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PHP - Show Next Result In Dropdown Box
Code: [Select]
for ($i = 1; $i<$rows+1; $i++) { $Choicequery ="SELECT PersonA, PersonB FROM modules WHERE GroupID = '$UpdateNumber'"; $Choiceresult = mysql_query($Choicequery); $ChoiceRows = mysql_fetch_array($Choiceresult); $PersonQuery = "SELECT FirstName, LastName FROM Persons p, modules m, users e, group t WHERE m.modID = $ChoiceRows[0] AND e.UserID = m.PersonA AND p.PersonID = e.PersonID"; $PersonResult = mysql_query($PersonQuery); $PersonRows = mysql_fetch_array($PersonResult); $Person2Query = "SELECT FirstName, LastName FROM Persons p, modules m, users e, group t WHERE m.modID = $ChoiceRows[0] AND e.UserID = m.PersonB AND p.PersonID = e.PersonID"; $Person2Result = mysql_query($Person2Query); $Person2Rows = mysql_fetch_array($Person2Result); echo "<Option value = \"$i\">$PersonRows[0] $PersonRows[1] and $Person2Rows[0] $Person2Rows[1] </Option>"; } How do I get it to show the next result when $i increases? All the options are the first people A and B $i number of times. Not sure how to use a loop here to go though the results. Whats the best way? ie $PersonRows[0] $PersonRows[1] are the same for every option Similar Tutorialsfriend the code display all the managers name
<?phpand the variable below displays the result $Manager= $row['Manager'] ; but how do i do it on the above dropdown list the it shows which result is in the $Manager variable? hi i am using yahoo api search i put a paragraph in a text area explode with ".Dot " and than serah each sentance one by one in yahoo api. Problem is i want when its get all sentancce in one site its give me result one time but my code give result as foreach loop end if it explode 5 time it give me same result 5 time but i want only one time some one help me $queryz=$_REQUEST['query']; $queryz1=explode('.',$queryz); foreach ($queryz1 as $k=>$v){ $q = build_query($v); //exit(); performTask($q); } // To cache, we save the result xml to a filename that is a // hash of the query string. Note the use of tempnam() and // rename() to make sure the file is created atomically. function performTask($q=""){ $cache_file = '/tmp/yws_'.md5('http://search.yahooapis.com/WebSearchService/V1/webSearch'.$q); if(file_exists($cache_file) && filemtime($cache_file) > (time()-7200)) { $raw = file_get_contents($cache_file); } else { $raw = file_get_contents('http://search.yahooapis.com/WebSearchService/V1/webSearch'.$q); $tmpf = tempnam('/tmp','YWS'); file_put_contents($tmpf, $raw); @rename($tmpf, $cache_file); } $xml = simplexml_load_string($raw); // Load up the root element attributes foreach($xml->attributes() as $name=>$attr) $res[$name]=$attr; $first = $res['firstResultPosition']; $last = $first + $res['totalResultsReturned']-1; echo "<p>Matched ${res[totalResultsAvailable]}, showing $first to $last</p>\n"; if(!empty($res['ResultSetMapUrl'])) { echo "<p>Result Set Map: <a href=\"${res[ResultSetMapUrl]}\">${res[ResultSetMapUrl]}</a></p>\n"; } $stored=""; for($i=0; $i<$res['totalResultsReturned']; $i++) { foreach($xml->Result[$i] as $key=>$value) { if(stristr($key,'ClickUrl')){ if(strpos($stored,$value)){ continue; } } if(stristr($key,'Title')) echo "<a href=\"$value\">$value</a> <br /> \n"; if(stristr($key,'ClickUrl')){echo "Url: <a href=\"$value\">$value</a> <br /> \n"; $stored.