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PHP - Simple Php Form To Insert Into Mysql
Alright so I am trying to code a very simple form that adds a user to my SQL database with certain information filled in and certain information kept hidden with default values in a form.
My index.php file is as follows (not all of the code but just the form part): <?PHP $submitMessage = $_GET['value']; if ($submitMessage == success) { echo '<div class="congratulations"><font color="#84d20c"><strong>Congratulations:</strong></font> The user has been added.</div>'; }else if($submitMessage == NULL){ }else if($submitMessage == fail){ echo '<div class="error"><font color="#d3430c"><strong>Error:</strong></font> An error occurred please check the error details below:</div>'; echo 'ERROR DETAILS:'; echo mysql_error(); } ?> <h1><i>Add User</i></h1> <p>This page is where you would manually add a user to the donations databases (for example you or a member of the community with elevated status that does not need to pay).</p> <br/> <form enctype="multipart/form-data" action="scripts/admin_save_sm_db.php" method="post"> <input name="authtype" value="steam"/><br /><br /> <h3><i>STEAM ID:</i></h3> <input name="identity" value="STEAM_0:X:XXXXXXXX"/><br /> <div class="form_help">Steam ID of the player you wish to add. Must be in the format STEAM_0:X:XXXXXXXX</div><br /> <input name="flags" value="o"/><br /><br /> <input name="name" value="Donator"/><br /><br /> <input name="immunity" value="0"/><br /><br /> <h3><i>Your Email Address</i></h3> <input name="user_email"/><br /> <div class="form_help">Your Email Address for security purposes.</div><br /> <input name="Submit" type="submit" value="Submit" class="form_submit" /> </form> My admin_save_sm_db.php file is as follows: <?php session_start(); if(!isset($_SESSION["username"])) { header('Location: login.php'); exit; } @require("../sm_admin_db.php"); $authtype = $_POST['authtype']; $identity = $_POST['identity']; $flags = $_POST['flags']; $name = $_POST['name']; $immunity = $_POST['immunity']; $user_email = $_POST['user_email']; $link = @mysql_connect(_HOST,_USER,_PASS); @mysql_select_db(_DB); $sql = @mysql_db_query(_DB,"INSERT INTO "._TBL." (`authtype`, `identity`, `flags`, `name`, `immunity`, `user_email`) VALUES (NULL, '$authtype', '$identity', '$flags', '$name', '$immunity', '$user_email')"); $okay = @mysql_affected_rows(); if($okay > 0) { header( "Location: ../index.php?value=success" ); } else { header( "Location: ../index.php?value=fail" ); } @mysql_close($link); ?> And finally my sm_admin_db.php file is as follows: <?PHP //host loaction define("_HOST", "localhost", TRUE); //database username define("_USER", "thatsact_admin", TRUE); //database username`s password define("_PASS", "*********", TRUE); //database name define("_DB", "thatsact_sadadmins", TRUE); //database table name change this to install multiple version on same database define("_TBL", "sm_admins", TRUE); //This is the email that you will recieve emails when someone signs up. define("_EMAIL", "admin@tag-clan.com", TRUE); ?> All of this together does not work and gives the echo error code, however the mysql_error() string does not return anything. Nothing is inserted into the database. Can I get some help on where I went wrong and please keep in mind I am VERY new to php and didn't write most of this script so just tell me what to edit and exactly how to do it please. Thanks in advance. Similar TutorialsI have a form that submits a record and saves it to the database, I've got that working already, I'm trying to figure out if there is a cleaner way to delete a record with a button that gets a value from the unique key, in this case 'id' here is how the delete button looks like: // get info from table $query = "SELECT id, Title, Message FROM table_name"; $result = mysql_query($query); //displaying all data while($row = mysql_fetch_assoc($result)) { echo" <div class='status'><h3>{$row['Title']} <br></h3>" . " <h5>{$row['Message']} <br><br></h5>"; $id = $row['id']; //trying to get unique key from database //delete button echo "</div> <form action='delete.php' method='post' /> <input type='hidden' name='delete' value='yes' /> <input type='hidden' name='id' value='$id' /> <input type='submit' value='remove' /></form>"; } As you can see, i'm trying to give $id a unique value but for some reason i'm not getting it. The delete.php code looks like this: if (isset($_POST['delete']))// check if delete was clicked { $query = "DELETE FROM table_name WHERE id='$id'"; echo "$id Deleted successfully"; } elseif(!mysql_query($query, $db_server)) { echo "DELETE failed: $query<br />" . myql_error() . "<br /><br />"; } mysql_close(); I'm new to php and still learning so, if you think there are other ways to do this, please let me know, the button won't do anything to the data. Thanks in advance Hi,
I created a form that inserts first - last name, address, and email address into a mysql databse table.
