PHP - Insert Into Databae Between 2 Dates
i have a form that inputs into a mysql database.
2 of the fields are dates. from and to. ive been trying to search for a way to insert into the database for the days inbetween the dates given and i dont no if to do this in php or the mysql query. $post_a = val1 $post_b = val2 $post_c = val3 $post_d = val4 $post_e = 10/12/2010 $post_f = 15/12/2010 $date = loop of $post_e to $post_f( 10/12/2010 11/12/2010 12/12/2010 13/12/2010 14/12/2010 15/12/2010) $sql="insert into $table (a, b, c, d, date) values ('$post_a', '$post_b', '$post_c', '$post_d', '$date') "; Similar TutorialsHello:
How could I use php to automatically insert the correct 3 letter month abbreviations and four digit year in the following pdf filenames on the first of each month?
(For example "...Feb2015.pdf" then "...Mar2015.pdf" and so on....
<div>Book One: <a href="http://monthlybookfi...One_Jan2015.pdf">Download Here</a></div> <div>Book Two: <a href="http://monthlybookfi...Two_Jan2015.pdf">Download Here</a></div> <div>Book Three: <a href="http://monthlybookfi...ree_Jan2015.pdf">Download Here</a> </div> <div>Book Four: <a href="http://monthlybookfi...our_Jan2015.pdf">Download Here</a> </div> Please advise, Eggie Hi All, I need to subtract dates and display the number of days left. I have a 'Start' date and an 'End' date in DATETIME format in the DB. Not quite sure where to start. A simply start - end doesn't work . Start = 2011-11-01-00:00:00 End = 2011-11-30-23:59:59 Since it is now 2011-11-27, my output should equal 3. Any help is appreciated. Hi guys, I am trying to do a multidates events availability calender. The script below indicates todays date by highlighting an orange colour and also indicates the start and end date of the event highlighting grey colour on the two dates (The colour are link via css classes as shown). Code: [Select] //Today's date $todaysDate = date("d/m/Y"); $dateToCompare = $daystring . '/' . $monthstring . '/' . $year; echo "<td align='center' "; if($todaysDate == $dateToCompare){ echo "class='today'"; }else{ //Compare's the event dates $sqlcount = "select event_start,event_end from b_calender where event_start ='".$dateToCompare."' AND event_end='".$dateToCompare."'"; $noOfEvent = mysql_num_rows(mysql_query($sqlcount)); if($noOfEvent >= 1){ echo "class='event'"; } } It works ok i.e. if start date = 01/01/2012 and end date = 04/01/2012 both date will be highlighted with grey colour. However I want it to also highlight grey on the dates between the 1st and 4th to show that then anydates between the 1st and 4th are not available and this is when I'm stuck. Please guys I need help. Thanks Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; I'm missing something here. I have a form, and when the submit is pressed, the relevant post data inserts into table one, then I want the last insert id to insert along with other form data into a second table. The first table's still inserting fine, but I can't get that second one to do anything. It leapfrogs over the query and doesn't give an error. EDIT: I forgot to add an error: I get: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'usage, why VALUES ('14', '', '123', '','1234', '', '')' at line 1 query:INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('test 14', 'asdfa', 'asdf', 'adf','asdf', '', '', '', '123', '', '') Code: [Select] if (empty($errors)) { require_once ('dbconnectionfile.php'); $query = "INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('$description12', '$sn', '$description4', '$cne','$description5', '$description6', '$description7', '$description8', '$description9', '$description10', '$description11')"; $result = @mysql_query ($query); if ($result) { $who_donated=mysql_insert_id(); $query2 = "INSERT INTO tbl_donation (donor_id, donor_expyear, donor_cvv, donor_cardtype, donor_authorization, amount, usage, why) VALUES ('$who_donated', '$donate2', '$donate3', '$donate4','$donate5', '$donate6', '$donate7')"; $result2 = @mysql_query ($query2); if ($result2) {echo "Info was added to both tables! yay!";} echo "table one filled. Table two was not."; echo $who_donated; //header ("Location: http://www.twigzy.com/add_plant.php?var1=$plant_id"); exit(); } else { echo 'system error. No donation added'; Hey, I have just recently coded a forum and my topics are ordered by date. This means if there is a topic at 4pm and then there is another topic made at 4:01pm the topic which was posted at 4:01pm will be listed at the top. I know how to add timezones but there is bit of a problem, if person from the UK posts a topic and his/hers timezone is set to: date_default_timezone_set('Europe/London');() this