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PHP - Counting The Rows In Mysql Database - The Obvious Choices Aren't Working!
I wish to have a page that will display a form if there aren't already enough registrations in the database. The following it an outline of how it will be:
<?php require_once "../scripts/connect_to_mysql.php"; //this works fine // Count how many records in the database (1) $sqlCommand = "SELECT * FROM teams"; (2) $sqlCommand = "SELECT COUNT (*) FROM teams"; (3) $sqlCommand = "SELECT COUNT (id) FROM teams"; $query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); (1) $numRegistrations = mysql_num_rows($query); //Count how many rows are returned from the query above (2) $numRegistrations = $query (3) $numRegistrations = mysql_num_rows($query); mysqli_free_result($query); ?> (Some HTML code, like DOCTYPE, head, start of body tags) <?php if($numRegistrations > 35){ echo "Sorry, registrations for this event is at it's maximum."; }else{ ?> <form blah blah blah> </form> <?php } ?> (end of body and html tag) You'll see above there is (1), (2), (3). These are the main 3 that I've been trying, and they match up the $sqlCommand to the $numRegistrations. What would be the problem with this code? I use wamp server to test, have been using it for ages. Chrome browser to test in. If I remove the database query, the rest of the page will load. With the query in there, only the HTML code up until the database query is parsed, so therefore nothing is display on the page. Please help. Thanks Denno Similar TutorialsHi I have a table (applicant) that has a number of fields but included a applicantid party1 party2 party3 party4 party5 Any number of these party entries could have data in them but I need to know, for any specific applicantid, the count of how many non null entries there are. I can't find a way to do it. Does anyone have any ideas. Many thanks Hey I'm trying to check a row in my database to see if its empty but this isnt working $usercheck = mysql_query("SELECT pet FROM users where name='$user'"); $returned_rows = mysql_num_rows($usercheck); if ($returned_rows == 0){ // do stuff if no pet }else{ echo 'There was ' . $returned_rows . ' records found.'; } The problem is its not checking the row pet its just checking to see if anything exists my database has id name pet 1 joe <empty> its just seeing joe and echoing "there was 1 record found" instead of seeing that the row pet is empty. thanks for the help A while back, I started using Doctrine and feel it brings many benefits, however, I experience many issues when the database schema contains unique indexes. I have since learned that deferrable constraints exist for some DB's and their use will eliminate my issues. According to MySQL's documentation the SQL standard is to make them the default, however, MySQL does not do so (and apparently neither does MariaDB which I typically use). I am considering changing databases. Any recommendations? I've always heard good things about postgresql. Thoughts? Much of a learning curve to change?
Thanks
Per https://dev.mysql.com/doc/refman/8.0/en/ansi-diff-foreign-keys.html: In an SQL statement that inserts, deletes, or updates many rows, foreign key constraints (like unique constraints) are checked row-by-row. When performing foreign key checks, InnoDB sets shared row-level locks on child or parent records that it must examine. MySQL checks foreign key constraints immediately; the check is not deferred to transaction commit. According to the SQL standard, the default behavior should be deferred checking. That is, constraints are only checked after the entire SQL statement has been processed. This means that it is not possible to delete a row that refers to itself using a foreign key.
