up the result is $132.25 - the query is as follows select ttl_invoice_due from 65_it where st_id = 96011;   When I run the following query that uses sum and group by - the $132.25 becomes $132.26 - the sum query is   SELECT 65_st.job_compid, 65_client.uid_client,  65_client.comp_name, Sum(65_it.ttl_invoice_due) AS SumOftotal_due, Sum(65_it.ttl_invoice) AS SumOftotal_invoice, Sum(65_it.ttl_invoice_payments) AS SumOftotal_amnt_paid FROM 65_client INNER JOIN (65_st INNER JOIN 65_it ON 65_st.st_id = 65_it.st_id) ON 65_client.uid_client = 65_st.uid_client WHERE   65_st.uid_client = 1905 and 65_st.job_compid = 1 and 65_st.sales_date<=curdate() GROUP BY 65_st.job_compid, 65_client.uid_client HAVING (((Sum(65_it.ttl_invoice_due))<>0)) order by 65_client.comp_name;   The 65_it.ttl_invoice_due field is defined in the table as Double(12,2)   I dont know why the sum is returing $132.26 where it should be $132.25 as in the simple query ?.    

       

Hello,
I've had success creating a cool vanity QR code with rounded edges for my organization by generating a standard QR code, then applying a noise -> median effect in Photoshop to get the edges rounded among some other effects.



Photoshop is great, but I want to automate this. I found a great PHP library to generate QR codes. The part I don't get is the rounding of the hard edges.

I've seen other sites do it like this one.

So far google searches are yielding rounded corner tutorials. Any thoughts on how to do this with GD or ImageMagic?

Best regards,

Chris

Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment.

My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted."
The program should not accept any numbers greater than 100 or any characters.

Once I do this, I must take a second number and do a similar thing.

Finally, I must have a statement show up at the bottom stating which number is greater.

Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters.

Any help you can provide will be greatly appreciated!

I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here.  It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere.

<?PHP require('connect.php'); ?>

<form action ='' method='post'> <select name="id">

<?php
$extract = mysql_query("SELECT * FROM cars");
   
   while($row=mysql_fetch_assoc($extract)){
   $id = $row['id'];
   $make= $row['make'];
   $model= $row['model'];
   $year= $row['year'];
   $color= $row['color'];

echo "<option value=$id>$color $year $make $model</option>
";}?>

</select>

Which attribute would you like to change?<br />
<input type="radio" name="getchanged" value="make"/>Make<br />
<input type="radio" name="getchanged" value="model"/>Model<br />
<input type="radio" name="getchanged" value="year" />Year<br />
<input type="radio" name="getchanged" value="color"   />Color<br /><br />

   <br /><input type='text' value='' name='tochange'>
   <input type='submit' value='Change' name='submit'>

</form>

//This is where I need help...

<?PHP
if(isset($_POST['submit'])&&($_POST['tochange'])){
mysql_query("
   UPDATE cars
   SET '$_POST[getchanged]'='$_POST[tochange]'
   where id = '$_POST[id]'
         ");}?>

I have just re-installed Xampp and suddenly my sites are now displaying lots of:

Notice: Use of undefined constant name - assumed 'name' in ...
Notice: Use of undefined constant price - assumed 'price' in ...

this is an example of the line its refering too:

$defineProducts[1001] = array(name=>'This is a product', price=>123);