The record inserts correctly - No problems here.
The problem is I only want to insert the data if the email and address doesn't exist.
I set it up for just the email right now to try to get this to work but have failed.
When the form is submitted and the record exists it inserts the record anyway and sends the email which it's not suppose to do.
The form is suppose to after submitting -
1. validate
2. insert only if the record doesn't exist
3. send the email.
Here's the code
<?php
$to = "email@email.com";
if(isset($_POST['submit']))
{
// VALIDATION
if(empty($_POST['firstName']))
{
$errorfirstName .= "First Name Required";
}
if(empty($_POST['lastName']))
{
$errorfirstName .= "Last Name Required";
}
if(empty($error)) # No error go ahead and email it.
{
$to = "$to";
$subject = 'the form';
$msg .="<html><head>
<meta http-equiv='Content-Type' content='text/html; charset=utf-8' />
<title>The Form</title>
</head>
<body>
<table>
<tr>
<td>Email sent for confirmation</td>
</tr>
</table>
</body>
</html>";
$mail($to, $subject, $headers, $msg);
if(!$result)
{
$error = "<div id='errors'>There was an unknown error </div>";
}
else
{
include('connection.php');
$firstName = mysqli_real_escape_string($con, $_POST['firstName']);
$lastName = mysqli_real_escape_string($con, $_POST['lastName']);
$address = mysqli_real_escape_string($con, $_POST['address']);
$email = mysqli_real_escape_string($con, $_POST['email']);
$email = $_POST['email'];
$sql = "SELECT * FROM table WHERE `email` = '{$email}'";
$result = mysql_query($sql);
if ( mysql_num_rows ( $result ) > 0 )
{
$error = "Email Exists.";
}
else
{
$error = "Email does not exist. Insert it!!!";
$sql="INSERT INTO table (firstName, lastName, address, email) VALUES ('$_POST[firstName]','$_POST[lastName]','$_POST[address]', '$_POST[email]')";
}
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error($con));
}
mysqli_close($con)
{
}
}
}
}
?>
<!-- Form -->
<html>
<head></head>
<body>
<section>
<form method="POST" action="theform" name="for" onsubmit="return validateForm(this)">
<?php
if(!empty($error))
{
echo "$error";
}
?>
This where the inputs would go not going to include them because not having an issue with the form
</form>
</section>
</body>
</html>
Edited by barkly, 26 October 2014 - 06:54 PM. Hi. I'm making a private webpage for my self where i can post news, games, music titles and movies. I'm made it so that i can post and delete them from my page. Also i wanted to have the option to edit them. So i made a action that shows me a list og the posts in each category. And then i want the option to hit UPDATE, and then it should open the form with the info's from MySQL. I've made those two options as the following: Code: [Select] elseif ( $action == "EditNews" ) { // EDIT NEWS START if ( !$_GET['id'] ) { ?> <div id="content"> <?php $sql = mysql_query("SELECT * FROM news") or die(mysql_error()); while ( $row = mysql_fetch_assoc($sql) ) { echo "<a href=\"?page=Admin&action=UpdateNews&id=" . $row['news_id'] . "\">Update</a> | " . $row['subject'] . "<br>"; } echo "</div>"; } else { $type = $_GET['type']; $id = $_GET['id']; } // EDIT NEWS END } elseif ( $action == "UpdateNews" ) { // UPDATE NEWS START if ( !$_POST['submit'] ) { $id = $_GET['id']; $sql = mysql_query("SELECT * FROM news WHERE news_id='$id'") or die(mysql_error()); $user_id = $_SESSION['uid']; $subject = $_row['subject']; $body = nl2br($_row['body']); ?> <div id="content"> <form action="?page=Admin&action=EditNews" method="post"> <div id="">Subject</div> <div id=""><input id="input" type="text" name="subject"></div> <div id="">Message</div> <div id=""><textarea id="input" name='body' cols='15' rows='4'></textarea></div> <div id=""><input id="submit" class="input" type="submit" name="submit" value="Post News"></div> </form> </div> <?php } else { ?