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PHP - Cannot Include Array From Another File...
Hi all,
I'm at a dead-end here. I have a php file that I can query to return an array containing a bunch of data about a job listing. I include and query it by calling it like so within another file on my site. Quick Notes: The original file is in a different directory on my site than the page it's being included in. I have tried returning the array at the end of the script. I can print_r the array on the page I'm including the script on (so the URL path is correct). If I go to this URL directly and print_r on the array, I see the entire array as expected. Also, if I include the file on page 2 like I did above with print_r on the array in the original file, I see the array printed out on page 2. Code: [Select] include 'http://www.example.com/php/job-details.php?job=jobname&city=thecity'; However, if I do not print_r on the array in the original file and just include it on page 2, I cannot do anything with it and the array variable isn't found. Is this a case of variable scope? I'm so frustrated... Here is the code I have in my original file: Code: [Select] <? include('functions.php'); $jobtitlematch = $_GET["job"]; $jobcitymatch = $_GET["city"]; //echo $jobtitlematch; //echo $jobcitymatch; $url = 'http://somesite.com/something'; $xml = simplexml_load_file($url); foreach($xml->job as $job) { $jobtitle = makeURL((string)$job->title); $jobcity = makeURL((string)$job->region); if ($jobtitle == $jobtitlematch && $jobcity == $jobcitymatch) { $jobdata[] = array( Title => ((string)$job->title), URL_Title => makeURL((string)$job->title), Location => ((string)$job->region), URL_Location => makeURL((string)$job->region), Department => ((string)$job->department), URL_Department => makeURL((string)$job->department), Overview => ((string)$job->joboverview), Responsibilities => ((string)$job->responsibilities), Qualifications => ((string)$job->qualifications), Keywords => ((string)$job->metakeywords) ); } return $jobdata; //I have also tried return global $jobdata; } print_r($jobdata); ?> Thanks in advance for any help you can provide... Similar TutorialsHere is a section of php file A include_once(dirname(__FILE__) . '/PhpfileB.php') $VALID_RATING_IDS = $Ratethese Here is all of php file B $Ratethese = "array("1", "2",);" I need the var $VALID_RATING_IDS to = $Ratethese from file B I am trying to include an array from php file B in php file A. Is this possible? How can i accomplish this? I have an array created to control the down states of the my buttons in my navigation. Which is working well. This array will have quite a few strings in it before I'm done. I then want to conditionally load a CSS file for all the files in that array with the exception of two, is this possible? In plain in english I want to say If in array apart from these values then load my css file. My array (will have more values when complete) Code: [Select] $otherTitles = array('Product Selector', 'Avon Range', 'Knightsbridge Range', 'Kingston Range' ); My code to load a css file Code: [Select] <?php if (in_array($title, $otherTitles)) { ?> <link rel="stylesheet" type="text/css" href="homepage.css"/> <?php } ?> I want all titles in the otherTitles array to get this CSS file apart from two Product Selector and Avon Range. Thanks Richard I have a php file that generates a string that I need to use in a .js (javascript)file. Being that php developers sometimes using javascript with php, Im hoping someone can help me with this, cause i dont know any javascript. Code: [Select] //This is the varible inside the .js file var suggestionText = "I need to be able to include my string generated by the php file here..."; www.desmond-otoole.co.uk/secure/securefunctions.php /bank/admin/index.php what should I do in the index.php file to access securefunctions.php
require("../secure/SecureFunctions.php"); Nothing seems to work