=$value;} if(stristr($key,'Summary')) echo "$value <br /> \n"; if(stristr($key,'ModificationDate')) echo "Update: $value From Yahoo <br /> \n"; } echo "<hr />\n"; } next_prev($res, $first, $last); } done(); ?> I have found postings close, but not close enough to find my error. I am looking up data from a MySql table and putting it in a dropdown box on a form. I can select the item, but apparently not really. I am not able to echo it, or post it to a record. I'm sure I am missing something simple, but... Code attached if anyone can show me the errors of my ways. Thank you. This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=331067.0 <SCRIPT LANGUAGE="javascript"> Hello to all. I'm new here and i am very glad to be a part of this community. I am new in PHP/mysql but i try to learn as much as i can in php & mysql. And here is the problem: Into a php or html page i want to display 2 dropdown list to act as a filter for displaying a table. I managed to display a table based on option select from first dropdown but i don'y know how to make or activate the second dropdown list to act as a filter, and when i press "result" to display on the same page the results. Thanks a lot. I´ve reached to
<?php require_once('Connections/conexxion.php'); ?>
<?php
mysql_select_db($database_conexxion, $conexxion);
$query_consulta = "SELECT venta,compra,taller,regula_mas,regula_menos,movimiento.id_item,sum(compra+regula_mas-venta-taller-regula_menos) as stock, cilindro, esfera FROM movimiento join item on item.id_item=movimiento.id_item join rx on rx.id_rx=item.id_rx join cilindro on cilindro.id_cil=rx.id_cil join esfera on esfera.id_esf=rx.id_esf GROUP BY movimiento.id_item ORDER BY esfera desc, cilindro desc";
$consulta = mysql_query($query_consulta, $conexxion) or die(mysql_error());
$row_consulta = mysql_fetch_assoc($consulta);
$totalRows_consulta = mysql_num_rows($consulta);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>test</title>
</head>
<body>
<?php
echo "<table align=center>";
$columnes = 10; # Número de columnas (variable)
if (($rows=mysql_num_rows($consulta))==0) {
echo "<tr><td colspan=$columnes>No hay resultados en la BD.</td></tr> ";
} else {
echo "<tr><td colspan=$columnes>$rows Resultados </td></tr>";
}
for ($i=1; $row = mysql_fetch_row ($consulta); $i++) {
$resto = ($i % $columnes); # Número de celda del <tr> en que nos encontramos
if ($resto == 1) {echo "<tr>";} # Si es la primera celda, abrimos <tr>
echo "<td>$row[1]</td>";
if ($resto == 0) {echo "</tr>";} # Si es la última celda, cerramos </tr>
}
if ($resto <> 0) { # Si el resultado no es múltiple de $columnes acabamos de rellenar los huecos
$ajust = $columnes - $resto; # Número de huecos necesarios
for ($j = 0; $j < $ajust; $j++) {echo "<td> </td>";}
echo "</tr>"; # Cerramos la última línea </tr>
}
mysql_close($connexion);
echo "</table>";
?>
</body>
</html>
<?php
mysql_free_result($consulta);
?>
it "works", but results doesn´t start at number 1 but number 2
anyways, The intent of this table is to show the stock of a product, a lens, that has a range of Rx, we use to see this range this way, and show the stock this way would be very productive, but I can´t figure out how to achive it, any sugestion??
