PHP - Syntax Error, Unexpected T_string

When I try to run a program, I am getting an error message. Not sure why

and the code that has the error is shown below. Error message is syntax error, unexpected T_STRING

setcookies("username","$username",time()+86400);

Well sorry to bother you guys with this seemingly stupid problem. I have a file hmgc.php from a friend, and I try to modify the codes myself to add some sort of features to my site. Unfortunately, I am unable to proceed because of this error:

Quote

Parse error: syntax error, unexpected T_STRING in /home7/pkmnhofc/public_html/adoptables/hmgc.php on line 115



The file is attached in this message already, please take a look at it and tell me what exactly was wrong? I tried to add another if-elseif-else statement within an else statement, may this be a problem? Also this is the scripts around line 115 looks like:


if($act == "2"){
  $query = "SELECT * FROM ".$prefix."user_inventory WHERE item_owner='$loggedinname' and item_name='Old Rod'";
  $result = mysql_query($query);
  $num = mysql_numrows($result);
  
  if($num == 0){
   $article_title = "Oops it appears that you do not have an Old Rod yet...";
   $article_content = "<center><table style='color: #FFFF31; background: Green; width: 400px; border: 1px solid #9BDDFF;'><tr><td>
   It seems that you do not have an Old Rod in your inventory yet, are you sure it is the best choice for you to fish without a rod?<br><br>
   To fix this issue, simply go back and take Fishing Quiz. You syhould be able to acquire an Old Rod for yourself if you answer all these
   questions successfully. Trust me, they aint really hard at all if you know something about pokemon and the fishing mechanism already.<br>
   <br><a href='fishingquiz.php'>Take the Fishing Quiz now!!!</a> 
  }
  
  else{
   $randnum1 = rand(1, 500);

    if($randnum1 >= 1 and $randnum1 < 225){
      $article_title = "You got a Magikarp";
      $article_content = "<center><table style='color: #b60400; background: black; width: 400px; border: 1px solid #b60400;'><tr><td><br><br>
      Now is your chance to adopt a wild Magikarp!</td></tr></table></center>";

      }
      else if($randnum1 >= 225 and $randnum1 < 250){
      $article_title = "You got a Goldeen";
      $article_content = "<center><table style='color: #b60400; background: black; width: 400px; border: 1px solid #b60400;'><tr><td><br><br>
      Now is your chance to adopt a wild Goldeen</td></tr></table></center>";

      }
      else{
      $article_title = "Not even a bite";
      $article_content = "<center><table style='color: #b60400; background: black; width: 400px; border: 1px solid #b60400;'><tr><td><br><br>
      Too bad you got nothing...</td></tr></table></center>";

      } 
  }
}



Thank you so much for reading this thread, I appreciate it a lot.

Hi everyone,    I am fairly new to PHP coding, and I am attempting to write a script that reads entries from a contact entry from and adds them to a database. However I keep receiving an error that states:   " Parse error: syntax error, unexpected 'name' (T_STRING), expecting ']' in C:\wamp\www\it665\addContact.php on line 16"   I have been trying to figure out what I am missing, or need to remove, and I am having the hardest time. Below is the entire code for the addContact.php script that I keep receiving this error for. I would really appreciate any feedback.   <?php

Hi folks,

I am a complete n00b at php and mysql. I am teaching myself from books and the WWW, but alas I am stuck...

the error I get is:
Parse error: syntax error, unexpected T_STRING in X:\xampp\htdocs\search.php on line 7

here is the code:




<?php
  
  mysql_connect ("localhost", "user", "password") or die (mysql_error());
  mysql_select_db ("it_homehelp_test") or die (mysql_error());
  
  $term = $_POST['term'];
  $sql = $mysql_query(select * from it_homehelp_test where ClientName1 like '%term%');   <<<------this is line 7
  while ($row = mysql_fetch_array($sql)){
   echo 'Client Name:' .$row['ClientName1'];
echo 'Address:' .$row['Address1'];
echo 'Phone:' .$row['Tel1'];
}
?>



Any help you can offer would be great. I can also post the ".html" file that creates the search bar if it is needed.

Thanks

Hello everyone,
I am a total newbie in PHP and so do here. I am trying to build a table consisting foreign key and primary key and it is showing error like "Parse error: syntax error, unexpected 'cities' (T_STRING) in line number 29". I have marked up my lines according to sublime text 3 editor. I am trying to create a database. 

 

1 <?php
2 $servername = "localhost";
3 $username = "username";
4 $password = "password";
5 $dbname = "newDB";

7 // Create connection
8 $conn = new mysqli($servername, $username, $password, $dbname);

10 // Check connection
11 if ($conn->connect_error) {
12   die("Connection failed: " . $conn->connect_error);}

14 $firstname = $conn->real_escape_string($_REQUEST['firstname']);
15 $lastname = $conn->real_escape_string($_REQUEST['lastname']);
16 $address = $conn->real_escape_string($_REQUEST['address']);
17 $city = $conn->real_escape_string($_REQUEST['city']);
18 $country = $conn->real_escape_string($_REQUEST['country']);
19 $phone_number = $conn->real_escape_string($_REQUEST['phone_number']);
20 $email = $conn->real_escape_string($_REQUEST['email']);
 
22 // Attempt insert query execution
23 $sql1 = "INSERT INTO cities VALUES ('$city')";

25 $sql2 = "INSERT INTO countries VALUES ('$country')";

27 $sql3 = "INSERT INTO Contacts (firstname, lastname, address, city, country, phone, email) VALUES ('$firstname', '$lastname', '$address', $city, $country, '$phone_number','$email')";

29 SELECT * FROM cities;
SELECT * FROM countries;
SELECT * FROM Contacts;

if($conn->query($sql1) === true){
    echo "City added successfully.";
} else{
    echo "ERROR: Could not able to execute " . $conn->error;
}

if($conn->query($sql2) === true){
    echo "Çountry added successfully.";
} else{
    echo "ERROR: Could not able to execute " . $conn->error;
}

if($conn->query($sql3) === true){
    echo "Çontact added successfully.";
} else{
    echo "ERROR: Could not able to execute " . $conn->error;
}
 
// Close connection
$conn->close();
?>