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PHP - How Do I Populate A "select" Box Drop Down Menu In A Form With Database Fields?
I am currently creating a form and I want to populate a drop down selection menu with data from two fields in a form. For example, I want it to pull the first and last name fields from a database to populate names in a drop down menu in a form. I want the form to submit to the email address of the person selected in the drop down. Is this possible to do? The email is already a field in the record of the person in the database.
Can anyone give me some pointers or advice on how I should go about setting up the "Select" box drop down? I am not sure how to code it to do what I am wanting. Any links to relevant help would be appreciated too. Thanks in advance! Similar TutorialsCan someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> Hello, I am trying to populate the value="" of my form with the data from the mysql database so users can see what is already completed, trial and error have failed me. what am i doing wrong? <?php session_start(); include 'english.php'; if (!isset($_SESSION['user'])) die("<br /><br />You need to login to view this page"); $user = $_SESSION['user']; echo "<h3>Edit your Profile Search</h3>"; //opend database $connect = mysql_connect("$dbhost","$dbuser","$dbpass"); mysql_select_db("$dbname"); //select database // Get all the data from the "housing" table $result = mysql_query("SELECT * FROM users WHERE user='$user'") or die(mysql_error()); // keeps getting the next row until there are no more to get while($row = mysql_fetch_array( $result )) // Print out the contents of each row into a table ?> <form action="/includes/insert_profile.php" method="post"> <table border="0" cellspacing="0" cellpadding="3"> </td></tr> <tr><td>First Name:</td><td><input type="text" name="first" value="$first"> <tr><td>Middle Name:</td><td><input type="text" name="middle" value="$middle"> <tr><td>Last Name:</td><td><input type="text" name="last" value="$last"> <tr><td>Email:</td><td><input type="text" name="email" value="$email"> </td></tr> <tr><td>Date of Birth:</td><td> <select id="day" name="day" class="short"> <option value="1" selected="selected">1</option> <option value="2">2</option> <option value="3">3</option> </select> <select id="month" name="month" class="medium"> <option value="January" selected="selected">January</option> <option value="February">February</option> </select> <select id="year" name="year" class="medium"> <option value="2010" selected="selected">2010</option> <option value="2009">2009</option> <option value="2008">2008</option> </td></tr> <tr><td> <input type="Submit" value="Save"/> </td></tr> </table> </form> Hi there, i am relatively new to php, mysql, css etc but learning fast. My problem is such; i have a php file which is doing a SELECT mysql_query, WHILE results to strings, then ECHO the resulting rows to produce a list formatted using <table> and finally this <table> is inside a <form> which will POST the changes back to the specific database.tble.row. I wish to have a drop down menu within the <form><table> which will be populated from a separate database.table. I have accomplished the drop down menu outside the <?php ?> tags inside <form><table> which POSTS to a php file but my problem is to add the populating drop down menu inside <?php ?> an already ECHOing resulting rows from the sql query. i.e <?php blurb and stuff ?> <form><table><tr><td> <select name etc> <?php $result = mysql_query("SELECT * FROM tbl WHERE string = tble.rw ORDER BY column"); while($row=mysql_fetch_array($result)){ echo "<OPTION VALUE=".$row['column'].">".$row['column']."</OPTION>"; } ?> </select> WORKS!!!! but placing this inside <?php $x =mysql_query[select] while {strings = conditions; echo ("<form><table><tr><td> insert populated drop menu here </td> etc "); echo"";}?> doesnt work and just leaves the select drop menu blank Hoep you understand my problem. I do not think i can attached the population WHILE loop to a string and just insert the string to the form but maybe i am wrong. thanks in advance and if you go tthis far reading you must be on lots and lots of coffee zark