Edited by gralfitox, 16 December 2014 - 06:45 AM. hi, I would like to show a list of pubs in a town that the user has selected from the drop down list http://www.mypubspace.com/dashtest/order.html it is all there working but in a different way If you type Brighton into the Town search, it shows a list of pubs in that town, GREAT! If you click the 'show towns list' link, a drop down appears, (this is where my problem is) When you click the town, I would like to get the list of pubs in that town basically get rid of the form where you type in the box and click the button here is my code HTML and Javascript Code: [Select] <html> <body> <script language="javascript" type="text/javascript"> <!-- //Browser Support Code function ajaxFunction(){ var townRequest; // The variable that makes Ajax possible! try{ // Opera 8.0+, Firefox, Safari townRequest = new XMLHttpRequest(); } catch (e){ // Internet Explorer Browsers try{ townRequest = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try{ townRequest = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e){ // Something went wrong alert("Your browser broke!"); return false; } } } // Create a function that will receive data sent from the server townRequest.onreadystatechange = function(){ if(townRequest.readyState == 4){ var ajaxDisplay = document.getElementById('ajaxDiv'); ajaxDisplay.innerHTML = townRequest.responseText; } } var name = document.getElementById('name').value; var county = document.getElementById('county').value; var town = document.getElementById('town').value; var queryString = "?name=" + name + "&county=" + county + "&town=" + town; townRequest.open("GET", "http://www.mypubspace.com/dashtest/pubs.php" + queryString, true); townRequest.send(null); } function townlistFunction(){ var ajaxRequest; // The variable that makes Ajax possible! try{ // Opera 8.0+, Firefox, Safari ajaxRequest = new XMLHttpRequest(); } catch (e){ // Internet Explorer Browsers try{ ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try{ ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e){ // Something went wrong alert("Your browser broke!"); return false; } } } // Create a function that will receive data sent from the server ajaxRequest.onreadystatechange = function(){ if(ajaxRequest.readyState == 4){ var ajaxDisplay = document.getElementById('ajaxTownlist'); ajaxDisplay.innerHTML = ajaxRequest.responseText; } } ajaxRequest.open("GET", "http://www.mypubspace.com/dashtest/town-select.php", true); ajaxRequest.send(null); } function countylistFunction(){ var ajaxRequest; // The variable that makes Ajax possible! try{ // Opera 8.0+, Firefox, Safari ajaxRequest = new XMLHttpRequest(); } catch (e){ // Internet Explorer Browsers try{ ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try{ ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e){ // Something went wrong alert("Your browser broke!"); return false; } } } // Create a function that will receive data sent from the server ajaxRequest.onreadystatechange = function(){ if(ajaxRequest.readyState == 4){ var ajaxDisplay = document.getElementById('ajaxCountylist'); ajaxDisplay.innerHTML = ajaxRequest.responseText; } } ajaxRequest.open("GET", "http://www.mypubspace.com/dashtest/county-select.php", true); ajaxRequest.send(null); } function MM_jumpMenu(targ,selObj,restore){ //v3.0 eval(targ+".location='"+selObj.options[selObj.selectedIndex].value+"'"); if (restore) selObj.selectedIndex=0; } //--> </script> <a href="#" onClick="townlistFunction();">show towns list</a> <a href="#" onClick="countylistFunction();">show counties list</a> <div id="ajaxTownlist"></div> <div id="ajaxCountylist"></div> <form name='myForm'> Pub Name: <input type='text' id='name' /> <br /> County: <input type='text' id='county' /> <br /> Town: <input