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PHP - Not Understanding A Line Of Code From A Simple Cms Program
Hello --
I'm trying to work through a very simple CMS that I found on the web (just for learning purposes). I need some help understanding this line: <table> <form method="POST" action="account.php?mode=save<?=( isset($_REQUEST['id']) ? "&id={$_REQUEST['id']}" : null )?> <? I understand the Method = "POST", but not the "action = " line. Thanks for any help. Similar TutorialsI recently converted my business to an ip-pbx that has lots of capabilites. Among them is a feature I would like to use called http_notify. It sends a post to a url with parameters such as caller id number, caller id name etc.. I need to write a simple program to accept these parameters and write them to a csv file along with a date/time stamp. This seems like a super easy, short piece of code to come up with and as a noob I was hoping to write this myself. I have found a few examples where the post is for a form but I can't find any examples where the data is coming in as part of the url. This is the description of the feature on the phone system site: HTTP Notify Sends notifications to a remote web server through a URL. This allows allows an event in a Jive Core PBX to trigger an action on a remote system. Simply enter a URL in the node, and that URL will be hit with an HTTP POST as calls 'pass through'. Multiple variables are available and all variables are also included in the post body. URL Defines the URL to be used (limit of 255 characters). Next Node Connects nodes together to create a call flow. Drag and drop on the next node in the dial plan. I'm just trying to incorporate some of what I've learned into practice and I can't believe I'm having problems with this but I really want to figure it out. I'm trying to create a simple program where a user enters the name of a song, and gives it a rating (out of 5), and it displays the output first by song rating then (if the ratings are the same) displays it by the name of the song alphabetically. The idea in practice would work like this...user enters: Quote Song Name: My Song Rating: 3 Song Name: His Song Rating: 5 Song Name: Her Song Rating: 5 Your list so far is: Her Song - 5 stars His Song - 5 stars My Song - 3 stars I just keep undoing things and clearly I'm not getting it. I had many ideas making it so I'll show you what I wrote (which isn't much): http://pastebin.com/2AGqgxQd It looks terrible I know, I was just trying to find out how to put things from the form INTO an array and trying to output the array as I described above. If I could figure out how to use these session arrays to hold the entries from the post, then I'd be able to sort them properly, I'm just lost right now because everything I've read online and tried wasn't fixing the problem. Thank you so much for the help! Hey guys. I have this code which connect me to the database and displays info in the web. However i do not understand a few lines of it. Code: [Select] <?php while ($query = mysql_fecth_assoc($result)) { $field01 = $result['Name']; $field02 = $result['Username']; ?> Can someone try to explain in they're own, simple words? Thank you. Full code. Code: [Select] <?php $dbhost = ""; $dbuser = ""; $dbpass = ""; $db = ""; $connection = mysql_connect($dbhost, $dbuser, $dbpass); mysql_select_db($db, $connection); $query = 'SELECT * FROM users'; $result = mysql_query($query); while ($query = mysql_fecth_assoc($result)) { $field01 = $result['Name']; $field02 = $result['Username']; echo $field01; echo $field02; } ?> Sorry for my noob question, I've learned about sessions a bit and tried to make a simple "game", basically a user has to enter one of the colors of the rainbow and after they name all 7, they win. Sounds simple enough, but I'm clearly making an obvious mistake and I've googled and read and experimented, but obviously something is alluding me. Here is the pastebin: http://pastebin.com/XmN4YLp8 I suppose what I want to know is...how do I store the values from the form (that is, $_POST['color']) and save that information to something like an array, because whatever I'm doing now is resetting the counter ($_SESSION['left']) and if a user guesses "red" for instance, it temporarily goes from 7 to 6, but then bumps up to 7? I want my application will send a email after 10 minutes of sending another email. In my application A user completes registration with payment Application sends the user a payment confirmation emailNow I want to send another email 10 minutes After payment confirmation email with welcome tipsBelow is the function where for user setup .