Hi All, I'm hoping someone can help me. I'm looking to create a form that will submit multiple entries to a MySQL database depending on the options selected on the form. I am able to submit single entries, but the multiple entire is a bit of a mystery to me. I have attached an JPG image to show an example of how I would like the form to work. I have also added the description/explination below to this example: Example 1 The form was completed and three access types were selected. Thus Three entries, all with the Same Reference number were captured into the database Example 2 The form was completed and Two Access Types were selected. Thus Two entries, all with the Same Reference number were captured into the database Example 3 The form was completed and Four Access Types were selected. Thus Four entries, all with the Same Reference number were captured into the database Hi Forum I have this script below which i thought would update multiple rows in my database, but all it does is refresh and revert back to its original data. Im guessing my problem is in my update script but I cant seem to find where I have gone wrong. Any help would be greatly appreciated. <?php $host="*****"; $username="*****"; $password="*****"; $db_name="*****"; $tbl_name="*****"; // Connect to server and select databse. $db = new PDO('mysql:host=' . $host . ';dbname=' . $db_name, $username, $password); // If there is an update, process it. if (isset($_POST['submit'], $_POST['pageorder']) && is_array($_POST['pageorder'])) { $stmt = $db->prepare("UPDATE `$tbl_name` SET `pageorder`=:pageorder WHERE id=:id"); $stmt->bindParam(':id', $id, PDO::PARAM_INT); $stmt->bindParam(':pageorder', $pageorder, PDO::PARAM_STR); foreach ($_POST['pageorder'] as $id => $pageorder) { $stmt->execute(); } echo '<h1>Updated the records.</h1>'; } // Print the form. echo '<form action="' . htmlspecialchars($_SERVER['PHP_SELF']) . '" method="post">'; foreach ($db->query("SELECT `id`, `pageorder`, `pagetitle`, `linklabel` FROM `$tbl_name` ORDER BY `pageorder`") as $row) { echo '<input type="text" pageorder="pageorder[' . (int)$row['id'] . ']" value="'. htmlspecialchars($row['pageorder']) . '" />'; echo '<input type="text" pagetitle="pagetitle[' . (int)$row['id'] . ']" value="'. htmlspecialchars($row['pagetitle']) . '" />'; echo '<input type="text" linklabel="linklabel[' . (int)$row['id'] . ']" value="'. htmlspecialchars($row['linklabel']) . '" /><br />'; } echo '<input type="submit" name="submit" value="Update" /></form>'; ?> I'm trying to echo multiple rows from a MySQL database with no luck. I've tried this code and many other combinations with it, but can't seem to get a result. Quote $query = "select email,mens,womens from newsletters"; $result = mysql_query($query); while ($row = mysql_fetch_assoc($result)) {foreach ($row as .$email. .$mens. .$womens.) {echo "$email - $mens - $womens<BR>";}} What am I doing wrong? Hello folks I am new to php and I have been trying to put together a database that a user can search and choose from the results. I have managed to make this script by copying code from google searches and trial and error. The script so far has been tested and works. The hard part is the code for choosing from the results, I have tried some things but I have been far from the mark, the thing is I can't get my head around the problem, if the first field is a number which is unique to each row, how can I pick that up in a php argument. I have tried making the first field an href link to send that number to a different table which would collect the results of the users choices, but I'm just not sure what to put in the code. Could someone throw me a lifeline here I've searched for hours on google to find any code that looks like it would work with no luck. // Get the search variable from URL $var = @$_GET['a'] ; $trimmed1 = trim($var); //trim whitespace from the stored variable $var = @$_GET['b'] ; $trimmed2 = trim($var); $var = @$_GET['c'] ; $trimmed3 = trim($var); $var = @$_GET['d'] ; $trimmed4 = trim($var); $var = @$_GET['e'] ; $trimmed5 = trim($var); $var = @$_GET['f'] ; $trimmed6 = trim($var); //connect to your database mysql_connect("localhost","root",""); //(host, username, password) //specify database mysql_select_db("a2149809_MV") or die("Unable to select database"); //select which database we're using // Build SQL Query $query = "SELECT * FROM `table` WHERE `field1` LIKE \"%$trimmed1%\" AND `field2` LIKE \"%$trimmed2%\" AND `field3` LIKE \"%$trimmed3%\" AND `field4` LIKE \"%$trimmed4%\" AND `field5` LIKE \"%$trimmed5%\" AND `field6` LIKE \"%$trimmed6%\" order by `field1`"; $result=mysql_query($query); $num=mysql_num_rows($result); mysql_close(); <table width="100%" border=2 cellspacing=2 cellpadding=2> <tr><form name="form" action="" method="get"> <td colspan="6"><input type="submit" name="Submit" value="Search" /> </td> </tr> <tr> <td><input type="text" name="a" value="" size="4" /></td> <td><input type="text" name="b" value="" size="40" /></td> <td><input type="text" name="c" value="" size="3" /></td> <td><input type="text" name="d" value="" size="10" /></td> <td><input type="text" name="e" value="" size="10" /></td> <td><input type="text" name="f" value="" size="10" /></td> </form></tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"Field1"); $f2=mysql_result($result,$i,"Field2"); $f3=mysql_result($result,$i,"Field3"); $f4=mysql_result($result,$i,"Field4"); $f5=mysql_result($result,$i,"Field5"); $f6=mysql_result($result,$i,"Field6"); ?> <tr> <td><?php echo $f1; ?></td> <td><?php echo $f2; ?></td> <td><?php echo $f3; ?></td> <td><?php echo $f4; ?></td> <td><?php echo $f5; ?></td> <td><?php echo $f6; ?></td> </tr> <?php $i++; } ?> </table> I have a commenting system and i have a limit of a certain number of comments to be shown. What i want to do is have a button on the bottom of the page at the end of the comments that are showing and when you click it ajax loads the next certain number of of rows (but not all of them),and then you click it again and it shows more of them, etc. So for example. comment 1 comment 2 comment 3 comment 4 --click button--(loads 4 more)--- comment 5 comment 6 comment 7 comment 8 --click button--(loads 4 more)-- comment 9 comment 10 comment 11 comment 12 etc. until there are no more rows. what's the best way to do this? (I know how to do the ajax and all, i just need help with the script to select the rows) Thanks. Hello I have a table that inserts a new row with data when a member views a page. I wish to count all the rows for each member, and then be able to show what the cuurent members "position" is eg. what members has the highest row count. Example. counting the rows for member_A returns 1000 rows, the number of rows for member_B returns 1500 rows. How can I display for member_A that he is in "second" place? Hi I'm using php file to retrieve the amount of records in my database, but all of a sudden I get 0 results. It worked fine a few days ago. I got PHP 5.2.* on my host. Here is the current script that I use.
Did I made a mistake somewhere?
<?php
$con=mysqli_connect("******","*****","*****","****");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql="SELECT * FROM mxit";
if ($result=mysqli_query($con,$sql))
{
$rowcount=mysqli_num_rows($result);
//printf("Result set has %d rows.\n",$rowcount);
// Free result set
mysqli_free_result($result);
}
mysqli_close($con);
?>
I want to delete rows in a table of my database using check-box. Here are my codes below: Code: [Select] <?php $con = mysql_connect('localhost', 'root', '') or die ('Connection Failed'); mysql_select_db('img', $con) or die ('Connection Failed'); $display = mysql_query("SELECT * FROM photos WHERE email='$lemail'"); echo '<input type="submit" value="Delete" name="del"/>'; echo "<table> <tr> <th>#</th> <th>Images</th> <th>Image description</th> <th>Delete</th> </tr>"; while($row = mysql_fetch_array($display)) { echo "<tr>"; echo "<td>".$row['img_ID']."</td>"; echo "<td><img src='folder/".$row['imaged']."' alt='alt text' width='100' height='100' class='thumb'/> </td>"; echo "<td>".$row['image_description']."</td>"; echo '<td><input type="checkbox" name="delete[]" value="'.$row['img_ID'].'"/></td>'; echo "</tr>"; } echo "</table>"; echo "</form>"; if (isset($_POST['delete'])) { $del = $row['img_ID']; for($i=0;$i<count($_POST["delete"]);$i++) { if($_POST["delete"][$i] != "") { $str = "DELETE FROM photos WHERE img_ID='$del' "; mysql_query($str); echo "Record Deleted."; } } } mysql_close($connect); ?