type='text' id='town' /> <input type='button' onclick='ajaxFunction()' value='Query MySQL' /> </form> <div id='ajaxDiv'></div> </body> </html> here is my pubs.php code Code: [Select] <?php $dbhost = "xxx"; $dbuser = "xxx"; $dbpass = "xxx"; $dbname = "xxx"; //Connect to MySQL Server mysql_connect($dbhost, $dbuser, $dbpass); //Select Database mysql_select_db($dbname) or die(mysql_error()); // Retrieve data from Query String $name = $_GET['rsPubName']; $sex = $_GET['rsTown']; $wpm = $_GET['rsCounty']; // Escape User Input to help prevent SQL Injection $name = mysql_real_escape_string($name); $town = mysql_real_escape_string($town); $county = mysql_real_escape_string($county); //build query $query = "SELECT * FROM pubs WHERE rsTown = '$town'"; $qry_result = mysql_query($query) or die(mysql_error()); //Build Result String $display_string = "<table>"; $display_string .= "<tr>"; $display_string .= "<th>Region</th>"; $display_string .= "<th>Pub Name</th>"; $display_string .= "<th>Town</th>"; $display_string .= "<th>County</th>"; $display_string .= "</tr>"; // Insert a new row in the table for each person returned while($row = mysql_fetch_array($qry_result)){ $display_string .= "<tr>"; $display_string .= "<td>$row[Region]</td>"; $display_string .= "<td>$row[rsPubName]</td>"; $display_string .= "<td>$row[rsTown]</td>"; $display_string .= "<td>$row[rsCounty]</td>"; $display_string .= "</tr>"; } $display_string .= "</table>"; echo $display_string; ?> here is my town_select.php code Code: [Select] <?php $dbhost = "xxx"; $dbuser = "xxx"; $dbpass = "xxx"; $dbname = "xxx"; //Connect to MySQL Server mysql_connect($dbhost, $dbuser, $dbpass); //Select Database mysql_select_db($dbname) or die(mysql_error()); // Retrieve data from Query String $town = $_GET['rsTown']; // Escape User Input to help prevent SQL Injection $town = mysql_real_escape_string($town); //build query $query = "SELECT DISTINCT rsTown, COUNT(PUBID) As PubCount FROM pubs GROUP BY rsTown ORDER BY rsTown ASC"; $qry_result = mysql_query($query) or die(mysql_error()); // Insert a new row in the table for each person returned $display_string .= "<form name=\"form3\" method=\"post\" action=\"\">"; $display_string .= "<select name=\"menu2\" onChange=\"MM_jumpMenu('parent',this,0)\" class=\"textbox\">"; $display_string .= "<option value=\"\">Search by Town...</option>"; while($row = mysql_fetch_array($qry_result)){ $display_string .= '<option value="rsTown='.$row['rsTown'].'" onclick=\"ajaxFunction()\" id=\"town\">'.$row['rsTown'].' ('.$row['PubCount'].')</option>'; } $display_string .= "</select>"; $display_string .= "</form>"; echo $display_string; ?> I am really lost here with this date issue of mine. The below code is the last part of a query: Code: [Select] $defendercheck_3 = $row_checkifattacked3['atdate']; $defendercheck1_3 = strtotime("$defendercheck_3"); $defendercheck2_3 = date("D", $defendercheck1_3); The query does not return any results as expected, but when echoing the various steps I get following: echo "$defendercheck3"; = nothing (as expected) echo "$defendercheck1_3"; = nothing (as expected) echo "$defendercheck2_3"; = result! (NOT expected) why does it return anything on "date("D", $defendercheck1_3)" when "$defendercheck1_3" is blank? I have a form with dropdown list that is populated with values from Sql Server table. Now i would like to use this selected item in SQL query. The results of this query should be shown in label or text field. So when a user selects item from dropdown menu, results from SQL query are shown at the same time. I have two dropdown list at the moment in my form. First one gets all values from a column in table in SQL Server. And the second one should get a value from the same table based on a selection in first dropdown list.