public function finishUserSetup($Sub){
if($Sub == 0){
$subscription = SubscriptionPlans::where('identifier', '=', "Monthly")->first();
$expiry = date('Y-m-d', strtotime('+' . $subscription->months . ' months'));
$sub_period = "monthly";
} else{
$subscription = SubscriptionPlans::where('identifier', '=', "Annually")->first();
$expiry = date('Y-m-d', strtotime('+' . $subscription->months . ' months'));
$sub_period = "annually";
}
$this->expiry_date = $expiry;
$this->user_type = "SUB";
$this->subscription_period = $sub_period;
$this->update();
$replaceArray = array(
'fullname' => $this->forename . " " . $this->surname,
'subscriptionName' => $subscription->name,
);
EmailTemplate::findAndSendTemplate("paymentconfirm", $this->email, $this->forename . " " . $this->surname, $replaceArray);
}
In the above function the last line of code is the one which sends a payment confirmation email to the user which is
EmailTemplate::findAndSendTemplate("paymentconfirm", $this->email, $this->forename . " " . $this->surname, $replaceArray);
I want to execute the following line of code 10 minutes after the above one
EmailTemplate::findAndSendTemplate("WelcomeTips", $this->email, $this->forename . " " . $this->surname, $replaceArray);
How to do that. that is running the last line of code 10 minutes after This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=350166.0 This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=327190.0
For example with an IDE to run a program is there a way to put some code in the path and let it tell me where it came from like a referral?
$ref = $_SERVER['HTTP_REFERER'];
echo("$ref<br>";
Result: https://www.mydomain.com/wp-admin/admin.php?page=lambo As you can clearly see the page that we have entered the code in is referred by the URL here. It tells me that it was last at a word press page /wp-admin/admin-php and I can go to that page and it will be the last page it was at.. So bottom line then if i add this code to the admin page and click the same button i had before.. it will tell me the file that called out the admin page. Baslcaly I am looking for ideas on how to track the page i am now all the way back to the page with the button on it and all intermediate pages that it passes thru to get to the final destination. It seems that to succesfully troubleshoot a fault is to follow the path of the entire job and see if any breaks... Any thoughts or suggestions on how to best do this would greatly be appreciated.
Hi all, I have a question. How do I put a new line in a script? I've tried everything. <?php $con = mysql_connect("localhost","*","*"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("my_db", $con); $sql="SELECT * FROM People WHERE FirstName='Borko' AND LastName='Borkov'"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Found!"; echo($sql); mysql_close($con) ?> I wrapped it in <html> and so on, <br /> doesn't work. Saved it in html, <br /> still doesn't work and the script doesn't execute. The output I get right now is Quote Found!SELECT * FROM People WHERE FirstName='Borko' AND LastName='Borkov' I want it to display Quote Found! SELECT * FROM People WHERE FirstName='Borko' AND LastName='Borkov' And another question - how can I see what the sql variable is searching for from the browser? For now, as you have seen, I just use the echo($sql) but it doesn't quite cut it - is there a way to see just FirstName and LastName without the whole code? I tried echo($sql [FirstName] [LastName], as you've already guessed it didn't work... A hint would also be greatly appreciated! Any help on these two issues? Is there a simple way getting PHP to open a single file and write to a specific line? Like: fwrite (line = 102) {"bla bla bla"}; fclose; Hi All, I'm trying to debug my first few lines of PHP where I have all my "checks" to make sure someone is logged in. I have this code all by itself and it is still not executing. This is the only page that I'm having trouble with. header('Location: login.php?logout=1'); PHP = 5.5.14
MySQL = 5.2.17
I've cloned a mysqli_connect() statement in a 'require' file placed in a non-public access location on the server. It's the same format (and location) currently working fine with another application, EXCEPT i changed the database name to what I need to use for this application, AND added the $con= part on the front end to substitute for the commented out $con= line in the example code I'm modifying to insert data into a new MySQL DB Table.
The dB Table is fine and I have Inserted data via myPHPAdmin with no problems. Only two form variables are in the simple PHP script thus far just to test if it will work before proceeding.
I've used pseudonames for the actual /home/.... location and filename, and am now Baffled about the Line 2 Error Message I'm getting (below the code).
<?php
require '/home/myusername/domains/mydomain.com/myclonedrequire.php';
//$con=mysqli_connect("example","uid","pwd","my_db");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// escape variables for security
$year = mysqli_real_escape_string($con, $_POST['year']);
$callsign = mysqli_real_escape_string($con, $_POST['callsign']);
$sql="INSERT INTO `lqplogs` (`year`, `callsign`)
VALUES ('$year', '$callsign');
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
}
echo "1 record added";
mysqli_close($con);
?>
ERROR Message:
Warning: Unexpected character in input: '\' (ASCII=92) state=1 in (above file & location) on line 2
There are NO '\' characters in any of my files.
