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PHP - Including A File Of Root Directory From Subdomain
Suppose, i have created a sub.domain.com and i want to include a file 'config.php' from root directory i.e domain.com . While i tried include("../config.php"); i wasn't successful. Anyone can help me please??
I need the solution very urgently, so please help me soon. pracasify@yahoo.com facebook.com/agptj Similar TutorialsI was wondering of it was possible to have a file say style.css in the root folder of a site like www.example.com/style.css and then get a subdomain called www.sub.example.com which points to www.example.com/subarea to get that file without the use of absolute paths? Sorry if its not clear. Hi guys, I am searching for the definitive way of obtaining the root directory of my app. I need to it to work on localhost and also on ALL platforms, NIX, Windows etc. I would like to do this as I wish to use it to locate all my sub directory files - includes, model etc. For example, I may have this as my landing page: http://www.mywebsite.com/index.php The root directory might be: html The index.php might reside he html/index.php ... but my includes files might be he html/lib/includes So I would be looking to obtain the root in an absolute kind of way to allow me to string together the includes sub directory in a relative kind of way. In summary then: 1. How to obtain the root with 100% percent success, all of the time on all platforms. 2. How to string the sub directory together with 100% percent success, all of the time on all platforms. 3. Any comments on this as an approach, also welcome. Many thanks in advance, S hi, Is it possible to display an image that is above the root directory using php? for example if i have an image in /home/user/uploads/test.jpg and lets say my root directory for my site is /home/user/public_html/ is it possible to display test.jpg on /home/user/public_html/index.html ? i am trying to create a secure file upload script and i think not having the file be directly accessed by the public is one of the main steps. I came accross this code on YouTube and it works great for listing the content of a folder that the .php file is in. However, how can I alter this code to list files of all folders and sub-folders? I thought plugging in an asterik might work on the "$path =" line, but it didn't. Code: [Select] <?php $path = "."; $handle = opendir($path); while ($file = readdir($handle)) { echo $file . "<br>"; } closedir($handle); ?> I'm making an admin so I need to be able to do this: https://admin.mysite.com Run an upload image script from a file, saves image to folder in http://www.mysite.com Image Folder How can i find out parent (including) file of included file? Lets imagine that we want to for example auto_prepend file to each file on our server that would write out the name of file its being executed. I know, i can use PHP_SELF but what if i want to write name of file which is already included? I have a web page and i want on it show its name even if it was included, but not the included page itself is showing name but auto_prepend file to each php file, its duty of this auto_prepend_file to write it out i dont want myself to echo it on each page? do you feel me? Hi everyone.... I have a simple search.php And I want to include that in my html output page. I tried using <?php include ('search.php'); ?> Below is my HTML code which is part of a php file...what am I doing wrong here? Code: [Select] // Final Output echo <<<__HTML_END <html> <head> <title>Photography</title> </head> <body> <table width='100%' border='0' align='center' style='width: 100%;'> $result_final <?php include("search.php");?> </table> </body> </html> __HTML_END; how to get the name of the file including a file from the included file, This one has me mixed up a bit.. I am trying to record site activity information from a common.php file using a user object. But since the file is included into different php files based on different situations I need a dynamic way of finding the file name that is including it. I could be over complicating things but right now this seems like the best solution other wise I'll have to rewrite the code on every page i write. Is there a function for doing this? Or if someone gets what I'm trying to do if they could point me to the direction of some more information on it. Thanks. How to include root files from subdirectory in php? I have tried include '../configure.php'; but got error. Also tried include($DOCUMENT_ROOT."../configure.php"); but same result. For example, I have "root/admin" directory, and can't connect (from "/admin" dir) to the file configure.php which is in root. There are also other files to include. The root directory:
header.php
stylesheet.css
In the following example I am trying to include the header.php file in a sub folder.
When I include the header.php like in the following example then the stylesheet.css file will not work anymo
<?php
include("../header.php");
?>
The stylesheet.css file is included in the head tags of the header.php file.
Is the above example the right way to do it? If yes, how can I do it so the stylesheet.css file will work too.
See if I can explain this right.
I am currently using static files for a very basic set of pages.
Right now i have a main file that has three includes. a header include, body and footer.
Due to needing to add pages, i don't want to keep adding more and more files. instead I want to use php to change one of the includes based on the url.
so thissite.com/index.php?lesson1 would change this
<?php include("header.php"); ?>
<?php include("content-lessons.html"); ?>
<?php include("footer.php"); ?>
to this
<?php include("header.php"); ?>
<?php include("lesson1.html"); ?>
<?php include("footer.php"); ?>
or whichever way would be the best way to set the second include.
my guess was that if the second line had something like this?
if(isset($_GET['lesson1'])){
include('include/in-'.$_GET['lesson1.html']
can someone give me a starting place here? i am pretty sure i can pick ti up if someone gets me going in the right direction.
thanks a ton.