Hello I have an issue with a form that has been built by someone else on Wordpress. <div class="steps">
<div class="step gap-large step-1">
<h2 class="step-title"><span class="gold">Step 1.</span> Calculate the value of your <span class="gold">gold</span></h2>
[gold_calculator your-items]
</div>
<div class="step gap-large step-2">
<h2 class="step-title"><span class="gold">Step 2.</span> Submit your details</h2>
<div class="row">
<div class="column col-xs-12 col-sm-2 col-lg-4">
<label class="required" for="sell-title">Title</label>
[select* your-title id:sell-title class:form-control "Mr" "Mrs" "Miss" "Ms"]
</div>
<div class="column col-first-name col-xs-12 col-sm-5 col-lg-4">
<label class="required" for="sell-first-name">First Name</label>
[text* your-first-name id:sell-first-name class:form-control placeholder "Enter your first name"]
</div>
<div class="column col-last-name col-xs-12 col-sm-5 col-lg-4">
<label class="required" for="sell-last-name">Last Name</label>
[text* your-last-name id:sell-last-name class:form-control placeholder "Enter your last name"]
</div>
<div class="column col-xs-12 col-sm-12 col-lg-4">
<label class="required" for="sell-email">Email Address</label>
[email* your-email id:sell-email class:form-control placeholder "Enter your email address"]
</div>
<div class="column col-xs-12 col-sm-6 col-lg-4">
<label class="required" for="sell-daytime-phone">Daytime Telephone</label>
[tel* your-daytime-phone id:sell-daytime-phone class:form-control placeholder "Enter your telephone number"]
</div>
<div class="column col-xs-12 col-sm-6 col-lg-4">
<label class="" for="sell-mobile-phone">Mobile Telephone</label>
[tel your-mobile-phone id:sell-mobile-phone class:form-control placeholder "Enter your mobile number"]
</div>
<div class="column col-xs-12 col-sm-6 col-lg-6">
<label class="required" for="sell-address-1">Address Line 1</label>
[text* your-address-1 id:sell-address-1 class:form-control placeholder "Enter your address"]
</div>
<div class="column col-xs-12 col-sm-6 col-lg-6">
<label class="" for="sell-address-2">Address Line 2</label>
[text your-address-2 id:sell-address-2 class:form-control placeholder "Enter your address"]
</div>
<div class="column col-xs-12 col-sm-12 col-lg-4">
<label class="required" for="sell-city">Town/City</label>
[text* your-city id:sell-city class:form-control placeholder "Enter your town/city"]
</div>
<div class="column col-xs-12 col-sm-6 col-lg-4">
<label class="required" for="sell-county">County</label>
[text* your-county id:sell-county class:form-control placeholder "Enter your county"]
</div>
<div class="column col-xs-12 col-sm-6 col-lg-4">
<label class="required" for="sell-postcode">Postcode</label>
[text* your-postcode id:sell-postcode class:form-control placeholder "Enter your postcode"]
</div>
<div class="column col-xs-12 col-sm-12 col-lg-6">
<label class="required" for="sell-method">Choose your method of payment</label>
[select* your-method id:sell-method class:form-control "Instant Bank Transfer" "Cash" "Cheque"]
</div>
<div class="column col-xs-12 ccol-sm-12 col-lg-6">
<div class="input-label required">Terms & Conditions</div>
[acceptance your-price-acceptance id:sell-price-acceptance]I accept the price offered above for my gold.[/acceptance]
[acceptance your-terms-acceptance id:sell-terms-acceptance]I accept the <a href="/terms-conditions/" target="_blank">terms & conditions</a>.[/acceptance]
[acceptance your-acknowledgement id:sell-acknowledgement]I declare and acknowledge that: 1. I confirm the property enclosed is mine to sell, 2. I believe the items(s) to be genuine gold or platinum 3. You will contact me if the value calculated upon receipt differs in weight or carat 4. I accept payment will only be made to the person named on the submission form.[/acceptance]
