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PHP - Pass Post Vars When Opening Web Page With Php
Hi guys,
I know that you can open web page with $handle = fopen("http://www.example.com/", "r"); but i am wondering is there a way to pass POST vars when doing so, or there is another method that can that like you do it with ajax. I have mvc application that i want to test. I am using CodeIgniter framework so i want to call my controllers with POST values. Every controller method returns data holder object that holds the data of operation whether is successful or not. Also every method inside controller can be called with parameter input or with post input. If you omit the parameters when calling controller method than he will try to load that parameters from post and that is why i want to pass POST vars with php when calling controller for example i want to call: fopen("http://localhost/MyAppFolder/index.php/controller/method"); but i want to pass it some POST vars if that is possible Thanks. Similar TutorialsTrying to pass VARS $URL1 and $type to header location.Heres the code. Code: [Select] $URL1 = $_POST['url']; $type = $_POST['type_request']; session_start(); $string = strtoupper($_SESSION['string']); $userstring = strtoupper($_POST['userstring']); session_destroy(); if (($string == $userstring) && (strlen($string) > 4)) { header("Location: $success"); exit(); The VARS come from a FORM and then go to this script for checkind data. I need to have them continue to the next page. Alright, so I am writing a script for a secretary to do some data entry. With this script there is a few file upload fields, now depending on the item entered not all fields need to be filled out. Therefore, the SQL statement will change depending on whether or not that field was filled out. Should I just use IF statements to check too see if the POST var was sent, then change the statement accordingly, or would there be a more productive way? Thanks for any feedback.. Hi there, I am new to PHP and trying to put my learning together as I progress. Here's the problem: I would like to open HTML file after a certain condition is met. I tried to fopen() but it gave an empty page. Here's the code: Code: [Select] <?php $shape = $_POST['shape']; if($shape=='Triangle') { fopen('ogc_show_triangle.php', 'r'); } else { echo "Select a shape."; } ?> Thanks in advance! ^_^ Some code from my pages ,
Page1 ( Redirecting page )
<html> <title>login_redirect.</title> body> <form name="redirect" action="http://mysite/page2.php" method="post"> <input type="hidden" name="mac" value="$(mac)"> </form> <script language="JavaScript"> <!-- document.redirect.submit(); //--> </script> </body> </html>Page 2 ( select product )
<?php
session_start();
ini_set('display_errors',1);
error_reporting(E_ALL);
include '../lib/config.php';
include '../lib/opendb.php';
// get user mac adres from redirect post page1
$_SESSION['macid'] = $_POST['mac'];
// set $macid for other use ( maybe not needed, am learning )
$macid = $_SESSION['macid'];
// echo $macid does show mac adress, so variable is not empty here
if (!empty($_POST["submit"]))
{
$product_choice = $_POST['accounttype'];
$query= "SELECT AccountIndex, AccountCost, AccountName FROM AccountTypes WHERE AccountIndex='$product_choice'";
$result = mysql_query($query) or die('Query failed. ' . mysql_error());
while($row = mysql_fetch_array($result))
{
$_SESSION['AccountIndex'] = $row['AccountIndex'];
$_SESSION['AccountCost'] = $row['AccountCost'];
$_SESSION['AccountName'] = $row['AccountName'];
}
header('Location: page3.php');
}
// did leave out the other/html/form stuff here
Page 3 ( show Session variables )
<?php
ini_set('display_errors',1);
error_reporting(E_ALL);
session_start();
print_r($_SESSION);
?>
Now, on page 3 i do see the right session varables, only the "macid" is empty.
why ?
Hello, everyone. I have code that effectively calls a PHP page with AJAX (no JQuery). The PHP responds fine with an echo. Here is the javaScript that calls the PHP so refreshing the page doesn't need to be done.
function deleteCategory()
{
var e= document.getElementById("dropDown1");
var var1 = e.options[e.selectedIndex].text;
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = alerta() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("insert").innerHTML = xmlhttp.responseText;
}
};
xmlhttp.open("GET", "deleteRow.php?q=" + var1 , true);
xmlhttp.send();
}
How do I call a PHP function on the same page while preserving the above AJAX.
