PHP - Writing Javascript In Php
I don't think the start of my code is right?!
Code: [Select] echo '<button onclick=\"gohere(viewpub.php?PubID='.$row['PubID'].')" id="button" type="button" class="ui-button ui-widget ui-state-default ui-corner-all ui-button-text-only" role="button" aria-disabled="false"><span class="ui-button-text">View Pub</span></button>'; Please help?! Similar TutorialsI need help! I cant get this to write the correct way! What i need is based on the value of what is posted to the script it has to write it in the config file and also make a folder! Please help Code: [Select] <?php $start = '$uploadpath=\''; $structure = '../banner/images/'.$_POST['FOLDER'].'\';\n'; $myFile = "PHP/confup.php"; $fh = fopen($myFile, 'w') or die("can't open file"); $stringData = "<?\n"; fwrite($fh, $stringData); $stringData = "$start $structure"; fwrite($fh, $stringData); $stringData = "?>\n"; fwrite($fh, $stringData); fclose($fh); // Desired folder structure // To create the nested structure, the $recursive parameter // to mkdir() must be specified. if (!mkdir($structure, 0777, true)) { die('Failed to create folders...'); } // ... ?> I am using a script I adapted from a tutorial to print the contents of a text box to a txt file. Basically, it's a really simple way of seeing who has logged in. I only have a handful of users. The problem is, although the text file is being created in the proper folder, it isn't being written to and just remains blank. <div align="center"> <table width="300" border="2" bordercolor="#FFFFFF" style="-moz-border-radius: 18px; -webkit-border-radius: 18px;" height="120" cellpadding="0" cellspacing="0"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" background="images/loginbg.jpg" style="-moz-border-radius: 15px; -webkit-border-radius: 15px;"> <tr align="center"> <td colspan="3"><font color="#FFFFFF"><strong>Family Login </strong></font></td> </tr> <tr> <td width="78"><font color="#000000">Username</font></td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"> <?php $myusername = $_POST['myusername']; $data = "$myusername\n"; //open the file and choose the mode $fh = fopen("logs/login.txt", "a"); fwrite($fh, $data); fclose($fh); ?></td> </tr> <tr> <td><font color="#000000">Password</font></td> <td>:</td> <td><input name="mypassword" type="password" id="mypassword"></td> </tr> <tr> <td> </td> <td> </td> <td><input type="submit" name="Submit" value="Login"> </td> </tr> </table> </td> </form> </tr> </table> </div> I'm not sure what's going wrong but I'm guessing it's the placing of the php, or at least some of it. I'd quite like to add the time they logged in as well. Any idea's anyone? Hi everyone. Still new to PHP and to Object-Oriented Programming. My goal for today is to write a few dummy Classes in PHP that do enough so that I can see something on my webpage. I am wondering if there is someone here who would be willing to help in either the forums or one-on-one. It may sound like a silly request, but this is all new to me as a Procedural Programmer who has actively programmed in about 10 years!! Thanks, TomTees Greetings,
I am new to these forums, I am working on this assignment, and these are the current issues I am running into.
Notice: Undefined variable: year in G:\EasyPHP-5.3.2i\www\PHP_Projects\ChineseZodiacs\zodiac_year_switch.php on line 77
ie. $year = validateInput($year,"Birth Year");
Notice: Undefined variable: year_count in G:\EasyPHP-5.3.2i\www\PHP_Projects\ChineseZodiacs\zodiac_year_switch.php on line 138
ie. echo "<p>You are person " . $year_count . "to enter " . $year . "</p>\n";
Honestly, I believe they are linked, because what should be happening, as the user enters the year, and hits submit, it should create a file called counts/$year.txt - $year should equal the entered data in the textbox, any help would be appreciated.
Thank you for your help.