> <div id="content">Not Working!</div> <?php } // UPDATE NEWS END } - I know i miss something, but i've tried to get to the point, where i only have the form as blank, and need some help from there. I hope someone can help me with my problem. MOD EDIT: [code] . . . [/code] tags added. Need a little help with this code. I'm running Apache 2.21 / PHP 5.3.5 on Windows. This is a V6 application. I am running Windows 7. I am new, and trying to learn. What am I doing wrong in line 8 with the 'if' statement? The idea is to create a table in mySQL using a form interface. Thank you in advance. Parse error: syntax error, unexpected '{' in C:\website\do_createtable.php on line 8 <? $db_name="booster"; $connection=mysql("localhost", "user", "password") or die (mysql_error()); $db=mysql_select_db($db_name, $connection) or die (mysql_error()); $sql="CREATE TABLE $_POST[table_name] ("; for ($i=0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] != "" { $sql .= " (".$_POST[field_length][$i]."),"; } else { $sql .= ","; } } $sql=substr($sql,0,-1); $sql .= ")"; hello i have a db with name which populates a form dropdown list there are various variables like this in the form. the user selects their choices and then submits the form to a new db table at the moment it does not capture the dropdown data to the insert sql help please here is the code: =============================== <?php include ('connect.php'); // Insert any new image into database if(isset($_POST['xsubmit']) && $_FILES['imagefile']['name'] != "") { $fileName = $_FILES['imagefile']['name']; $fileSize = $_FILES['imagefile']['size']; $fileType = $_FILES['imagefile']['type']; $content = addslashes (file_get_contents($_FILES['imagefile']['tmp_name'])); $jeweltype = $_POST['jeweltype']; $jewelsize = $_POST['jewelsize_in']; $jewelcolour = $_POST['jewelcolour_in']; $jewelmaterial = $_POST['jewelmaterial_in']; $jewelgender = $_POST['jewelgender_in']; if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); } // Checking file size if ($fileSize < 150000) { mysql_query ("INSERT into jewel_images (name,size,type,content,jeweltype,jewelsize,jewelcolour,jewelmaterial,jewelgender) " . "values ('$fileName','$fileSize','$fileType','$content','$jeweltype','$jewelsize','$jewelcolour','$jewelmaterial','$jewelgender')"); } else { $err = "The Image file to too large!"; } } // Find out about latest image $gotten = mysql_query("select * from jewel_images order by row_id desc"); $row = mysql_fetch_assoc($gotten); $bytes = $row['content']; // If this is the image request, send out the image if ($_REQUEST['pic'] == 1) { header("Content-type: $row[type];"); print $bytes; } ?> <html> <head> <title>Upload an image to a database</title> </head> <body> <font color="#FF3333"><?php echo $err ?></font> <table> <form name="Upload" enctype="multipart/form-data" method="post"> <tr> <td>Upload <input type="file" name="imagefile"><br /> Jewelery Type: <select> <?php $sql="SELECT jeweltype FROM jeweltypes"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jeweltype" ><?php echo $data['jeweltype'] ?></option> <?php } ?> </select> <br /> Jewelery Size: <select> <?php $sql="SELECT jewelsize FROM jewelsizes"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelsize" ><?php echo $data['jewelsize'] ?></option> <?php } ?> </select> <br /> Jewelery Colour: <select> <?php $sql="SELECT jewelcolour FROM jewelcolours"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelcolour_in" ><?php echo $data['jewelcolour'] ?></option> <?php } ?> </select> <br /> Jewelery Material: <select> <?php $sql="SELECT jewelmaterial FROM jewelmaterials"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelmaterial_in" ><?php echo $data['jewelmaterial'] ?