Sincerely, Joshua Hi.. I have an issue on my project.I want to open a particular page of a PDF file by clicking a hyper link.How should I do it?any idea ? I used the following code <?php header("Content-Type: application/pdf"); $pdfFile="readme.pdf#page=10"; ?> <html> <head> <title>Untitled Document</title> </head> <body> <a href="http://<?php echo $pdfFile; ?>">Click Here</a> </body> </html> But it showing an alert like following File does not begin with '%PDF-' After clicking alert showing a black screen.. can u please send me the entire code? Thanks... This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=347360.0 How would I pass variables from one page to another without using forms or $_GET features. Let say I have page (1.php) where If define $secret_phrase = "open sesame";. On that page (1.php) I have multiple html links to multiple pages (2.php, 3.php, ...) if you click on the link to 2.php page I would like to pass the $secret_phrase as well without having it encoded into a link or using forms. Is there a way to do it? Thanks i knw dis mst a simple question but how to pass variable to other page for eg i hav created a page where user submits username n telephone then via sms some random number goes to user mobile ...i want this random number variable in other page dis is my code for startreg.php <form action="startregprocess.php" method="post"> username:<input type="text" name="username"> telephone<input type="text" name="telephone" <input type="submit" name="submit"> </form> <?php srand ((double) microtime( )*1000000); $random_number = rand( ); echo $random_number; ?> i want tht $random_number in other page called startregprocess.php Hello I have this login page with code Code: [Select] <?php header("Expires: Thu, 17 May 2001 10:17:17 GMT"); // Date in the past header ("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT"); // always modified header ("Cache-Control: no-cache, must-revalidate"); // HTTP/1.1 header ("Pragma: no-cache"); // HTTP/1.0 session_start(); //Below means if session database server crdentials is not set, require to use/set that connection then if (!isset($_SESSION['SESSION'])) require ( "../db_connection.php"); if($_SESSION['LOGGEDIN'] == TRUE) { header("Location: account.php"); exit; } $_SESSION['FORM_SUBMITTED'] = ""; $CRLF = chr(13).chr(10); $user_id = ""; if (isset($HTTP_GET_VARS["user_id"])) $user_id = $HTTP_GET_VARS["user_id"]; if ($user_id == '') { if (isset($_SESSION['user_id'])) $user_id = $_SESSION['user_id']; } //Validations $flg = ""; $error = ""; if (isset($HTTP_GET_VARS["flg"])) $flg = $HTTP_GET_VARS["flg"]; switch ($flg) { case "yellow": $error = "<font class=\"txt_main_str12_mar\"><BR>Your Account Has Not Been Verified.<BR>Check your email for Activation Instructions.<br>Click <a href=\"/courses/forgot_login.php\">here</a> to have the activation email resent.</font>"; break; case "red": $error = "<font class=\"txt_main_str12_mar\"><BR>That userid/password combination is not in our database.<br>Please Try Again.</font>"; break; case "blue": $error = "<font class=\"txt_main_str12_mar\"><BR>Your Session has Expired.<br>Please Login Again.</font>"; break; default: $error = " <br>"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Login Page</title> <script language="JavaScript"> <!-- function loadedPage() { } function submitForm() { if (isEmpty(document.forms[0].user_id.value)) { alert("Please enter your UserID."); bSubmit = false; return false; } if (isEmpty(document.forms[0].password.value)) { alert("Please enter your Password."); bSubmit = false; return false; } document.forms[0].submit(); } //--> </script> </head> <body><center><br /><br /> <form name="form1" method="post" id="form1" action="/php/sessions/login/login_processing.php"> <table> <tr> <td>User ID</td> <td><input type="text" name="user_id" id="user_id" value="<?php echo $user_id ?