<!DOCTYPE html> <head> <title>Write to and From a File</title> <meta http-equiv="content-type" content="text/html; charset=iso-8859-1" /> <?php $dir = "counts"; if ( !file_exists($dir)) { mkdir ($dir, 0777); } function validateInput($year, $fieldname) { global $errorCount; if (empty($year)) { echo "\"$fieldname\" is a required field.<br />\n"; ++$errorCount; $retval = ""; } else { // if the field on the form has been filled in if(is_numeric($year)) { if($year >=1900 && $year <=2014) { $retval = $year; } else { ++$errorCount; echo "<p>You must enter a year between 1900 and 2014.</p>\n"; } } else { ++$errorCount; echo "<p>The year must be a number.</p>\n"; } } //ends the else for empty return($retval); } //ends the function function displayForm() { ?> <form action = "<?php echo $_SERVER['SCRIPT_NAME']; ?>" method = "post"> <p>Year of Birth: <input type="text" name="year" /></p> <p><input type="reset" value="Clear Form" /> <input type="submit" name="submit" value="Show Me My Sign" /></p> </form> <?php } function StatisticsForYear($year) { global $year_count; $counter_file = "counts/$year.txt"; if (file_exists($counter_file)) { $year_count = file_get_contents($counter_file); file_put_contents($counter_file, ++$year_count); } else { $year_count = 1; file_put_contents($counter_file, $year_count); } return ($year_count); }?> </head> <body> <?php $showForm = true; $errorCount = 0; //$year=$_POST['year']; $zodiac=""; $start_year =1900; if (isset($_POST['submit'])) $year = $_POST['year']; $year = validateInput($year,"Birth Year"); if ($errorCount==0) $showForm = false; else $showForm = true; if ($showForm == true) { //call the displayForm() function displayForm(); } else { //begins the else statement //determine the zodiac $zodiacArray = array("rat", "ox", "tiger", "rabbit", "dragon", "snake", "horse", "goat", "monkey", "rooster", "dog", "pig"); switch (($_POST['year'] - $start_year) % 6) { case 0: $zodiac = $zodiacArray[0]; break; case 1: $zodiac = $zodiacArray[1]; break; case 2: $zodiac = $zodiacArray[2]; break; case 3: $zodiac = $zodiacArray[3]; break; case 4: $zodiac = $zodiacArray[4]; break; case 5: $zodiac = $zodiacArray[5]; break; case 6: $zodiac = $zodiacArray[6]; break; case 7: $zodiac = $zodiacArray[7]; break; case 8: $zodiac = $zodiacArray[8]; break; case 9: $zodiac = $zodiacArray[9]; break; case 10: $zodiac = $zodiacArray[10]; break; case 11: $zodiac = $zodiacArray[11]; break; default: echo "<p>The Zodiac for this year has not been determined.</p>\n"; break; } //ends the switch statement echo "<p>You were born under the sign of the " . $zodiac . ".</p>\n"; echo "<p>You are person " . $year_count . "to enter " . $year . "</p>\n"; } //ends the else statement ?> </body> </html> Edited by mstevens, 16 October 2014 - 06:36 PM. I have written some code to past information from one page to a diffrent page however all the variables are sent over but they are not writting to the database could anyone help me out please .... $ud_P_Id = $_POST['ud_P_Id']; $ud_LastName = $_POST['ud_LastName']; $ud_FirstName = $_POST['ud_FirstName']; $ud_GroupCode=$_POST['ud_GroupCode']; $ud_P_Unit1=$_POST['ud_P_Unit1']; $ud_P_Unit2=$_POST['ud_P_Unit2']; $ud_P_Unit3=$_POST['ud_P_Unit3']; $ud_P_Unit6=$_POST['ud_P_Unit6']; $ud_P_Unit14=$_POST['ud_P_Unit14']; $ud_P_Unit20=$_POST['ud_P_Unit20']; $ud_P_Unit27=$_POST['ud_P_Unit27']; $ud_P_Unit28=$_POST['ud_P_Unit28']; $ud_P_Unit42=$_POST['ud_P_Unit42']; $ud_P_Unit10=$_POST['ud_P_Unit10']; $ud_P_Unit11=$_POST['ud_P_Unit11']; $ud_P_Unit12=$_POST['ud_P_Unit12']; $ud_P_Unit13=$_POST['ud_P_Unit13']; $ud_P_Unit1454=$_POST['ud_P_Unit1454']; $ud_P_Unit15=$_POST['ud_P_Unit15']; $ud_P_Unit16=$_POST['ud_P_Unit16']; $ud_P_Unit17=$_POST['ud_P_Unit17']; $ud_P_Unit18=$_POST['ud_P_Unit18']; $con = mysql_connect('localhost', 'lccstude_progre', '********'); $db= "lccstude_pro"; if (! $con) die("Couldn't connect to MySQL"); mysql_select_db($db , $con) or die("Couldn't open $db: ".mysql_error()); mysql_query("UPDATE BTECL31113 SET