When i load ajax.php i get 2 error mesages: This is my code so far. I have tried to do it with this Ajax script. But i can only get first dropdown to work. The second dropdown(sub_machinery) does not show values, when first dropdown item is selected. The second dropdown should show values from databse table with this query( *$machineryID* is first dropdown selected item): SELECT MachineID FROM T013 WHERE Machinery=".$machineryID. Index.php
<!doctype html>
<?PHP
$server = "server";
$options = array( "UID" => "user", "PWD" => "pass", "Database" =>
"database");
$conn2 = sqlsrv_connect($server, $options);
if ($conn2 === false) die("<pre>".print_r(sqlsrv_errors(), true));
echo " ";
?>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>
<body>
<section id="formaT2" class="formaT2 formContent">
<div class="row">
<div class="col-md-2 col-3 row-color remove-mob"></div>
<div class="col-md-5 col-9 bg-img" style="padding-left: 0;
padding-right: 0;">
<h1>Form</h1>
<div class="rest-text">
<div class="contactFrm">
<p class="statusMsg <?php echo
!empty($msgClass)?$msgClass:''; ?>"><?php echo $statusMsg; ?></p>
<form action="connection.php" method="post">
<div>machinery</div>
<select id="machinery">
<option value="0">--Please Select Machinery--</option>
<?php
// Fetch Department
$sql = "SELECT Machinery FROM T013";
$machanery_data = sqlsrv_query($conn2,$sql);
while($row = sqlsrv_fetch_array($machanery_data) ){
$id = $row['Id'];
$machinery = $row['Machinery'];
// Option
echo "<option value='".$id."' >".$machinery."</option>";
}
?>
</select>
<div class="clear"></div>
<div>Sub Machinery</div>
<select id="sub_machinery">
<option value="0">- Select -</option>
</select>
<input type="submit" name="submit"
id="submit" class="strelka-send" value="Insert">
<div class="clear"> </div>
</form>
</div>
</div>
</div>
</div>
</section>
</script>
<script type="text/javascript">
$(document).ready(function(){
$("#machinery").change(function(){
var machinery_id = $(this).val();
$.ajax({
url:'ajaxfile.php',
type: 'post',
data: {machinery:machinery_id},
dataType: 'json',
success:function(response){
var len = response.length;
$("#sub_machinery").empty();
for( var i = 0; i<len; i++){
var machinery_id = response[i]['machinery_id'];
var machinery = response[i]['machinery'];
$("#sub_machinery").append("<option
value='"+machinery_id+"'>"+machinery+"</option>");
}
}
});
});
});
</script>
</body>
</html>
Ajaxfile.php
<?php
$server = "server";
$options = array( "UID" => "user", "PWD" => "pass",
"Database" => "database");
$conn2 = sqlsrv_connect($server, $options);
if ($conn2 === false) die("<pre>".print_r(sqlsrv_errors(), true));
echo " ";
$machineryID = $_POST['machinery']; // department id
$sql = "SELECT MachineID FROM T013 WHERE Machinery=".$machineryID;
$result = sqlsrv_query($conn2,$sql);
$machinery_arr = array();
while( $row = sqlsrv_fetch_array($result) ){
$machinery_id = $row['ID'];
$machinery = $row['MachineID'];
$machinery_arr[] = array("ID" => $machinery_id, "MachineID" =>
$machinery);
}
// encoding array to json format
echo json_encode($machinery_arr);
?>
Edited May 6, 2019 by davidd
Hi freaks, I'm new to php first of all. I'm dynamically binding a dropdownlist with mysql database . After the user selects an item from it , I want to match that item with another table so as to populate another database. The code I'm using to populate dropdown: Code: [Select] <?php $con = mysql_connect("localhost","root",""); if(!$con) { die ('Can not connect to : '.mysql_error()); } mysql_select_db("ims",$con); $result=mysql_query("select cat_id,cat_name from category"); echo "<select name=cat>"; while($nt=mysql_fetch_array($result)) { echo "<option value=$nt[cat_id]> $nt[cat_name] </option>"; } echo "</select>"; mysql_close($con); ?> Now after the user selects any one of the item , I want to bind another dropdown on the same page using such query like $result=mysql_query("select subcategory.sc_id,subactegory.sc_name from subcategory,category where subcategory.sc_id=$nt[cat_id]"); Please anyone tell me the logic and code to do it. Also tell me do I need an intermediate page to post the 1st dropdown value and then continue with 2nd dropdown. I couldn't figure out the concept anyhow. Help on this will be highly appreiable . (Tell me if I'm not clear with my question) I want to show a cookie of a referral's username on a sign up page. The link is like this, www.mysite.com/signup?ref=johnsmith. The cookie doesn't show if I go to that url page. But it does show up once I reload the page. So I'm wondering if it's possible to show the cookie the first time around, instead of reloading the page? Here is my code.