>" size="24" maxlength="30" /></td> </tr> <tr> <td>Password</td> <td><input type="password" name="password" id="password" size="24" maxlength="30" /></td> </tr> <tr> <td> </td> <td><input type="submit" name="Submit" value="Submit" onclick="submitForm();" /></td> </tr> </table> </form> </center> </body> </html> and login processing page with code Code: [Select] <?php header("Expires: Thu, 17 May 2001 10:17:17 GMT"); // Date in the past header ("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT"); // always modified header ("Cache-Control: no-cache, must-revalidate"); // HTTP/1.1 header ("Pragma: no-cache"); // HTTP/1.0 session_start(); //Below means if session database server crdentials is not set, require to use/set that connection then if (!isset($_SESSION['SESSION'])) require ( "../db_connection.php"); // reset session variables... $_SESSION['user_id'] = ""; $_SESSION['LOGGEDIN'] = false; $_SESSION['EMAIL'] = ""; $_SESSION['FNAME'] = ""; $_SESSION['LNAME'] = ""; // initialize variables... $user_id = ""; $password = ""; $email = ""; // make sure post parameters were sent... if (isset($HTTP_POST_VARS["user_id"])) $user_id = addslashes($HTTP_POST_VARS["user_id"]); if (isset($HTTP_POST_VARS["password"])) $passwd = addslashes($HTTP_POST_VARS["password"]); $_SESSION['user_id'] = $user_id; // form variables must have something in them... if ($user_id == "" || $password == "") { header("Location: ./login_page.php?flg=yellow&user_id=".$user_id); exit; } ?> I'm having problem with the last piece of code above, it's redirecting me eventhough I have entered a value on the userid and password from the login page... I have this function where i want to pass the month and year according to the date drop down that is chosen by the user. But can't seem to get the selected month and year. But instead, i got the month and year for now (which is April 2020). Can any one show me how can i achive this? I mean how can i pass the month and year selected to my `allreport-summary.php` page. It would be better if you guys can show me examples of codes on how can i implement this. Any help will be appreciated. Thank you so much. cheers!
<div class="row">
<div class="col-4 my-auto">
<input type="month" id="month" class="form-control" value="<?php echo date('Y-m'); ?>">
</div>
<div class="col-4 my-auto">
<select class="form-control" id="seller">
<option value="">Select All</option>
<?php
$sql = "SELECT * FROM sellers ORDER BY seller_registered";
$query = $conn->query($sql);
while ($row = $query->fetch_assoc()) {
?>
<option value="<?php echo $row['id'];?>"><?php echo $row['seller_fullname'];?></option>
<?php } ?>
</select>
</div>
<div class="col-4">
<button type="button" class="btn btn-info" onclick="loadreports();">
<i class="nc-icon nc-zoom-split"></i>
</button>
<a href="allreport-summary.php?month=<?php echo date('Y-m');?>">
<button type="button" class="btn btn-info" style="height: 40px;">
<i class="fa fa-file-excel-o"></i> Export All Report
</button>
</a>
</div>
I have a page that has roughly 100 text input fields. Once the user is done, I need to put the data in my mysql db. How do I get the data from the user input page to the php page that will process the data (e.g. process.php)? I've done some searching and found a few possibilities use a ajax style call back to load a seperate asp page (e.g. createsession.asp) and that page set session variables that can then be read by process.php write everything to a cookie using some sort of a delimiter so that it can handle multiple variables (e.g. cookie data => var1/var2/var3/var4... write all the data to a text file and then have process.php load that file Which should I pursue? Is there a better option? First, I will select checkbox then click generate report then it displays the items with download link Then i click download link to download the selected checkbox values in pdf I want to download the selected checkbox items by clicking download link Now i am getting all check box items in the pdf download How to download only the selected check box items Code: [Select] <?php session_start(); $_SESSION['pidd'] = 2; $sessvar = $_SESSION['pidd']; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Untitled Document</title> <link rel="stylesheet" type="text/css" href="css/style.css" /> <style type="text/css" media="print"> DIV#noprint{visibility:hidden;} INPUT#printbutt{visibility:hidden;} #downloadlink{visibility:hidden;} </style> <script