></option> <?php } ?> </select> <br /> Jewelery Gender: <select> <?php $sql="SELECT jewelgender FROM jewelgenders"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelgender_in" ><?php echo $data['jewelgender'] ?></option> <?php } ?> </select> <br /> <input type="submit" name="xsubmit" value="Upload"> </td> </tr> <tr> <td>Latest Image</td> </tr> <tr> <td><img src="?pic=1"></td> </tr> </form> </table> </body> </html> Not sure exactly what my problem is here, but i have looked at this at least a hundred times and I just can't figure out what is going on. Everything works great except for the sending the email part. It displays the error "There was a problem sending the mail". The form field checking works fine, the insert into mysql works fine - - but it won't send the email. I have tried using double quotes and single quotes for the email information ($to, $subject, etc...) I have even eliminated the form data from the email information and it still doesn't send. I am hopelessly stuck at this point Any ideas?? Code below: <html> <body bgcolor = 'blue'> <div align = 'center'> <h1>test FORM</h1> </div> <p> <?php If ($_POST['submit']) //if the Submit button pressed { //collect form data $fname = $_POST['FName']; $lname = $_POST['LName']; $email = $_POST['Email']; $tel = $_POST['Tel']; $mess = $_POST['Mess']; $errorstring = ""; if (!$fname) $errorstring = $errorstring."First Name<br>"; if (!$lname) $errorstring = $errorstring."Last Name<br>"; if (!$email) $errorstring = $errorstring."Email<br>"; if ($errorstring !="") echo "<div align = 'center'><b>Please fill out the following fields:</b><br><font color = 'red'><b>$errorstring</b></font></div>"; else { $fname = mysql_real_escape_string($fname); $lname = mysql_real_escape_string($lname); $email = mysql_real_escape_string($email); $tel = mysql_real_escape_string($tel); $mess = mysql_real_escape_string($mess); $con = mysql_connect("localhost","user","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mec", $con); $sql="INSERT INTO formtest (FName, LName, Title, Tel, Email, Mess) VALUES ('$fname','$lname','$title','$tel','$email','$mess')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } $to = 'myemailaddress'; $subject = 'test form'; $message = 'Hello'; $headers = 'From Me'; $sent = mail($to, $subject, $message, $headers); if($sent) {print "Email successfully sent";} else {print "There was an error sending the mail";} mysql_close($con); } } ?> <p> <form action= 'testmecform.php' method= 'POST'> <table width = '640' border = '0' align = 'center'> <tr> <td align = 'right'><b>First Name</b></td> <td><input type = 'text' name = 'FName' value = '<?php echo $fname; ?>' size = '25'></td> <td><div align = 'right'><b>Telephone</b></div></td> <td><input type = 'text' name = 'Tel' value = '<?php echo $tel; ?>' size = '25'></td> </tr> <tr> <td align = 'right'><b>Last Name</b></td> <td><input type = 'text' name = 'LName' value = '<?php echo $lname; ?>' size = '25'></td> <td> </td> <td> </td> </tr> <tr> <td align = 'right'><b>Email</b></td> <td><input type = 'text' name = 'Email' value = '<?php echo $email; ?>' size = '25'></td> <td> </td> <td> </td> </tr> <tr> <th colspan = '4'><b>Please enter any additional information he </b></th> </tr> <tr> <th colspan = '4'><textarea name = 'Mess' cols = '50' rows = '10'><?php echo $mess; ?></textarea></th> </tr> <tr> <th colspan = '4'><b>Please make sure all information is correct before submitting</b></th> </tr> <tr> <th colspan = '4'><input type = 'submit' name = 'submit' value = 'Submit Form'></th> </tr> </table> </form> </body> </html> Hi Folks,
Firstly I am new, I have read several topics here and learned a lot, I would class myself as 'slightly better than basic', but my knowledge is mostly gained from reading code.