// This is in the header
$url_ref_name = (!empty($_GET['ref']) ? $_GET['ref'] : null);
if(!empty($url_ref_name)) {
$number_of_days = 365;
$date_of_expiry = time() + 60 * 60 * 24 * $number_of_days;
setcookie( "ref", $url_ref_name, $date_of_expiry,"/");
} else if(empty($url_ref_name)) {
if(isset($_COOKIE['ref'])) {
$user_cookie = $_COOKIE['ref'];
}
} else {}
// This is for the sign up form
if(isset($_COOKIE['ref'])) {
$user_cookie = $_COOKIE['ref'];
?>
<fieldset>
<label>Referred By</label>
<div id="ref-one"><span><?php if(!empty($user_cookie)){echo $user_cookie;} ?></span></div>
<input type="hidden" name="ref" value="<?php if(!empty($user_cookie)){echo $user_cookie;} ?>" maxlength="20" placeholder="Referrer's username" readonly onfocus="this.removeAttribute('readonly');" />
</fieldset>
<?php
}
I am displaying rows from a database onto a page using: while($row=mysql_fetch_array($query)){ echo $row['name']; } I need to figure out how to limit the rows shown to the page to 100. And if there are 100 rows on the page, a link will be displayed at the bottom, that says "Next 100". Then this will display the next 100 rows. Can you give an example how to do this please? Thanks Hi, I would like to do the following but not sure how. If the you/user is on index.php of http://www.domain.com/ show one page If not show another How would I do this? Thanks Hi , I know my code sucks but i'm learning fast!! I'm trying to show a form if the qty value in a database == 10 or a different form if the value ==20. I tried but failed. Any help really appreciated. Code: [Select] <?php require_once('Connections/book.php'); ?> <?php $colname_cardpayment = "-1"; if (isset($_GET['orderid'])) { $colname_cardpayment = (get_magic_quotes_gpc()) ? $_GET['orderid'] : addslashes($_GET['orderid']); } mysql_select_db($database_book, $book); $query_cardpayment = sprintf("SELECT * FROM cards WHERE orderid = '%s' ORDER BY qty ASC", $colname_cardpayment); $cardpayment = mysql_query($query_cardpayment, $book) or die(mysql_error()); $row_cardpayment = mysql_fetch_assoc($cardpayment); $totalRows_cardpayment = mysql_num_rows($cardpayment); // Database connect $con = mysql_connect("mysql1.myhost.ie","admin_book","root123"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("book_test", $con); //Parse Values from Coupon.php Form $orderid = mysql_real_escape_string(trim($_POST['orderid'])); $name = mysql_real_escape_string(trim($_POST['name'])); $surname = mysql_real_escape_string(trim($_POST['surname'])); $add1 = mysql_real_escape_string(trim($_POST['add1'])); $add2 = mysql_real_escape_string(trim($_POST['add2'])); $town = mysql_real_escape_string(trim($_POST['town'])); $county = mysql_real_escape_string(trim($_POST['county'])); $postcode = mysql_real_escape_string(trim($_POST['postcode'])); $phone = mysql_real_escape_string(trim($_POST['phone'])); $email = mysql_real_escape_string(trim($_POST['email'])); $letterstyle = mysql_real_escape_string(trim($_POST['letterstyle'])); $sql="INSERT INTO custdetails (orderid, name, surname, add1, add2, town, county, postcode, phone, email, letterstyle) VALUES ('$orderid','$name','$surname','$add1','$add2','$town','$county','$postcode','phone','$email','$letterstyle')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Digital Scribe Books</title> <link href="style.css" rel="stylesheet" type="text/css" /> <script type="text/javascript"> function MM_preloadImages() { //v3.0 var d=document; if(d.images){ if(!d.MM_p) d.MM_p=new Array(); var i,j=d.MM_p.length,a=MM_preloadImages.arguments; for(i=0; i<a.length; i++) if (a[i].indexOf("#")!=0){ d.MM_p[j]=new Image; d.MM_p[j++].src=a[i];}} } function MM_swapImgRestore() { //v3.0 var i,x,a=document.MM_sr; for(i=0;a&&i<a.length&&(x=a[i])&&x.oSrc;i++) x.src=x.oSrc; } function MM_findObj(n, d) { //v4.01 var p,i,x; if(!d) d=document; if((p=n.indexOf("?"))