Edited by story97, 12 January 2015 - 09:03 PM. I don't know if this relevant to php or css in my template folder I have file named (index.template.php). It contains this code <?php echo '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <meta name="Keywords" content="BHL-SimpleTool Content Manager System" /> <meta name="Author" content="BHL-SimpleTool is coded by Othman A. Taha" /> <meta name="Description" content="Site Powered by BHL-SimpleTool CMS" /> <title>BHL-SimpleTool v1.0 - Alpha</title> <link rel="stylesheet" href="themes/default/style.css" media="all" type="text/css" /> <link rel="stylesheet" href="themes/default/forms/forms.css" media="all" type="text/css" /> <link rel="stylesheet" href="modules/forum/Themes/default/style.css" type="text/css" /> <link rel="stylesheet" href="inc/jq/css/style.css" type="text/css" /> <script language="javascript" type="text/javascript" src="js/bbcodes.js"></script> <script language="javascript" type="text/javascript" src="js/smileys.js"></script> <script type="text/javascript" src="js/jquery.js"></script> <script type="text/javascript" src="js/easySlider1.5.js"></script> </head> <body> <div id="wrapper"> my website run here </div> </body> </html>'; ?> It works fine( I made the top-margin to be 0px). But when I include index.template.php in my main (index.php) the top margin show a big margin from the top Note: I included (index.template.php) in my main (index.php) like this: <?php function __autoload($class_name) { require_once 'classes/Sessions' . '.php'; } $sessInfo = new Sessions(); $sessInfo->RunAllBhlSimpeToolStuff(); ?> Or is it all pieced together into one file then executed? I ask because I'm thinking of a weird way to handle errors on my site that would integrate with the interface smoothly without much work on my part. Every page on my site requires template_top.php at the start of the script and template_bottom.php at the bottom. I believe this is a pretty common thing to do, and it standardizes all my menus and interfaces and whatever else, plus it gives me a nice place to deliver messages to the user. What I want to do is something like this simplified example: template_top.php: <?php // layout stuff here try { ?> index.php: <?php require_once('template_top.php'); // a wild error appears! throw new Exception('oh no!'); require_once('template_bottom.php'); ?> template_bottom.php: <?php } catch (Exception $e) { echo 'An error occured! Message: ' . $e->getMessage(); } // layout stuff here ?> So that's where my question comes in. Both template files contain code that, if executed on it's own, is invalid. Pieced together in my pages though, it forms correct code. I'd really like to do this since all I'd have to do if my script encounters a problem is throw an Exception and everything is instantly handled without me having to fight with display issues. If this isn't possible, does anybody have any better suggestions? I havent included the whole title as it wouldnt let me but I was wondering if someone could help me on this? I know this is possible as torrentflux caters for this but unsure of where to start. I dont want to allow file or directory uploads or creation in my /etc/php.ini file (this is turned off). Yet then torrentflux allows me to link a torrent from an external source (using legal downloads of course ) but then it uploads it on my server and creates folders on a per user basis. How is this possible can someone give me some pointers please? I look forward to any replies, Jeremy. In my script, I'm trying to create a file with the name of a variable in a different directory. My code is: Code: [Select] $handle = fopen("cheese/" . $page . ".html", "w");Output: Warning: fopen(cheese/test.html) [function.fopen]: failed to open stream: No such file or directory in /home/a5938041/public_html/newfile/newpage.php on line 6 What's happening here? (sorry I'm a total noob.) I'm in the middle of making my own CMS system, where a user can create a page online via a text editor, I know how to create and save the file, but to make the process easier I would like to a function where a user can click a button find a list of files and folders, pick the folder location to save a new file to. Instead of having to type something like this /commonPages/aboutUs/ with the file name being test.php What would be the easiest way to do this? I have just been looking at opendir() and my first thought was to use <input type="file" />, but then I remember that was only for inputting a particular file name, which would be useful for renaming a file at a later date. For example, if we wanted to change test.php to something more meaningful ie history.php Why does this code: Code: [Select] require_once "../../media/php/classes/Mysql.inc.php"; Work when I go to: http://mysite.com/API/v1/index.php But when I go to: http://mysite.com/index.php it doesn't work. The require is being called from another class, which I call from the two pages above. The class loads, but in the second link, I get failed to open stream: No such file or directory but the first one works fine. What would cause this? could this be an htaccess thing? htaccess: Code: [Select] Options +FollowSymlinks RewriteEngine On RewriteBase / RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_FILENAME}.php -f RewriteRule ^(.+)$ /$1.php [L,QSA] Hi,