> Here are the problems: 1/ Not working at all, I mean no image is being deleted 2/ At then end, I display a message that the record has been deleted, but if I check multiple checkbox, it keeps writing the message "Records deleted" multiple times My images are stored in a folder while its details in database... Help, thank you I know how much you guys hate people asking for help without any starting code but I'm not even sure how to start this.. I want a script to read this page and count all the admins and referees. If anyone is willing to help, here's a sample of the html code: Code: [Select] <div class="boxInner"><h3>Arena Referees</h3><table class="list"><thead><tr><th style="width:16px;"></th><th style="width:150px;">Name</th><th style="width:300px;">Position</th><th style="width="150px;">Gamertag</th></tr></thead><tbody><tr><td><a href="http://gamebattles.com/profile/GottaHaveFaith78"><img src="http://media.gamebattles.com/icons/16/profile.png" class="icon16" /></a></td><td class="alt1">Faith</td><td><b>Head Referee</B></td><td class="alt1">GB CombatBarbie</td></tr><tr><td class="alt2"><a href="http://gamebattles.com/profile/Jack.-"><img src="http://media.gamebattles.com/icons/16/profile.png" class="icon16" /></a></td><td>Jack</td><td class="alt2"><b>Asst. Head Referee</b></td><td>Get Jacked x</td></tr><tr><td><a href="http://gamebattles.com/profile/amghawk"><img src="http://media.gamebattles.com/icons/16/profile.png" class="icon16" /></a></td><td class="alt1">Mike</td><td><b>Asst. Head Referee (IS)</b></td><td class="alt1">GB amghawk</td></tr><tr><td class="alt2"><a href="http://gamebattles.com/profile/cory94bailly"><img src="http://media.gamebattles.com/icons/16/profile.png" class="icon16" /></a></td><td>Cory</td><td class="alt2">Referee</td><td>Cory xz</td></tr><tr><td><a href="http://gamebattles.com/profile/crago"><img src="http://media.gamebattles.com/icons/16/profile.png" class="icon16" /></a></td> I'm just wondering how I could even count them. Any help will be appreciated, thanks. Hi, I have a problem regarding counting rows in a mysql table. Here is the code: Code: [Select] <?php require_once('includes/connection.inc.php'); $conn = dbConnect('read'); $check = 'SELECT COUNT(*) FROM images'; $checkRes = $conn->query($check) or die(mysqli_error()); if($checkRes <= 0) { header('Location: empty_blog.php'); // redirect to another page } else { // do something else... } ?> The error I'm getting: "Notice: Object of class mysqli_result could not be converted to int in C:\xampp\htdocs\photoblog\index.php on line 6" Any help is greatly appreciated! Hi all I need to combine these two scripts: Firstly, the following decides which out of the following list is selected based on its value in the mySQL table: <select name="pack_choice"> <option value="Meters / Pack"<?php echo (($result['pack_choice']=="Meters / Pack") ? ' selected="selected"':'') ?>>Meters / Pack (m2)</option> <option value="m3"<?php echo (($result['pack_choice']=="m3") ? ' selected="selected"':'') ?>>Meters / Pack (m3)</option> <option value="Quantity"<?php echo (($result['pack_choice']=="Quantity") ? ' selected="selected"':'') ?>>Quantity</option> </select> Although this works OK, I need it also to show dynamic values like this: select name="category"> <?php $listCategories=mysql_query("SELECT * FROM `product_categories` ORDER BY id ASC"); while($categoryReturned=mysql_fetch_array($listCategories)) { echo "<option value=\"".$categoryReturned['name']."\">".$categoryReturned['name']."</option>"; } ?> </select> I'm not sure if this is possible? Many thanks for your help. Pete Alright, I need to find a way to display the top ten duplicated rows for a table in my database. I have tried multiple methods but I have failed. Can you please assist me with this problem. I currently run a query in phpmyadmin to get the result, but i cant figure out how to properly code the php script. Folks, Having trouble here. Forgot how you use the COUNT. Not interested in the num_rows due to it being slow compared to COUNT. I have users table like this: id|username|sponsor_username 0|barand|requinix 1|phpsane|alison 2|mickey_mouse|requinix Now, I want to check if a sponsor username exists or not. Such as does the entry "requinix" exists or not in one of the rows in the "sponsor_username" column. In our example it does twice and so the variable $sponsor_username_count should hold the value "2". Else hold "0". I get error: Fatal error: Uncaught mysqli_sql_exception: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '?' at line 1
My code:
$stmt_1 = mysqli_prepare($conn,"SELECT COUNT(sponsor_username) from users = ?");
mysqli_stmt_bind_param($stmt_1,'s',$sponsor_username_count);
mysqli_stmt_execute($stmt_1);
//Show error if 'users' tbl was not successfully queried".