Here is the simple Form file code:
<?php ?> <html: <head><title></title></head> <body> <form action="insert.php" method="post"> YEAR: <input type="text" name="year"> CALLSIGN: <input type="text" name="callsign"> <input type="submit"> </form> </body> </html> <?php ?>Thanks for any assistance! -FreakingOUT Can you suggest a better way to write this code (I didn't create it):
<body onload="getParameterByName('url')">
<a href="" id="urllink" >Click Here</a>
</body>
so, I don't have to change the <body> tag?
Hi, can any see is the are mistakes in this for me. Thanks echo'<img src="skinFiles/'.$skin['thumb_name'].'"class="skinImage" onclick="changeSkin(\'skinFiles/'.$skin["css_name"].'\')" />'; ok, this is a much shorter version, but i have: Code: [Select] $val = "1"; then i have a function Code: [Select] function include_function_name{ echo' <ul><li> <a href="index.php?pageID="{$val}"">page name</a> <li/><ul/>'; } i have tried all sorts of variations but i can get it to make pageID=1 plaease help thanks ricky for timthumb in my wordpress i use this code to function first_image() { global $post, $posts; $first_img = ''; ob_start(); ob_end_clean(); $output = preg_match_all('/<img.+src=[\'"]([^\'"]+)[\'"].*>/i', $post->post_content, $matches); $first_img = $matches [1] [0]; if(empty($first_img)){ //Defines a default image $first_img = "images/default.gif"; } return $first_img; } it works really well, then i thought why not to make it show random images if timthumb dont find any image? so the 1st googling i did came up with this function: <?php function getRandomFromArray($ar) { mt_srand( (double)microtime() * 1000000 ); $num = array_rand($ar); return $ar[$num]; } function getImagesFromDir($path) { $images = array(); if ( $img_dir = @opendir($path) ) { while ( false !== ($img_file = readdir($img_dir)) ) { // checks for gif, jpg, png if ( preg_match("/(\.gif|\.jpg|\.png)$/", $img_file) ) { $images[] = $img_file; } } closedir($img_dir); } return $images; } $root = ''; // If images not in sub directory of current directory specify root //$root = $_SERVER['DOCUMENT_ROOT']; $path = 'images/'; // Obtain list of images from directory $imgList = getImagesFromDir($root . $path); $img = getRandomFromArray($imgList); ?> and to show random image i Place the following where i wish the random image to appear: Code: [Select] <img src="<?php echo $path . $img ?>" alt="" /> my question is how to place this code in my function first_image?? i need to do something like this, but it doesnt make any sense: if(empty($first_img)){ //Defines a default image $first_img = " <img src="<?php echo $path . $img ?>" alt="" /> this was my thought, if i can mix those 2 normally it should work, right? or maybe there is another way to show random image in the Code: [Select] [i] if(empty($first_img)){ //Defines a default image[/i] [b] $first_img = ? How do I remove the captcha check on this line and keep it valid? if ($author && $message && ($capatcha == 6 || controlPosts::isAdmin())) I tried if ($author && $message && (controlPosts::isAdmin())) but the script wont post like this? I looked up 'how to get all POST variables' and I ended up putting this bit of code together. Im not experienced at all with OOP programming, but I think that when '=>' is used its to do with OOP? Anyway. I dont get this code. I understand Foreach $_POST, as $someVar, (BTW im looking for checkboxes from a form), However, If I leave out the '=> $val' I simply get a lot of 'on' values, indicating the checkboxes I checked. However, WITH the '=> $val' I end up with the checkbox name. Now i've changed the name of '$val' so i know its not a keyword. But i dont get it. Is there a way to access the value of the checkbox? Can someone explain to me whats going on here? I know that I can get the value of the checkbox by $_POST['$checkRows'] But, I have a feeling It can be done in the foreach line. foreach($_POST as $checkRows => $hip) { echo "POSTED: $checkRows<br>\n"; } Please help! can anyone help me with an overwhelming problem ? I want to use this command in the php curl code. curl -v --data "WSCommunityStringRW?2=1200ve50set&Submit=Submit" http://10.2.3.111/Forms/SnmpCommunityString -u "admin:a1s2d3" --anyauth I'm using a templated PHP script and have successfully added a link (to an image) |
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