PHP - Mysql_num_rows Count Rows And Echo Row Number?

I am trying to echo the count for blog posts that have not been review yet, but I get this error.

Notice: Undefined index: status

but I feel like I have defined my status in my query.  Plus my query is working as I have checked it in phpmyadmin

Here is my function:

Code: [Select]
function unapproved_post_counter()
{
$sql = "SELECT
COUNT(`approved`) AS `status`
FROM `blog_posts`
WHERE `approved` = 0
";

$result = mysql_query($sql);

$data = array();

while (($row = mysql_fetch_assoc($result)) !== false)
{
$data[] = $row;
}

return $data;

}

Here is how I am echoing it.

Code: [Select]
$count = unapproved_post_counter();

<h1>Blog<span class="blogadds f_right"><?php echo $count['status']; ?> New Articles</span>

print_r($count) tells me this...

Array ( => Array ( [status] => 2 ) )

Hi. I having trouble with counting rows in phpmyadmin.

It works fine this way:
Code: [Select]
$result_rows = mysql_query("SELECT * FROM events");

But when i modify the code to this it doesnt work at all.
Code: [Select]
$result_rows = mysql_query("SELECT * FROM events WHERE category = 'adults' ORDER BY 'date'");

Any idea what is wrong?

I have a mysql table that holds data for cars - each car has it's own ID, name, and year. Some cars are repeated.

Example: (ID - year - car name)
0001 - 2009 - Honda Civic
0002 - 2008 - Toyota Prius
0003 - 2009 - Honda Civic
0004 - 2008 - Toyota Prius
0005 - 2008 - Toyota Prius
0006 - 2007 - Honda Civic

How would I count how many of the same type of cars I have in that table and then display the quantity next to the car name? Like for the above example it would be:

2009 Honda Civic: 2
2007 Honda Civic: 1
2008 Toyota Prius: 3

Thanks in advance for any help  :D

Hi

I'm not at all good at PHP and haven't really played with it for some years, so bare with me if code examples are old

I'm looking for a simple solution to count rows (MySQL), without using multiple queries.

The below code is quite simple, counting rows where 'Department' is 'Sales':

$sql ="SELECT * FROM DB WHERE Department ='Sales'";
$result=mysqli_query($con,$sql);
$rowcount=mysqli_num_rows($result);

But what If I need to count the rows for the different departments?:

$sql ="SELECT * FROM DB WHERE Department ='Sales'";
$result=mysqli_query($con,$sql);
$rowcount=mysqli_num_rows($result);

$sql ="SELECT * FROM DB WHERE Department ='Support'";
$result=mysqli_query($con,$sql);
$rowcount=mysqli_num_rows($result);

$sql ="SELECT * FROM DB WHERE Department ='Online'";
$result=mysqli_query($con,$sql);
$rowcount=mysqli_num_rows($result);

There must be a better / simpler way to this with a single query?

Hope for someone to show me the light

 

PS. Once this is resolved, I'll probably need further help, to accomplish my final result.

It's late and I'm not thinking straight. I'm posting this question. Hopefully I get a reply in the morning.

I have two tables.

TABLE 1 - PRODUCTS

TABLE 2 - LIKES

I am a User who has posted these products. I want to find out ALL the Likes I have received for all my products. Here is my code.

$find_products = $db->prepare("SELECT product_id FROM products WHERE user_id = :user_id");
$find_products->bindParam(':user_id', $my_user_id);
$find_products->execute();
$result_products = $find_products->fetchAll(PDO::FETCH_ASSOC);
if(count($result_products) > 0) {
  foreach($result_products as $row) {
    $product_id = $row['product_id'];

    $find_likes = $db->prepare("SELECT like_id FROM product_likes WHERE product_id = :product_id");
    $find_likes->bindParam(':product_id', $product_id);
    $find_likes->execute();
    $result_likes = $find_likes->fetchAll(PDO::FETCH_ASSOC);
    if(count($result_likes) > 0) {
      $get_likes  = 0;
      foreach($result_likes as $row) {
        $get_likes++;
      }
    }
  }
}

The issue with the above code is that It only shows the Likes if I echo inside the foreach loop. And it'll show combined Likes from each of my products. But I want to actually combine ALL the Likes from ALL the products and be able show them as a single number, outside of the foreach loop.

How do I do that?

Edited August 17, 2019 by imgrooot

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;
i need help .. with calculating how many days are between example:  january = 1  ; day =23 to feb =2; day 23
in php ... how can i do that

Hi Everyone,

I am working on implementing a blog comment system using the query below to display comments. My question is what is the best way to do a row count for the id column with this query or do I need to do a second db query to accomplish this? The purpose of this is to echo out the number of comments for that post, before displaying them.

Any help is appreciated.