I just get a stupid google chrome page saying I want to include a php file after an succesfully login. Let's suposed that I have a login form on index.php. If the login was ok I want to include a php file with some content instead of the login form. Something like: Code: [Select] <? if($_POST['ok']){ require('content.php'); } else { //login form } ?> It's ok to include in the code the name of the file that you have on server ? From security point of view. Thanks Can I include a class file in the same page that I use an instance of the same class with my action attribute with my form. Here's the code Code: [Select] <?php include 'Resources/User.php';?> <html> <head> <title></title> <link href="stylesheets/styles.css" rel="stylesheet" type="text/css"/> </head> <body> <form action = "Resources/testClass.php" method="post" enctype="multipart/form-data"> <label>First Name: </label> <input type="text" name="fname" id="fname" size="25" maxlength="25"/> <label>Last Name: </label> <input type="text" name="lname" id="lname" size="25" maxlength="25"/> <label>Email: </label> <input type="text" name="email" id="email" size="25" maxlength="40"/> <label>Username: </label> <input type="text" name="username" id="username" size="25" maxlength="32"/> <label>Password: </label> <input type="password" name="password" id="password" size="25" maxlength="32"/> <label>Re-enter Password: </label> <input type="password" name="conf_pass" id="conf_pass" size="25" maxlength="32"/> <br /><br /> <input type="submit" name="submit" id="submit" value="Register"/> <input type="reset" name="reset" id="reset" value="Reset"/> </form> </body> </html> Hello, Im trying to pass a variable to a newly created page using GET. Code: [Select] $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title'>" . $nt[$i] . "</a>" . "<br/>"; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); header.php Code: [Select] <head> <?php $title = $_GET['Title']; ?> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <p>HEADER UPDATED!</p> <p>TESTING - the heading below should read (title goes here in capital letters)</p> <?php <h1>$title</h1> ?> //This is line 12 </body> </html> Im getting the error; Parse error: syntax error, unexpected '<' in D:\Hosting\3753557\html\1pw\mexican.php on line 12 I suspect that I have my syntax muddled in header.php? Is there a better way to pass variables to a newly created page? (fopen). Many thanks for any ideas. I'm really embarrassed asking this.. I have two files. config.php & program.php config.php<php $max_columns = 3; ?> program.php<?php include ('config.php'); echo $max_columns; ?> I can't get the script to echo anything. I have tried... $max_columns = '3'; $max_columns = "3"; include_once include ("config.php"); include ('/path/to/file/config.php'); require .....etc. etc. Any thoughts? PLEASE, I'm going nuts here. Thanks for you patience with what must be a very trivial question for you guys hi php freaks, Is there a way to parse an include file through the php engine and then place the contents into a variable? Code: [Select] $x = include ($myfile); Hello, I have a simply query that will if a simple two different things: Code: [Select] $cssyn = mysql_query("SELECT `12` FROM `12345` WHERE `abc` = '$_SESSION[number]'"); $cssy = mysql_fetch_row($cssyn); if($cssy[0] == "YES") { echo "Yes"; } else { echo "No"; } The YES or NO result is stipulated earlier on so thats not the problem. But basically before I added the if statement simply would have echoed a table with all the rows etc from another query. However I would like to give the user a choice between echoeing the results into one table or a neater two. I have separated the code for the table and the queries into two separate files but say if I use: file_get_contents then it just prints the HTML and doesnt actually populate it will the queried parts. Nor if I use something like include() then it wont echo anything, which it wouldnt unless called so what I am asking is: Is there a way to get EVERYTHING from the file if the answer is YES or the other file if NO. My catalog uses a template file to list product details. One part of it is responsible for putting these details into nifty little tabs: <?php $template = '{magictabs style=black_rounded, tabwidth=110px}'; $template .= 'Technical Specifications'; $template .= '::'; $template .= '<table colspan="3"><tr><td>'; $template .= $details; $template .= '</td></tr></table>'; $template .= '||||'; ?> I don't want it to output $details, I want it to output a separate script instead. How do I include this separate file as a variable? I want this: <?php include('specs.php'); ?> to replace the $details variable.