if (!$stmt_1)
{
echo "ERROR 1: Sorry! Our system is currently experiencing a problem loading this page!";
exit();
}
else
{
mysqli_stmt_bind_result($stmt_1,$sponsor_username_count);
mysqli_stmt_fetch($stmt_1);
mysqli_stmt_close($stmt_1);
//Check if Sponsor Username in Url ($_GET) is already registered or not. If not then show "Invalid Url" or Link message.
if ($sponsor_username_count < 1)
{
echo "<b>Invalid Url or Link!<br> Invalid Sponsor: \"$sponsor_username\"!</b><?php ";
exit();
}
}
i have 8 division (div), i want to display 4 rows in 4 division and the remain 4 rows in the next 4 division here is my code structure for carousel
<div class="nyie-outer"> second row third row
fourth row fifth row sixth row seven throw eighth row
</div><!--/.second four rows here-->
sql code
CREATE TABLE product( php code
<?php how can i echo that result in those rows
Here are the two if statements: if (!($start <= 0)){ $prev_button = "<a href='forum.php?category_id=$category_id&start=$prev'>Prev</a>"; } if (!($start >= $record_num - $per_page)){ $next_button = "<a href='forum.php?category_id=$category_id&start=$next'>Next</a>"; } But they are not properly working. This is part of a pagination script for the next and previous buttons. Hi everyone, I have been trying to get this code working but no matter what I try it will not work, I am trying to allow a user to update their personal details when they login to my website. I have created a form and submit button, the code is shwn below: <?php echo $_SESSION['myusername']; ?> <br><br> <form action="updated.php" method="post"> Firstname: <input type="text" name="firstname" /><br><br> Surname : <input type="text" name="surname" /><br><br> Date Birth: <input type="text" name="dob" /><br><br> Total Wins: <input type="text" name="wins" /> Total Loses: <input type="text" name="loses" /><br><br> Email Add: <input type="text" name="email" /><br><br> Country : <input type="text" name="born" /><br><br> Other Info: <input type="text" name="other" /><br><br> <input type="submit" name="Submit" value="Update" align="right"></td> </form> The updated.php file <?php mysql_connect ("localhost","root","") or die("Cannot connect to Database"); mysql_select_db ("test"); $sql=mysql_query("UPDATE memberdetails SET firstname='{$_POST['firstname']}', surname='{$_POST['surname']}', dob='{$_POST['dob']}', totalwins='{$_POST['wins']}', totalloses='{$_POST['loses']}', email='{$_POST['email']}', country='{$_POST['born']}', info='{$_POST['other']} WHERE username=$_SESSION['myusername']); if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "Details Updated"; ?> This is the error i recieve: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\wamp\www\website\updated.php on line 45 Line 45 is $sql=mysql_query line If anybody can help it will be very much appreciated! Is there an alert method for the MySQL database or something similar?
What is the proper way to check if the MySQL database connection is working?
I mean other than "creating" and "retrieving" with "insert" and "select".
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