type="text/javascript"> function gen() { var st1=document.getElementById("ckbox1").checked; var st2=document.getElementById("ckbox2").checked; var st3=document.getElementById("ckbox3").checked; var st4=document.getElementById("ckbox4").checked; if(st1 == true) { document.getElementById('g1').style.display = 'block'; } if(st2 == true) { document.getElementById('g2').style.display = 'block'; } if(st3 == true) { document.getElementById('g3').style.display = 'block'; } if(st4 == true) { document.getElementById('g4').style.display = 'block'; } document.getElementById('p_info').style.display = 'none'; document.getElementById('histree').style.display = 'none'; document.getElementById('insurence').style.display = 'none'; document.getElementById('billin').style.display = 'none'; } function showuser() { document.getElementById('g1').style.display = 'none'; document.getElementById('g2').style.display = 'none'; document.getElementById('g3').style.display = 'none'; document.getElementById('g4').style.display = 'none'; var str1=document.getElementById("ckbox1").checked; var str2=document.getElementById("ckbox2").checked; var str3=document.getElementById("ckbox3").checked; var str4=document.getElementById("ckbox4").checked; if(str1 == true) { document.getElementById('p_info').style.display = 'block'; } else document.getElementById('p_info').style.display = 'none'; if(str2 == true) { document.getElementById('histree').style.display = 'block'; } else document.getElementById('histree').style.display = 'none'; if(str3 == true) { document.getElementById('insurence').style.display = 'block'; } else document.getElementById('insurence').style.display = 'none'; if(str4 == true) { document.getElementById('billin').style.display = 'block'; } else document.getElementById('billin').style.display = 'none'; } function checkByParent(aId, aChecked) { var collection = document.getElementById(aId).getElementsByTagName('INPUT'); for (var x=0; x<collection.length; x++) { if (collection[x].type.toUpperCase()=='CHECKBOX') collection[x].checked = aChecked; } } </script> </head> <body> <div id="main_content"> <div id="left"> <div id="noprint"> <h4>Patient Report</h4> <a id="check_all" href="#" style="text-decoration:none" onClick="checkByParent('checkboxes', true); return false;">check all</a> <a id="uncheckall" href="#" style="text-decoration:none" onClick="checkByParent('checkboxes', false); return false;">uncheck all</a> <br> <br> <form method="post" name="myform" action=""> <div id="checkboxes"> <div id="cb_id1"> <input id="ckbox1" name="cbox1" type="checkbox" <? if(isset($_REQUEST['cbox1'])) echo 'checked="checked"' ; ?> value="p_info" /> Patient Info </div> <div id="cb_id2"> <input id="ckbox2" name="cbox2" type="checkbox" <?php if(isset($_REQUEST['cbox2'])) echo 'checked="checked"' ; ?> value="histree" /> History </div> <div id="cb_id3"> <input id="ckbox3" name="cbox3" type="checkbox" <?php if(isset($_REQUEST['cbox3'])) echo 'checked="checked"' ; ?> value="insurance" /> Insurence </div> <div id="cb_id4"> <input id="ckbox4" name="cbox4" type="checkbox" <?php if(isset($_REQUEST['cbox4'])) echo 'checked="checked"' ; ?> value="billin" /> Billing </div> </div> <!--checkboxes div --> <br> <input id="vuprint" name="view" type="button" value="View" onClick="showuser();"> <hr/> <label for="docs"> Documents:<br> <br> </label> <input name="sub" type="button" value="Generate report" onclick="gen();"> <hr/> </form> <input id="printbutt" name="prt" type="button" value="Print" onClick="javascript:window.print();"> </div> <!--No print --> </div> <!--Left div --> <div id="side"> <div id="p_info"> <?php require("db_conn.php"); $pinfo = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='".$sessvar."' "); while($fet = mysqli_fetch_array($pinfo)) { echo "<h4>Patient Info</h4>"; echo "<b>Name: </b>" . $fet["P_Fname"] . " " . $fet["P_Lname"]. "<br>"; echo "<b>Dob:</b> " . date("d-m-Y",strtotime($fet["P_Dob"]))."<br>"; echo "<b>Age:</b> " . $fet["P_Age"]."<br>"; echo "<b>Gender:</b> " . $fet["P_Gender"]."<br>"; echo "<b>Marital Status:</b> " . $fet["P_Mstatus"]."<br>"; echo "<b>Blood: </b>" . $fet["P_Blood"]."