>0&&parent.frames.length) { d=parent.frames[n.substring(p+1)].document; n=n.substring(0,p);} if(!(x=d[n])&&d.all) x=d.all[n]; for (i=0;!x&&i<d.forms.length;i++) x=d.forms[i][n]; for(i=0;!x&&d.layers&&i<d.layers.length;i++) x=MM_findObj(n,d.layers[i].document); if(!x && d.getElementById) x=d.getElementById(n); return x; } function MM_swapImage() { //v3.0 var i,j=0,x,a=MM_swapImage.arguments; document.MM_sr=new Array; for(i=0;i<(a.length-2);i+=3) if ((x=MM_findObj(a[i]))!=null){document.MM_sr[j++]=x; if(!x.oSrc) x.oSrc=x.src; x.src=a[i+2];} } </script> </head> <body onload="MM_preloadImages('images/buttons/home_over.png','images/buttons/books_over.png','images/buttons/cards_over.png','images/buttons/letters_over.png')"> <div id="snow"> <div id="wrapper"> <div id="header"> <div id="logo"><img src="images/digital_scripe.png" width="218" height="91" /></div> <div id="menu"><a href="index.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Home','','images/buttons/home_over.png',1)"><img src="images/buttons/home_act.png" name="Home" width="131" height="132" border="0" id="Home" /></a><a href="books.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Books','','images/buttons/books_over.png',1)"><img src="images/buttons/books_act.png" name="Books" width="131" height="132" border="0" id="Books" /></a><a href="cards.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Cards','','images/buttons/cards_over.png',1)"><img src="images/buttons/cards_act.png" name="Cards" width="131" height="132" border="0" id="Cards" /></a><a href="letters.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Letters','','images/buttons/letters_over.png',1)"><img src="images/buttons/letters_act.png" name="Letters" width="131" height="132" border="0" id="Letters" /></a></div> </div> <div id="content"> <?php echo 'Order ID is : '. $orderid . '.<br />'; if ($row2['qty'] == 10) echo "<div> <form action="https://www.paypal.com/cgi-bin/webscr" method="post"> <input type="hidden" name="cmd" value="_xclick"> <input type="hidden" name="business" value="accounts@agraphics.ie"> <input type="hidden" name="lc" value="IE"> <input type="hidden" name="item_name" value="10 Christmas Cards"> <input type="hidden" name="item_number" value="<? echo $orderid; ?>"> <input type="hidden" name="amount" value="12.99"> <input type="hidden" name="currency_code" value="EUR"> <input type="hidden" name="button_subtype" value="services"> <input type="hidden" name="shipping" value="2.99"> <input type="hidden" name="return" value="http://www.digitalscribe/thanks.php"> <input type="hidden" name="bn" value="PP-BuyNowBF:btn_buynowCC_LG.gif:NonHosted"> <input type="image" src="https://www.paypalobjects.com/en_US/i/btn/btn_buynowCC_LG.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!"> <img alt="" border="0" src="https://www.paypalobjects.com/en_US/i/scr/pixel.gif" width="1" height="1"> </form> </div>"; if ($row2['qty'] == 20) echo "<div> <form action="https://www.paypal.com/cgi-bin/webscr" method="post"> <input type="hidden" name="cmd" value="_xclick"> <input type="hidden" name="business" value="accounts@agraphics.ie"> <input type="hidden" name="lc" value="IE"> <input type="hidden" name="item_name" value="20 Christmas Cards"> <input type="hidden" name="item_number" value="<? echo $orderid; ?>"> <input type="hidden" name="amount" value="21.99"> <input type="hidden" name="currency_code" value="EUR"> <input type="hidden" name="button_subtype" value="services"> <input type="hidden" name="shipping" value="2.99"> <input type="hidden" name="return" value="http://www.digitalscribe/thanks.php"> <input type="hidden" name="bn" value="PP-BuyNowBF:btn_buynowCC_LG.gif:NonHosted"> <input type="image" src="https://www.paypalobjects.com/en_US/i/btn/btn_buynowCC_LG.