I am using an inclue file on my layout.php page. Hi peeps iv been trying to figure out this but i cant see it....its probably obvious!!! in the $header variable the include files dont show... any ideas here the php code <? session_start(); ?> <link href="/styles/main.css" rel="stylesheet" type="text/css" /> <? //get data $button = $_GET['submit']; $search = $_GET['search']; $search = strtoupper($search); $header = ("<table width='100%' border='0' height='80' cellpadding='4' bgcolor='#000000' > <tr> <td width='39%' height='76' valign='top'><p><span class='stigrosheadfont'><strong>www.StigRos.com</strong></span><strong><span class='headnocrap'><br /> ( No Crap - Just Quality Movie & Music Downloads )</span></span><br /> <a href='http://mysite' class='headerlinkcolor'>Home</a> | <a href='register.php' class='headerlinkcolor'>Register</a> | <a href='#' class='headerlinkcolor'>Contact us</a></strong></td> <td width='47%' valign='bottom'><p class='normalblacktext'>You are currently logged in, <b>$_SESSION[username]</b></td> <td width='14%' valign='top'><div align='center'> <div align='center'><span class='headfont'><strong>Disclaimer</strong></span></div> <div align='center'> <? include_once 'countertest.php'; ?> <? date('F d, Y'); ?></div></td> </tr> </table>"); $s = $_GET['s']; if (!$s) $s = 0; $e = 10; // Just change to how many results you want per page $next = $s + $e; $prev = $s - $e; if (strlen($search)<=2) echo "Must be greater then 3 chars $user"; else { echo $header; echo " <form action='search.php' method='GET'> <center> <br> <input name='search' type='text' class='blacktext' size='50'> <input name='submit' type='submit' class='blacktext' value='Search Film'></font></p> </center> </form> "; //connect to db include('db.php'); //explode out search term $search_exploded = explode(" ",$search); foreach($search_exploded as $search_each) { //construct query $x++; if ($x==1) $construct .= "keyword LIKE '%$search_each%'"; else $construct .= " OR keyword LIKE '%$search_each%'"; } //echo outconstruct $constructx = "SELECT * FROM movies WHERE $construct"; $construct = "SELECT * FROM movies WHERE $construct LIMIT $s,$e"; $run = mysql_query($constructx); $foundnum = mysql_num_rows($run); $run_two = mysql_query("$construct"); if ($foundnum==0) echo "No results found for <b>$search</b>"; else { echo "<table bgcolor='#000000' width='80%' height='1px' align='center'><br /></table><table bgcolor='#000000' width='80%' height='10px' align='center'><tr><td><div align='right'><font color='#E6E6E6'>Showing 1-10 of <b>$foundnum</b> results found for <b>$search.</b></font></div></td></tr></table><p>"; echo "<br>"; while ($runrows = mysql_fetch_assoc($run_two)) { //get data $title = $runrows['film']; $desc = $runrows['description']; $url = $runrows['dl_link']; $imdb = $runrows['imdb']; $pic = $runrows['pic']; $film = $runrows['film']; echo "<table width='900' border='1' align='center'> <tr> <td width='229' align='center'><IMG SRC='$pic'></td> <td class='blacktext' width='655' align='center'><b>$film</b><br /><br />$desc<br /><br /><a href='$url' target='_blank'><b>Download Now</b></a> | <a href='$imdb' target='_blank'><b>IMDb</b></a></td> </tr> </table> "; } ?> <table width='100%'> <tr> <td> <div align="center"> <?php if (!$s<=0) echo "<a href='search.php?search=$search&s=$prev'>Prev</a>"; $i =1; for ($x=0;$x<$foundnum;$x=$x+$e) { echo " <a href='search.php?search=$search&s=$x'>$i</a> "; $i++; } if ($s<$foundnum-$e) echo "<a href='search.php?search=$search&s=$next'>Next</a>"; } } ?> </div> </td> </tr> </table> Hi I'm in a need of help here, I need to inluded this: "http://site.com/products.php?do=groups&groupid=2" in a a tpl file. Any way that this can be done? an example would be greatly appreciate it. cheers In my code include_once "http://myserver.com/someFile.php" does not work but include_once "/someFile.php" works I NEED to be able to full URL. Anyone know what PHP setting I need to change to get this working for me? Thanks This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=308660.0 How do I include a file that is located two directories above the file that I want to include the file into? My absolute hosting path is /home/content/52/8840652/html if this would be of any use. I'm not quite sure about the PHP include functions. Any help would be greatly appreciated, Thanks! @requinix, In an earlier thread of mine this week, I think you - or maybe it was @Psycho - suggested putting my code which create an array of my photo files into an include file. I think the logic was that then when either my "photo-gallery.php" OR "photo-detils.php" scripts call that code, that the array will always synched because it is the same array. Ring a bell? So super newbie question, but I am rusty on includes... How does this sound...
1.) Create an "/includes/retrieve-photos.php" script?
2.) Reference that in each script, I would do this...
require_once('../../includes/retrieve-photos.php
right?
3.) To use that code, I would then just reference the populated array...
foreach($photoFiles as $photoKey => $photoValue){
}
Right?
Hi all I have a string in an include file for a javascript lightbox value. I need this value to increase by one every time it loops. Here's my code: $fetchproducts = mysql_query(" SELECT * FROM `products` "); while($returnedProduct = mysql_fetch_array($fetchproducts)) { include('product-cell.php'); } The string is called $lightboxcount in the product-cell.php file Can I fit a ++ into the code above? Many thanks for your help Pete |
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