I have this code
<?php
// Must include this
include("geoiploc.php");
function getYJLINKS($default_font_family,$yj_copyrightear,$yj_templatename,$show_tools,$show_fres,$show_rtlc,$validators_off,$totop_off){
$allLinks = array();
if((function_exists('toolbox_urls') && $show_tools == 1) || $validators_off == 1 || $totop_off == 1){
echo '<div class="validators">';
if($validators_off == 1){
$allLinks[] ='<a href="http://jigsaw.w3.org/css-validator/check/referer?profile=css3" target="_blank" title="CSS Validity">CSS Valid</a>';
$allLinks[] ='<a href="http://validator.w3.org/check/referer" target="_blank" title="XHTML Validity">XHTML Valid</a>';
}
if($totop_off == 1){
$allLinks[] ='<a class="yjscroll" href="#stylef'.$default_font_family.'">Top</a>';
}
if (function_exists('toolbox_urls') && $show_tools == 1):
global $font_size;
global $font_direction;
if ($show_fres == 1):
$allLinks[] = '<a id="fontSizePlus" class="fs" href="javascript:;" rel="nofollow">+</a>';
$allLinks[] = '<a id="fontSizeMinus" class="fs" href="javascript:;" rel="nofollow">-</a>';
$allLinks[] = '<a id="fontSizeReset" class="fs" href="javascript:;" rel="nofollow">reset</a>';
endif;
if ($show_rtlc == 1):
$allLinks[] = '<a class="tdir" href="'.$font_direction[1].'" rel="nofollow">RTL</a>';
$allLinks[] = '<a class="tdir" href="'.$font_direction[2].'" rel="nofollow">LTR</a>';
endif;
endif;
echo implode(' | ',$allLinks);
echo '</div>';
}
// loading this from a database
$ip = $_SERVER["REMOTE_ADDR"];
// listing Country Flags Images
$dir = 'images/flags';
$file_display = array('png');
if (file_exists ($dir) == false) {
echo 'Directory \'', $dir, '\' not found!';
}
else{
$dir_contents = scandir($dir);
foreach($dir_contents as $file) {
$file_type = strtolower(end(explode('.', $file)));
If($file !== '.' && $file !== '..' && in_array($file_type, $file_display) == true)
if($file == '..' || $file == '.') {
continue;
}
$code = strtolower(getCountryFromIP($ip, "code"));
echo '<div class="yjsgcp">Palana.it ® 1994 - '.$yj_copyrightear.' :: Tutti i diritti riservati :: Realizzazione Palana.it ││ Utente rilevato: IP: '. $ip . ', '.getCountryFromIP($ip, " NamE ").' ('.getCountryFromIP($ip, "code").'-'.getCountryFromIP($ip, "AbBr").') ';
echo '<img src="', $dir, '/', $code, '.png" /> </div>';
}
}
}
?>
The problem, as we see (http://www.palana.it), is that code printed the Italian flag but many times there are images in the directory, that is over 204. See bottom of the page. How can I fix the code to get ONE display?
$file="../myclients/clients/".$company_name."/Download/".$file_name; $size = filesize($path); // not working i try with function also function formatbytes($file, $type) { switch($type){ case "KB": $filesize = filesize($file) * .0009765625; // bytes to KB break; case "MB": $filesize = (filesize($file) * .0009765625) * .0009765625; // bytes to MB break; case "GB": $filesize = ((filesize($file) * .0009765625) * .0009765625) * .0009765625; // bytes to GB break; } if($filesize <= 0){ return $filesize = 'unknown file size';} else{return round($filesize, 2).' '.$type;} } echo formatbytes($file, "KB"); uploaded file size is 488 kb but it showing "unknown file size" please help me. Hey, I dont know whats wrong but i was hoping someone could take a look at the code and provide some errors that maybe causing this script not to work. I want it to display all the .jpg pictures in thumbnails, it currently does not even get the pictures. code: <?php $pic_listing = mysql_query("SELECT * FROM toplist WHERE id='". $id ."'") or die(mysql_error()); while($serverpic = mysql_fetch_array($pic_listing)) { $servername = $serverpic["servername"]; } $directory = "images/serverpic/" . $servername . ""; $images = glob("" . $directory . "*.jpg"); if(empty($images)) { ?> <div class="highslide-gallery"> <?php foreach($images as $image) { ?> <a href="images/serverpic/<?php echo $servername . "/" . $image; ?>" class="highslide" onclick="return hs.expand(this)"> <img src="images/serverpic/<?php echo $servername . "/" . $image; ?>" alt="Highslide JS" width="100" height="100" title="Click to enlarge" /> </a> <div class="highslide-caption"> <?php } ?> </div> </div> <?php } ?> |
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