FirstName='$ud_FirstName' , LastName='$ud_LastName' , GroupCode='$ud_GroupCode' , Unit1='$ud_P_Unit1' , Unit2='$ud_P_Unit2' , Unit3='$ud_P_Unit3' , Unit6='$ud_P_Unit6' , Unit14='$ud_P_Unit14' , Unit20='$ud_P_Unit20' , Unit27='$ud_P_Unit27' , Unit28='$ud_P_Unit28' , Unit42='$ud_P_Unit42' , Unit10='$ud_P_Unit10' , Unit11='$ud_P_Unit11' , Unit12='$ud_P_Unit12' , Unit13='$ud_P_Unit13' , Unit1454='$ud_P_Unit1454' , Unit15='$ud_P_Unit15' , Unit16= $ud_P_Unit16' , Unit17='$ud_P_Unit17' , Unit18='$ud_P_Unit18' WHERE P_Id='$ud_P_Id'"); echo "Record Updated"; mysql_close($con); Please any help would be great Hey Guys. I am trying to write to the file depending on which condition is met. The code works fine on my local machiene but not on my remote server. I have also tried to output any error messages to see if it would output anything, and I don't get anyting on my browser. Can anyone help me with this issue? Thanks <?php if($_SERVER['REQUEST_METHOD'] == "POST") { isset($_POST['interfax']) ? $option= "interfax" : $option= ""; isset($_POST['metrofax']) ? $option= "metrofax" : $option= ""; switch ($option) { case 'interfax': $file = "fax.php"; $fax_client = "interfax"; if(file_put_contents($file, "<?php ".'$fax_client = "' . $fax_client . '"'." ?>")) { echo "Successful"; } else { die("Can't write file"); } break; // By defualt all the orders go to metrofax so by selecting the variable it resets it self case 'metrofax': $file = "fax.php"; $fax_client = "metrofax"; file_put_contents($file, "<?php ".'$fax_client = "' . NULL . '"'." ?>"); break; } } ?> <form action="#" method="POST"> <input type="radio" name="interfax" value="interfax">Switch To Interfax<br> <input type="radio" name="metrofax" value="metrofax">Switch To Metrofax<br> <input type='submit' name="submit" > I am using a cache script, well it writes a array to a file like this: Code: [Select] fwrite($fh, '<?php'."\n\n".'define(\'PUN_LOTTERY_LOADED\', 1);'."\n\n".'$lottery = '.var_export($output2, true).';'."\n\n".'?>'); output2 is Code: [Select] $result2 = $db->query('MY QUERY '); $output2 = array(); while ($cur_donors = $db->fetch_assoc($result2)) $output2[] = $cur_donors; Now, I want to ditch the mysql and I want to use this script with 7 variables that I already have loaded, so I dont need to use the mysql, how do I add my 7 variables to my var_export function instead of using mysql to loop them? I'm trying to write to a file with the following code. $fh = fopen("../inc/config.php", "a") or die("\r\nCan't open file."); $write = "\$config['database_host'] = {$mysqlh}; \$config['database_user'] = {$mysqlu}; \$config['datbase_pass'] = {$mysqlp}; \$config['datbase_name'] = {$dbn}; \$config['table_prefix'] = {$tp};"; fwrite($fh, $write); fclose($fh); It is printing out "Can't open file", which I guess means it can't find the file or I've given the wrong path. The file that is executing this code is /install and the file I'm trying to write to is /inc/config.php. I thought .. put you up a directory so if I do .. I will be at the root and then do /inc I will be in inc. Can someone please guide me on what I'm doing wrong? Thanks. I have a code for writing a log file... The code is working fine but it inserts the new details at the bottom of the file but i want to insert in the top... So what function should i use... Here is the file my_log.php Code: [Select] <?php $usname = $_SESSION['usname']; date_default_timezone_set('Asia/Calcutta'); $date = date("l dS \of F Y h:i:s A"); $file = "log.php"; $open = fopen($file, "a+"); fseek($open,289); fwrite($open "<b><br/>USER NAME:</b> ".$usname . "<br/>"); fwrite($open, "<b>Date & Time:</b> ".$date. "<br/>"); fwrite($open, "<b>What have they done :</b> ".$reason . "<br/><br/>"); fclose($open); ?> and here is my log.php file : Code: [Select] <?php session_start(); if($_SESSION['stage']!=1 || $_SESSION['stage2']!=2) {header('location:index.php'); die(" "); } ?> <?php if($_GET['valu']=="view_log") { $reason=" ".$_SESSION['usname']." Viewed the LOG"; include('my_log.php'); header('location:log.php'); die(""); } // bytes till here are 289 //LINE 1 : Log details have to insert here I want to insert every detail from the top of the page but just below the php code.. What should i do... ANy helo would be appreciated Pranshu Agrawal pranshu.a.11@gmail.com I'm writing a script that takes user input from a html form and updates the database with the new data. In this example the user is updating the data about the university they attend. The problem with this is, the script to update the database with the new information appears to be not working - the new data is not being added to the database. The SQL queries used in the script work in phpMyadmin, and the variables - $uni and $username - contain the data the correct data. This has me stumped, could someone look over this for me please and tell me what is going wrong here. Code: [Select] <?php include 'connect.php'; session_start(); $_SESSION['username']; if(!