</div>
<div class="column col-submit col-xs-12 col-sm-12">
<div class="alert alert-info">After clicking the ‘Submit’ button below, we'll email you a form to print off and include with the package you send to us. If you wish to be paid by bank transfer, please write your bank details on the form once printed.</div>
<div class="submit">[submit class:btn class:btn-gold "Submit"]</div>
</div>
</div>
</div>
</div>
<?php /** @var \Strive\Sections\Pdf_Form $this */ ?>
<head>
<style>
h1, h2 {
margin-top: 0;
}
th, td {
text-align: left;
vertical-align: top;
}
.section {
padding: 20px 0;
}
.border-top {
border-top: solid 1px #E7E7E7;
}
.cut-top {
border-top: dashed 1px #E7E7E7;
}
.text-placeholder {
background-color: #F7F7F7;
}
.cut-note {
text-align: center;
font-size: 80%;
margin-bottom: 5px;
}
</style>
</head>
<body>
<h1>Step 3. Print & post this form with your gold</h1>
<div class="section quote border-top">
<h2 class="section-title">Customer Quote:</h2>
<div>
<?php if ( $this->calculator['empty'] 😞 ?>
<p>You didn't weigh your gold - don't worry, we'll do it for you and call you with an offer. </p>
<?php else: ?>
<ol>
<?php foreach ( $this->calculator['items'] as $item 😞 ?>
<li><?php echo $item['weight']; ?>g of <?php echo $item['name']; ?> -
£<?php echo $item['price']; ?></li>
<?php endforeach; ?>
</ol>
<p>Total: £<?php echo $this->calculator['total']; ?></p>
<?php endif; ?>
</div>
</div>
<div class="section details border-top">
<h2 class="section-title">Customer Details:</h2>
<table width="100%">
<tr>
<td width="50%">
<table width="100%">
<tr>
<th>Reference:</th>
<td><?php echo $this->reference; ?></td>
</tr>
<tr>
<th>Name:</th>
<td></td><?php echo empty( $this->title ) ? '' : $this->title; ?>
<?php echo empty( $this->first_name ) ? '' : $this->first_name; ?>
<?php echo empty( $this->last_name ) ? '' : $this->last_name; ?></td>
</tr>
<tr>
<th>Email:</th>
<td><?php echo empty( $this->email ) ? '-' : $this->email; ?></td>
</tr>
<tr>
<th>Telephone:</th>
<td><?php echo empty( $this->daytime_phone ) ? '-' : $this->daytime_phone; ?></td>
</tr>
<tr>
<th>Mobile:</th>
<td><?php echo empty( $this->mobile_phone ) ? '-' : $this->mobile_phone; ?></td>
</tr>
</table>
</td>
<td width="50%">
<table width="100%">
<tr>
<th>Address 1:</th>
<td><?php echo empty( $this->address_1 ) ? '' : $this->address_1; ?></td>
</tr>
<tr>
<th>Address 2:</th>
<td><?php echo empty( $this->address_2 ) ? '' : $this->address_2; ?></td>
</tr>
<tr>
<th>Town/City:</th>
<td><?php echo empty( $this->city ) ? '' : $this->city; ?></td>
</tr>
<tr>
<th>County:</th>
<td><?php echo empty( $this->county ) ? '' : $this->county; ?></td>
</tr>
<tr>
<th>Postcode:</th>
<td><?php echo empty( $this->postcode ) ? '' : $this->postcode; ?></td>
</tr>
</table>
</td>
</tr>
</table>
</div>
<div class="section payment border-top">
<p>Preferred Payment Method: <?php echo empty( $this->method ) ? '' : $this->method; ?></p>
<?php if ( $this->method === 'Instant Bank Transfer' 😞 ?>
<p>Write down your bank details below for the account in which you wish funds to be deposited.</p>
<table width="100%">
<tr>
<th width="25%">Bank:</th>
<td width="75%" class="text-placeholder"> </td>
</tr>
<tr>
<th>Name on Account:</th>
<td width="75%" class="text-placeholder"> </td>
</tr>
<tr>
<th>Sort Code:</th>
<td width="75%" class="text-placeholder"> </td>
</tr>
<tr>
<th>Account No:</th>
<td width="75%" class="text-placeholder"> </td>
</tr>
</table>
<?php endif; ?>
</div>
<div class="cut-note">Print this form, include the above part in your package and post to the address below.</div>
<div class="section address cut-top">
<p>
SMG<br><br>
<?php echo empty( $this->send_address ) ? '' : $this->send_address ?>
</p>
</div>
</body>