<br>"; echo "<b>Height: </b>" . $fet["P_Height"] . $fet["P_Hval"]."<br>"; echo "<b>Weight: </b>" . $fet["P_Weight"] . $fet["P_Wval"]; } ?> </div> <div id="histree"> <?php $his = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='".$sessvar."' "); while($hisrow = mysqli_fetch_array($his,MYSQLI_ASSOC)) { echo "<h4>Patient Histroy</h4>"; echo "<b>P_Idate: </b>" . date("d-m-Y",strtotime($hisrow["P_Idate"]))."<br>"; echo "<b>P_Edate: </b>" . date("d-m-Y",strtotime($hisrow["P_Edate"]))."<br>"; echo "<b>D_Ddate: </b>" . date("d-m-Y",strtotime($hisrow["D_Ddate"])); } ?> </div> <!-- Insurence --> <div id="insurence"> <?php $insu = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='".$sessvar."' "); while($insrow = mysqli_fetch_array($insu,MYSQLI_ASSOC)) { ?> <?php echo "<h4>Insurence</h4>"; echo "<b>P_Isname: </b>" . $insrow["P_Isname"]."<br>"; // echo $insow[""]; } ?> </div> <div id="billin"> <?php $bilrow = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='1' "); while($bill = mysqli_fetch_array($bilrow,MYSQLI_ASSOC)) { ?> <?php echo "<h4>Billing</h4>"; echo "<b>P_Fbill: </b>" . $bill["P_Fbill"]."<br>"; echo "<b>Fees: </b>" . $bill["fees"]; } ?> </div> </div> <!--/side div --> <div id="generatereport"> <div id="g1" style="display:none; clear:both;"> <label for="Gen_reports">Generaterd reports</label> <br /> <br /> <?php $pinfo = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='1' "); while($fet = mysqli_fetch_array($pinfo,MYSQLI_ASSOC)) { $new_dob = date("d-m-Y",strtotime($fet["P_Dob"])); ?> <?php echo "<h4>Patient Info</h4>"; echo "<b>Patient Id:</b> ". $fet["P_Id"]."<br>"; echo "<b>Name:</b> " . $fet["P_Fname"] . " " . $fet["P_Lname"]."<br>"; echo "<b>Dob:</b> " . $new_dob ."<br>"; echo "<b>Age:</b> " .$fet["P_Age"]."<br>"; echo "<b>Gender:</b> " . $fet["P_Gender"]."<br>"; echo "<b>Marital Status:</b> " . $fet["P_Mstatus"]. "<br>"; echo "<b>Blood:</b> " . $fet["P_Blood"] . "<br>"; echo "<b>Height:</b> " . $fet["P_Height"] . $fet["P_Hval"]. "<br>"; echo "<b>Weight:</b> " . $fet["P_Weight"] . $fet["P_Wval"]. "<br>"; } echo "*************************************************************************************************************************"; ?> </div> <div id="g2" style="display:none"> <?php $his = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='1' "); while($secrow = mysqli_fetch_array($his,MYSQLI_ASSOC)) { echo "<h4>Patient Histroy</h4>"; echo "<b>P_Idate:</b> " . date("d-m-Y",strtotime($secrow["P_Idate"])) ."<br>"; echo "<b>P_Edate:</b> " . date("d-m-Y",strtotime($secrow["P_Edate"])) ."<br>"; echo "<b>D_Ddate:</b> " . date("d-m-Y",strtotime($secrow["D_Ddate"])) ."<br>"; } echo "*************************************************************************************************************************"; ?> </div> <div id="g3" style="display:none"> <?php $insu = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='1' "); while($insrow = mysqli_fetch_array($insu,MYSQLI_ASSOC)) { echo "<h4>Insurence</h4>"; echo "<b>P_Isname:</b>" . $insrow["P_Isname"]."<br>"; } echo "*************************************************************************************************************************"; ?> </div> <div id="g4" style="display:none"> <?php $bilrow = mysqli_query($mysqli,"SELECT * FROM patient_datas WHERE P_Id='1' "); while($bill = mysqli_fetch_array($bilrow,MYSQLI_ASSOC)) { echo "<h4>Billing</h4>"; echo "<b>P_Fbill:</b> " . $bill["P_Fbill"]."<br>"; echo "<b>Fees:</b> " . $bill["fees"]; } ?> </div> <?php $infochk = 'p_info'; $hischk = 'histree'; $insuchk = 'insurance'; $billchk = 'billin'; ?> <a id="downloadlink" href="download_pdf2.php?info=<?php if(isset($infochk)) echo $infochk; ?>&hist=<?php if(isset($hischk)) echo $hischk; ?>&insu=<?php if(isset($insuchk)) echo $insuchk; ?>&billin=<?php if(isset($billchk)) echo $billchk; ?>">Download</a> </div> <!--generate report --> </div> <!--/main_coontent --> </body> </html> I want to query a database (search) and pass the desired columns from the search results to another page like so: Code: [Select] <?php //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); //authenticate user require('auth.php'); if (isset($_POST['submit'])) { // Connect to the database. require_once ('config.php'); //Query the database. $sql = "SELECT* FROM members INNER JOIN images ON members.member_id = images_member_id WHERE members.ethnicity = '{$_POST['ethnicity']}'"; $query = mysql_query($sql); if(mysql_num_rows($query) > 0){ while(($row = mysql_fetch_assoc($query)) !