means the time at which the topic was posted will be 20:36pm (Just a randome time example). However if someone posted a topic from america/los_angeles one hour before the one above his/her time will be 11:36 am. Even though this topic was posted one hour before the UK post. The UK topic will override it because it is 8:36pm. In fact, all UK topics will show up at the top and all the america/los_angeles topics will show bellow. How do I slove this problem? I just don't get it even tough I looked online. Please help, thanks. i want to created a case like the following need help with the syntax: Code: [Select] switch (true) { case($fromdate-$todate==17-04-2001-25-04-2011): echo $finalprice = $result; break; } Hi guys, I am trying to create a program which manages campaigns. each campaign has a start date and and end date. a user has to enter data releated to the campaign everyday example start date: 10-1-2011 end date: 17-1-2011 now all this information is stored in 2 tables 1st table is "campaigns" this stores the campaign name, start date and end date and 2nd table is "campaign_data" this table stored the data for each campaign and also date of when that data was entered my question is, if the user did not enter data on 11-1-2011 how will I know this, keeping in mind the month diffrence which can accur if the length of the campign was 2 month long? table: campaigns fields: id | campaign_name | start_date | end_date table: campaign_data fields: id | campaign_id | date | page Thank you Hey guys, What I'm trying to do is set 2 dates. Today's date and then a date 14 days from now. However, I want it to increase the month if by adding 14 days will bring me to the next month, same with the year. I have this, but it doesn't increment the month or year. $week = mktime(11, 59, 59, date("m"), date("d")+14, date("y")); $date = date("Y-m-d H:i:s", $week); Hi, So I only want my users to be able to perform certain tasks each 12 hours. This is the code I use: Code: [Select] function canVote($ip, $vote_id, $updateTimer = true){ $time = date("Y-m-d H:i:s"); $this->CI->db->where('vote_id', $vote_id); $this->CI->db->where('user_ip', $ip); $this->CI->db->from('votes_voters'); $count = $this->CI->db->count_all_results(); /*$count = $this->CI->db ->where('vote_id =', $vote_id) ->where('user_ip =', $ip) ->from('votes_voters') -count_all_results();*/ $row = $this->CI->db ->where('vote_id =', $vote_id) ->where('user_ip =', $ip) ->get('votes_voters') ->row(); if($count == 0){ $data = array( 'vote_id' => $vote_id, 'user_ip' => $ip, 'last_vote' => $time ); $this->CI->db->insert('votes_voters', $data); return true; } else{ $last_vote = $row->last_vote; if($last_vote + strtotime("12 hours") < $time){ return false; } else{ if($updateTimer = true){ $data = array( 'last_vote' => $time, ); $this->CI->db->where('vote_id', $vote_id); $this->CI->db->where('user_ip', $ip); $this->CI->db->update('votes_voters', $data); } return true; } } } Apparently the failing bit is this: Code: [Select] if($last_vote + strtotime("12 hours") < $time){ return false; } I believe you can guess what I'm trying to do here, if variable 1 + 12 hours is smaller than variable 2, then return false. Any help is much appreciated. Hello there, I have a DB table where everyday I insert my meetings for the future. I want to ask you guys if anybody can help me with creating some sort of a weekly report. EXAMPLE: I have meeting from the beginning of the year (Mon-Sat)...could be 4-10 meeting per day, so a lot in general. I want them to appear , with sql, under the WEEK they were in for example: (a year has 52 weeks) WEEK 1 (01-01-2011 -> 08-01-2011) *M1 *M2 *M3 ... WEEK 2 (09-01-2011 -> 16-01-2011) *M4 *M5 *M6 ... etc... Is there a way to define the date's range after the week ended automatically? Thanks Hi, I have a created comment system, now what i am after is when the comment is posted the time is posted in hidden format. All is going fine but what i don't know, what should the time be posted as example date(H:m:s) or... the result i want is time in minutes first e.g. commented 2 mins ago and increasing to hours after that days. Could some one kindly guide me in the right directions. When just generating HTML, where should dates be formatted? What about when generating JSON (I've found that date formatting is not so straight forward using JavaScript)? Are there factors which may make one approach better than the other (i.e. querying one record versus a list of records)? How important is consistency of an approach? Any other factors I should consider? Please provide rational for your decision. Thank you
At the database?