(isset($_SESSION['login']) && $_SESSION['login']!= " ")){ header("Location: login.php"); } $username = $_SESSION['username']; $tablename = 'usr_test'; $uni = $_POST['uni']; $uni = stripslashes($uni); $uni = mysql_real_escape_string($uni); $uni = trim($uni); if(isset($uni)) { $username = $_SESSION['username']; $loc = mysql_query("SELECT * FROM usr_test WHERE usr = '$username'"); if (mysql_num_rows($loc) == 0) header("Location:notlogged.php"); else { extract(mysql_fetch_array($loc)); mysql_query("UPDATE usr_test SET uni = ('$uni') WHERE usr = '$username'") or die (mysql_error()); header("Location:profile.php"); } } ?> I have a web app hosted on Just Host that I have nearly finished writing but still needs to have coded the ability to write a text file to user's computer. the user should be able to specify where on their computer they would like the file to be stored. Is this possible ? And can you tell me how it's done, or point me to a souce that can tell me I rarely ever ask for help regarding programming, but this has flumoxed me. If it is not possible to do this, then would I have to generate this file on the Host's server (Just Host in my case), then download it ? If this can be done then can you please tell me how, as any info I have found related to file downloads seems a bit obscure thanks in advance im trying to make a program that changes some files from 0 to 1,but im having some trouble... heres my code, Code: [Select] $id = $_GET["id"]; $file1 = "http://mysite.co.cc/users/".$id."/file1.txt"; $fh = fopen($file1, 'w'); fwrite($fh, "1"); fclose($fh); I followed this tut: http://www.tizag.com/phpT/filewrite.php I cant find anything wrong with the code,but it will not make the file have 1 in it. Ok, I know how to write to a file, but what I'm looking for is to check if a line of code exists, and if it is, don't recreate it. It would also be nice to not recreate the file either. Code: [Select] $file = fopen("index.html", "w"); fwrite($file,"This is a line of text"); fclose($file); Greetings, I am trying to write XML using SimpleXML for a web service call. I was having success until the XML got a little more complicated. Here is the XML format where I am running into problems: Code: [Select] <Agent> <Person Last='Smith' First='John'> <Addresses /> <PhoneNumbers> <Phone Type='1' Number='888-555-1212'> </PhoneNumbers> </Person> </Agent> Here is my php: Code: [Select] $xmlOutput = new SimpleXMLElement('<?xml version="1.0"?><ReportRequest> </ReportRequest>'); $xmlOutput->addAttribute('CID','9200'); $xmlOutput->addAttribute('Diagram','1'); $xmlOutput->addAttribute('DueDate','2011-11-15'); $xmlOutput->addAttribute('NumPhotos','6'); $xmlOutput->addAttribute('InspectAfter',''); $xmlOutput->addAttribute('PolicyNumber','JTC0004425'); $reportType = $xmlOutput->addChild('ReportType'); $reportType->addAttribute('CPType','Commercial'); $reportType->addAttribute('SectionIDs',''); $reportType->addAttribute('Description',''); $reportType->addAttribute('ReportTypeID','123'); $locations = $xmlOutput->addChild('Locations')->addChild('Addresses')->addChild('Address'); $locations->addAttribute('Zip','91216'); $locations->addAttribute('City','Chatsworth'); $locations->addAttribute('Line1','123 Main St'); $locations->addAttribute('Line2','Suite 201'); $locations->addAttribute('State','CA'); $locations->addAttribute('Latitude',''); $locations->addAttribute('Longitude',''); $agent = $xmlOutput->addChild('Agent')->addChild('Person')->addChild('Addresses')->addChild('PhoneNumbers')->addChild('Phone'); $agent->addAttribute('Last','Smith'); $agent->addAttribute('Email',''); $agent->addAttribute('First','John'); $agent->addAttribute('Title',''); $agent->addAttribute('Type','1'); $agent->addAttribute('Number','888-555-1212'); $agent->addAttribute('TypeName','Office'); $agent->addAttribute('Extension',''); Header('Content-type: text/xml'); echo $xmlOutput->asXML(); Everything outputs as it should until the line that starts with $agent. I want the output to match the section above. I have tried several variations but I cannot seem to figure it out. I know the current PHP sample doesn't work. Help?? Thanks in advance, John Hi, I found this very good tutorial at IBM's site: http://www.ibm.com/developerworks/xml/library/x-validxphp/ BUT my question is, what if any arbitrary XML file is passed passed to this xml validator function as parameter (that I will soon write), so meaning there may not be an xml schema created, so how would I validate it then b/c the link above assumes there a schema is made to use to validate. Any help much appreicated! I am trying to write to a document that is open doc format. Are there any libraries that help out with this specifically mailing labels? for($i=0; $i!=count($account_data); $i++){ echo "\n::: ".strtoupper($account_data[$i][0])." :::\n"; if($account_data[$i][1] != "" && stristr($account_data[$i][0], "@") && stristr($account_data[$i][0], ".")){ list($place[0],$place[1],$place[2],$place[3]) = authorize($account_data[$i], $game_link); if($place[2] > 1 && strlen($place[3]) == 40){ $filename = 'auth-keys.txt'; $fp = file($filename,'a+'); $data = $place[2]." ".$place[3]."\r\n"; file_put_contents($filename, $data, FILE_APPEND); echo $data; } else echo "Account Skipped: wrong password/email combo, or a login error...\n"; $echo = file_put_contents($filename, FILE_APPEND); } else echo "Account Skipped: invalid email or blank password...\n"; } echo "\n::: PROGRAM FINISHED, YOU CAN CLOSE THIS AT ANY TIME :::"; sleep(10000); You see where I tried to put $echo file_put_contents etc... On success the acct writes a security id and a security auth key to a file, ever acct puts the tokens on a new line every acct... now when an acct echos account skipped, how can I make it print the echo on the file new line instead of nothing being writen and it just skipping the account i made a little uploader class, its not refined but it works, here is the class <?php /* This is a simple file uploader class created by me: Hugo Johnson website: www.jwmstudios.com email: hugoj@hotmail.com Its my first real shot at creating a php class, i am still a todler to this. */ Class Uploader { // Declaring my variables needed for this class, it makes sense. public $input_field_name = "userfile"; // default input field name public $file_size =300000; // default file size public $path_directory = ""; // location to send the file public $action_path_and_file = "uploader.php"; // default form action function form() { // This form is optional used if no form is provided, only good for one file echo <<<END <form enctype="multipart/form-data" method="post" action="$this->action_path_and_file "> <input name="$this->input_field_name" type="file" /><br /><input type="hidden" name="max_size" value="$this->file_size" /> <input type="submit" value="Upload" /> </form> END; } function file_field($field_name) { // optional for adding more than one file echo "<br /><input name=\"$field_name\" type=\"file\" /><br />"; } function upload($input_field_name) { // this will upload a file that coresponds to a field name of type file $filename = $_FILES[$input_field_name]['name']; // coming from the form $filesize = $_FILES[$input_field_name]['size']; // " " $temp = $_FILES[$input_field_name]['tmp_name']; // " " // move Uploaded File function places the file from its temp directory and puts it into the desired directory, $path = $this->path_directory.$filename; // you can type a path directory structure between the quotes eg. ../ or /filestorage etc. $uploadfile = move_uploaded_file($temp, $path); // moving file from temp location to new chosen path echo $uploadfile === TRUE ? '<br />File uploaded<br />' : '<br />Awaiting File Upload<br />'; } } ?