Thanks in advance,

kaiman


<?php
// get url variables
$post_id = mysql_real_escape_string($_GET['id']);

include ("../../scripts/includes/nl2p.inc.php");

// connects to server and selects database
include ("../../scripts/includes/dbconnect.inc.php");

// table name
$tbl_name3="blog_comments";

// select info from comments database
$result3 = mysql_query ("SELECT count(*) FROM $table_name3 WHERE id='$post_id' ORDER BY id DESC LIMIT 1") 
or trigger_error("A mysql error has occurred!");
if (mysql_num_rows($result3) > 0 ) {
while($row = mysql_fetch_array($result3)) {
extract($row);

// display number of comments


// display date
$row_date = strtotime($row['date']);
putenv("TZ=America/Denver");
echo "<p class=\post\">On ".date('F, jS, Y', $row_date)." ";

// display commenter name
if($row['url'] == "") { 
echo $row['name']." wrote:</p>\n"; 
} 
     else { 
echo "<a href=\"".$row['url']."\" target=\"_blank\">".$row['name']."</a> wrote:</p>\n"; 
} 

// display content
$comments = $row['comment'];
echo nl2p($comments);
}
}
else {
echo "<p class=\"large_spacer\">No Comments</p>";
}
?>

 $result = mysql_query("SELECT *  FROM `friend_system` WHERE `friend_system_accepter` = '$myusername' ");
echo mysql_num_rows($result);

This displays the total rows in the table.

$result = mysql_query("SELECT COUNT(friend_system_accepter)  FROM `friend_system` WHERE `friend_system_accepter` = '$myusername' ");
echo mysql_num_rows($result);

This displays '1', which is incorrect.   I want to echo out the number of rows where 'friend_system_accepter' = $myusername   Thanks

The following works, but I don't want to have to write 50 query statements for 50 states.  How can I just write one query (using a variable I presume) and then echo the variable count each time for each state?  I'm just trying to list the total number of rows for each state, that exist in the db. 

<?         
$result = mysql_query("SELECT * FROM mytable WHERE source = 'alabama'") 
or die(mysql_error());  
$num_rows = mysql_num_rows($result);

?>
 
href="/state/alabama/">alabama</a> (<?php echo("$num_rows");?>) <br>
 
 <?
$result = mysql_query("SELECT * FROM mytable WHERE source = 'alaska'") 
or die(mysql_error());  
$num_rows = mysql_num_rows($result);
?>
href="/state/alaska/">alaska</a>  (<?php echo("$num_rows");?>) <br>   

 
The above would give output such as:
alabama (122)
alaska (212)

I got to thinking late last night (which generally leads to trouble), so please be gentle if some educating is in order, as I suppose I will touch a few related issues.

As I develop my database, I will include two seperate columns.  One for the time/date that an order was placed.
A second for the time/date that an order is updated (unless there's a better way, please inform me).

I pressume that if a record is updated several times, it will continually overwrite the time/date to the point that I will only see the latest update.  Now I was wondering if I could create a third column to keep count of the number of times a record had been updated, so if it were altered 16 times, I would know when the last update occurred, and have the count number also.

Will something like this coding work?

SELECT updates FROM myTable WHERE id="$id"
$updates =n
if n<1, n=1
}else{ n++

I need help with a count query and displaying it.  Right now have the following query

$query = "SELECT COUNT(*) as num1 FROM spoiler WHERE id='$id";
$total_trophies = mysql_fetch_array(mysql_query($query));
$total_trophies = $total_trophies[num1];

So I have another query that pulls how many trophies there are.  That way I can do the following


?  echo $total_trophies; echo 'of'; echo $row[trophy_count];  ?>

But the problem is sometimes in my database I could have mulitple entrys per trophy.  For Trophy 1 I might have only one record so It counts it correctly for trophy 2 I could have 3 records so It counts each one of those records when I only one to count it once for that trophy

How do you count the number of folders in a directory?

hi, I want to count the total number of multiple select that user has selected instead of getting the value the user has selected How should I go about doing the counting part?

Code: [Select]
<form action="1.php" method="post">
<select name="test[]" multiple="multiple">
<option value="one">one</option>
<option value="two">two</option>
<option value="three">three</option>
<option value="four">four</option>
<option value="five">five</option>
</select>
<input type="submit" value="Send" />
</form>


<?php
$test=$_POST['test'];
if ($test){
 foreach ($test as $t){echo 'You selected ',$t,'<br />';}
}
?>

How to count the number of files/images from a folder?

I insert data in mysql table row using multiple method : 1#2#3 . 1 is ID of country, 2 is Id of state, 3 is ID of town . now i have this table for real estate listings. for each list(home) i have country/state/town (1#2#3). in country table i have list of country - in country table i have list of state - in country table i have list of town. i need to The number of houses in country / state / town . my mean is :
Code: [Select]
USA [ 13 ] <!-- This Is equal of alabama+alaska+arizona -->
----Alabama [8] <!-- This Is equal of Adamsville+Addison+Akron -->
-------Adamsville [2]
-------Addison[5]
-------Akron[1]
......(list of other City)
----Alaska [ 3 ]
-------Avondale[3]
......(list of other City)
----Arizona [ 2 ]
-------College[2]
......(list of other City)
Lisintg Table :

Code: [Select]
ID -- NAME -- LOCATION -- DATEJOIN -- ACTIVE
 1 -- TEST -- 1#2#3    -- 20110101 -- 1
 2 -- TEST1 -- 1#2#3    -- 20110101 -- 1
 3 -- TEST2 -- 1#3#5    -- 20110101 -- 1
 4 -- TEST3 -- 1#7#6    -- 20110101 -- 1
Country Table :

Code: [Select]
id       -- name 
 1        -- USA 
stats Table :

Code: [Select]
id        -- countryid -- name 
 1        -- 1             -- albama
 2        -- 1             -- alaska
 3        -- 1             -- akron
town Table :
Code: [Select]
id        -- countryid -- statsid -- name 
 1        -- 1             -- 1         -- adamsville
 2        -- 1             -- 1         -- addison
 3        -- 1             -- 1         -- akron
Thanks For Any Help.