any help would be appreciated. Edited July 28 by Barandcode tags added I want to post some form identifyer when I hit submit, so that I can use this in an SQL query. Previously I used the below code and would retrieve either page1.php or page2.php etc from $_POST['subject']); Code: [Select] <td> <select name="subject" id="subject" onchange="gotourl(this.value)"> <option value="" >Please Select</option> <option value="page1.php" >page1</option> <option value="page2.php">page2</option> <option value="page3.php">page3</option> </select> </td> will this work? Code: [Select] <form id="form1" name="form1" value="tableName" method="post" action=""> $_POST['form1']) returns tableName...... Thanks Hi, I need a clue on how to do a form with a "List/Menu" that when I choose one value on the "List" the page will reload and show that "List/Menu" and other new one. There are exemples on how to do this? Best Regards, Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! Hi everyone, I have the task of building a PHP page where users can enter or remove as many records as they like into different categories. This then makes the number of records entered unknown, and therefore it becomes more complicated. To make this clearer, I have attached an image of what I am trying to do. Two questions: - Before submitting the form, how can each record entry be matched with the correct category? (maybe hidden form fields somehow?) - What is the best way of inserting each record (and it's associated category) into a MySQL database table from a single form submit? I want to try and keep this as simple as possible as the data will later be updated, removed etc. I'm experiencing a brain fart and just cannot picture the best way of going about this Any help and advice is much appreciated! Thanks in advance. Code: [Select] Basic table schema example... CATEGORY TABLE ---------------------------- | catid | category | ---------------------------- | 1 | Category A | | 2 | Category B | etc. etc. ---------------------------- DATA ENTRY TABLE ---------------------------- dataid | catid | data | -------------------------------- | 1 | 2 | data xyz | | 2 | 1 | data zyx | etc. etc etc. -------------------------------- ...added to an error log? Currently, my coding is as follows: Form to gather data: Code: [Select] <html><head><title>Car Accident Report Form</title></head> <form action="errorlog.php" method="post"> First Name: <br><input type="text" name="name"><br> Surname:<br> <input type="text" name="surname"><br> Age: <br><input type="text" name="age"><br> Weeks Since Accident: <br><input type="text" name="weeks"><br> <input type="submit" value="Submit"> </form> Coding for error log: Code: [Select] <html><head><title>Validating Car Accident Report Form Details</title></head> <?php $name=$_POST["name"]; $surname=$_POST["surname"]; $age=$_POST["age"]; $weeks=$_POST["weeks"]; $subtime = strftime('%c'); $pass = "The details uploaded are fine<br><br>"; if ((((trim($name)="" && trim($surname)="" && trim($age)="" && trim($weeks)="")))) { echo "It seems that you have not entered a value for the Name, Surname, Age or Weeks fields. This has been added to the error log.<br><br>"; error_log("<b><u>Error</b></u><br>The user has not entered any values", 3, "C:/xampp/htdocs/errorlog.txt"); } if (($age<18)&& ($weeks<=1)) { echo "It seems that you have entered an invalid age and number of weeks since the accident. This has been added to the error log.<br><br>"; error_log("<b><u>Error</b></u><br>The user has entered an age that is below 18 and the number of weeks since the accident is equal to or under 1 week!<br>Age entered:" . $age . "<br>Number Of Weeks Since Accident entered:" . $weeks . "<br>Time that form was submitted:" . $subtime . "<br><br>", 3, "C:/xampp/htdocs/errorlog.txt"); } else if ($age<18) { echo "It seems that you have entered an invalid age. This has been added to the error log.<br><br>"; error_log("<b><u>Age Error</b></u><br>The user has entered an age that is below 18!<br>Age entered:" . $age . "<br>Time that form was submitted:" . $subtime . "<br><br>", 3, "C:/xampp/htdocs/errorlog.txt"); } else if ($weeks<=1) { echo "It seems that you have entered an invalid age number of weeks since the accident. This has been added to the error log.