I am making a simple POST form for work, the data gets inserted into MySQL, nice and easy, I can make it work if I write out the statement completely, BUT I need to make a new form, it will have HUNDREDS of input fields, I really don't want to write the code, and I figured programmatically is a good way to go anyway as forms change and new forms may be required, so I set about building a function to completely handle my post data, bind it to a statement and insert it into a table, I have scrapped it a half dozen times already because something fundamentally doesn't work, but I am very close! The function can write the statement, but I need to bind the POST values before I can insert, something going wrong here and I would appreciate some help, I have a feeling it's a problem with an array, but anyway I will show you what I have, give you some comments as to my reasoning, and hopefully you can help me with the last bit
public function getColumnNames($table){
$sql = "SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE table_name = :table";
try {
$stmt = $this->dbh->prepare($sql);
$stmt->bindValue(':table', $table, PDO::PARAM_STR);
$stmt->execute();
$output = array();
while($row = $stmt->fetch(PDO::FETCH_ASSOC)){
$output[] = $row['COLUMN_NAME'];
}
$all = array($output);
$a1 = array_slice($output, 1); // I don't want column 1, it contains the ID, its auto incremented.
$a2 = array_slice($a1, 0, -3); // I don't want the last 3 columns as they have default values
$selected = array($a2); // contains all the columns except those excluded by array_slice, columns now match all of the input fields on the form
foreach ($selected as $row){
$fields = "`" . implode('`, `', $row) . "`"; // I'm making `fields` here,
$bind = ":" . implode(', :', $row); // And making :values here
}
return array (
"raw" => $all,
"fields" => $fields,
"bind" => $bind
);
}
catch(PDOException $pe) {
trigger_error('Could not connect to MySQL database. ' . $pe->getMessage() , E_USER_ERROR);
}
}
public function addRecord(){
$col = array();
$col = $this->getColumnNames("table");
$raw = array($col['raw']);
$fields = array($col['fields']);
$bind = array($col['bind']);
$columnList = implode('`, `', $fields);
$paramList = implode(', ', $bind);
$sql = "INSERT INTO `{$this->dbtable}` ($columnList) VALUES ($paramList)";
return $sql; // this returns something like:
INSERT INTO `table` (`field1`, `field2`, `field3`) VALUES (:field1, :field2, :field3)";
perfect I thought, now I just need to bind the values from $_POST... then I get stuck.
Edited by luke3, 08 January 2015 - 12:10 PM. Hi, I m doing some work for my self an because of that i been reading a lot arround about PHP, and theres something that i would like to ask a bit of enlightenment. So my question is as the title says about html form's using php to insert data into mysql, i been reading tutorials arround the interwebs and even made afew successful tests, but pretty much all tutorials use 2 files to accomplish this the html file with the form and an insert.php where the actual code is stored so this made me think is this how usually it's done? in over all you will have 1 file for the form, 1 for the insert, 1 for the edit php code and 1 for delete. How do you guys usually do it? PS: one of the tests i did was making 1 single file with all these using an switch. My interest in making this question is solo to learn how other people do it to see if i m in the right way. Thanks in advance. Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Hello, I'm having a bit of a problem here, all help to this issues would be much appreciated I am trying to use text boxes to insert numbers into the database based on what is inputed. If I have a string, like this for example: $variable = 09385493; And I want to insert it into the database like this: mysql_query("INSERT INTO integers(number) VALUES ('$variable')"); When checking the integers table in my database, looking at the number field, the $variable that was inserted is outputted as 9385493 Notice the number zero was taken out of the front of the number. If the number is double 0's (009385493), both of those zero's would disappear, too. Thanks Im sure this is simple, but I cannot see what my problem is! I am hitting an error on my insert query Code: [Select] Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1 I know the output of $user_id is 1, so my error is on $mysavepath Code: [Select] $mysavepath = $folder.'