== false) { //Redirect to search results page. header("Location: search_results.php?friend='.$row['member_id'].'&me='.$_SESSION['id'].' &pic='.$row['image'].'&name='.$row['username'].'"); } } else { //If no results found. echo 'No results match this search query.' ; } } ?> I get the following error when i try to run the page (by submitting a form from another page which executes this page): Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /home/a4993450/public_html/profile_search.php on line 31 The culprit line is this one: header("Location: search_results.php?friend='.$row['member_id'].'&me='.$_SESSION['id'].' &pic='.$row['image'].'&name='.$row['username'].'"); As you can see, I eliminated all white space between the variables and concatenations, thinking that that was the problem but I keep getting the error message. I'm at a loss about what to do next. Any help? Code: [Select] <form action='test.php' method='post'> <input id="Username" type="hidden" name="date2" /> <input type="submit" name="action" value="Submit"></form> Hi I want to pass a Username javascript variable to test.php as hidden, anyone can help? When code this Code: [Select] <input id="Username" type="input" name="date2" />Data can pass to test.php When code this Code: [Select] <input id="Username" type="hidden" name="date2" />Data fail to pass over I work with a large codebase and I have this situation come up fairly often:
the legacy class has large objects such as:
$design->motor->dimensions->a; $design->motor->dimensions->bd; $design->specifications->weight; $design->data->height; //etcWhen I create a new class, that class sometimes operates on the specific data, so say:
class MyClass
{
public function compute($weight, $height, $a)
{
//stuff
}
}
//and I call this for example as such:
(new MyClass())->compute($design->specifications->weight, $design->data->height, $design->motor->dimensions->a);
CONS: Potential issue: if design specs change and I need to change things parameters in "compute" function, I need to "re-key" the variables I pass to the function, and adjust things accordinly in MyClass as wel.
PROS: only the exact data is being passed, and this data can come from anywhere it is viable, so in effect the function is fairly well separated, I think.
Alternative option for me is to pass the entire design object, i.e
class MyClass
{
public function compute(&$design) //can also be done via DI through a setter or constructor.
{
print $design->specifications->weight;
print ($design->data->height + $design->motor->dimensions->a);
//stuff
}
}
(new MyClass())->compute($design);
PROS: In this case when things change internally in which variables are needed and how things are computed, I only need to change the code in compute function of the class itself.
CONS: MyClass now needs to be aware of how $design object is constructed.
When it comes to this parameter passing, and Dependency Injection like this in general, does Computer Science advocate a preference on this issue? Do I pass the entire object, or do I pass only the bits and pieces I need?
This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=357747.0 I'm trying to get a simple table to display and am not sure how to make it happen. Table will have just 2 columns. A TIME and an EVENT. What I want to have happen is for the first row to show the TIME and next to that, the EVENT. If a TIME has more than one event going I want the next row to show an empty first cell and then the second event below the first. If I set up the loop the only way I know how (so far) it would also output the TIME value again and again as many times as there were events for that same time. For example what I don't want is: 9:15 Sunday School 9:15 Nursery Available What I do want is: 9:15 Sunday School Nursery Available Thanks. |
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