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!"> <img alt="" border="0" src="https://www.paypalobjects.com/en_US/i/scr/pixel.gif" width="1" height="1"> </form> </div>"; ?> </div> <div id="footer" class="clear"><div id="sign"><div id="sign_text">Personalised<br /> Books</div> </div></div> </div></div> </body> </html> <?php mysql_free_result($cardpayment); ?> I am not a developer but I can modify code to work for me. The following code works on my test machine (Windows 10, IIS, PHP 7.4) but doesn't work on my website (cPanel, Some version of Linux, PHP 7.4). The two dropdowns are for State and City. You are supposed to be able to select the state and then select a city from that state then bring up a report for craft breweries in the city. When selecting State from the first dropdown, the page refreshes, the URL is correct with the reports.php?cat=<STATE> so $cat is being set, but the first dropdown no longer has the state selected and the second dropdown is populated with All cities and not just one ones from the selected state. Any ides why this is working fine on one machine and not the other? Selected code from reports.php
<?php
?>
/////// for second drop down list we will check if State is selected else we will display all the cities/////
echo "<form method=post action='brewerylistbycity.php'>";
}
////////// Starting of second drop downlist /////////
//// End Form /////
Ok i call a function like so ... <?php PunchTime($monday,"in","1",$etime_who); ?> Below is the function, if you look closely i echo the query after it's been ran, and that query works 100% since i copied & pasted the query into the database and it returns a result that's needed. But for some bloody reason it doesn't work via code. function PunchTime($pdate,$type,$num,$ewho) { if($type == "in") { if($num == "1") { $etime_col = "PUNCH_IN"; } elseif($num == "2") { $etime_col = "PUNCH_IN2"; } } elseif($type == "out") { if($num == "1") { $etime_col = "PUNCH_OUT"; } elseif($num == "2") { $etime_col = "PUNCH_OUT2"; } } include_once('oracleCON.php'); $etime_qry = "SELECT $etime_col FROM tablename WHERE who= '$ewho' AND punch_date = '$pdate'"; echo $etime_qry; $etime_go = oci_parse($conn, $etime_qry); oci_execute($etime_go); $etime_res = oci_fetch_assoc($etime_go); $time = $etime_res[$etime_col]; if($time == "") $time = "--"; echo $time; } All i get are "--" even though some should return a time stamp. Basically I want this to do do is: if (there is no result found in the query){ echo "nothing for this brand"; }else{ echo this link; } this is my code...im just confused on what i want the if statement to to ask for. any help would be greatly appreciated Code: [Select] <?php $mypro = mysql_query("SELECT * FROM Sheet1 WHERE pro_catagory LIKE '%People%' ORDER BY pro_id DESC"); while($row=mysql_fetch_array($mypro)) { if(Not sure what to put here){ echo "There are no listings for the brand right now"; }else{ print "- <a href='proList.php?proNumber=".$row['pro_id']."'>".$row['pro_name']."</a><br />"; } } ?> at the moment i have my page: addevent.php i have written: Code: [Select] $q = "SELECT username " ."FROM ".TBL_USERS." ORDER BY ASC"; $result = $database->query($q); on the database.php page here is what query looks like: Quote /** * query - Performs the given query on the database and * returns the result, which may be false, true or a * resource identifier. */ function query($query){ return mysql_query($query, $this->connection); } then i want to display $result in a drop down menu so i wrote back on addevent.php: Code: [Select] <select name="Select1"> <option value="<? echo("$result"); ?>"><? echo("$result"); ?></option> </select> |
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