<br><br>"; error_log("<b><u>Week Error</b></u><br>The user has entered a number of weeks since the accident that is equal to or under 1 week!<br>Number Of Weeks Since Accident entered:" . $weeks . "<br> Time that form was submitted:" . $subtime . "<br><br>", 3, "C:/xampp/htdocs/errorlog.txt"); } else { echo $pass; } echo "Car Accident Report Form details have been sent<br>"; echo "<a href='readlog.php'>Read Error Log</a>" ?> </html> How can I get it so that if a user presses the space bar in a field, then the trim function sees that there's no white space and then this gets added to the error log? Any help is appreciated! Is there any way using only PHP? The problem is that I don't have access to the form processor, or to MySQL. Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks Hi all. I was wondering if there was a way (other than retrieving db fields with a query) to show something like "customer_id" as "Customer ID". Is there a functionality of this nature in either MySQL or PHP? I'm aware of preg_replace and such but that would still require two queries; one for the field names and one for the data (right?) What I am looking for is that if any field in a database is empty, the form comes back and puts in the word "empty" into the web page, but not the database. I got this right now, it shows the first part fine, but the second part it doesn't show the "Empty" comment... I don't understand why... as far as I can tell the code is fine... Code: [Select] <?php //Nonconformity, Disposition, Comments and Comments & Additional Details echo '<div id="box3">'; if (!empty($row['Nonconformity']) || !empty($row['Disposition']) || !empty($row['Comments']) || !empty($row['CommentsAdditional_Details'])) { echo '<div id="non"><span class="b">Nonconformity: </span><br />' . $row['Nonconformity'] . '</div>'; echo '<div id="dis"><span class="b">Disposition: </span><br />' . $row['Disposition'] . '</div>'; echo '<div id="comm"><span class="b">Comments: </span><br />' . $row['Comments'] . '</div>'; echo '<div id="comma"><span class="b">Comments and/or Additional Details: </span><br />' . $row['CommentsAdditional_Details'] . '</div>';} else if (empty($row['Nonconformity']) || empty($row['Disposition']) || empty($row['Comments']) || empty($row['CommentsAdditional_Details'])) { echo '<div id="non"><span class="b">Nonconformity: </span><br />Empty</div>'; echo '<div id="dis"><span class="b">Disposition: <br /></span>Empty</div>'; echo '<div id="comm"><span class="b">Comments: <br /></span>Empty</div>'; echo '<div id="comma"><span class="b">Comments and/or Additional Details: </span><br />Empty</div>';} echo '</div>'; ?> cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/aci/docs/admin/hours.php on line 20 Code: [Select] <?php $user = $_SESSION['myusername']; $result = mysql_query("SELECT * hours WHERE member='$user'"); while ($row = mysql_fetch_array($result)){ echo $row['date'] . " " . $row['time'] . "<br />"; } ?> Code: [Select] CREATE TABLE `hours` ( `hoursID` int(5) NOT NULL auto_increment, `member` varchar(20) NOT NULL default '', `date` date NOT NULL default '0000-00-00', `time` time NOT NULL default '00:00:00', PRIMARY KEY (`hoursID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=7 ; -- -- Dumping data for table `hours` -- INSERT INTO `hours` VALUES (4, 'aci', '2010-11-30', '14:31:39'); INSERT INTO `hours` VALUES (2, 'aci', '2010-11-30', '14:31:08'); INSERT INTO `hours` VALUES (3, 'aci', '2010-11-30', '14:31:23'); INSERT INTO `hours` VALUES (5, 'aci', '2010-11-30', '14:31:40'); Hi, I need to call to this text to add a all with value "blank/empty" or "0" to the dropdownlist code below.. it should be inserted int the first position in the dropdownlist and have a value blank and call to this text from the language files: $searchAll = gettext('_LANGUAGE_SEARCH_ALL',_LANGUAGE_SEARCH_ALL,false,false); example