> Save the file as uploader_bk.php Here is the test form: <?php // This is the test upload form include_once("uploader_bk.php"); // importing the Uploader class $myupload = new Uploader(); // declaring a new uploader object $myupload->file_size = 400000; // setting a different file size $myupload->path_directory = "myfiles/"; // You can mod the path directory at any time, leave blank if is on the same path as the script $myupload->action_path_and_file = $_SERVER['PHP_SELF']; // use $_SERVER['PHP_SELF'] if its the same script that is doing the processing $fieldname = array("joe", "Mary"); // This can apply to one file you may need to prefix variable names to add more fields; this could also be an include $max_fields = count($fieldname); // getting the maximum number of fields that you need echo "<br />"; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Handling File Uploads</title> </head> <body> <form enctype="multipart/form-data" method="post" action="<?php echo $myupload->action_path_and_file; ?>"> <?php for ($i=0 ; $i < $max_fields; $i++) { $myupload->file_field($fieldname[$i]); // input field. $myupload->upload($fieldname[$i]); // The uploading process. } ?> <input type="submit" value="Send File" /> </form> </body> </html> I've been using PHP includes for a while now but I've just started to try to get more advanced. (not much more) I'm using this code to both generate my page titles and give my li tags a class of active so I can style them with css as being in a down state. All is working but I just need a more efficient way of doing this I think. I currently have Code: [Select] <?php $title = basename($_SERVER['SCRIPT_NAME'], '.php'); if ($title == 'index') { $title = 'home'; } $title = ucfirst($title); $title = str_replace('-', ' ', $title); $title = ucwords($title); ?> Then in my unordered list I have Code: [Select] <?php if ($title == 'Product Selector'||$title == 'Kingston Range') {echo 'class="active"';} ?> I could continue to say if title = a or b or c or d etc but could I use an array to store all of these titles and check to see if the title is in the array? or is there a better way to do this? Thanks in advance i have this script where the user enters their name and their favorite quotes. It adds their favorite quotes and their names to quotes.txt and prints out their name and their quotes on view_quote.php. I need to use a foreach() loop to print out the name and the quotes, but I'm confused about how to set it up. Here's my files. add_quote.php Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <title>Add A Quotation</title> </head> <body> <?php // add_quote.php /* This script displays and handles an HTML form. This script takes text input and stores it in a text file. */ // Identify the file to use: $file = 'quotes.txt'; // Check for a form submission: if ($_SERVER['REQUEST_METHOD'] == 'POST') { // Handle the form. if ( !empty($_POST['quote']) && ($_POST['quote'] != 'Enter your quotation here.' ) ){ // Need some thing to write. if (is_writable($file)) { // Confirm that the file is writable. file_put_contents($file, $_POST['quote'] . PHP_EOL, FILE_APPEND | LOCK_EX); // Write the data. file_put_contents($file, $_POST['name'] . PHP_EOL, FILE_APPEND | LOCK_EX); // Print a message: print '<p>Your quotation has been stored.</p>'; } else { // Could not open the file. print '<p style="color: red;">Your quotation could not be stored due to a system error.</p>'; } } else { // Failed to enter a quotation. print '<p style="color: red;">Please enter a quotation!</p>'; } } // End of submitted IF. // Leave PHP and display the form: ?> <form action="add_quote.php" method="post"> <p>Name:<input type="text" name="name"/><br /> <textarea name="quote" rows="5" cols="30">Enter your quotation here.</textarea><br /> <input type="submit" name="submit" value="Add This Quote!" /> </form> </body> </html>view_quote.php Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <title>View A Quotation</title> </head> <body> <h1>View My Quotes</h1> <?php // view_quote.php /* This script displays and handles an HTML form. This script reads in a file and prints a random line from it. */ // Read the file's contents into an array: $data = file('quotes.txt'); // Count the number of items in the array: $n = count($data); // Pick a random item: $rand = rand(0, ($n - 1)); // Print the quotation: print '<p>' . trim($data[$rand]) . '</p>'; ?> </body> </html>and the quotes.txt file is blank until the user enters their names and quotes. Im trying to get this done kind of quick so any help would be awesome. |