/'.$worldname.'_'.date("dMjY"); echo $mysavepath; $savepath = mysql_query("INSERT INTO saves (user_id,savepath) VALUES ('$user_id','$mysavepath')"); echo '<br>'.$savepath; if(!mysql_query($savepath)) { die('<br>Error: ' . mysql_error()); } however it all echos out ok? Code: [Select] 188ea678f0dcdc8252aeb15e3c910408/world_15Jan152012 1 Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1 Can anyone see the problem? Cheers Dave Hi Guys, in code below i dont see any reason why it doesnt add anything into my mysql, can u please tell me where is wrong? <?php session_start(); include ("includes/db.php"); include ("includes/function.php"); //authentication if (loggedin()==FALSE) { Header("Location: login.php"); exit(); } //username session $_SESSION['username']=='$username'; $username=$_SESSION['username']; echo "Welcome, " .$_SESSION['username']."!<p>"; //get details from user table to be passed to page(text fields) $getdetails=mysql_query("SELECT * FROM users WHERE username='$username'"); while($row = mysql_fetch_array($getdetails)) { $users_id=$row['id']; $first_name=$row['first_name']; $last_name=$row['last_name']; $email=$row['email']; } /////////////////////////////////////// //****************************// //post starts here if (isset($_POST['next']) && $_POST['next']) { $myfirstname = addslashes(strip_tags($_POST['firstname'])); $mylastname = addslashes(strip_tags($_POST['lastname'])); $myemail = addslashes(strip_tags($_POST['email'])); $mybookingdate = addslashes(strip_tags($_POST['datetime'])); $mytime = addslashes(strip_tags($_POST['time'])); $myseatnumber = addslashes(strip_tags($_POST['seatnumber'])); $ride_id=1; //check if booking exists $checkbooking=mysql_query("SELECT * FROM booking WHERE date='$mybookingdate' AND time='$mytime' AND seat_no='$myseatnumber'"); if (mysql_num_rows($checkbooking)>=1) { echo "Seat No $myseatnumber For $mybookingdate at $mytime has been already taken, Please try a different seat, time or date"; } else { $addbooking=mysql_query("INSERT INTO booking (ride_id, users_id, time, date, seat_no) VALUES ('$ride_id','$users_id','$mytime','$mybookingdate','$myseatnumber'"); } } ?> <html> <head> <link type="text/css" href="css/smoothness/jquery-ui-1.8.6.custom.css" rel="stylesheet" /> <script type="text/javascript" src="includes/jquery-1.4.2.min.js"></script> <script type="text/javascript" src="includes/jquery-ui-1.8.6.custom.min.js"></script> <script type="text/javascript"> $(function() { $('#datetime').datepicker({ dateFormat: 'dd.mm.yy' }); }); </script> </head> <body> <form name="booking" method="post" action=""> <p>First Name:<br /> <input type="text" name='firstname' value="<? echo "$first_name";?>"> <p>Last Name:<br /> <input type="text" name='lastname' value="<? echo "$last_name";?>"> <p>Email:<br /> <input type="text" name='email' value="<? echo "$email";?>"> <p>Choose a Date:<br /> <input type="text" name='datetime' id="datetime"> </p> <p> Select a Time:<br/> <select name='time'> <option value="9:00">9:00 <option value="9:07">9:07 <option value="9:14">9:14 <option value="9:21">9:21 <option value="9:28">9:28 <option value="9:35">9:35 <option value="9:42">9:42 <option value="9:49">9:49 <option value="9:56">9:56 <option value="10:03">10:03 <option value="10:10">10:10 <option value="10:17">10:17 <option value="10:24">10:24 <option value="10:31">10:31 <option value="10:38">10:38 <option value="10:45">10:45 <option value="10:52">10:52 <option value="10:59">10:59 <option value="11:02">11:02 <option value="11:09">11:09 <option value="11:16">11:16 <option value="11:23">11:23 <option value="11:30">11:30 <option value="11:37">11:37 <option value="11:44">11:44 <option value="11:51">11:51 <option value="11:58">11:58 </select> </p> <p> Select Seat Number:<br/> <select name='seatnumber'> <option value="1">Seat 1 <option value="2">Seat 2 <option value="3">Seat 3 <option value="4">Seat 4 <option value="5">Seat 5 <option value="6">Seat 6 <option value="7">Seat 7 <option value="8">Seat 8 <option value="9">Seat 9 <option value="10">Seat 10 <option value="11">Seat 11 <option value="12">Seat 12 <option value="13">Seat 13 <option value="14">Seat 14 <option value="15">Seat 15 <option value="16">Seat 16 <option value="17">Seat 17 <option value="18">Seat 18 <option value="19">Seat 19 <option value="21">Seat 20 <option value="22">Seat 22 <option value="23">Seat 23 <option value="24">Seat 24 <option value="25">Seat 25 <option value="26">Seat 26 <option value="27">Seat 27 <option value="28">Seat 28 <option value="20">Seat 29 <option value="30">Seat 30 <option value="31">Seat 31 <option value="32">Seat 32 <option value="33">Seat 33 <option value="34">Seat 34 <option value="35">Seat 35 <option value="36">Seat 36 <option value="37">Seat 37 <option value="38">Seat 38 <option value="39">Seat 39 <option value="40">Seat 40 <option value="41">Seat 41 <option value="42">Seat 42 <option value="43">Seat 43 <option value="44">Seat 44 <option value="45">Seat 45 <option value="46">Seat 46 <option value="47">Seat 47 <option value="48">Seat 48 </select> <p> <input type='submit' name='next' value='Next Step'> </form> <p> </body> </html> Hello, can any1 show me how to insert the following in db Code: [Select] <?php include('dbconnect.php'); include('simple_html_dom.php'); $html = file_get_dom('test3.php'); foreach($html->find('h2') as $heading) { //echo $heading; foreach ($heading->find('a') as $link) { $item_title = md5($link); echo $link."<br/>"; $sql = "INSERT INTO articles(article_id, article_link) VALUES($item_title, $link)"; $result = mysql_query($sql); } } ?> what i want to do is insert every link in the db, but this is not working. The output is ok but the insert doesnt work. Any help please?? Hi Guys, having one of them "why wont it work" nightmares whilst doing some updates on a web page someone else has coded, its a simple php and mysql insert string that has some validation on but no matter what I do it wont add a new property, it updates fine, i have only added three new fields to the original source files, property_county, property_size, property_status, it should have been a simple job but has got me stumped, anyone got any suggestions? The script uses three files, properties.php - which is the page which holds the form class.properties.php - which contains the functions - this is where i think the problem is.... and property_form.php - which is just the form, this is fine, just the above two that seem to be causing the problem!! any suggestions would be greatly appreciated. Thanks Matt The code.... very simple: $punc_body = explode(". ", $body); foreach ($punc_body as $k => $v) { $v = ucfirst($v); echo $v . "<br>"; // this is only here for testing purposes. } $body = implode(". ", $punc_body); Why doesn't this work? I threw in the echo $v in which it shows that it is doing everything properly, however when I implode the array everything that was capitalized is reverted back to lower-case. Can someone tell me whats wrong or what I'm missing here please. I'd like to write - or acquire - code that displays a simple table (name, phone number, email address, plus a comments field) on a web page in a password-protected page and allows a user to add his own information, update it or delete it. I figure hundreds of people and companies have written something like this so I'd like to find either an example I can imitate or even an existing package that I can simply customize to the specifics for my own table. Can anyone help me with that? Or am I going to have to reinvent the wheel for the gazillionth time and write it myself? I have this code: <?php $con = mysql_connect("localhost","hhh","hhh"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("hhh", $con); // -------------------- // Avatar insert check // -------------------- session_start(); $name = $_POST[name]; $group = $_POST[group]; $age = $_POST[age]; $usernameid = $_SESSION[id]; $result = mysql_query("SELECT * FROM avatars WHERE name='$_POST[name]'"); $num = mysql_numrows($result); if ($num == 0) { mysql_query("INSERT INTO avatars (id, usernameid, name, group, age, xp) VALUES ('', '$usernameid', '$name', '$group', '$age', '0')"); header( 'Location: me/' ) ; } else echo 'Sorry, please pick a new name'; ?