DATE_FORMAT(my_date, "%m/%d/%Y %r") AS my_dateIn the controller? $date = new DateTime($my_date); $my_date=$date->format('m/d/Y');In a twig or smarty template? {{ mydate|date("m/d/Y g:i A") }}At the client using handlebars and the Moment library? UI.registerHelper("formatDate", function(datetime, format) { if (moment) { f = DateFormats[format]; return moment(datetime).format(f); } else { return datetime; } }); ... {{formatDate MyISOString "short"}} Hi again! I'm trying to use this code that i found somewhere in the net to display all the dates between 2 dates. It is exactly what i need but.. I understand the code and its structure (i think) but it gives me an error (maximum execution time of blah blah) which i think is because it makes an infinite loop(not sure.. ) Code: [Select] function GetDays($sStartDate, $sEndDate) { $sStartDate = gmdate("Y-m-d", strtotime($sStartDate)); $sEndDate = gmdate("Y-m-d", strtotime($sEndDate)); $aDays[] = $sStartDate; $sCurrentDate = $sStartDate; while($sCurrentDate < $sEndDate){ $sCurrentDate = gmdate("Y-m-d", strtotime("+1 day", strtotime($sCurrentDate))); $aDays[] = $sCurrentDate; } return $aDays; } Appreciate the help and suggestions! Gonna browse the forums for answers for the meantime... i have installed a calendar i want to extract the available id_item that are not id_state=1(booked) i want to query all the items that are not booked the dates: $fromdate=22-03-2011; $todate=25-03-2011; Code: [Select] this is bookings.php mysql_select_db($database_international, $international); $query_RsBookingIO = sprintf("SELECT * FROM `bookings` LEFT JOIN bookings_items ON bookings.id_item = bookings_items.id WHERE dateDIFF (2011-03-22, 2011-03-25) and bookings.id_state ='1' LIMIT 0 , 30 ", GetSQLValueString($colname_RsBookingIO, "int")); $RsBookingIO = mysql_query($query_RsBookingIO, $international) or die(mysql_error()); $row_RsBookingIO = mysql_fetch_assoc($RsBookingIO); <?php do { echo $row_RsBookingIO['the_date']; ?> <?php } while ($row_RsBookingIO = mysql_fetch_assoc($RsBookingIO)); ?> now when creating the searchfunction.php <?php $data = file_get_contents('http://localhost/bookings.php?fromdate=$fromdate and todate=$todate'); $fromdate = $_GET['fromdate']; $todate = $_GET['todate']; $dates = explode(' ',$data); var_dump($data); foreach($dates as $aDate) { echo $aDate; //$aDate = '\''.$aDate.'\''; if (!in_array($aDate, $dates)) { $available = true; } } return $available; ?> //tables CREATE TABLE `bookings` ( `id` int(11) NOT NULL AUTO_INCREMENT, `id_item` int(20) NOT NULL DEFAULT '0', `the_date` date NOT NULL DEFAULT '0000-00-00', `id_state` int(11) NOT NULL DEFAULT '0', `id_booking` int(10) NOT NULL DEFAULT '0', PRIMARY KEY (`id`), KEY `id_item` (`id_item`), KEY `id_state` (`id_state`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=12 ; -- -- Dumping data for table `bookings` -- INSERT INTO `bookings` VALUES(1, 2, '2011-03-22', 1, 0); INSERT INTO `bookings` VALUES(3, 2, '2011-03-23', 1, 0); INSERT INTO `bookings` VALUES(4, 2, '2011-03-24', 1, 0); INSERT INTO `bookings` VALUES(5, 2, '2011-03-25', 1, 0); INSERT INTO `bookings` VALUES(6, 2, '2011-03-26', 1, 0); INSERT INTO `bookings` VALUES(7, 3, '2011-03-23', 1, 0); INSERT INTO `bookings` VALUES(8, 3, '2011-03-24', 1, 0); INSERT INTO `bookings` VALUES(9, 3, '2011-03-25', 1, 0); INSERT INTO `bookings` VALUES(10, 3, '2011-03-26', 1, 0); INSERT INTO `bookings` VALUES(11, 3, '2011-03-27', 1, 0); CREATE TABLE `bookings_items` ( `id` int(11) NOT NULL AUTO_INCREMENT, `id_user` int(11) NOT NULL DEFAULT '1', `id_ref_external` int(11) NOT NULL COMMENT 'link to external db table', `desc_en` varchar(100) NOT NULL DEFAULT '', `desc_es` varchar(100) NOT NULL DEFAULT '', `list_order` int(11) NOT NULL DEFAULT '0', `state` tinyint(1) NOT NULL DEFAULT '1', PRIMARY KEY (`id`), KEY `id_user` (`id_user`), KEY `id_ref_external` (`id_ref_external`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=4 ; -- -- Dumping data for table `bookings_items` -- INSERT INTO `bookings_items` VALUES(1, 1, 4600, 'Suite_A', 'Suite_A', 2, 1); INSERT INTO `bookings_items` VALUES(2, 1, 4601, 'Suite_B', 'Suite_B', 2, 1); Hi, I'm trying to get the date, using this code <?php include('config.php'); $today = date('Y-m-d 00:00:00'); $nineyesterday = date('Y-m-d H:i:s', mktime(date("H") - (date("H") + 6), date("i") - date("i"), date("s") - date("s"), date("m") , date("d"), date("Y"))); $now = date('Y-m-d H:i:s'); $nineam = date('Y-m-d 9:00:00'); $ninepm = date('Y-m-d 18:00:00'); if ((strtotime($now) >= strtotime($today)) && (strtotime($now) <= strtotime($nineam))) { //count the answers by yes or no $q = "SELECT opt, count(opt) FROM plus_poll_ans WHERE date<='".$nineyesterday."' AND date>='".$nineam."' GROUP BY opt desc "; } elseif ((strtotime($now) >= strtotime($nineam)) && (strtotime($now) <= strtotime($ninepm))) { //count the answers by yes or no $q = "SELECT opt, count(opt) FROM plus_poll_ans WHERE date<'".$nineam."' AND date>='".$ninepm."' GROUP BY opt desc "; } $q = mysql_query($q) or die(mysql_error()); //separate the results while($row = mysql_fetch_array($q)) { $total_opt[] = $row['count(opt)']; } mysql_freeresult($q); $yes = intval($total_opt[0]); $no = intval($total_opt[1]); $total = $yes + $no; echo $total."<br/>"; echo $yes."<br/>"; echo $no."<br/>"; ?> but it didn't work, why isn't it working? Thanks Hi, I am trying two compare to dates but have not been successful. A row is filled in Mysql database called htime with $check=mktime(17,0,0,04,10,2011); My first question is that in the mktime function I have entered 17 which is hours. I would like to know if thats like the 17th hour of the given day or thats not how it works? My second question is it a valid query to use <= or >= or < in a mysql query for example. $query="SELECT * FROM hdb WHERE htime <='".time()."'"; Thirdly I want to know if a row is filled with mktime(17,0,0,04,10,2011); for example How can I only extract the day from the database based on the time has passed? This is because my own query doesnt seem to be working which is the query above I have no errors but the results dont seem to be right. Any help is much appreciated thanks. Hi There, I am trying to create a table, and accross the top I would like the Week Commencing Dates of the last 5 weeks. So for example: <table> <tr><td>07/02</td><td>31/01</td><td>24/01</td><td>17/01</td><td>10/01</td></tr> </table> Can anyone help? Cheers Matt I was just wondering if anyone can reccomend the best way to get dates from a database and turn them into dates you can display. For example if you have a date stored such as 23/08/10, is there an easy way to turn this into 23rd August 2010? Thanks for any help. |