is: ratestitle=>0 gettext('_LANGUAGE_SEARCH_ALL',_LANGUAGE_SEARCH_ALL,false,false); the words it calls is "ALL" when the user selects or leaves the "ALL" in the list the value remains empty this allows the search to search everything.. basically im stuck how to get it in the dropdown list as the first default position: can anyone help? here is my code://this is a search function which calls to the field rate_title the text from the select box is matched to the database table and the search pages shows the search option is the search is successful.. I have 5 of these types of searches but cant give a broader search option to my users as the values must be selected to search--- i need the option "ALL" to have a "EMPTY" value or no value.... if (in_array("ratestitle",$searchOptions)&& $showSearchOptions ) { if (empty($sch->filter['ratestitle']) ) $selectOption=$output['LANGUAGE_SEARCH_RATESTITLE']; else $selectOption=$sch->filter['ratestitle']; $showButton=true; $query = "SELECT DISTINCT rate_title FROM #__rates_table ORDER BY rate_title ASC"; $dropDownList ="<select class=\"inputbox\" name=\"ratestitle\">"; $ratesitles =doSelectSql($query); foreach ($ratesitles as $ratetitle) { $selected=""; $rate_title=$ratetitle->rate_title; if ($ratetitle==".$sch->filter['ratestitle'].") $selected="selected"; $dropDownList .= "<option ".$selected." value=\"".$rate_title."\">".$rate_title."</option>"; } $dropDownList.="</select>"; $output['RATESTITLE']=$dropDownList; } I am trying to print the list of a table which I requested with "SELECT DISTINCT" as below Code: [Select] $db_connect = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $sql_get = "SELECT DISTINCT category FROM con"; $sql_run = mysqli_query($db_connect, $sql_get) or mysqli_error($db_connect); $sql_assoc = mysqli_fetch_assoc($sql_run); What is now needed to print the list of the table data by this conditions? I tried the while loop, but I seem to approach wrong, and get endless loops or errors. I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
I am attempting to use use two tables from the same database as described below. My db connection is made and is good. As part of a larger application I am creating a comments feature. Each row is a separate comment that was left by a user. I've no problem getting each row from the database and printing each out as I want formatted. The second table I am using contains all of the personal info of each member including their username, their displayed name, location and among other things the URL to an image they want associated with their account. Each row in the comments table contains the following id # of the comment, username of the person that left it, the date and of course the body of the message itself. Now I am trying to get the comment to show the image found at the URL in the second table (personal info). So for each row in the comments table I want it to pull the commentor's img_url from the second table. $result = mysql_query("SELECT * FROM page_comments WHERE page_id = '$id'"); if(mysql_num_rows($result)==0) { echo "There are currently no comments."; }else{ while($row = mysql_fetch_array($result)) { echo "<table>"; echo "<tr>"; echo "<td>"; echo "<img sro=\"$img_url\" width=50 height=50>"; echo "</td>"; echo "<td>"; echo "<a href=profile.php?member="; echo $row['commentor']; echo ">"; echo $row['commentor']; echo "</a>"; echo "</td>"; echo "<td>"; echo $row['date']; echo "</td>"; echo "</tr>"; echo "<tr>"; echo "<td cospan=3>"; echo $row['comment']; echo "</td>"; echo "</tr>"; echo "</table>"; echo "<br />"; } } As you can see I've thrown the "$img_url" in there as a placeholder for the time being. I've tried a couple of ideas and while none of them threw any errors it, of course, didn't return a value so the img was broken and the HTML source was just empty. Any and all ideas are greatly appreciated. |
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