> And it does everything but put the data into the datebase. If I add a session befor and after '$request' they both run, but the sql doesn't. No error returns, if just redirects to the other page. Any help? I need help badly! What I want to do is insert into database the value from the selected radio group buttons.. All of them. There are 10 radio groups total (they can be less, but not more). Thanks! Code: [Select] <?php require_once('Connections/strana.php'); mysql_select_db($database_strana, $strana); ?> <link href="css/styles.css" rel="stylesheet" type="text/css" /> <table width="100%" height="100%" style="margin-left:auto;margin-right:auto;" border="0"> <tr> <td align="center"> <form action="" method="post" enctype="multipart/form-data" name="form1"> <table> <?php $tema = mysql_query("SELECT * from prasanja where tip=2")or die(mysql_error()); function odgovor1($string) { $string1 = explode("/", $string); echo $string1[0]; } function odgovor2($string) { $string1 = explode("/", $string); echo $string1[1]; } while ($row=mysql_fetch_array($tema)) { $id=$row['prasanje_id']; $prasanje=$row['prasanje_tekst']; $tekst=$row['odgovor']; ?> <tr> <td> </td> </tr> <tr> <td class="formaP"> <?php echo $prasanje?> </td> </tr> <tr> <td class="formaO"> <p> <label> <input type="radio" name="Group<?php echo $id?>" value="<?php odgovor1($tekst) ?>" /> <?php odgovor1($tekst) ?></label> <br /> <label> <input type="radio" name="Group<?php echo $id?>" value="<?php odgovor2($tekst) ?>" /> <?php odgovor2($tekst) ?></label> <br /> </p></td> </tr> <tr> <td> <br /> </td> </tr> <?php } ?> </table> <input align="left"type="submit" name="submit" value="Внеси" > </form> </td> </tr> </table> prasanje = question tekst/odgovor = answer The answer table: id - primary question_id - the questions ID whose answer is selected in the radio group user_id - cookie takes care of this answer - the value from radio group date - automatic Hi guys I have a registration form working fine, my database is as below: userid username password repeatpassword I have added another column which is "name", users can update their profile once they have logged in so I have created updateprofile.php and when I login-->go to update profile and insert my name nothing adds to mysql name column this is my code below: <?php include ("global.php"); //username session $_SESSION['username']=='$username'; $username=$_SESSION['username']; //welcome messaage echo "Welcome, " .$_SESSION['username']."!<p>"; if ($_POST['register']) { //get form data $name = addslashes(strip_tags($_POST['name'])); $update = mysql_query("INSERT INTO users (name) VALUES ('$_POST[name]') WHERE username='$username'"); } ?> <form action='updateprofile.php' method='POST'> Company Name:<br /> <input type='text' name='name'><p /> <input type='submit' name='register' value='Register'> </form> can you please tell me where in this code is wrong? Im new in php so please excuse me if I have silly mistakes. thanks in advance well this is truely embarrising...i have a insert statement which works within phpmyadmin but when using mysqli_query it returns a error.
INSERT INTO users (username, timestamp) VALUES ('test', UTC_TIMESTAMP())
Unknown column 'timestamp' in 'field list'
i've been playing about with this for a few hours now ...tried changing the column name (timestamp), adding ` around column names as well as table name.
the column exists which is the strangest part, and ive even checked there is no space after the column name in the db.
whats going on please?
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